9514 1404 393
Answer:
23) 35.77 in²
25) 48.19 cm²
Step-by-step explanation:
Use the appropriate area formula with the given information.
__
23) The area of a triangle is given by the formula ...
A = 1/2bh . . . . . base b, height h
A = 1/2(9.8 in)(7.3 in) = 35.77 in²
__
25) The area of a parallelogram is given by the formula ...
A = bh . . . . . . base b, height h
A = (7.9 cm)(6.1 cm) = 48.19 cm²
_____
The height in each figure is measured perpendicular to the base. This tells you that the length 10.6 cm of the diagonal side of the triangle is not relevant to finding the area.
Answer:
23) 35.77 in2
24) 48.19cm2
if u(x)=-2x^2+3 and v(x)=1/x, what is the range of (uxv)(x)
Answer:
u(x)=−2x2+3.
Step-by-step explanation:
v(x )=1x whichever notation you prefer: (u∘v)(x)=u(v(x)).
Answer:
u(x)=−2x2+3.
Step-by-step explanation:
Rectangle F'G'H'I' is a translation of rectangle FGHI. Write the translation rule.
What does area mean? When you are asked to find the
area what are you doing?
Answer:
you want to muliply the length and width to find area.
Step-by-step explanation:
Which pair of inequalities is equivalent to 0
Choose the correct answer below.
Answer: D is correct
Step-by-step explanation:
Answer:
C. x > 0 and x ≤ 3
Step-by-step explanation:
0 < x ≤ 3
when 0 < x then x > 0
Example: 0 < 2 then 2> 0
Therefor
x > 0 and x ≤ 3
i’m so confused.. a little help?
Answer:
Triangle has a greater perimeter.
Step-by-step explanation:
Triangle perimeter = 21cm
Add the sides.
Square perimeter = 16cm
Add the sides (since it's a square the sides are the same.)
Helpppppppppppppppp meeeeeeeeeeee plssssssssssssssssss
Answer:
A: NO
B: YES
C: NO
D: NO
Step-by-step explanation:
Solve for the value of z
Answer:
z=26
Step-by-step explanation:
4z-8+3z+6=180
7z-2=180
7z=182
z=26
Answer:
z=26
Step-by-step explanation:
add the 2 equation together to equal 180
4z-8+3z+6
combine like terms
7z-2=180
add 2 to both sides
7z=182
divide by 7 to isolate z
z=26
PLEASE HELP!!!!!!!!!!!
Answer:
I think it's 18
Step-by-step explanation:
because I'm looking at 12/8 to be a ratio, that means that the size of the bigger figure had decreased by 12/8 or 1.5
then I divided the 27 by 1.5 to get the area of the small one which was 18.
Which is the best estimate for the weight of a bicycle?
A. 2 ounces
B. 2 pounds
C. 20 ounces
D. 20 pounds
Answer:
B
Step-by-step explanation:
i know this already from another
What is the area of this square?
A= 12
B= 48
C= 72
D= 144
No links, docs, files, drives etc
I will mark the correct answer brainlyest
You earn many points
========================================================
Explanation:
A square has all four sides that are the same length. So all four sides are 12 cm
area = side*side = 12*12 = 144 cm^2
Or you could say
area = (side)^2 = (12)^2 = 144 cm^2
Squaring a number is the same as multiplying it by itself. Hence the name "square" refers to a side length pairing up with its corresponding area value.
---------
Side note: The perimeter is 4*(side) = 4*12 = 48 cm. It's possible that choice B is put in there as a trick answer.
B
If you do 4x12 you will end up with 48
A book which was bought for Rs.100 was sold at Ra.90 what will be the loss percent?
Answer:
10% or 1%
Step-by-step explanation:
i swear u better not remove this
If 2^2x = 2^3, what is the value of x?
Answer:
x=2
Step-by-step explanation:
Given LP, LM = (3x + 1), MN = (4x –3), NP = (6x – 5), and LM =NP.
M
AN
What is the length of MP?
Answer:
[tex]MP = 12[/tex]
Step-by-step explanation:
Given
[tex]LM = (3x + 1), MN = (4x -3), NP = (6x - 5)[/tex]
[tex]LM = NP[/tex]
Required
Find MP
We have:
[tex]LM = NP[/tex]
This gives:
[tex]3x + 1 = 6x - 5[/tex]
Collect like terms
[tex]3x - 6x = -1-5[/tex]
[tex]-3x = -6[/tex]
Solve for x
[tex]x = 2[/tex]
MP is calculated as:
[tex]MP = MN + NP[/tex]
[tex]MP = 4x - 3 + 6x - 5[/tex]
Collect like terms
[tex]MP = 4x + 6x - 3 - 5[/tex]
[tex]MP = 10x - 8[/tex]
Substitute [tex]x=2[/tex]
[tex]MP = 10*2 - 8[/tex]
[tex]MP = 20 - 8[/tex]
[tex]MP = 12[/tex]
I WILL GIVE 90 POINTS!!!! PLEASE EEEEXXXXPPPLLLAAAIIIIIIIIIIIIINNNNNNN!!!!!!!!!!!!!!!!!
