Which postulate or theorem could you use to prove (triangle)XYZ = (triangle)ABC?Choose the correct answer below.AAS theoremSSS postulateASA postulateSAS postulate
Answers
From the given figures in the 2 triangles XYZ and ABC
mXZ = AC
m
Since we have two equal angles and the sides between them are equal, then
The 2 triangles are congruent using ASA postulate
The answer is C
Related Questions
Hello, I need assistance with this question within the image posted below.
Answers
A(-4, 0) and B(4, 0)
Explanation:A parabola is symmetrical about the y-axis, if the vertex is of the form (0, y). The y-axis is the line of symmetry. That is, the point x = 0.
If the parabola is symmetric about the y-axis, points A and B should fall on opposite sides of the y-axis.
For the parabola to be symmetric about the y-axis, the possible points to move A and B to are A(-4, 0) and B(4, 0)
Identify the augmented matrix for the system of equations and the solution using row operations.
Answers
Given:
The system of equation is given as,
[tex]\begin{gathered} 7x-4y=28 \\ 5x-2y=17 \end{gathered}[/tex]The objective is identify the augmented matrix for the system of equations and the solution using row operations.
Explanation:
The required augmented matrix will be,
Performing the Gauss-Jordan elimination with the following operation,
[tex]R_2=R_2-\frac{5R_1}{7}[/tex]By applying the operation to the augmented matrix,
To find y :
On equating the second row of the matrix,
[tex]\begin{gathered} \frac{6y}{7}=-3 \\ y=\frac{-3}{\frac{6}{7}} \\ y=\frac{-3\times7}{6} \\ y=\frac{-7}{2} \end{gathered}[/tex]To find x :
On equating the first row of the matrix,
[tex]\begin{gathered} 7x-4y=28 \\ 7x=28+4y \\ x=\frac{28+4y}{7} \end{gathered}[/tex]Substitute the value of y in the above equation.
[tex]\begin{gathered} x=\frac{28+4(\frac{-7}{2})}{7} \\ x=\frac{28-14}{7} \\ x=\frac{14}{7} \\ x=2 \end{gathered}[/tex]Thus the value of solutions are,
[tex]\begin{gathered} x=2 \\ y=-\frac{7}{2}=-3.5 \end{gathered}[/tex]Hence, option (3) is the correct answer.
I will give brainliest. By the way, two people need to answer for someone to give brainliest.
For the direct variation equation y=223x, what is the constant of proportionality?
A: 2
B: 2 2/3
C: 2/3
D: 3
The equation y=7x gives the relationship between the number of road projects, x, and the number of weeks it takes a crew of workers to complete all the projects, y. What is the constant of proportionality? What does it mean in this context?
A: The constant of proportionality is 7. It takes the crew of workers 7 weeks to complete 1 road project.
B: The constant of proportionality is 7. It takes the crew of workers 7 days to complete all of their road projects.
C: The constant of proportionality is 7. It takes the crew of workers 7 days to complete 1 road project.
D: The constant of proportionality is 7. It takes the crew of workers 7 weeks to complete all of their road projects.
Write a direct variation equation to find the number of miles a jet travels in 3 hours if it is flying at a rate of 600 mph.
A: 600 = 3x
B: 3 = 600x
C: y = 600/3
D: y = 600 x 3
Jamal earns $125,000 a year as a systems analyst. He wants to know how much he will earn if he continues at the same rate of pay for 7 years. Which equation will help him find this amount?
A: x = 125,000/5
B:125,000 = 7x
C:125,000 = 7/x
D: y = 125,000 x 7
Answers
Answer: I think B and for the second one I think C
Step-by-step explanation: The constant of proportionality is 7. It takes the crew of workers 7 days to complete 1 road project. That means they have to take at least 7 days which is correct.
