The required exponential function f(x) = (4)(2)ˣ which is passes through the two points (-1,2) and (3,32).
What is an exponential function?An exponential function is defined as a function whose value is a constant raised to the power of an argument is called an exponential function.
It is a relation of the form y = aˣ in mathematics, where x is the independent variable
Let the formula for an exponential function would be as
⇒ f(x) = abˣ
The exponential function passes through the two points (-1,2) and (3,32).
f(-1) = 2
f(3) = 32
2 = ab⁻¹
2b = a
32 = ab³
Substitute the value of a = 2b in the above equation,
32 = 2b×b³
32 = 2b⁴
b⁴ = 16
b⁴ = 2⁴
b = 2
Substitute the value of b = 2 in the equation a = 2b,
So a = 2×2 = 4
⇒ f(x) = (4)(2)ˣ
Therefore, the required exponential function f(x) = (4)(2)ˣ
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Looking to receive help on the following practice question thank you.
use the definition of sec and write it in terms of cos
[tex]r=4\cdot\frac{1}{\cos \theta}[/tex]multiply both sides by cos
[tex]r\cos \theta=4[/tex]then we know that r*cos is equal to x in the cartesian
[tex]x=4[/tex]What are the solutions to the equation (x-3)(x+5)=-15
Hence, the solutions of the equation is [tex]x = 0, -2[/tex].
What is the equation?
A mathematical statement that shows that two mathematical expressions are equal.
Here given expression is
[tex](x-3)(x+5)=-15\\\\x^2+5x-3x-15=-15\\\\x^2+5x-3x=0\\\\x^2+2x=0\\\\x(x+2)=0\\\\x=0,-2[/tex]
Hence, the solutions of the equation is [tex]x = 0, -2[/tex].
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calculate the surface area of a hollow cylinder which is closed at one end if the base radius is 3.5 cm and the height is 8 cm
Answer:
A=2πrh+2πr2=2·π·3.5·8+2·π·3.52≈252.89821cm²
The surface area is 214.305cm².
What is surface area?The surface area is the area of the outer covering of the object.
It is given that radius, r=3.5 cm, and height, h=8 cm.
The surface area of the given object will be the sum of curved surface area and the area of the bottom, which is circle.
Surface Area = Curved Surface Area + Area of bottom circle
=2πrh+πr²
=2π(3.5)(8)+π(3.5)²
=56π+12.25π
=68.25π
Substitute π=3.14 to determine the surface area.
Surface Area = 68.25(3.14)
=214.305
So, the surface area will be 214.305cm².
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How many values does the expression 6+(x+3)^2 have?
The solution of a quadratic equation is imaginary.
What are the solutions of a quadratic function?
A quadratic equation with real or complex coefficients has two solutions, called roots.
These two solutions may or may not be distinct, and they may or may not be real.
The solution of the given quadratic function is calculated as follows;
6 + (x + 3)² = 0
subtract 6 from both sides of the equation;
6 + (x + 3)² - 6 = 0 - 6
(x + 3)² = - 6
take square root of both sides
x + 3 = √-6
x + 3 = 6i
x = 6i - 3
Thus, the solution of a quadratic equation can be determined solving for the value of unknown in the equation.
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the difference between 58% of a number and 39% of the same number is 247. what is 62% of that number
Answer
62% of the number = 806
Explanation
We are told that that the difference between 58% of a number and 39% of the same number is 247.
We are then asked to compute 62% of the number.
Let the number be x.
From the first statement,
58% of x = 0.58 × x = 0.58x
39% of x = 0.39 × x = 0.39x
The difference between them is 247
0.58x - 0.39x = 247
0.19x = 247
Divide both sides by 0.19
(0.19x/0.19) = (247/0.19)
x = 1300
So, we can now calculate 62% of the number
62% of x = 0.62 × x = 0.62 × 1300 = 806
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Write an equation of each circle described below. Show work! (Hint: find the coordinates of the center first)Given a circle with (5, 1) and (3,-1) as the endpoints of the diameter.(x − B1)² + (y - B2)² = (B3)²B1=B2=B3=Blank 1:Blank 2:Blank 3:Submit
Given:
It is given that a circle is represented by two end points (5,1) and (3,-1).