Moby rolls two dice. what is the probability that the sum of the numbers on the dice will be 8?
A. 1/36
B. 3/36
C. 5/36
D. 8/36
Answer:
C) 5/36
Step-by-step explanation:
Now, suppose, dice 1 gives 2. Here also, dice 2 can be anything between 1 and 6. But, the sum of both the dices will be 8 only if dice 2 shows 6.
Similarly, now, if dice 1’s face is 3, sum will be 8 only if dice 2’s upper face shows 5.
If dice 1 shows 4, sum = 8 only if dice 2 is 4.
If dice 1 is 5, sum = 8 only if dice 2 is 3.
If dice 1 is 6, sum= 8 only if dice 2 is 2.
Therefore, sum will be 8 only 5 times. But, sample space consists of 36 values ( combination of values of dice 1 and dice 2).
Therefore, probability = 5/36.
Hope it helps.
Answer:
Now, suppose, dice 1 gives 2. Here also, dice 2 can be anything between 1 and 6. But, the sum of both the dices will be 8 only if dice 2 shows 6.
Similarly, now, if dice 1’s face is 3, sum will be 8 only if dice 2’s upper face shows 5.
If dice 1 shows 4, sum = 8 only if dice 2 is 4.
If dice 1 is 5, sum = 8 only if dice 2 is 3.
If dice 1 is 6, sum= 8 only if dice 2 is 2.
Therefore, sum will be 8 only 5 times. But, sample space consists of 36 values ( combination of values of dice 1 and dice 2).
Therefore, probability = 5/36.
Hope it helps.
Step-by-step explanation:
The Unit Circle
What is the domain of a sine function?
a. positive numbers
b. All real numbers
c. negative numbers
d. positive numbers including zero
Please select the best answer from the choices provided
Answer:
B. All real numbers
Step-by-step explanation:
I calculated it logically
Answer:
I believe it is all real numbers
Use the information giving in the figure to find the length FH. If applicable, round your answer to the nearest whole number.
The lengths on the figure are not drawn accurately.
9514 1404 393
Answer:
FH = 16
Step-by-step explanation:
ΔGHE is a 5-12-13 triangle.
ΔEHF is a 3-4-5 triangle with a scale factor of 4, so side FH is 4·4 = 16 units.
_____
(3, 4, 5), (5, 12, 13), (7, 24, 25), (8, 15, 17) are all commonly used Pythagorean triples. The first two on the list are used in these triangles.
If you like, you can work out the numbers using the Pythagorean theorem, which tells you the square of the hypotenuse is equal to the sum of the squares of the other two sides.
For ΔEHG, that is ...
GE² = EH² + HG²
13² = EH² + 5²
EH² = 13² -5² = 169 -25 = 144
And for ΔEHF, ...
FE² = EH² +HF²
20² = 144 + HF²
400 -144 = HF² = 256
HF = √256 = 16
The length of side FH is 16 units.
PLEASE HELP I DONT KNOW
Answer:
28π is the circumference
Step-by-step explanation:
Melissa started a game at 5:06 PM and finished it at 6:32 PM.
How long did it take her? Give your answer in hours and minutes.
Answer:
1 hour 26 minutes
Step-by-step explanation:
PLEASE ANSWER THIS ASAP IM ALWAYS SO GRATEFULL!!
Answer:
P(6) is 1/12, P(Shaded) is 8/12, P(Odd or Unshaded) is 10/12, and P(Even and Shaded) is 11/12
Step-by-step explanation:
Can you help me with Math
Answer:
42+106=x
148=x
Step-by-step explanation:
A bag contains 4 red marbles, 6 blue marbles and 7 green marbles. If three marbles are drawn out of the bag, what is the probability, to the nearest 1000th, that all three marbles drawn will be blue?
Answer:
.070
Step-by-step explanation:
Answer:
0.94
Step-by-step explanation:
5/11 is .455
11 total marbles 5 are green
but thats the probability of just one draw
so .455 x .455 x .455 is .094 for three separate draws
Select two equations of lines that are perpendicular to the line whose equation is x + 5y = 50. I need help please.