Which of the following is a solution to the equation c + ( 4 -3c) - 2 = 0?A. -1B. 0C. 1D. 2
Answers
Given data:
The given equation is c+(4-3c)-2=0
The given equation can be written as,
c+4-3c-2=0
-2c+2=0
-2c=-2
c=1
Thus, the value of c is 1, so option C) is correct.
it's Hamilton path and Hamilton circuitweighted graph / graph theoryyou have to add each angle up and find the answer for each row 12 grade math
Answers
What you need to do in order to solve this is add the values that are defined by the begining and end points declared in there:
[tex]A\text{ B D E C A}[/tex]that means the distance defined by AB, BD, DE, EC & CA:
[tex]4+8+11+10+8\text{ = 41}[/tex]And in the same manner all of the other series of distances.
can you please help me on e. f. and g.
Answers
His temperature was 100.1 degree farad initially which is around 6 pm. At 7 pm it became 101 degree farad.
[tex]\begin{gathered} \text{slope = }\frac{y_2-y_1}{x_2-x_1}=\frac{101-100.1}{7-6}=\frac{0.9}{1}=0.9 \\ m=0.9 \end{gathered}[/tex]y = mx + b
where
m = slope
b = y - intercept
let find the y intercept
[tex]\begin{gathered} 101=0.9(7)+b \\ 101-6.3=b \\ b=94.7 \end{gathered}[/tex]Therefore, the equation is
[tex]y=0.9x+94.7[/tex]e. let us draw a graph
His temperature will be critical above 22 minutes past 9 pm.
f . He should go to emergency room.
g.
[tex]\begin{gathered} y=0.9x+94.7 \\ 98.6=0.9x+94.7 \\ 98.6-94.7=0.9x \\ 3.9=0.9x \\ x=\frac{3.9}{0.9} \\ x=4.33333333333 \end{gathered}[/tex]His temperature will be normal around past 4 pm which is 98.6 degree farad.
A basic cellular package costs $20/month for 60 minutes of calling with an additional charge of $0.20/minute beyond that time. The cost function C(x) for using x minutes would beIf you used 60 minutes or less, i.e. if if x≤60, then C(x)=20 (the base charge). If you used more than 60 minutes, i.e. (x−60) minutes more than the plan came with, you would pay an additional $0.20 for each of those (x−60) minutes. Your total bill would be C(x)=20+0.20(x−60). If you want to keep your bill at $50 or lower for the month, what is the maximum number of calling minutes you can use?
Answers
The maximum number of calling minutes you can use for $50 is 210 minutes.
To solve this, we have the function cost C(x) that depends on the amount of acalling munutes (x)
We want this cost to be $50 or lower. This means:
[tex]\begin{gathered} CostFunction\colon C(x)=20+0.2(x-60) \\ Maximum\text{ value of 50:}C(x)\le50 \end{gathered}[/tex]Then we can create an inequality:
[tex]50\ge20+0.2(x-60)[/tex]And now we can solve for x:
[tex]\begin{gathered} 50\ge20+0.2(x-60) \\ \frac{50-20}{0.2}\ge x-60 \\ 150+60\ge x \\ x\le210\text{ minutes} \end{gathered}[/tex]Thus, with $50 we can talk up to 210 minutes.
To be sure of the result, let's plug x = 210 in the function and it should give us a cost of C(210) = 50:
[tex]\begin{gathered} x=210\Rightarrow C(210)=20+0.2(210-60) \\ C(210)=20+0.2\cdot150 \\ C(210)=20+30=50 \end{gathered}[/tex]This confirms the result.
ratios 1 to 32 spoonful of 32 sprinkles
Answers
If for each sundae the shop uses 4 spoonfuls of sprinkles, if we want to know how many sundaes the shop did with 32 spoonfuls we must divide 32 by 4, if we do it we get
[tex]32\div4=8[/tex]Therefore, the shop did 8 sundaes! we can count it to make sure:
4 spoonfuls - 1 sundae
8 spoonfuls - 2 sundaes
12 spoonfuls - 3 sundaes
16 spoonfuls - 4 sundaes
20 spoonfuls - 5 sundaes
24 spoonfuls - 6 sundaes
28 spoonfuls - 7 sundaes
32 spoonfuls - 8 sundaes
A jar of marbles contains the following: two red marbles, three white marbles, five blue marbles, and seven green marbles.What is the probability of selecting a red marble from a jar of marbles?