Find:
we have to find the equation of the circle, radius and center of the circle using end points.
Explanation:
The circle represented by two end points (5,1) and (3,-1) is drawn as
The diameter of the circle is
[tex]d=\sqrt{(5-3)^2+(1-(-1))^2}=\sqrt{4+4}=\sqrt{8}=2\sqrt{2}[/tex]Therefore radius of the circle is
[tex]B3=\frac{d}{2}=\frac{2\sqrt{2}}{2}=\sqrt{2}[/tex]The center of the circle is
[tex](B1,B2)=(\frac{5+3}{2},\frac{1-1}{2})=(\frac{8}{2},\frac{0}{2})=(4,0)[/tex]Therefore, the equation of the circle is
[tex](x-4)^2+(y-0)^2=(\sqrt{2})^2[/tex]where,
[tex]\begin{gathered} B1=4 \\ B2=0 \\ B3=\sqrt{2} \end{gathered}[/tex]HELP PLEASEEEEE!!!!!!
A rational number that is between -0.45 and -0.46 is -0.455.
What is the rational number?The values given are negative decimal numbers. A decimal is a method that is used to write non-integers. An example of a decimal is 0.48. A negative number is a number whose value is less than one.
A rational number is a number that can be expressed as a fraction of two integers
Examples of rational numbers are 2 , -0.455.
-0.455 can be expressed as an integer of -0.22750 and 0.22750.
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The table shows the numbers of ships that visited a port in the past 5 years. Identify a polynomial function for thenumber of ships in thousands that visited the port in a given year.
The function is f(x) = 1.3x^2 + 0.1X
Eddie brought his DVD set to the secondhand store to sell he was paid for all three DVDs in the set before he left Eddie used $15.70 of his earnings to purchase a pair of headphones had $2.30 remaining which equation can you use to find the amount of money Eddie received for each DVD
15.70(d-3)=2.30
3d-15.70=2.30
15.70d-3=2.30
3(d-15.70)=2.30
Eddie brought his DVD set to the secondhand store to sell he was paid for all three DVDs in the set before he left Eddie used $15.70 of his earnings to purchase a pair of headphones had $2.30 remaining which equation can you use to find the amount of money Eddie received for each DVD
15.70(d-3)=2.30
3d-15.70=2.30
15.70d-3=2.30
3(d-15.70)=2.30
answer reflects:
3 dvds sold for d price - cost of headphones and a remaining $2.30
given A(2, 3), B(8, 7), C(6 1), which will make line AB perpendicular to line CD?D(9, 3)D(4, 4)D(3, 3)D(8, 4)
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
A(2, 3), B(8, 7), C(6 1)
Step 02:
Line AB
Slope formula
m = (y2 - y1) / (x2 - x1)
A (2 , 3) x1 = 2 y1 = 3
B (8 , 7) x2 = 8 y2 = 7
[tex]m\text{ = }\frac{7-3}{8-2}=\frac{4}{6}=\frac{2}{3}[/tex]Step 03:
Slope of the perpendicular line, m’
m' = -1 / m
[tex]m\text{'}=\text{ }\frac{-1}{m\text{ }}=\text{ }\frac{-1\text{ }}{\frac{2}{3}}\text{ = -}\frac{3}{2}[/tex]Step 04:
Line CD
m' = (y2 - y1) / (x2 - x1)
C (6 , 1) x1 = 6 y1 = 1
D ( x2, y2) x2 = x2 y2 = y2
[tex]-\frac{3}{2}=\text{ }\frac{y2-1}{x2-6}[/tex][tex]\frac{3}{2}=\frac{1-y2}{6-x2}[/tex]We must test the numerical values to verify equality,
x2 = 9
y2 = 3
[tex]\frac{3}{2}=\frac{1-9}{6-3}\text{ = }\frac{-8}{3}\text{ }[/tex]x2 = 4
y2 = 4
[tex]undefined[/tex]X+87°2x⁰ i have to solve for x it’s a 180 angle
Answer:
31
Step-by-step explanation:
x + 87 and 2x are linear pair angles.
