a) t = 4.08 s
b) Response = 20.39m
c) t = 0.991 and 3.087 seconds.
Initially, the vertical speed was 20 m/s.
(a) how long is the ball in the air?
The ball is tossed upward, rises to its highest point, and then hits the ground again.
Consequently, the end height will be equal to the starting height.
h = h o = Om
Use the equation s= ut + -at.
2764 – An = 14
Put a negative sign for g because the ball is being thrown upwards and g is acting downwards.
Om = t - 0.5 * 9.81 m/s * 20 m/s
0 = 20 *t - 0.5 * 9.81 *t
20 *t=0.5*9.81 *t
20 = 0.5 * 9.81 *t
20 0.5*9.81
Answer (a): t = 4.08 s
(b) what is the greatest height reached by the ball?
Vertical velocity for the ball decreases to zero when it reaches its highest point.
Use the equation 2-u=295
-2ghmas for - u
(20m/s - (Om/s)2) = -2 * 9.81 m/s2 *
02 – 20= -2*9.81 *
-20% = -2 *9.81 *
202 = 2 * 9.81 *
b) RESPONSE: H = 20.39m
(c) when is the ball 15 m above the ground?
The ball will be 15 meters above the earth on two separate occasions.
1. When climbing
2. When descending
Use the equation s= ut + -at.
2,264 – fn = 4
0.5 * 9.81 m/s * 15m = 20 m/s*t
15 = 20 *t - 0.5 * 9.81 *t
15 = 20t – 4.9057
4.905 – 20t + 15 = 0
Calculator-based quadratic equation solution
(c) t = 0.991 and 3.087 seconds.
Hence the answers are,
a) t = 4.08 s
b) RESPONSE: Hmar = 20.39m
c) t = 0.991 and 3.087 seconds.
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Efficiency of Machines Quick Check
Which is the equation for a machine's efficiency? (1 point)
O Efficiency
O Efficiency input energy - output energy
input energy . 100
=
=
=
output energy
input energy
O Efficiency output energy
O Efficiency input energy + output energy
=
. 100
The equation for a machine's efficiency is Efficiency = Output energy / Input energy * 100
Efficiency = ( Output energy / Input energy ) * 100
The efficiency of an ideal machine is 100% where Output energy is equal to Input energy. The efficiency cannot be greater than 100% in any machine. Because work done by the machine cannot be more than the work done on the machine.
The efficiency of a machine in real world is always less than 1 because some of the input energy is lost as friction or heat in any type of machine. So the ideal machine is possible in real world applications.
Therefore, the equation for a machine's efficiency is Efficiency = Output energy / Input energy * 100
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Why do the planets orbit the Sun?
A. The sun has enough mass to attract the planets
B. The sun has enough heat to attract the planets
C. The sun has enough velocity to attract the planets
D. The sun has enough energy to attract the planets
A. The sun has enough mass to attract the planets. is the correct statement for the given question.
What are planets?A planet is a celestial body that revolves in an orbit around the Sun, planet has sufficient mass for self-gravity to overcome rigid body forces. It has space around its orbit to revolve around the sun. A gas Giant is a planet composed mainly of gas. Super-Earth is a rocky planet that is larger than Earth.
Neptune-like planets that are about the size of Neptune. A terrestrial is a rocky world that is outside our solar system. The basic reason the planets revolve around the Sun is the gravity of the Sun that keeps them in their orbits. As the Moon orbits the Earth because of the Earth's gravitational pull and the Earth orbits the Sun because of the Sun's gravitational pull.
So we can conclude that the planets orbit the Sun because the sun has enough mass to attract the planets.
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What average mechanical power (in W) must a 76.5 kg mountain climber generate to climb to the summit of a hill of height 305 m in 42.0 min? Note: Due to inefficiencies in converting chemical energy to mechanical energy, the amount calculated here is only a fraction of the power that must be produced by the climber's body.
Power is given by, P= W/t, where W is mechanical work done and t is time taken.
From work-energy relation, work done is equal to the change in potential or kinetic energy.
W = mg[tex]h_{2}[/tex] - mg[tex]h_{1}[/tex]
Given,
Mass of mountain climber, m =76.5kg
Height of mountain hill, [tex]h_{2}[/tex] = 305m
Time taken to climb, t = 42 min= 42×60s= 2520s.
