why is the response to a temperature change as a stress in a chemical reaction different from the response to a change in concentration?

Answers

Answer 1

The response to a temperature change as a stress in a chemical reaction is different from the response to a change in concentration because temperature affects the rate of the reaction

Temperature: Temperature affects the rate of a reaction by increasing the number of molecules with enough energy to react. As the temperature rises, molecules move faster, collide more often and with more energy, and react more frequently. This increases the rate of a reaction. Concentration: Concentration affects the amount of reactants and products in a chemical reaction, not the rate. When the concentration of reactants increases, there is an increased chance of collisions, and the amount of product produced will increase as well. When the concentration of reactants decreases, the number of collisions decreases, and the amount of product produced decreases.

To summarize, the response to a temperature change as a stress in a chemical reaction is different from the response to a change in concentration because temperature affects the rate of the reaction, while concentration affects the amount of reactants and products.

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the rate constant of a certain first order reaction is 45.9s^-1 at 300k. what is the value of the rate constant at 310.0 k? the energy of activation is 81.0 kj/mol?

Answers

Answer: The value of the rate constant at 310.0 K is 54.90 s^-1.




The Arrhenius equation is used to calculate the rate constant of a reaction. It provides a way to relate the temperature of a system to the rate constant of a reaction.

Given the rate constant of a certain first-order reaction, which is 45.9 s^-1 at 300 K, and the energy of activation of 81.0 kJ/mol, we have to calculate the rate constant at 310.0 K.

What is the Arrhenius equation?

The Arrhenius equation is given by: k = Ae^(-Ea/RT)

where: k is the rate constant of the reaction, A is the pre-exponential factor or the frequency factor, Ea is the activation energy, R is the universal gas constant (8.314 J/mol K) T is the temperature in kelvin.

From the given information: k1 = 45.9 s^-1, T1 = 300 K, T2 = 310 K, and Ea = 81.0 kJ/molCalculating the rate constant at 310.0 K using the Arrhenius equation:

k2 = Ae^(-Ea/RT2)

Taking the ratio of the two equations:

k2/k1 = (Ae^(-Ea/RT2))/(Ae^(-Ea/RT1)) k2/k1 = e^(Ea/R) (1/T1 - 1/T2)

Putting in the values:

k2/45.9

= e^ (81000/8.314) (1/300 - 1/310) k2/45.9

= 1.196k2

= 54.90 s^-1

Therefore, the value of the rate constant at 310.0 K is 54.90 s^-1.



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a 20.0 g piece of a metal with specific heat of 0.900 j/g.0c at 98.0 0c dropped into 50.0 g water in a calorimeter at 20.0 0c. the specific heat of water is 4.18 j/g.0c calculate the final equilibrium temperature of the mixture group of answer choices

Answers

The final equilibrium temperature of the mixture will be 40.5°C. Option A is correct.

To calculate the final equilibrium temperature of the mixture, we need to use the principle of conservation of energy, which states that the total energy of a closed system remains constant. In this case, the initial energy of the metal at 98.0°C is transferred to the water and calorimeter, raising their temperature until they reach a final equilibrium temperature.

We can use the following equation to calculate the final equilibrium temperature ([tex]T_{f}[/tex]) of the mixture:

m₁c₁(T₁ - [tex]T_{f}[/tex]) = m₂c₂([tex]T_{f}[/tex] - T₂)

where m₁ and c₁ are the mass and specific heat of the metal, T₁ is the initial temperature of the metal, m₂ and c₂ are the mass and specific heat of the water, and T₂ is the initial temperature of the water.

Substituting the given values, we get:

(20.0 g)(0.900 J/g°C)(98.0°C - [tex]T_{f}[/tex]) = (50.0 g)(4.18 J/g°C)([tex]T_{f}[/tex] - 20.0°C)

Simplifying and solving for [tex]T_{f}[/tex], we get:

1764 - 18[tex]T_{f}[/tex] = 2090[tex]T_{f}[/tex] - 83600

2108[tex]T_{f}[/tex] = 85364

[tex]T_{f}[/tex] = 40.5°C

Hence, A. 40.5°C is the correct option.

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--The given question is incomplete, the complete question is

"A 20.0 g piece of a metal with specific heat of 0.900 j/g.0c at 98.0 0c dropped into 50.0 g water in a calorimeter at 20.0 0c. the specific heat of water is 4.18 j/g.0c calculate the final equilibrium temperature of the mixture group of answer choices: A) 40.5°C. B) 48.9°C. C) 36.7°C. D) 45.5°C."--

Give two reasons why meteorological seasons were needed?

