Let's assume that each van and each bus can carry "x" number of students.
What is the equations based information?Let's assume there are "x" students in each van and each bus. Therefore, the total number of students in High School A's senior class is 8x + 8x = 16x. We know that the total number of students in High School A's senior class is 240, so we can set up an equation:
16x = 240
Solving for x, we get:
x = 15
So, each van and each bus had 15 students in it for High School A's senior class.
Similarly, for High School B, the total number of students is 4x + 1x = 5x. We know that the total number of students in High School B's senior class is 54, so we can set up an equation:
5x = 54
Solving for x, we get:
x = 10.8
Since the number of students must be a whole number, we can round up to 11. Therefore, each van and each bus had 11 students in it for High School B's senior class.
Therefore, the total number of students in High School A's senior class is 1x + 6x = 7x. We know that the total number of students in High School A's senior class is 372, so we can set up an equation:
7x = 372
Solving for x, we get:
x = 53
Therefore, each van and each bus can carry 53 students for High School A's senior class.
Similarly, for High School B, the total number of students is 4x + 12x = 16x. We know that the total number of students in High School B's senior class is 780, so we can set up an equation:
16x = 780
Solving for x, we get:
x = 48.75
Since the number of students must be a whole number, we can round up to 49. Therefore, each van and each bus can carry 49 students for High School B's senior class.
Let's assume that the price of one senior citizen ticket is "s" and the price of one child ticket is "c". Therefore, we can set up two equations based on the given information:
[tex]3s + 9c = 75[/tex]
[tex]8s + 5c = 67[/tex]
We can solve these equations simultaneously to find the values of "s" and "c". One way to do this is to multiply the first equation by 8 and the second equation by 3, so that we can eliminate "c" and solve for "s":
[tex]24s + 72c = 600[/tex]
[tex]24s + 15c = 201[/tex]
Subtracting the second equation from the first, we get:
57c = 399
Solving for "c", we get:
c = 7
Substituting this value into one of the original equations, we can solve for "s":
[tex]3s + 9(7) = 75[/tex]
[tex]3s + 63 = 75[/tex]
[tex]3s = 12[/tex]
[tex]s = 4[/tex]
Therefore, one senior citizen ticket costs $4 and one child ticket costs $7.
Let's assume that the speed of the boat in still water is "b" and the speed of the current is "c".
Therefore, we can set up two equations based on the given information:
[tex]336 = (b + c) * 12[/tex]
[tex]336 = (b - c) * 14[/tex]
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I need help with this problem. Joe bought a gallon of gasoline for 2. 85 per gallon and c cans of oil for 3. 15 per can
From the given information provided, the expression that need to determine the total amount is Total cost = $2.85/gallon x g gallons + $3.15/can x c cans.
The expression that can be used to determine the total amount Joe spent on gasoline and oil is:
Total cost = Cost of gasoline + Cost of oil
We can represent the cost of gasoline as:
Cost of gasoline = price per gallon x number of gallons
Substituting the given values, we get:
Cost of gasoline = $2.85/gallon x g gallons
Similarly, we can represent the cost of oil as:
Cost of oil = price per can x number of cans
Substituting the given values, we get:
Cost of oil = $3.15/can x c cans
Putting it all together, we get:
Total cost = $2.85/gallon x g gallons + $3.15/can x c cans
Expression that can be used to determine the total amount Joe spent on gasoline and oil is:
Total cost = $2.85/gallon x g gallons + $3.15/can x c cans
Question - Joe bought g gallons of gasoline for $2.85 per gallon and c cans of oil for $3.15 per can. What expression can be used to determine the total amount Joe spent on gasoline and oil?
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for the beam and loading shown, (a) draw the shear and bending-moment diagrams, (b) determine the equations of the shear and bending-moment curves. 5.1
Bending moment curve equation below point A will be:
M = 15x - 3x² for 0 ≤ x ≤ b
Determination of shear and bending moment curves.
