The greatest distance away from the initial position that an object can be if it struck by the airplane is 12.5 ft, if the initial speed of the airplane is 10 ft/s.
Initial speed of the paper airplane, u = 10 ft/s
Final speed of the paper airplane, v = 0
deceleration of the airplane, a = -4 ft/s²
By the first equation of motion, v = u -at
Time of flight, t = (v-u)/a
t = (0 - 10)/-4 = 2.5 sec
Maximum distance travelled by the airplane, = S
S = ut + 0.5at²
S = 10 × 2.5 - 0.5 × 4 × 2.5²
S = 12.5 ft
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a ferry boat shaped just like a brick is 7.7 m wide and 6.2 m long. when a truck pulls onto it, the boat sinks 5.57 cm in the water. what is the weight of the truck? the acceleration of gravity is 9.81 m/s 2 . answer in units of n.
The weight of the truck is approximately 254,979 N or 254.9 kN
To find the weight of the truck, we can use the principle of buoyancy, which states that the buoyant force exerted on an object submerged in a fluid is equal to the weight of the fluid that is displaced by the object.
First, we need to find the volume of the water displaced by the boat when the truck pulls onto it. We can use the dimensions of the boat and the amount it sinks in the water to calculate this. The boat is shaped like a brick, so we can assume it has the same dimensions on the top and bottom.
The boat's width is 7.7 m and its length is 6.2 m. The boat sinks 5.57 cm or 0.0557 m in the water.
The volume of the water displaced is the product of the boat's width, length, and the amount it sinks in the water.
Volume of water displaced = 7.7 m x 6.2 m x 0.0557 m = 25.9 m^3
Next, we can use the density of water, which is about 1000 kg/m^3 to find the weight of the water displaced.
Weight of water displaced = 1000 kg/m^3 x 25.9 m^3 = 25900 kg
Finally, we can use the weight of the water displaced to find the weight of the truck using the equation of buoyancy force which is equal to the weight of the fluid displaced.
Weight of truck = weight of water displaced x g
Weight of truck = 25900 kg x 9.81 m/s^2 = 254979 N
Therefore, the weight of the truck is approximately 254,979 N or approximately 254.9 kN.
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a body at temperature of 100f is placed in a room of temperature 50. the room temperature does not change appreciably. if after 10 minutes the temperature of the body has dereased to 90 f, when will the body be at a temperature of 60*f?
The body will be at a temperature of 60°F after around 72 minutes.
The problem can be solved using Newton's law of cooling, which states that the rate of change of temperature of an object is proportional to the difference in temperature between the object and its surroundings. Mathematically, this can be represented as:
T(t) = T_s + (T₀ - T_s) e^(-kt)
where T(t) is the temperature of the object after time t, T₀ is the initial temperature of the object, T_s is the temperature of the surroundings, t is time and k is a constant of proportionality called the cooling coefficient.
Use the initial condition T = 90°F at t = 10 min, T_s = 50°F, T₀ = 100°F to solve for the value of k.
T(t) = T_s + (T₀ - T_s) e^(-kt)
90°F = 50°F + (100°F - 50°F) e^(-k)(10)
40°F = 50°F e^(-k)(10)
e^-10k = 0.8
k = 0.0223
thus we can calculate the time it takes for the body to reach a temperature of 60°F:
T(t) = T_s + (T₀ - T_s) e^(-kt)
60°F = 50°F + (100°F - 50°F) e^(-0.0223)(t)
10°F = 50°F e^(-0.0223)(t)
e^(-0.0223)(t) = 0.2
t = 72.1721
t ≅ 72 minutes
Therefore, it would take around 72 minutes for the body to reach a temperature of 60*F.
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a point charge of 8.74 x 10-6 c is at the origin while a second point charge of -5.91 x 10-6 c is at the coordinates (0.53, 0.41) meters. in degrees relative to the positive x direction, what is the direction of the force exerted on the charge at the origin?
