A 0.40 kg bead slides on a straight frictionless wire with a velocity of 3.50 cm/s to the right. The
bead collides elastically with a larger 0.60 kg bead initially at rest. After the collision the smaller
bead moves to the left with a velocity of 0.70 cm/s. Find the distance the larger bead moves along
the wire in the first 5.0 s following the collision?||

Answers

Answer 1

Answer:

Total momentum before collision

P1 =.4 * 3.5 = 1.4       ignoring units here

Total momentum after collision

P2 = .6 * V - .4 * .7 = .6 V - .28

.6 V = 1.4 + .28   momentum before = momentum after

V = 2.8 cm/sec

In 5 sec V moves 2.8 cm/sec * 5 sec = 14 cm


Related Questions

A system consisting of two particles is known to have zero total momentum. Does it follow that the kinetic energy of the system is zero as well?

Answers

Answer:

all of the particles are at rest (v = 0)

Explanation:

Therefore, since nothing is moving, the total momentum of the system must also be zero.

As a system consisting of two particles is known to have zero total momentum, the kinetic energy of the system will be zero as well.

What is momentum?

Momentum is the product of a particle's mass and velocity. Momentum is a vector quantity, which means it has a magnitude as well as a direction.

According to Isaac Newton's second law of motion, the time rate of change of momentum equals the force acting on the particle.

Momentum describes the relationship between an object's mass, velocity, and direction.

Any change in momentum generates force. As a result, a change in momentum is used to calculate the force acting on the object.

Because the total kinetic energy is zero, all of the particles are at rest (v = 0). As a result, because nothing is moving, the system's total momentum must also be zero.

Thus, the statement is true.

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Jeff Gordon leads his race and must drive into a curve at top speed to win it all. The radius of the curve is 1000 m and the coefficient of static friction between his tires and the dry pavement is 0.50.

Answers

Answer:

Apparently the curve is not banked.

The maximum frictional force is -

Ff = m g * .5

Fc = m v^2 / R     where Fc is the centripetal force that must be present in

                            order for the car not to slip.

.5 g = v^2 / R      equating forces

v^2 = .5 R g = .5 ^ 1000 * 9.80

v = (500 * 9.80)^1/2 = 70 m/s

(about 230 ft/sec = 230/88 * 60 = 157 mph

A car traveling in a northeasterly direction at a rate of 50 km/h represents which of the following?
A.
deceleration
B.
velocity
C.
speed
D.
acceleration

Answers

Answer:

c.

Explanation:

Speed is the time rate at which an object is moving along a path, while velocity is the rate and direction of an object's movement. Put another way, speed is a scalar value, while velocity is a vector.

Formula

s = \frac{d}{t}

s = speed

d = distance traveled

t = time elapsed

an object moves 15.0 m north and then 11.0 m south. find both the distance it has traveled and the magnitude of its displacement.

Answers

Distance is 15 m + 11 m =26 m
Displacement is North 15 - 11 south= 4 m north.

The weight of a person in an elevator at rest = 500 N. Acceleration due to gravity is 9.8 m/s2. When lift accelerated, the tension force is 750 N. What is the acceleration of lift.

Answers

Answer:If the elevator accelerated downward then the tension force smallest then 500 N. Otherwise, if the elevator accelerated upward then the tension force larger then 500 N.

The tension force = 750 N because the elevator accelerated upward. Force acts upward has plus sign and force acts downward has minus sign.

T – w = m a

750 – 500 = 50 a

250 = 50 a

a = 250 / 50

a = 5.0 m s–2

Explanation:

10. What do you think the effect is of jet airplanes on global warming?

Answers

Answer:

Like other emissions resulting from fossil fuel combustion, aircraft engines produce gases, noise, and particulates, raising environmental concerns over their global effects and their effects on local air quality.[2]Jet airliners contribute to climate change by emitting carbon dioxide (CO2), the best understood greenhouse gas, and, with less scientific understanding, nitrogen oxides, contrails and particulates. Their radiative forcing is estimated at 1.3–1.4 that of CO2 alone, excluding induced cirrus cloud with a very low level of scientific understanding. In 2018, global commercial operations generated 2.4% of all CO2 emissions.

Between 1940 and 2018, aviation CO2 emissions grew from 0.7% to 2.65% of all CO2 emissions.[1]

Jet airliners have become 70% more fuel efficient between 1967 and 2007, and CO2 emissions per Revenue Ton-kilometer (RTK) in 2018 were 47% of those in 1990. In 2018, CO2 emissions averaged 88 grams of CO2 per revenue passenger per km. While the aviation industry is more fuel efficient, overall emissions have risen as the volume of air travel has increased. By 2020, aviation emissions were 70% higher than in 2005 and they could grow by 300% by 2050.

