you place in a dark bag 24 marbles. 12 marbles are red, 5 marbles are blue and 7 marbles are yellow. you select 2 random marbles (one after the other without putting the first back in). what is the probability that the marbles have the same color?

The results of the balls in Phillip's bag are:

The mean = 8.

The median = 7.

The mode = blue

The range = 12

The mean (or the average) is the sum of all the values divided by the total number of values. Let's calculate the mean for the given data:

Total number of balls = 8 + 3 + 6 + 3 + 13 + 15 = 48

Mean = (8 + 3 + 6 + 3 + 13 + 15) / 6 = 48 / 6 = 8

Mean = 8.

The median is the middle value when a set of values is arranged in ascending or descending order.

Let's arrange the given data in ascending:

3, 3, 6, 8, 13, 15

As the total number of values is even, the median will be the average of the two middle values, which are 6 and 8.

Median = (6 + 8) / 2 = 7

The median = 7.

The mode is the value that appears most frequently in a set of values. Let's find the mode of the given data:

Red balls: 8

Green balls: 3

Yellow balls: 6

Orange balls: 3

Black balls: 13

Blue balls: 15

Blue balls have the highest frequency (i.e., 15) among all the colors.

The range is the difference between the highest and lowest values in a set of values. Let's find the range of the given data:

Highest value = 15 (blue balls)

Lowest value = 3 (green balls and orange balls)

Range = Highest value - Lowest value = 15 - 3 = 12

Range = 12.

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Answer:

Step-by-step explanation:

y = abx

a is the y-intercept

y = 16bx

Now substitute 2 for x and 1296 for y

1296 = 16(b)2

81 = b2

b = 9

y = 16(9)x

1. x = 4.7 for f(x) and x = 25 for g(x), f(x) reaches 50 first.

2. x = 9.7 for f(x) and x = 50 for g(x), f(x) reaches 100 first.

1. Which function reaches 50 first?

To answer this, we need to solve for x in each function when the output is 50:

For f(x): 50 = 10x + 3

47 = 10x

x = 4.7

For g(x): 50 = 2x

x = 25

Since x = 4.7 for f(x) and x = 25 for g(x), f(x) reaches 50 first.

2. Which function reaches 100 first?

Similarly, we'll solve for x in each function when the output is 100:

For f(x): 100 = 10x + 3

97 = 10x

x = 9.7

For g(x): 100 = 2x
x = 50

Since x = 9.7 for f(x) and x = 50 for g(x), f(x) reaches 100 first.

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More people that rode the roller coaster are between the ages of 11 and 30, than people that are between the ages of 41 and 60 is the best description of the data which is obtained by using the arithmetic operations.

What are arithmetic operations?

Any real number may be explained using the four basic operations, also referred to as "arithmetic operations." Operations like division, multiplication, addition, and subtraction come before operations like quotient, product, sum, and difference in mathematics.

We are given a chart. From the chart we get the following data:

Number of people aged 11 - 20 riding roller coaster = 20

Number of people aged 21 - 30 riding roller coaster = 15

Number of people aged 31 - 40 riding roller coaster = 10

Number of people aged 41 - 50 riding roller coaster = 5

Number of people aged 51 - 60 riding roller coaster = 0

Using addition operation, we get

Total people = 20 + 15 + 10 + 5 + 0

Total people = 40

Now,

Total riders between 11 - 30 = 20 + 15

Total riders between 11 - 30 = 35

Similarly,

Total riders between 41 - 60 = 5 + 0

Total riders between 41 - 60 = 5

Hence, the fourth option is the correct answer.

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Therefore (t) can  be written as **(2 - 3Q) / (Q + 4)**.

Within the given equation, Q is a variable. It stands for an unknowable amount or value that can be ascertained by equation-solving.

A quantity that can take on any one of a number of values is referred to as a variable. A variable in mathematics is a symbol or letter that denotes an unknowable amount or value. The variable Q in the given equation stands for an unknowable quantity or value that can be ascertained by resolving the equation.