Sum of linear pair angles is 180,
x + 87 + 2x = 180
x + 2x + 87 = 180
3x + 87 = 180
3x = 180 - 87
3x = 93
x = 93 / 3
x = 31
Select the correct answer from each drop-down menu.Glven: W(-1, 1), X(3, 4), Y(6, 0), and Z(2, -3) are the vertices of quadrilateral WXYZ.Prove: WXYZis a square.
ANSWER
all four sides have a length of 5
EXPLANATION
The distance between two points (x₁, y₁) and (x₂, y₂) is,
[tex]d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}[/tex]Let's find the distance between each pair of points, WX, XY, YX, and WZ,
[tex]WX=\sqrt{(3-(-1))^2+(4-1)^2}=\sqrt{(3+1)^2+(4-1)^2}=\sqrt{4^2+3^2}=\sqrt{16+9}=\sqrt{25}=5[/tex][tex]XY=\sqrt{(6-3)^2+(0-4)^2}=\sqrt{(3)^2+(-4)^2}=\sqrt{3^2+4^2}=\sqrt{9+16}=\sqrt{25}=5[/tex][tex]YZ=\sqrt{(2-6)^2+(-3-0)^2}=\sqrt{(-4)^2+(-3)^2}=\sqrt{4^2+3^2}=\sqrt{16+9}=\sqrt{25}=5[/tex][tex]WZ=\sqrt{(2-(-1))^2+(-3-1)^2}=\sqrt{(2+1)^2+(-4)^2}=\sqrt{3^2+4^2}=\sqrt{9+16}=\sqrt{25}=5[/tex]Hence, using the distance formula we found that all four sides have a length of 5.
2 x— =-------7 x+ 10x = ???
Answer:
x = 4
Explanation:
Given the expression;
2/7 = x/x+10
Cross multiply
2(x+10) = 7x
Expand the bracket
2x + 20 = 7x
Subtract 7x from btoh sides
2x+20-7x = 7x - 7x
2x-7x+20 = 0
-5x + 20 = 0
-5x = -20
Divide both sides by -5;
-5x/-5 = -20/-5
x = 4
hence the value of x is 4
determine the point and slope that were used to write each linear equation in point slope form
The slope-point form is:
[tex]y-y_0=m(x-x_0)[/tex]where (x0,y0) is a point in the line and m is the slope.
A) If the equation is written in slope-point form, we have:
[tex]y-0=2(x-5)[/tex]Then, the point is (5,0) and the slope is m=2.