Since climber starts from the down of hill, [tex]h_{1}[/tex] = 0m. So, [tex]h_{2} - h_{1}[/tex] = 305m.
Work done, W = 76.5kg × 9.8m/[tex]s^{2}[/tex] × 305m
⇒W = 22.866×[tex]10^{4}[/tex] J.
Average mechanical power, P = 22.866×[tex]10^{4}[/tex]J ÷ 2520s
⇒P = 90.7375 W (watt)
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On average, there is enough wind in the UK each year to supply all of the UK's electricity needs.
Explain why the UK may still need power stations that use fuel to generate electricity
Explanation:
Unplanned maintenance at nuclear plants and lower than average wind speeds mean the country is currently relying on gas-powered stations to generate about half its electricity.
testing of a light switch is being discussed. technician a says a switch can be tested with a voltmeter. technician b says to use a fused jumper wire to see if the switch is operating. who is correct?
Both technician are correct .
What is voltmeter ?
A voltmeter, also known as a voltmeter, is an instrument used to measure the potential difference or voltage between two points in an electrical or electronic circuit. Some voltmeters are intended for use on direct current (DC) circuits. Others are designed for AC circuits. A dedicated voltmeter can measure radio frequency (RF) voltage.
A simple analog voltmeter consists of a sensitive galvanometer (ammeter) in series with a high resistance. The internal resistance should be high inside . Otherwise, significant currents will flow and interfere with the operation of the circuit under test. The sensitivity of the galvanometer and the value of the series resistance determine the range of voltages the meter can display.
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1.A 98.0 kg basketball player runs at a speed of 7.0 m/s. What is KE?
2.A jogger whose mass is 65 kg is moving at a speed of 4 m/s. What is the jogger's KE?
Answer:
Brainliest Answer?
2401J 520JExplanation:
E = ( 1 / 2 )mv²
b = ( 1 / 2 )( 98kg )( 7ms⁻¹ )²
b = ( 49 )²kgm²s⁻²
b = 2401J
j = ( 1 / 2 )( 65kg )( 4ms⁻¹ )²
j = ( 1 / 2 )( 65kg )( 16m²s⁻² )
j = 520kgm²s⁻²
j = 520J
Answer:
Explanation:
Given:
m = 98.0 kg
V = 7.0 m/s
__________
Ek - ?
KE - kinetic energy
Ek = m·V² / 2
Ek = 98.0*7.0² / 2 ≈ 2 400 J
if a 3.0 kg toy is moving at 4.0 m/s then what would be kentic energy of the cart is moving twice as faster
It tells us that a toy has a mass of 3.0 kg, with a speed of 4.0 m/s.
We apply the following formula:
Ec = m * v²/2
We replace data and solve:
Ec = 3.0 kg* (4.0 m/s)²
Ec = 3.0 kg* 16 m²/s²/2
Ec = 48 kg * m²/s²/2
Ec = 24 kg * m²/s²
Ec = 24 N * m ========> Joules units
Ec = 24 J
The new cartia of the cart would be of 24 joules.consider newton's 3rd law, the force that the earth exerts on a person will be equal and opposite that what the person applies to the earth. however, why don't we see the earth accelerate?
According to Newton's third law, for every action there is an equal and opposite reaction. However, the land we see on earth is stationary and the force applied by us is not at all sufficient to make a movement or to accelerate.
What is Newton's third law of motion ?According to Newton's third law, for every action there is an equal and opposite reaction. Therefore, when we apply a force on an object, the object will exerts an equal and opposite force.
According to Newton's second law of motion, the force exerted on a body is the product of mass and acceleration. Hence, the force acting on body is directly proportional to the mass of the body and it accelerates by the applied force.
The mass of humans in earth is negligible compared to the mass of earth . Therefore, the force we exert on earth is not at all sufficient to accelerate the earth. However, earth in turn exerts an equal and opposite force.
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Energy that comes from sources whose supplies are capable of being regenerated or are virtually inexhaustible is called.
Answer: Renewable
Explanation: Hope this helps.
1. A vector of 15 units acts to the left, and a vector of 3 units acts to the right. What is the resultant?
Answer: 12
Explanation:
The resultant vector is 12 unit.