For the beam and loading shown, we can do the following:
Equation of shear curve (above point A):V = RA - w.x
For x = a,V = RA - w.a
For x = b,V = RA - w.b
Since the loading is symmetric, RA = w(a + b) / 2= (6 * 5) / 2= 15kNV = 15 - 6a for a ≤ x ≤ b
Equation of shear curve (below point A):
V = RA - w.x
For x = 0,V = RA - w.0RA = w(a + b) / 2= (6 * 5) / 2= 15kNV = 15k for 0 ≤ x ≤ a
The shear curve equation becomes;
V = 15k for 0 ≤ x ≤ a
V = 15 - 6a for a ≤ x ≤ b
Equation of bending moment curve (above point A):
M = RAx - ½w.x²For 0 ≤ x ≤ a,
M = 15x - ½(6x²) = 15x - 3x²For a ≤ x ≤ b,
M = 15x - 6a(x - a) - ½(6x²)= 15x - 6ax + 6a² - 3x²
The bending moment curve equation above point A becomes:
M = 15x - 3x² for 0 ≤ x ≤ a
M = 15x - 6ax + 6a² - 3x² for a ≤ x ≤ b
Equation of bending moment curve (below point A):
M = RAx - ½w.x²For 0 ≤ x ≤ b,
M = 15x - ½(6x²) = 15x - 3x²
The bending moment curve equation below point A becomes;
M = 15x - 3x² for 0 ≤ x ≤ b
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ten chairs are arranged in a circle. find the number of subsets of this set of chairs that contain at least three adjacent chairs.
Ten chairs are arranged in a circle. The number of subsets of this set of chairs that contain at least three adjacent chairs is 310.
The given that 10 chairs arranged in a circle.
Now we have to find the number of subsets of this set of chairs that contain at least three adjacent chairs.
To solve this, we can use the concept of permutations and combinations. The first step is to consider the number of ways in which three chairs can be selected and arranged in a subset that is adjacent to each other.
This can be done in 10 different ways, as there are 10 chairs in total and we can select any one of them as the starting point.
The next step is to consider the number of ways in which we can add additional chairs to this subset. For example, we can add a fourth chair to the subset in two different ways: either to the left of the first chair or to the right of the third chair.
Similarly, we can add a fifth chair to the subset in four different ways, a sixth chair in six different ways, and so on. Using this logic, we can create the following table:
Length of subset number of ways to select the subset number of ways to add chairs
Total number of subsets31 (adjacent)
= 10 ---43 (adjacent) 10*2
=20---55 (adjacent)10*4
=40---67 (adjacent)10*6
=60---79 (adjacent)10*8
=80---810 (adjacent)10*10
=100---
As we can see from the table, the total number of subsets that contain at least three adjacent chairs is given by:
Total number of subsets = 10 + 20 + 40 + 60 + 80 + 100
= 310
Therefore, the number of subsets of this set of chairs that contain at least three adjacent chairs is 310.
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The graphs of line a and b are shown in this coordinate grid
Match each line with it's equation. Drag each equation to the corresponding box for each line
The correct option for the given graph is option 1 and option 3. The equation matches the intersection point (1,1).
For option 1: intersection point (1,1)
substitute the values of x & y in the given equation.
1 = 3 (1) - 2
1 = 1
LHS = RHS
For option 2: point (1,1)
substitute the values of x & y in the given equation.
1 = 2 (1) + 3
1 = 5
LHS ≠ RHS
For option 3: point (1,1)
substitute the values of x & y in the given equation.
1 = -2 (1) + 3
1 = 1
LHS = RHS
For option 4: point (1,1)
substitute the values of x & y in the given equation.
1 = - [tex]\frac{1}{2}[/tex] (1) + 3
1 = [tex]\frac{5}{2}[/tex]
LHS ≠ RHS
For option 5: point (1,1)
substitute the values of x & y in the given equation.
1 = - [tex]\frac{1}{3}[/tex] (1) + 3
1 = [tex]\frac{8}{9}[/tex]
LHS ≠ RHS
Therefore, correct option for the given graph is option 1 and option 3.
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Triangle ABC has vertices at A(−4, 3), B(0, 5), and C(−2, 0). Determine the coordinates of the vertices for the image if the preimage is translated 4 units down.
A′(−4, −1), B′(0, 1), C′(−2, −4)
A′(−4, 7), B′(0, 9), C′(−2, 4)
A′(0, 3), B′(4, 4), C′(3, 0)
A′(−8, 7), B′(−4, 9), C′(−6, 4)
The coordinates of the vertices for the image if the preimage is translated 4 units down are A′(-4, -1), B′(0, 1), C′(-2, -4).
What is meant by preimage?
