write your answer in exponential form. 3^9 * 3^-3

Answers

Answer 1

Step 1

Given;

[tex]3^9\times3^{-3}[/tex]

Required; To write the answer in exponential form

Step 2

[tex]\begin{gathered} Using\text{ the index law below;} \\ a^b\times a^c=a^{bc} \\ Hence,\text{ 3}^9\times3^{-3}=3^{9-3}=3^6 \end{gathered}[/tex]

Answer;

[tex]3^6[/tex]


Related Questions

Rectangle CARD has a length of 2x-5 and a width of 6x+10. Triangle BEST has a length of 10x+3 and a width of 4x-7. Find the difference between triangle CARD and triangle BEST. *

Answers

Given:

Rectangle CARD: {length = 2x-5 and width = 6x+10}

Triangle BEST: {length = 10x+3 and width = 4x-7}

To find the differnce, let's first the perimeter of both.

Perimeter of rectangle CARD: 2(length + width)

= 2(2x - 5 + 6x + 10)

= 2(2x + 6x - 5 + 10)

= 2(8x + 5)

= 16x + 10

Perimeter of triangle BEST: 2(length + width)

2(10x + 3 + 4x - 7)

= 2(10x + 4x + 3 - 7)

= 2(14x - 4)

= 28x - 8

Therfore, the difference between both of them is calculated below:

(28x - 8) - (16x + 10)

= 28x - 8 - 16x + 10

= 28x - 16x - 8 10

= 12x - 18

ANSWER:

12x -

Write an explicit rule for the following arithmetic sequence: 28, 38, 48, 58,

Answers

When you have an arithmetic sequence you can use the next general formula to get the explicit formula:

[tex]a(n)=a(1)+d(n-1)[/tex]

Where a(1) is the first term in the sequence, d is the difference between each term in the sequence, and n is the nth term

You have the sequence: 28,38,48,58

The difference in this sequence is d=10

The first term is: a(1)=28

Then:

[tex]a(n)=28+10(n-1)[/tex][tex]a(n)=28+10n-10[/tex][tex]a(n)=18+10n[/tex]Then, the explicit rule for the given arithmetic sequence is: a(n)=18+10n

i need help with this. for 2nd option, select only one sub-option

Answers

A matrix being in row echelon form means that Gaussian elimination has operated on the rows.

A matrix is in reduced row echelon form (also called row canonical form) if it satisfies the following conditions:

- It is in row echelon form.

-The leading entry in each nonzero row is a 1 (called a leading 1).

-Each column containing a leading 1 has zeros in all its other entries.

The matrix presented on the problem satisfies all conditions, therefore, the matrix is indeed in reduced row-echelon form.

draw and label: ray LM

Answers

To draw a Ray; Draw a line with an arrowhead at one end of the line segmen:

Ray LM:

if A/B and C/D are rational expressions,then which of the following is true?*PHOTO*

Answers

In general,

[tex]\begin{gathered} \frac{w}{x}*\frac{y}{z}=\frac{w*y}{x*z} \\ x,z\ne0 \end{gathered}[/tex]

Therefore, in our case, (Notice that since A/B and C/D are rational expressions, B and D cannot be equal to zero)

[tex]\frac{A}{B}*\frac{C}{D}=\frac{A*C}{B*D}[/tex]

Notice that the left side of each option includes the term

[tex]\frac{A}{B}*\frac{D}{C}[/tex]

However, we cannot assure that C is different than zero because it is only stated that C/D is rational.

Furthermore,

[tex]\frac{A}{B}*\frac{D}{C}=\frac{A*D}{B*C}[/tex]

And (A*D)/(B*C) is not included among the options.

Therefore, the answer has to be option D as it is the only one that correctly expresses the multiplication of two fractions.Remember that there is a mistake in each option, the left side has to be A/B*D/C

How many tiles of 8 cm² is needed to cover a floor of dimension 6 cm by 24 cm? A. 6 B. 12 C. 18 D. 24​

Answers

Answer:

18 tiles.