Aircraft noise pollution disrupts sleep, children's education and could increase cardiovascular risk. Airports can generate water pollution due to their extensive handling of jet fuel and deicing chemicals if not contained, contaminating nearby water bodies. Aviation activities emit ozone and ultrafine particles, both of which are health hazards. Piston engines used in general aviation burn Avgas, releasing toxic lead.

Aviation's environmental footprint can be reduced by better fuel economy in aircraft or Air Traffic Control and flight routes can be optimised to lower non-CO2 effects on climate from NO

x, particulates or contrails. Aviation biofuel, emissions trading and carbon offsetting, part of the ICAO's CORSIA, can lower CO2 emissions. Aviation usage can be lowered by short-haul flight bans, train connections, personal choices and aviation taxation and subsidies. Fuel-powered aircraft may be replaced by hybrid electric aircraft and electric aircraft or by hydrogen-powered aircraft.

Over a period of 2.50 seconds, a speedboat accelerates uniformly from 18.5 m/s to 46.5 m/s. What is the acceleration of the speedboat relative to the shore?

Answers

The answer is : 11.2 m/s2

According to the question, the acceleration of the speedboat relative to the shore is found to be 11.2 [tex]m/sec^2.[/tex]

What is Acceleration?

Acceleration may be characterized as the rate of change of the velocity of an object with respect to time. It is a vector quantity, as it defined both magnitude and direction. This allows you to measure how fast velocity changes in meters per second squared (m/s^2).

According to the question,

The initial velocity of the boat = 18.5 m/s.

The final velocity of the boat = 46.5 m/s.

Difference in velocity = Final velocity - Initial velocity = 46.5-18.5 = 28 m/s.

The formula for calculating the acceleration of the boat is as follows:

a = Difference in velocity/time taken.

           = 28/2.50 = 11.2 [tex]m/sec^2[/tex].

Therefore,  the acceleration of the speedboat relative to the shore is found to be 11.2 [tex]m/sec^2.[/tex]

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What is an object's mass if it accelerates at 5 m/s2 when a force of 0.5 N is applied?

Answers

Answer:

0.1kg

Explanation:

mass = force / acceleration

0.5 / 5

0.1kg

what are the variables that affect the force of gravity?

Answers

Answer:

Mass and distance.

Explanation:

The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them.

On average, how many stars would we have to search before we would expect to hear a signal? assume there are 500 billion stars in the galaxy.

Answers

We would have to search at least 5,000,000,000 (5 billion) stars before we would expect to hear a signal.

To find out the number of stars that we will need to search to find a signal, we need to use the following formula:

total of stars/civilizations500,000,000,000 (500 billion) stars / 100 civilization = 5,000,000,000 (5 billion)

This shows it is expected to find a civilization every 5 billion stars, and therefore it is necessary to search at least 5 billion stars before hearing a signal from any civilization.

Note: This question is incomplete; here is the complete question.

On average, how many stars would we have to search before we would expect to hear a signal? Assume there are 500 billion stars in the galaxy.

Assuming 100 civilizations existed.

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1. Apply a constant force of 50 N directed to the right of the 50 kg Box. (2 pts)
Hypothesis:?
Conclusion: ?

Answers

As the box is moving with a constant velocity, the two forces acting on the box are canceling each other.

Then   friction force = 80 Newtons              but in the opposite direction.

Friction force =  Mu  * Normal force exerted by ground  =  Mu * weight of box

So we find Mu.

Mu = coefficient of friction between box and horizontal surface

          = Force of friction / weight  =  80 / 50 * 9.81 = 0.163

When an identical box is placed on top, the force of friction is

      = Mu * total weight = 0.163 * (50+50) * 9.81 = 159.9 Newtons

why is it less air pressure up in the sky and why does it affect our ears

Answers

Answer:

When you in a airplane you are in high altitude and thats where air density drops. Thats where ear pops come from.

Explanation:

which term is defined by the interaction between two charged particles?

Answers

Answer: Electromagnetism

The term which is defined by the interaction between two charged particles is known as electromagnetism.

What is an electromagnet?

The study of charge and the fields and forces it generates is known as electromagnetism. Electromagnetism has two components: electricity and magnetism.

The special theory of relativity, developed by Albert Einstein in 1905, proved beyond a shadow of a doubt that both are components of the same reality. But in reality, magnetic and electric forces behave very differently and are modeled by various equations. Electric charges can produce forces whether they are stationary or moving. On the other hand, magnetic forces are only created by moving charges and only affect charges that are moving.

