Write a proportion to determine the missing measure.

A lighthouse casts a 72-yard shadow at the same time as a 32-foot tall billboard casts a 19-foot shadow.
What is the height of the lighthouse?



A 121.3 yd
B 64.8 yd
C 42.8 yd
D 118.4 ft

There are 5²⁵ possible ways to select 25 cans of soda from 5 types, while there are [5¹⁸] (25 choose 7) possible ways to select 25 cans with at least 7 Dr. Peppers, and only [3²²] (25 choose 3) possible ways to select 25 cans with only 3 Dr. Peppers available.

(a) Since there are five types of soda and we are selecting 25 cans, we can choose any type of soda for each can. Therefore, the number of ways to select 25 cans of soda is 5²⁵.

(b) If we must include at least seven Dr. Peppers, then we can choose the remaining 18 cans from any of the five types of soda (including Dr. Pepper). We can choose 7 Dr. Peppers in (25 choose 7) ways. Therefore, the number of ways to select 25 cans of soda with at least seven Dr. Peppers is (25 choose 7) [5¹⁸].

(c) If there are only three Dr. Peppers available, then we must choose all three Dr. Peppers and select the remaining 22 cans from the four types of soda (excluding Dr. Pepper). We can choose the remaining 22 cans in 4²² ways. Therefore, the number of ways to select 25 cans of soda with only three Dr. Peppers available is 3 [4²²].

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Complete question:

From an unlimited selection of five types of soda, one of which is Dr. Pepper, you are putting 25 cans on a table.

(a) Determine the number of ways you can select 25 cans of soda.

(b) Determine the number of ways you can select 25 cans of soda if you must include at least seven Dr. Peppers.

(c) Determine the number of ways you can select 25 cans of soda if it turns out there are only three Dr. Peppers available.

Answer:

6 and 10

Step-by-step explanation:

first find what 1 min is in meters

1/3 is 8 so 8x3 = 1m which is 24

now divide based on the next two numbers

1/4 of 24 = 6

6x 1 = 6

now the next

24/12 = 2

2x5 = 10

these two results, 6 and 10, are the answers to the missing meter values

The x-intercept is (4.5, 0) and  y-intercept is (0, -1) for the given function.

What are intercepts ?

Intercepts are the points at which a curve intersects with the x-axis and y-axis on a coordinate plane. The x-intercept is the point where the curve intersects with the x-axis, and its y-coordinate is zero. The y-intercept is the point where the curve intersects with the y-axis, and its x-coordinate is zero. The intercepts provide useful information about the behavior and properties of a curve, such as its roots and symmetry.

According to the question:

To find the x-intercept, we need to set y = 0 and solve for x:

[tex]0 = log(2x + 1) - 11 = log(2x + 1)10 = 2x + 19 = 2xx = 4.5[/tex]

Therefore, the x-intercept is (4.5, 0).

To find the y-intercept, we need to set x = 0 and evaluate the function:

[tex]f(0) = log(2(0) + 1) - 1[/tex]

= 0 - 1[tex]= log(1) - 1[/tex]

= -1

Therefore, the y-intercept is (0, -1).

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If i have four boxes arranged in a [tex]2 \times 2[/tex] grid, in 6 distinct ways can i place the digits 1, 2, and 3 in the boxes, using each digit exactly once, such that each box contains at most one digit

If a student has four boxes arranged in a 2 × 2 grid, the distinct ways to place the digits 1, 2, and 3 in the boxes, using each digit exactly once, such that each box contains at most one digit are six in number.

There are two possibilities for which box is left blank, so let's consider them separately:

Case 1: The top left box is left blank. In this case, the other three boxes must contain the digits 1, 2, and 3. There are three choices for what digit goes in the top right box, and then two choices for what digit goes in the bottom left box, and then one choice for what digit goes in the bottom right box.

This gives a total of 3·2·1 = 6 ways to place the digits in the boxes when the top left box is left blank.

Case 2: A different box is left blank. In this case, one of the digits must be left out. There are three choices for which digit is left out, and then three choices for which box is left blank. Once the digit and the blank box have been chosen, the remaining two digits can be placed in the other two boxes in any order, giving 2 ways.