Step-by-step explanation:

24x6= 144

144/8= 18

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in a classroom there are 28 tablets which includes 5 that are defective. if seven tablets are chosen at random to be used by student groups. 12. how many total selections can be made? a. 140 b. 98280 c. 11793600 d. 4037880 e. 1184040 13. how many selections contain 2 defective tablets? a. 10 b. 21 c. 336490 d. 706629 e. 33649

Answers

Using the combination formula, it is found that:

The number of total selections that can be made is: e. 1184040.The number of selections that contain two defective tablets is: c. 336490.

Combination formula

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula, involving factorials. It is used when the order in which the elements are chosen does not matter.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

In the context of this problem, we have that seven tablets are chosen from a set of 28 tablets, hence the number of selections that can be made is given by:

[tex]C_{28,7} = \frac{28!}{7!21!} = 1,184,040[/tex]

For two defective tablets, the selections are given as follows:

Two defective from a set of five.Five non-defective from a set of 23.

Hence the number of selections is calculated as follows:

[tex]C_{23,5}C_{5,2} = \frac{23!}{5!18!} \times \frac{5!}{2!3!} = 336,490[/tex]

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Use the given information to select the factors of f(x). f(4)=0 f(-1)=0 f(3/2)=0. Make sure to select all correct answers for full credit.

Answers

The binomials x - 4, x + 1 and 2 · x - 3 are factors of the polynomials.

How to derive the equations of the factors of a polynomial

Herein we know the x-values of a polynomial such that the expression is equal to zero. Mathematically speaking, these x-values are known as roots and the mathematical expressions that contain them are known as factors, which are represented by binomials of the form:

a · r - b = 0

Where a, b are real coefficients.

If we know that x₁ = 4, x₂ = - 1, x₃ = 3 / 2, then the factors of the polynomials are listed below:

x₁ = 4:

x - 4 = 0

x₂ = - 1:

x + 1 = 0

x₃ = 3 / 2

2 · x - 3 = 0

x - 4, x + 1 and 2 · x - 3 are factors of the polynomials.

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You have a total of 21 coins, all nickels and dimes. The total value is $1.70. Which of the following is the system of linear equations that represent this scenario? Let n = the number of nickels and let d = the number dimes.

Answers

n = number of nickels

d = number of dimes

1 nickel = 5 cents

1 dime = 10 cents

total number of 21 coins:

n + d = 21

Total value = $1.70

5n + 10 d = 170

Divide by 100

0.05n + 0.10 d = 1.70

Answer:

n + d = 21

0.05n + 0.10 d = 1.70

If z = 12.8, what's is the value of 2(z - 4)?

Answers

The given expression is

[tex]2(z-4)[/tex]

Let's replace z = 12.8.

[tex]2(12.8-4)=2(8.8)=17.6[/tex]Therefore, the value is 17.6.

Multiply -5 1/2 × 7 5/6 =

Answers

You have to multiply:

[tex]-5\frac{1}{2}\cdot7\frac{5}{6}[/tex]

First write the compound fractions as impropper fractions.

To do so, divide the whole number by one to express it as a fraction and add both fractions:

[tex]\begin{gathered} 5\frac{1}{2}=\frac{5}{1}+\frac{1}{2}\to\text{ common denominator 2} \\ \\ \frac{5\cdot2}{1\cdot2}+\frac{1}{2}=\frac{10}{2}+\frac{1}{2}=\frac{11}{2} \end{gathered}[/tex][tex]\begin{gathered} 7\frac{5}{6}=\frac{7}{1}+\frac{5}{6}\to\text{ common denominator 6} \\ \frac{7\cdot6}{1\cdot6}+\frac{5}{6}=\frac{42}{6}+\frac{5}{6}=\frac{47}{6} \end{gathered}[/tex]

Rewrite the multiplication using the corresponding impropper fractions:

[tex]-\frac{11}{2}\cdot\frac{47}{6}[/tex]

And solve the multiplication, numerator * numerator and denominator*denominator:

[tex]-\frac{11}{2}\cdot\frac{47}{6}=-(\frac{11\cdot47}{2\cdot6})=-\frac{517}{12}[/tex]

