130 is what percent of 70?

Answer:

A) slope is 1

B) Slope is 3

C) slope is 0.5

Step-by-step explanation:

Using Rise over run method and mx+b

The result of the given expression in simplest form is [tex]\frac{4}{7}[/tex].

The given parameters:

16÷(2+12)2

The given expression can be evaluated in the following order as shown below;

add the numbers in the bracket;

2 + 12 = 14

multiply the numbers in the bracket by 2;

14 x 2 = 28

divide the 16 by your result after the multiplication;

[tex]= \frac{16}{28} \\\\[/tex]

divide the numerator and denominator by their common factor which is 4;

[tex]\frac{16}{(2+ 12) 2} = \frac{16}{28} = \frac{4}{7}[/tex]

Thus, the result of the given expression in simplest form is [tex]\frac{4}{7}[/tex].

Learn more about simplification of algebra here: https://brainly.com/question/432678

Answer:

6 red balls

Step-by-step explanation:

The probability in the first pick

6/21

The probability in the second pick (without replacement)

5/20

the requested probability

(6/21)(5/20) = 30/420

simplification

30/420 = 3/42 = 1/14

Hope this helps

Answer:

6 red balls.

Step-by-step explanation:

If there are x red balls then

probability of 2 red balls

= x/21 * (x - 1)/20 = 1/14

x^2 - x / 420 = 1/14

x^2 - x = 30

x^2 - x - 30 = 0

(x - 6)(x + 5) = 0

x = 6.

[tex]\text{Given that,}\\\\(x_1,y_1) = (-1,-2)~~ \text{and}~~ (x_2,y_2) = (-2,2)\\\\\text{Slope, m =} \dfrac{y_2-y_1}{x_2 -x_1} = \dfrac{2 -(-2)}{-2-(-1)} = \dfrac{2+2}{-2+1} = \dfrac{4}{-1} = -4[/tex]

Answer:

10.5

Step-by-step explanation:

A=a+b

2h=2+5

2·3=10.5

Answer:

solution given:

let's see only in a right-angled triangle Δ ACD.

AC=3 units

AD=5 units

since Δ ACD is a right-angled triangle. It satisfies Pythagoras law

[tex]AD^{2}=AC^{2}+CD^{2}[/tex]

25=9+[tex]CD^2[/tex]

[tex]CD^2[/tex]=25-9=16

[tex]CD=\sqrt{16} =4 units[/tex]

Now

Area of rectangle Δ ACD=[tex]\frac{1}{2} CD*AC=\frac{1}{2}*4*3=6\: square \:units[/tex]

similarly,

[tex]\frac{1}{2} AD*CE=6\: square \:units\\ 5*CE=6*2\\CE=\frac{12}{5}=2.4 units[/tex]

since AB=CE=2.4 units

Δ ACE is a right-angled triangle. It satisfies Pythagoras law.

[tex]AC^{2}=AE^{2}+CE^{2}\\3^2=AE^2+2.4^2\\9-5.76=AE^2\\AE and BC=\sqrt{1.24} =1.11 units[/tex]

now

area of trapezoid=area ofΔACD+Area of ΔABC

=6+[tex]\frac{1}{2}AB*BC=6+\frac{1}{2}*2.4*1.11=6+1.33 =7.33\: square \:units[/tex]

Step-by-step explanation:

Similar triangles may or may not have congruent sides, but the ratio of the corresponding sides will always be congruent.

(3) Corresponding sides of △MNP and △RST

Given that △MNP ∼△RST.

This means that, the corresponding sides are:

(4) The equal measures

Given that △ABC ∼△TUV

This means that, the corresponding angles are equal, but corresponding sides are not.

So, the equal measures are:

The unequal measure is:

(c) Scale mapping

The scale mapping is given as:

[tex]Ratio = 1\ in : 100\ mi[/tex]

The above scale means that 1 inches on the scale represents 100 miles of the actual distance.

Take for instance, 5 inches would represent 500 miles.

500 is 5 times 100

Hence, the actual distance between two towns 100 times the map distance between the two towns

Read more about similar triangles at:

https://brainly.com/question/14285697

Answer:

C. Multiply the first equation by -4

Step-by-step explanation:

Hi there!

In order to eliminate the y values, we would have to find a number in which the sum of the top y value and the bottom y value would equal 0. In this case, the bottom y value is equal to +4 (the +4y), so we would have to find the number that would add to make that 0, which is -4. Since the y value for the top equation is 1, all we have to do is multiply the equation by -4 so that our y value is equal to -4y and the y can be eliminated.

I hope this helps!!

Answer:

year 3:25 A,C,E

Step-by-step explanation:

Answer:

E

Step-by-step explanation:

[tex]\sqrt{\dfrac{64}{49}} = \dfrac{\sqrt{64}}{\sqrt{49}} = \dfrac 87[/tex]

Answer:

E

Step-by-step explanation:

Answer:

[(P - (2 x l)] / 2

Step-by-step explanation:

[Perimeter - ( 2 x length) ] / 2

(64 - 2x22)/2 = 10 pulgadas de ancho

Answer: It is f(x)= -3/2x-2

Step-by-step explanation: f(x) is the same as y. The formula for a line is slope-intercept form (y=mx+b). The -2 is the y-intercept, and the line intercepts the graph at -2. The slope is -3/2 because it rises 3 and goes to the left -2.

Step-by-step explanation:

first we use Pythagoras to get t :

c² = a² + b²

with c being the Hypotenuse.

so,

t² = r² + s² = 10² + 31² = 100 + 961 = 1061

t = sqrt(1061)

and then we use the law of sine :

a/sin(A) = b/sin(B) = c/sin(C)

with the angles being opposite of their related sides.

so, r/sin(R) = t/sin(T) = t/sin(90) = t/1 = t

sin(R) = r/t = 10/sqrt(1061) = 0.30700278...