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The four traditional meteorological seasons, which are based on the annual temperature cycle and the location of the Earth in its orbit around the sun, split the year into four seasons of three months each. The following describes these seasons:

Spring: March, April, MaySummer: June, July, AugustFall (or Autumn): September, October, NovemberWinter: December, January, February

Here are two reasons why meteorological seasons were needed:

Consistency: Based on the annual temperature cycle, meteorological seasons offer a consistent method of dividing the year into four separate times. This makes it simple to compare weather patterns from one year to the next and to monitor long-term weather pattern changes over time.

Ease of communication: By dividing the year into four seasons based on set calendrer months, it is simpler for people to discuss the weather and make appropriate plans for their daily activities. Because January falls within the winter season according to the meteorological calendar, it is simple to know what kind of weather to anticipate when someone states, "I'm going skiing in January."

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Ion channels are classified as membrane transport proteins. Channels discriminate by size and charge. In addition to Na+, which one of the following ions would you expect to be able to freely diffuse through a Na+ channel?
a) Mg2+
b) H+
c) K+
d) Cl-

Answers

Ion channels are classified as membrane transport proteins. Channels discriminate by size and charge.  

What are transport membrane proteins?

Transport membrane proteins are proteins that aid in the movement of molecules across the membrane. These transport membrane proteins come in various forms and serve various functions, including regulating molecules' passage. As a result, they play a vital role in cell homeostasis.

What are ion channels?

Ion channels are pore-forming proteins found in the membranes of all cells, which facilitate the diffusion of ions down their electrochemical gradient across the plasma membrane.

What is diffusion?

Diffusion is the random movement of particles from an area of higher concentration to an area of lower concentration. It is the primary mechanism of particle transport in cells.

How does ion diffusion work?

Ion diffusion is a type of passive transport that occurs spontaneously down an electrochemical gradient, from an area of high concentration to an area of low concentration, through a semipermeable membrane. It is facilitated by ion channels, which are membrane transport proteins that allow ions to move across the plasma membrane down their electrochemical gradient.

The charge and size of the ion channels determine the molecules that can pass through the membrane via these channels. Small ions like Na+ and K+ can pass through the ion channels easily, while larger ions cannot.

Na+ channels also permit the passage of K+ ions but not Mg2+ or Cl-.

Therefore, in addition to Na+, K+ is expected to freely diffuse through Na+ channels.

Answer: c) K+.

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if 3.43 mol 3.43 mol of an ideal gas has a pressure of 2.17 atm 2.17 atm and a volume of 68.83 l, 68.83 l, what is the temperature of the sample in degrees celsius?

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The temperature of the sample in degrees Celsius is 257.5 °C.

The temperature of the sample can be calculated using the ideal gas law, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature.

In this case, P = 2.17 atm, V = 68.83 L, n = 3.43 mol, and R = 0.08206 L atm mol-1 K-1.

Rearranging the equation will give us the equation for the temperature, T.

T = PV/nR

Pugging in the values, we get:

T = (2.17 atm)(68.83 L) / (3.43 mol)(0.08206 L atm/mol K)

T = 530.65 K

Converting Kelvin to degree Celcius, we have:

T = 530.65 - 273.15 = 257.5 °C

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Question: Why Are The Properties Of Diamond And Graphite Different, Even Though They Are Both Composed Of Pure Carbon? Select The Two Answers That Explain This Difference. Group Of Answer Choices The Atoms In Diamond And Graphite Have Different Hybridizations. The Bonding In Diamond Can Be Modeled With Valence Bond Theory Whereas The Bonding In Graphite Can Only Be
Why are the properties of diamond and graphite different, even though they are both composed of pure carbon? Select the two answers that explain this difference.
Group of answer choices
The atoms in diamond and graphite have different hybridizations.
The bonding in diamond can be modeled with Valence Bond Theory whereas the bonding in graphite can only be modeled with Molecular Orbital Theory.
The bonding in diamond and graphite are different.
The atoms in diamond and graphite are different isotopes of carbon.

Answers

The correct answer is option a. and option c.

The properties of diamond and graphite are different, even though they are both composed of pure carbon because the atoms in diamond and graphite have different hybridizations and the bonding in diamond and graphite is different.

In diamonds, carbon atoms are sp3 hybridized, forming a tetrahedral structure with strong covalent bonds, making it hard and rigid. In graphite, carbon atoms are sp2 hybridized, forming planar hexagonal layers with weaker van der Waals forces between the layers, making it soft and slippery.



The bonding in diamond is composed of strong covalent bonds, while in graphite, there are strong covalent bonds within the layers and weaker van der Waals forces between the layers. This difference in bonding leads to the distinct properties of each allotrope.