In geometry, a preimage is the original figure or shape before any transformation is applied. It is the initial configuration of the object that is being transformed. For example, if we have a square and we rotate it by 90 degrees, the original square is the preimage and the resulting figure after the rotation is the image.
To translate the preimage 4 units down, we need to subtract 4 from the y-coordinates of all vertices. Therefore, the coordinates of the image vertices are:
A′(-4, 3-4) = (-4, -1)
B′(0, 5-4) = (0, 1)
C′(-2, 0-4) = (-2, -4)
Therefore, the vertices of the image triangle are A′(-4, -1), B′(0, 1), and C′(-2, -4).
So, the correct option is: A′(-4, -1), B′(0, 1), C′(-2, -4).
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Determine which property(s) the following relation R on the set of all integers satisfy(s)?( a , b ) ∈ R iff a b ≥ 1 .
In conclusion, the relation R on the set of all integers satisfies reflexivity and symmetry but not transitivity.
To determine which properties the relation R on the set of all integers satisfy, we need to check for reflexivity, symmetry, and transitivity.
1. Reflexivity: A relation R is reflexive if for every element a in the set, (a, a) ∈ R.
In this case, we need to check if a * a ≥ 1 for all integers a.
Since any integer squared (a * a) is greater than or equal to 1, R is reflexive.
2. Symmetry: A relation R is symmetric if for every pair (a, b) ∈ R, (b, a) also ∈ R.
In this case, we need to check if a * b ≥ 1 implies b * a ≥ 1.
Since multiplication is commutative (a * b = b * a), the condition holds true, and R is symmetric.
3. Transitivity: A relation R is transitive if for every (a, b) ∈ R and (b, c) ∈ R, (a, c) also ∈ R.
In this case, we need to check if a * b ≥ 1 and b * c ≥ 1 imply a * c ≥ 1.
Let's take the counterexample: a = -1, b = 2, and c = -1. We have -1 * 2 ≥ 1 and 2 * -1 ≥ 1, but -1 * -1 ≥ 1 is false.
Therefore, R is not transitive.
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Help me pls, i need the process too!
Option A,B,C,D : Elias might have gotten the answer by calculating the percentage discounts of each item and comparing them to see which ones are the same.
To find which items have the same percent discount, we need to calculate the percent discount for each item.
For the sweater, the percent discount is (20/50) x 100% = 40%.
For the shorts, the percent discount is (12/30) x 100% = 40%.
For the shirt, the percent discount is (14/35) x 100% = 40%.
For the jeans, the percent discount is (24/60) x 100% = 40%.
Therefore, all items have the same percent discount of 40%, and option C (jeans and shirt only) is incorrect. The correct answer is A, sweater and shorts only, B, sweater, shorts, and shirt only, and D, sweater, shorts, and jeans only, have the same percent discount. Elias may have chosen C because he overlooked that the percent discount is the same for all items.
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Which items have the same percent discount?
A. sweater and shorts only
B. sweater, shorts, and shirt only
C. jeans and shirt only
D. sweater, shorts, and jeans only
Elias chose C as the correct answer. How might he have gotten that answer?
a bag contains red balls, green balls, and yellow balls. if balls are drawn one at a time without replacement, the probability that the first yellow ball is drawn on the eighth draw is , what is the value of ?
The probability of drawing the first yellow ball on the eighth draw is 1/2772.
The probability of drawing a yellow ball on the eighth draw is the probability of drawing 7 non-yellow balls followed by a yellow ball.
The probability of drawing a non-yellow ball on the first draw is 7/12 since there are 7 non-yellow balls out of a total of 12 balls in the bag. After the first non-yellow ball is drawn, there will be 6 non-yellow balls left out of a total of 11 balls. So the probability of drawing a non-yellow ball on the second draw is 6/11. Continuing in this manner, the probability of drawing 7 non-yellow balls in a row is
(7/12) × (6/11) × (5/10) × (4/9) × (3/8) × (2/7) × (1/6)
Now, there are 5 yellow balls left out of a total of 5 + 7 + 3 = 15 balls. So the probability of drawing a yellow ball on the eighth draw is 5/15.
Therefore, the probability of drawing the first yellow ball on the eighth draw is
(7/12) × (6/11) × (5/10) × (4/9) × (3/8) × (2/7) × (1/6) × (5/15)
Simplifying this expression, we get
(7 × 6 × 5 × 4 × 3 × 2 × 1 × 5) / (12 × 11 × 10 × 9 × 8 × 7 × 6 × 15)
which simplifies to:
1/2772
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The given question is incomplete, the complete question is:
A bag contains 3 red balls, 4 green balls, and 5 yellow balls. If balls are drawn one at a time without replacement, what is the probability that the first yellow ball is drawn on the eighth draw?
