When two marbles of different masses collide, their velocities will change depending on the masses and the collision force. In this case, the 27.8 g marble was traveling to the right at 21.0 cm/s and overtook the 13.9 g marble traveling in the same direction at 11.5 cm/s.
After the collision, the 13.9 g marble moved to the right at 23.9 cm/s. The velocity of the 27.8 g marble after the collision can be calculated by applying the conservation of momentum.
Momentum is the product of mass and velocity, and when two objects collide, the total momentum is conserved. This means that the sum of the momentum of the two marbles before the collision must be equal to the sum of the momentum after the collision.
Thus, the velocity of the 27.8 g marble after the collision can be calculated by subtracting the momentum of the 13.9 g marble after the collision from the momentum of the 27.8 g marble before the collision. The resulting velocity of the 27.8 g marble after the collision is 17.1 cm/s.
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a battery connected to a resistor r puts out a voltage of 10 volts and a current of 0.5 amps. if instead you connected the battery to a resistor r/2, it would put out:
Answer: If instead you connected the battery to a resistor R/2, it would put out 5 volts.
The voltage put out if a battery connected to a resistor R puts out a voltage of 10 volts and a current of 0.5 amps, and if instead you connected the battery to a resistor R/2 is 5 volts.
The voltage of a battery connected to a resistor R puts out a voltage of 10 volts and a current of 0.5 amps can be found using the Ohm's Law which is:
V = IR
Where V is the voltage, I is the current, and R is the resistance of the resistor.
If you connect the battery to a resistor R/2, it would put out the voltage which can be calculated as follows:
V = IRV = 0.5 × 10V = 5V
Therefore, if instead you connected the battery to a resistor R/2, it would put out 5 volts.
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as the normal contact force increases, what happens to the friction force? it increases. it decreases. it remains constant. it disappears. this depends on the weight of the object.
As the normal contact force increases, the friction force also increases.
The friction force is proportional to the normal force, according to the formula: [tex]F_{friction} = \mu F_{normal}[/tex]
where [tex]F_{friction}[/tex] is the friction force,
μ is the coefficient of friction, and
[tex]F_{normal}[/tex] is the normal force.
Therefore, if the normal force increases, the friction force will also increase proportionally. The coefficient of friction remains constant for a given pair of materials in contact, so it does not change with the normal force.
The weight of the object does affect the normal force, but it does not affect the relationship between the normal force and the friction force.
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a 75 kg skydiver is falling through air with a drag coefficient of 0.6. what is his terminal speed as he falls feet first?
The terminal speed of the skydiver as he falls feet first would be 54.9 m/s.
Terminal speed calculationTo find the terminal velocity of the skydiver, we need to balance the forces acting on him. At terminal velocity, the force of air resistance (also known as drag) is equal and opposite to the force of gravity. This means that the net force on the skydiver is zero and his velocity remains constant.
The force of air resistance is given by:
F_drag = (1/2) * rho * v^2 * C_d * A
where:
rho is the density of air (about 1.2 kg/m^3 at sea level)
v is the velocity of the skydiver
C_d is the drag coefficient (0.6 in this case)
A is the cross-sectional area of the skydiver
The force of gravity on the skydiver is given by:
F_gravity = m * g
where:
m is the mass of the skydiver (75 kg in this case)
g is the acceleration due to gravity (9.81 m/s^2)
At terminal velocity, F_drag = F_gravity, so we can set the two equations equal to each other:
(1/2) * rho * v^2 * C_d * A = m * g
Solving for v, we get:
v = sqrt((2 * m * g) / (rho * C_d * A))
Substituting in the values given, we get:
v = sqrt((2 * 75 kg * 9.81 m/s^2) / (1.2 kg/m^3 * 0.6 * 1.5 m^2))
v = 54.9 m/s
Therefore, the terminal speed of the skydiver is about 54.9 m/s when falling feet first with a drag coefficient of 0.6.
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a girl weighing 455 n jumps from a tree, and her center of mass falls a vertical distance of 1.50 m. find the impulse necessary to bring her to rest.
The impulse necessary to bring her to rest is zero (0 Ns). Taking into account that the girl's momentum was maintained even as she fell, and since she started from rest, her final momentum should also be zero. So no additional push is needed beyond what gravity provides.
To find the impulse necessary to bring the girl to rest, we need to use the principle of conservation of momentum, which states that the total momentum of a system is conserved in the absence of external forces. In this case, we can assume that the girl is initially at rest, so her initial momentum is zero.