The equation is as follows:

Q = (2 - 4t) / (t + 3)

When we divide both sides by (t + 3), we obtain:

Q(t + 3) = 2 - 4t

When we increase the left side of the equation, we obtain:

Qt + 3Q = 2 - 4t

The result of adding 4t to both sides of the equation is:

Qt + 3Q + 4t = 2

Combining related concepts gives us:

t(Q + 4) = 2 - 3Q

The result of dividing both sides by (Q + 4) is:

t = (2 - 3Q) / (Q + 4)

t can therefore be written as **(2 - 3Q) / (Q + 4)**.

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The number of bacteria after 5 hours is approximately 1013.8.

We can use the formula for exponential growth to solve this problem. If a population grows at a rate proportional to its size, then we can writ

N(t) = N₀ × e^(rt),

where N(t) is the size of the population at time t, N₀ is the initial size of the population, r is the growth rate, and e is the mathematical constant approximately equal to 2.71828.

We know that the culture starts with 40 bacteria, so N₀ = 40. We also know that after 2 hours, the size of the population is 180. We can use this information to solve for r:

180 = 40 × e^(2r)

180/40 = e^(2r)

ln(180/40) = 2r

r = ln(180/40)/2

r ≈ 0.6931

Now we can use the formula to find the size of the population after 5 hours:

N(5) = 40 × e^(0.6931×5)

N(5) ≈ 1013.8

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The smallest positive integer divisible by 6 and 2 that can be written using at least one 2 and one 6 is 6.

The smallest positive integer that is divisible by both 2 and 6 is their least common multiple (LCM), which is equal to the product of the highest power of each prime factor that appears in the factorization of 2 and 6.

The prime factorization of 2 is simply 2, while the prime factorization of 6 is 2 × 3. The highest power of 2 that appears in the factorization of 6 is just 2 itself, so the LCM of 2 and 6 is 2 × 3 = 6.

We are asked to write this integer using at least one 2 and one 6. We can do this by simply writing 6, which is the LCM of 2 and 6 and is divisible by both of them. Since 6 contains one 2 and one 6, this meets the requirement of the problem. Therefore, the smallest positive integer divisible by 6 and 2 that can be written using at least one 2 and one 6 is 6.

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Sue works 5 out of 7 days a week, which implies that she has two days off. We need to discover how numerous conceivable plans there are for her to work on Tuesday or Friday or both.

There are two cases to consider:

1. Sue works on Tuesday as it were, Friday as it were, or both Tuesday and Friday.

2. Sue does not work on Tuesday or Friday.

For the primary case, there are three conceivable outcomes:

1. Sue works on Tuesday as it were and has Friday off.

2. Sue works on Friday as it were and has Tuesday off.

3. Sue works on both Tuesdays and Fridays.

For the moment case, there are two conceivable outcomes:

1. Sue works on one of the other 5 days of the week and has both Tuesday and Friday off.

2. Sue has Tuesday and Friday off.

In this manner, there are added up to 3 + 2 = 5 conceivable plans for Sue to work on Tuesday or Friday or both. 

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The equation with the new substitutions and conversion factor is a'B'T' = (1/6) * (2/3)^(1/3) * a^(1/3) * d^(1/2)*a^6/6 where k is (1/6) * (2/3)^(1/3) * a^(1/3) * d^(1/2) The intercept value of the log-log graph would have been -1.108.