The base year is 2012. Real GDP in 2012 was $15 trillion. The GDP price index in 2019 was 105, and real GDP in 2019 was $16 trillion. What was the percentage increase in production from 2012 to 2019, and by what percentage did the price level rise from 2012 to 2019?
Real GDP increase in 2019 was $16 trillion, representing a 6.67% increase from 2012. The price level rose by 5% from 2012 to 2019, with a GDP price index of 105 in 2019.
To calculate the percentage increase in production from 2012 to 2019, we need to use the following formula:
Percentage increase in production = ((Real GDP in 2019 - Real GDP in 2012) / Real GDP in 2012) x 100
Substituting the given values, we get:
Percentage increase in production = ((16 trillion - 15 trillion) / 15 trillion) x 100
Percentage increase in production = (1 trillion / 15 trillion) x 100
Percentage increase in production = 6.67%
Therefore, there was a 6.67% increase in production from 2012 to 2019.
To calculate the percentage increase in price level from 2012 to 2019, we can use the following formula:
Percentage increase in price level = ((GDP price index in 2019 - GDP price index in 2012) / GDP price index in 2012) x 100
Substituting the given values, we get:
Percentage increase in price level = ((105 - 100) / 100) x 100
Percentage increase in price level = (5 / 100) x 100
Percentage increase in price level = 5%
Therefore, the price level rose by 5% from 2012 to 2019.
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Tonya's income is four times as much as Nora's income. Write an Algebraic expression representing Nora's income in terms of Tonya's
An algebraic expression for representing the Nora's income in form of Tonya's income is given by y = ( x / 4 ) .
Let us consider 'x' represents the Tonya's income.
And variable 'y' represents the Nora's income.
Tonya income is equal to four times of Nora's income.
This implies,
Nora's income is equal to one fourth times of Tonya's income.
⇒ y = ( x / 4 )
Rewrite an algebraic expression to represents Tonya's income in terms of Nora's income we have,
Simplify by multiplying both the sides of the algebraic expression by 4 we get,
⇒ x = 4y
Therefore, an algebraic expression to represents the Nora's income in terms of Tonya's income is equal to y = ( x / 4 ).
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julio has $31.00 he earns half of that much mowing a lawn. How much money does he have in all?
Answer: $ 46.50
First divided 31 by 2
Which equals...
15.50
Then add 15.50 to 31.
46.50
The answer is $46.50
the area of the figure
Answer:
432
Step-by-step explanation:
go 16x27 and that is your answer
Answer:
The area of the figureo will be 432
BECAUSE :-
You have to multiply 16 × 27 = 432
Hope Its Help You !!
Factor
[tex]64h^3+216k^9[/tex]
Answer:
Factor 64h^3+216k^9
Step-by-step explanation:
The given expression is a sum of two terms:
[64h^3+216k^9
Notice that each term has a common factor. For the first term, the greatest common factor (GCF) is 64h^3, and for the second term, the GCF is 216k^9. So we can factor out these GCFs to get:
64h^3+216k^9 = 64h^3(1 + 3k^6)
This expression cannot be factored any further, so the final answer is:
64h^3+216k^9 = 64h^3(1 + 3k^6)
If you can, give me brainliest please!
Please help 30 points I've been struggling
Identify the Slope and y - intercept from the graph
Slope (m) =
b =
Write the equation of the line in Slope-Intercept form
a sock drawer contains 18 black socks and 12 red socks. if you randomly choose two socks at once, what is the probability you get a matching pair?
There are 12 red socks and 18 black socks in a sock drawer. If you randomly choose two socks at once, the probability you get a matching pair is 50%.
The probability of getting a matching pair of socks can be calculated as follows:
First, we can calculate the total number of ways to choose 2 socks out of 30:
C(30, 2) = 30! / (2! * (30-2)!) = 435
Now, we need to calculate the number of ways to choose 2 socks such that they are both black or both red:
Number of ways to choose 2 black socks: C(18, 2) = 153
Number of ways to choose 2 red socks: C(12, 2) = 66
Therefore, the total number of ways to choose a matching pair of socks is 153 + 66 = 219.