Answer:
[tex]y = 5x + 1[/tex] and [tex]y = 5x + 2[/tex] are two equations of lines that are perpendicular to the line whose equation is x + 5y = 50.
Step-by-step explanation:
Equation of a line:
The equation of a line has the following format:
[tex]y = mx + b[/tex]
In which m is the slope and b is the y-intercept.
Perpendicular lines:
If two lines are perpendicular, the multiplication of their slopes is -1.
In this question:
The equation of the line is:
[tex]x + 5y = 50[/tex]
Placing in the standard format:
[tex]5y = -x + 50[/tex]
[tex]y = -\frac{x}{5} + 10[/tex]
The slope is [tex]-\frac{1}{5}[/tex]
Slope of the perpendicular lines:
[tex]-\frac{m}{5} = -1[/tex]
[tex]m = 5[/tex]
So
[tex]y = 5x + b[/tex]
Attributing two values to b:
[tex]y = 5x + 1[/tex] and [tex]y = 5x + 2[/tex] are two equations of lines that are perpendicular to the line whose equation is x + 5y = 50.
3х2+9х+6
Foil method of
Answer:
3(4+3x)
Step-by-step explanation:
See Image below.
An architect is creating a scale drawing of a school computer lab. The length of the lab is 32 feet and the width of the lab is 48 feet. If each 16 feet of the lab equals 2 centimeters on a scale drawing, which of the following drawings is the scale drawing of the computer lab?
Answer:
The answer is B
Step-by-step explanation:
Length:
32ft. / 16ft. = 2
2 x 2cm. = 4 cm.
Width:
48ft. / 16ft. = 3
3 x 2cm. = 6cm
Answer:
b
Step-by-step explanation:
24. Identify the center and radius of the circle given the equation (x +15)2 + (7 - 9)2 = 25 .
a. Center: (-15, 9), Radius: 5
b. Center: (15, -9), Radius: 25
c. Center: (-15, -9) Radius: 5
d. Center: (15,9) Radius: 25
Answer:
a. Center: (-15, 9), Radius: 5
Step-by-step explanation:
Equation of a circle:
The equation of a circle of center [tex](x_0, y_0)[/tex] and radius r is given by:
[tex](x - x_0)^2 + (y - y_0)^2 = r^2[/tex]
In this question, we have that:
[tex](x + 15)^2 + (y - 9)^2 = 25[/tex]
Comparing both equations:
[tex]x - x_0 = x + 15[/tex]
[tex]x_0 = -15[/tex]
And
[tex]y - y_0 = y - 9[/tex]
[tex]y_0 = 9[/tex]
The center is [tex](-15,9)[/tex].
For the radius:
[tex]r^2 = 25[/tex]
[tex]r = \sqrt{25} = 5[/tex]
The correct answer is given by option a.
juan and jose are in charge of buying candy for pinatas. Each pinata will hold 6 pounds of candy how many puonds of candy will they need to fill 12 pinatas
Answer:
75.36
Step-by-step explanation:
bc it sinple math if you think about it
LINK=REPORT
(4^2)^3=
A. 4^5
B. 4^6
C. 8^5
D. 16^5
(5^2)(5^3)=
A. 5^5
B. 5^6
C. 10^5
D. 25^5
(3^4)(3^5)=
A. 3^9
B. 9^9
C. 3^20
D. 6^20
Which is equivalent to 2^3•2^-5?
A. 2^-15
B. 2^-8
C. 2^-2
D. 2^2
If you answer all four of them and they are right I will give brainliest!
Answer:
a) 4^6
b) 5^5
c)3^9
d)2^-2
Step-by-step explanation:
When raising a number to a power and then to another power, you can multiply the exponents.
When multiplying numbers with the same base to different exponents, you can add the exponents.
Find the solution(s) to the system of equations. Select all that apply.
y=x-4
y = 2x- 5
Answer:
Y
Step-by-step explanation:
Find the missing dimension.