Starting with Equation 4: T = ka^6/6, we can substitute a = (d/k)^(1/6) and b = (2/3)^(1/2) * (d/k)^(1/3) to get

T = k[(d/k)^(1/6)]^6/6

T = k(d/k)^(1/2)/6

T = (k^(1/2)/6) * d^(1/2)

Now we can rearrange the equation so that a, b, and t are on the left side

a'B'T' = ka^6/6

(a/d)^(1/6) * b^(2/3) * T' = k[(a/d)^(1/6)]^6/6 * T'

(a/d)^(1/6) * (2/3)^(1/2) * (d/k)^(1/3) * T' = (k^(1/2)/6) * d^(1/2) * T'

(2/3)^(1/2) * (a/d)^(1/6) * d^(1/3) * T' = (k^(1/2)/6) * d^(1/2) * T'

(2/3)^(1/2) * (a/d)^(1/6) * d^(1/3) = k^(1/2)/6

k = [(2/3)^(1/2) * (a/d)^(1/6) * d^(1/3)]^2/6

k = (1/6) * (2/3)^(1/3) * a^(1/3) * d^(1/2)

With this new conversion factor, the intercept of the log-log graph would have changed. The intercept represents the value of T when a = 1 (since log(1) = 0). Using the new conversion factor, we have

T = (1/6) * (2/3)^(1/3) * d^(1/2) * a^(1/3)

T = (1/6) * (2/3)^(1/3) * d^(1/2)

log(T) = log[(1/6) * (2/3)^(1/3) * d^(1/2)]

log(T) = log(1/6) + log[(2/3)^(1/3)] + log(d^(1/2))

log(T) = log(1/6) + (1/3) * log(2/3) + (1/2) * log(d)

So the intercept of the log-log graph would be log(1/6) + (1/3) * log(2/3) = -1.108, assuming that d is held constant. This intercept represents the value of log(T) when log(a) = 0, or when a = 1. In other words, when a = 1, the predicted value of T would be 0.162 (or 16.2% of its maximum value).

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--The given question is incomplete, the complete question is given

" Plug the two substitutions into Equation 4 (T = ka^6/6)). Rearrange the equation so that a, b,t are on the left side of the equation and d remains on the right side, e.g. a'B'T' = ka^6/6 you will figure out what the "k" if you used this version of the equation (including your new conversion factor, how would this have changed the intercept of your log-log graph? what would its value have been?"--

The answer is B

The internal angles of a triangle have to be 180

IN ΔABC, m∠A=70° and m∠B=35°.

70°+35°+x=180°

105°+x=180°

x=180°-105°

x=75°

Answer B meets the requirements because in ΔPQR m∠P=70° and m∠R=75°

70°+75°+x=180°

145°+x=180°

x=180°-145°

x=35°

The angles of both triangles measure the same

a) The probability of a given woman in this age group having a cholesterol level less than 200mg/dl is 6.68%.

b) The probability of a given woman in this age group having a cholesterol level more than 200mg/dl is 93.32%.

c) The probability of a given woman in this age group having a cholesterol level between 190mg/dl and 210mg/dl is 15.87%.

d) If a woman in this age group has a cholesterol level higher than 230mg/dl, it is considered high and puts her at risk of heart disease

To calculate the probability of a given woman in this age group having a cholesterol level less than 200mg/dl, we need to find the z-score first. The z-score is the number of standard deviations that a given value is from the mean. The formula to calculate the z-score is:

z = (x - μ) / σ

where x is the given value, μ is the mean, and σ is the standard deviation.

For a cholesterol level of 200mg/dl, the z-score is:

z = (200 - 230) / 20 = -1.5

We can then use a z-table or calculator to find the probability of a z-score being less than -1.5, which is 0.0668 or approximately 6.68%.

Next, to find the probability of a given woman in this age group having a cholesterol level more than 200mg/dl, we can use the same process but subtract the probability of a z-score being less than -1.5 from 1 because the total probability is always 1.

So, the probability of a given woman in this age group having a cholesterol level more than 200mg/dl is:

1 - 0.0668 = 0.9332 or approximately 93.32%.

Finally, to find the probability of a given woman in this age group having a cholesterol level between 190mg/dl and 210mg/dl, we need to find the z-scores for both values.

