Which statement explains why 49 is a perfect square?

Answer:

 α = 2.13 10⁻⁵ C⁻¹    ,  the closest material is ALUMINUM

Explanation:

The expression for thermal expansion is

          ΔL = α L₀ ΔT

temperatures are

         ΔT = 85 - 10 = 75 ° C

the length of the rod is L₀ = 125 m and L_f = 125.20 m

        ΔL = 125.20 - 125 = 0.20 m

        α = [tex]\frac{1}{L_o} \frac{\Delta L }{\Delta T}[/tex]

        α = [tex]\frac{ 1}{125} \ \frac{0.20 }{75}[/tex]

        α = 2.13 10⁻⁵ C⁻¹

When reviewing the table, the closest material is ALUMINUM

Answer:

Perpendicular ; Parallel

Answer:

Part A

The power to turn on the lamp, ∑P = 3.36 W

Part B

The Resistor required is approximately 8.04 Ohms

Part C

The time for all the lights to go out is approximately 21.43 hours

Explanation:

The input voltage of the motor battery , V = 12 V

The capacity of the battery, Q = 6 Ah

The number of lamps in parallel = 8 lamps

The maximum voltage of each lamp,  = 3 V

The electric current in each lamp = 140 mA

The energy available in a battery, E = Q × V

For the battery, we have;

E = 6 Ah × 12 V = 72 Wh

The energy available in a battery, E = 72 Wh

Part A

The power used by the lamps, [tex]P_i[/tex] = [tex]I_i[/tex] × [tex]V_i[/tex]

∴ The total power used by the lamp, ∑P = 8 × 0.14 A × 3 V = 3.36 W

The power to turn on the lamp, ∑P = 3.36 W

Part B

The resistance required, is given as follows;

Resistor required = (Battery voltage - Lamp voltage)/(The sum of bulb current)

∴ Resistor required = (12 V - 3 V)/(8 × 0.14 A)

The Resistor required = 8.03571429 Ohms

The Resistor required ≈ 8.04 Ohms

Part C

The time for all the lights to go out = The time for the lamps to use all the power available in the battery

The time for all the lights to go out, t = E/∑P

∴ t = 72 Wh/(3.36 W) = 21.4285714 h

∴ The time for all the lights to go out, t ≈ 21.43 h

The time for all the lights to go out = The time for the lamps to use all the power available in the battery = t ≈ 21.43 h

∴ The time for all the lights to go out ≈ 21.43 hours.

Explanation:

With most of our blue planet covered by water, it's little wonder that, centuries ago, the oceans were believed to hide mysterious creatures including sea serpents and mermaids. Merfolk (mermaids and mermen) are, of course, the marine version of half-human, half-animal legends that have captured human imagination for ages. One source, the "Arabian Nights," described mermaids as having "moon faces and hair like a woman's but their hands and feet were in their bellies and they had tails like fishes."

C.J.S. Thompson, a former curator at the Royal College of Surgeons of England, notes in his book "The Mystery and Lore of Monsters" that "Traditions concerning creatures half-human and half-fish in form have existed for thousands of years, and the Babylonian deity Era or Oannes, the Fish-god ... is usually depicted as having a bearded head with a crown and a body like a man, but from the waist downwards he has the shape of a fish." Greek mythology contains stories of the god Triton, the merman messenger of the sea, and several modern religions including Hinduism and Candomble (an Afro-Brazilian belief) worship mermaid goddesses to this day.

Answer:

Valence electrons are outer shell electrons with an atom and can participate in the formation of chemical bonds. In single covalent bonds, typically both atoms in the bond contribute one valence electron in order to form a shared pair. The ground state of an atom is the lowest energy state of the atom.

Answer:

k and...

Explanation:

Answer:

no thank you.

explanation: Do not want to

Answer:

2

Explanation:

wave length is the distance between corresponding points of two consecutive waves

3. hertz

300

could i get brainiest

Answer:

III. The lift force is present because the pressure across the top is less than the pressure across the bottom of the wing.