Finally, we can calculate the probability of getting a matching pair of socks by dividing the number of ways to choose a matching pair by the total number of ways to choose 2 socks:
P(matching pair) = 219 / 435 ≈ 0.5034
Therefore, the probability of getting a matching pair of socks is approximately 0.5034 or 50.34%.
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For any acute angle A if sin A = 2x-1/2x+1, what is the value of cos A cot A?
The trigonometric expression cosAcotA = 8x/(4x² - 1)
What is a trigonometric expression?A trigonometric expression is an expression that contains trigonometric ratios.
Given that for any acute angle A if sin A = 2x-1/2x+1, we desire to find the value of cos A cot A?
So, we proceed as follows
cosAcotA = cosA × cosA/sinA (since cotA = cosA/sinA)
= cos²A/sinA
Now using the trigonometric identity
sin²A + cos²A = 1
⇒ cos²A = 1 - sin²A
So, substituting this into the equation, we have that
cosAcotA = cos²A/sinA
= (1 - sin²A)/sinA
= 1/sinA - sin²A/sinA
= 1/sinA - sinA
Substituting the value of sinA into the equation, we have
= 1/(2x - 1)/(2x + 1) - (2x - 1)/(2x + 1)
= (2x + 1)/(2x - 1) - (2x - 1)/(2x + 1)
Taking the L.C.M, (2x - 1)(2x + 1), we have
= [(2x + 1)² - (2x - 1)²]/[(2x - 1)(2x+ 1)]
= [(2x + 1)² - (2x - 1)²]/[(2x)² - 1²)]
= [(2x + 1 + 2x - 1)(2x + 1 - (2x - 1)]/(2x)² - 1²)
= [(2x + 1 + 2x - 1)(2x + 1 - 2x + 1)]/4x² - 1)
= [(4x)(2)]/4x² - 1)
= 8x/(4x² - 1)
So, cosAcotA = 8x/(4x² - 1)
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SOMEONE HELP PLEASE
Kiki runs 4 3/7 miles during the first week of track practice she runs 6 2/3 miles during the second week of track practice. How much longer does kiki run during the second week of track practice than the first week of track practice
Total longer distance is [tex]3\frac{2}{21} miles[/tex], that kiki run during the second week of track practice than the first week of track practice.
We have, a runner Kiki and she runs on track for practice. In first week,
Distance runs by Kiki on track practic = [tex]4 \frac{3}{7} miles[/tex]
which is a mixed fraction so, simplify it into simple fraction that is 25/7 miles. In second week,
Distance runs by Kiki on track practice = [tex]6 \frac{2}{3} miles[/tex]
After simplification, it is equals to 20/3 miles. We have to calculate the longer distance that kiki run during the second week of track practice than the first week of track practice. Let the distance run during second week be longer by 'x miles' from distance run during first week. The required distance can be calculated by difference between the distance that kiki run during the second week of track practice and the first week of track practice. So, [tex]x = \frac{20}{3} - \frac{25}{7 }[/tex].
taking least common multiple of (3,7)= 21
=> [tex] x = \frac{20× 7 - 3× 25}{21} [/tex]
[tex] =>x = \frac{ 140 - 75}{21} = \frac{65}{21 }[/tex].
Hence, required distance value is
[tex]3\frac{2}{21} [/tex].
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11. Hannah recorded the number of miles she jogged. She started jogging 3 41 miles. Every week she jogged an additional
1 21 miles. Select all true statements. The y-intercept is the rate of change. The y-intercept is the starting value. The slope is 121. The slope is 3 41. The y-intercept is 1 21. The y-intercept is 3 41
Using coordinate geometry,
The y-intercept is the starting value (true).The slope is 1/2 or 0.5, not 121 or 3/41 (false).The y-intercept is 3/41 is also false as it contradicts the first true statement, therefore, the y-intercept is the starting value and the y-intercept of 3/41 is also true.The problem provides two pieces of information about Hannah's jogging routine: she started with 3 41 miles and added 1/21 miles every week. We can use this information to create a linear equation that represents the number of miles Hannah jogged as a function of the number of weeks she has been jogging.
To create this equation, we first identify the starting value, which is 3 41 miles. This is also the y-intercept of the line. Next, we determine the slope of the line, which is the rate at which the number of miles increases each week. The slope is equal to the change in y (miles) divided by the change in x (weeks), which in this case is (1/21 - 3/41)/1 = -2/1 = -2. Therefore, the slope of the line is -2.