For a cholesterol level of 190mg/dl, the z-score is:

z = (190 - 230) / 20 = -2

For a cholesterol level of 210mg/dl, the z-score is:

z = (210 - 230) / 20 = -1

We can then use the z-table or calculator to find the probability of a z-score being between -2 and -1, which is 0.1587 or approximately 15.87%.

Finally, a brief report on the guidance that you would give a woman having high cholesterol levels in this age group is:

It is essential to make lifestyle changes such as eating a healthy diet, exercising regularly, quitting smoking, and managing stress to lower cholesterol levels.

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The most appropriate response to the claim would be: "At the 95% confidence level, the mean exercise time of all students might not be 10 hours per week based on the sample data."

Based on the given data, we can see that the sample mean exercise time is 7.8133 hours per week. The standard deviation of the exercise time is 5.8032, indicating that there is some variability in the data.

To determine whether the claim that the mean exercise time of all students is 10 hours per week is reasonable, we can conduct a hypothesis test.

Our null hypothesis would be that the mean exercise time of all students is equal to 10 hours per week, and the alternative hypothesis would be that the mean exercise time is different from 10 hours per week.

We can then calculate a test statistic and compare it to a critical value based on a t-distribution with n-1 degrees of freedom, where n is the sample size.

Alternatively, we can use the confidence interval provided in the table to make a statement about the claim.

We can see that the 95% confidence interval for the mean exercise time is [7.0769, 8.5497]. Since 10 is outside of this interval, we can say that at the 95% confidence level, the claim that the mean exercise time of all students is 10 hours per week is not supported by the data.

Therefore, the most appropriate response to the claim would be: "At the 95% confidence level, the mean exercise time of all students might not be 10 hours per week based on the sample data."

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The sample space are:

{AR, AS, AT, AE, RA, RS, RT, RE, SA, SR, ST, SE, TA, TR, TS, TE, EA, ER, ES, ET}

The favorable outcomes care:

{RS, RT, SR, ST, TR, TS}

The probability is  0.3 or 30%

Part A:

The sample space represents all possible outcomes that can occur when two cards are randomly selected without replacement from the given pile of cards.

The sample space can be represented as follows:

{AR, AS, AT, AE, RA, RS, RT, RE, SA, SR, ST, SE, TA, TR, TS, TE, EA, ER, ES, ET}

Part B:

The favorable outcomes are those outcomes in which both cards are consonants. In this case, the consonants are R, S, and T.

The favorable outcomes can be represented as follows:

{RS, RT, SR, ST, TR, TS}

Part C:

To calculate the probability of selecting 2 cards that are consonants, we need to find the ratio of favorable outcomes to the sample space.

The number of favorable outcomes is 6, and the size of the sample space is 20.

Therefore, the probability of selecting 2 cards that are consonants is:

P(consonants) = favorable outcomes / sample space

P(consonants) = 6 / 20

P(consonants) = 0.3 or 30%

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∠A = ∠C in trapezoid ABCD with arcAB = arcCD, can be proven with the property of isosceles triangles.

Since arcAB = arcCD, the lengths of the two arcs are equal. This implies that the lengths of the segments subtended by these arcs, AB and CD, are also equal.

Let E and F be the midpoints of the non-parallel sides AD and BC, respectively. Connect E and F with a line segment EF.

Since E and F are midpoints, DE = EA and BF = FC. In addition, since AB = CD = L, we can say that:

DE + EA = BF + FC

EA = FC

So, by the Hypotenuse-Leg (HL) theorem of congruence, triangles AEF and CFE are congruent:

ΔAEF ≅ ΔCFE

Now, since the triangles are congruent, their corresponding angles are equal:

∠A = ∠C

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The numerical measure of linear association is b. correlation coefficient.

The correlation coefficient is a statistical measure that represents the degree of linear relationship between two variables. It takes values between -1 and 1, where -1 represents a perfect negative linear correlation, 0 represents no linear correlation, and 1 represents a perfect positive linear correlation.