What is addition of two vector?When two vectors point in the same direction, their sum is equal to the total of their respective magnitudes pointing in the same direction.
When two vectors are pointed in opposite directions, the resultant vector is pointed in the direction of the larger vector and is equal to the difference between their magnitudes.
Here, one vector of 15 unit is acting to the left and another vector of 3 unit acting rightwards. As they are acting in opposite direction, vector summation of two vector will be equal to the value of subs traction of their magnitude.
So, Resultant vector= 15 unit + (-3 unit)
= 15 unit - 3 unit
= 12 unit.
Hence, the resultant vector will be 12 unit.
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Consider a planet orbiting a sun-like star that has been detected by the doppler and that has an orbital period of one year. The larger the velocity changes measured for the star, the __________.
The larger the velocity changes measured for the planet, the larger will be the mass of the star and smaller will be the orbit's radius.
v = √ ( G M / r )
v = Orbital velocity
G = Gravitational constant
M = Mass of the central body
r = Radius of orbit
v ∝ √ M
v ∝ 1 / √ r
From the above equation is is clear that velocity of the planet increases with the increase of star's mass and increases with the decrease of planet's orbital radius.
Therefore, the larger the velocity changes measured for the star, the larger will be the mass of the star and smaller will be the orbit's radius.
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Decreasing a telescope's eyepiece focal length will:
increase magnification
decrease magnification
have no effect on magnification
Decreasing a telescope's eyepiece focal length increases magnification.
What is Magnification?The degree to which a telescope magnifies its subject. It is equal to the focal length of the telescope divided by the focal length of the eyepiece.
By doing two things, a telescope makes celestial objects visible:
1) making very faint objects visible by collecting much more light than the human eye can by itself using a big lens or mirror.
2) enlarging the things' size to make it easier to perceive their features.
On decreasing the focal length of the eyepiece focal length the magnification will increase.
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Air pressure increases as you travel higher above sea level. This is the reason that cabins in commercial airliners require pressurization.
True
False
The answer is true about the cabins in commercial airliners that require pressurization.
Why are the cabins of commercial airplanes pressurized?Airplanes are pressurized because the air is very thin at the high altitude where they fly. The passenger jet has a cruising altitude of about 30,000 - 40,000 feet. At this altitude or height, humans can't breathe very well and our body gets less amount of oxygen. Most aircraft cabins are pressurized to an altitude about 8,000 feet. This is called cabin altitude. Aircraft pilots have access to the control's mode of a cabin pressure control system and if needed it can command the cabin to depressurize.
So we can conclude that cabins in commercial airliners require pressurization because of the greater pressure of the surrounding environment.
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(1 point) suppose a spring with spring constant 8 n/m is horizontal and has one end attached to a wall and the other end attached to a mass. you want to use the spring to weigh items. you put the spring into motion and find the frequency to be 0.9 hz (cycles per second). what is the mass? assume there is no friction. mass
According to the given statement The mass attached to the spring is 3.99 kg.
What is Spring mass system ?A spring system with a block hanging from or affixed to the spring's free end is known as a spring-mass system. The spring-mass system is typically used to calculate the duration of any object in a simple harmonic motion.
Briefing:F = -kx
where k is the spring constant, and
x is the displacement of the spring
The angular frequency of the spring is:
[tex]\omega=\sqrt{\frac{k}{m}}[/tex]
m is the mass of object attached to the spring
So, frequency:
f = ω/2π = [tex]\frac{1}{2 \pi} \sqrt{\frac{k}{m}}[/tex]
m = 4π²f² / k
given that f = 0.9 Hz, and
k = 9 N/m
m = (4×π²×0.9²)/8
m = 3.99 kg
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If air resistance can be neglected, what happens to the horizontal velocity
of a basketball as it is thrown to the basket from the free-throw line?
O decreases
O stays constant
O increases
increases while the ball is going up, and then decreases while the ball is coming
down
O decreases while the ball is going up, and then increases while the ball is coming
down
If air resistance can be neglected, what happens to the horizontal velocity of a basketball as it is thrown to the basket from the free-throw line increases while the ball is going up, and then decreases while the ball is coming down.
Does the horizontal velocity change if air resistance is neglected?- When anything is hurled horizontally, gravity accelerates the object downward. – The only direction in which gravitational acceleration occurs is vertical. If we exclude the effects of air resistance, the object's horizontal velocity remains constant.
