You may have noticed that all the elements in the first column of the periodic table, the alkali metals, have a 1 charge when they combine with negative ions. Another group of positive ions are the alkaline earth metals located in the second column of the periodic table. What charge is typical for ions of the alkaline earth metals?

Answers

Answer 1

Answer:

The charge that is typical for ions of the alkaline earth metals is +2

Explanation:

Group 1 elements (alkali metals such as Li, Na, K...) all have one valence electron that they donate when forming ionic bonds. This will cause them to have a charge of +1.T he alkaline earth metals (Ca, Mg) have two valence electrons they donate which means their charge when forming ions is +2. The members of the aluminum family lose three electrons giving them a charge of +3.


Related Questions

What inference can be drawn from the graph? a graph of reactant and product concentration vs. time; a red curve shows the reactant decreasing and a blue curve shows the product concentration increasing over time; the two curves do not intersect; the chemical equation shows A + B reacting to produce C + D A. The reaction between A and B is reactant favored. B. The amount of product is greater than the amount of reactant. C. The reaction uses all its reactants to form products. D. The reaction reaches equilibrium at 1.5 seconds. E. The amount of reactants is highest at equilibrium.

Answers

The reaction between A and B is reactant favored. This  inference can be drawn from the graph.

Chemical reactions occur all around us, including in our body's digestion of food and the creation of the sunlight's light. Understanding both chemical and physical alterations is crucial before starting any chemical reactions. The best illustration of a chemical and physical alteration is a burning candle. The reaction between A and B is reactant favored. This  inference can be drawn from the graph.

Therefore, the correct option is option A.

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1. (16 points) Shown below are IR and MS data for a compound with a molecular formula of C3H₂O
a) Identify the functional groups
responsible for the labeled
absorptions in the IR spectrum.
i) 1601 cm¹
ii) 1691 cm¹
Relative Intensity
100-
80-
m/z
rel. Intensity
22.6
73.1
105 100.0
120
26.2
$1.0
77.0
50 60
TRATT
100 110 120
1601 cm
1691 cm³
iii) From the parent,
what mass is lost to form
the base peak at m/z =
105?
iv) What is the likely
structure of that
fragment that is lost
to form m/z 105?
70
m/z
v) From the parent, what mass is lost to form the m/z = 77 peak?

Answers

a) Based on the IR spectrum, the functional groups responsible for the labeled absorptions are:

i) 1601 cm⁻¹: This absorption indicates the presence of an unsaturated carbonyl group, such as a conjugated or isolated enone.

ii) 1691 cm⁻¹: This absorption indicates the presence of a saturated carbonyl group, such as a ketone or aldehyde.

iii) The base peak at m/z = 105 suggests the loss of a fragment with a mass of 28 (105 - 77). This mass corresponds to the loss of a carbon monoxide (CO) group.

iv) The likely structure of the fragment lost to form m/z 105 is a carbonyl group (C=O).

v) The peak at m/z = 77 suggests the loss of a fragment with a mass of 28 (105 - 77). This mass corresponds to the loss of a methyl group (CH₃). Therefore, the parent compound might contain a methyl group that is lost to form the peak at m/z = 77.

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et D Q.No. 9 Convert 1-bromopropane to 2-bromopropane.[2]​

Answers

1-bromopropane can be converted to 2-bromopropane through a substitution reaction with sodium iodide in acetone.

Conversion of 1-bromopropane to 2-bromopropane

One possible method to convert 1-bromopropane to 2-bromopropane is through a substitution reaction with sodium iodide (NaI) in acetone. The following procedure can be followed.

Dissolve 1-bromopropane and sodium iodide in dry acetone in a round-bottom flask.Reflux the mixture for several hours with stirring and heating to about 50-60°C. This allows for the formation of an alkyl iodide intermediate.After cooling the reaction mixture, add water to it and extract the organic layer with a separating funnel.Dry the organic layer with anhydrous sodium sulfate (Na2SO4) and filter it to remove any solid impurities.Concentrate the organic layer by distillation under reduced pressure to obtain 2-bromopropane as a product.

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Numbers placed in front of formulas in an aquation are called

Answers

The numbers placed in front of formulas to balance equations are called coefficients, and they multiply all the atoms in a formula.

HELP ME PLEASE!! I NEED HELP ANSWERING THESE!!