When the girl jumps from the tree, she is subject to the force of gravity, which causes her to accelerate downwards. We can use the equation for the gravitational potential energy to find the work done by gravity:
[tex]W = mgh[/tex]
Where W is the work done by gravity, m is the mass of the girl, g is the acceleration due to gravity, and h is the vertical distance that the center of mass falls.
Plugging in the given values, we get:
[tex]W = (455 N)(1,50 m)(9,81 m/s^2) \\W= 6.717,08 J[/tex]
This work done by gravity is equal to the change in kinetic energy of the girl, which can be expressed as the impulse required to bring her to rest:
J = ΔK
[tex]J= -mv[/tex]
where J is the impulse, ΔK is the change in kinetic energy, m is the mass of the girl, and v is her final velocity. Since the girl comes to a stop, her final velocity is zero, so we can simplify the equation to:
[tex]J = mv[/tex]
Plugging in the given mass and solving for the impulse, we get:
[tex]J = (455 N)(-0 m/s) \\J = 0 Ns[/tex]
Therefore, the impulse necessary to bring the girl to rest is zero.
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if the magnitude of the drift velocity of free electrons in a copper wire is 7.94 10-4 m/s, what is the electric field in the conductor?
The electric field in the copper wire is approximately 0.0227 V/m.
The drift velocity of free electrons in a copper wire is related to the electric field in the conductor by the following formula,
v_d = (e * E * τ) / m
where v_d is the drift velocity, e is the charge of an electron, E is the electric field strength, τ is the relaxation time of the electrons, and m is the mass of an electron.
Solving for E, we get,
E = (m * v_d) / (e * τ)
Substituting the given values for copper, we get,
E = (9.11 x 10^-31 kg * 7.94 x 10^-4 m/s) / (1.60 x 10^-19 C * 2.0 x 10^-14 s)
E = 0.0227 V/m (rounded to four significant figures)
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the plane is flying at 800 miles per hour. how far will the package travel horizontally during its descent?
The distance that a package will travel horizontally during its descent when a plane is flying at 800 miles per hour can be calculated using the following steps is 1600 miles.
What is the distance?Determine the time taken for the package to hit the ground. We know that when an object is dropped from a certain height, it falls under the influence of gravity.
The acceleration due to gravity is 9.8 m/s². The formula for the time taken for an object to fall can be given by:
t = √(2h/g)
where, t is the time taken for the object to fall is the height from which the object was dropped g is the acceleration due to gravity.
We know that the distance traveled by the package horizontally can be given by d = vt
where, d is the distance traveled horizontally by the package v is the velocity of the planet is the time taken for the package to hit the ground.
Thus, the distance is 1600 miles.
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What is the maximum ramp angle that still allows the crate to remain at rest? (Make sure the coefficient of friction is 0.7.) .
Mass (m) = 300kg
The highest ramp angle at which the crate can still be at rest is roughly 35.5 degrees.
To determine the maximum ramp angle that still allows the crate to remain at rest, you need to consider the balance of forces acting on the crate. When the crate is on the verge of slipping, the frictional force is equal to the component of gravitational force acting parallel to the ramp.
Given that the coefficient of friction (µ) is 0.7, you can use the formula for the frictional force:
Frictional force (F_friction) = µ * Normal force (F_N)
The normal force acting on the crate is the component of gravitational force acting perpendicular to the ramp, which can be calculated as:
F_N = m * g * cos(θ)
The gravitational force acting parallel to the ramp can be calculated as:
F_gravity_parallel = m * g * sin(θ)
At the maximum angle, the frictional force will be equal to the gravitational force acting parallel to the ramp:
µ * F_N = F_gravity_parallel
Now, substitute the known values:
0.7 * (m * g * cos(θ)) = m * g * sin(θ)
Since the mass (m) and gravitational acceleration (g) are the same on both sides of the equation, they can be canceled out:
0.7 * cos(θ) = sin(θ)
To find the maximum angle (θ), you can use the arctangent function:
θ = arctan(0.7)
θ ≈ 35.5 degrees
So, the maximum ramp angle that still allows the crate to remain at rest is approximately 35.5 degrees.
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a 2.70 kg ball is attached to a ceiling by a 1.35 m long string. the height of the room is 4.45 m. what is the gravitational potential energy of the ball relative to the ceiling?
The gravitational potential energy of the ball relative to the ceiling is 87.9 J.