Answer:
1.66
Step-by-step explanation:
a = b*h
5.833 = 5*h
5.833/5 = h
1.166 = h
------------------------------------------
check work:
b*h = a
5 * 1.166 = 5.833
True
Answer:
1.66
Step-by-step explanation:
I did this already in my math class
I need help with the solutions for 19,20,21 thank you
Answer:
GIVEN :-
Coordinates of points are :-
(-5 , 12)(2 , 8)(3 , -6)TO FIND :-
All the trigonometric values of given pointsFACTS TO KNOW BEFORE SOLVING :-
It's important to know that :-
In 1st quadrant (0° to 90°) , all the trigonometric values are positive .In 2nd quadrant (90° to 180°) , except sin & cosec , rest all trigonometric values are negative.In 3rd quadrant (180° to 270°) , except tan & cot , rest all trigonometric values are negative.In 4th quadrant (270° to 360°) , except cos & sec , rest all all trigonometric values are negative.SOLUTION :-
Q1)
Plot (-5,12) on the cartesian plane and name it 'A'Drop a perpendicular to x-axis from 'A' and name the point 'B' where the perpendicular meets x-axis.Join the point A with the origin 'O'.You'll notice a right-angled ΔABO formed (∠B = 90°) in the 2nd quadrant of the plane whose :-
length of perpendicular of triangle (AB) = 12 unitslength of base of triangle (OB) = 5 unitslength of hypotenuse (OA) = 13 unitsLet the angle between OA & positive x-axis be θ.
⇒ ∠AOB = 180 - θ
So ,
[tex]\sin (AOB) = \sin(180 - \theta) = \sin \theta = \frac{12}{13}[/tex][tex]\cos(AOB) = \cos (180 - \theta) = -\cos \theta = -\frac{5}{13}[/tex][tex]\tan(AOB) = \tan(180 - \theta) = -tan \theta = -\frac{12}{5}[/tex][tex]\csc(AOB) = \csc(180 - \theta) = \csc \theta = \frac{1}{\sin \theta} = \frac{13}{12}[/tex][tex]\sec(AOB) = \sec(180 - \theta) = -\sec \theta = -\frac{1}{\cos \theta} = -\frac{13}{5}[/tex][tex]\cot(AOB) = \cot(180 - \theta) = -\cot \theta = -\frac{1}{\tan \theta} = -\frac{5}{12}[/tex]Q2)
Plot (2,8) on the cartesian plane and name it 'A'Drop a perpendicular to x-axis from 'A' and name the point 'B' where the perpendicular meets x-axis.Join the point A with the origin 'O'.You'll notice a right-angled ΔABO formed (∠B = 90°) in the 1st quadrant of the plane whose :-
length of perpendicular of triangle (AB) = 8 unitslength of base of triangle (OB) = 2 unitslength of hypotenuse (OA) = 2√17 unitsLet the angle between OA & positive x-axis be θ.
⇒ ∠AOB = θ
So ,
[tex]\sin(AOB) = \sin \theta = \frac{8}{2\sqrt{17} } = \frac{4}{\sqrt{17} }[/tex][tex]\cos(AOB) = \cos \theta = \frac{2}{2\sqrt{17}} = \frac{1}{\sqrt{17}}[/tex][tex]\tan(AOB) = \tan \theta = \frac{8}{2} = 4[/tex][tex]\csc(AOB) = \csc \theta = \frac{1}{\sin \theta} = \frac{\sqrt{17}}{4}[/tex][tex]\sec(AOB) = \sec \theta = \frac{1}{\cos \theta} = \sqrt{17}[/tex][tex]\cot (AOB) = \cot \theta = \frac{1}{\tan \theta} = \frac{1}{4}[/tex]Q3)
Plot (3,-6) on the cartesian plane and name it 'A'Drop a perpendicular to x-axis from 'A' and name the point 'B' where the perpendicular meets x-axis.Join the point A with the origin 'O'.You'll notice a right-angled ΔABO formed (∠B = 90°) in the 4th quadrant of the plane whose :-
length of perpendicular of triangle (AB) = 6 unitslength of base of triangle (OB) = 3 unitslength of hypotenuse (OA) = 3√5 unitsLet the angle between OA & positive x-axis be θ . [Assume it in counterclockwise direction].
⇒ ∠AOB = 360 - θ
So ,
[tex]\sin(AOB) = \sin(360 -\theta) = -\sin \theta = -\frac{6}{3\sqrt{5} } = -\frac{2}{\sqrt{5} }[/tex][tex]\cos(AOB) = \cos(360 - \theta) = \cos \theta = \frac{3}{3\sqrt{5} } = \frac{1}{\sqrt{5} }[/tex][tex]\tan(AOB) = \tan(360 - \theta) = -tan \theta = -\frac{6}{3} = -2[/tex][tex]\csc(AOB) = \csc(360 - \theta) = -\csc \theta = -\frac{1}{\sin \theta} = -\frac{\sqrt{5} }{2}[/tex][tex]\sec(AOB) =\sec (360 - \theta) = \sec \theta = \frac{1}{\cos \theta} = \sqrt{5}[/tex][tex]\cot(AOB) = \cot(360 - \theta) = -\cot \theta = -\frac{1}{\tan \theta} = -\frac{1}{2}[/tex]