The direction of the force on the charge at the origin is towards the charge at (0.53, 0.41) m, since the charges have opposite signs and attract each other.
The direction of the force exerted on a point charge at the origin by a second point charge can be found using Coulomb's law, which states that the force between two point charges is proportional to the product of their charges and inversely proportional to the square of the distance between them. The formula for the force is:
F = k * q1 * q2 / r^2
where k is the Coulomb constant (8.99 x 10^9 N * m^2 / C^2), q1 and
q2 are the charges, and
r is the distance between the charges.
To find the direction, we must first find the components of the force along the x and y axes.
Then, we can use arctan to find the angle relative to the positive x direction.
The distance between the charges can be found using the Pythagorean theorem:
[tex]r = \sqrt{((0.53 m)^2 + (0.41 m)^2)[/tex] = 0.65 m
The x and y components of the force can then be found using the formula:
Fx = F * cos(θ) = k * q1 * q2 * x / r^3
Fy = F * sin(θ) = k * q1 * q2 * y / r^3
where θ is the angle between the force and the positive x direction, and x and y are the x and y components of the displacement vector between the charges, respectively.
Finally, the direction of the force can be found using arctan:
θ = arctan(Fy / Fx)
The direction of the force on the charge at the origin is towards the charge at (0.53, 0.41) m,
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a quartz crystal vibrates with a frequency of 77,621 hz. what is the period of the crystal's motion?
Formula for period:
[tex]T=\dfrac{1}{f}[/tex]
period(measured in seconds) = 1 / frequency(measured in hertz)
__________________________________________________________
Given:
[tex]f=77,621Hz[/tex]
[tex]T=?[/tex]
__________________________________________________________
Finding period:
[tex]T=\dfrac{1}{f}[/tex]
[tex]T=\dfrac{1}{77,621}[/tex]
__________________________________________________________
Answer:
[tex]\fbox{T = 0.0000129}[/tex]
a baseball player feels a frictional force of 400N as she slides into home. what impulse would be created?
The impulse that would be created by the baseball player is 600 Ns.
What is the impulse created by the baseball player?The impulse created by the baseball player is the product of force and time of the force impact.
J = Ft
where;
F is the applied forcet is the time of force actionThe frictional force created by the baseball player = 400 N.
The time of force action = 1.5 seconds
The impulse that would be created by the baseball player is calculated as follows;
J = 400 N x 1.5 seconds
J = 600 Ns
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The complete question is below:
A baseball player feels a frictional force of 400N as she slides into home. what impulse would be created if the force acted for 1.5 seconds?
while in horizontal flight at a speed of 20 m/s, a baseball of mass 0.11 kg is struck by a bat. after leaving the bat, the baseball has a speed of 29 m/s in a direction opposite to its original direction. the magnitude of the impulse given the ball is
The baseball's change in momentum is equal to the impulse applied to it. An object's momentum is determined by multiplying its mass by its velocity. The baseball received an impulse with a magnitude of -5.39 kg*m/s.
The baseball's change in momentum is equal to the impulse applied to it. An object's momentum is determined by multiplying its mass by its velocity.
The baseball's initial momentum is equal to 0.11 kg times 20 m/s, or 2.2 kg/s.
The baseball's ultimate velocity is calculated as (0.11 kilogramme) * (-29 m/s) = -3.19 kgm/s.
The difference between the baseball's final and starting velocities, or its change in momentum, is equal to 5.39 kg*m/s (final momentum - beginning velocities = -3.19 kgm/s - 2.2 kgm/s).
As a result, the baseball received an impulse with a magnitude of -5.39 kg*m/s.
Due to the ultimate velocity being in the opposite direction of the original vector, the impulse is negative.
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medical x-rays have a wavelength of 0.052 nm. calculate the frequency of light, in hz (1/s), that this wavelength corresponds to?
The frequency of the light is 5.77 × 10¹⁸ Hz, if the wavelength of the x-rays is 0.052 nm.