Answers

1) Indium and aluminum belong to the same group.

2) Barium belongs to groups 2 and 6

The periodic table is what?

The compounds' names are;

Tetrachloro phosphorus chloride

Calcium bromide

Hexasulfur nitrogen

The following molecules balance the charges:

K3P, CaS, Al2O3

Chlorine and fluorine are elements of group 17

Magnesium and salt are the components that make up period 3.

The data are used to create the balanced equations;

Sn + 2H2O = SnO2 + H2

3O2 + 4Al = 2Al2O3

2Au + 3H2S = Au2S3 + 3H2

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a) If the chemical formula for iron (III) chloride is FeCl 3 , what is the chemical formula for iron (III) nitrate?b) If the chemical formula for lead (II) oxide is PbO, what is the chemical formula for lead (II) sulfate?c) If the chemical formula for silver chloride is AgCl, what is the chemical formula for silver nitrate?

Answers

a) The chemical formula for iron (III) nitrate is Fe(NO₃)₃. b) The chemical formula for lead (II) sulfate is PbSO₄. c) The chemical formula for silver nitrate is AgNO₃.

In chemical nomenclature, the Roman numeral in the name of the compound indicates the oxidation state of the metal ion. To determine the chemical formula of a compound, it is important to balance the charge of the ions in the compound. In the case of iron (III) nitrate, the iron ion has a +3 charge and the nitrate ion has a -1 charge, so it takes three nitrate ions to balance the charge of the iron ion.

In the case of lead (II) sulfate, the lead ion has a +2 charge and the sulfate ion has a -2 charge, so it takes one lead ion and one sulfate ion to balance the charges. Similarly, in the case of silver nitrate, the silver ion has a +1 charge and the nitrate ion has a -1 charge, so it takes one of each to balance the charges.

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WILL MARK BRAINLIEST
Potential in a different kind of cell.  
A typical mammalian cell at 37


C, with only potassium channels open, will have the following equilibrium:
K+ (intracellular)   ⇌  K+ (extracellular),
with an intracellular concentration of 150 mM K+, and 4.0 mM K+ in the extracellular fluid.
What is the potential, in volts, across this cell membrane?  Note: in this case, n = the charge on the ion, and Eo for a concentration cell = 0.00 V. Please explain how to solve

Answers

Answer:

the potential across this cell membrane is -0.082 volts, with the inside of the cell being negative relative to the outside.

Explanation:

The Nernst equation can be used to calculate the equilibrium potential (in volts) for a given ion across a membrane, given the concentration of the ion inside and outside the cell:

E = (RT/zF) ln([ion]out/[ion]in)

where E is the equilibrium potential, R is the gas constant (8.314 J/mol*K), T is the temperature in Kelvin (37+273=310 K), z is the charge on the ion (+1 for K+), F is the Faraday constant (96,485 C/mol), [ion]out is the extracellular concentration of the ion (4.0 mM for K+), and [ion]in is the intracellular concentration of the ion (150 mM for K+).

Plugging in these values:

E = (8.314310/196485) ln(4.0/150)

E = -0.082 V

Therefore, the potential across this cell membrane is -0.082 volts, with the inside of the cell being negative relative to the outside.

1. Calculate the % H₂O for each of the following hydrated metal salts?
1. Molecular formula: CaSO4 * 2 H₂O, % water: ???
2. Molecular formula: CoCl2 * 6 H₂O, % water: ???
3. Molecular formula: CuSO4* 5 H2O, % water: ???
4. Molecular formula: MgSO4 * 7 H₂O, % water: ???

2. Based on your Experimental Calculations from the Data Sheet, what is the identity of
your unknown. (Choose from one of the four choices above).

3. What is the % error? (Use only one of your trials for your calculation.)

Answers

The percentage composition of the water of hydration for each compound is shown below.

Percentage of water of hydration

The percentage of water of hydration, also known as percent water of crystallization, is a measure of the amount of water that is chemically bound to a salt or other compound as part of its crystal structure.

1) For CaSO4 * 2 H₂O

36/172 * 100/1

= 21%


For CoCl2 * 6 H₂O

108/238 * 100/1

= 45%

For CuSO4* 5 H2O

90/250 * 100/1

= 36%

For MgSO4 * 7 H₂O

126/246 * 100/1

= 51%

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please answer this question if any one knows

Answers

Based on the information, the solubility product of AgCl is 6.91 × 10^-10.