This gives a total of 3·3·2 = 18 ways to place the digits in the boxes when a different box is left blank.

Therefore, the distinct ways to place the digits 1, 2, and 3 in the boxes, using each digit exactly once, such that each box contains at most one digit are six in number.

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The perimeter of the updated blueprint will be 24 times the sum of the original length and width.

If Ezra wants to multiply the dimensions of the stage by a certain percentage to make the image 12 times larger than the original, he needs to find out what percentage that is.

To do this, he can divide the desired size of the new stage by the original size of the stage, and then multiply by 100 to get the percentage increase. So, if the original blueprint dimensions are x by y, and he wants to make the image 12 times larger, the new dimensions will be 12x by 12y.

To find the percentage increase, he can use the following formula:

Percentage increase = [(new size - original size) / original size] x 100

In this case, the new size is 12 times the original size, so the formula becomes:

Percentage increase = [(12x * 12y - x * y) / (x * y)] x 100

Simplifying this expression gives:

Percentage increase = [(144xy - x * y) / (x * y)] x 100 = 14300%

Therefore, Ezra needs to multiply the dimensions of the stage by 14300% to make the image 12 times larger than the original blueprint.

To find the perimeter of the updated blueprint, he can use the formula for the perimeter of a rectangle, which is: Perimeter = 2(length + width)

In this case, the length and width have been multiplied by 12, so the new perimeter becomes:

Perimeter = 2(12x + 12y) = 24(x + y)

Therefore, the perimeter of the updated blueprint will be 24 times the sum of the original length and width.

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The coordinates of point C are (4, 2), which is located in quadrant 1.

In a 30-60-90 degree triangle, the side opposite the 30-degree angle is half the length of the hypotenuse, and the side opposite the 60-degree angle is √3/2 times the length of the hypotenuse. Since the side opposite the 30-degree angle is the shortest side, it must be the distance between points A and B, which is 8 units.

Let's call point C (x, y). Since angle C is 90 degrees, side AC is perpendicular to side AB, which means it is a vertical line that passes through point A. Similarly, side BC is perpendicular to side AB, which means it is a horizontal line that passes through point B.

Therefore, point C must lie on both the vertical line passing through A and the horizontal line passing through B. The equation of the vertical line passing through A is x = -4, and the equation of the horizontal line passing through B is y = -2. So we have the system of equations

x = -4

y = -2

Solving this system gives us the coordinates of point C: (-4, -2). However, this point is not in quadrant 1, as we desired.

To find a point C in quadrant 1, we need to flip the signs of the x and y coordinates of point C. So the coordinates of point C are (4, 2).

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Answer:

Step-by-step explanation:

First, we need to determine the cost of making one necklace.

The total cost of supplies is $46 + $30 = $76.

If she makes one necklace, that cost is divided by one, so the cost of making one necklace is $76.

To find the selling price, we need to add a markup of 75%.

Markup = 75% x Cost = 0.75 x $76 = $57

The selling price will be the cost plus the markup:

Selling price = Cost + Markup = $76 + $57 = $133.

Therefore, Layla should charge $133 for each necklace.

The answer is d) 133.04, although it should be rounded to the nearest cent, so the final answer would be $133.

The solution to the system of equations is (x, y) = (2, 1).

A system of equations is a set of two or more equations that are to be solved simultaneously, meaning that the values of the variables that satisfy each equation in the system must be found. The solution to a system of equations is the set of values for the variables that satisfy all the equations in the system.

To solve the system of equations:

8x - 5y = 11 ...(1)

4x - 3y = 5 ...(2)

We can use the elimination method to eliminate one of the variables. We want to eliminate the variable "y", so we need to multiply equation (2) by -5/3, which will give us:

-5/3(4x - 3y) = -5/3(5)

-20x/3 + 5y = -25/3 ...(3)

Now we can add equations (1) and (3) to eliminate "y":

8x - 5y + (-20x/3 + 5y) = 11 - 25/3

Combining like terms, we get:

(24x - 15y - 20x + 15y)/3 = 8/3

Simplifying, we get:

4x/3 = 8/3

Multiplying both sides by 3, we get:

4x = 8

Dividing both sides by 4, we get:

x = 2

Now we can substitute x = 2 into equation (1) or (2) to find y. Let's use equation (1):

8x - 5y = 11

8(2) - 5y = 11

16 - 5y = 11

Subtracting 16 from both sides, we get:

-5y = -5

Dividing both sides by -5, we get:

y = 1

Therefore, the solution to the system of equations is (x, y) = (2, 1).