We know that the horizontal component of the force acting on the projectile at any given time will be zero if the air resistance is ignored in the projectile motion, which results in Fx=0.
The only force operating on the body in a horizontal direction if we neglect air resistance is gravity, which is acting in a vertical direction. As a result, the horizontal motion moves at a constant speed.
Therefore, option C is correct.
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a projectile with a mass of 20 grams is launched with a horizontal linear momentum of 15000 g cm/s; after it falls 250 cm vertically what would be its horizontal displacement? assume horizontal velocity remains constant after launch.
The horizontal displacement of the projectile is determined as 5.3 m.
What is the horizontal displacement of the projectile?The horizontal displacement of the projectile is calculated using the following equation.
X = vt
where;'
v is the horizontal velocity if the projectilet is the time of motionThe time of motion of the projectile is calculated as follows;
t = √(2h/g)
where;
h is the height of fall of the projectile = 250 cm = 2.5 mg is acceleration due to gravityt = √(2 x 2.5 / 9.8)
t = 0.71 s
The horizontal velocity of the projectile is calculated as follows;
P = mv
where;
P is momentum of the projectilem is massv is horizontal velocityv = P/m
v = (15000 g cm/s) / (20 g)
v = 750 cm/s = 7.5 m/s
X = 7.5 x 0.71
X = 5.3 m
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A car with a weight of 6996 N is subjected to a net force of 1.74e4. The cars acceleration will be
Answer: 24.37 m/s/s [forward] = a
Explanation:
First, find mass with the Fgrav formula.
Fgrav=mg
6996=m(9.8)
713.88 kg
Then, plug the answer into Newton's second law formula.
Fnet = ma
1.74e4 = (713.88)a
(1.74e4)/(713.88) = a
24.37 m/s^2 = a
how do you find the average force applied for a wind-up toy car while it is speeding up? It speeds up for .8s and has a velocity of .741 m/s. Total motion is 220 cm over 2.70s. Converted the cm into m (100 cm = 1 M) any help?
The average force applied for a wind-up toy car while it is speeding up is 0.926m (N), where m is the mass of the toy.
What is the average force applied to an object?
The average force applied on an object is determined by applying Newton's second law of motion.
Mathematically, the average force applied on an object is given as;
F = ma
where;
m is the mass of the objecta is the acceleration of the objectThe acceleration of the wind up toy is calculated as follows;
a = v/t
where;
v is the velocity of the wind-up toyt is the time of motion of the toya = (0.741 m/s) / (0.8 s)
a = 0.926 m/s²
Substitute the value of the mass of the wind-up toy and its acceleration into the force equation to determine the average force applied to the toy.
F = m(0.926)
F = 0.926m (Newton)
Thus, the average force applied for a wind-up toy car while it is speeding up is 0.926m (N), where m is the mass of the toy.
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Scripture Spotlight: Proverbs 6:6-11
the term sluggard comes from slugs, which move like snails, s-l-o-w-l-y. What is the message of the above passage? Read it in several Bible versions
Answer: A sluggard is someone who is habitually lazy or inactive. Such a person does not take personal responsibility for his own life. The word sluggard is used 14 times in the book of Proverbs. In each case, the Bible condemns laziness and warns of the consequences of being a sluggard.
Proverbs 6:9 asks two rhetorical questions, highlighting one of the main traits of a sluggard: “How long will you lie there, you sluggard? / When will you get up from your sleep?” Verse 6 tells the sluggard to learn a lesson from an industrious insect: “Go to the ant, you sluggard; / consider its ways and be wise!”
Explanation:
a 6.0-kg fish swimming 1.1 m/s swallows an absentminded 1.0-kg fish swimming toward it at a speed that brings both fish to a halt immediately after lunch. find the speed of the approaching smaller fish before lunch.
The speed of the approaching smaller fish before lunch is 6m/s.
What is the speed?The entire distance that an object travels in a predetermined amount of time is the definition of speed.
Given that the speed v₁ of big fish is 1 m/s and mass m₁ is 6kg. The mass m₂ of small fish is 1 kg.