We can say that the properties of diamond and graphite are different because they have different hybridisation and bonding.

Therefore option a and option c are correct.

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if a zero order reaction has a half-life of 350 s when the initial reactant concentration is 1.50 m, how long until 0.1% of the reactant remains?

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It will take 3401 seconds for 0.1% of the reactant to remain.  

The half-life of a zero-order reaction is the time taken for the concentration of the reactant to decrease by half. This can be calculated using the equation:


t1/2 = 0.693/k


Where k is the rate constant of the reaction. The amount of time it takes for 0.1% of the reactant to remain, we can use the following equation:


t = (-log(0.001))/k


The rate constant of the reaction can be calculated as:


k = 0.693/t1/2 = 0.693/350 = 0.001988  


t = (-log(0.001))/k = (-log(0.001))/0.001988 = 3401 seconds  


Therefore, it will take 3401 seconds for 0.1% of the reactant to remain.  

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what is the relationship between intermolecular forces of attraction and the solubility of a compound in a solvent?

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The relationship between intermolecular forces of attraction and the solubility of a compound in a solvent is that the stronger the intermolecular forces of attraction, the greater the solubility in a given solvent.

Intermolecular forces are forces of attraction that exist between molecules, which allow them to interact and combine in various ways. The strength of intermolecular forces has a significant impact on a substance's properties, such as boiling and melting points, as well as its solubility in various solvents.

When two substances with different intermolecular forces are mixed together, the weaker substance is typically dissolved by the stronger one. Polar solvents, for example, can dissolve polar solutes because the forces between the molecules are comparable.The polar water molecules will surround and dissolve other polar molecules, such as sodium chloride or table salt, because they are attracted to the polar charges on the molecule. When nonpolar solvents, such as hexane, are added to a polar compound, it is the opposite. The polar compound would not dissolve because the intermolecular forces are not compatible.

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Which of the following weak acids would cause the greatest decrease in pH ? Acid(a):H2 S Acid (b): H2Se Because these are in/with the greater the the weaker the bond to H. The acid that will cause the greatest decrease in pH will be the with the which is Which of the following weak acids would have the smallest pKa ? Acid (a): H2 S Acid (b): H3P Because these are in/with , the greater the the weaker the bond to H. The acid with the smallest p Ka will be the with the which is

Answers

1. The acid that will cause the greatest decrease in pH will be H₂Se

2. The acid with the smallest pKa is Acid (b): H₃P.

What is pH?

The H+ ion concentration's negative constant is known as pH. As a result, the meaning of pH is validated as the strength of hydrogen.

1. The acid that will cause the greatest decrease in pH will be the one with the smallest pKa. This is because the smaller the pKa, the stronger the acid. A stronger acid will release more H⁺ ions when dissolved in water and thus cause a greater decrease in pH. So, the correct option is b. H₂Se will have greatest decrease in pH.

2. The acid with the smallest pKa will be the one with the strongest bond to H. This is because the stronger the bond to H, the weaker the acid. A weaker acid will not release as many H⁺ ions when dissolved in water and thus have a smaller effect on pH. Therefore, the acid with the smallest pKa is Acid (b): H₃P.

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which compound(s) can be used at high concentrations to dampen out electrostatic interactions among amino acid residues?

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The compound(s) that can be used at high concentrations to dampen out electrostatic interactions among amino acid residues are usually small neutral molecules such as glycerol, acetic acid, and ethylene glycol.

Electrostatic interactions between amino acid residues are often stabilized by hydrogen bonds and other covalent interactions. These interactions are sensitive to the surrounding environment and can be disrupted or dampened when exposed to compounds at high concentrations. Small neutral molecules, such as glycerol, acetic acid, and ethylene glycol, can effectively dampen out electrostatic interactions between amino acid residues, allowing them to retain their native conformation.

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the complex process whereby silicate minerals such as feldspar are broken down to make clay minerals by reacting with water molecules is .

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The complex process whereby silicate minerals such as feldspar are broken down to make clay minerals by reacting with water molecules is known as hydrolysis.

Hydrolysis is the process of breaking down a compound by adding water to it. It is a chemical process in which water reacts with minerals to form new compounds with new structures. The process is a crucial part of the formation of clay minerals. Hydrolysis is a common process in nature and occurs when water reacts with minerals to form new compounds. This reaction occurs in soil, rocks, and other natural materials.

The hydrolysis process breaks down minerals such as feldspar and releases other minerals like aluminum and iron oxides. The hydrolysis of silicate minerals such as feldspar creates clay minerals. This process is responsible for the formation of clay minerals, which are an important component of soil.