A positive correlation means that when one variable increases, the other variable also tends to increase, while a negative correlation means that when one variable increases, the other variable tends to decrease.

The correlation coefficient is calculated using the formula:

[tex]r = (nΣxy - ΣxΣy) / sqrt[(nΣx^2 - (Σx)^2)(nΣy^2 - (Σy)^2)][/tex]

where r is the correlation coefficient, n is the sample size, Σxy is the sum of the products of the corresponding values of x and y, Σx and Σy are the sums of x and y respectively, and Σx^2 and Σy^2 are the sums of the squares of x and y respectively.

In summary, the correlation coefficient is a measure of the strength and direction of the linear association between two variables.

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Thus, the appropriate measure of variability found for the given data is 10.

The difference here between maximum and smallest values in a data set is known as the range. Utilizing the exact same units as the data, it measures variability. More variability is shown by larger values.

Given length of ribbons:

3, 6, 9, 11, 12, 13

Minimum value = 3

Maximum value = 13

Actually, the range, which is determined by deducting the lowest value from the greatest value in the dataset, would be the proper measure of variability for this data.

Range = Maximum value - Minimum value

Range = 13 - 3

Range = 10

Thus, the appropriate measure of variability found for the given data is 10.

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The Probability that a student will complete the exam 0.2676.

The probability of completing the exam in one hour or less is:

[tex]P (x < 60)[/tex]

= [tex]P (z < (60-83)/13)[/tex]

=[tex]P (z < -1.77)[/tex]

= 0.0384.

The probability that a student will complete the exam in more than 60 minutes, but less than 75 minutes is.

[tex]P (60 < x < 75)[/tex]

= [tex]P (x < 75)-P (x < 60)[/tex]

Now,

[tex]P (x < 75)[/tex]

=[tex]P (z < (75-83)/13)[/tex]

= [tex]P (z < -0.62)[/tex]

=0.2676.

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The cardholder will pay an additional $1,471.66 in interest by making monthly payments of $200 until the balance is paid off instead of paying off the current balance in full.

First, we need to calculate the total interest that will accrue on the current balance of $4,528.34. We can do this using the formula

Interest = Balance x (APR/12)

where APR is the annual percentage rate and is divided by 12 to get the monthly interest rate. Plugging in the values, we get:

credit card Interest = $4,528.34 x (22.99%/12) = $87.80

So the total interest that will accrue on the current balance is $87.80.

Next, we need to calculate how long it will take to pay off the balance by making monthly payments of $200. We can use a credit card repayment calculator to do this, but we'll use a simplified formula here

Months = -log(1 - (Balance x (APR/12))/Payment) / log(1 + (APR/12))

where Payment is the monthly payment amount. Plugging in the values, we get

Months = -log(1 - ($4,528.34 x (22.99%/12))/$200) / log(1 + (22.99%/12)) = 29.6 months

So it will take about 30 months (or 2.5 years) to pay off the balance by making monthly payments of $200.

Finally, we can calculate how much more the cardholder will pay in total by subtracting the current balance from the total amount paid over 30 months

Total amount paid = $200 x 30 = $6,000

Total interest paid = $6,000 - $4,528.34 = $1,471.66

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Step-by-step explanation:

Use Pythagorean theorem to find the base of the right triangle

221^2 = 195^2 + b^2

b = 104 km

triangle area = 1/2 base * height =  1/2 * 104 * 195 = 10140 km^2

Now multiply by the height to find volume

10140 km^2  * 15 km  = 152100 km^3

The volume of this sphere is equal to 4,000 cm³.

In Mathematics and Geometry, the volume of a sphere can be calculated by using this mathematical equation (formula):

Volume of a sphere = 4/3 × πr³

Where:

r represents the radius.

Note: Radius = diameter/2 = 20/2 = 10 cm.