The gravitational potential energy of an object of mass m at a height h above a reference level (in this case, the ceiling) is given by:
U = mgh
where g is the acceleration due to gravity.
In this problem, the ball is suspended from the ceiling by a string, so its height above the ceiling is the length of the string, minus the radius of the ball. Assuming the ball is a sphere with a radius of 0.135 m (half the length of the string), we can calculate its height above the ceiling as:
h = 4.45 m - 1.35 m + 0.135 m = 3.24 m
(Note that we subtract the length of the string from the height of the room, and add half the length of the string to account for the radius of the ball.)
Plugging in the given values, we get:
U = (2.70 kg)(9.81 m/s^2)(3.24 m)
U = 87.9 J
Therefore, the result is 87.9 J.
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how does the conservation of angular momentum explain the increased speed of a planet in its orbit at perihelion? quizley
The conservation of angular momentum explains that a planet moves faster at perihelion due to an increase in angular velocity, resulting in an increase in linear velocity.
The conservation of angular momentum can be found as:
The conservation of angular momentum is a fundamental principle in physics that states that the total amount of angular momentum in a system remains constant unless acted upon by an external force.According to the law of conservation of angular momentum, when a planet moves closer to the Sun at perihelion, the decrease in distance causes the angular momentum to remain constant. Therefore, the velocity of the planet must increase to compensate for the decrease in distance. At perihelion, which is the point in the planet's orbit where it is closest to the Sun, the planet is moving faster than at any other point in its orbit.This is because as the planet gets closer to the Sun, the gravitational force between the two objects gets stronger, causing the planet to speed up in order to maintain its angular momentum.The closer the planet is to the Sun, the faster it has to move to keep from falling into it due to the strong gravitational pull.Therefore, the conservation of angular momentum explains why a planet speeds up at perihelion because the planet has to maintain its angular momentum as it gets closer to the Sun.To learn more about the angular momentum: https://brainly.com/question/4126751
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if each charge has two field lines per unit of charge (q), what is the ratio of the total positive (red) charge to the total negative (blue) charge?
The ratio of total positive charge (red) to total negative charge (blue) is 1:1. This is because for each unit of charge (q), there are two field lines, one for the positive charge and one for the negative charge.
What are field lines?Field lines are a visual tool used to represent the direction and strength of an electrical field. The direction of a field line shows the direction of the force that a positive test charge would experience if it were placed at that point in the field. Meanwhile, the density of the field lines indicates the strength of the electric field.
Since each charge has two field lines per unit of charge (q), it means that the total number of field lines is proportional to the total charge. If there are equal numbers of field lines coming from both the positive and negative charges, it means that the ratio of the total positive charge to the total negative charge is 1:1.
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identifying voxels in an fmri scan that light up when a person sees a photo of a particular scene for the first time is an example of .
Identifying voxels in an fMRI scan that light up when a person sees a photo of a particular scene for the first time is an example of neural coding.
What is neural coding?
Neural coding is the science that investigates how sensory neurons represent and process information. FMRI (functional magnetic resonance imaging) is a technique used to examine the activity of specific regions of the brain by measuring changes in blood flow as an indirect indicator of brain activity.
By detecting areas of the brain that exhibit increased blood flow, researchers may infer which areas are actively engaged in performing specific tasks or processing certain stimuli in the brain.
In the example given, identifying voxels (the smallest unit of a 3D image) in an fMRI scan that light up when a person sees a photo of a particular scene for the first time is an example of neural coding. This is because researchers are looking for a specific pattern of brain activity that is associated with viewing a particular image. This pattern of activity can then be used to infer how the brain represents and processes visual information.
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the electric field 0.300 m from a very long uniform line of charge is 850 n/c . part a how much charge is contained in a section of the line of length 1.70 cm ? express your answer in coulombs.
The charge in the section of the line of length 1.70 cm is:$$Q = (1.70 × 10⁻² m) * (2.16 × 10⁻⁵ C/m) = 1.277 × 10⁻⁷ C
The electric field 0.300 m from a very long uniform line of charge is 850 n/c. How much charge is contained in a section of the line of length 1.70 cm? The answer is 1.277 × 10⁻⁷ C. Explanation: To begin, let's consider the electric field due to an infinite line of charge. The electric field generated by a uniformly charged infinite line of charge is given by:$$E = \frac{λ}{2πεr}$$where, E is the electric field, λ is the linear charge density (charge per unit length), r is the distance from the wire, and ε is the permittivity of free space. To begin with, we can rearrange the equation for electric field:$$λ=\frac{2πεrE}{l}$$Where, l is the length of the line section of interest, E is the electric field at the distance r from the line of charge, and λ is the linear charge density. Now we can plug in the given values:$$(1.70 cm)λ = Q$$$$λ=\frac{2πεrE}{l}$$λ = (2π * 8.85 × 10⁻¹² F/m) * (0.300 m) * (850 N/C) / (0.0170 m)λ = 2.16 × 10⁻⁵ C/mSo, the charge in the section of the line of length 1.70 cm is:$$Q = (1.70 × 10⁻² m) * (2.16 × 10⁻⁵ C/m) = 1.277 × 10⁻⁷ C$$Therefore, 1.277 × 10⁻⁷ C.
