WILL GIVE BRAINLEST!!! What is the magnification of a virtual image if the image is 10.0 cm from a mirror and the object is 20.0 cm from the mirror?

a. -2.0
b. 0.50
c. 2.0
d. -0.50

Answer:

126 / 2 = 63 = angle between one rope and the direction of the resultant force

t = F cos 73 = .45 F      force on stump due to one horse

T = 2 t = .90 F       force on stump due to both horses - T would be the resultant of the two horses each pulling with force F

1. Resistance is the opposition offered in a path of flow of current by the atoms or molecules of the conductor.

Factors on which resistance of a conductor depends are:

2. Rheostat is used to change the resistance without changing the voltage source in an electric circuit.

3.

Given :

[tex]\dashrightarrow l = 50 m[/tex]

[tex]\dashrightarrow A = 0.01 {mm}^{2} [/tex]

[tex]\dashrightarrow A = 0.01 \times {10}^{ - 6} \: {m}^{2} [/tex]

[tex]\dashrightarrow \rho = 5 \times {10}^{ - 8} \: \Omega \: m[/tex]

We know that,

[tex] \dashrightarrow R = \rho \dfrac{l}{A}[/tex]

[tex] \dashrightarrow R = 5 \times {10}^{ - 8} \bigg(\dfrac{50}{0.01 \times {10}^{ - 6} } \bigg)[/tex]

[tex] \dashrightarrow { \pink{ \underline{ R = 250 \: \Omega }}}[/tex]

The resistance of a conductor is the opposition to the flow of current and depends on the length and area of the material

Resistance is the opposition to the flow of current by the atoms or molecules of the conductor.

The factors on which resistance of a conductor depends are:

A Rheostat is the device used to change the resistance without changing the voltage source in an electric circuit.

The resistanceis given as:

Area = 0.01 square mm = 1.0 × 10^-8 square m

R = (50 × 5 ×10 ^-8 ohm m)/1.0 × 10^-8 square m

Resistance = 250 ohm

Therefore, resistance of a conductor is the opposition to the flow of current.

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In a circuit, if the resistors were decreased by a factor of 1,000, it is true that the current would increase by a factor of 1,000, according to Ohm's Law.

It is a law in electricity that posits that the voltage that goes through a conductor is directly proportional to the current.

One formula in Ohm's law is:

Voltage = Current x Resistance

If the resistance were to decrease by a factor of 1,000, the current would have to increase by a factor of 1,000 as well in order to give the same voltage.

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For a mass m1 on the frictionless table, the speed m1 must rotate a with radius r if m2 is to remain hanging at rest is mathematically given as

[tex]v=\sqrt{m1/m2*xg}[/tex]

Generally, the equation for the Force  is mathematically given as

Fc=Fw

Therefore

[tex]\frac{m1v1}{x}=m2g[/tex]

[tex]v=\sqrt{m1/m2*xg}[/tex]

In conclusion,  if m2 is to remain hanging at rest the speed of ratio of m1 is calcuylated using

[tex]v=\sqrt{m1/m2*xg}[/tex]

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The value of the velocity for the mass m₁ on the frictionless table will be [tex]\rm v = \sqrt{\frac{m_1}{m_2 xg} }[/tex]. Velocity is a time-based component. Its unit is m/sec.

The change of distance with respect to time is defined as speed. Speed is a scalar quantity.

The given data in the problem is

m is the mass

g is the acceleration of free fall =10m/sec²

v is the velocity

From the balancing equation of force the centripetal force is equal to the weight;

[tex]\rm F_c= m_2 g \\\\ \rm \frac{m_1v_1^2}{x} = m_2 g \\\\ v= \sqrt{\frac{m_1}{m_2xg} } \\\\[/tex]

Hence the value of the velocity for the mass m₁ on the frictionless table will be [tex]\rm v = \sqrt{\frac{m_1}{m_2 xg} }[/tex].

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Hi there!

We can solve for the time constant using the following:
[tex]\tau = RC[/tex]

τ = Time Constant (s)
R = Resistance (Ω)
C = Capacitance (F)

Simply plug in the values. Remember that:
4.7 μF = 4.7 * 10⁻ ⁶ F = 0.0000047 F

22kΩ = 22 * 10³ Ω= 22000Ω

Solve:
[tex]\tau = 0.0000047 * 22000 = \boxed{0.1034 s}[/tex]

The electron energy does not depend on the focusing cylinder voltage because the magnetic field runs perpendicular to the electron's direction of movement.