Answer: Point = (5,0)
Slope = 2
B)
[tex]\begin{gathered} y+3=5x \\ y-(-3)=5(x-0) \end{gathered}[/tex]Answer: Point (0,-3)
Slope = 5
For one of the meals eaten duringthe field trip to Williamsburg, VA,WHMS will be charged $115.50 foradults to eat and $712.50 forstudents to eat WHMS will leave a10% tip. How much money willWHMS leave for the tip
The total amount the WHMS would be charged for adults and students to eat is
115.5 + 712.5 = $828
We were told that WHMS will leave a 10% tip. Recall that percentage is expressed in terms of 100. This means that the amount of money that WHMS will leave for the tip is
10/100 * 828 = $82.8
WHMS would leave $82.8 for the tip
What is the greatest common factor of 28y^2 and 49y^2?A. 196y^2B. 7y^2C. 21y^2D. 7y
the value is 7 and keep the y^2
so is
[tex]7y^2[/tex]How many megagrams(Mg) are there in 3.6 tons?[ ? ] MgMass in MgEnter
Step 1
Given;
[tex]3.6\text{tons}[/tex]Required; To find how many megagrams(Mg) are in 3.6 tonnes
Step 2
Find how many megagrams(Mg) are in 3.6 tonnes
[tex]\begin{gathered} 1\text{ tonne=1000000}g \\ 1\text{ megagram=1}000000g \end{gathered}[/tex]Therefore,
[tex]1\text{ tonne = 1 megagram}[/tex][tex]\frac{1\text{ tonne}}{3.6\text{ tonnes}}=\frac{1\text{ megagram}}{x\text{ megagram}}[/tex][tex]\begin{gathered} x\text{ megagram(1 tonne)=1 megagram(3.6 tonnes)} \\ \frac{x\text{ megagram}(1\text{ tonne)}}{1\text{ tonne}}\text{=}\frac{\text{1 megagram(3.6 tonnes)}}{1\text{ tonne}} \\ x=\text{ 3.6 megagrams} \\ x=3.6Mg \end{gathered}[/tex]
Find all critical points of the function f(x) = x^3 + 5x^2 - 7x - 3.The critical point(s) is(are) =
We are given:
[tex]f(x)=x^3+5x^2-7x-3[/tex]Now, we know that in order to determine the critical points we derivate and the derivative is then equal to 0, that is:
[tex]f^{\prime}(x)=3x^2-10x-7=0[/tex]Now, we solve for x, that is:
[tex]3x^2+10x-7=0\Rightarrow x=\frac{-(10)\pm\sqrt[]{(10)^2-4(3)(-7)}}{2(3)}[/tex][tex]\Rightarrow\begin{cases}x=-\frac{5+\sqrt[]{46}}{3}\Rightarrow x\approx-3.9 \\ \\ x=\frac{-5+\sqrt[]{46}}{3}\Rightarrow x\approx0.6\end{cases}[/tex]So, the critical points of the function are:
[tex]\begin{cases}x=-\frac{5+\sqrt[]{46}}{3} \\ \\ x=\frac{-5+\sqrt[]{46}}{3}\end{cases}[/tex]Now, we determine the y-components of the points, that is:
[tex]\begin{cases}f(-\frac{5+\sqrt[]{46}}{3})=(-\frac{5+\sqrt[]{46}}{3})^3+5(-\frac{5+\sqrt[]{46}}{3})^2-7(-\frac{5+\sqrt[]{46}}{3})-3\Rightarrow f(-\frac{5+\sqrt[]{46}}{3})=41.03608735 \\ \\ f(\frac{-5+\sqrt[]{46}}{3})=(\frac{-5+\sqrt[]{46}}{3})^3+5(\frac{-5+\sqrt[]{46}}{3})^2-7(\frac{-5+\sqrt[]{46}}{3})-3\Rightarrow f(\frac{-5+\sqrt[]{46}}{3})=-5.184235498\end{cases}[/tex]So, the two critical points are:
[tex](-\frac{5+\sqrt[]{46}}{3},41.03608735)[/tex]and:
[tex](\frac{-5+\sqrt[]{46}}{3},-5.184235498)[/tex]This can be seing as follows:
3. (02.04 MC)
Choose the equation that represents a line that passes through points (-6, 4) and (2, 0).
The answer to the question is here
Which of the following could be the areas of the three squares below? A. 12ft^2, 16ft^2, 20ft^2B. 10ft^2, 18ft^2, 30ft^2C. 4ft^2, 5ft^2, 12ft^2D. 8ft^2, 16ft^2, 24ft^2i have to show work too :(
The correct option is D
8ft^2, 16ft^2, 24ft^2 could be the three areas of the given squares
Explanation:To know the area of the three squares, we need to know the side length of each square. This can be done by applying Pythagorean rule on the right-angle triangle formed in the middle.