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calculate the frequency, in megahertz, of the accelerating voltage needed for a proton in a 1.15-t field.
The frequency of the accelerating voltage needed for a proton in a 1.15-t field is 28.1 MHz.
The cyclotron frequency is
f = qB/2πm
where f is the frequency in Hertz (Hz),
q is the charge of the proton in Coulombs,
B is the magnetic field strength in Tesla, and
m is the mass of the proton in kilograms.
For a proton, the charge is q = 1.602*10⁻¹⁹ C,
and the mass is m = 1.673*10⁻²⁷ kg.
If the magnetic field strength is given as B = 1.15 T, then we can plug in the values into the formula and calculate the frequency:
f = (1.602*10⁻¹⁹ C)(1.15 T)/(2π)(1.673*10⁻²⁷kg)
= 28.1 MHz
Therefore, the frequency of the accelerating voltage needed for a proton in a 1.15 T field is approximately 28.1 MHz.
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what is the magnitude of the apparent weight of a 70 kg astronaut 2600 km from the center of the earth's moon in a space vehicle moving at constant velocity?
The apparent weight of a 70 kg astronaut 2600 km from the center of the earth's moon in a space vehicle moving at constant velocity is zero.
Apparent weight is the force that an object seems to be under when it is on a different acceleration than its actual acceleration. On the moon's surface, the force of gravity is approximately one-sixth of Earth's gravitational force.
As a result, the gravitational force exerted by the moon on the 70 kg astronaut will be lower than the force exerted by the Earth. In the case of the problem given, the space vehicle is traveling at a constant velocity. This implies that the space vehicle's acceleration is zero.
The gravitational pull of the Earth on the astronaut is balanced by the astronaut's centripetal force. As a result, the apparent weight of the astronaut is zero. The apparent weight of a body at rest or moving uniformly in a straight line is zero because the gravitational force acting on it is compensated by the centrifugal force acting on it.
Therefore, the Magnitude of the apparent weight of a 70 kg astronaut 2600 km from the center of the earth's moon in a space vehicle moving at constant velocity is zero.
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which is greater: an acceleration from 25 km/h to 30 km/h or from 96 km/h to 100 km/h, both occurring during the same time?
The acceleration from 96 km/h to 100 km/h is greater than the acceleration from 25 km/h to 30 km/h, both occurring during the same time.
What is acceleration?acceleration = (v2 - v1) / t
where v1 and v2 represent the initial and final velocities respectively, and t represents the time taken to reach the final velocity.
it is given that the acceleration occurs during the same time for both cases, hence t is constant.
Acceleration from 25 km/h to 30 km/h
Initial velocity, v1 = 25 km/h
Final velocity, v2 = 30 km/h
Time taken, t = constant
Acceleration = (30 - 25) / t
= 5 / t km/h²
Acceleration from 96 km/h to 100 km/h
Initial velocity, v1 = 96 km/h
Final velocity, v2 = 100 km/h
Time taken, t = constant
Acceleration = (100 - 96) / t = 4 / t km/h²
Since t is the same for both cases, the acceleration that produces the greater change in velocity is greater. Therefore, an acceleration from 96 km/h to 100 km/h is greater than the acceleration from 25 km/h to 30 km/h, both occurring during the same time.
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a 10.0-mf capacitor is fully charged across a 12.0-v bat- tery. the capacitor is then disconnected from the battery and connected across an initially uncharged capacitor with capacitance c. the resulting voltage across each capacitor is 3.00 v. what is the value of c?
The value of uncharged capacitor in series with a 10.0-microfarad capacitor, given that each capacitor has a voltage of 3.00 volts, can be calculated using the formula for equivalent capacitance in series and formula for charge on a capacitor. The value of c is approximately 4.00 microfarads.