Explanation:

Answer:

ij

Explanation:

Answer:

  I = 1.8 N s,  it is directed towards the right  

Explanation:

For this exercise we use the relationship between momentum and moment

         I = Δp

         F t = p_f - p₀

in this case the initial velocity is v₀ = - 2,0 m / s and final velocity v_f = 10,0 m / s, we assume the positive right direction

          I = m (v_f - v₀)

let's calculate

         I = 0.150 (10.0 - (-2.0))

         I = 0.150 (10 + 2)

         I = 1.8 N s

as the impulse is positive it is directed towards the right

Answer:

32

Explanation:

Answer:

32

Explanation:

Sulfur has 16 protons and 16 neutrons. The atomic number is roughly 32. Therefore, 16 + 16 = 32 nucleons.  

Answer:

74.88N

Explanation:

From the question,

F = ma................... Equation 1

Where F = force exerted on the ball, m = mass of the ball, a = acceleration

But,

v² = u²+2as.............. Equation 2

Where v = final velocity, u = initial velocity, s = distance.

Given: v = 12 m/s, u = 0 m/s (from rest), s = 5.0 m

Substitute into equation 2 and solve for a

12² = 0²+2×a×5

144 = 10a

10a = 144

a = 144/10

a = 14.4 m/s²

Also Given: m = 5.2 kg,

Substitute into equation 1

F = 5.2×14.4

F = 74.88 N

Hence the force exerted on the ball is 74.88 N

Answer:

0.125 volts

Explanation:

The induced emf can be sufficient to stimulate neuronal activity.

One such device generates a magnetic field within the brain that rises from zero to 1.5 T in 120 ms.

We need to find the induced emf within a circle of tissue of radius 1.6 mm and that is perpendicular to the direction of the field. The formula for the induced emf is given by :

[tex]\epsilon=-\dfrac{d\phi}{dt}[/tex]

Where

[tex]\phi[/tex] is magnetic flux

So,

[tex]\epsilon=-\dfrac{d(BA)}{dt}\\\\=2\pi r\times \dfrac{dB}{dt}\\\\=2\pi \times 1.6\times 10^{-3}\times \dfrac{1.5-0}{120\times 10^{-3}}\\\\=0.125\ V[/tex]

So, the induced emf is equal to 0.125 volts.

Answer:

2000J

Explanation:

The formula for work is W=Force x Distance

W=FxD

W=500N x 4m

W=2,000 Joules

Solution :

Given :

Force, F = 500 N

Let [tex]$ \vec F = F_x\ \hat i + F_y\ \hat j$[/tex]

      [tex]$|\vec F|=\sqrt{F_x^2+F_y^2}$[/tex]

∴ [tex]$F_x=F \cos 60^\circ = 500 \ \cos 60^\circ = 250 \ N$[/tex]

  [tex]$F_y=-F \cos 30^\circ = -500 \ \cos 30^\circ = -433.01 \ N$[/tex]   (since [tex]$F_y$[/tex] direction is in negative y-axis)

[tex]$F=250 \ \hat i - 433.01 \ \hat j$[/tex]

So scalar components are : 250 N and 433.01 N

     vector components are : [tex]$250 \ \hat i$[/tex] and [tex]$-433.01\ \hat j$[/tex]

1.  Scalar components along :

 x' axis = 500 N, since the force is in this direction.

 [tex]$F_{x'}= F \ \cos \theta = 500\ \cos \theta$[/tex]

  Here, θ = 0° , since force and axis in the same direction.

So, cos θ = cos 0° = 1

∴ [tex]$F_{x'}=500 \times 1=500\ N$[/tex]

[tex]$F_{y'}= F \ \sin \theta = 500\ \sin 0^\circ=500 \times 0=0$[/tex]

[tex]$F_{y'}=F\ cos \theta$[/tex] but here θ is 90°. So the force ad axis are perpendicular to each other.

[tex]$F_{y'}=F\ \cos 90^\circ= 500 \ \cos 90^\circ = 500 \times 0=0$[/tex]

∴ [tex]$F_{x'}= 500\ N \text{ and}\ F_{y'}=0\ N$[/tex]

2. Scalar components of F along:

x-axis :

[tex]$F_x=F\ \cos \theta$[/tex],   here θ is the angle between x-axis and F = 60°.

[tex]$F_x=500 \times \cos60^\circ=250\ N$[/tex]

y'-axis :

[tex]$F_{y'}=F\ \cos \theta$[/tex],   here θ is the angle between y'-axis and F = 90°.

