The propagation delay of the link due to time dilatationis 1.152 x 10¹⁶ s.
We need to know about the time dilatation to solve this problem. Time dilatation represents that time is relative between the moving and static objects. From a static objects point of view, the time should be
t' = t / √(1 - v²/c²)
where t' is the interval time based on the static object, t is the interval time based on the moving object, v is velocity and c is the speed of light (3 x 10⁸ m/s),
From the question above, the given parameters are
v = 2.4 x 10⁸ m/s
D = 3.6 x 10⁷ m
Find the time taken based on moving objects
t = 2D . v
t = 2 . 3.6 x 10⁷ . 2.4 x 10⁸
t = 1.728 x 10¹⁶ s
Find the time interval based on static objects
t' = t / √(1 - v²/c²)
t' = 1.728 x 10¹⁶ / √(1 - (2.4 x 10⁸)²/(3 x 10⁸)²)
t' = 2.88 x 10¹⁶ s
Hence, the delay time is
Δt = t' - t
Δt = 2.88 x 10¹⁶ - 1.728 x 10¹⁶
Δt = 1.152 x 10¹⁶ s
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Find the total translational kinetic energy of0.5 L of oxygen gas held at a temperature of3◦C and a pressure of 1.5 atm.Answer in units of J.
Given
Volume of the oxygen gas is
[tex]V=0.5L=0.0005m^3[/tex]The temperature is
[tex]T=3^oC[/tex]Pressure is
[tex]\begin{gathered} P=1.5atm \\ \Rightarrow P=1.5\times101325=151,987.5Pa \end{gathered}[/tex]To find
The translational kinetic energy
Explanation
The translational kinetic energy is given by
[tex]K=\frac{3}{2}nRT[/tex]For ideal gas,
[tex]PV=nRT[/tex]Thus,
[tex]\begin{gathered} K=\frac{3}{2}PV \\ \Rightarrow K=\frac{3}{2}\times151987.5\times0.0005 \\ \Rightarrow K=113.99J \end{gathered}[/tex]Conclusion
The translational kinetic energy is 113.99J
a cart with a mass of 2.0 kg is pulled across a level desk by a horizontal foirce of 4.0n. if the coeffiecient of kinetic friciton is 0.12 what is the acceleration of the cart
Answer:
The acceleration of the cart:
a = 0.82 m/s²
Explanation:
Given:
m = 2.0 kg
F = 4.0 N
μ = 0.12
g = 9.8 m/s²
___________
a - ?
Friction force:
Ff = μ·m·g
2 Newton's law:
m·a = F - Ff
The acceleration of the cart:
a = ( F - Ff) /m
a = F/m - (μ·m·g) / m
a = F/m - μ·g
a = 4.0 / 2.0 - 0.12·9.8 ≈ 0.82 m/s²
a 7.0 g bullet is fired into a 1.5 kg ballistic pendulum. the bullet emerges from the block with a speed of 200 m/s, and the block rises to a maximum height of 11.7 cm. find the initial speed of the bullet.
the initial speed of the bullet: 520.31 m/sec
using the conservation of linear momentum we write
m1u1 + m2 u2 = m1 v1 + m2v2
where u1 and u2 are the initial velocities of masses m1 and m2\
where v1, and v2 are the final velocities of masses m1 and m2\
hence (.007) (u1) + 1.5(0) = 1.5(v2) + .007(200)
using the energy equation for the block alone we get
mgh = 1/2 m (v2[tex])^2[/tex]
hence 9.8(.0117) =.5 (v2[tex])^2[/tex]
hence v2= 1.494 m/sec
substitute it in 1
we get,
(.007) (u1) + 1.5(0) = 1.5(1.494 ) + .007(200)
u1 =initial speed of the bullet= 520.31 m/sec
What is Speed?The definition of speed can be given as a measure of the distance travelled by an object and the time needed to travel the distance. Simply put, it is a measure of how fast an object is moving, but it does not give direction. If we get direction by speed, it is called "velocity".