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Complete question:

Given the system of equation:

8x - 5y = 11

4x - 3y = 5

Find the value of x and y.

The probability of selecting two non-defective DVD players from a group of six is 2/5. This is based on the assumption that the selection is done without replacement.

We can use the formula for calculating probabilities of combinations:

P(not defective) = number of ways to choose 2 non-defective DVD players / total number of ways to choose 2 DVD players

Total number of ways to choose 2 DVD players out of 6 is:

C(6,2) = 6! / ([2!] [4!]) = 15

Number of ways to choose 2 non-defective DVD players out of 4 is:

C(4,2) = 4! / ([2!] [2!]) = 6

Therefore, the probability that Cecil chooses 2 non-defective DVD players is:

P(not defective) = 6/15 = 2/5

So the value of P(not defective) is 2/5.

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The inverse function is R(L) = (360 - L)/15. It will take 8 weeks to pay loan if student owes $240 and 24 weeks to pay off the whole loan.

A. Let's start by defining the function L(w) as the amount owed w weeks after the student borrows the money. The student borrowed $360 and agreed to pay $15 per week, so the amount owed after w weeks can be calculated as:

L(w) = $360 - $15w

B. To find the inverse of function L, we need to switch the roles of the input and output variables. Let's call the inverse function R, where R(L) is the number of weeks it takes to pay off the loan if the amount owed is L. We can solve the equation from part A for w:

L(w) = $360 - $15w

$15w = $360 - L

w = (360 - L)/15

Therefore, the inverse function R(L) is:

R(L) = (360 - L)/15

This function tells us how many weeks it will take to pay off the loan for a given amount owed. For example, if the student owes $240, we can plug that into the inverse function to find out how many weeks it will take to pay off the loan:

R($240) = (360 - 240)/15 = 8

So it will take 8 weeks to pay off the loan if the student owes $240.

C. To find out how many weeks it will take to pay off the loan, we need to find the value of w when L(w) = 0 (i.e., when the loan is fully paid off). We can set L(w) = 0 and solve for w:

L(w) = $360 - $15w = 0

$15w = $360

w = 24

So it will take 24 weeks to pay off the loan.

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As per the unitary method, Nikhil has 21 pencils and Cortez has 63 pencils.

Let's say Nikhil has x number of pencils. Then, according to the problem, Cortez has three times as many pencils as Nikhil. Therefore, Cortez has 3x number of pencils.

Together, they have a total of 84 pencils. So, we can write an equation based on the number of pencils owned by Nikhil and Cortez as follows:

x + 3x = 84

Simplifying the equation, we get:

4x = 84

Dividing both sides by 4, we get:

x = 21

So, Nikhil has 21 pencils. Using the fact that Cortez has three times as many pencils as Nikhil, we can find out how many pencils Cortez has:

Cortez has 3x = 3(21) = 63 pencils.

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Complete Question:

Lance has three times as many pencils as Nick, and they have 84 pencils together. How many pencils does each of them have?

The bottom of the ladder is moving at a rate of 4/3 ft per second.

To solve the problem, we can use the Pythagorean Theorem:[tex]$x^2 + y^2 = 64$[/tex], where x is the distance from the wall to the bottom of the ladder and y is the length of the ladder. We differentiate this equation with respect to time t and use the chain rule to get [tex]$\frac{d}{dt} (x^2 + y^2) = \frac{d}{dt} 64$[/tex]

Simplifying, we get

[tex]$2x \frac{dx}{dt} + 2y \frac{dy}{dt} = 0$[/tex]

When the bottom of the ladder is 4 feet from the wall, we have x = 4 and y = 8, so we can substitute these values into our equation and solve for [tex]$\frac{dx}{dt}$[/tex]:

[tex]$2(4)\frac{dx}{dt} + 2(8)(-2) = 0$[/tex]

[tex]$\frac{dx}{dt} = \frac{16}{8} = \frac{4}{3}$[/tex]

Therefore, the bottom of the ladder is moving at a rate of [tex]$\frac{4}{3}$[/tex] ft/s.