Answers
ANSWER
[tex]\frac{2}{17}[/tex]EXPLANATION
Given;
[tex]\begin{gathered} n(Red)=2 \\ n(white)=3 \\ n(blue)=5 \\ n(green)=7 \end{gathered}[/tex]The total number of marble is;
[tex]n(Total)=2+3+5+7=17[/tex]Recall, the probability of an event can be calculated by simply dividing the favorable number of outcomes by the total number of the possible outcome
Hence, the probability of selecting a red marble is;
[tex]\begin{gathered} Prob(Red)=\frac{n(Red)}{n(Total)} \\ =\frac{2}{17} \end{gathered}[/tex]74. Noam wants to put a fence around his rectangular garden. His garden measures 35 feet by 50 feet. Thegarden has a path around it that is 3 feet wide. How much fencing material does Noam need to enclose thegarden and path?A. 97 ftB. 194 ftC. 182 ftD. 146 ft
Answers
Given:
The length of the rectangular garden, l=50 feet.
The breadth of the rectangular garden, b=35 feet.
The width of the path around the garden, w=3 feet.
The figure can be drawn as,
So, the length of the fence, L=l+2w.
The breadth of the fence, B=b+2w
The perimeter of the fence can be calculated as,
[tex]\begin{gathered} P=2(L+B) \\ =2(l+2w+b+2w) \\ =2(l+b+4w) \\ =2(50+35+4\times3) \\ =2(50+35+12) \\ =2\times97 \\ =194\text{ ft} \end{gathered}[/tex]Therefore, the perimeter of the fence is 194 ft.
Option B is correct.
Gary is saving money to buy a ticket to a New York Jets game that costs $225. Healready has saved $18. What is the least amount of money Gary must save each week, sothat at the end of 9 weeks he has enough money to buy the ticket? (Only an algebraic- solution will be accepted.)
Answers
lillyvong13, this is the solution:
Cost of the ticket to a New York Jets game = $ 225
Savings up to now = $ 18
Difference = 225-18 = 207
Number of weeks = 9
Let x to represent the amount of money Gary must save each week for buying the ticket, as follows:
x = 207/9
x = 23
Gary must save $ 23 at the end of 9 weeks to have enough money to buy the ticket
13. A co-ed soccer team has a boy to girl ratio of 3:2. There are 15 boys on the team. What is the total number of players on the team?
Answers
The ratio of boy to girl is 3:2. There are 15 boys on the team. The total number of players on the team can be calculated as follows.
[tex]\begin{gathered} \frac{3}{5}\times x=15 \\ \text{where} \\ x=\text{total number of players in the teams} \\ \frac{3x}{5}=15 \\ \text{cross multiply} \\ 3x=15\times5 \\ 3x=75 \\ x=\frac{75}{3} \\ x=25 \end{gathered}[/tex]Total players = 25
Li’s family is saving money for their summer vacation. Their vacation savings account currently has a balance of $2,764. The family would like to have at least $5,000.Which inequality can be used to determine the amount of money the family still needs to save?
Answers
EXPLANATION
Savings account balance = $2,764
Desired amount = $5,000
Let's call x to the amount of money the family needs.