Thus, the term is known as electromagnetism.

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What is the frequency of a wave with a wavelength of 15 m and a wavespeed of
300 m/s?

Answers

Answer: f=20 (i think)

Explanation:

all I did was divide 300 and 15.

300/15= 20

What is the mass of a box if it accelerated 5 m/s from a force of 12 N?

Answers

Answer:

60

Explanation:

You multiply the acceleration and the force and you get your answer

This is not meant to be a long, mathematically-intensive problem. If you find yourself going down that road, you might want to rethink your approach.

Answers

Answer:

rethink your approach to what?

Explanation:

name an instrument that is used to measure atmospheric pressure

Answers

Answer:

Barometer also called barometric pressure.

Answer:

A barometer

Explanation:

There are two types of barometers;

Mercury barometerAneroid barometer

[tex]{}[/tex]

How far does an object travel if it is moving at a speed of 4 m/s for 3.2 seconds?

Answers

Answer:

12.8 meters

Explanation:

m/s means meters per second. So, to find how far it would travel in 3.2 seconds, you would multiply 4 meters every second by 3.2 seconds.

4×3.2=12.8 meters

what is the static friction force and kinetic friction for the image

Answers

According to the plot, static friction force has a maximum magnitude of around 3.0 N, and kinetic friction has a magnitude of about 1.5 N.

The plot appears to be telling you the force required to get the yellow block moving along the table. If one applies less than 3.0 N of force, the block remains motionless. But as soon as it starts to slide, one need only apply 1.5 N of force to keep it moving (presumably at a constant speed).

A seashell is suspended in the air at rest by two strands of spider silk. Each strand of silk makes an angle of 75 degrees above the horizontal, and experiences a tension of 1.42 N.

What is the mass of the seashell?

Answers

The mass of the seashell suspended by the two strands of spider silk is 0.28 kg.

The given parameters:

Tension on each strand of silk, T = 1.42 NAngle of inclination of each strand, θ = 75⁰

The mass of the seashell at equilibrium is calculated by applying Newton's second law of motion;

[tex]\Sigma F = 0\\\\T_1 sin(\theta) + T_2 sin(\theta) - W = 0[/tex]

where;

W is the weight of the seashell

The weight of the seashell is calculated as;

[tex]1.42 \times sin(75) \ + \ 1.42 \times sin(75) \ - W = 0\\\\2.743 - W = 0\\\\W = 2.743 \ N[/tex]

The mass of the seashell is calculated as follows;

[tex]W = mg\\\\m = \frac{W}{g} \\\\m = \frac{2.743}{9.8} \\\\m = 0.28 \ kg[/tex]

Thus, the mass of the seashell suspended by the two strands of spider silk is 0.28 kg.

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what is the definition for volume and density ​

Answers

Answer:

volume :: is the level at which something is heard or the amount of space that something takes up.

Density :: is a measure of mass per volume. The average density of an object equals its total mass divided by its total volume.

Answer:

The density, of a substance is its mass per unit volume. The symbol most often used for density is ρ, although the Latin letter D can also be used. Mathematically, density is defined as mass divided by volume: {\displaystyle \rho ={\frac {m}{V}}} where ρ is the density, m is the mass, and V is the volume

How did Thomson's model get its name?

Answers

Answer:

thats actually a really good question. sadly i don't know the answer to it. but im sure that there are others who can!

1. What do machines do? Change the amount of force one exerts. Decrease the amount of work that is done. Increase the amount of work that is done. Eliminate friction.​

Answers

Answer: increase the amount of work that is done?

Explanation:

I’m not entirely sure to be honest but I’ll just use my logic here. Machines are made to increase efficiency and production. Machines are made to save time and energy as a pose to human work. So several machines can mass produce a lot of things and keep business booming. I’m not very good at explaining things but I hope this makes sense eventually.

the motion of a particle along a straight line is represented by the position versus time graph above. at which of the labeled points on the graph is the magnitude of the acceleration of the particle greatest?

Answers

Point A has the largest magnitude of acceleration as compared to other points on the position verses time graph.

On the graph, A is the point where magnitude of the acceleration of the particle is greatest as compared to other positions on the graph because the height of point A is the largest as compared to other points of the graph.

The graph shows at which point acceleration of an object is higher and lower so we can conclude that point A has the largest magnitude of acceleration as compared to other points on the position verses time graph.

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What is the current in a 120V circuit if the resistance is 20Ω?

Answers

We have: [tex]I=\frac{U}{R}=\frac{120}{20}=6A[/tex]

ok done. Thank to me :>

Answer:

The Current is 6 Ampere.