A magnetic field is produced by moving negatively electric charges (electrons) which generate magnetic forces that are observable.

The negative electrons that orbit around atoms in a molecule generate small magnetic fields around such atoms.

According to Fleming's left-hand rule, the direction of a magnetic force acting on a current is perpendicular to the direction of the electric current and magnetic field.

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Because it exerts a force that's also parallel to the horizontal fields instead of in opposition to it, the final electron energy is unchanged by the focusing cylinder voltage.

An electron's energy is on the same scale (in the same range) as that of light. The lines in an element's spectrum represent changes in the energy of electrons within the element's atoms. Scientists have reached numerous conclusions regarding the behavior of electrons in atoms by studying these spectra.

Negative electrons orbiting around atoms in a molecule produce modest magnetic fields surrounding them.

The vector of a magnetic force that acts on a current is opposite to the axis of the electric current and magnetic fields, as per Fleming's left-hand rule.

Thus, because it exerts a force that's also parallel to the horizontal fields instead of in opposition to it, the final electron energy is unchanged by the focusing cylinder voltage.

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Answer:

Explanation:

w=F×S

F=mg

F =50×110

F=500N

S=0.1 m

W=500×0.1

W=50j

For A 100-cm long dipole is excited by a sinusoidally varying current with an amplitude i0=2 , the time average power radiated  is mathematically given as

P=0.1577w

Generally, the equation for the   is mathematically given as

[tex]\lambda =\frac{c}{f}[/tex]

Therefore

[tex]\lambda=\frac{3\times 10^{8}}{10^{6}}[/tex]

lambda=300m

In conclusion, for the power

[tex]P=40\pi^{2}(I_{0})^{2}(\frac{l}{\lambda})^{2}\\\\P=40* (3.14)^{2}\times6^{2} (\frac{1}{300})^{2}[/tex]

P=0.1577w

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The time-averaged power radiated by the dipole if the oscillating frequency is 150 MHz is 0.1577 w.

The distance between identical points (adjacent crests) in adjacent cycles of a waveform signal carried in space or down a wire is defined as the wavelength.

Given that the current is 2 amp, while the frequency is 150 MHz. Therefore, the wavelength can be written as,

[tex]\lambda = \dfrac cf = \dfrac{3 \times 10^8}{10^6} = 300\rm\ m[/tex]

Now, the power can be written as,

[tex]P=40 \pi^2 \times (I_o)^2 \times (\dfrac{l}{\lambda})^2\\\\P = 40 \times \pi ^2 \times 6^2 \times (\dfrac{1}{300})^2\\\\P = 0.1577\rm\ w[/tex]

Hence,  the time-average power radiated by the dipole if the oscillating frequency is 150 MHz is 0.1577 w.

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The time period of the simple pendulum is 2.4 seconds.

Given the data in the question;

Period is the time needed for a complete cycle of vibration to pass a given point.

Period of a pendulum is the of time needed for it to complete one full back-and-forth motion. It is the time required to for the pendulum to swing from leftmost point to rightmost point and back to leftmost point.

Now, if it took the pendulum [tex]1.2s[/tex] to swing from leftmost point to rightmost point, it will also take the pendulum [tex]1.2s[/tex] to swing back to its original position( leftmost point )

Hence,

[tex]T[/tex] = time taken to swing from leftmost to rightmost + time taken to swing from rightmost point to leftmost point.

[tex]T = 1.2s + 1.2s\\\\T = 2.4s[/tex]

Therefore, the time period of the simple pendulum is 2.4 seconds.

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Answer:

(B) Probably - Pitch will appear to be lower than the source

Pitch differences occur because of relative motions between the source and observer - it does not depend on distance measurements

Answer:

(B) Probably - Pitch will appear to be lower than the source

Pitch differences occur because of relative motions between the source and observer - it does not depend on distance measurements

Explanation:

The magnitude of the centripetal acceleration of the bicycle wheel is 40 m/s².

The centripetal acceleration of the bicycle wheel is the inward or radial acceleration of the bicycle on the circular path.

