Write fraction that represents the parts shaded red (indicated by "R*) in the figure shown below.
R
R
R
R
R
W
R
R
W

The step which is included in the graph of the function is Option(a)  

y=-5 for -4≤ x <-3.

From the properties of the greatest integer function y = [x], we know that

y = 0 for, 0 ≤ x < 1

y = -1 for, - 1 ≤ x < 0

y = -2 for, - 2 ≤ x < -1

Here,we are given a greatest integer function f(x) or y =[x-1]

Hence, the step which is included in the graph of the function is  

y=-5 for -4 ≤ x <-3.

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Answer:

The way I would best say is listing all the multiples then circle all the ones that are alike then find the lowest one they all have.

Example

Find the common multiples of 12,15,20

Multiples of 12:12, 24, 36, 48, 60, 72, 84, 96, 120……….

Multiples of 15:15, 30, 45, 60, 75, 90, 105, 120, 135, 150, 165, 180, 195, 210, 225, 240, 255, 270, 285, 300, 315, 330, 345, 360, 375, 390, 405,……..

Multiples of 20:20, 40, 60, 80, 100, 120, 140, 160, 180, and 200.

Step-by-step explanation:

They all have 60 so your lcm is 60

Neon (Ne), hydrogen (H), helium (He), and Carbon (C) are examples of; C: elements you can tell because they can be found on the periodic table

Elements are pure substances which are composed of only one type of atom. Compound are substances which are formed by two or more different types of elements that are united chemically in fixed proportions.

Now, Neon (Ne), hydrogen (H), helium (He), and Carbon (C) are examples of elements. This is because they are all composed of only one type of atom and they can as well be found in the periodic table that contains only elements.

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Answer:

43 10/19

Step-by-step explanation:

880 oz

Step-by-step explanation:

When x = 0 in the given equation, the value of y = 8.

The value is 'x' is not given then we will consider x = 0.

Now, substitute x = 0 in the equation.

Therefore, the value of y = 8 when x = 0 is in the given equation.

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The amount the she had in her savings before the trip was $825

From the question, we are to calculate how much Imani has in her savings before the trip

Let the amount she has in her savings before the trip be x

From the given information,

"Imani spent a third of her savings on airfare for a vacation"

That is,

She spent (1/3)x

The amount remaining after this time will be x - (1/3)x = (2/3)x

"She then spent another $300 on hotels"

The amount remaining after this time will be (2/3)x - $300

"If she has $250 left for meals and souvenirs"

That is,

(2/3)x - $300 = $250

Now, solve for x

(2/3)x - $300 = $250

(2/3)x = $250 + $300

(2/3)x = $550

x = $550 × 3/2

x = $825

Hence, the amount the she had in her savings before the trip was $825

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The 3 consecutive odd integers are -3, -5 and -7

Let the 3 consecutive odd integers be 2x-1,  2x+1 and 2x+3

If the sum of 2 times the first and the last term is equal to 5 times the middle integer, then;

2(2x-1)+2x+3 = 5(2x+1)

Expand

4x-2 + 2x +3 = 10x+5

6x +1 = 10x + 5

6x - 10x = 5 - 1

-4x = 4

x = -1

Determine the numbers

First number = 2(-1) - 1 = -3

Second number = -5

Third number = -7

Hence the 3 consecutive odd integers are -3, -5 and -7

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Mean = 0.5545, Median =0.57, Mode = 0.79  of the following data.

What is mean median and mode?

For the given data 0.29, 0.3, 0.34, 0.35, 0.37, 0.46, 0.51, 0.51, 0.52, 0.57, 0.57, 0.58, 0.62, 0.63, 0.65, 0.68, 0.77, 0.79, 0.79, 0.79.

The mean is calculated as:

Mean = (0.29 + 0.3 + 0.34 + 0.35 + 0.37 + 0.46 + 0.51 + 0.51 + 0.52 + 0.57 + 0.57 + 0.58 + 0.62 + 0.63 + 0.65 + 0.68 + 0.77 + 0.79 + 0.79 + 0.79)/20

= 11.09/20

Mean = 0.5545

Median is the middle value of the data set and since the sample size is even which is 20 hence the median is found between n/2 and n/2 +1 which is 10th value and 11th value when the data set is arrange in ascending order.

so, the 10th value is 0.57 and 11th value is also 0.57 so, the median is (0.57 + 0.57)/2 = 0.57

Median:

The median is the most occuring value in the dataset and as we can see that 0.79 appeared 3 times hence 0.79 is Mode.