Wavelength of the x-ray, λ = 0.052 nm = 5.2 × 10⁻¹¹ m.
Speed of x-rays, v = 3 × 10⁸ m/s
Let the frequency of the x-ray, = n
We know the relationship between speed of the wave, wavelength and the frequency of the wave is as follows:
speed = wavelength × frequency
3 × 10⁸ = 5.2 × 10⁻¹¹ × n
n = (3 × 10⁸)/(5.2 × 10⁻¹¹)
n = 5.77 × 10¹⁸ Hz
Alternate unit of frequency is 1/sec.
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the terminals of a 15 v battery. after a long time, the capacitor is disconnected from the battery but is not discharged. what are the charge on each electrode, the electric field strength inside the capacitor, and the potential difference between the electrodes a. right after the battery is disconnected? b. after insulating handles are used to pull the electrodes away from each other until they are 1.0 cm apart? c. after the original electrodes (not the modified electrodes of part b) are expanded until they are 20 cm in diameter?
After the original electrodes 0.8nC are expanded until they are 20 cm in diameter.
What is meant by diameter?
A line that is straight and cuts through the middle of a body or figure. Particularly: the length of a diameter; a line segment passing through the centre of a circle with its ends on the circumference.It is twice as long as a circle's radius, or Diameter = 2 Radius.The diameter of a circle cuts through the centre whereas the radius extends from the centre to the edges of the circle. The diameter of a circle effectively divides the shape in two.The diameter or length of a circle is its circumference. A straight line connecting a point on one end of the circle to a point on the other end, passing through the centre, is the diameter.To learn more about diameter refer to
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what is the process of splitting a uranium atom called?
a. Nuclear Fusion
b. Nuclear Fission
c. Nuclear Confusion
d. Nuclear Dillusion
Nuclear fission produces energy when atoms split apart. All nuclear power plants utilise nuclear fission, and uranium atoms are frequently employed in nuclear power reactors.
When a neutron meets with a uranium atom during nuclear fission, it splits the atom, releasing a large amount of energy in the form of heat and radiation. Nuclear fission, another name for the splitting of atoms, generates radiation and radioactivity. In 1939, Dr. Lise Meitner made the discovery of how radioactivity may be created. She discovered that radiation could be released when a neutron, a tiny particle, was fired into another atom. Fission is the process by which a heavy, unstable nucleus splits into two lighter nuclei, whereas fusion is the joining of two light nuclei to release large amounts of energy.
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at a specific moment, a falling object with mass 4 kg is moving 7 m/s and is 3 meters above the ground. how many joules of mechanical energy does the object have?
A falling item with a mass of 4 kg is 3 metres above the earth and is travelling at a speed of 7 m/s at that precise time. The item has a mechanical energy of 216.4 Joules.
A falling object's kinetic energy (KE) and potential energy may be used to compute its mechanical energy (PE).
KE = 1/2 mv ²
= 1/2 X 4 X 14 = 98
where m is the item's mass and v is its velocity,
The equation PE = m * g * h gives the potential energy of an item.
PE = 4 X 9.8X 3 = 117.6
E = KE + PE gives the object's total mechanical energy.
E = 98 + 117.6
= 215.6 J
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note that in this arrangement, the net charge is zero (so we expect no monopolar field far away). the two visible dipoles also cancel, so we expect no dipolar field far away. what might we call the first surviving term in the distant field?
The first surviving term in the distant field in this situation might be referred to as a quadrupolar field.
The Distant Field SituationThe determination that the first surviving term in the distant field is a quadrupolar field is based on the fact that the net charge and the visible dipoles in the arrangement cancel out, leaving no monopolar or dipolar fields.
A quadrupole is a distribution of charges in which there are two positive and two negative charges of equal magnitude and opposite sign, arranged symmetrically about a central point.
A quadrupole generates a quadrupolar field, which falls off as the inverse cube of the distance from the source, as opposed to the inverse square of the distance for a dipole.
So when a net charge and dipoles are cancelled, the next term that could survive is the quadrupolar term.