The magnitude of the centripetal acceleration of the bicycle wheel is calculated as follows;

a = ω²r

where;

ω is angular speed

r is the radius of the circular path

a = (10)² x 0.4

a = 40 m/s²

Thus, the magnitude of the centripetal acceleration of the bicycle wheel is 40 m/s².

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The acceleration of a body travelling in a circular route is known as centripetal acceleration.  The centripetal acceleration of the wheel at this time point is 40 m/sec².

The acceleration of a body travelling in a circular route is known as centripetal acceleration. It is given by the formula,

[tex]a_c = \dfrac{v^2}{r} = \omega^2 r[/tex]

The centripetal acceleration of the wheel with angular velocity 10 rad/sec and velocity 40cm (0.4 m) can be written as,

[tex]a_c = \omega ^2\times r\\\\a_c = (10)^2\times 0.4\\\\a_c = 40\rm\ m/sec^2[/tex]

Hence, the centripetal acceleration of the wheel at this time point is 40 m/sec².

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Answer:

C

Explanation:

65-35 = 30

30 divided by 5 = 6

The answer will be 6 m/s

Explanation:

c............ ......

...

Explanation:

wavelength = l

speed of wave = v

frequency = f

v = lf → f = v/l = 2.42 × 10⁴ ÷ 1.1 = 2.2 × 10⁴ 1/s

T = 1/f = 1/ 2.2 × 10⁴ = 0.45 × 10 -⁴ s

The frequency of the sound wave produced from the drum is the speed divided by the wavelength. The frequency of the wave 22 kHz.

Frequency of a wave is the number of wave cycles per unit time. Frequency of a wave is directly proportional to the energy and inversely proportional to the wavelength.

The relation between speed of the wave c, wavelength and frequency of the wave can be written as follows:

c = νλ.

Given speed of the sound wave produced from the drum = 2.42 × 10⁴ m/s

wavelength λ = 110 cm = 1.1 m

The frequency of the sound wave  = speed/wavelength

ν = 2.42 × 10⁴ m/s / 1.1 m = 22000 Hz or 22 kHz.

Time period = 1/frequency

T = 1/ 22000 = 4.45× 10⁻⁵ seconds.

Therefore, the frequency of the wave is 22 kHz and time period of  4.45× 10⁻⁵ seconds.

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Answer:c

Explanation: I took the identifying claims quick check and the answers are 1.yes it can be 2. No because it is an opinion 3.claims 4.it is prediction 5.both particles and waves 6.a wave model is most useful

Scientists use to describe electromagnetic radiation as It exhibits properties of both particles and waves. The correct option is B.

An electromagnetic wave is a type of wave that consists of oscillating electric and magnetic fields that travel through space at the speed of light.

Electromagnetic waves are produced by the movement of charged particles and are characterized by their frequency, wavelength, and amplitude.

Electromagnetic waves include a wide range of frequencies, which together form the electromagnetic spectrum. The spectrum includes radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays. Each of these types of electromagnetic waves has a different frequency and wavelength, which determines its properties and how it interacts with matter.

Here in the question,

Scientists describe electromagnetic radiation as exhibiting properties of both particles and waves.

This is known as the wave-particle duality of electromagnetic radiation, which means that electromagnetic radiation can exhibit both wave-like and particle-like behavior depending on how it is observed or measured.

The wave-like behavior is described by its frequency, wavelength, and amplitude, while the particle-like behavior is described by its energy, momentum, and photons.

Therefore, The electromagnetic wave shows duality i.e both particle and wave properties.

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Answer:

position

Explanation:

Okay, so this already exists

Colorblind people use the position of the light

Red on top, yellow in middle, green on bottom

Distance = (speed) x (time)  <== This is important.  You should memorize it.

Distance = (30 km/hr) x (3 hr)

Distance = (30 x 3) (km/hr x hr)

Distance = 90 km

Answer:

you divide the distance by the time it takes to travel that same distance, then you add your direction to it.

The type of circuit does this traffic situation model will be a parallel circuit because there is more than one path.

A parallel circuit has branches that split the current such that just a portion of it passes through each branch.

The voltage or potential difference between each branch of a parallel circuit is the same, but the currents might differ.