By substituting the given parameters into the formula for the volume of a sphere, we have the following;

Volume of a sphere = 4/3 × 3 × (10)³

Volume of a sphere = 4 × 1000

Volume of a sphere = 4,000 cm³

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We can see that they are similar because the ratio of the corresponding sides of the triangle are the same = 5/3.

A triangle is a polygon with three sides and three angles. It is one of the most basic shapes in geometry and is formed when three non-collinear points are connected by straight lines. The three sides of a triangle can have different lengths, and the three angles can have different measures. Triangles can be classified based on their sides and angles.

BC/DE = AD/AB

15/9 = AB/6

AB = (15 × 6)/9 = 90/9 = 10.

15/9 = 10/6 = 5/3.

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a) The zero rates for the five maturities are: 1 year is 2.01%, 2 years is 2.48%, 3 years is 2.77%, 4 years is 1.73%, and 5 years is 4.32%.

b) The price of the security is $128.31.

a) To find the zero rates for all 5 maturities, we can use the formula for the present value of a bond:

PV = C / [tex](1+r)^n[/tex]

where PV is the present value,

C is the coupon payment,

r is the zero rate, and

n is the number of years to maturity.

We can solve for r by rearranging the formula:

r = [tex](C/PV)^{(1/n) }[/tex]- 1

Using the bond data given in the question, we can calculate the zero rates for each maturity as follows:

For the 1-year bond, PV = 98 and C = 0, so r = 2.01%.

For the 2-year bond, PV = 101, C = 2.48, and n = 2, so r = 2.48%.

For the 3-year bond, PV = 103, C = 2.91, and n = 3, so r = 2.77%.

For the 4-year bond, PV = 101, C = 2, and n = 4, so r = 1.73%.

For the 5-year bond, PV = 103, C = 5, and n = 5, so r = 4.32%.

Alternatively, we can use linear algebra to find the zero rates. We can write the present value equation in matrix form:

PV = A × x

where A is a matrix of coefficients, x is a vector of unknowns (the zero rates), and PV is a vector of present values.

To solve for x, we can use the equation:

x = ([tex]A^{-1}[/tex]) x PV

where ([tex]A^{-1}[/tex]) is the inverse of matrix A.

Using this method, we can solve for the zero rates as follows:

[2.01% ]

[2.48% ]

[2.77% ] = x

[1.73% ]

[4.32% ]

PV = [tex]A^{-1}[/tex] x  [98]

                   [101]

                   [103]

                   [101]

                   [103]

PV =   [-0.0201]

          [ 0.0248]

          [ 0.0277]

          [-0.0173]

          [ 0.0432]

b) To find the price of the security which pays cash flows of $10 in one year, $25 in two years, and $100 in four years, we can use the formula for the present value of a series of cash flows:

PV = [tex]C1/(1+r)^1 + C2/(1+r)^2 + C3/(1+r)^4[/tex]

where PV is the present value, C1, C2, and C3 are the cash flows, r is the zero rate, and the exponents correspond to the number of years until each cash flow is received.

Using the zero rates calculated in part (a), we can calculate the present value of each cash flow:

PV1 = $10 /(1+2.01 % [tex])^1[/tex] = $9.80

PV2 = $25/(1+2.48%[tex])^2[/tex] = $22.15

PV3 = $100/(1+1.73%[tex])^4[/tex] = $81.36

Then, the price of the security is the sum of the present values:

PV = $9.80 + $22.15 + $81.36 = $128.31

Therefore, the price of the security is $128.31.

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Answer:

Step-by-step explanation:

Find the area of the circle with a circumference of

. Write your solution in terms of

.

Area in terms of

: ______

Teresa's expression, 8(4) - 8x, represents the area of the Quotations section. The expression is comprised of two parts: 8(4) and -8x.

8(4) represents the width of the Quotations section, as it is multiplied by the length of 4 units. This indicates that the Quotations section has a fixed width of 8 units.

-8x represents the variable length of the Quotations section. The term -8x indicates that the length of the section can vary based on the value of x, which is a variable. The negative sign indicates that the length decreases as the value of x increases, and vice versa.