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if dust deosnt have an intitial charge , then how can a charged object(such as a piece of paper) attract bits of dust, since coulombs law states tgat two different charges are needed for an attractive force?
Dust particles can acquire a charge through a process called triboelectrification, which occurs when two materials rub against each other, transferring electrons from one material to the other.
What is triboelectrification?Triboelectrification is the phenomenon in which a charge is generated through the contact and separation of two materials. It is also known as "friction electrification" or "contact electrification".
When dust particles rub against a piece of paper, transferring electrons from the dust particles to the paper and giving the dust particles a negative charge. Once the dust particles have acquired a charge, they can be attracted to a charged object, such as a piece of paper, through Coulomb's law, which states that objects with opposite charges will experience an attractive force.
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An aircraft decelerate at 0.5 m/.after 8 minute it velocity ha dropped to 160 m/ .find it initial velocity.
Acceleration (a) is the change in velocity (Δv) versus the change in time (Δt), given by the formula a = Δv/Δt. This allows you to measure how quickly the velocity changes in meters per second (m/s^2). Acceleration is also a vector quantity, so it contains both magnitude and direction. Negative acceleration is termed as deceleration
Deceleration can be calculated by dividing the final velocity minus the initial velocity by the time it takes for this velocity to drop.
The known and unknown quantities from the question are as follows:
u = initial velocity = ? m/s
v = final velocity = 160 m/s
a = acceleration = -0.5 m/s²
t = time interval = 8 min × 60 s/1 min = 480 s
Calculate the initial velocity using the following kinematic equation.
v = u + at
Solve for u.
u = v - at
u = 160 m/s - (-0.5 m/s² × 480 s) = 400 m/s
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A black suv was driving east on Ridge, as the suv drove through an intersection on a green light it was immediately hit by a silver 4 door sedan. The black suv was hit on the driver's side, the suv spun halfway around and pushed on the sidewalk. Explain why the suv gets pushed and jumps the crib
Answer:
The black suv gets pushed and jumps the curb because of the momentum the silver sedan had during impact.
Explanation:
Because the silver sedan ran the light and hit the black suv at full speed, the momentum from the sedan will have enough force to push the black suv into the curb.
A rock is thrown horizontally from a height of 6.00 m. what
is the time required for the rock to reach the ground
The time required for the rock to reach the ground is 1.11 second.
What is acceleration?
Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).
Initial height of the rock: h = 6.00 m.
Acceleration due to gravity: g = 9.8 m/s²
Let, the time required for the rock to reach the ground is = t.
Then:
h = 1/2 × gt²
t = √(2h/g)
= √ {(2 × 6.00)/9.8} second.
= 1.11 second.
Hence, the time required for the rock to reach the ground is 1.11 second.
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A small car (1400 kg) moving 35 m/s gradually comes to a complete
stop when the brakes are applied. It comes to a complete stop over a
period of 15.2 seconds. What is the force in newtons that is exerted
on the car during this time? (Remember, the force is negative
because it is exerted opposite to the motion).
The force in newtons that is exerted on a car during the given time is 3,223.68N.
How to calculate force?Force refers to a physical quantity that denotes ability to push, pull, twist or accelerate a body.
The force exerted on an object can be calculated by multiplying the mass of the body by the acceleration as follows:
Force = mass × acceleration
Force = mass × speed/time
According to this question, a small car (1400 kg) moving 35 m/s gradually comes to a complete stop when the brakes are applied. It comes to a complete stop over a period of 15.2 seconds.
Force = 1400 × 35/15.2
Force = 3,223.68N
Therefore, 3,223.68N is the force acting on the small car.
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Two people push on a shopping cart from opposite sides. In which situation
will the motion of the shopping cart stay the same?
A. The two people push with different amounts of force.
B. One of the people stops applying a force.
C. One of the people applies twice as much force.
D. The two people push with a balanced
face
Two people push on a shopping cart from opposite sides. Situation will the motion of the shopping cart stay the same, the correct option is (D) The two people push with a balanced face.