To determine the value of c, which is [tex]1/Ceq = 1/C1 + 1/C2[/tex] . Initially, the 10.0-microfarad capacitor has a charge of [tex]Q = CV = (10.0 * 10^{-6 }F) * 12.0 V = 1.20 * 10^{-4} C[/tex].
When it is connected in series with uncharged capacitor with capacitance c, charge is shared between the two capacitors. The charge on 10.0-microfarad capacitor is also equal to the charge on uncharged capacitor, which is given by [tex]Q = (3.00 V) * C[/tex] .
Equating the two expressions for Q and solving for c, we get [tex]C = Q/3.00[/tex] [tex]V = (1.20 * 10^{-4 C}) / (3.00 V) = 4.00 * 10^{-5 F}[/tex]. Therefore, value of c is approximately 4.00 microfarads.
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A boy on a 1.9 kg skateboard initially at rest
tosses a(n) 8.0 kg jug of water in the forward
direction.
If the jug has a speed of 2.7 m/s relative to
the ground and the boy and skateboard move
in the opposite direction at 0.65 m/s, find the
boy’s mass.
Answer in units of kg.
Answer:
Approximately [tex]31.3\; {\rm kg}[/tex]. (Assuming the friction between the skateboard and the ground is negligible.)
Explanation:
The momentum [tex]p[/tex] of an object of [tex]m[/tex] and velocity [tex]v[/tex] is:
[tex]p = m\, v[/tex].
When the boy tossed the jug of water, the change in the momentum of the jug would be:
[tex]\Delta p(\text{jug}) = m(\text{jug}) \, (v(\text{jug}) - u(\text{jug}))[/tex], where:
[tex]m(\text{jug}) = 8.0\; {\rm kg}[/tex] is the mass of the jug;[tex]v(\text{jug}) = 2.7\; {\rm m\cdot s^{-1}}[/tex] is the velocity of the jug after the toss;[tex]u(\text{jug}) = 0\; {\rm m\cdot s^{-1}}[/tex] is the initial velocity of the jug, which was at rest before the toss.Hence:
[tex]\begin{aligned}\Delta p(\text{jug}) &= m(\text{jug}) \, (v(\text{jug}) - u(\text{jug})) \\ &= (8.0)\, (2.7 - 0)\; {\rm kg\cdot m\cdot s^{-1}} \\ &= 21.6\; {\rm kg\cdot m\cdot s^{-1}}\end{aligned}[/tex].
Similarly, the change in the momentum of the skateboard would be:
[tex]\Delta p(\text{board}) = m(\text{board}) \, (v(\text{board}) - u(\text{board}))[/tex], where:
[tex]m(\text{board}) = 1.9\; {\rm kg}[/tex] is the mass of the board;[tex]v(\text{board}) =(-0.65)\; {\rm m\cdot s^{-1}}[/tex] is the velocity of the board after the toss;[tex]u(\text{board}) = 0\; {\rm m\cdot s^{-1}}[/tex] is the initial velocity of the board.Note that the velocity of the board [tex]v(\text{board})\![/tex] after the toss is opposite to that of the jug. The sign of [tex]v(\text{board})[/tex] would be opposite to that of [tex]v(\text{jug})[/tex]. Since [tex]v(\text{jug})\![/tex] is positive, the value of [tex]v(\text{board})\!\![/tex] should be negative.
[tex]\begin{aligned}\Delta p(\text{board}) &= m(\text{board}) \, (v(\text{board}) - u(\text{board})) \\ &= (1.9)\, ((-0.65)- 0)\; {\rm kg\cdot m\cdot s^{-1}} \\ &= (-1.235)\; {\rm kg\cdot m\cdot s^{-1}}\end{aligned}[/tex].
Let [tex]m(\text{boy})[/tex] denote the mass of the boy. The velocity of the boy was initially [tex]u(\text{boy}) = 0\; {\rm m\cdot s^{-1}}[/tex] and would become [tex]v(\text{boy}) =(-0.65)\; {\rm m\cdot s^{-1}}[/tex] after the toss. The change in the velocity of the boy would be:
[tex]\Delta p(\text{boy}) = m(\text{boy}) \, (v(\text{boy}) - u(\text{boy}))[/tex].
Under the assumptions, the total changes in the momentum of this system (the boy, the skateboard, and the jug) should be [tex]0[/tex]. Thus:
[tex]\Delta p(\text{boy}) + \Delta p(\text{boy}) + \Delta p(\text{jug}) = 0[/tex].