Adnan's expression, 8(4 - x), also represents the area of the Quotations section. The expression is slightly different from Teresa's, as the subtraction operation (4 - x) is contained within the parentheses.

(4 - x) represents the variable width of the Quotations section. The expression indicates that the width of the section is determined by the value of x. As x changes, the width of the section changes accordingly.

8(4 - x) then multiplies the variable width by a fixed length of 8 units, indicating that the Quotations section has a fixed length of 8 units.

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Answer:

To find the greatest possible value of x + y, we need to maximize the values of x and y such that they are still positive integers and satisfy the given equation 18x + 11y = 2020.

We can start by rearranging the equation to solve for y:

11y = 2020 - 18x

y = (2020 - 18x)/11

For y to be a positive integer, 2020 - 18x must be divisible by 11. We can test values of x starting from x = 1 and increasing by 1 until we find the largest possible value of x that satisfies this condition.

When x = 1, 2020 - 18x = 2002, which is divisible by 11. This gives us a value of y = 182/11, which is not a positive integer.

When x = 2, 2020 - 18x = 1984, which is divisible by 11. This gives us a value of y = 180/11, which is not a positive integer.

When x = 3, 2020 - 18x = 1966, which is divisible by 11. This gives us a value of y = 178/11, which is not a positive integer.

When x = 4, 2020 - 18x = 1948, which is divisible by 11. This gives us a value of y = 176/11, which is not a positive integer.

When x = 5, 2020 - 18x = 1930, which is divisible by 11. This gives us a value of y = 174/11, which is not a positive integer.

When x = 6, 2020 - 18x = 1912, which is divisible by 11. This gives us a value of y = 172/11, which is not a positive integer.

When x = 7, 2020 - 18x = 1894, which is divisible by 11. This gives us a value of y = 170/11, which is not a positive integer.

When x = 8, 2020 - 18x = 1876, which is divisible by 11. This gives us a value of y = 168/11, which is not a positive integer.

When x = 9, 2020 - 18x = 1858, which is divisible by 11. This gives us a value of y = 166/11, which is not a positive integer.

When x = 10, 2020 - 18x = 1840, which is divisible by 11. This gives us a value of y = 164/11, which is not a positive integer.

When x = 11, 2020 - 18x = 1822, which is divisible by 11. This gives us a value of y = 162/11, which is not a positive integer.

When x = 12, 2020 - 18x = 1804, which is divisible by 11. This gives us a value of y = 160/11, which is not a positive integer.

When x = 13, 2020 - 18x = 1786, which is divisible by 11. This gives us a value of y = 158/11, which is not a positive integer.

When x = 14, 2020 - 18x = 1768, which is divisible by 11. This gives us a value of y = 156/11, which is not a positive integer.

When x = 15, 2020 - 18x = 1750, which is divisible by 11. This gives us a value of y = 154/11, which is not a positive integer.

When x = 16, 2020 - 18x = 1732, which is divisible by 11. This gives us a value of y = 152/11, which is not a positive integer.

When x = 17, 2020 - 18x = 1714, which is divisible by 11. This gives us a value of y = 150/11, which is not a positive integer.

When x = 18, 2020 - 18x = 1696, which is divisible by 11. This gives us a value of y = 148/11, which is not a positive integer.

When x = 19, 2020 - 18x = 1678, which is divisible by 11. This gives us a value of y = 146/11, which is not a positive integer.

When x = 20, 2020 - 18x = 1660, which is divisible by 11. This gives us a value of y = 144

Scenic Cinemas should offer discounted weekday matinee showings for seniors and continue to focus on weekend showings for their broader audience.

Based on the survey results, it would be wise for Scenic Cinemas to tailor their offerings to accommodate both preferences.

One option would be to offer discounted weekday matinee showings targeted toward seniors. This could incentivize them to visit on weekdays while also offering them a more affordable option. At the same time, Scenic Cinemas could continue to focus on weekend showings to cater to their broader audience.