In this situation, the net force on the shopping cart will be zero, since the two forces are equal in magnitude and opposite in direction. If the forces are balanced, the shopping cart will not accelerate and will stay in the same state of motion (at rest or moving at a constant velocity). In scenario A and C, the forces are not balanced and therefore will cause acceleration. In scenario B, the net force will be non-zero and the acceleration will cause the shopping cart to change its velocity and direction.
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what is the magnitude and direction of the electric force on an electron ina uniform electric field of strenght 2360n/c that points due east
The magnitude of the electric force on the electron is 2360 N and it points due east.
What is electric force?Electric force is an attractive or repulsive force between two particles that have an electric charge. This force is generated when two charged particles interact due to their charges. The strength of the electric force depends on how much charge each particle has, as well as their distance from each other. Electric forces are responsible for phenomena such as static electricity and lightning, and they can also be used to power electric motors and other devices.
This is because an electric field exerts a force on a charged particle in the direction that is opposite to the direction of the field. Since the electric field points due east, then the force on the electron will point due west.
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a person walks first at a constant speed of 5.10 m/s along a straight line from point circled a to point circled b and then back along the line from circled b to circled a at a constant speed of 3.30 m/s. (a) what is her average speed over the entire trip?
The average speed of that person with two constant speed for a certain distance is 4 m/s.
How to calculate average speed over the entire trip?Assume the distance from point a and b is c, As per data given velocity from a to b = 5.10 m/sec. So,
time a to b = c : 5.10.
Since the constant speed is 3.3. then
time b to a = c : 3.30
The we can determine the average speed as follow:
Total distance = c + c = 2c
Total time = time a to b + time b to a
Total time = c : 5.10 + c : 3.30
Total time = 0.196c + 0.303c
Total time = 0.499c
Average speed = total distance : total time
Average speed = 2c : 0.499c
Average speed = 4.00801603206
Let round the result, so the average speed = 4 m/s
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The spring-held follower AB has a mass of 0. 45 kg and moves back and forth as its end rolls on the contoured surface of the cam, where r = 0. 15 m and z=(0. 02cos2θ)m. The cam is rotating at a constant rate of 30 rad/s. The spring is uncompressed when θ = 90∘
The body and through a specific angle experience angular accelerations of 0.87266 rad/sec2 and 12566.8 rad, respectively.
Calculate angular acceleration ?A rotating rigid body's angular velocity rises from 500 to 1500 rev/min under the given conditions.
Time= 120s
Finding - Angle and angular acceleration
The basic idea is that we must change rev/min to rad/sec.
ωf= ωi + αt
ωf- ωi = αt
Formula for angular acceleration: = [f- i]/t
Angle deviation formula: =it + t2/2
Calculations-
Rev/Min to rad/Sec conversion
I equals 500 rev/min
500 x 2 rad/rev x 1 minute and 60 seconds equals 52.3598 rad/sec.
f = 1500 rev/min
=1500 x 2 rad/rev x 1 minute and 60 seconds = 157.079 rad/sec
52.3598 rad/sec for I
ωf=157.079rad/sec
Now, to calculate angular acceleration, use the formula: [f- i]/t.
52.3598 rad/sec − 157.079 rad/sec = 120
1.872666 rad/sec
To calculate the angle deviated, enter -=i t + t2/2.
=52.3598 x 120 + [0.87266 x 120 x120]/2
ΔФ= 12566.8rad
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1. A student is sitting on the edge of a swimming pool. The student repeatedly dips his foot in and out of the pool, making waves that move across the water. The student dips his foot slowly at first and then does it faster, each time to the same depth. Which of the following properties of the waves increases as the student dips his foot faster?
A. frequency
B. period
C. velocity
D. wavelength
Frequency of the waves increases as the student dips his foot faster.
What is frequency?