How to explain the information

The common ion effect concerns the decrease in solubility of a salt when it comes into contact with another compound containing an identical ion within its make-up. This phenomenon is caused by the dependetics that arise from this shared element, which results in a decreasing amount of ions required for dissolving said salt. An illustrative instance is seen when observing the effects of calcium chloride (CaCl2) on calcium sulfate (CsSO4).

Named reactions constitute a subclass of chemical interchanges widely used within organic chemistry. These yield profound utilization due to their notorious titles attributed to notable scientists or related to other respective exploits; they are thus named following mannerisms peculiar to the substance itself.

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3.20 g is the measurement of which of the following.

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3.20 g is the measurement of mass.

Mass is a measure of the amount of matter in an object, and is typically expressed in grams (g), kilograms (kg) or pounds (lb). Mass is an intrinsic property of an object, meaning it is independent of its environment.

Mass is measured using a balance or scale, which compares the mass of an object to a known standard. In the case of 3.20 g, this would be the mass of an object compared to the mass of a reference object, such as a kilogram.

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The formation of magnesium bromide from Mg and Br2 is represented in the particle diagram. Which of the following statements about the reaction is correct?

Answers

Based on the particle diagram provided and the given statements, the correct statement about the reaction is; Mg is oxidized because it loses two electrons as it forms Mg²⁺. Option A is correct.

In the particle diagram, Magnesium (represented as Mg) loses two electrons, indicated by the arrows pointing away from the Mg particle. This means that Mg undergoes oxidation, as it loses electrons and its oxidation state increases from 0 to +2 when it forms Mg²⁺. Oxidation is defined as the loss of electrons or an increase in oxidation state.

On the other hand, Br₂ (represented as Br Br) gains two electrons, indicated by the arrows pointing towards the Br Br particles. This means that Br₂ undergoes reduction, as it gains electrons and its oxidation state decreases from 0 to -1 when it forms Br⁻. Reduction is defined as the gain of electrons or a decrease in oxidation state.

Hence, A. is the correct option.

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--The given question is incomplete, the complete question is

"'Mg Br Mg? Br Br Br The formation of magnesium bromide from Mg ad Brz is represented in the particle diagram. Which of the following statements about the reaction is correct? A) Mg is oxidized because it loses two electrons as it forms Mg²⁺? B) Mg is reduced because it gains two electrons as it forms Mg? C) Br is oxidized because it gains an electron as it forms Br Br is reduced because it loses proton as it forms Br J3DE'."--

Answer: Mg is oxidized because it loses two electrons as it forms Mg²⁺

Explanation:

what statement is true about the potential energy diagram for an exothermic reaction?

Answers

It is in the exothermic reaction, system loses heat to surroundings. Since heat is given out in exothermic reactions, enthalpy of products will be less than that of the reactants. Products have less potential energy than reactants for exothermic reactions.

The chemical reactions which proceed with the evolution of heat energy are called the exothermic reactions. The energy hump corresponds to the energy barrier existing between the reactants and products in an exothermic reaction.

From the energy diagram of an exothermic reaction, products have less potential energy than the reactants.

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actetic acid only partially ionizes in water

Answers

Acetic acid only partially ionizes in water as it is a weak acid.

Weak Acids are the acids that do not completely dissociate into their constituent ions when dissolved in solutions.

When dissolved in water, an equilibrium is established between the concentration of the weak acid and its constituent ions.

Acetic acid, also known as ethanoic acid, is a weak acid with the chemical formula CH₃COOH. It is known to be the active component of vinegar.

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The equilibrium constant, K, for the synthesis of ammonia
N₂(g) + 3H₂(g) <—>2NH3(g)
is approximately 44005 at 127 °C.

What is the value of K, for the decomposition of ammonia at 127 °C, as described by the following equation?
NH3 (g)<—> 1/2N₂(g) + 3/2 H₂(g)

Answers

The value of K, for the decomposition of ammonia at 127 °C is 2.27x10⁻⁵

Understanding Equilibrium Constant

The Equilibrium Constant is denoted by K and it is a quantitative measure of the extent to which a chemical reaction reaches equilibrium.

It is defined as the ratio of the concentrations (or partial pressures) of the products to the concentrations (or partial pressures) of the reactants, with each concentration or partial pressure raised to a power equal to its stoichiometric coefficient in the balanced chemical equation.

