A child traveling 5 m/s on a sled passes her younger brother. If her average acceleration on the sledding hill is 2 m/s^2. how fast is she passes her older brother 4 s later?

By using Specific heat capacity, 741.76 x [tex]10^4[/tex]heat energy is needed to raise the temperature.

The amount of heat required to increase the temperature of 1 gram of a substance by 1 degree Celsius (°C) is known as the specific heat capacity.

The importance of specific heat capacity may be summed up as the quantity of energy needed to heat or cool an item of a given mass by a certain amount.

Given:

Mass of vat, mvat = 20kg

Mass of water, mwater = 3kg

ΔT = 90 – 10 = 80℃

Specific heat capacity of iron, Ciron = 450J/kg

Specific heat capacity of water, Cwater = 4186J/kg

To find:

Heat energy required, Q = ?

Formula:

C = Q / (m ΔT)

Calculations:

Q = mCΔT

Q = Qempty + Qwater

Q = (20 x 450 x 80) + (3 x 4186 x 80)

Q = 172.464 x [tex]10^4[/tex]J

Result:

Heat energy required is 172.464 x [tex]10^4[/tex]J

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The speed of the ball at launch is 23m/s.

After 0.5 seconds, the ball initially passed the pole.

Then it will again reach the top of the pole after 4.1 seconds.

Consequently, the ball's travel time above the pole is

Δt  = 4.1 - 0.5 = 3.6sec

Now the time it will take to reach the highest point from the top of the pole is given as t = Δt/2 = 1.8sec.

Now the total time to reach the top from the bottom is given as 2.3sec.

After 0.5 seconds, the ball initially passed the pole.

Consequently, the ball's travel time above the pole is

[tex]v_{f} - v_{i} = at[/tex]

[tex]v_{i}=22.54m/s[/tex]

also the speed after 0.5 s is

[tex]v_{f} = 17.64m/s[/tex]

So, the speed of the ball at launch is 23m/s.

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projectile's vertical speed v yv y v, start , y,  drops prior to reaching its maximum height since its acceleration is in the opposite direction. Since the object's height is rising, the initial direction of the velocity is upward

.

At the projectile's highest point, vertical velocity zeroes out. After reaching the highest point, the vertical speed increases due of the same-direction acceleration. As the object's height lowers, the vertical velocity has a downward direction.

In projectile The beginning vertical velocity determines the maximum height. Increasing the launch angle raises the maximum height because steeper launch angles have a larger vertical velocity component.

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Average speed must the car have for the average speed for the entire 24.0 km trip 67.039 km/hr.

Average speed for entire journey (jogging + drive) = 20 km/hr

total distance traveled = 24 km

total time spent (on jog + drive) = total distance/average speed

total time spent (on jog + drive) = 24/20

total time spent (on jog + drive) = 1.2 hr

Jogging:

Speed = 9.5 km/hr

Distance = 8.0 km

Time spent jogging = Distance/Speed

= 8.0 / 9.5 = 0.842 hr

Driving car :

Speed = ?

Distance = 24 km

time spent driving = total time spent on journey - time spent jogging

time spent driving = 1.2 - 0.842 = 0.358 hr

average speed for driving = distance / time

average speed for driving = 24/0.358

average speed for driving = 67.039 km/hr

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Using conservation of momentum we will get that the ratio of velocity of mass M₁ and mass M₂ is ratio of M₂ to M₁

i.e. v₁/v₂=M₂/M₁

What is conservation of momentum ?

conservation of momentum states that in an isolated system the initial momentum will always be equal to final momentum.

given:

initial velocity of the object= 0m/s

initial momentum of the object = 0kg.m/s

now the mass M breaks into 2 pieces such that:

M₁ is the mass of first piece

M₂ is the mass of first piece

velocity of M₁ is v₁

velocity of M₂ is -v₂ as to conserve momentum

using conservation of momentum we get,

initial momentum = final momentum

0 = M₁×v₁ + M₂×(-v₂)

M₁×v₁= M₂×v₂

v₁/v₂ = M₂/M₁

using conservation of momentum we will get that the ratio of velocity of mass M₁ and mass M₂ is ratio of M₂ to M₁

i.e. v₁/v₂=M₂/M₁

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The correct answer is V_f = 1.81 × 10^14.