The square of the longest side (hypotenuse) is equal to the sum of the squares of the other two sides (legs).
The area of a square is the square of its side length.
Taking the square roots of each of the given options, which ever option has Pythagorean triple is the correct option.
A.
[tex]2\sqrt[]{3},4,2\sqrt[]{5}[/tex]This is NOT a Pythagorean triple.
B.
[tex]\sqrt[]{10},3\sqrt[]{2},\sqrt[]{30}[/tex]This is NOT a Pythagorean triple.
C.
[tex]2,\sqrt[]{5},2\sqrt[]{3}[/tex]This is NOT a Pythagorean triple
D.
[tex]2\sqrt[]{2},4,2\sqrt[]{6}[/tex]This is a Pythagorean triple.
CHECK[tex]\begin{gathered} (2\sqrt[]{2})^2+4^2=(2\sqrt[]{6})^2 \\ 8+16=24 \\ 24=24 \end{gathered}[/tex]The total fixed costs of producing a product is $36,000 and the variable cost is $124 per item. If the company believes they can sell 1,800 items at $170 each, what is thebreak-even point?667 items695 items705 items783 itemsNone of these choices are correct.
Identify the leading coefficient, degree and end behavior. write the number of the LC and degree
Given
[tex]P(x)=-4x^4-3x^3+x^2+4[/tex]Solution
The LC is -4
End behavior is determined by the degree of the polynomial and the leading coefficient (LC).
TThe degree of this polynomial is the greatest exponent is
[tex]\begin{gathered} x\rightarrow\infty\text{ then P\lparen x\rparen} \\ p(\infty)=-4(\infty)^4-3(\infty)^3+\infty^2+4 \\ p(\infty)=-4\infty^4-3\infty^3+\infty^2+4 \\ P(\infty)=-\infty \\ \end{gathered}[/tex][tex]\begin{gathered} x\rightarrow-\infty \\ p(-\infty)=-4(-\infty)^4-3(-\infty)^3+(-\infty)^2+4 \\ P(-\infty)=-4\infty^4+3\infty^3+\infty^2+4 \\ P(-\infty)=-\infty \end{gathered}[/tex]The degree is even and the leading coefficient is negative.
The final answer
if you run 5/6 of a mile in 1/12 of how hour how much is that
The entire miles that the person runs in 1 hour is 10 miles
What is a fraction?A fraction simply means the numbers that's expressed as a/b where a = numerator and b = denominator.
In this case, the person runs 5/6 of a mile in 1/12 of an hour.
The number of miles for the entire run will be the division of the fractions given. This will be illustrated as:
= 5/6 ÷ 1/12
= 5/6 × 12
= 5 × 2
= 10 miles
The entire race is 10 miles.
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Prove the Question according to the theorem of a Circle
Given -
P,Q,R and S are 4 points on the circle and PQRS is a cyclic quadrilateral
Prove -
[tex]\angle PQR\text{ + }\angle PSR\text{ = 180}[/tex]Explanation -
[tex]\angle1\text{ = }\angle6\text{ ------\lparen1\rparen \lparen Angles in same segment\rparen}[/tex][tex]\angle5\text{ = }\angle8\text{ ------\lparen2\rparen \lparen Angles in the same segment\rparen}[/tex][tex]\angle2\text{ = }\angle8\text{ ------\lparen3\rparen \lparen Angles in the same segment\rparen}[/tex][tex]\angle7\text{ = }\angle3\text{ -------\lparen4\rparen\lparen Angles in the same segment\rparen}[/tex]By using angle sum property of quadrilateral
[tex]\angle P\text{ + }\angle Q\text{ + }\angle R\text{ + }\angle S\text{ = 360}[/tex][tex]\angle1\text{ + }\angle2\text{ + }\angle3\text{ + }\angle4\text{ + }\angle5\text{ + }\angle6\text{ + }\angle7\text{ + }\angle8\text{ = 360}[/tex][tex](\angle1+\angle2+\angle7+\angle8)+(\angle3+\angle4+\angle5+\angle6)=360[/tex]By using equation 1,2,3 and 4
[tex]2(\angle3+\angle4+\angle5+\angle6)\text{ = 360}[/tex][tex]\angle3+\angle4+\angle5+\angle6\text{ = 180}[/tex][tex](\angle3+\angle4)+(\angle5+\angle6)\text{ = 180}[/tex][tex]\angle PQR\text{ + }\angle PSR\text{ = 180}[/tex]Hence Proved
Exam Content
Question 25
Approximately how many years would it take money to grow from $5,000 to $10,000 if it could earn 6% interest?