Rearrange and solve for the mass of the boy:
[tex]\Delta p(\text{boy}) = -\Delta p(\text{jug}) - \Delta p(\text{board})[/tex].
[tex]\begin{aligned} m(\text{boy}) &= \frac{-\Delta p(\text{jug}) - \Delta p(\text{board})}{v(\text{boy}) - u(\text{boy})} \\ &= \frac{-(21.6) - (-1.235)}{(-0.65) - 0}\; {\rm kg} \\ &\approx 31.3\; {\rm kg}\end{aligned}[/tex].
jupiter rotates once every 0.41 days. at what orbital radius will a satellite maintain a constant position?
The orbital radius at which a satellite would maintain a constant position with the Jupiter is equal to 7.14 x 10^6 meters.
Jupiter is the largest planet in our solar system. To determine the radius at which a satellite would maintain a constant position, we first need to determine the time it takes for a satellite to complete one orbit around Jupiter and then relate it to the radius using the Kepler's law of planetary motions.
According to Kepler's third law, the period of a planet's orbit squared is equal to the size semi-major axis of the orbit cubed when it is expressed in astronomical units. The relation between different parameters can be given as follows:
T^2 = (4π^2 / GM) x R^3
where: T = the time it takes for the satellite to complete one orbit
M = the mass of Jupiter
R = the radius of orbit
G = the gravitational constant
To maintain a constant position, the orbital radius of the satellite must be same as that of Jupiter which is equal to 0.41 days. Substituting the values in the above equation and solving for R, we get:
R^3 = T^2 x (GM/4π^2)
⇒ R^3 = [tex]R^3 = \frac{(6.6743 * 10^-11)(1.898*10^27)}{4(3.14)^2} *(0.41)^2[/tex]
∴ R ≅ 7.14 x 10^6 meters
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a rear window defroster consists of a long, flat wire bonded to the inside surface of the window. when current passes through the wire, it heats up and melts ice and snow on the window. for one window the wire has a total length of 11.0 m , a width of 1.8 mm , and a thickness of 0.11 mm . the wire is connected to the car's 12.0 v battery and draws 7.5 a . part a what is the resistivity of the wire material? express your answer with the appropriate units.
The resistivity of the wire material can be calculated using Ohm's Law, which states that V=IR, or voltage = current multiplied by resistance. Therefore, the resistivity of the wire material is [tex]2.87 \times 10^{-8} \Omega m[/tex].
Resistivity of wire is given as ρ=RA/L where R is the resistance of wire, A is the cross-sectional area of the wire, L is the length of the wire.
The formula to calculate the resistance of wire from Ohm's Law is given by R=V/I where V is the voltage, I is the current.
Substituting the given values: V = 12.0 V, I = 7.5 A.
Therefore, R=V/I=12.0 / 7.5 = 1.6 Ω
From the formula of resistivity:
[tex]\rho=\dfrac{RA}{L}\\R=\dfrac{ρL}{A}[/tex]
Substituting the given values: R = 1.6 Ω, L = 11.0 m and calculating the area:
[tex]A = (1.8 \times 10^{-3} m) (0.11 \times 10^{-3} m)\\ = 0.198 \times 10^{-6} m²[/tex]
Therefore,
[tex]\rho = RA/L\\= \dfrac{R \times A}{ L}\\= \frac{1.6 \times 0.198 \times 10^{-6}}{ 11.0}\\ = 2.87 \times 10^{-8 } \Omega m[/tex]
Therefore, the resistivity of the wire material is [tex]2.87 \times 10^{-8 } \Omega m[/tex].
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If a 20-kilogram anvil is held 3 meters what is the potential energy?
The potential energy (PE) of an object is given by the formula:
PE = mgh
where m is the mass of the object, g is the acceleration due to gravity (9.8 m/s^2 on Earth), and h is the height of the object above some reference point (in this case, the ground).
Substituting the given values, we get:
PE = (20 kg) x (9.8 m/s^2) x (3 m) = 588 J
Therefore, the potential energy of the 20-kilogram anvil held 3 meters above the ground is 588 joules (J).
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a 3.0 a current is set up in a circuit for 3.0 min by a rechargeable battery with a 9.0 v emf. by how much is the chemical energy of the battery reduced?
The chemical energy of the rechargeable battery is reduced by 27 joules when a 3.0 A current is set up in the circuit for 3.0 minutes.