Step-by-step explanation:

Given :

[tex]\small\red\bull[/tex] Voltage = 120V[tex]\small\red\bull[/tex] Resistance = 20Ω

To Find :

[tex]\small\red\bull[/tex] Current

Using Formula :

[tex] \star{\small{\underline{\boxed{\sf{ I = \dfrac{V}{R}}}}}}[/tex]

[tex]\small\blue\star[/tex] I = Current[tex]\small\blue\star[/tex] V = Voltage[tex]\small\blue\star[/tex] R = Resistance

Solution :

Substituting all the given values in the formula to find Current :

[tex]{\dashrightarrow{\pmb{\sf{ I = \dfrac{V}{R}}}}}[/tex]

[tex]{\dashrightarrow{\sf{ Current = \dfrac{Voltage}{Resistance}}}}[/tex]

[tex]{\dashrightarrow{\sf{ Current = \dfrac{120}{20}}}}[/tex]

[tex]{\dashrightarrow{\sf{ Current = \cancel{\dfrac{120}{20}}}}}[/tex]

[tex]{\dashrightarrow{\sf{ Current = 6A}}}[/tex]

[tex]{\star{\underline{\boxed{\sf{\red{ Current = 6A}}}}}}[/tex]

Hence, the Current is 6 Ampere.

[tex]\rule{300}{1.5}[/tex]

AB
ca
The trough of a transverse wave is BEST shown by choice
es - )
8
8

Answers

Answer:

bro the way you worded it makes no since

How many volts would it take to push 1 amp through a resistance of 1 ohm?

Answers

V=I x R so V= 1 x 1 =1V

Answer:

[tex]1\; \rm V[/tex].

Explanation:

Ohm's Law give the following relationship between the potential [tex]V[/tex] across a conductor, the electrical resistance [tex]R[/tex] of that conductor, and the current [tex]I[/tex] through that conductor:

[tex]V = I \, R[/tex].

It is given that the current through this conductor is [tex]I = 1\; {\rm A}[/tex], and that the electrical resistance of this conductor is [tex]R = 1\; \rm \Omega[/tex].

Note, that the unit of electrical resistance Ohm is a composite unit; [tex]1\; {\rm \Omega} = 1\; {\rm V \cdot A^{-1}}[/tex] (volts per ampere.)

Substitute the value of [tex]I[/tex] and [tex]R[/tex] into the equation [tex]V = I \, R[/tex] from Ohm's Law to find the potential across this conductor:

[tex]\begin{aligned}V &= I \, R \\ &= 1\; {\rm A} \times 1\; {\rm \Omega} \\ &= 1\; {\rm A} \times 1\; {\rm V \cdot A^{-1}} \\ &= 1\; {\rm V}\end{aligned}[/tex].

7. A drag car takes off at the green light heading in a straight line. The car goes
from a complete stop to 45m/s in 9 seconds. What is its acceleration?

Answers

Answer:

405

Explanation:

If the car stops at 45m/s in 9 seconds then it took the car 405 meters to stop

Help please physics work

Answers

At any point along the track, the rollercoaster's mechanical energy is equal to the sum of its potential and kinetic energies,

M = P + K

and we assume the coaster's total mechanical energy is conserved throughout its motion along the track, so that M is the same at every point.

At the first point,

K + 75,000 J = 90,000 J   ⇒   K = 15,000 J

At the second point, since M = 90,000 J everywhere,

K + 45,000 J = M   ⇒   K = 45,000 J

At the third point,

K + 0 J = M   ⇒   K = 90,000 J

The same principles apply to the pendulum, so M = 5,100 J throughout its swing.

At the first point,

K + 4,500 J = 5,100 J   ⇒   K = 600 J

At the second point,

K + 0 J = M   ⇒   K = 5,100 J

At the third point,

600 J + P = M   ⇒   P = 4,500 J

Please help my physics teacher cannot teach pls hurry pls help uwu

Answers

Hi there!

To find how much the spring stretches with the mass attached, we must find the spring's equilibrium point.

The equilibrium point satisfies the following:

[tex]\large\boxed{\Sigma F = 0}[/tex]

The two forces acting in this situation are the weight of the mass and the spring force.

The spring force (restoring force) is in the opposite direction of the weight, so:

[tex]\Sigma F = 0 = Mg- k\Delta x[/tex]

Mg = weight

k = Spring Constant (N/m)

Δx = distance to equilibrium point (m)

Now, we can set the two equal to each other:

[tex]Mg = k\Delta x\\\\544 = 1146\Delta x\\\\\boxed{\Delta x= .475 m}[/tex]

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