For a general chemical equation:

aA + bB ⇌ cC + dD

The equilibrium constant expression is written as:

K =  [tex]\frac{[C]^c[D]^d}{[A]^a[B]^b}[/tex]

where [A], [B], [C], and [D] represent the molar concentrations (or partial pressures) of the reactants and products at equilibrium, and a, b, c, and d represent their stoichiometric coefficients in the balanced chemical equation.

Back to our main question, the equilibrium constant for the reverse reaction (decomposition of ammonia) can be obtained from the equilibrium constant of the forward reaction (synthesis of ammonia) using the relationship:

Kreverse = 1 / Kforward

where Kforward is the equilibrium constant for the synthesis of ammonia.

Substituting the given value of Kforward:

Kreverse = 1 / 44005 = 0.0000227

In standard form, we have 2.27x10⁻⁵

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Another component of acid rain is nitric acid, which forms when NO2, also a pollutant, reacts with oxygen and water according to the simplified equation 4NO2(g)+O2(g)+2H2O(l) → 4HNO3(aq) The generation of the electricity used in a medium-sized home produces about 16 kg of NO2 per year. Part A Assuming that there is adequate O2 and H2O, what mass of HNO3, in kg, can form from this amount of NO2 pollutant? Express the mass to two significant figures and include the appropriate units

Answers

The mass of [tex]HNO_3[/tex] that can form from 16 kg of [tex]NO_2[/tex] pollutant is 22 kg

The balanced equation for reaction between [tex]NO_2[/tex], oxygen, and water to form nitric acid :

[tex]4NO_2[/tex](g) + O2(g) + [tex]2H_2O[/tex](l) → [tex]HNO_3[/tex](aq)

Molar mass of [tex]NO_2[/tex] is 46.01 g/mol, so :

16 kg / 46.01 g/mol = 347.77 mol of [tex]NO_2[/tex]

We see that for every 4 moles of [tex]NO_2[/tex], 4 moles of [tex]HNO_3[/tex] are produced.

Therefore, number of moles of [tex]HNO_3[/tex] produced from 347.77 mol  [tex]NO_2[/tex] is:

moles of [tex]HNO_3[/tex] =[tex]4/4 * 347.77\ mol = 347.77\ mol[/tex]

The mass of [tex]HNO_3[/tex] produced is:

mass of [tex]HNO_3[/tex] = 347.77 mol x 63.01 g/mol = 21.92 kg

Rounding to two significant figures and including the appropriate units, the mass of [tex]HNO_3[/tex] that can form from 16 kg of [tex]NO_2[/tex] pollutant is 22 kg.

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Choose the best term or phrase to fill in the blanks in the sentences below. Not all answer choices will be used. Question 10 options: (2) The probability that these parents will have an offspring affected with sickle cell anemia is ______ percent. (3) The probability that their offspring would also be a carrier like them is ______ percent (1) The image shows the cross between two parents who are carriers for sickle cell anemia, a recessive genetic disorder that affects the red blood cells in humans. Both parents are considered to be ______________.

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The image shows the cross between two parents who are carriers for sickle cell anemia, a recessive genetic disorder that affects the red blood cells in humans. Both parents are considered to be carrier.

The scientific study of inheritance and genes is covered in this page, along with details on the structure of DNA, chromosomes, gene variants, and the evolution of living beings and their genomes.

(1) The image shows the cross between two parents who are carriers for sickle cell anemia, a recessive genetic disorder that affects the red blood cells in humans. Both parents are considered to be carrier. (2) The probability that these parents will have an offspring affected with sickle cell anemia is 50 percent.  (3) The probability that their offspring would also be a carrier like them is 50 percent.

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Determine what is wrong with (a), (b),(c),(d). Lewis structure and write the correct structure.

Draw the molecule by placing atoms on the grid and connecting them with bonds. Include all lone pairs of electrons.

Answers

In (a) the octet rule is  not satisfied

In (b) Si does not satisfy the octet rule

In (d) N does not satisfy the octet rule

What is the Lewis structure?

Every valence electron is represented as a dot, while pairs of shared electrons between atoms in a covalent connection are represented by lines.

The Lewis structure helps to predict the geometry and properties of a molecule, as well as the nature of the chemical bonds between atoms.