The inequality that could be used to determine the amount of money the family needs is the following:
2,764 + x ≥ 5,000
Find extreme values of function f(x) = x³ - (3/2)x² on interval [- 1,2]
Answers
we have the function
[tex]f(x)=x^3-\frac{3}{2}x^2[/tex]Find out the first derivative of the given function
[tex]f^{\prime}(x)=3x^2-3x[/tex]Equate to zero the first derivative
[tex]\begin{gathered} 3x^2-3x=0 \\ 3x(x-1)=0 \end{gathered}[/tex]The values of x are
x=0 and x=1
we have the intervals
(-infinite,0) (0,1) (1,infinite)
Interval (-infinite,0) -----> f'(x) is positive
interval (0,1) ---------> f'(x) is negative
interval (1,infinite) -----> f'(x) is positive
that means
x=0 is a local maximum
x=1 is a local minimum
Find out the y-coordinates of the extreme values
For x=0 -----> substitute in the function f(x) ---------> f(x)=0
For x=1 ------> substitute in the function f(x) ------> f(x)=-0.5
therefore
The extreme values are
local maximum at (0,0)local minimum at (1,-0.5)-2 decimal 3/% because if you divide the principal in half its 1% of 3
Hello! I think this works but I'm not 100% sure
Answers
Given:
1 counsellor for every 9 campers.
Lets' determine the type of variation and write the equation.
Here, we can see that for every 9 campers, there is one extra counsellor. This means that as the number of campers increase, the number of counsellors will also increase.
Since one variable as the other increases, this is a direct variation.
Hence, we have the equation which represents the direct variation below:
y = 9x
Where x represents the number of counsellors and y represents the number of campers.
ANSWER:
Direct variation.
y = 9x
Find the coordinates of the vertex of the graph of y=4-x^2 indentify the vertex as a maximum or minimum point A.(2,9);maximumB.(0,4);minimumC.(0,4);maximum D.(2,0);minimum
Answers
Let's begin by identifying key information given to us:
[tex]\begin{gathered} y=4-x^2 \\ y=-x^2+4 \\ a=-1,b=0,c=4 \\ x_v=-\frac{b}{2a}=-\frac{0}{2(-1)}=0 \\ y_v=-\frac{b^2-4ac}{4a}=-\frac{0^2-4(-1)(4)}{4(-1)} \\ y_v=-\frac{0+16}{-4}=\frac{-16}{-4}=4 \\ y_v=4 \\ \\ \therefore The\text{ vertex of the equation is }(0,4) \end{gathered}[/tex]To know if the vertex is the maximum or minimum point, we will follow this below:
[tex]\begin{gathered} y_v=4 \\ \Rightarrow This\text{ is a minimum point} \end{gathered}[/tex]Hence, the answer is B.(0,4); minimum
Derek has $20 to spend on used books, but he can not spend all $20.Hardcover books cost $5 each and paperbacks cost $2 each. Create aninequality which determines the number (x) of hardcover books and the number(y) of paperback books he can buy.
Answers
Given:
The amount to spend on books, T=$20.
The cost of a handcoverbook, m=$5.
The cost of a paperback, n=$2.
Let x be the number of handcover books and y be the number of paperback books.
It is said that the complete amount of $20 cannot be spend.
So, the inequality to determine x and y can be written as,
[tex]\begin{gathered} T>mx+ny \\ 20>5x+2y \end{gathered}[/tex]So, the inequality is 20>5x+2y.
Divide the polynomial by the binomial. (Simplify your answer completely.)
(q² + 5q + 20) / (q + 8)
Answers
Answer:
It's already in its simplest form.
Step-by-step explanation:
Factorising QuadraticsI'm writing a book/document on this topic but it's not finished. I suspect there is an error in this question because it's practically impossible to factorise it into integers.
The quadratic polynomial in the numerator has imaginary roots because 5 squared is less than 20 times 4.
ax² + bx + c;
if ( b² < 4ac ) { 'solution is imaginary' }
The quadratic equation will explain the above.
7) The water park is a popular field trip destination. This year the senior class at High School A and thesenior class at High School B both planned trips there. The senior class at High School A rented andfilled 1 van and 14 buses with 309 students. High School B rented and filled 4 vans and 14 buseswith 354 students. Each van and each bus carried the same number of students. Find the number ofstudents in each van and in each bus.C) Van: 19 Bus: 29 D) Van: 15, Bus: 21
Answers
Given
The water park is a popular field trip destination. This year the senior class at High School A and the senior class at High School B both planned trips there. The senior class at High School A rented and filled 1 van and 14 buses with 309 students. High School B rented and filled 4 vans and 14 buses with 354 students. Each van and each bus carried the same number of students.