Putting these two pieces of information together, we get the equation y = -2x + 3 41, where y is the number of miles jogging and x is the number of weeks of jogging. This is a linear equation in slope-intercept form, where the slope is -2 and the y-intercept is 3 41.
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What is the volume of the cone expressed in terms of pi?
Answer: V≈339.29 in
Step-by-step explanation:
a 336-m long fence is to be cut into pieces to make three enclosures, each of which is square. how should the fence be cut up in order to minimize the total area enclosed by the fence?
The fence ought to be cut into 12 pieces, every one of length 28 m, to make three squares, each with a side length of 28 m. This will limit the total area encased by the fence.
To limit the total area encased by the fence, the three squares ought to have equivalent areas. Let x be the length of each side of the squares. Then the perimeter of each square is 4x, and the total length of the fence is 3(4x) = 12x. Since the total length of the fence is given to be 336 m, we have:
12x = 336
Addressing for x, we get:
x = 28
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what's a drawback to using a histogram?
Answer:
Step-by-step explanation:
One potential drawback of using a histogram is that it can be sensitive to the choice of bin width or bin size. If the bin size is too small, the histogram may appear too noisy or have too many empty bins, which can obscure patterns in the data. If the bin size is too large, important features of the distribution may be lost or smoothed out. Additionally, histograms do not always show the actual values of the data points, but rather a summary of the data. This means that some details about the data may be lost, such as the exact values of outliers or individual data points.
there are 3 soccer games in a month, and 8 are played at night. the season is 4 months. how many games are the season?
There are a total of 48 soccer games in the season.
Since there are 3 soccer games in a month, there will be 12 games in a season (3 games/month x 4 months). Since 8 games are played at night and assuming that all games are played either during the day or at night, we can calculate the number of games played during the day as:
Number of day games = Total number of games - Number of night games
= 12 games/month x 4 months - 8 night games/month x 4 months
= 48 games - 32 games
= 16 games
Therefore, the total number of games in the season is:
Total number of games = Number of day games + Number of night games
= 16 games + 32 games
= 48 games
So, there are 48 soccer games in the season.
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a die is rolled twice and the sum of numbers appearing on the upper faces of them is observed to be 7. what is the probability that the number 2 has appeared atleast once? hint: use the concept of conditional probability)
The probability of getting at least one 2 given that the sum of the numbers is 7 is 2/6 or 1/3.
To find the probability that the number 2 has appeared at least once given that the sum of the numbers is 7, we need to use the concept of conditional probability.
Let's consider the possible outcomes when two dice are rolled. The total number of outcomes is 36, as each die has six possible outcomes.
Out of these 36 outcomes, there are six outcomes in which the sum of the numbers appearing on the upper faces is 7. These outcomes are (1,6), (2,5), (3,4), (4,3), (5,2), and (6,1).
Out of these six outcomes, there are two outcomes in which the number 2 appears at least once: (1,6) and (2,5).
We can use the formula for conditional probability to verify our answer:
P(2 appears at least once | sum is 7) = P(2 appears at least once and sum is 7) / P(sum is 7)
P(2 appears at least once and sum is 7) = 2/36 = 1/18 (as there are two outcomes with a sum of 7 that have a 2 in them)
P(sum is 7) = 6/36 = 1/6
So, P(2 appears at least once | sum is 7) = (1/18) / (1/6) = 1/3, which is consistent with our previous answer.
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the ages of students at a university are normally distributed with a mean of 20. what percentage of the student body is at least 20 years old?
The percentage of the student body that is at least 20 years old is 50%.
The ages of students at a university are normally distributed with a mean of 20. To find the percentage of the student body that is at least 20 years old solution to the is as follows: As the Mean of ages of students at a university, μ = 20. Age is normally distributed so it will be divided into two groups Therefore, the mean age is equal to the median age. As the age is normally distributed, 50% of the population will have an age greater than or equal to 20 years old. Thus, the percentage of the student body that is at least 20 years old is 50%. Hence, the required percentage of the student body that is at least 20 years old is 50%.
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Determine the magnitude of the force P for which the resultant of the four forces acts on the rim of the plate. Given: F= 320 N. 30° 120 N 80 N P x 250 mm F 7 The magnitude of the force P is N.