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The probability that it will take at least 5 minutes until the student is served when he enters the restaurant today is 50%.

This is because there is an equal chance that it could take less than 5 minutes or more than 5 minutes until the student is served.

In probability terms, the student's wait time is a random variable with two possible outcomes - wait time less than 5 minutes, or wait time greater than or equal to 5 minutes. Since there is an equal chance of either outcome occurring, the probability of the wait time being greater than or equal to 5 minutes is 50%.

This is also known as the Law of Large Numbers.

To further illustrate this concept, imagine that the student flips a fair coin. The two possible outcomes of the coin toss are heads or tails. Since each outcome has an equal chance of occurring, the probability of either heads or tails is 50%.

In this case, the probability of the student's wait time being at least 5 minutes is the same as the probability of the coin toss being heads or tails, hence making the probability 50% or 0.5.

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The best type of inspection to use depends on the nature of the purchase. Each type of inspection has its own advantages and disadvantages, and should be chosen based on the requirements of the product and the level of risk associated with the inspection.

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Answer:

[tex]60n - 97[/tex]

Step-by-step explanation:

[tex]3 - 5( - 3n + 5)3 - 5( - 3n + 5)[/tex]

[tex]3 + (15n - 25)3 + 15n - 25[/tex]

[tex]3 + 45n - 75 + 15n - 25[/tex]

[tex]60n - 97[/tex]

The option that would result in the smallest margin of error in estimating the mean salt content, u, is 95% confidence, n = 50. The correct answer is Option D.

The margin of error is the amount by which a statistic is expected to differ from the true value of the population parameter. The interval estimate is calculated with the help of a margin of error. The margin of error and the interval estimate are inversely related to each other. If we want a small margin of error, we must increase the sample size.

The confidence level is the likelihood that a population parameter will fall within a specified range of values. The confidence level is determined by the sample size and margin of error. The sample size and margin of error are directly related to each other. When the sample size is smaller, the margin of error is larger. When the sample size is larger, the margin of error is smaller.

The margin of error is the highest at a confidence level of 50%. In general, as the confidence level increases, the margin of error decreases, and vice versa. As the sample size increases, the margin of error decreases. It follows that a 95% confidence level, n = 50 would yield the smallest margin of error in estimating the mean salt content, u. Hence, option D) 95% confidence, n = 50 would result in the smallest margin of error in estimating the mean salt content, u.

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[tex]10 + 9 + 2 + 4 = 25[/tex] possible outcomes

[tex]25 - 4 = 21[/tex] outcomes that are not green

[tex]\dfrac{21}{25}[/tex] chance that you don’t choose green

[tex]\frac{21}{25}=\bold{84\%}[/tex]

The dimensions that maximize the enclosed area are L = 41.665 feet and W = 41.665 feet for each corral and the maximum area is 10868.09 square feet.

To find the dimensions that maximize the enclosed area, we need to use optimization techniques. Let's denote the length of each rectangular corral by L and the width by W. We can write the total enclosed area as A = 6LW.

The perimeter of each corral is given by P = 2L + 2W, and we have a total of 6 corrals, so the total length of fencing required is 6P = 12L + 12W.

We are given that we have 1,000 feet of fencing, so we can write 12L + 12W = 1000, or equivalently, L + W = 83.33 (rounded to two decimal places).

We can now use this equation to express one of the variables (say, W) in terms of the other: W = 83.33 - L.

Substituting this expression for W into the formula for the enclosed area, we get A = 6L(83.33 - L) = 499.98L - 6L^2.

To find the value of L that maximizes the area, we need to take the derivative of A with respect to L and set it equal to zero: dA/dL = 499.98 - 12L = 0. Solving for L, we get L = 41.665 (rounded to three decimal places).

Substituting this value back into the expression for W, we get W = 83.33 - L = 41.665.

The maximum area is A = 6LW = 10868.09 square feet (rounded to two decimal places).