Speed can be calculated in science. The speed formula is a formula derived from science and is used to calculate different speeds. The formula for speed is:
[tex]Speed = \frac{Distance}{Time}[/tex]
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a uniformly charged conducting sphere of 1.22 m radius has a surface charge density of 8.13 c/m*. (a) find the charge on the sphere. (4) what ts the total electric flux leaving the surface of the sphere? (c) calculate the electric field at the surface of the sphere.
We select a spherical-shaped Gaussian surface that is concentric with the conducting sphere and has a little bigger radius. Gauss's law determines the flux:
ϕ= ϵ 0 q \s = 8.85×10 −12 C 2 /N.m 2
3.66×10 −5 C =4.1×10 6 N.m 2 /C
What makes it the Gauss law?Gauss' Law, which bears the name of German physicist Carl Friedrich Gauss, is the third of Maxwell's four equations. According to Gauss' Law, an electric charge, qv, or static electricity, produces an electric field, E. (voltage). According to this equation, adding more charge will result in a larger electric field.
According to Gauss's Law, the flux of an electric field through a closed surface equals the contained charge divided by a constant.
Gauss's Law may be used to determine the field due to four different types of equally charged objects: a straight wire, an infinite plate sheet, a thin spherical shell, and a low evenly charged sphere.
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The deepest section of ocean in the world is the Mariana Trench, located in the Pacific Ocean. Here,the ocean floor is as low as 10,918m below the surface. If the index of refraction of water is 1.33, howlong would it take a laser beam to reach the bottom of the treach?
Given:
The depth of the trench, d=10,918 m
The refractive index of the water, n=1.33
To find:
The time it takes for the laser beam to reach the bottom of the ocean.
Explanation:
The refractive index of water is given by,
[tex]n=\frac{c}{v}[/tex]Where c is the velocity of the laser in vacuum and v is the velocity of the laser in water.
On substituting the known values,
[tex]\begin{gathered} 1.33=\frac{3\times10^8}{v} \\ \implies v=\frac{3\times10^8}{1.33} \\ =2.3\times10^9\text{ m/s} \end{gathered}[/tex]The velocity is given by the equation,
[tex]v=\frac{d}{t}[/tex]Where t is the time it takes for the laser to reach the bottom of the trench.
On substituting the known values,
[tex]\begin{gathered} 2.3\times10^8=\frac{10,918}{t} \\ \implies t=\frac{10,918}{2.3\times10^8} \\ =47.5\times10^{-6}\text{ s} \\ =47.5\text{ }\mu\text{s} \end{gathered}[/tex]Final answer:
The laser beam would reach the bottom in 47.5 μs
larry uses a lever to list a box. where does inefficiency occur in the lever
Answer:
low internal resistance.
Explanation:
A lever has a high efficiency due to the fact that it has low internal resistance. The work it puts out is almost equal to the work it receives, because energy used up by friction is quite small. On the other hand, an a pulley might be relatively inefficient due to a considerably greater amount of internal friction.
a boy and a girl are at rest on separate skis 12 m apart on a horizontal icy surface. the boy and his skis have twice the inertia of the girl and her skis. determine the location of the center of mass in meters measured from the position of the girl.
With the position of the girl as a reference point, the center of mass is 8 m from the girl position.
If there are two objects as shown on the attached picture, the center of mass is:
xc = m₁ / (m₁ + m₂) . x₁ + m₂ / (m₁ + m₂) . x₂
From the problem, we know that the boy and his skis have twice the inertia of the girl and her skis. We can replace the mass in the equation with inertia, hence:
xc = I₁ / (I₁ + I₂) . x₁ + I₂ / (I₁ + I₂) . x₂
Let:
I₁ = the girl's inertia
I₂ = the boy's inertia
Hence,
I₂ = 2 I₁
Let make the position of the girl as a reference point, then,
x₁ = 0
x₂ = 12
Plug these parameters into the formula:
xc = I₁ / (I₁ + I₂) . 0 + 2 I₁ / (I₁ + 2 I₁) . 12
xc = 2/3 . 12 = 8 m
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When resistors are put in series next to each other, their overall resistance isA. Larger than that of any individual resistorB.the same as the resistance of one of the resistorsC. Smaller than the resistance of any of the resistors
Answer:
A. Larger than that of any individual resistor
Explanation:
When resistors are put in series, the overall resistance is equal to the sum of all the resistances. So, the overall resistance will be larger than that of any individual resistor.
alena is performing a floor routine. in a tumbling run she spins through the air, increasing her angular velocity from 43.00 to6 5.00 rev/s while rotating through one-half of a revolution. how much time does this maneuver take?