Frequency is a measure of how often something occurs over a given period of time. It can be used to measure the rate of events, such as the number of times a sound or light wave occurs in a given second. Frequency is measured in hertz (Hz), which is the number of occurrences per second. Frequency can also refer to the number of times a certain event occurs in a given sample size, such as the number of times a person visits a website in a month. It is a common measure used in statistics and is often used to compare data sets.
Therefore, Frequency of the waves increases as the student dips his foot faster.
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1. A quarterback passes a football at a velocity of 15.2 m/s at an angle of 40° to the horizontal
toward an intended receiver 27.4 m downfield. The pass is released 1.3 m above the ground. Assume
that the receiver is stationary. Does he catch the ball to complete the pass if he were to catch the ball
at the same height it is released?
The intended receiver did not receive the ball since the ball travelled a shorter distance.
What is the time of motion of the ball?
The time of motion of the ball is calculated by applying the following formula as shown below.
h = vt + ¹/₂gt²
where;
v is the velocity of the ballg is the acceleration due to gravityt is the time of motion1.3 = ( 15.2 x sin40 )t + ¹/₂ ( 9.8 )(t²)
1.3 = 9.8t + 4.9t²
4.9t² + 9.8t - 1.3 = 0
solve the quadratic equation suing formula method;
t = 0.13 second
The horizontal distance of the ball is calculated as;
d = Vₓt
d = ( 15.2 x cos 40) x 0.13
d = 1.51 m
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asportscar, electro-fiasco i, can accelerate uniformly to 100 km/h in 3.5 s. its maximum braking rate can not exceed 0.7g. what is the minimum time required to go 1.0 km, assuming it begins and ends at rest?
The minimum time required to travel 1.0 km is 8.75 seconds.
What is travel?Travel is the movement of people from one place to another, usually over a certain distance and for a certain period of time. It can be done for many reasons, including pleasure, business, or to visit family or friends.
This can be calculated by taking the total distance traveled (1.0 km) and dividing it by the average speed (100 km/h). The average speed is 100 km/h because the car accelerates uniformly from 0 km/h to 100 km/h in 3.5 seconds.
Therefore, the total time required is 10 seconds (1 km / 100 km/h). However, this does not take into account the deceleration time of the car, which must also be taken into account.
The maximum braking rate of the car is 0.7 g, which is equivalent to 7 m/s2. Since the car must come to a complete stop at the end of the 1.0 km journey, the time required for deceleration must be calculated. This can be done using the equation:
Time for deceleration = (Final Velocity - Initial Velocity) / Acceleration
Since the initial velocity is 0 m/s and the final velocity is 0 m/s, the equation simplifies to:
Time for deceleration = 0 / 7 m/s2 = 0 seconds
Therefore, the total time required to travel 1.0 km is 10 seconds (for acceleration) + 0 seconds (for deceleration) = 10 seconds. Subtracting this from the total time required gives us the minimum time required to travel 1.0 km, which is 8.75 seconds.
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A 60 kilogram person jumps off a platform, landing while moving at 2. 0 meters per second. Determine the force exerted on the persons feet when he lands if he stops in 0. 25 seconds
The force exerted on the person's feet when he lands if he stops in 0. 25 seconds is found to be 480 N.
What is Force?Force may be characterized as a type of circumstance that significantly deals with the pushing or pulling of an object resulting from the object's interaction with another object. Whenever there is an interaction between two objects, there is a force upon each of the objects.
According to the context of this question,
The mass of a person, m = 60 Kg.
The velocity of a person, v = 2.0 meters/sec.
The time is taken, t = 025 seconds.
The formula for calculating force is as follows:
F = mv/t.= 60 × 2 ÷ 0.25 = 480 N.
Therefore, the force exerted on the person's feet when he lands if he stops in 0. 25 seconds is found to be 480 N.