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what volume of 0.415 m silver nitrate will be required to precipitate as silver bromide all the romide in 35.0 ml of 0.128 m calcium bromide?

Answers

The volume of 0.415 M silver nitrate needed to precipitate all the bromide in 35.0 mL of 0.128 M calcium bromide is 5.41 mL.

There are different ways to approach stoichiometry problems, but one common method is to use the balanced chemical equation, the molar ratios, and the concentration-volume relationships.

The balanced chemical equation for the precipitation reaction between silver nitrate and calcium bromide:AgNO3(aq) + CaBr2(aq) → AgBr(s) + Ca(NO3)2(aq)

Determine the limiting reactant and the theoretical yield of silver bromide.

Use the molar mass of AgBr to convert its moles to grams or volume of the precipitate.

The moles of calcium bromide:moles of CaBr2 = concentration × volume (in liters)moles of CaBr2 = 0.128 mol/L × 0.035 Lmoles of CaBr2 = 0.00448 mol

Use the molar ratio between CaBr2 and AgNO3 to find the moles of AgNO3 needed to react with all the bromide ions.

moles of AgNO3 = moles of CaBr2 × (1 mol AgNO3/1 mol CaBr2)moles of AgNO3 = 0.00448 mol × (1 mol AgNO3/2 mol Br-)moles of AgNO3 = 0.00224 mol

Since the stoichiometry of the reaction is 1:1 for AgBr and AgNO3, the theoretical yield of AgBr is also 0.00224 mol.

The volume of 0.415 M AgNO3 needed to provide the theoretical yield of AgBr.

Use the concentration-volume relationship to find the volume of AgNO3 that contains the same amount of moles as the theoretical yield of AgBr.

Moles of AgNO3 = 0.00224 molvolume of AgNO3 = moles of AgNO3/concentration of AgNO3volume of AgNO3 = 0.00224 mol/0.415 mol/Lvolume of AgNO3 = 0.00541 L or 5.41 mL

Therefore, the volume of 0.415 M silver nitrate needed to precipitate all the bromide in 35.0 mL of 0.128 M calcium bromide is 5.41 mL.

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which of the following most favors elimination rather substitution in a reaction with 2-bromopropane? question 6 options: sodium methoxide sodium ethoxide sodium isoproxide sodium tert-butoxide

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The best choice to favor elimination over substitution in a reaction with 2-bromopropane is sodium tert-butoxide. This is because this reagent is a stronger base, allowing for the deprotonation of 2-bromopropane.

The reaction of 2-bromopropane most favors elimination over substitution when reacted with the sodium tert-butoxide favors elimination over substitution in a reaction with 2-bromopropane.

In organic chemistry, substitution reaction occurs when an atom or a group of atoms in a molecule is replaced by another atom or a group of atoms. In contrast, elimination reactions occur when atoms or groups of atoms are removed from a molecule. The most significant difference between the two is that one leaves another behind. This means that if one group is substituted by another, then it results in a completely different compound than before.

In the reaction between 2-bromopropane and sodium tert-butoxide, the sodium tert-butoxide (Na + OC(CH3)3) serves as a strong base. The tert-butoxide ion, as a strong base, abstracts a hydrogen ion from a carbon adjacent to the bromine, leading to the formation of a reactive alkene intermediate.

The elimination of HBr from 2-bromopropane to form propene is made possible by this alkene intermediate. Therefore, the reaction most favors elimination over substitution when reacted with sodium tert-butoxide.

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a solution is made using 400.0 ml of phenol (density 1.070 g/ml) and 1217.9 ml of water (density 1.000 g/ml). what is the mass percent of the phenol?

Answers

The mass percent of phenol in the solution is 26.01%.

To calculate the mass percent of phenol in the solution, we need to know the total mass of the solution and the mass of phenol in the solution.

The mass of phenol in the solution can be calculated as follows:

mass of phenol=volume of phenol x density of phenol

mass of phenol = 400.0 ml x 1.070 g/ml

mass of phenol = 428.0 g

The total mass of the solution can be calculated by adding the mass of phenol and the mass of water:

total mass of solution = mass of phenol + mass of water

total mass of solution = 428.0 g + (1217.9 ml x 1.000 g/ml)

total mass of solution = 1645.9 g

Now we can calculate the mass percent of phenol in the solution:

mass percent of phenol = (mass of phenol / total mass of solution) x 100%

mass percent of phenol = (428.0 g / 1645.9 g) x 100%

mass percent of phenol = 26.01%

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a 175.0 ml solution of 2.594 m strontium nitrate is mixed with 215.0 ml of a 3.162 m sodium fluoride solution. calculate the mass of the resulting strontium fluoride precipitate.