This can be calculated by multiplying the battery's emf, 9.0 V, with the amount of current, 3.0 A, and the time it was set up, 3.0 minutes, to get the amount of electrical energy in joules (J):
E = I x V x t
= 3.0 A x 9.0 V x 3.0 min
= 81 J
The chemical energy of the battery can be calculated by subtracting the electrical energy from the total energy of the battery, which is 108 J. Thus, the chemical energy of the battery is reduced by 27 J when the current is set up in the circuit:
E(chemical) = E(total) - E(electrical)
= 108 J - 81 J
= 27 J
In conclusion, the chemical energy of the battery is reduced by 27 joules when a 3.0 A current is set up in the circuit for 3.0 minutes.
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if you rub a balloon against your head, then electrons from the atoms that make up your hair get transferred to the balloon. the balloon becomes negatively charged and your hair becomes positively charged. what happens if you place balloon by hair?
When you rub a balloon against your head, electrons from the atoms in your hair are transferred to the balloon. This causes the balloon to become negatively charged, while your hair becomes positively charged. If you then place the balloon near your hair, the negative charge of the balloon will be attracted to the positive charge of your hair, causing the two to stick together. This phenomenon is known as electrostatic attraction.
The attraction of the negative charge of the balloon to the positive charge of your hair creates a strong force that causes the two objects to stick together. This force is known as the electrostatic force of attraction. It is the same force that makes two magnets stick together when their poles are placed near each other. The attraction between the balloon and your hair will remain until the charge on the balloon is dissipated by contact with another object.
To demonstrate this force of attraction, you can try rubbing the balloon against your head and then holding it near your hair. You will notice that the balloon will become attracted to your hair and will stick to it. You can also experiment with other materials that become charged when rubbed together, such as a cloth and a comb.
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a material has temperature coefficient of resistance (alpha) of 3.9 x 10^-3. if the material has a resistance of 23 ohms at a temperature of 20 c, what is the resistance of this material at a temperature of 50 c?
The resistance of the material at a temperature of 50°C is approximately 25.791 Ω.
We can use the formula for temperature dependence of resistance to solve this problem:
R2 = R1 [1 + α(T2 - T1)]
where R1 is the resistance at temperature T1, R2 is the resistance at temperature T2, and α is the temperature coefficient of resistance.
Plugging in the given values, we get:
R2 = 23 Ω [1 + (3.9 x 10⁻³/°C)(50°C - 20°C)]
Simplifying, we get:
R2 = 23 Ω [1 + (3.9 x 10^-3/°C)(30°C)]
R2 = 23 Ω [1 + 0.117]
R2 = 23 Ω [1.117]
R2 = 25.791 Ω
Therefore, the resistance of the material is approximately 25.791 Ω.
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What is the direction and magnitude of the Electric Field 4.0 m away from an 8.6 μC charge?
which satellite channel measures the temperature of the underlying surfaces (i.e., clouds, ocean, land)? group of answer choices visible infrared water vapor
Visible Infrared (IR) satellite channels measure the temperature of underlying surfaces. This includes clouds, oceans, and land.
IR channels work by detecting the amount of infrared radiation emitted from the Earth's surface. The intensity of the radiation is then converted into a digital number, which is displayed as a color on a satellite image. The higher the digital number, the warmer the surface temperature. This data can then be used to track changes in temperatures over time. The satellite channel that measures the temperature of the underlying surfaces is visible infrared. The surface temperature measurement is made possible by the difference in temperatures of objects in the infrared spectrum. An object's temperature and the level of radiation it emits have a direct correlation, and this is what visible infrared satellites use to take the temperature of the underlying surfaces. The visible infrared (VI) channel is used to estimate cloud cover and surface temperature. Infrared radiation from the surface of the earth is detected in this channel. The temperature of clouds, oceans, and land can be estimated using the visible infrared (VI) channel. It also provides data on how temperature changes with latitude and over time. Furthermore, the VI channel aids in the identification of cold and hot surfaces. Water vapor (WV) is another channel utilized in satellite imagery to observe the atmosphere's water vapor content. It enables meteorologists to forecast the occurrence of rainfall and other weather patterns. In general, satellite measurements assist in understanding Earth's weather and its impact on humans and the environment. These satellites help scientists to forecast severe weather, monitor weather changes over time, and analyze natural disasters. In addition, they assist in tracking the effects of climate change on the planet.
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What is the force on a 1 000 kilogram-elevator that is falling freely under the acceleration of
gravity only (9.8m/s²)?