The tumbling run by Alena lasted for 0.009 seconds.
The time of tumbling can be calculated using the formula -
time = (2 × theta) ÷ (initial angular velocity + final angular velocity)
Keep the values in formula to find the amount of time took while tumbling.
Time = (2 × 0.5) ÷ (43 + 65)
Performing multiplication in numerator and addition in denominator of Right Hand Side of the equation
Time = 1 ÷ 108
Performing division on Right Hand Side of the equation
Time = 0.009 seconds
Thus, Alena took 0.009 seconds in tumbling while performing floor routine.
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i would appreciate it if you could help me if would help a bunch on getting caught up with my work.
2. Experiment:
We need to make a circuit to test which of the materials are conductors and insulators.
Build the circuit as shown below.
If the light bulb is on then it is a conductor otherwise it is an insulator.
Keep replacing the material one by one to test all the materials.
Equal masses are suspended from two separate wires made of the same material. The wires have identical lengths. The first wire has a larger cross-sectional area than the second wire. Which wire will stretch the least?.
The original lengths of both wires are equal, the thicker wire will stretch less as a result since Young's Modulus predicts that its original length will change less.
Young's modulus is a measurement of a material's capacity to endure changes in length when subjected to compression or tension along its length. Young's modulus, also known as the modulus of elasticity, is determined by dividing the longitudinal stress by the strain. i.e.Young's modulus = stress/strain
We can assume that the thicker wire must have less strain if it suffers less stress than the thinner wire because strain is defined as the percentage change in length.
Therefore we can said that, For the Young's modulus to remain constant, which it does, it must also drop correspondingly as strain rises. The thicker wire will stretch less as a result since its original length will change less because both wires started off the same length.
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What is the BEAT FREQUENCY when 512 Hz and a 515 Hz tuning forks are sounded at the same time?
The beat frequency is 3 beats/sec.
Beat frequency(n) can be found by using the following formula:
n=f2-f1, where f2 and f1 are the given frequencies
n= 515-512
n= 3 beats/sec
Therefore the beat frequency when 512 Hz and 512Hz tuning forks are sounded together is 3 beats/sec.
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How long would it take an airplane to travle 1089 miles if its flying at a speed of 375 miles per hour
Answer:
2.904
Explanation:
It would take an airplane 2.904 hours to travel 1089 miles.
As a fraction, this would equal 363/125
As a percentage, this would equal 290.4%
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32. heavy rain reduces your ability to see and be seen; in daytime turn on your a. windshield wipers. b. low beam headlights. c. windshield defroster. d. all of the above
Heavy rain reduces your ability to see and be seen. So in daytime turn on all of the above ( d ) mentioned options.
Windshield wipers and windshield defroster are for the ability to see and the low beam headlights are for the ability to be seen by others. If it is night time drive below the speed limit because it is extremely hard to maneuver under those conditions.
Windshield wipers wipes the water off your windshield consistently. Low beam headlights indicate the presence of your car. Windshield defroster condenses the frosted windshield.
Therefore, in daytime turn on your windshield wipers, low beam headlights and windshield defroster.
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Neptune has a mass that is about 17 times the mass of earth. the distance between the sun and neptune is about 30.1 times the distance between the sun and earth. if the gravitational force between the sun and earth is 3.5 x 1028 n, which is closest to the force between neptune and the sun? 6 x n 6 x n 6 x n 6 x n
Answer: 6 x 10^26 N
Explanation:
describe the forces that are acting on the cake as it falls and when it lands on the ground.
Answer:
gravitational force
Explanation:
expressed the weight of the object.
When the cake falls into the ground gravitational force and electromagnetic forces are working on it and when it lands on the ground gravitational, electromagnetic and normal force act on it.