D = 2cm = 0.02 m

ΔV = 150 V

V_i = 2.6 × 10^5 m/s

The coulomb force,

F = qE

ma = qE

a = qE/m

Potential difference

ΔV = ED

E = ΔV/D

a = qΔV/mD

Using equation of motion,

V_f^2 = V_i^2 + 2ad

V_f = √V_i^2 + 2ad

V_f = √V_i^2 + 2d ( qΔV/mD)

here q= 1.6  × 10^-19 C

m = 9.11 × 10^-31 kg

for d= 0.1 cm =  0.001 m

V_f = √(2.6 × 10^5)^2 + 2 (0.001)(1.6  × 10^-19 C × 150V/9.11 × 10^-31 × 0.02)

V_f = √(6.76 × 10^10) + 0.002(24× 10^-18 C)/1.822× 10^-32)

V_f = √(6.76 × 10^10) + 48 × 10^-15/1.822× 10^-32

V_f = √(6.76 × 10^10) + 26.3 × 10^17

V_f = √33.06 × 10^27

V_f = 1.81 × 10^14

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1. The waterfall is 8.54 m high

2. The velocity with which the swimmer enters the water is 14.836 m/s

s = ut

2.5 = 1.9 × t

Divide both sides by 1.9

t = 2.5 / 1.9

t = 1.32 s

h = ½gt²

h = ½ × 9.8 × 1.32²

h = 8.54 m

The velocity with which the swimmer enters the water can be obtained as follow:

v = u + gt

v = 1.9 + (9.8 × 1.32)

v = 1.9 + 12.936

v = 14.836 m/s

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The narration style in the para is third person omniscient

As it narrates the whole incident which is going on.

What is third person omniscient?

The most flexible and open POV available to writers is third person omniscient. An omniscient narrator is one who has all knowledge and all sight, as the name suggests.

The narrator may occasionally access the consciousness of a few or many different characters while the narration is taking place outside of any one particular character.

Some authors employ this viewpoint to build a more "godlike" or purposefully "authorial" persona that enables them to offer dispassionate commentary on the action. Detailed location descriptions that contribute to the mood or atmosphere of a scene may be an example of this, as well as philosophical tangents that serve to develop concepts that only loosely link to the action of the story.

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The thickness of the barrier that will stop a car travelling at 76.86 km/h is 0.76 m.

The thickness of the barriers can be calculated using a kinematic equation as shown below;

v² = u² + 2ad

where;

The given final velocity of the car;

v = 76.86 km/h = 21.35 m/s

Thickness of the barrier that will stop a car travelling at 76.86 km/h is calculated as follows;

d = v²/2a

d = (21.35²) / (2 x 300)

d = 0.76 m

Thus, the thickness of the barrier that will stop a car travelling at 76.86 km/h is 0.76 m.

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Answer: $638,00

Explanation: Hi Tania... I believe we're in the same class and I was just doing the Science homework when I saw your question... Take this as a gift for doing the Spanish homework last time... Thx! Oh, btw that's the procedure and the response.

X=(1100*0.58)/1= 638,00

At distance of 40/7 m from A the particles will collide.

Let particles collide at C

And let distance AC = x and BC = y

then, x+y = 20

As the equation used for distance required here is: s= ut +1/2 a[tex]t^{2}[/tex] and  here u=0

Then, 1/2 (2)[tex]t^{2}[/tex]  +1/2 (5)[tex]t^{2}[/tex]  =20  

7/2[tex]t^{2}[/tex]  =20

[tex]t^{2}[/tex] = 40/7

Now

x= 1/2 (2)[tex]t^{2}[/tex] = 40/7 m

Therefore, at distance of 40/7 m from A the particles will collide.

