Answer:get pranked
Explanation:A chemist needs to neutralize 349 L of HF solution that has a molarity of 3.6 M. She currently has an NaOH solution with a molarity of 5.4 M. How many liters of her NaOH solution would she need to neutralize the HF? The chemical equation for this reaction is HF + NaOH → NaF + H2O. I need the answer in 20 ish minutes! Please help!
Sure, I'd be happy to help! Based on the chemical equation you provided, one mole of HF reacts with one mole of NaOH to form one mole of NaF and one mole of water.
To calculate the number of moles of HF in 349 L of 3.6 M solution, we can use the formula:
moles of solute = molarity x volume in liters
So, moles of HF = 3.6 M x 349 L = 1256.4 moles of HF
Because the reaction is a 1:1 ratio between HF and NaOH, we would need the same number of moles of NaOH to neutralize the HF.
Therefore, we can find the number of liters of 5.4 M NaOH solution needed using the formula:
moles of NaOH = moles of HF
5.4 M x volume of NaOH solution in liters = 1256.4 moles of NaOH
volume of NaOH solution in liters = 1256.4 moles of NaOH / 5.4 M
volume of NaOH solution = 232.3 L
So, the chemist would need approximately 232.3 L of 5.4
What product(s) would you expect to obtain from reaction of 1,3-cyclohexadiene with each of the following?
(a) 1 mol Br2 in CH2Cl2
(b) O3 followed by Zn
(c) 1 mol HCl in ether
(d) 1 mol DCl in ether
(e) 3-Buten-2-one (H2C ═ CHCOCH3)
(f) Excess OsO4, followed by NaHSO3
(a) 1,3-cyclohexadiene would react with 1 mol Br2 in CH₂Cl₂ to give 1,2-dibromo-1,3-cyclohexadiene.
(b) 1,3-cyclohexadiene would react with O₃ followed by Zn to give adipic acid.
(c) 1,3-cyclohexadiene would react with 1 mol HCl in ether to give chlorocyclohexene.
(d) 1,3-cyclohexadiene would react with 1 mol DCl in ether to give deuterated cyclohexene.
(e) 1,3-cyclohexadiene would react with 3-buten-2-one in the presence of an acid catalyst to give a Diels-Alder adduct.
(f) 1,3-cyclohexadiene would react with excess OSO₄, followed by NaHSO₃ to give a vicinal diol.
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what is the next stage after the body plan is established chapter 4 embryological similarities
The next stage after the body plan is established is the process of differentiation into organs and organ systems.
What is a body plan in animal or metazoan developmental stages?A body plan in animal or metazoan developmental stages refers to a group f features developed in the embryo stages that can define a particular taxonomic group such as the formation of the embryo layers in mammals.
Therefore, with this data, we can see that a body plan in animal or metazoan developmental stages is required before continuing with the development of organs by differentiation.
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Which of the following describes the weather forecast shown in the image?
1. Low air pressure and low chance of precipitation
2. Low air temperatures and a high chance of precipitation
3. Low chance of precipitation and low air temperatures
4. Low humidity and high air temperatures
Drag each tile to the correct location. Physical property. Chemical property. Tiles: acetic acid can react with another substance and change color. The melting point of tin is 231.9 degrees C. Sodium can react with water to form sodium hydroxide and hydrogen. Iron does not burn when exposed to flame. The density of solid silver is 10.49 grams/centimeter3. Pure water is odorless.
The melting point of tin is 231.9 degrees C, Iron does not burn when exposed to flame, The density of solid silver is 10.49 grams/centimeter³ and Pure water is odorless are Physical property.
Although a physical change happens when substance alters forms without changing its chemical identity, a chemical change is the result of a chemical reaction. If enough energy is provided, many physical changes can be reversed. A different chemical reaction is the only way to undo a chemical change.
The melting point of tin is 231.9 degrees C, Iron does not burn when exposed to flame, The density of solid silver is 10.49 grams/centimeter³ and Pure water is odorless are Physical property. Sodium can react with water to form sodium hydroxide and hydrogen is Chemical property.
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You receive the following prescription:
Progesterone 4% cream
Apply as directed
60 g
Your pharmacy stocks progesterone cream 10%. How much stock cream is needed to fill the prescription?
Select one:
We need 24 g of the 10% progesterone cream to fill the order for 2 oz (60 g) of 4% progesterone cream.
To determine the amount of stock cream needed to fill the order, we can use a simple formula that involves cross-multiplication.
First, we need to find out how much progesterone is contained in the 4% cream. This can be calculated by multiplying 4% (or 0.04) by the weight of the cream (60 g):
0.04 * 60 g = 2.4 g
So each 60 g of 4% cream contains 2.4 g of progesterone.
To find out how much stock cream (which is 10% progesterone) is needed to provide 2.4 g of progesterone, we can set up the following equation:
10% x y g = 2.4 g
Here, "y" represents the amount of stock cream needed. To solve for "y," we can divide both sides by 10% (or 0.1):
y g = 2.4 g ÷ 0.1
y g = 24 g
Therefore, we need 24 g of the 10% progesterone cream to fill the order for 2 oz (60 g) of 4% progesterone cream.
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complete question:
You receive the following order: Progesterone 4% cream Apply as directed 2 oz (60 g) Your pharmacy stocks progesterone cream 10%. How much stock cream is needed to fill the order? A) 2.4g B) 24 g C)40 g D)4g
For the following reaction, K > 1. Classify each of the reactants and products based on their strength as Bronsted-Lowry acids or bases.
C9H7N + HNO2Doublearrow.GIFC9H7NH+ + NO2-
a) HNO2 1) stronger acid
b) NO2- 2) weaker acid
c) C9H7NH+ 3) stronger base
d) C9H7N 4) weaker base
For the given reaction with K > 1, we can classify the reactants and products based on their strength as Bronsted-Lowry acids or bases:
a) 1, b) 4, c) 2, d) 3.
C9H7N + HNO2 ⇄ C9H7NH+ + NO2-
a) HNO2 is a stronger acid (1) because it donates a proton to C9H7N.
b) NO2- is a weaker base (4) because it accepts a proton less readily compared to C9H7N.
c) C9H7NH+ is a weaker acid (2) because it donates a proton less readily compared to HNO2.
d) C9H7N is a stronger base (3) because it accepts a proton from HNO2.
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