The magnitude of the force P is 464.77 N.
STEP BY STEP EXPLANATION:
Step 1: Break down each force into components.
F = 320 N at 30°
Fx = F * cos(30°) = 320 * cos(30°) = 277.13 N (horizontal)
Fy = F * sin(30°) = 320 * sin(30°) = 160 N (vertical)
120 N is in the horizontal direction (assume positive x-direction):
Fx2 = 120 N
80 N is in the vertical direction (assume positive y-direction):
Fy2 = 80 N
Step 2: Sum up the components.
Total horizontal force (Fxtotal) = Fx + Fx2
= 277.13 + 120 = 397.13 N
Total vertical force (Fytotal) = Fy + Fy2
= 160 + 80 = 240 N
Step 3: Find the magnitude of the resultant force.
Resultant force (R) = sqrt(Fxtotal^2 + Fytotal^2)
= sqrt(397.13^2 + 240^2) = 464.77 N
Step 4: Determine the magnitude of the force P.
Since the resultant of the four forces should act on the rim of the plate, it means that the force P should be equal in magnitude and opposite in direction to the resultant force R.
The magnitude of the force P is 464.77 N.
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13. The area of the kite is 30 m². What is the value
of x? Explain.
4m
xm
6 m
xm
14.
Answer:
answer is 3
Step-by-step explanation:
Subtract the following polynomials.
The subtraction of the polynomials (3.1x + 2.8z) - (4.3x - 1.2z) is -1.2x + 4x
How to subtract polynomials?A polynomial is an expression consisting of a sum of a finite number of terms, each term being the product of a constant coefficient and one or more variables raised to a non-negative integer power.
(3.1x + 2.8z) - (4.3x - 1.2z)
open parenthesis
3.1x + 2.8z - 4.3x + 1.2z
combine like terms
3.1x - 4.3x + 2.8z + 1.2z
-1.2x + 4x
Ultimately, -1.2x + 4x is the results of the subtraction of the polynomial.
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Answer
D =
E =
Please help
Answer:
d = 3.75
e = 8/3
Step-by-step explanation:
8/6 = 5/d = e/2
4/3 = 5/d
4d = 3 × 5
d = 3.75
4/3 = e/2
3e = 4 × 2
e = 8/3
Write the ratios for sin A and cos A. The diagram is not drawn to scale.
sin A= 14/50 cos A 48/50
sin A= 48/50 cos A 14/50
sin A 48/14 cos A 14/50
sin A= 48/50 cos A 14/48
The ratio of SINA and COSA = 48/50 and 14/50
What is trignometric ratios?This is the boundary or contour length of a 2D geometric shape.
Depending on their size, multiple shapes may have the same circumference. For example, imagine a triangle made up of wires of length L.
The same wire can be used to create a square if all sides are the same length.
The length covered by the perimeter of the shape is called the perimeter. Therefore, the units of circumference are the same as the units of length.
As we can say, the surroundings are one-dimensional. As a result, you can measure in meters, kilometers, millimeters, etc.
Inches, feet, yards, and miles are other globally recognized units of circumference measurement.
According to our question,
sina = perpendicular\ hypotenuse
= 48/50
cosa= base\ perpendicular
=
14/50
Hence, The ratio of SINA and COSA = 48/50 and 14/50
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On a certain hot summers day, 402 people used the public swimming pool. The daily prices are 1. 50$ for children and 2. 00$ for adults. The receipts for admission totaled 648. 50$. How many children and how many adults swam at the public pool that day?
From the given information provided, there were 311 children who swam at the pool that day.
Let's use C to represent the number of children who swam at the pool and A to represent the number of adults who swam at the pool.
From the problem, we know that:
C + A = 402 (Equation 1) (The total number of people who used the pool was 402)
1.50C + 2.00A = 648.50 (Equation 2) (The total receipts from admission were $648.50)
To solve for C and A, we need to eliminate one of the variables. We can do this by multiplying Equation 1 by 1.50, which will give us:
1.50C + 1.50A = 603 (Equation 3)
Now we can subtract Equation 3 from Equation 2 to eliminate C:
2.00A - 1.50A = 648.50 - 603
0.50A = 45.50
A = 91
So there were 91 adults who swam at the pool that day. To find the number of children, we can substitute A = 91 into Equation 1:
C + 91 = 402
C = 311
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