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The magnitude of the given vectors for B - 3A expression is determined as 105.5 m.

The magnitude of a vector is the length of the vector. The magnitude of the vector a is denoted as |a|.

The magnitude of a vector represents the absolute value of the given vector.

The magnitude of the expression B - 3A is calculated as follows;

B - 3A = 26.5 - 3(44)

B - 3A = 26.5 - 132

B - 3A =  -105.5

|B - 3A| = 105.5

Thus, the magnitude of the given vectors for B - 3A expression is determined as 105.5 m.

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Answer: Hydrothermal vents is your answer.

Explanation:

it's very hot, there is no light, there are bacteria, and there it's mineral-rich.

The Net magnetic field will be at the left in case I, right in Case II, In-between in Case III, and Nowhere in Case IV and V.

Case I

As the current in both wires is not equal, the net magnetic field will not be zero in the middle. It will be zero somewhere near the 3 A current carrying wire and farther from the 9A current carrying wire. Which is to the Left.

Case II

It is similar to the case I, as the current in both wires is not equal, and the net magnetic field will not be zero in the middle. It will be zero somewhere near the 3 A current carrying wire and farther from the 9A current carrying wire. Which in this case is to the Right.

Case III

As the current in both wires is the same and equal to 3 A, the net magnetic field will be zero in the middle. Which is in Between.

Case IV

As the current flowing in the wire is opposite in the direction, the magnetic field will always be in the same direction. So the magnetic field will be zero Nowhere.

Case V

It is similar to the above case IV, as the current flowing in the wire is opposite in the direction, and the magnetic field will always be in the same direction. So the magnetic field will be zero Nowhere.

Therefore, the Net magnetic field will be at left in case I, right in Case II, In-between in Case III, and Nowhere in Case IV and V.

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The bus's displacement from Houston to Texas with average velocity = -16.170 km/h

Evaluation :

average velocity = ( initial velocity -- final velocity )

                                    ( v-u )

displacement = [tex]\frac{v-u}{t}[/tex]

displacement =  [tex]\frac{0 - 76 }{4.7}[/tex]

                            = - 16.170 km/h

Average velocity is determined  as the change in position or displacement (∆x) divided by the time period  (∆t) in which the displacement results . The average velocity could be positive or negative based upon the sign of the displacement. The SI unit of average velocity is defined as  meters per second (m/s or ms-1).

The displacement is commonly the difference in the position of the two marks and is independent of the path covered  when traveling between the two of the  marks. The distance covered , however, is the total length of the path chosen  between the two marks. Displacement defined  as a vector quantity that mean  to "how far out of  the place an object is"; it's the object  overall changes  in  the position.

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As we go up the y-axis, the number of sprouted bean seeds increase (option B).

Graph is a data chart intended to illustrate the relationship between a set (or sets) of numbers (quantities, measurements or indicative numbers) and a reference set.

In a graph, there are two axes as follows;

According to this question, a graph of number of sprouted bean seeds on the y-axis is plotted against temperature on the x-axis.

We can observe that as we go up the y-axis, the number of sprouted bean seeds increase.

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by using all the four type of parenting here is the descriptive answer which include 4 types of parenting by parents.

When a child queries the justification for a regulation, authoritarian parents are infamous for responding, "Because I said so," They are more concerned with obeying than they are with negotiating. Parental authority figures may substitute punishment for instruction. So instead of instructing a child on how to make better decisions

Parents who are authoritative put time and effort into avoiding behavioral issues before they arise. Additionally, they employ positive discipline techniques like reward and praise systems to reinforce good conduct.

Parents that are liberal with their children typically act more like friends than parents. They frequently encourage their kids to talk to them about their issues, but they typically don't make an attempt to discourage poor decisions or misbehavior because they are either uninvolved parents who don't understand how kids develop, or they are unaware of it.

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Answer: Bias

Explanation:

Answer:

d) Krypton

Explanation:

Krypton has similar properties to that of neon, as they are noble gases (in same group). Hence, option (d) is the answer.