I have already found X . I need help finding m<2

Answers

Given:

[tex]m\angle1=8x-102\text{ and }m\angle4=2x+6[/tex]

Required:

[tex]\text{ Find the measure of }\angle2.[/tex]

Explanation:

Step 1:

[tex]m\angle1=m\angle4[/tex]

Step 2:

[tex]\begin{gathered} 8x-102=2x+6 \\ 6x=108 \\ x=18 \end{gathered}[/tex]

Step 3:

[tex]\begin{gathered} m\angle1=8(18)-102 \\ m\angle1=144-102 \\ m\angle1=42 \\ Now, \\ m\angle1+m\angle2=180 \\ 42+m\angle2=180 \\ m\angle2=180-42 \\ m\angle2=138 \end{gathered}[/tex]

Answer:

Measure of angle 2 equals 138.

Rapheal is traveling in a straight line at a constant speed from point A to point B. His distance from point B in miles is -20t + 45, where t is the number of hours he has been traveling. What is his speed in miles per hour?

Answers

Rapheal is traveling in a straight line. Its speed in miles per hour is 20 miles per hour.

 A and B are the two points of a straight line.Distance between two points is given as :

            d₀ =  -20t + 45 miles

t = the number of hours of travelling.

The starting time = 0

i.e. the initial position = 0

Then

we put t=0

At t=0

d₀ = -20(0) + 45

= 0 + 45

= 45 miles

the distance travel after starting first hour is :

T= d₁ & d₀

than we put t = 1

At t = 1;

d₁ = -20(1) + 45

= -20 + 45

= 25 miles

now

Difference between d₁ & d₀ is

d = d₁ - d₀

45 - 25 = 20 miles

Total distance covered =  20 miles

To find the  speed we use formula:

Speed = distance/time

Speed=20/1

Speed = 20 miles/hour

Rapheal is traveling in a straight line. Its  speed in miles per hour is 20 miles per hour.

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From least to greatest. -1.4-1.02 -1.20

Answers

We could put these values in the number line:

Therefore, the order of the numbers from least to greatest is:

-1.4 , -1.20 , -1.02

The least number between all the options given is -1.4 because if you see, all numbers are negative, so, when a negative number is greater, as the amount after the negative sign becomes greater, the number is going to be least. That's the reason of the order.

For the polynomial below, 1 is a zero.h(x) = x² – 3x? - 2x + 4Express h(x) as a product of linear factors.

Answers

Step 1

Given the zero, 1, we can use synthetic division to acquire the other factors

Using synthetic division we will write out all coefficients of the terms of h(x) and proceed thus

1 | 1 -3 -2 +4

1 -2 -4

-----------------------

1 -2 -4 0

Hence the quadratic equation we will need to split into linear factors is given as

[tex]x^2-2x-4[/tex]

Since the remainder is 0

Step 2

Factorize the quadratic equation above completely

[tex]\begin{gathered} x^2-2x-4=0 \\ we\text{ will use} \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \end{gathered}[/tex]

Where

a= 1

b= -2

c= -4

[tex]\begin{gathered} x=\frac{-(-2)\pm\sqrt[]{(-2)^2-4\times1\times-4}}{2\times1} \\ x=\frac{2\pm\sqrt[]{4+16}}{2} \end{gathered}[/tex][tex]\begin{gathered} x=\frac{2\pm\sqrt[]{20}}{2} \\ x=\frac{2}{2}+\frac{\sqrt[]{20}}{2}=1+\frac{2\sqrt[]{5}}{2}=1+\sqrt[]{5} \\ Or \\ x=\frac{2}{2}-\frac{\sqrt[]{20}}{2}=1-\frac{2\sqrt[]{5}}{2}=1-\sqrt[]{5} \end{gathered}[/tex]

Hence the product of linear factor will be

[tex](x-1)(1+\sqrt[]{5})(1-\sqrt[]{5})[/tex]

How do you write 6 tens + 4 ones + 5 tenths + 2 hundredths + 8 thousandths

Answers

Answer:

Step-by-step explanation:

64.528 is the decimal

64.528 would be the numerical form of the alphabetical order you listed your question in

12 is what percent of 18

Answers

We have that

[tex]12\cdot\text{ }\frac{100}{18}=\text{ }\frac{1200}{18}\text{ = 66.6666}[/tex]

So the answer is: 66.6666 .

so I've been using the formula for the volume of a cylinder but I'm still not getting anything even remotely close to my answer choices. the volume is 438.08π mL and the radius is 3.7 cm. I'm solving for the height

Answers

Answer:

H = 32 cm

Explanation:

The area of a cylinder is given by

[tex]V=\pi r^2h[/tex]

Now solving for h gives

[tex]h=\frac{V}{\pi r^2}[/tex]

Now V = 438.08 π and r = 3.7 cm. Putting these values in the above equations gives

[tex]h=\frac{438.08\pi\operatorname{cm}^3}{\pi(3.7cm)^2}[/tex][tex]\boxed{h=32\operatorname{cm}\text{.}}[/tex]

which is our answer!

Can you please help me out with a question

Answers

Given data:

The given radius is r=16 ft.

The expression for the surface area is,

[tex]\begin{gathered} SA=4\pi(r)^2 \\ =4\pi(16ft)^2 \\ =1024\pi ft^2 \end{gathered}[/tex]

The expression for the volume of the sphere is,

[tex]\begin{gathered} V=\frac{4}{3}\pi(r)^3 \\ =\frac{4}{3}\pi(16ft)^3 \\ =\frac{16384\pi}{3}ft^3 \end{gathered}[/tex]

Thus, the surface area is 1024π sq-ft, and volume is (16384π)/3 cube-ft.

Solve the system using algebraic methods.
y = x² + 4x
y = 2x² + 3x - 6

Solution x =

Answers

Two or more expressions with an Equal sign is called as Equation. x is -6 and 7 for equations y = x² + 4x and y = 2x² + 3x - 6

What is Equation?

Two or more expressions with an Equal sign is called as Equation.

The given two equations are

y = x² + 4x

y = 2x² + 3x - 6

Let us simplify these equations as below.

x² + 4x-y=0..(1)

2x² + 3x -y= 6..(2)

subtract equations (2) from (1)

x² + 4x-y-2x² - 3x+y=-6

-x² +x=-6

x(-x+1)=-6

x=-6

and -x+1=-6

Subtract -1 from both sides

-x=-7

x=7

Hence solution of x is -6 and 7 for equations y = x² + 4x and y = 2x² + 3x - 6

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Suppose that you follow the same path on the return trip from Dubuque to Council Bluffs. What would be thetotal number of (actual) miles for the round trip?

Answers

We know the trip from Council Bluffs to Dubuque had a total distance of 348 miles; if we take the same route to go back this will mean that we need to travel the same distance, 348 miles. The total distance then we will be 696 miles.

In a newspaper, it was reported that the number of yearly robberies in Springfield in 2013 was 180, and then went down by 40% in 2014. How many robberies were there in Springfield in 2014?

Answers

As given that the number of yearly robberies in Springfield in 2013 was 180

And then went down by 40% in 2014.

So robberies were there in Springfield in 2014:

[tex]\begin{gathered} N=180-180\times\frac{40}{100} \\ N=180-72 \\ N=108 \end{gathered}[/tex]

So robberies were there in Springfield in 2014 are 72

Using Calculus with Data in a tablePlease let me know if you have any questions regarding the material, thanks!

Answers

ANSWER

g'(0.1) = 4

EXPLANATION

As stated, g(x) is a composition of two functions: f(x) and 2x. To find its derivative, we have to use the chain rule,

[tex]g^{\prime}(x)=f^{\prime}(x)\cdot(2x)^{\prime}=f^{\prime}(2x)\cdot2[/tex]

So, the derivative of g(x) = f(2x) is twice the derivative of f(x) and, therefore,

[tex]g^{\prime}(0.1)=f^{\prime}(2\cdot0.1)\cdot2=f^{\prime}(0.2)\cdot2=2\cdot2=4[/tex]

Hence, g'(0.1) = 4.