A parallel circuit is having more than one path in order to reach it on time he has to take a different path.

Hence the type of circuit does this traffic situation model will be a parallel circuit because there is more than one path.

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Answer:

C) a parallel circuit because there is more than one path

Explanation: edge

(a) The impulse on the puck is 1.323 kgm/s.

(b) The magnitude of the force that acted on the puck is 264.5 N.

The impulse on the puck is equal to the change in momentum of the puck.

The change in th momentum of the puck is calculated as follows;

ΔP = m(u - v)

where;

Magnitude of the final velocity

|v| = √[(-25)² + (5)²] = 25.5 m/s

ΔP = 0.115(37 - 25.5)

ΔP = 1.323 kgm/s

Thus, the impulse on the puck is 1.323 kgm/s.

The magnitude of the force that acted on the puck is calculated as follows;

F = ΔP/t

F = 1.323/0.005

F =264.5 N

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Answer:

5,886 Joules or 5.886 KJ.

Explanation:

FORMULA IN FINDING WORK is

W = F x D

Where W is working;

F is force; and

D is distance

However, let us first discuss what work is.

When there is an object being moved by a force through a certain distance, the measure of energy transfer is what we call WORK.

One of the most common units used in work is JOULES (commonly used as a unit of energy). It is the work by which 1 Newton (1N = 1 kg.m/sec²) of force is used/expended through a distance of 1 meter (1m).

Refer to the problem.

It is said that the 30 kg set of bricks is to be raised to a height of 20 meters. As we see, there is no force given. But recall that force (F) is the product of the mass (m) of an object and its acceleration (a)

F = ma

However, in the formula, (g = 9.81 m/s²) or acceleration due to gravity is used in replacement of (a) because the object is moving upward.

So now we have  

F = mg

Thus, we have the new work formula as

W = (mg)(D)

Substituting the given values, we have

W = (mg)(D)

W = (30kg)(9.81 m/s²)(20m)

W = 5,886 kg.m²/sec² or W = 5,886 Joules

The work done in lifting the bricks is 5,886 Joules or 5.886 KJ.

~hope this helps~

According to Hooke 's law

[tex]\\ \rm\rightarrowtail \nu=k\sqrt{\dfrac{\ell}{m}}[/tex]

[tex]\\ \rm\rightarrowtail \nu\propto \dfrac{1}{\sqrt{m}}[/tex]

Hence lower the mass higher the frequency

Answer:

Answer:

Option B

Explanation:

Option B talks about how the frequency of the wave increases the shorter it's wavelengths

Answer:

b

Explanation

B: As the frequency of a wave increases, the shorter its wavelength is.

Answer:

Power of the motor.

Explanation:

If it didn't have grip, it would still move. If it was barely aerodynamic (pretty sure nothing can be not aerodynamic at all) it would still move. If it weighed more that the sun (and you had a strong enough motor) it would still move but without a motor, it won't move. Therefore, the motor is the most effective.

Answer:

A, flat water

Explanation:

Answer:

Voltage and current sources are two different sorts of sources that may be found in an electrical network. A voltage source has an emf forcing function, whereas a current source has a current forcing function.

☆ ------ ☆ ------ ☆ ------ ☆ ------ ☆

(1) The image of an object placed further from the lens than the focal point will be upside down and smaller than the object.

(2) When light rays reflect, they bounce back.

(3)  Images formed by a concave lens will look magnified.

(4) When light rays enter a different medium, they bend.

The image of an object placed further from the lens than the focal point will be diminished and inverted.

Thus, the correct answer will be "upside down and smaller than the object".

The ability of light to bounce back when it strike a hard surface is known as refection.

A concave lens is diverging lens is usually virtual, erect and magnified.

The change in speed of light when it travels from medium to another medium is known as refraction. Refraction is also, the ability of light to bend around obstacles.

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Answer:

It is upside down and larger than the object

They bounce back

Magnified

They bend

Explanation:

Let's know the formula

[tex]\\ \rm\rightarrowtail T=2\pi \sqrt{\dfrac{l}{g}}[/tex]

So

[tex]\\ \rm\rightarrowtail T\propto \sqrt{l}[/tex]

Hence if length is doubled time period will be √2 times

#2

Decrease by 5% will decrease the time period 5/2=2.5%

So

It's