Both fish have linear momentum of,
p₁ = m₁v₁ + m₂v₂
Where,
p₁ is the initial linear momentum
v₂ is the speed of the small fish.
Since both fish are traveling in the same direction and v is their ultimate meeting velocity, the final linear momentum will be given as,
p₂ = (m₁ + m₂) v
Linear momentum is held constant hence,
p₁ = p₂
m₁v₁ + m₂v₂ = (m₁ + m₂) v
The fish's final speed will be zero because they stopped moving., so
m₁v₁ + m₂v₂ = 0
v₂ = - m₁v₁/m₂
v₂ = -6×1/1
v₂ = -6
The negative symbol indicates that the tiny fish are swimming against the current.
The speed of the approaching smaller fish before lunch is 6m/s.
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A manufacturer of echo effects for music recording studios has built a prototype of an echo device that sounds exactly like a beloved echo machine from the 1970s. even though its computer chips are cheap, they are hard to find because the compounds originally used to make the chips are no longer being manufactured. what type of issue does the effects manufacturer need to overcome in order to be able to mass produce this echo device? availability cost effectiveness safety time effectiveness
Since sound expands and loses intensity as it moves farther away, the echo is weaker than the initial sound and has a smaller amplitude. For instance, when a speaker's voice is heard and its echo is compared.
One kind of audio effect that involves gradually delaying a signal is an echo effect. In this instance, after some amount of time, listeners hear the same signal repeated audibly. When the time delay is relatively long (more than 30 milliseconds), listeners can distinguish between the echoes.
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Answer:
D: Availability
Explanation:
correct on edge 2023
6. A ball rolls off a table and falls 0.75 m to the floor, landing with a speed of 4.0 m/s. 1. What is the acceleration of the ball just before it strikes the ground? 2. What was the initial speed of the ball? 3. What initial speed must the ball have if it is to land with a speed of 5.0 m/s?
1 ) Acceleration of the ball just before it strikes the ground = 10.67 m/s²
2 ) The initial speed of the ball = 1.15 m / s
3 ) The initial speed of the ball if the ball lands at 5.0 m/s = 3.2 m / s
v² = u² + 2 a s
v = Final velocity
u = Initial velocity
a = Acceleration
s = Displacement
1 ) In vertical motion,
v = 4 m / s
s = 0.75 m
u = 0
4² = 0 + ( 2 * a * 0.75 )
a = 16 / 1.5
a = 10.67 m / s²
2 ) The initial speed of the ball,
Resolving the velocity into its horizontal and vertical components,
[tex]V_{y}[/tex]² = [tex]U_{y}[/tex]² + 2 a s
[tex]V_{y}[/tex]² = 0 + ( 2 * 9.8 * 0.75 )
[tex]V_{y}[/tex] = 3.83 m / s²
V² = [tex]V_{x}[/tex]² + [tex]V_{y}[/tex]²
4² = [tex]V_{x}[/tex]² + 3.83²
[tex]V_{x}[/tex] = √ 16 - 14.67
[tex]V_{x}[/tex] = 1.15 m / s
[tex]V_{x}[/tex] = [tex]U_{x}[/tex] = 1.15 m / s
3 ) If the ball lands with a speed of 5.0 m/s,
V² = [tex]V_{x}[/tex]² + [tex]V_{y}[/tex]²
5² = [tex]V_{x}[/tex]² + 3.83²
[tex]V_{x}[/tex] = √ 25 - 14.67
[tex]V_{x}[/tex] = 3.2 m / s
[tex]V_{x}[/tex] = [tex]U_{x}[/tex] = 3.2 m / s
Therefore,
1 ) Acceleration of the ball just before it strikes the ground = 10.67 m/s²
2 ) The initial speed of the ball = 1.15 m / s
3 ) The initial speed of the ball if the ball lands at 5.0 m/s = 3.2 m / s
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a marble is rolling across a flat surface with a velocity of 2 m/s. it begins to roll up a ramp. ignoring rotational kinetic energy and friction, what will be the vertical height of the marble when it comes to a stop before rolling back down?
The vertical height of the marble when it comes to a stop before rolling back is 20 centimeters.
As per the Law of conservation of energy,
If there is no external force acting on the system, the energy will always remains the same at every point of the motion.