What is Force?Force is the influence of either pull or pushes in the body. Basically, gravitation forces, nuclear forces, and friction forces are the types of forces. For e.g. when the wall is hit by a hand then a force is exerted by the hand on the wall as well as the wall also exerts a force on the hand. There are different laws given to Newton to understand force.
Two fundamental forces are at play while the ball falls: gravity, which causes the ball to descend, and electromagnetic forces, which causes the ball to interact with the air.
The gravity force still affects the ball when it strikes the ground, but it is less significant than the electromagnetic force generated by the earth and the ball itself. The deformation and restoration of the ball's shape are caused by the EM (electromagnetic) inside the ball. The ball stops descending due to the EM force with the earth.
So the simple answer is consistent with the other answers here: the electromagnetic force is responsible for the force between the ball and the ground.
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A tennis player can accelerate a tennis ball at 295m/s² using an average force of
58 N with his racquet. What is the mass of the tennis ball?
answer of the question is into the picture ️
Four different balls with different masses (measured in grams) were dropped from the same height on Earth. Assuming no other forces acted on the balls, match each ball with the gravitational force (measured in newtons) it experienced as it fell.gravitational force = 9.8 m/s2
We will have the following:
1. 143 g = 0.143 kg:
[tex]F=(0.143kg)(9.8m/s{}^2)\Rightarrow F=1.4014N[/tex]2. 110 g = 0.110 kg:
[tex]F=(0.110kg)(9.8m/s^2)\Rightarrow F=1.078N[/tex]3. 410 g = 0.410 kg:
[tex]F=(0.410kg)(9.8m/s^2)\Rightarrow F=4.018N[/tex]4. 46 g = 0.046 kg:
[tex]F=(0.046kg)(9.8m/s^2)\Rightarrow F=0.4508N[/tex]From this we can see that the given weights do not correspond to any of the values of column B, since the calculations to obtain the values of column B were done using grams, instead of kg, thus those values do not correspond to the unit of force Newtons.
a 60- kg mountain climber moves 10 m up a vertical slope. if the muscles in her body convert chemical energy into gravitational potential energy with an efficiency of no more than 5%, what is the chemical energy used to climb the slope?
120000 Joules of Chemical Energy is used by the climber to climb the rope.
As the climber is moving up, its gravitation potential energy energy (G) will be given by,
Gravitational potential Energy = MgH
G = MgH
Where,
M is mass of climber which is 69 Kg,
g is acceleration due to gravity which is 10m/s².
H is the height above the earth's surface which is 10 meters.
It is provided that the chemical energy is converted to gravitational energy at a rate of 5%.
So, we can write,
5% Chemical energy (C) = Gravitational potential energy (G)
So,
5%C = MgH
Putting all the values,
5C/100 = 60(10)(10)
C = 120000 Joules.
The used chemical energy is 120000 Joules.
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would not be an indication of a car getting ready to pull into your lane. a. a turn signal b. a hand signal c. wheels turned toward the street d. an open car door
The option that would not be an indication of a car getting ready to pull into your lane is an open car door ( d ).
Option A is an indication of a car getting ready to pull into your lane because a turn signal is an indicator installed in the car to indicate the change of lanes. Option C is an indication of a car getting ready to pull into your lane, but it is not a 100% indication, because not every driver is going to notice if your wheels are turned or not.
Option B is an indication of a car getting ready to pull into your lane during day time because during day time the turn signal might not be bright enough to see. So one probably uses hand signal to make sure that other drivers see clearly that you are about to change lanes.
Therefore, the option that would not be an indication of a car getting ready to pull into your lane is an open car door ( d ).
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The separation distance between two 2.0 kg masses is decreased by two-thirds. How is the gravitational force between them affected?
Given:
The mass of two objects is: m1 = m2 = m = 2 kg
The distance between the object is decreased by two-thirds
To find:
How on reducing the distance, the gravitational force between them affects them.
Explanation:
Let the distance between two objects each having mass "m" be "r". The gravitational force between them is given as:
[tex]F_1=G\frac{m_1\times m_2}{r^2}[/tex]Here, G is the universal gravitational constant.