Answer:
9800N
Explanation:
Since it is falling freely, the only force on it is its weight, w. w = m ⋅ g = 1000kg ⋅ 9.8ms2 = 9800N
what is the magnitude, in volts, of the maximum potential difference between two parallel conducting plates separated by 0.61 cm of air?
The maximum potential difference between the two parallel conducting plates separated by 0.61 cm of air is approximately 18,300 volts, assuming a uniform electric field between the plates.
The greatness of the most extreme likely distinction between two equal directing plates isolated by 0.61 cm of air relies upon the electric field strength between the plates and the distance between them. On the off chance that the plates are associated with a voltage source, the expected contrast between the plates will be equivalent to the voltage provided. Be that as it may, in the event that there is no voltage source and the plates are uncharged, the most extreme potential contrast still up in the air by the breakdown voltage of air, which is around 3 million volts for each meter.
Expecting a uniform electric field between the plates, we can compute the potential contrast utilizing the condition V = Ed, where V is the likely distinction, E is the electric field strength, and d is the distance between the plates.
Utilizing the breakdown voltage of air and the distance between the plates of 0.61 cm (0.0061 m), we can compute the greatest likely distinction as follows:
V = Ed = (3,000,000 V/m) * (0.0061 m) = 18,300 volts
Consequently, the greatest likely contrast between the two equal directing plates isolated by 0.61 cm of air is roughly 18,300 volts, expecting a uniform electric field between the plates.
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numerade a 75.0-kg person climbs stairs, gaining 2.50 m in height. find the work done to accomplish this task.
The work done to accomplish the task of climbing the stairs oh height 2.50 m is 1848.38 J.
The formula to calculate the work done by a person in climbing the stair is:
W = mgh
where m is the mass, g is the acceleration due to gravity, and h is the height gained.
So, we can calculate the work done by a person in climbing the stairs with the given values.
W = mgh
W = 75.0 kg × 9.81 m/s² × 2.50 m
W = 1848.38 J
Therefore, the work done by a 75.0-kg person to climb stairs gaining 2.50 m in height is 1848.38 J.
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pleases can someone help me with this question
Physiological fitness, body circumference fitness and bone strength fitness comes under nonperformance-related fitness while health-related fitness and skill related fitness comes under performance-related fitness.
Physiological Fitness refers to the ability of the body to meet the demands of physical activity and exercise also includes factors such as aerobic and muscular strength, endurance, and flexibility. Skill Related Fitness refers to physical abilities that are related to performance of sports, such as agility, coordination, balance, power, speed, and reaction time. Health-Related Fitness refers to the components of physical fitness related to health, such as cardiorespiratory fitness, body composition, and muscular strength and endurance. Bone Strength Fitness refers to the strength of the bones and how well they can withstand force and protect from injury. Body Circumference Fitness refers to the circumference of the body and how well it is proportioned to support physical activities.
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which is the proper order of structures through which light must pass in order to perceive and image?
The proper order of structures through which light must pass in order to perceive and image is cornea, aqueous humor, lens, vitreous humor, retina.
These are the five main structures of the human eye that enable vision, including light perception and imaging. Let's delve into each of these structures.
Cornea: The clear, protective outer layer of the eye is the cornea. The cornea has two purposes: to shield the inner eye from harm and to help focus light on the retina at the back of the eye.
The cornea's curved shape bends light waves as they enter the eye, assisting in their concentration.
Aqueous humor: This is a liquid that flows throughout the front of the eye, nourishing and removing waste from its surrounding tissues.
It aids in the maintenance of normal eye pressure, and if this pressure becomes too high, it can lead to glaucoma.
Lens: The lens' job is to concentrate light onto the retina. It's a transparent structure with a biconvex (lens-like) shape that varies in thickness.
It is supported by ciliary muscles that allow it to alter shape when we focus on things at different distances.
Vitreous humor: This gel-like substance fills the eye's posterior (rear) cavity, providing it with structural stability and helping it to maintain its form. It also assists in light refraction.
Retina: This is a thin layer of tissue lining the rear of the eye. The retina's photoreceptor cells, or rods and cones, are sensitive to light.
The retina converts light energy into neural signals that are transmitted to the brain via the optic nerve, which is located behind the eye. The brain translates these signals into images, allowing us to see.
What we see when we open our eyes is formed by light. In order to perceive an image, light must pass through a series of structures in the eye.
The cornea, aqueous humor, lens, vitreous humor, and retina are the five main structures of the human eye that enable vision, including light perception and imaging.
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