Answer
Let students in Van be x
And students in bus be y
A/Q
x + 14y = 309 (1)
4x + 14y = 354 (2)
Subtracting (1) and (2)
3x = 45
x = 15
Put in eq (1)
15 + 14 y = 309
14y = 309 - 15
14 y = 294
y = 21
St
Pic includes all informatin
Answers
Answer: 8squares
Step-by-step explanation:
how to solve 2x^2-3x-1=0
Answers
Explanation
[tex]2x^2-3x-1=0[/tex]Step 1
remember the quadratic formula.
if you have the equation
[tex]ax^2+bx+c=0[/tex]the value for x is
[tex]x=\frac{-b^2+\sqrt{b^2}-4ac}{2a}[/tex]Step 2
let
[tex]ax^2+bx+c=2x^2-3x-1[/tex]a=2
b=-3
c=-1
Step 3
replace
[tex]undefined[/tex]Determine if the correlation between the two given variables is likely to be positive or negative, or if they are not likely to display a linear relationship.A child’s age and the number of hours spent napping-positive-negative-no correlation
Answers
We know that a a childresn spend more hours napping when they are youngers therefore we have a negative correlation
Given the base band height of a triangle, calculate the area A using the formula for the area of a triangle: A ) bh
Answers
Solution
For this case the area is given by:
[tex]A=\frac{1}{2}bh[/tex]Then we can replace b = 5ft and h = 20 ft and we got:
[tex]A=\frac{1}{2}(5ft)(20ft)=50ft^2[/tex]Juan and María López wish to invest in a no-risk saving account. they currently hace $30,000 in an account bearing 5.25% annual interest, compounded continuously. the following choices are available to them.A. Keep the Money in The account they currently have B. invest the Money in an account earning 5.875% interest compounded annually c. invest the Money in an account earning 5.75% compounded semi annually d. invest Money in an account earning 5.5% annual interést compounded quarterly
Answers
The general formula for the amount in savings account compounded annually is given as;
[tex]\begin{gathered} A=P(1+\frac{r}{100n})^{nt} \\ \text{Where A=Amount} \\ P=\text{Initial deposit} \\ r=\text{rate} \\ n=n\text{ umber of times it is compounded annually} \\ t=\text{time} \end{gathered}[/tex]A. The equation for the value of the investment as a function of t in the current account they have is;
[tex]A(t)=\text{ \$30000(1+}\frac{5.25}{100})^t[/tex]B. The equation for the value of the investment in an account earning 5.875% interest compounded annually is;
[tex]A(t)=\text{ \$30000(1+}\frac{5.875}{100})^{t^{}}[/tex]C. The equation for the value of the investment in an account earning 5.75% compounded semi-annually; that is twice in a year is;
[tex]\begin{gathered} A(t)=\text{ \$30000(1+}\frac{5.75}{100(2)})^{2t} \\ A(t)=\text{ \$30000(1+}\frac{5.75}{200})^{2t} \end{gathered}[/tex]D. The solution for the value of the investment in an account earning 5.5% annual interest compounded quarterly; that is four times in a year;
[tex]\begin{gathered} A(t)=\text{ \$30000(1+}\frac{5.5}{100(4)})^{4t} \\ A(t)=\text{ \$30000(1+}\frac{5.5}{400})^{4t} \end{gathered}[/tex]I need some help with this! I know about the trig identitys and stuff like that, but I just get a little confused on how to apply sometimes.