So, finally:

Mean = 0.5545

Median =0.57

Mode = 0.79

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If the speed limit in Canada is 100km/hr than it's limit in mi/hr will be 62.15 mi/hr.

It is given in the question that 1.609 km = 1 mi

So , 1km= 1/1.609 mi

1km = 0.6215 mi

So if a car travels 1 km in 1 hr then it will travel 0.6215 miles in hr.

that means 1km/hr = 0.6215mi/hr

Now ,

to convert 100km/hr to mi/hr

we have  ,

100km/hr = 100*0.6215 mi/hr

=62.15 mi/hr

Therefore , If the speed limit in Canada is 100km/hr than it's limit in mi/hr will be 62.15 mi/hr.

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Answer:

2 because the unit rate is not the same for all the others it is consistant

Step-by-step explanation:

Answer:

10.6 ounces

Step-by-step explanation:

1. Divide the total spent by the cost per ounce to get number of ounces bought.

2.65 ÷ 0.25 = 10.6 ounces

Answer:

for the plug-in settings to determine

Step-by-step explanation:

GG from Shahs of sunset Blvd suite is the best way to the answer to the answer to the answer to the plug-in the plug-in the whole thing is I don't have a email the e I m not sure if you have any questions or concerns please visit the plug-in settings to determine

Answer:

I think is higher

Step-by-step explanation:

Answer: 64t^2

Step-by-step explanation:

everything in the parenthesis has to get the exponent so it first becomes 8^2t^2 and then you simplify

Answer:

64t^2

Step-by-step explanation:

First, you need to distribute the exponent

8^2*t^2

Then you need to simplify

64t^2

And thats the answer

The length of each side of the tank is 9 feet.

Height = 8

Volume = 648

Let y be the cross sectional area

Therefore, 648 = 8y

y² = 648/8

y² = 81

Therefore, y = ✓81

y = 9

The length of each side of the tank is 9 feet.

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Answer:

Step-by-step explanation:

You want to know the number of outcomes in the sample space when 3 marbles are chosen from 7. If four are red marbles, you want to know the number of outcomes when all chosen are red.

There are C(7,3) = 7!/(4!·3!) = 35 ways to choose 3 marbles from 7. Given that there are different colored marbles involved, not all of these outcomes are unique.

There are 35 possible outcomes.

There are C(4, 3) = 4 ways to choose 3 red marbles from 4 red marbles.

There are 4 possible outcomes with all red marbles.

__

Additional comment

The 35 possible outcomes are ...

  (RRR) - 4, (RRG) - 12, (RRY) - 6, (RGG) - 4, (RGY) - 8, (GGY) - 1

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Answer:

24

Step-by-step explanation:

8. 6

16. 12

24. ✔️ 18

32. 24✔️

40. 30

48. 36

56. 42

64. 48

72. 54

80. 60

The meaning of |-36| is  the absolute value of negative 36.

We know that, the absolute value of any real number m is the positive value of m.

For any ±m ∈ R,

| ±m | = m

The absolute value of a number is also know as modulus of number.

In this question we have been given an absolute value |-36|

|-36| = 36

So, the meaning of |-36| would be,

- the absolute value of negative 36

Therefore, the meaning of |-36| is  the absolute value of negative 36.

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1. Euphoria's opportunity cost of producing a a bushel of rye is 4 pairs of jeans.

Contentes opportunity cost of producing a bushel of rye is 2 pairs of jeans.

2. Contente has comparative advantage in producing rye

Euphoria has comparative advantage in jeans production

For Euphoria:

The opportunity cost of producing a unit of rye in terms of jeans is;

Opportunity Cost = 20/5 = 4

For contente:

The opportunity cost of producing a unit of rye in terms of jeans is;

Opportunity Cost = 16/8 = 2

The opportunity cost of producing 1 unit of jean in terms of unit of rye:

For euphoria = 5/20 = 1/4

For contente = 8/16 = 1/2

1. Euphoria's opportunity cost of producing a a bushel of rye is 4 pairs of jeans.

Contentes opportunity cost of producing a bushel of rye is 2 pairs of jeans.

2. Contente has comparative advantage in producing rye

Euphoria has comparative advantage in jeans production

3. Contente produces 8 bushels of rye so with 4 million hours of labor = 8x4 = 32 million bushels in a week.

Euphoria 20 pairs of jean in a week, using 4 million hours of labor. 20x4 = 80 pairs of jean a week

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If  the number lies between 60 and 70 then the number is 63

The given parameters are

LCM = 126

Second number = 42

The initial number is said to be between 60 and 70

The only number between 60 and 70 that has the same common factor as 126 and 42 is 63

Hence, if the number lies between 60 and 70 then the number is 63

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Given that

To find

So, according to the question

We have,

∵ From figure m∠1 and m∠2 divided 90° into two parts

∴       m∠1 + m∠2  = 90° ----------------------(1)

Now putting the values of m∠1 and m∠2 in equation (1)

        m∠1 + m∠2  = 90° ----------------------(1)

       (x+38)° + 3x° =  90°

       x°+38° + 3x° =  90°

                     4x° =  90° - 38°

                     4x° =  52°

                     x° =  (52/4)°

                     x° =  13°

So,

                m∠1 = (x+38)°

                        = (13+38)°

               m∠1 = 51°  

And

                m∠2 = 3x°

                        = (3 × 13)°

                m∠2 = 39°

The angles are

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Answer: The answer is 16.62

Using the Poisson and the normal distributions, the probabilities are given as follows:

a) 0.0895 = 8.95%.

b)

Without correction, P(X < 8) = 0.1251 = 12.51%.

With continuity correction, P(X < 8) = 0.0968 = 9.68%.

c)

Without correction, P(16 < X < 24) = 0.1248.

With correction, P(16 < X < 24) = 0.1558 = 15.58%.

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]

The parameters are:

In this problem, the mean is given by:

[tex]\mu = 12[/tex]

Hence the probability that X is less than 8 is given by:

P(X < 8) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7).

In which:

[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]

[tex]P(X = 0) = \frac{e^{-12}12^{0}}{(0)!} = 0.00001[/tex]

...

[tex]P(X = 7) = \frac{e^{-12}12^{7}}{(7)!} = 0.04368[/tex]

The middle values are found applying the same formula, and adding them, the probability is given by:

P(X < 8) = 0.0895 = 8.95%.

The z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

Without continuity correction, the probability that X is less than 8 is the p-value of Z when X = 8, hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{8 - 12}{\sqrt{12}}[/tex]

Z = -1.15

Z = -1.15 has a p-value of 0.1251.

Hence:

Without correction, P(X < 8) = 0.1251 = 12.51%.

With continuity correction, as the Poisson distribution is discrete and the normal is continuous, the probability is P(X < 7.5), which is the p-value of Z when X = 7.5, hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{7.5 - 12}{\sqrt{12}}[/tex]

Z = -1.3

Z = -1.3 has a p-value of 0.0968.

Hence:

With continuity correction, P(X < 8) = 0.0968 = 9.68%.

For item c, without correction, the probability is the p-value of Z when X = 24 subtracted by the p-value of Z when X = 16, hence:

X = 24:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{24 - 12}{\sqrt{12}}[/tex]

Z = 3.46

Z = 3.46 has a p-value of 0.9997.

X = 16:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{16 - 12}{\sqrt{12}}[/tex]

Z = 1.15

Z = 1.15 has a p-value of 0.8749.

0.9997 - 0.8749 = 0.1248.

Hence:

Without correction, P(16 < X < 24) = 0.1248.

With correction, the probability is the p-value of Z when X = 23.5 subtracted by the p-value of Z when X = 15.5, hence:

X = 23.5:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{23.5 - 12}{\sqrt{12}}[/tex]

Z = 3.32

Z = 3.32 has a p-value of 0.9996.

X = 15.5:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{15.5 - 12}{\sqrt{12}}[/tex]

Z = 1.01

Z = 1.01 has a p-value of 0.8438.

0.9996 - 0.8438 = 0.1558.

Hence:

With correction, P(16 < X < 24) = 0.1558 = 15.58%.

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