Substituting the values in the above equation, we get:
[tex]\begin{gathered} F_1=G\times\frac{2\text{ kg}\times2\text{ kg}}{r^2} \\ \\ F_1=G\times\frac{4\text{ kg}^2}{r^2}..........(1) \end{gathered}[/tex]Now, the distance between the mass is reduced by two-thirds. Thus, the new distance between them will be "R" which is given as:
[tex]R=r-\frac{2}{3}r=r(1-\frac{2}{3})=\frac{r}{3}[/tex]Now, the gravitational force between two masses with their distance of separation reduced by two-thirds is given as:
[tex]F_2=G\frac{m_1\times m_2}{R^2}[/tex]Substituting the values in the above equation, we get:
[tex]\begin{gathered} F_2=G\times\frac{2\text{ kg}\times2\text{ kg}}{(\frac{r}{3})^2} \\ \\ F_2=G\times\frac{4\text{ kg}^2}{\frac{r^2}{9}} \\ \\ \begin{equation*} F_2=G\times\frac{9\times4\text{ kg}^2}{r^2} \end{equation*} \\ \\ F_2=9\times(G\times\frac{4\text{ kg}^2}{r^2})..........(2) \end{gathered}[/tex]Substituting equation (1) in equation (2), we get:
[tex]\begin{gathered} F_2=9\times(G\times\frac{4\text{ kg}^2}{r^2}) \\ \\ F_2=9F_1 \end{gathered}[/tex]From the above equation, we observe that the new gravitational force F2 between two masses when their distance of separation is reduced by two-thirds will be nine times that of the original value of gravitational force F1.
Final answer:
The new gravitational force F2 between two masses when their distance of separation is reduced by two-thirds will be nine times that of the original value of gravitational force F1.
a pipe that is 0.46 m long and open at both ends vibrates in the second overtone with a frequency of 1150 hz. in this situation, the distance from the center of the pipe to the nearest antinode is closest to group of answer choices zero. 7.7 cm. 15 cm. 12 cm. 3.8 cm.
The distance of the center pipe to the nearest antinode at the second harmonic frequency is closest to 12 cm.
We need to know about the harmonic frequency to solve this problem. When the string is vibrating at its second harmonic frequency, it should follow the rule
λ = L
where λ is wavelength and L is the length of the string
From the question above, we know that
f = 1150 Hz
L = 0.46 cm
Find the wavelength
λ = L
λ = 0.46 m
The distance from the center of the pipe to the nearest antidote is equal to 1/4 of the wavelength. Hence,
s = 1/4 λ
s = 1/4 . 0.46
s = 0.115 m
s ~ 12 cm
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A 10 kg box is pulled across a level floor, where the coefficient of kinetic friction is
0.35. What horizontal force is required for an acceleration of 2.0 m/s2?
A 10 kg box is pulled across a level floor, where the coefficient of kinetic friction is 0.35. The horizontal force is required for an acceleration of 2.0 m/s2 will be 54.3 N
Newton’s second law states that the acceleration of an object depends upon two variables – the net force acting on the object and the mass of the object. The acceleration of the body is directly proportional to the net force acting on the body and inversely proportional to the mass of the body.
equation of motion will be
F(net) = mass * acceleration
F - fr = m * a
where
F = force by which the box is moving
fr = force due to friction
m = mass of the object
a = acceleration by the object is moving
F = fr + m * a
= (mu * N) + ma where N = mg
= (mu * mg) + ma
= (0.35 * 10 * 9.8) + 10 * 2
= 54.3 N
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psychology is the ___ study of behavior and mental processes
Answer:
scientific study
Explanation:
I hope that helps
Answer:
scientific studies
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Isaac is practicing his volleyball skills by volleying a ball straight up and down, over and over again. His teammate
Marie notices that after one volley, the ball rises 3.6 m above Isaac's hands. What is the speed with which the ball left
Isaac's hand? (8.4 m/s)
Answer:
the velocity of a ball at highest point is 8.5m/s
Explanation:
: The Freefall Problem
Xue,is standing on the roof of a building. Emily is standing below and tosses a ball straight upwards to Xue. It travels up past
Xue, comes back down and Xue reaches out and catches it. Xue catches the ball 6.0 m above Emily’s hands. The ball was
travelling at 12.0 m/s upwards the moment it left Emily’s hand. We would like to know how much time this trip takes.