Answers

The mass of the resulting strontium fluoride precipitate is 42.40 grams if a 175.0 ml solution of 2.594 m strontium nitrate is mixed with 215.0 ml of a 3.162 m sodium fluoride solution.

Volume of 2.594 M strontium nitrate = 175.0 mL = 0.175 L

Volume of  3.162 M sodium fluoride = 215.0 mL = 0.215 L

The Molar mass of SrF2 is 125.62 g/mole

Step 2: The balanced equation:

Sr(NO3)2(aq.) + 2NaF(aq.) → SrF2(s) + 2NaNO3(aq.)

From the balanced equation we know that, SrF2 will precipitate, NaNO3 will dissociate in 2Na+ + 2NO3-

The moles Sr(NO3)2 = molarity * volume

Moles Sr(NO3)2 is,

                     =  3.162 M * 0.175 L

                     = 0.553 moles

We have to calculate moles Na F.

moles Na F is,

              = 3.162 M * 0.215 L

              = 0.679 moles

We get that for 1 mole of Sr(NO3)2 we need 2 moles of Na F to produce 1 mole of SrF2 and 2 moles of NaNO3. here Na F is the limiting reactant.

There will Sr(NO3)2 is in excess react 0.553/2 = 0.276 moles which will precipitate.

There will remain 0.553 - 0.276 = 0.277 moles that will not precipitate.

Now we have to calculate moles of SrF2 produced. For 1 mole of Sr(NO3)2 we need 2 moles of Na F to produce 1 mole of SrF2 and 2 moles of NaNO3.

For 0.679 moles of Na F consumed, we produced 0.679/2 = 0.3375 moles of SrF2

Now we have to calculate mass of SrF2 produced

Mass SrF2 = moles SrF2 * molar mass SrF2

Mass SrF2 = 0.3375 moles * 125.62 g/mole

Mass SrF2 = 42.40 grams

The mass of the resulting strontium fluoride precipitate is 42.40 grams.

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a gas has a volume of 91 ml at a temperature of 91oc. what is the volume of the gas if the temperature is reduced to 0oc at constant pressure?

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If the temperature of the gas is reduced from 91°C to 0°C at constant pressure, the volume of the gas will decrease from 91 ml to 68.5 ml.

A gas has a volume of 91 ml at a temperature of 91°C. Use the combined gas law, which is a variation of the ideal gas law that holds pressure constant while allowing for changes in volume and temperature.

V1/T1 = V2/T2P = constant

Where V1 is the initial volume of the gas, T1 is the initial temperature of the gas, V2 is the final volume of the gas, T2 is the final temperature of the gas, and P is the constant pressure that the gas is held at.

We'll begin by plugging in the values that we know. V1 = 91 ml, T1 = 91°C, P = constant, V2 = ?, T2 = 0°C.

We can simplify the temperature values by converting them to Kelvin, since Kelvin is the temperature scale that is used in the gas laws. To convert Celsius to Kelvin, we simply add 273 to the Celsius value.

T1 = 91°C + 273 = 364 KT2 = 0°C + 273 = 273 KNow we can plug in the values and solve for V2. V1/T1 = V2/T2(91 ml)/(364 K) = V2/(273 K)Simplifying this equation, we get:V2 = (91 ml)(273 K)/(364 K)V2 = 68.5 ml

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if the equillibrium is established by beginning with equal number of moles of So2 and O2 what must be true at equillibrium

Answers

Explanation:

the reaction being referred to is the one where sulfur dioxide (SO2) and oxygen (O2) react to form sulfur trioxide (SO3) according to the following balanced equation:

2 SO2(g) + O2(g) ⇌ 2 SO3(g)

If the equilibrium is established by beginning with equal numbers of moles of SO2 and O2, i.e., if the initial molar amounts of SO2 and O2 are the same, then we can conclude the following at equilibrium:

The rate of the forward reaction (2 SO2(g) + O2(g) → 2 SO3(g)) is equal to the rate of the reverse reaction (2 SO3(g) → 2 SO2(g) + O2(g)).

The concentrations of SO2, O2, and SO3 will remain constant over time.

The amounts of SO2, O2, and SO3 present at equilibrium will depend on the temperature, pressure, and other conditions of the system.

The value of the equilibrium constant (Kc) for the reaction will have a specific numerical value at equilibrium, which will depend on the temperature and other conditions of the system.