R = 17.8786966... ≈ 17.9°

Answer:

y = 0.5x + 3

Step-by-step explanation:

Answer:

d. Line UR and Line VW are parallel

Step-by-step explanation:

If they were to continue going straight, they would not touch, making them parallel.

I hope this helps!

By Green's theorem (all the conditions are met), we have

[tex]\displaystyle \int_C \sqrt y \, dx + \sqrt x \, dy = \iint_D \frac{\partial(\sqrt x)}{\partial x} - \frac{\partial(\sqrt y)}{\partial y} \, dx \, dy[/tex]

where D is the interior of the path C, or the set

[tex]D = \left\{ (x, y) : 0 \le y \le \dfrac{x^2}2 \text{ and } 0 \le x \le 2 \right\}[/tex]

So, the line integral reduces to the double integral,

[tex]\displaystyle \frac12 \int_0^2 \int_0^{\frac{x^2}2} x^{-\frac12} - y^{-\frac12} \, dy \, dx[/tex]

[tex]\displaystyle = \frac12 \int_0^2 x^{-\frac12}\left(\frac{x^2}2\right) - 2\left(\frac{x^2}2\right)^{\frac12} \, dx[/tex]

[tex]\displaystyle = \frac12 \int_0^2 \frac12 x^{\frac32} - \sqrt 2 \, x \, dx[/tex]

[tex]\displaystyle = \frac14 \int_0^2 x^{\frac32} - 2\sqrt 2 \, x \, dx[/tex]

[tex]\displaystyle = \frac14 \left(\frac25\cdot2^{\frac52} - \sqrt2\cdot2^2\right) = \boxed{-\frac{3\sqrt2}5}[/tex]

Answer: the cost would be 2398.19

Step-by-step explanation: hope this helps:)

Answer:

Answer:

[tex]x=\frac{75}2[/tex]

Step-by-step explanation:

Give letters, as in the attached image.

The triangles ABE and CDE are similars (AAA). In particular [tex]AE:CE=BE:DE \rightarrow 46:30=(x+20):x \rightarrow 46x=30(x+20) \rightarrow 23x=15x+300 \rightarrow 8x=300\rightarrow x=\frac{75}2[/tex]

Answer: B

Step-by-step explanation: Function A starts at 0,2 and function B starts at 2,2

Answer:

It is C

Step-by-step explanation:

"No; Function A has an initial value of 2, and Function B has an initial value of 1. So, the functions do not have the same initial value."

Answer:

5

Step-by-step explanation:

You divide your number by the denominator and then times it by the numerator

Answer:

20°

Step-by-step explanation:

∡EFJ = 70°

∡JFK = 90°

So, ∡KFG = 180 - ∡JFK - ∡EFJ = 180 - 90 - 70 = 20°

Answer:

60

Step-by-step explanation:

i put 30 then it said the answer was 60

Answer:

i think it's 1.8.

Step-by-step explanation:

why? bc if u add 6/20 + 1.5 = 1.8

i think it's 1.8, im not sure, hopefully it's correct!!

Answer:

1.8

Step-by-step explanation:

you just simplify -6/20 into a decimal and you get .3 then you add it to 1.5.

Answer:

[tex]\sqrt{242}[/tex]

Answer: √490  

Step-by-step explanation:

.........................

11/12

Answer:

1. find the least common denominator (LCD) of 2/3, 1/4 in other words, find the Least Common Multiple (LCM) of 3,4

Least Common Multiple (LCM) of 3,4 LCD = 12

Least Common Multiple (LCM) of 3,4 LCD = 122.

Least Common Multiple (LCM) of 3,4 LCD = 122.Make the Denominators the Same As The LCD.

Least Common Multiple (LCM) of 3,4 LCD = 122.Make the Denominators the Same As The LCD.2_x_4_ + _1 x 3__

Least Common Multiple (LCM) of 3,4 LCD = 122.Make the Denominators the Same As The LCD.2_x_4_ + _1 x 3__3 x 4 4x3

Least Common Multiple (LCM) of 3,4 LCD = 122.Make the Denominators the Same As The LCD.2_x_4_ + _1 x 3__3 x 4 4x33. Simplify denominators are Now The Same.

8/12 + 3/12

4. join the denominators

__8+3_____

12

5. Answer 11/12

Btw the Lines are Just For Separating numbers.

Answer:

Step-by-step explanation:

You asked: How do you know when to rewrite square trinomials and difference of squares binomials as separate factors? First, and mostly obviously is when the directions say to factor the given expression. Next, if you're given an equation and asked to solve it. You set it equal to 0 and factor the perfect square trinomial or the difference of squares binomial. Set each factor equal zero and solve. This is a little bit oversimplified but, solutions are roots are zeros are x-intercepts, so if you are asked to find any of those things. Set your equation equal to zero, factor and solve. Also, if you have a rational expression (a fraction with a polynomial on top and a polynomial on the bottom) you would need to factor in order to simplify, to sketch a graph without technology. Anytime you need to simplify, factoring is good to try.

You also asked: How can sums and differences of cubes be identified for factoring? The sum or difference of cubes is in the form a^3 + b^3 or a^3 - b^3

You can memorize how to factor these a^3 + b^3 = (a+b)(a^2 - ab + b^2) and

a^3 - b^3 = (a-b)(a^2 + ab + b^2)

If you take the trouble to multiply these two factors back together you will see how four terms drop out and you get a binomial. Also the is an acronym SOAP to help you memorize it. Factoring cubes is used in the same way as you previous question. To factor, to solve, to simply, to graph. This was a really general question. I hope this helps.