Answers
we have that
Let
x ------> the distance in miles from a point on the ground (the red line)
In the right triangle of the figure
sin(6.5)=7,000/x
solve for x
x=7,000/sin(6.5)
using a calculator
x=61,835.70 ft
Convert to miles
Remember that
1 mile=5,280 ft
so
61,835.7 ft=61,835.7/5,280=11.71 miles
therefore
the answer is 11.71 miles3. x-intercept 4, y-intercept 2, passes through 5. Center on x = 3, radius 13, passes through Center on the y-axis, radius 5, x-intercept 3 cle having the given center and radius. (b) C (-2,-5), r = 4 (d) C(2, -3), r= 6 ving the given properties. (0,0) (6, 5)
Answers
Samantha, this is the solution to problem 5:
With the information given in the statement you can solve for k, where k is the center in y:
(x-h)^2 + (y-k)^2 = r^2
(6-3)^2 + (5-k)^2 = (√(13))^2
(3)^2 + (5-k)^2 = 13
9+(5-k)^2 = 13
(5-k)^2 = 4
√((5-k)^2) = √4
5-k = 2
-k = -3
k = 3
Then the equation of the circle will be
(x-3)^2 + (y-3)^2 = 13
at a sale a desk is being sold for 24% of the regular price. the sale price is $182.40 what is the regular price
Answers
at a sale a desk is being sold for 24% of the regular price. the sale price is $182.40 what is the regular price
we have that
24% ------> represent $182.40
so
Applying proportion
Find out the 100%
Let
x ----> the regular price
182.40/24=x/100
solve for x
x=(182.40)*(100)/24
x=$760
therefore
The regular price is $760The figure ABCD is a rectangle. AB = 2 units, AD = 4 units, and AE = FC = 1 unit.Find the area of triangle ABE.
Answers
Area of triangle ABE can be calculated using the formula 1/2 x b xh
From the question,
base b = AE = 1
height h =AB = 2
substitute the values into the formula
[tex]A=\frac{1}{2}\times1\times2[/tex]Area = 1 square unit
Several friends go to a casino and do some gambling. The following are the profits each of these friends make: $120, -$230, $670, -$1020, $250, -$430, and -$60. What is the average profit of this group? A. $100 B. -$100 C. -$1020 D. $397
Answers
The average profit of this group is B. -$100.
The average represents the total profits and losses generated by the group of friends, divided by the number in the group.
The average is the data set's mean after performing the mathematical operations of addition and division on the data values.
Friends Profits
A $120
B -$230
C $670
D -$1020
E $250
F -$430
G -$60
Total -$700
Average profit = -$100 (-$700/7)
Thus, we can conclude that the friends generated an average profit of B. -$100 from gambling or a total loss of $700.
Learn more about the average at https://brainly.com/question/130657
#SPJ1
i need help, i already did the first part but i don’t understand the second part.
Answers
a) To convert to radical form, we follow this:
[tex]m^{\frac{a}{b}}=\sqrt[b]{m^{a}}[/tex]So:
[tex]R=73.3m^{\frac{3}{4}}=73.3\sqrt[4]{m^{3}}[/tex]b) The formula we have is for mass in Kilograms, so the first step is to convert the mass stated from lbs to kg.
1 lb -- 0.454 kg
160 lb -- m
[tex]m=0.454\cdot160=72.64\operatorname{kg}[/tex]Now, we can use this value in the formula:
[tex]R=73.3m^{\frac{3}{4}}=73.3\cdot(72.64)^{\frac{3}{4}}=1823.84[/tex]a) To convert to radical form, we follow this:
[tex]m^{\frac{a}{b}}=\sqrt[b]{m^{a}}[/tex]So:
[tex]R=73.3m^{\frac{3}{4}}=73.3\sqrt[4]{m^{3}}[/tex]b) The formula we have is for mass in Kilograms, so the first step is to convert the mass stated from lbs to kg.
1 lb -- 0.454 kg
160 lb -- m
[tex]m=0.454\cdot160=72.64\operatorname{kg}[/tex]Now, we can use this value in the formula:
[tex]R=73.3m^{\frac{3}{4}}=73.3\cdot(72.64)^{\frac{3}{4}}=1823.84[/tex]