The value of the reaction quotient (Qc) for the reaction will be equal to the equilibrium constant (Kc) at equilibrium, indicating that the system is at equilibrium

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The specific heat capacity of liquid water is 4.184 J/goC

Calculate the energy (in kJ) required to heat 25 g of liquid water from 25oC to 100 oC

Answers

Explanation:

25 g   *   (100 - 25 ) C  *  4.184  J / (g C)  = 7845 J

What salt would be produced by the reaction of H2SO4 with LiHCO3? a) Li2S b) LiSO4
c) Li2SO4 d) Li2CO3

Answers

The salt that would be produced by the reaction of H2SO4 with LiHCO3 is option C-Li2SO4.

Lithium sulfate (Li2SO4) is an inorganic compound with the formula Li2SO4. It is a white crystalline material that is soluble in water. The salt would be produced as a result of the following reaction: H2SO4 + LiHCO3 → Li2SO4 + H2O + CO2.

Lithium carbonate (Li2CO3) would not be produced in this reaction because LiHCO3 reacts with H2SO4 to form Li2SO4. Li2S cannot be produced because it requires Li2S2, which is not one of the reactants or products. LiSO4 is not produced because H2SO4 reacts with LiHCO3 to form Li2SO4 instead. Thus, option (c) Li2SO4 is the correct answer.

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benefits/advantages of friedel crafts acylation reactions as compared to friedel crafts alkylation reactions?

Answers

Friedel crafts acylation is preferred over Friedel craft alkylation. Friedel crafts acylation reactions have many benefits as compared to Friedel crafts alkylation reactions.

Friedel-Crafts acylation and Friedel-Crafts alkylation reactions are both types of electrophilic substitution reactions that involve the formation of carbocations as intermediates. However, acylation is preferred over alkylation in certain situations.

Here are some benefits of Friedel-Crafts acylation reactions compared to Friedel-Crafts alkylation reactions:

1. Friedel-Crafts acylation reactions produce pure compounds as their major products because they do not involve any byproducts like Friedel-Crafts alkylation reactions.

2. The yields of Friedel-Crafts acylation reactions are often higher than those of Friedel-Crafts alkylation reactions.

3. Friedel-Crafts acylation reactions are more selective than Friedel-Crafts alkylation reactions because the acyl group is a better electrophile than the alkyl group.

4. The carbonyl group in the acylating agent (usually an acid chloride) can be selectively protected or modified using a variety of functional groups without affecting the aromatic ring. This is not possible in Friedel-Crafts alkylation reactions.

5. Friedel-Crafts acylation reactions can be carried out with a wider range of substrates (such as anisole or benzene) than Friedel-Crafts alkylation reactions.

6. The products of Friedel-Crafts acylation reactions are often more reactive than the starting materials, which allows for further functionalization or modification of the aromatic ring.

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How many liters in 9.87 moles of 0^3

Answers

The volume (in liters) in which 9.87 moles of ozone, O₃ can occupy is 221.09 liters

How do i determine the volume?

From the question given above, the following data were obtained:

Number of mole of ozone, O₃ = 9.87 molesVolume of ozone, O₃ =?

The volume of 9.87 moles of ozone, O₃ can be obtained as illustrated below:

From the ideal gas theory, we understood that:

1 mole of ozone, O₃ = 22.4 Liters

Therefore,

9.87 moles of ozone, O₃ = (9.87 moles × 22.4 Liters) / 1 mole

9.87 moles of ozone, O₃ = 221.09 liters

Thus, we can conclude that the volume is 221.09 liters

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49.2 ml of a 0.524 m solution of hno3 is titrated with fe(oh)3. it takes 85 ml of fe(oh)3 to reach the equivalence point. what is the concentration (molarity) of the fe(oh)3? answer to 2 decimal places

Answers

The Fe(OH)₃ solution has a content of 0.304 M.

In this titration, HNO₃ is the acid and Fe(OH)₃ is the base. At the equivalence point, all the H+ ions from the HNO₃ react with all the OH- ions from the Fe(OH)₃ to form water and the salt, Fe(NO₃)₃. We can use the balanced chemical equation for the reaction to determine the stoichiometric ratio of HNO₃ to Fe(OH)₃ and calculate the molarity of Fe(OH)₃.