As, we can see, there is no external force on the marble,
Energy of the marble at start will be equal to energy of the marble at the vertical height
We can write,
Energy while rolling = Energy at the highest point
1/2MV² = MgH
Where,
M is the mass of the marble,
V is the velocity of the marble,
g is the acceleration due to gravity and,
H is vertical height of the marble.
So,
1/2MV² = MgH
1/2V² = gh
Putting all the values,
1/2(2)² = 10H
H = 4/20
H = 0.2 meters.
So, the vertical height of the marble is 20 cm.
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most interstellar clouds are made mostly of hydrogen (because hydrogen is the most common element in the universe). why are these clouds usually dominated by the color red?
The interstellar clouds that are made mostly of hydrogen are usually dominated by the color red because of its strong visible emission lines
Hydrogen is the most common element in the universe because a hydrogen is a pair of protons and electrons. Since they are oppositely charged they attract each other and it is easier to bond without the need of any external forces.
Red is colour in visible light spectrum with longest wavelength and has the lowest frequency. Because of its longer wavelength it can travel much farther distances than other colours in visible spectrum.
Therefore, these clouds usually dominated by the color red because of its strong visible emission lines
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Neptune has a mass that is about 17 times the mass of earth. the distance between the sun and neptune is about 30.1 times the distance between the sun and earth. if the gravitational force between the sun and earth is 3.5 x 1028 n, which is closest to the force between neptune and the sun? 6 x n 6 x n 6 x n 6 x n
We would weigh 114 kg on Neptune if we weighed 100 kg on Earth. In comparison, we would experience much lower gravity on the Moon (16.5%) or Mars (37.6%).
Neptune is much larger than Earth. In fact, its mass is 17 times that of the Earth. Neptune's surface gravity is approximately 110% that of Earth's, so if you weigh 100 pounds on Earth, you would weigh 110 pounds on Neptune (assuming you could find someplace to, well, stand). M is subdivided into two parts, m1 and m2. The ratio of m1/M for which the gravitational attraction between the two parts becomes maximum at a given separation is. 1:1.
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Answer:
6 x 10^26 N
Explanation:
two circuits present the same resistance to the cu rrent. in one circuit the battery causing the flow of current has a voltage of 9.0 v, and the current is 3.0 a. in the other circuit the battery has a voltage of 1.5 v. what is the current in this other circu it?
The current in this other circuit while the time remains constant, the current is doubled and the resistance is cut in half.
According to Ohm's law, the resistance (R) in a circuit has an inverse relationship to the electrical current (I), which is proportional to the voltage (V) (R). Therefore, if the voltage is raised, the current will rise as long as the circuit's resistance remains constant. Ohm's Law describes the relationship between current, voltage, and resistance. This states that, provided the temperature stays constant, the current flowing in a circuit is directly proportional to the applied voltage and inversely proportional to the circuit resistance. As long as the resistance is kept constant, an increase in voltage will therefore result in an increase in current.
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in general, what is true about the frequency at which an object vibrates? multiple choice question. the slower the vibrations, the softer the sound the slower the vibrations, the higher the pitch the faster the vibrations, the louder the sound produced the faster the vibrations, the higher the pitch
The statement that is true concerning the frequency include the following: slower the vibrations, the softer the sound, the faster the vibrations, the louder the sound produced and the faster the vibrations, the higher the pitch. That is option A,C and D.
What is sound?Sound is defined as the type of wave that is being created when disturbance causes vibration through a medium such as water, air or solid medium.
The properties of a sound wave include the following:
Frequency,Pitch,Wavelength andAmplitude.The frequency of the sound wave is affects other properties which is the number of sound waves a sound produces per second.
A low frequency would lead to low sound and pitch production while a high frequency would lead to a high sound and pitch production.
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Describe and explain a danger to a driver of not wearing a safety belt during a sudden stop.
How much gravitational force is acting on a 5 kg bowling ball resting on the floor?
A. 0.2 N
B. 9.8 N
C. 1 N
D. 49 N
Answer:
Explanation:
F = m * a = 5 kg * 9.81 m/s^2 = ~ 49 N
A vector is 253 m long and points in a 55.8 degree direction. Find the y-component of the vector. Please help!!
Answer:
209.3 m
Explanation:
x component will be 253 cos 55.8
y component will be 253 sin 55.8 = 209.3 m