It would take 16.66 years to grow from $5,000 to $10,000 if it could earn 6% interest.
Time it would take money to grow from $5,000 to $10,000
The prinicipal amount is $ 5000
The total amount is $ 10000
The rate of interest is 6%
Interest = Amount - principal
interest = 10000 - 5000 = 5000
By putting the simple interest formula
SI = prt/100
where p is the principal, r is the rate of interest and t is the time period
SI = 5000 x 6% x t/100
5000 = 5000 x 6 x t / 100
5000 x 100= 5000 x 6 x t
t = 100/6
t = 16.66
Therefore, it would take 16.66 years to grow from $5,000 to $10,000 if it could earn 6% interest.
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need help with this problem answer in a quick and clear response
Answer:
A system of inequalities with parallel boundaries doesn't have a solution when the regions for each inequality don't intersect. This region depends on the sign of inequality, so the signs of inequality determine if the system has solutions.
What does 10 represent in 10/6
10/6
This is a fraction, in a fraction the bottom number represents the denominator and the top number represents the numerator.
So, in this case, 10 represents the numerator.
Please hurry!!!
Is there a relationship between the distance and the sum? Is there a relationship between the distance and the difference?
A 5-column table with 3 rows. Column 1 is labeled a with entries 1, 4, negative 6. Column 2 is labeled b with entries 2, negative 1, negative 3. Column 3 is labeled a + b with entries 3, 3, negative 9. Column 4 is labeled a minus b with entries negative 1, 5, negative 3. Column 5 is labeled Distance with entries 1 unit, 5 units, 3 units.
Which describes the relationship between the distance and the difference?
The distance is always the opposite of the difference.
The distance is exactly the difference.
The distance is the absolute value of the difference.
The distance is not related to difference.
The third option that is the distance is the absolute value of the difference describes the relationship between distance and difference.
We know that the distance between two points is the difference of those two values.
But as the distance between two points can never be negative, we will write the absolute value of the difference as the distance between the two points.
Here we can see that,
a - b = -1 when distance = 1
a - b = 5 when distance = 5
a - b = 3 when distance = 3
Hence, the relationship between difference and distance is described by the third option.
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laws exponents multiplication band power to a power simplifymake it small steps please the smallest you canbare minimum of steps
Answer:
[tex](4r^4s^{-2})(-3rs^{-3})(rs)=-12r^6s^{-4}[/tex]Explanation:
Given the expression:
[tex](4r^4s^{-2})(-3rs^{-3})(rs)[/tex]This can be rearranged using law of multiplication (That multiplication is cummutative) to become:
[tex](4)(-3)(r^4rr)(s^{-2}s^{-3}s)[/tex]This becomes, using the law of exponents:
[tex]-12r^{4+1+1}s^{-2-3+1}[/tex]and finally, we have:
[tex]-12r^6s^{-4}[/tex]у = -3х5х + y = 14i need help finding the matrix of this
3x + y = 0
5x + y = 14
[tex]\Delta\text{ = }\begin{bmatrix}{3} & 1{} & \\ {5} & 1{} & {} \\ {} & {} & {}\end{bmatrix}\text{ = (3 x 1) - (5 x 1) = 3 - 5 = -2}[/tex][tex]undefined[/tex]