Answer:

[tex]{ \tt{displacement = velocity \times time }} \\ { \tt{ = 2.4 \times 46}} \\ { \tt{ = 110.4 \: m}}[/tex]

The maximum speed of the stone tied to the string is 5.32 m/s.

The mass of the stone is m = 1.2 kg.

The mass is tied to a string and it swung in a vertical radius of r = 0.85 cm.

The tension on the string is T = 40 N.

The centripetal force of a body moving in a circle of radius r is given as:

T = ( mv² / r )

Where T is the tension, m is the mass of the body and r is the radius of the circle.

Then,

v² = ( T × r ) / m

v = √ [ T × r / m ]

v = √ [ 40 × 0.85 / 1.2 ]

v = √ [ 34 / 1.2 ]

v = √28.3

v = 5.32 m/s

The maximum speed of the stone before the string breaks is 5.32 m/s.

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(a) The expression for the horizontal acceleration of the cart is

a = (T - μN)/Mc.

(b) The expression for the vertical acceleration of the hanging mass is

a = (T - Mhg)/Mh.

(c) The expression for the acceleration of both cart and the hanging mass is a = (Mhg - μN) / (Mc - Mh).

The horizontal acceleration of the cart is calculated as follows;

The horizontal acceleration of the cart is determined from the net horizontal force acting on the system.

T - μN = Mca

where;

a = (T - μN)/Mc

T - Mhg = Mha

where;

a = (T - Mhg)/Mh

If the acceleration of the cart and the hanging mass are equal, our final equation becomes;

From first equation;

a = (T - μN)/Mc

Mca = T - μN

Mca + μN = T

From second equation;

a = (T - Mhg)/Mh

Mha = T - Mhg

Mha + Mhg = T

Solve the two equation together;

Mca + μN = Mha + Mhg

Mca - Mha = Mhg - μN

a(Mc - Mh) = Mhg - μN

a = (Mhg - μN) / (Mc - Mh)

Thus, the expression for the acceleration of both cart and the hanging mass is a = (Mhg - μN) / (Mc - Mh).

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The information provided above demonstrates that the range of the tube's radius within which we are certain is from 23.7 to 24.3.

Accurate findings are desired when any quantity is being measured. Closeness of the measurements to a particular value is referred to as accuracy (like the theoretical value). It is not insignificant that measurements can contain inaccuracies; as a result, the outcome frequently includes a margin error. The sentence above displays the radius's measured value along with its margin of error.

In other words, the aforementioned statement represents a quantity's numerical value along with its tolerance, or the only permissible (and conceivable) values to ensure that the measurement is accurate. The information provided above demonstrates that the range of the tube's radius within which we are certain is from 23.7 to 24.3.

These are all valid radius values, along with all others within this interval. By increasing the number of trials in a measurement, the value for the upper and lower bounds of the error can be decreased.

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The experiment to show the random motion of the particles is the movement of particles in a solution is the simplest representation of motion of particles.

Pick up two glass beakers. Fill one beaker with hot water and the second one with cold water. Add KMnO4 crystals in very small quantities to both. We thus see that KMnO4 particles move faster in hot water than in cold water.

Pick up some iron and  a piece of chalk. We learn that it's quite difficult to work with iron. This leads us to believe that the Forces can affect matter particles. among them. The pressure kept between  particles and the power of the attraction in materials is at its strongest between particles the least in gases.

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Answer:

The FM carrier waves should have different frequencies than the carrier waves, not different amplitudes.

Explanation:

The label at the top of the diagram should be “FM Radio,” not “Cell Phone.

Answer:

[tex]{ \tt{acceleration = \frac{ \triangle \: v}{t} }} \\ \\ { \tt{a = \frac{110 - 70}{t} }} \\ \\ { \tt{t = \frac{40}{a} } \: s}[/tex]

For a body under free fall; a = g = 9.8

[tex]{ \tt{t = \frac{40}{9.8} }} \\ \\{ \tt{t = 4.08 \: s}}[/tex]

Answer:

Explanation:

yes, it will.40