Another approach would be to offer more diverse programming during the weekdays, such as classic films or independent movies that may appeal more to seniors. This could create a niche for Scenic Cinemas and attract a more loyal customer base.

Ultimately, it's important for Scenic Cinemas to balance the needs of their different audience segments to maximize revenue and customer satisfaction. By offering targeted promotions and programming, they can ensure that both seniors and other moviegoers feel valued and have a reason to visit the theatre.

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9. The volume of the triangular pyramid is given by:

V = (1/3)Bh

Here, B is the base area.

The base is shaped as a right triangle thus, using the Pythagoras Theorem we have:

h = sqrt(26.7² - 11.7²) = 23.274 km

The area if the base is:

B = (1/2)bh = (1/2)(11.7 km)(23.4 km) = 136.89 sq. km

Now, the volume is:

V = (1/3)(136.89)(15) = 2053.35 cubic km

Hence, the volume of the triangular pyramid is 2053.35 cubic km.

9. The volume of the triangular pyramid is 2053.35 cubic km. 11. The area of the shaded portion is 348.19 cubic in 13. The slant height of the cone is 8.53 meters.

A fundamental conclusion in geometry relating to the lengths of a right triangle's sides is known as Pythagoras' theorem. According to the theorem, the square of the length of the hypotenuse, the side that faces the right angle, in any right triangle, equals the sum of the squares of the lengths of the other two sides, known as the legs.

9. The volume of the triangular pyramid is given by:

V = (1/3)Bh

Here, B is the base area.

The base is shaped as a right triangle thus, using the Pythagoras Theorem we have:

h = √(26.7² - 11.7²) = 23.274 km

The area if the base is:

B = (1/2)bh = (1/2)(11.7 km)(23.4 km) = 136.89 sq. km

Now, the volume is:

V = (1/3)(136.89)(15) = 2053.35 cubic km

Hence, the volume of the triangular pyramid is 2053.35 cubic km.

11. The volume of a cone is given by:

V = (1/3)πr²h

The dimension of the bigger cone is radius is 9 in, and height 15 in:

V1 = (1/3)π(9 in)²(15 in) = 381.7 cubic in

The dimension of the smaller cone is radius is 4 in, and height 10 in:

V2 = (1/3)π(4 in)²(10 in) = 33.51 cubic in

Now, the area of the shaded portion is:

V1 - V2 = 381.7 - 33.51  = 348.19

13. The volume of a cone is given by:

V = (1/3)πr²h

Substituting the values we have:

542.87 = (1/3)π(6 m)²h

h = 542.87 / [(1/3)π(6 m)²] = 6.05 m

Now, using the Pythagoras Theorem for the slant height we have:

s² = r² + h²

s² = (6 m)² + (6.05 m)²

s² = 72.9

s = √(72.9) = 8.53 m

The slant height of the cone is 8.53 meters.

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Step-by-step explanation:

4^-3   =   1/4^3   =   1/64

Answer:

  $9.50

Step-by-step explanation:

You want Suzie's hourly rate on Saturday if she babysat for 3.5 hours on Friday, earning 8.50 per hour, and for 4.5 hours on Saturday, earning a total of 72.50 from both jobs.

For (hours, rates) of (h1, r1) and (h2, r2), Suzie's total earnings for the two jobs are ...

  earnings = h1·r1 +h2·r2

Filling in the known values, we can find r2:

  72.50 = 3.5·8.50 +4.5·r2

  72.50 = 29.75 +4.5·r2 . . . . . . . simplify

  42.75 = 4.5·r2 . . . . . . . . . . . subtract 29.75

  9.50 = r2 . . . . . . . . . . . . divide by 4.5

Suzie earned $9.50 per hour on Saturday.

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Additional comment

The steps of the "multistep" problem are ...

Effectively, these are the steps to solving the equation we wrote.