The balanced chemical equation for the reaction is:

HNO₃ + 3Fe(OH)₃ → Fe(NO₃)₃ + 3H₂O

From the equation, we see that 1 mole of HNO₃ reacts with 3 moles of Fe(OH)₃. Therefore, the number of moles of HNO₃ in the solution can be calculated as:

moles of HNO₃ = Molarity of HNO₃ x Volume of HNO₃ solution in liters

moles of HNO₃ = 0.524 M x (49.2 mL / 1000 mL/L)

moles of HNO₃ = 0.0258 mol

At the equivalence point, the number of moles of Fe(OH)₃ added is equal to the number of moles of HNO₃ in the solution. Therefore, we can calculate the molarity of Fe(OH)₃ as:

Molarity of Fe(OH)₃ = moles of Fe(OH)₃ added / Volume of Fe(OH)₃ solution in liters

Since the volume of the Fe(OH)₃ solution added is 85 mL, or 0.085 L, we can calculate the moles of Fe(OH)₃ as:

moles of Fe(OH)₃ = moles of HNO₃ = 0.0258 mol

Therefore, the molarity of Fe(OH)₃ is

Molarity of Fe(OH)₃ = 0.0258 mol / 0.085 L

Molarity of Fe(OH)₃ = 0.304 M

Thus, the concentration (molarity) of the Fe(OH)₃ solution is 0.304 M, rounded to two decimal places.

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if 7.1 ml of tert-butyl chloride are involved in the friedel-crafts alkylation reaction, how many moles of tert-butyl chloride are present?

Answers

The moles of tertiary-butyl chloride present are 0.065 moles.

To calculate the number of moles of tert-butyl chloride involved in Friedel-Crafts alkylation, we will use the following formula:

Number of moles = Mass / Molar mass

The molar mass of tert-butyl chloride = 92.57 g/mol

The volume of tert-butyl chloride = 7.1 ml

Using the density of tertiary-butyl chloride, we can convert the volume into mass.

The density of tertiary-butyl chloride is 0.853 g/ml.

Therefore, Mass of tert-butyl chloride = 7.1 ml × 0.853 g/ml = 6.05g

Substituting the values in the formula:

The number of moles = 6.05 g / 92.57 g/mol= 0.065 moles

Therefore, 0.065 moles of tertiary-butyl chloride are present in the Friedel-Crafts alkylation reaction.

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which statement is true a-in a reaction, oxidation can occur independently of reduction b-a redox reaction involves either the transfer of an electron or a change in oxidation state of an element c-if any of the reactants or products in a reaction contain oxygen the reaction is a redox reaction d- the reducing agent reduces another substance and is itself oxidized

Answers

The correct statement is option B - A redox reaction involves either the transfer of an electron or a change in oxidation state of an element.Redox reactions involve the transfer of electrons from one substance to another.

The term "redox" refers to the simultaneous oxidation and reduction of molecules in the reaction, with one molecule losing electrons and the other gaining electrons.

Redox reactions is:Oxidation: Loss of electronsReduction: Gain of electrons. A molecule or atom that loses electrons is said to be oxidized, while one that gains electrons is said to be reduced.

The oxidized substance is an oxidizing agent, while the reduced substance is a reducing agent.

The statement "A redox reaction involves either the transfer of an electron or a change in oxidation state of an element" is true as the redox reaction involves both reduction and oxidation reactions.

Any substance that is oxidized should be reduced by another substance, and vice versa. Thus, a redox reaction involves the transfer of electrons from one substance to another.

Although oxygen is often present in redox reactions, it is not a necessary component of them. So, the statement C is false, and oxidation can not occur independently of reduction, so the statement A is false too.

The reducing agent reduces another substance and is itself oxidized; thus, statement D is also true.

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when the temperature of a rigid hollowsphere containing 685 l of helium gasis held to 621 k, the pressure of the gasis 1 kpa. how many moles ofhelium does the sphere contain?

Answers

Answer:

610 k because is the hollwsphere is the gasis and 1 kpa of helium

How does matter, such as carbon, move through an environment?

Answers

Carbon and other types of matter can move through the environment through a combination of physical, biological, and human processes.

How does matter, such as carbon, move through an environment?

Matter, including carbon, can move through an environment in several ways, including:

Diffusion: Diffusion is the movement of particles from an area of high concentration to an area of low concentration. Carbon can diffuse through the air or water from areas where it is more concentrated to areas where it is less concentrated.

Advection: Advection is the movement of matter due to the flow of a fluid, such as air or water. Carbon can be transported through the environment by advection, for example, by wind carrying carbon particles or by water currents transporting dissolved carbon.

Biogeochemical cycling: Carbon can also be cycled through the environment by biological and geological processes. Plants and algae take up carbon dioxide from the air or dissolved carbon from water and convert it into organic matter through photosynthesis. This organic matter can then be consumed by other organisms, leading to the transfer of carbon through the food chain. Carbon can also be stored in soils and sediments for long periods of time.

Human activities: Human activities can also move carbon through the environment. For example, the burning of fossil fuels releases carbon dioxide into the atmosphere, which can then be transported by diffusion and advection. Land-use changes, such as deforestation, can also affect the cycling of carbon through the environment.