1. Represent. Complete part A below. Indicate the y-origin for position measurements and draw a sign convention where
upwards is positive. Label the important events.
2. Represent. Complete part C below. Make sure the two graphs line-up vertically. Draw a single dotted vertical line
through the graphs indicating the moment when the ball is at its highest.
A: Pictorial Representation
Sketch, coordinate system, label givens, conversions, describe events
Event 1:
Event 2:
Event 3:
C: Physics Representation
Motion diagram, motion graphs, key events
The total length of the path traveled by an object is the distance. The change in position, from one event to another is the
displacement. Distance is a scalar quantity and displacement is a vector quantity.
3. Reason. Explain why this in this example it is relatively easy to find the displacement, but harder to find the distance.
4. Reason. The BIG 5 equations are valid for any interval of motion where the acceleration is uniform. Does the ball
accelerate uniformly during events 1 and 3? Explain D: Mathematical Representation
Describe steps, complete equations, substitutions with final statement isThere are multiple ways of solving…one
will require the use of the quadratic formula.
The other way will take additional steps.
x = -b+-under root b^2-4ac/2a
Study the graph shown below. It is a graphic of a car trip taken by Amber and Ken. The starting position (0,0) is their home.
Graph of position versus time, with position on the y axis from 0 to 75 miles and time on the x axis from 0 to 8.5 hours. Segment 1 goes from 0,0 to 1,30. Segment 2 goes from 1,30 to 3,50. Segment 3 goes from 3,50 to 4,50. Segment 4 goes from 4,50 to 5,70. Segment 5 goes from 5,70 to 6,70. Segment 6 goes from 6,70 to 7,30. Segment 7 goes from 7,30 to 8,0.
How far had they traveled after four hours of travel?
a
30 miles
b
40 miles
c
50 miles
d
60 miles
The distance that they had traveled after four hours is given by:
c 50 miles.
How to find the distance traveled?We are given the a set of points (x,y) in this problem, in which the input and the output are defined as follows:
Input: x is the number of hours.Output: y is the distance traveled, in miles, after a time of x hours.The endpoints of the segments are as follows:
(0,0): Initially, 0 miles were traveled.(1,30): 30 miles were traveled in one hour.(3, 50): 50 miles were traveled in three hours.(4,50): 50 miles were traveled in four hours.Hence, the distance that they had traveled after four hours is given by 50 miles, and option c is the correct option in the context of this problem (how long they had traveled).
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when resistors 1 and 2 are connected in series, the equivalent resistance is 13.6. when they are connected in parallel, the equivalent resistance is 2.40. what are (a) the smaller resistance and (b) the larger resistance of these two resistors?
The larger resistance is R₂ =12Ω.
Resistance values are expressed in ohms (Ω). when an electron differential exists among terminals, energy will float from excessive to low. Resistance counteracts that waft. The greater the resistance, the lower the current. Conversely, the decrease in the resistance, the extra the modern.
series connection:- R equivalent = R₁ + R₂
R₁ + R₂ = 13.6 Ω
R₁ = 13.6 Ω - R₂
parallel connection:- R equival;ent = R₁R₂ / R₁ + R₂
2.40 = R₁R₂ / R₁ + R₂
2.40 = R₁R₂ / 13.6 Ω
R₁R₂ = 2.40 × 13.6 Ω
R₁R₂ = 32.64 Ω
2.40 = R₁R₂ / R₁ + R₂
R₁ + R₂ = 32.64 Ω / 2.40 Ω
R₁ + R₂ = 13.6.
must be 4.0Ω and 13.6Ω, respectively.
(a) The smaller resistance is R₁ =4.0Ω
(b) The larger resistance is R₂ =12Ω
An electric-powered cutting-edge flows when electrons flow through a conductor, consisting of a metallic cord. The moving electrons can collide with the ions in the steel. This makes it greater tough for the present day to flow, and reasons for resistance.
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what is a tone? multiple choice question. a sound with definite and steady vibrations a note that is emphasized the distance between two pitches the distinctive sound quality of an instrument
A tone is a sound with definite and steady vibrations.
What is tone?
The author's attitude toward the topic they are writing about is the definition of tone in literature. The Latin word tonus, which means a sound or accent, and the French word tonne, which denotes a musical sound, are the origins of the word tone. Whether the author intends it or not, the reader always picks up on the tone of a work of literature. The words an author chooses as well as how they are used make up their diction. The way an author speaks affects the reader's mood. The syntax, point of view (a particular attitude as well as way of describing a subject), diction, and degree of formality used in writing all convey the tone of the piece. Writing can take on a formal or informal tone.
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A periodic wave has a wavelength of 1.6 m and a speed of 16 m/s. What is the wave frequency?
ANSWER
10 Hz
EXPLANATION
Given:
• The wavelength of a periodic wave, λ = 1.6 m
,• Its speed, v = 16 m/s
Find:
• The wave frequency, f
The frequency of a wave is given by the quotient between the wave's speed and its wavelength,
[tex]f=\frac{v}{\lambda}[/tex]Replace the known values and solve,
[tex]f=\frac{16m\/s}{1.6m}=10\text{ }\frac{1}{s}=10\text{ }Hz[/tex]Hence, the frequency of the wave is 10 Hz.
a passenger walks along the aisle of a train at a speed of 1.3 m/s. the train moves at a speed of 30.2 m/s with respect to the ground. calculate the relativistic correction to the classical value of the passenger speed with respect to the ground. what is the percentage of this correction?
The parameters of speed are time divided by distance.The most often used unit of speed in daily life is the kilometer per hour (km/h), or miles per hour in the US and the UK. The SI's unit of speed is the metre per second (m/s) (mph).
How are speeds determined?
Speed is calculated as follows: speed = distance * time.Knowing the units for distance and time is necessary to calculate the units for speed.The units will be in metres per second (m/s) in this example since the distance is measured in metres (m) and the time is measured in secondsWe have provided The passengers' speed in relation to the train is 2.30 mph, not 2.30 g.Additionally, the passenger is moving at a speed of 30.2m/s relative to the ground.And at a 28 degree angle to the north-west.Therefore, the cost for us passengers will be 4.5 cost 28 and the I. component will be 30.2 signed 28.Now that we know the train's velocity with respect to the ground, we can calculate the passengers' velocity with respect to the train by subtracting the train's velocity with respect to the ground.We shall rearrange this equation once we have determined a city of trained individuals with regard to the ground.Now, if we just insert all of these variables, the passenger's velocity is equal to 30.2 28° I + 4.5 Cost 28° J minus 2.30 G.And after calculation, this will be equal to 3.97 G -2.30 G less, or -2.11 I.Furthermore, this will result in -2.11 I plus 1.67 G.The equation for training velocity with respect to the ground will now be as follows.The size and direction of the trend's velocity with respect to the ground must be determined.Therefore, the magnitude will be 2.11 sq plus 1.67, square root off.We shall rearrange this equation once we have determined a city of trained individuals with regard to the ground.Now, if we just insert all of these variables, the passenger's velocity is equal to -4.5 9 28° I + 4.5 Cost 28° J minus 2.30 G.Calculating yields a value of 2.69 meters per second, and the direction is equal to 2.11 divided by 1.67, which will result in 51.63 agreement.As a result, the trend's magnitude and direction will be B, 2.69 m/s, and 51.63°, respectively, with regard to the ground.
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As a result, the trend's magnitude and direction will be B, 2.69 m/s, and 51.63°, respectively, with regard to the ground.
How are speeds determined?Knowing the units for distance and time is important to determine the units for speed. In this example, the units will be measured in metres per second (m/s), as the distance is measured in metres (m) and the time is measured in seconds.We have said that, rather than 2.30 g, the passengers' speed in respect to the train is 2.30 mph.In addition, the passenger is traveling at a relative speed of 30.2 m/s to the ground.Additionally, at a 28-degree northwestern angle.As a result, our guests will pay 4.5 cost 28 and the I. component will be signed at 30.2 and be.To learn more about value of speed refer
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