What would you have to divide 584,900 by in order to have the 4 shift to the onesplace Explain your answer on the lines below.

Answers

in order to shift the 4 to the ones place, divide the given number 584,900 by 100. After dividing the the number 584,900 by 100, the new number is 584.900. It is clear that 4 is at ones olace.

Jordan’s of Boston sold Lee Company of New York computer equipment with a $7,000 list price. Sale terms were 4/10, n/30 FOB Boston. Jordan’s agreed to pay the $400 freight. Lee pays the invoice within the discount period. What does Lee pay Jordan’s?

Answers

If Sale terms were 4/10, n/30 FOB Boston and Jordan’s agreed to prepay the $400 freight. Lee pays the invoice within the discount period. The amount that  Lee pay Jordan’ s is $7,120.

What is the amount received?

Using this formula

Amount received = [ ( Cost of computer equipment × ( 1 - rate )] + Freight

Let plug in the formula

Amount received = [ $7,000 × ( 1 - 0.04) ] +$400

Amount received = ( $7,000  x  .96 ) + $400

Amount received = $6,720  + 400

Amount received  =   $7,120

Therefore Lee pay Jordan the amount of $7,120.

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Solve the equation 10x+14= - 2x+38 explaining all the steps of your solution as in the examples in this section.

Answers

[tex]10x+14=-2x+38[/tex]

To solve the given equation:

1. Add 2x in both sides of the equation:

[tex]\begin{gathered} 10x+2x+14=-2x+2x+38 \\ \\ \text{Combine like terms:} \\ 12x+14=38 \end{gathered}[/tex]

2. Subtract 14 in both sides of the equation:

[tex]\begin{gathered} 12x+14-14=38-14 \\ \\ 12x=24 \end{gathered}[/tex]

3. Divide both sides of the equation into 12:

[tex]\begin{gathered} \frac{12}{12}x=\frac{24}{12} \\ \\ x=2 \end{gathered}[/tex]Then, the solution for the given equation is x=2

Find two points on the graph of this function other than the origin that fits in the given grid express each coordinate as an integer or simplified fraction or around four decimal places as necessary another coordinates to plot points on

Answers

Substitute arbitrary values of x for which -10 < h(x) < 10.

In this instance, we can use x = 1, and x = -1

[tex]\begin{gathered} h(x)=-\frac{5}{8}x^5 \\ h(1)=-\frac{5}{8}(1)^5 \\ h(1)=-\frac{5}{8} \\ h(1)=-0.625 \\ \\ h(x)=-\frac{5}{8}x^{5} \\ h(-1)=-\frac{5}{8}(-1)^5 \\ h(-1)=\frac{5}{8} \\ h(-1)=0.625 \end{gathered}[/tex]

Therefore, the points that fits in the grid in the function h(x) are (1, -0.625) and (-1, 0.625).

Make the following conversions.5 pounds 16 ounces toa. Ounces:? ozb. Pounds: ? lbNote : I have attempted 80 ounces in 1 pound as the answers and it is incorrect

Answers

In order to calculate these conversions, we need to know the following conversion rate:

1 pound is equal to 16 ounces.

Knowing that, let's convert:

a. to ounces:

[tex]5\text{ pounds 16 ounces }=5\cdot16\text{ ounces + 16 ounces}=80\text{ + 16 ounces }=96\text{ ounces}[/tex]

b. to pounds:

[tex]5\text{ pounds 16 ounces }=5\text{ pounds + 1 pound }=6\text{ pounds}[/tex]

Help me answer these thank u :)

Answers

6. -2

7.-38

8.-15

9.0

10.-13

11.-30

12.38

13.33

14.-23

These are pretty easy if you add them to your calculator.
6. -2
7.-38
8.-15
9. 0
10. -13
11. -30
12. 38
13. 33
14. -23

An asteroid is traveling at 32.0 kilometers per second. At this speed, how much time will it
take the asteroid to travel 1,040 kilometers?
Write your answer to the tenths place.

Answers

Answer:

1040 × 33.0 =

33,280

tenths= 33.3km\s

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