[tex]$F_{y'}=500 \times \cos90^\circ=500\times 0=0\ N$[/tex]

∴ [tex]$F_{x}= 250\ N \text{ and}\ F_{y'}=0\ N$[/tex]

Answer:

The SI unit of time is second (s) and temperature is Kelvin (K)

Explanation:

hope it is helpful to you

Answer:

False.

Explanation:

An aurora is a natural electric phenomenon that creates bright and colorful light displays in the sky. These dramatic and colorful lights are created when electrically charged particles from solar winds enter the Earth's atmosphere and interact with gases in the atmosphere.

Answer:

V = f x λ

Explanation:

The options are confusing

Answer:

7.35..kg

Explanation:

Hope this will help you

Please,Mark me as Brainllist .

Answer:

The magnitude of the magnetic force acting on the conductor is 0.75 Newton

Explanation:

The parameters given in the question are;

The length of the straight segment of wire, L = 25 cm = 0.25 m

The current carried in the wire, I = 5 A

The orientation of the wire with the magnetic field = Perpendicular

The strength of the magnetic field in which the wire is located, B = 0.60 T

The magnetic force, 'F', is given by the following formula;

F = [tex]\underset{I}{\rightarrow }[/tex]·L×[tex]\underset{B}{\rightarrow }[/tex] = I·L·B·sin(θ)

Where;

[tex]\underset{I}{\rightarrow }[/tex] = The current flowing, I

L = The length of the wire

[tex]\underset{B}{\rightarrow }[/tex] = The magnetic field strength, B

θ = The angle of inclination of the conductor to the magnetic field

Where I = 5 A, L = 0.25 m, B = 0.60 T, and θ = 90°, we get;

F = 5 A × 0.25 m × 0.60 T × sin(90°) = 0.75 N

Therefore

The magnitude of the magnetic force, F = 0.75 N.

Answer:

I = 1.666... amps

Explanation:

P = I*V or Power = Current * Voltage

(100 watts) = I * (60 Volts)

I = 1.666... amps

Answer:

The torque is approximately 3.82 N·m

Explanation:

The relationship between work done, 'W', and the applied torque, 'τ' can be presented as follows;

W = τ × Δθ

Where;

W = The work done by the torque

τ = The magnitude of the torque

Δθ = The angle through which the object is turned

The parameters for 'W' and 'Δθ' are;

W = 3j

Δθ = 1/4 × π

From W = τ × Δθ, we have;

τ = W/Δθ

∴ τ = 3j/(1/4 × π) ≈ 3.81971863421 N·m

The torque, τ ≈ 3.82 N·m

Explanation:

transfer to babes are always at your advice by a particular motion being a particular wave motion along didn't wave is a wave which particular is a medium move a direction parallel to the direction of the wave moves something that is similar in the surveys on the medium moves of the same direction and bathe an accident to one or two Dimensions do in London killing babe attacks in one dimension and transverse waves attacks in two Dimensions the Waze cannot be paralyzed or organized

Answer:

Velocity can be directly added or subtracted.

For example, if a boat has a velocity V in still water.

And now you put the boat in a river with a current that has a velocity V'

The total velocity of the boat in that river is just the addition of these two velocities.

Velocity in the river  = V + V'

Where the only tricky part is that the velocity is a vector, so you need to take in account the directions of each vector.

In this case, we have a plane with a maximum velocity of 160km, let's assume a direction for this velocity, let's say that is in the positive x-direction.

Then we can write the velocity in the vector form:

velocity  = (vel in x-axis, vel in y-axis)

The velocity of the plane can be written as:

v = (160km/h, 0)

Now we add a crosswind of 30km/h

crosswind means that it is perpendicular, then it acts on the y-axis.

Then the total velocity of the plane will be:

velocity = (160km/h, 0) + (0, 30km/h)

velocity = (160km/h, 30km/h)

Now you can compute the total velocity of the airplane as the module of that vector.

Remember that for a vector (x, y) the module is:

mod = √(x^2 + y^2)

Then the module of the velocity is:

v = √( (160km/h)^2 + (30km/h)^2) = 162.8 km/h

Answer: 2

Explanation:

The distance - time graph of the humming bird is missing, so i have attached it.

Answer:

Instantaneous velocity = 0.5 m/s

Explanation:

From the attached graph, at time t = 1 s, the corresponding distance is 0.5 m.

Instantaneous velocity is the velocity at that point.

Thus;

Instantaneous velocity = 0.5/1

Instantaneous velocity = 0.5 m/s