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The probability that a randomly selected adult weighs between 120 and 165 lbs is approximately 0.8186.

Since the weights of adults are normally distributed with a mean of 140 lbs and a standard deviation of 25 lbs, we can use the standard normal distribution to calculate the probability.

We first need to standardize the values using the formula: z = (x - μ) / σ, where x is the weight, μ is the mean, and σ is the standard deviation.

For x = 120 lbs, z = (120 - 140) / 25 = -0.8, and for x = 165 lbs, z = (165 - 140) / 25 = 1.0. We can then use a calculator to find the probability between -0.8 and 1.0, which is approximately 0.8186.

Thus, the chance of picking an adult at random who weighs between 120 and 165 lbs is roughly 0.8186.

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A candidate's final multiple score main answer can have a maximum of three cumulative Pass Not Advanced (PNA) points applied to it.

PNA points are a form of assessment for a candidate's answers to multiple-choice questions.

They are awarded when the candidate selects an answer that is not necessarily wrong, but does not go into sufficient depth or demonstrate the required level of understanding.

Each PNA point is worth a fraction of a mark, with a total of three PNA points making up one mark of the candidate's final multiple score main answer.

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Answer:

Sure, here are the numbers arranged from greatest to least

Step-by-step explanation:

Order from greatest to least

1.3, 4.5%, 1/3, -4/5, -0.04, -21.5%

Answer:

From the greatest to least

Step-by-step explanation:

1.3, 4.5%, 1/3, -4/5, -0.04, -21.5%

You can identify which number is greater than other by using a number line.

What is a number line?

A number line is what a math student can use to find the answer to addition and subtraction questions. A straight line, theoretically extending to infinity in both positive and negative directions from zero, that shows the relative order of the real numbers.

Hope this helps :)

Pls Brainliest...

There are 3 adults in the family by using the method of substitution and elimination.

Substitution is a method used in mathematics to replace one or more variables in an equation or expression with a value or expression that is equivalent to the variable(s). This is done in order to simplify an equation or expression or to solve for a variable.

Elimination is a method used in mathematics to solve a system of equations by eliminating one variable. This method involves manipulating the equations in such a way that one of the variables is eliminated, leaving a simpler equation with only one variable that can be solved easily.

In the given question,

Here's how we can solve for x, the number of adults:

Multiply the first equation by 2 to get rid of the coefficient of x in the second equation:

12x + 10y = 56

10x + 14y = 58

Subtract the first equation from the second equation to eliminate y:

10x + 14y - (12x + 10y) = 58 - 56

-2x + 4y = 2

Divide both sides by -2 to isolate x:

x - 2y = -1

x = 2y - 1

Substitute x = 2y - 1 into one of the original equations (let's use the first one) and solve for y:

6x + 5y = 28

6(2y - 1) + 5y = 28

12y - 6 + 5y = 28

17y = 34

y = 2

Substitute y = 2 into the equation x = 2y - 1 to solve for x:

x = 2(2) - 1

x = 3

Therefore, there are 3 adults in the family.

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Coupling tetraalkylammonium and ethylene glycol ether side chain is an effective method to enable highly soluble anthraquinone-based ionic species for nonaqueous redox flow battery. The side chains of the tetraalkylammonium are modified with the ethylene glycol ether, which is a highly polar solvent, allowing for better solubility in nonaqueous electrolyte solutions. Additionally, the ethylene glycol ether has the ability to modify the stability of the ionic species, preventing aggregation and ensuring the longevity of the battery. This increases the redox capacity and enhances the performance of the flow battery.

The ethylene glycol ether-tetraalkylammonium coupling has been proven to be an effective method for improving the solubility and stability of anthraquinone-based ionic species. For example, it has been observed that the coupling of ethylene glycol ether to anthraquinone-based ionic species enhanced the current density of the battery by more than 3 times. Furthermore, the coupling process has also been found to improve the energy efficiency and storage capacity of the nonaqueous redox flow battery.

Overall, coupling tetraalkylammonium and ethylene glycol ether side chain is an effective method for enabling highly soluble anthraquinone-based ionic species for nonaqueous redox flow battery. This process has been proven to improve the performance of the battery, including current density, energy efficiency, and storage capacity.