The issues with each of the Lewis structures have been shown above.

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explain the shapes of simple molecules​

Answers

Answer:

Simple molecules, also known as covalent molecules, are made up of two or more non-metal atoms that share electrons to form a covalent bond. The shape of a simple molecule is determined by the arrangement of its atoms in space, which is influenced by the number of electron pairs surrounding the central atom and the repulsion between them.

In general, there are two types of electron pairs: bonding pairs and non-bonding pairs (also known as lone pairs). Bonding pairs are shared between two atoms and create a strong bond that holds the molecule together. Non-bonding pairs are not shared and exert a repulsive force on the other electron pairs in the molecule.

The repulsion between electron pairs determines the shape of the molecule. For example, if a molecule has two electron pairs (a bonding pair and a non-bonding pair), they will arrange themselves as far apart as possible, which results in a linear shape. If a molecule has three electron pairs (two bonding pairs and one non-bonding pair), they will arrange themselves in a trigonal planar shape. If a molecule has four electron pairs (three bonding pairs and one non-bonding pair), they will arrange themselves in a tetrahedral shape.

Overall, the shape of a simple molecule is determined by the number of electron pairs and the repulsion between them.

can you please answer these

Answers

The balanced reactions are;

NH3 (aq) + HBr (aq) → NH4Br (aq)

PO4^3-(aq) + H3O^+(aq) ----> HPO4^2- (aq)+ H2O(l)

HS^-(aq) + OH^-(aq) ----> H2O(l) + S^2-(aq)

What is a conjugate acid/base?

A conjugate acid/base pair consists of two species that are distinct from one another by one proton. The base is the species that can accept a proton, and the acid is the species that can donate a proton. When a base takes a proton, it changes into an acid, and when an acid gives a proton, it changes into a base.

In reaction (1) above, the conjugate acid of NH3 is NH4^+ while the conjugate base of HBr is Br^-.

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You have 400,000 atoms of a radioactive substance. After 3 half-lives have past, how many atoms remain? Remember that you cannot have a fraction of an atom, so round the answer to the nearest whole number.

Answers

Answer:

Explanation:

The number of atoms that remains after 3 half-lives given that it was originally 300000 atoms is 37500 atoms

Data obtained from the question

Original amount (N₀) = 300000 atoms

Number of half-lives (n) = 3

Amount remaining (N) =?

How to determine the amount remaining

The amount remaining after 3 half-lives can be obtained as illustrated below:

N = N₀ / 2ⁿ

N = 300000 / 2³

N = 300000 / 8

N = 37500 atoms

9.0 mol Al reacts with 6.0 mol O2 to
form Al2O3 according to the
reaction below:
4A1+302 → 2Al2O3
How many moles of Al2O3 form from
6.0 mol O2?
[?] mol Al₂O3
Round your answer to the tenths place.
mol ALO
HELP PLS TO MOVE ON !!

Answers

4.0 moles of Al₂O₃ will be form from 6.0 moles of O₂.

How to solve for the amout that would form oxygen

(2 moles Al₂O₃) / (3 moles O₂)

= (x moles Al₂O₃) / (6.0 moles O₂)

To solve for x, we can cross-multiply:

(2 moles Al₂O₃) * (6.0 moles of  O₂)

= (3 moles of O₂) * (x moles of Al₂O₃)

12.0 moles Al₂O₃ = 3x moles Al₂O₃

Now, divide both sides by 3:

x = 4.0 moles Al₂O₃

So, 4.0 moles of Al₂O₃ form from 6.0 moles of O₂.

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To measure the reaction heat more accurately at isobaric condition, what modification (s) would you suggest making on the coffee cup calorimeter ?

Answers

To measure the reaction heat more accurately at isobaric condition, we can add a lid to the calorimeter to prevent heat loss due to evaporation.

Thus, to measure the reaction heat more accurately at isobaric condition, some certain modifications can be made to the coffee cup calorimeter which includes adding a lid to the calorimeter to prevent heat loss due to evaporation to keep the pressure inside the calorimeter constant.

Using a magnetic stir bar to ensure even mixing of the reactants to ensure the accurate temperature readings, use of thermometer with a smaller stem to reduce the amount of heat transferred from the solution to the thermometer, etc. are some other modifications that can be made on the coffee cup calorimeter to measure the reaction heat more accurately at isobaric condition.

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