To draw the structural formula for 6-Ethyl-4,7-dimethyl-non-1-ene, we need to identify the position of each substituent on the parent chain and consider the given alkene (double bond) location.
The name of the compound provides the following information:
6-Ethyl: There is an ethyl group (CH2CH3) attached to the sixth carbon atom.
4,7-dimethyl: There are two methyl groups (CH3) attached to the fourth and seventh carbon atoms.
non-1-ene: The parent chain is a nonane (nine carbon atoms) with a double bond (ene) at the first carbon atom.
Based on this information, we can construct the structural formula as follows:
CH3 CH3
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CH3 - CH - CH - CH = CH - CH2 - CH2 - CH2 - CH2 - CH3
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CH3 CH2CH3
In this structure:
The ethyl group (CH2CH3) is attached to the sixth carbon atom.
There are methyl groups (CH3) attached to the fourth and seventh carbon atoms.
There is a double bond (ene) between the first and second carbon atoms.
The resulting compound is 6-Ethyl-4,7-dimethyl-non-1-ene, which follows the naming conventions for the substituents and the double bond position on the parent chain.
It's important to note that the structural formula provided here is a two-dimensional representation of the molecule, showing the connectivity of atoms but not the three-dimensional arrangement.
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