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In this simplex tableau, x₄, x₅, and z are the basic variables, while x₁, x₂, x₃, x₆, x₇, and x₈ are the nonbasic variables. The values of all the variables associated with this basic feasible solution are x₁ = 0, x₂ = 0, x₃ = 0, x₄ = 620, x₅ = 12, x₆ = 0, x₇ = 0, x₈ = 0, and z = 620.

In this tableau, the basic variables are x₄, x₅, and z, while the nonbasic variables are x₁, x₂, x₃, x₆, x₇, and x₈.

The basic variable associated with row 1 is x₄, the basic variable associated with row 2 is x₅, and the basic variable associated with row 3 is z.

The values of all the variables associated with this basic feasible solution are:

x₁ = 0, x₂ = 0, x₃ = 0, x₄ = 620, x₅ = 12, x₆ = 0, x₇ = 0, x₈ = 0, z = 620.

Note that these values correspond to the entries in the tableau in the "BV" column.

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The missing tableau is in the image attached below

Answer: No

Step-by-step explanation:

Because the length of the box is shorter than the length of the club

20in<26in

The width of the box is also shorter than the width of the club

13in<16in

The height of the box is also shorter than the height of the club

11in<16in

But what about putting it at an angle?

So we know  [tex]a^{2} +b^{2} =c^{2}[/tex]

so let's try [tex]20^{2} +13^{2} =x^{2}[/tex]

                               [tex]x^{2}[/tex]=569

                               [tex]x=\sqrt{159}[/tex]

x is near 23.85 in, but 23.85<26. So no.

Answer: It should be -1,7

Step-by-step explanation: x=1-2=-1

y=8-1=7

Answer:

(-1, 7)

Step-by-step explanation:

A left translation is a negative number affecting the x-coordinate.

1 - 2 = -1

A down translation is a negative number affecting the y-coordinate.

8 - 1 = 7

(1, 8) --------> (-1, 7)

Answer:

Step-by-step explanation:

Ronaldo's family drove a total of 6.90 kilometres to get from their house to the store.

To determine the total distance Ronaldo's family drove, we need to add the distance from their house to the gas station and the distance from the gas station to the store. We can write this as:

[tex]4 6/10 km + 2 30/100 km[/tex]

To add these two distances, we need to find a common denominator for the fractions. The smallest common denominator for 10 and 100 is 100, so we can convert the first distance to an equivalent fraction with a denominator of 100:

[tex]4 6/10 km = 4 60/100 km = 4.60 km[/tex]

Then we can add the two distances:

[tex]4.60 km + 2.30 km = 6.90 km[/tex]

Therefore, Ronaldo's family drove a total of 6.90 kilometres to get from their house to the store.

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Using the identity sin² 0 + cos² 0 = 1, the value of cos 0 is 0.951 (to the nearest hundredth)

Using the identity sin² 0 + cos² 0 = 1, we can solve for cos 0:

cos² 0 = 1 - sin² 0

cos² 0 = 1 - (-0.31)²

cos² 0 = 1 - 0.0961

cos² 0 = 0.9039

Taking the square root of both sides, we get:

cos 0 ≈ ±0.951

Since 0 is in the interval ³ < 0 < 2π, we know that cos 0 must be positive. Therefore, to the nearest hundredth, cos 0 ≈ 0.95.

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The correct answer is (A) r² - 2rs +s² which is a square of a Binomial.

What exactly are binomials?

In algebra, a binomial is a polynomial which consists of two terms. The terms may be separated by a plus or minus sign. The general form of a binomial is:

ax + b

where "a" and "b" are constants and "x" is the variable. A binomial can be added, subtracted, multiplied, and divided using algebraic operations. Binomials are commonly used in algebra to represent and solve problems involving two quantities or variables.

Now,

The correct answer is (A) r² - 2rs +s².

This is a perfect square trinomial, which can be written as (r - s)².

Option (B) c² + d² is not a binomial, it is the sum of two squares.

Option (C) 16x² - 25y² is a difference of two squares, which can be written as (4x + 5y)(4x - 5y).

Option (D) d² - de + e² is also a perfect square trinomial, but it cannot be written as the square of a binomial.

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