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a) Two tugboats are towing a tanker of mass 3.30 x 107 kg. If one tug is pulling at 2.40 X 104 N [E16°N] and the other is pulling at 2.40 x 104 N [E9°S], calculate the acceleration of the tanker, assuming no resistance. Use both vector methods to solve this part of the problem.
b) If the tanker has a resistive force on it of 5.60 x 10³ N, find its acceleration using the component method.
c) Calculate the speed reached in each of the two cases after 2.0 minutes. Convert it to km/h.
d) Calculate the distance required in each case to reach a speed of 5.0 km/h.
So the net force acting on the tanker is: F_net = sqrt(Fx^2 + Fy^2) = 2.4 x 10^4 N And the acceleration of the tanker is: a = F_net / m = 2.4 x 10^4 N / 3.3 x 10^7 kg = 7.27 x 10^-4 m/s^2.
How to calculate net force and acceleration?
To find the acceleration of the tanker using vector methods, we can use the following equation:
F_net = ma
where F_net is the net force acting on the tanker, m is the mass of the tanker, and a is the acceleration of the tanker.
In this case, the two tugboats are pulling in opposite directions, so we need to find the vector sum of their forces to find the net force acting on the tanker.
Using the component method, we can find that the x-component of the net force is:
Fx = 2.4 x 10^4 N * cos(16) - 2.4 x 10^4 N * cos(9) = -2.4 x 10^4 N
and the y-component of the net force is:
Fy = 2.4 x 10^4 N * sin(16) + 2.4 x 10^4 N * sin(9) = 0 N
So the net force acting on the tanker is:
F_net = sqrt(Fx^2 + Fy^2) = 2.4 x 10^4 N
And the acceleration of the tanker is:
a = F_net / m = 2.4 x 10^4 N / 3.3 x 10^7 kg = 7.27 x 10^-4 m/s^2
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a skier starts from rest on the higher peak. at what speed would she arrive at the lower peak if she just coasted without using poles? assume there is no friction.
The kinetic friction observed by skier when he starts from rest on the higher peak is 0.0.0313.
Here is the information we need:
h1 denotes the starting height (850 m)
The final height is given by h2 (750 m)
is the inclination angle (30°)
k is the kinetic friction coefficient.
The total distance traveled is given by d.
The distance traveled downward is denoted by d1.
The distance traveled uphill is denoted by d2.
Where:
d=d1 + d2 =h1/sin + h2/sin =850/sin30+750/sin30
=3200 m
Because the skier begins and ends at rest, the change in kinetic energy is zero.
When traversing a distance d, the energy dissipated by kinetic friction (negative sign) is equal to the change in gravitational potential energy.
[h2-h1]k =h1-h2d
=850-750/3200
=0.0313
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Complete question : Two snow-covered peaks are at elevations of 850 and 750 m above the valley between them. Both elevations have an incline of 30 degrees. A ski-run extends from the top of the higher peak to the top of the lower one. A skier starts from rest on the higher peak and stops on top of the lower peak. What is the kinetic friction coefficient?
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Thermal conductivity may be measured with simple equipment.A slab of the material to be tested is clamped between an ice block and a steam chamber that both maintain constant temperatures of 0 °C and 100 °C.
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why (if you are careful) are you able to float a needle on the surface of water?water has adhesive properties.
Floating a needle on the surface of water is possible because of the phenomenon known as surface tension.
Surface tension occurs when molecules of a liquid stick together, creating a thin film of liquid on the surface. This film is able to support objects that are light enough to float.
The adhesive properties of water are due to its molecules bonding together, creating a strong force that allows it to hold objects on its surface. When a needle is placed carefully on water, it is light enough to be supported by the surface tension and the needle will float.
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a 2.0-mm-diameter glass bead is positively charged. the potential difference between a point 2.0 mm from the bead and a point 4.0 mm from the bead is 500 v. what is the charge on the bead?
The glass bead has a 0.001 m radius. The distance between the first and second points from the bead's center is 0.003 and 0.005 meters, respectively.
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what are tiny solid and liquid particles of matter suspended in the atmosphere?
Answer:
I think the answer you're looking for is particulate matter.
Explanation: