2. Write a story that can be represented by the equation y = x + 1/4 x.Question 2 On a hot day a football team drank an entire 50-gallon cooler of water and half as much again. How much water did they drink? Create an equation to represent this situation.

Answers

Answer 1

y= x+ 1/4 x

Y = dependent variable

x= independent variable

Jenny has a bank account. In the first month, she deposits a certain amount of money (x), and in the month after she deposits 1/4 of that amount.

Find the total amount of money deposited (y).


Related Questions

2.Find the range of thisquadratic function.1-3-2-11y = x2 + 2x-27А-1 < y< ooB- < y < oo

Answers

Okay, here we have this:

Considering that the range of a function is the complete set of all possible resulting values of the dependent variable (y), we can see in the graph of the function that:

The values of the variable "y" go from -1 to plus infinity, this mean that the range is:

-1≤y<∞

Finally we obtain that the correct option is the first option.

Using the formula C =5/9(F −32), find C when F is −58∘.? C∘

Answers

ANSWER

C = -50 degree Celcius

STEP-BY-STEP EXPLANATION:

What to find? The value of C in degree Celcius

Given Parameters

F = -58 degree Fahrenheit

The formula is given below

[tex]C=\text{ }\frac{5}{9}(F\text{ - 32)}[/tex]

Substitute the value of into the equation

[tex]\begin{gathered} C\text{ = }\frac{5}{9}(-58\text{ - 32)} \\ \text{Solve the expression inside the parenthesis first} \\ C\text{ = }\frac{5}{9}(-90) \\ C\text{ = }\frac{-5\cdot\text{ 90}}{9} \\ C\text{ = }\frac{-450}{9} \\ C=-50^oC \end{gathered}[/tex]

Hence, the value of C is -50 degrees

Which of the following are a qualitative catecorical variables

Answers

A qualitative variable, also called a categorical variable, is a variable that isn’t numerical. It describes data that fits into categories.

From the given options below, the arrival status of a train ( early, on time, late, canceled) and a person's blood type are the only qualitative variables.

Hence, Option 3 and Option 5 are the correct answers.

Please help me solve this math problemRewrite in exponential form Ln3=y

Answers

[tex]\begin{gathered} 1)\ln(x)=6\: \\ 2)e^y=3 \end{gathered}[/tex]

1) Let's rewrite it as a logarithmic expression of the following exponential one. Let's do it step by step.

[tex]\begin{gathered} e^6=x \\ \ln e^6=\ln x \\ \ln(x)=6 \end{gathered}[/tex]

Note that when we apply the natural log on both sides, we use one of those properties that tell us that we can eliminate the log since the base of a natural log is "e", as well as, "e" is the base of that power.

2) To rewrite in the exponential form we can do the following:

[tex]\ln(3)=y\Leftrightarrow e^y=3[/tex]

Note that in this case, we have used the definition of logarithms.

O EQUATIONS AND INEQUALITIESSolving a decimal word problem using a linear equation with th.

Answers

Given:

[tex]PlanA=0.16\text{ for each minutes of calls}[/tex][tex]PlanB=25\text{ monthly fee plus 0.12 for each minute of calls}[/tex]

To Determine: The numbers of calls for the which the two plans are equal

Solution

Let x be the number of minutes of calls for which the two plans are equal

The cost of plan A is

[tex]C_{ost\text{ of plan A}}=0.16x[/tex]

The cost of plan B

[tex]C_{ost\text{ of plan B}}=25+0.12x[/tex]

If the cost for the two plans are equal, then

[tex]0.16x=25+0.12x[/tex]

Solve for x

[tex]\begin{gathered} 0.16x-0.12x=25 \\ 0.04x=25 \\ x=\frac{25}{0.04} \\ x=625 \end{gathered}[/tex]

Hence, the number of minutes of calls for which two plans are equal is 625 minutes

10(6 + 4) ÷ (2³-7)² =

Answers

Answer:

100

Explanation:

Given the expression

[tex]10\mleft(6+4\mright)\div(2^3-7)^2[/tex]

First, we evaluate the bracket and exponents.

[tex]=10\mleft(10\mright)\div(8-7)^2​[/tex]

This then gives us:

[tex]\begin{gathered} 100\div(1)^2 \\ =100\div1 \\ =100 \end{gathered}[/tex]

What is the distance from the ball to the base of the building? Round to the nearest foot.*

Answers

Given:

[tex]\theta=37^{\circ}\text{ ; height of the building is }60\text{ ft}[/tex][tex]\begin{gathered} \tan 37^{\circ}=\frac{Height\text{ of the building}}{\text{Distance between the ball and foot of the building}} \\ 0.7536=\frac{60}{\text{Distance between the ball and foot of the building}} \\ \text{Distance between the ball and foot of the building}=\frac{60}{0.7536} \\ =80\text{ feet} \end{gathered}[/tex]

80 feet is the final answer.

Triangle A is rotated 90° about the origin. Which triangle shows the image?

Answers

Rotation 90° about the origin.

First, choose a point from triangle A.

For example: (-2,2)

For any point (x,y) rotated 90° =(-y,x)

So:

(-2,2) becames = (-2,-2)

Triangle D

Find all the solutions and if there is an extraneous solution, identify them and explain why they are extraneous.

Answers

ANSWER

Solution: b = 3

It is extraneous

EXPLANATION

We want to solve the equation given and to see if there are any extraneous solutions.

We have:

[tex]\begin{gathered} \frac{7}{b\text{ + 3}}\text{ + }\frac{5}{b\text{ - 3}}\text{ = }\frac{10b}{b^2\text{ - 9}} \\ \Rightarrow\text{ }\frac{7}{b\text{ + 3}}\text{ + }\frac{5}{b\text{ - 3}}\text{ = }\frac{10b}{(b\text{ + 3)(b - 3)}} \\ \text{Multiply both sides by (b + 3)(b - 3):} \\ \Rightarrow\text{ }\frac{7(b+3)(b\text{ - 3)}}{b\text{ + 3}}\text{ + }\frac{5(b\text{ + 3)(b - 3)}}{b\text{ - 3}}\text{ = }\frac{10b(b\text{ + 3)(b - 3)}}{(b\text{ + 3)(b - 3)}} \\ 7(b\text{ - 3) + 5(b + 3) = 10b} \\ 7b\text{ - 21 + 5b + 15 = 10b} \\ \text{Collect like terms:} \\ 7b\text{ + 5b - 10b = 21 - 15} \\ 2b\text{ = 6} \\ Divide\text{ both sides by 2:} \\ b\text{ = }\frac{6}{2} \\ b\text{ = 3} \end{gathered}[/tex]

That is the solution to the equation.

To find if the solution is extraneous, we will insert the value of b = 3 into the original equation.

That is:

[tex]\begin{gathered} \Rightarrow\text{ }\frac{7}{3\text{ + 3}}\text{ + }\frac{5}{3\text{ - 3}}\text{ = }\frac{10(3)}{(3\text{ + 3)(3 - 3)}} \\ \frac{7}{6}\text{ + }\frac{5}{0}\text{ = }\frac{30}{(6)(0)} \\ \frac{7}{6}\text{ + }\frac{5}{0}\text{ = }\frac{30}{0} \end{gathered}[/tex]

An extraneous solution is a solution that derives from solving a rational equation but does not exactly satisfy the original equation, that is, it is invalid for the equation.

By inserting b = 3 into the equation, we see that the equation is undefined.

Therefore, since b = 3 is a solution, but it does not satisfy the equation, it is an extraneous solution.

Evaluate( - 4) ^ 3/2

Answers

[tex]\begin{gathered} -4^{\frac{3}{2}}=\sqrt[2]{(-4)^3}=\sqrt[2]{-64}=\sqrt[2]{-1\cdot64}=8i \\ \end{gathered}[/tex]

Answer: 8i

Hayley's rectangular bedroom is 6 meters by 5 meters. What is the diagonal distance from one corner to the opposite corner? If necessary, round to the nearest tenth.

Answers

Hayley's rectangular bedroom is 6 meters by 5 meters. What is the diagonal distance from one corner to the opposite corner? If necessary, round to the nearest tenth.

Apply the Pythagorean Theorem

c^2=a^2+b^2

we have

a=6 m

b=5 m

c^2=6^2+5^2

c^2=36+25

c^2=61

square root c=7.8 m

answer is 7.8 meters

What is the probability that the spinner lands on a prime number?

Answers

Answer:

Step-by-step explanation:

50

The probability that the spinner lands on a prime number is 1/9 welcome

Ms. Wong sold 28 cars. She sold 8 fewer cars that 3/4 as many cass as Mr. Diaz. Which equation can be used to find the number of cars that Mr. Diaz sold,c?

Answers

The equation that we can be used to find the number of cars that Mr. Diaz sold is  [tex]\frac{3}{4}x[/tex][tex]8=28[/tex].

Ms Wong sold cars = 28.

She sold [tex]8[/tex] fewer cars that is 3/4 as many cars as Mr. Diaz.

Let Mr. Diaz sold [tex]x[/tex] cars.

Cars is 3/4 as many cars as Mr. Diaz so the term [tex]3/4x[/tex].

She sold 8 fewer cars.

Now from the statement the Ms Wong sold cars [tex]\frac{3}{4}x[/tex]−[tex]8[/tex].

As it is given that Ms Wong sold 28 cars.

So the equation must be

[tex]\frac{3}{4}x[/tex]−[tex]8=28[/tex]

So equation that we can be used to find the number of cars that Mr. Diaz sold is  [tex]\frac{3}{4}x[/tex][tex]8=28[/tex].

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What is the volume of the right triangular prism below? a 1600cm 800cm 400cm 160cm

Answers

The formula for determining the volume of a triangular prism is expressed as

Volume = area of triangular face * height of prism

The fotmula for finding the area of the triangular face is

Area = 1/2 * base * height

Looking at the diagram,

base = 8 cm

height = 10 cm

Area of triangular face = 1/2 * 8 * 10 = 40 cm^2

height of prism = 20 cm

Volume of prism = 40 * 20 = 800 cm^3

Option B is correct

Fill in the blanks. (6x)^2 = _x^_

Answers

Step-by-step explanation:

[tex](6x) {}^{2} = -x { }^{?} - [/tex]

When should the Empirical Rule be used?

Answers

Answer:

The empirical formula should be used after calculating the standard deviation and collecting the exact data needed for a forecast.

Explanations:What is the empirical rule?

The empirical rule is a term used in statistics also known as the 68–95–99.7 rule. This rule is majorly used in forecasting the final outcome of events.

The empirical rule can be used to therefore determine a rough estimate of the outcome of the impending data to be collected and analyzed. This is done after calculating the standard deviation and collecting the exact data needed.

68–95–99.7 rule,

the rate of change at which the water level rises is ___ centimeters per minutes. so, involving the equation ____ for y gives a y-value equal to___

Answers

We will have the following:

The rate at which the water rises is 13/4 cm per minute.

So, solvinng the equation:

[tex]\frac{13}{4}=\frac{y}{12}[/tex]

For y gives a value for y equal to:

[tex]y=\frac{13\cdot12}{4}\Rightarrow y=39[/tex]

(Combining Equation)What is the result of subtracting the second equation from the first ?-2x + y = 0 -7x + 3y = 2

Answers

We are given the following two equations

[tex]\begin{gathered} -2x+y=0\quad eq.1 \\ -7x+3y=2\quad eq.2 \end{gathered}[/tex]

Let us subtract the second equation from the first equation.

Therefore, the result of subtracting the second equation from the first is

[tex]5x-2y=-2[/tex]

Jenny originally bought her car for $42,000. Four years later, she sold it to a used car salesman for $14,000. What is the ratio for the amount she sold it for to the amount that it depreciated?

Answers

SOLUTION

The amout that Jenny sold the car for is $14,000

The amout that the car depriciated will be

$42,000 - $14,000 = $28,000

The ratio for the amount she sold it for to the amount that it depreciated becomes

[tex]\begin{gathered} \frac{14,000}{28,000} \\ \\ =\text{ }\frac{1}{2} \\ \\ =\text{ 1 : 2} \end{gathered}[/tex]

Draw a sketch of f(x) = (x-4)^2+5. Plot the point for the vertex, label the coordinates as a maximum or minimum, draw and write the equation for the axis of symmetry

Answers

Given the function:

[tex]f(x)=(x-4)^2+5[/tex]

the given function is a quadratic function

The graph of the function is as shown in the following picture

As shown the function has a minimum point at ( 4, 5 )

So, vertex = ( 4, 5 )

And Axis of symmetry: x = 4

I would like to learn the long multiplication so I can teach my fifth grader this math problem

352x20=

Answers

Answer: 7040

Step-by-step explanation:

1
352

x20

——-

000
7040

+
———

7040

The answer is 7040 first, I add

A park has several rows of trees. Each row has 5 trees. How many trees could be in the park?

Answers

Answer: so lets say x =the exact amount of rows

so each row has 5 tree's

then a is the answer

its an equation of x·5=a

so that would be a unknown number of trees so you assume that there is more than 1 row because there is several rows so its a incomplete question

Step-by-step explanation:

How many times in the parabola does a line intersect?

Answers

The line can intersect the parabola at one or two points.

See the example below.

The black line intersects the parabola at (1, -1)

The blue line intersects the parabola at two points: (0, 0) and (4, 8).

The population of Somewhere, USA was estimated to be 658,100 in 2003, with an expected increase of 5% per year. At the percent ofincrease given, what was the expected population in 2004? Round your answer to the nearest whole number.

Answers

To solve for the expected population in 2004:

[tex]\begin{gathered} \text{Estimated population for 2003=658100} \\ \text{rate = 5 \%} \\ nu\text{mber of year = 1} \end{gathered}[/tex]

Using compound interest formular to solve for the expected popupation:

Expected population = Amount

[tex]\begin{gathered} A=p(1+\frac{r}{100})^n \\ A\text{ = 658100 (1+}\frac{5}{100})^1 \\ A=658100\text{ (1+0.05)} \\ A=658100(1.05) \\ A=691005 \end{gathered}[/tex]

Hence the expected population in 2004 = 691,005

2. What is an algebraic expression for each phrase?a. the product of 9 and a number tb. the difference of a number x and 1/2c. the sum of a number m and 7.1 d. the quotient of 207 and a number n

Answers

The algebraic expression for each phrase would be the following:

a. the product of 9 and a number t would be expressed as:

9*t

b. the difference of a number x and 1/2 would be expressed as:

x - 1/2

c. the sum of a number m and 7.1 would be expressed as:

m + 7.1

d. the quotient of 207 and a number n​ would be expressed as:

207 / n

what property tells us that m

Answers

Reflexive Property

1) For this assertion m∠GHK ≅ m∠GHK we have the Reflexive Property, which states that the same segment or geometric entity has the same measure.

"A quantity is congruent to itself"

m∠GHK ≅ m∠GHK

a =a

The function f(x) = 6x represents the number of lightbulbs f(x) that are needed for x chandeliers. How many lightbulbs are needed for 7 chandeliers? Show your work

Answers

There are a total of 42 lightbulbs needed for 7 chandeliers

How to determine the number of lightbulbs needed?

From the question, the equation of the function is given as

f(x) = 6x

Where

x represents the number of chandeliersf(x) represents the number of lightbulbs


For 7 chandeliers, we have

x = 7

Substitute x = 7 in f(x) = 6x

So, we have

f(7) = 6 x 7

Evaluate the product

f(7) = 42

Hence, the number of lightbulbs needed for 7 chandeliers is 42

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The number of lightbulbs needed for 7 chandeliers would be; 42

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

From the given problem, the equation of the function is;

f(x) = 6x

Where

x be the number of chandeliers and f(x) represents the number of lightbulbs.

For 7 chandeliers, x = 7

Now Substitute x = 7 in f(x) = 6x

Therefore, f(7) = 6 x 7

Evaluate the product;

f(7) = 42

Hence, the number of lightbulbs needed for 7 chandeliers would be; 42

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Fill in the reason that justifies the step to solve for x in the diagram Given: QS = 42 X + 3 + 2x = 42 o R A. Substitution PropertyB. Segment Addition Postulate C. Simplify.

Answers

[tex]\begin{gathered} QS=42 \\ x+3+2x=42 \end{gathered}[/tex]

With the Segment Addition Postulate you have that:

[tex]QS=QR+RS[/tex]

As you have that 42 is equal to QS, and 42 is equal to X + 3 + 2, you use

help meeeeeeeeee pleaseee !!!!!

Answers

The composition of functions g(x) and f(x) evaluated in x = 5 is:

(g o f)(5) = 6

How to evaluate the composition?

Here we have two functions f(x) and g(x), and we want to find the composition evaluated in x = 5, this is:

(g o f)(5) = g( f(5) )

So first we need to evaluate f(x) in x = 5, and then g(x) in f(5).

f(5) = 5² - 6*5 + 2 = 25 - 30 + 2 = -3

Then we have:

(g o f)(5) = g( f(5) ) = g(-3)

Evaluating g(x) in x = -3 gives:

g(-3) = -2*(-3) = 6

Then the composition is:

(g o f)(5) = 6

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I really need help solving this problem from my trigonometry prepbook

Answers

The terminal ray of 145° lies in II Quadrant.

The terminal ray of -83° lies in IV Quadrant.

The terminal ray of -636 lies in I Quadrant.

The terminal ray of 442 lies in I Quadrant.

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