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which of following statement does not describe the saturated liquid if heat is added to it? multiple choice question. it's about to condense. it is about to vaporize. it refers to a point on a t-v diagram. it's still considered a liquid. any heat added will cause some of the liquid to vaporize.

Answers

It is about to vaporize does not describe the saturated liquid if heat is added to it. Here option B is the correct answer.

A saturated liquid is a liquid that is in equilibrium with its vapor at a given temperature and pressure. If heat is added to a saturated liquid, its temperature will increase while its pressure remains constant until it reaches the saturation temperature. At this point, the saturated liquid will start to vaporize or boil, and the temperature will remain constant until all of the liquid has been converted to vapor.

Option A - "it's about to condense" - is true for a saturated vapor if heat is removed from it. Option C - "it refers to a point on a t-v diagram" - is also true since a saturated liquid corresponds to a point on the liquid-vapor saturation line on a temperature-volume (t-v) diagram.

Option D - "it's still considered a liquid" - is true since the saturated liquid is still in the liquid state even though it is about to vaporize. Option E - "any heat added will cause some of the liquid to vaporize" - is true since any additional heat added to a saturated liquid will cause it to vaporize or boil at a constant temperature and pressure.

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Complete question:

Which of the following statement does not describe the saturated liquid if heat is added to it? multiple choice questions.

A - it's about to condense.

B - it is about to vaporize.

C - it refers to a point on a t-v diagram.

D - it's still considered a liquid.

E - any heat added will cause some of the liquid to vaporize.

generally only the carbonates of the group 1 elements and the ammonium ion are soluble in water; most other carbonates are insoluble. how many milli- liters of 0.125 m sodium carbonate solution would be needed to precipitate the calcium ion from 37.2 ml of 0.105 m cacl2 solution?

Answers

The volume of the sodium carbonate needed to precipitate is 31.248 ml. This is calculated using the dilution formula.

The molarity of the solution and the volume of the first solution can be correlated with the molarity and the volume of diluted solution. It is called as dilution formula.

Molar concentration is the another term for molarity. Molarity is a measure of the concentration of a chemical species in particular of a solute in a solution in terms of amount of substance per unit volume of solution.

The expression for molarity of the solution is,

M1 V1 = M2 V2

here we have 0.125 m sodium carbonate solution would be needed to precipitate the calcium ion from 37.2 ml of 0.105 m cacl2 solution.  

putting all the values we get,

0.105 * 37.2 = 0.125 * V2

V2 = 31.248

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what happens to the rate if the concentration of chlorocyclopentane is tripled and the concentration of sodium hydroxide reamins the same

Answers

The rate of the reaction between chlorocyclopentane and sodium hydroxide will increase when the concentration of chlorocyclopentane is tripled and the concentration of sodium hydroxide remains the same.

This is due to the fact that increasing the concentration of a reactant increases the frequency of collisions between particles of the reactants, resulting in a higher reaction rate.

When a reactant's concentration is increased, the number of molecules or atoms per unit volume also increases. As a result, the frequency of collisions between the reactant particles increases.

The greater the frequency of collisions between the reactant particles, the greater the chance of a successful reaction, thus increasing the reaction rate.

When the concentration of one of the reactants is increased and the concentration of the other reactant remains the same, the reaction rate increases.

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what is the ph of a 0.138m solution of h3po4 (assume complete dissociation for the sake of the example)?

Answers

Answer: The pH of a 0.138 M solution of H3PO4 (assuming complete dissociation for the sake of the example) is 1.49.

The following steps can be used to determine the pH of the solution.

Phosphoric acid is a triprotic acid, which means that it can donate three hydrogen ions (H+) to a solution. Phosphoric acid's first dissociation reaction is as follows:

H3PO4(aq) → H+(aq) + H2PO4-(aq) This means that in water, H3PO4 will donate one hydrogen ion (H+) to the solution, leaving behind the negatively charged H2PO4- ion.

To determine the pH of the solution, we can use the formula:

pH = -log[H+]

First, we need to determine the concentration of H+ ions in the solution, which we can find from the dissociation of H3PO4. H3PO4(aq) → H+(aq) + H2PO4-(aq) Initially, the concentration of H3PO4 is 0.138 M. Since we're assuming complete dissociation for the sake of this example, we can say that 100% of the H3PO4 dissociates into H+ and H2PO4-.

This means that the concentration of H+ in the solution is equal to the initial concentration of H3PO4:0.138 MWe can now substitute this value into the pH formula:

pH = -log[H+]pH = -log[0.138]pH = 1.49

Therefore, the pH of the 0.138 M solution of H3PO4 (assuming complete dissociation for the sake of the example) is 1.49.



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