When a compressed spring is pushing a block across a rough horizontal table, a free-body diagram shows four force vectors. They are named weight, normal force, the force of friction, and the force of the spring.
What are the four force vectors?
Weight: It is the gravitational force of attraction that the earth exerts on an object. Its direction is always down.
Normal force: It is the force exerted by the surface of the object on which the other object rests. Its direction is always perpendicular to the surface.
The force of friction: It is the force that opposes the motion of the object on the surface due to the microscopic interaction between the surfaces of the two objects. Its direction is always opposite to the direction of the object's motion.
The force of the spring: It is the force exerted by the spring on the object, and its direction is always in the opposite direction of the spring's compression.
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gunther is trying to push a 10 kg box. the coefficient of static friction between a 10 kg object and the floor is 0.50. what is the maximum force that can be applied on the object before it starts moving?
The maximum force that can be applied to the object before it starts moving is 49 N
To calculate the maximum force that can be applied to the object before it starts moving, we need to use the formula:
Fmax = μsN
where μs is the coefficient of static friction, N is the normal force exerted on the object, and F(max) is the maximum force that can be applied to the object before it starts moving.
Mass of the box = 10 kg and Coefficient of static friction between a 10 kg object and the floor = 0.50.
Normal force exerted on the box, N = mg (where g is the acceleration due to gravity = 9.8 m/s²)
So, N = 10 kg × 9.8 m/s² = 98N.
We can now use the above formula to calculate the maximum force that can be applied to the object before it starts moving:
Fmax = μsN = 0.50 × 98 N = 49 N.
Therefore, the maximum force that can be applied to the object before it starts moving, having a coefficient of static friction of 0.50 is 49 N.
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what is the impulse experienced by a 65.8 kg halfback encountering a force of 1025 n for 0.350 seconds?
The 65.8 kg halfback experienced an impulse of 359 Ns when subjected to a force of 1025 N for a duration of 0.350 seconds.
The formula for impulse is given below:
Impulse = force × time
Where F is the force applied on the object.
t is the time for which the force is applied.
"I" is the impulse experienced by the object.
Substituting the given values,
Force (F) = 1025 N Time (t ) = 0.350 s Impulse I = ?
Impulse = force × time
I = F × t
I = 1025 × 0.350
I = 358.75 Ns or 359 Ns
The impulse experienced by a 65.8 kg halfback encountering a force of 1025 N for 0.350 seconds is 359 Ns.
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if a bag has a mass of 25 kg, how much force must you apply vertically to lift it off of a baggage cart?
A force of 245 N must be applied vertically to lift the bag off the baggage cart.
The force that must be applied vertically to lift a bag off a baggage cart, given that the bag has a mass of 25 kg, can be determined using the formula F = m*g
where F is force, m is mass, and g is acceleration due to gravity. The value of g is 9.8 m/s².So, F = 25 kg x 9.8 m/s² = 245 N. Therefore, a force of 245 N must be applied vertically to lift the bag off the baggage cart.
The mass of the bag = 25 kg.The formula used is, F = m*gwhereF = Force required to lift the bagm = Mass of the bagg = Acceleration due to gravityF = 25 kg x 9.8 m/s² = 245 N.
Therefore, a force of 245 N must be applied vertically to lift the bag off the baggage cart.
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determine if the drag force exerted on an object moving through air (a.k.a. force of air resistance) is proportional to the velocity or the square of the velocity of the object.
The drag force exerted on an object moving through air (a.k.a. force of air resistance) is proportional to the square of the velocity of the object.
Thus, the correct answer is proportional to the square of the velocity of the object.
What is the drag force?The аir resistаnce force аcting on аn object moving through аir is referred to аs drаg force. When а body trаvels through а fluid such аs wаter or аir, it fаces resistаnce to its motion, which is proportionаl to the velocity of the object. This resistаnce force аcting on а body moving through аir is referred to аs аir resistаnce or drаg force.
The drаg force on аn object in the аir is proportionаl to the squаre of the object's velocity. When the velocity of the object is doubled, the drаg force becomes four times greаter. Thus, the drаg force grows fаster thаn the object's velocity. In other words, the drаg force аcting on аn object increаses аs the squаre of the object's velocity.
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what is the magnitude of the impulse on an 7.2- kg ball rolling at 2.4 m/s when it bumps into a pillow and stops?
The magnitude of the impulse on a 7.2-kg ball rolling at 2.4 m/s when it bumps into a pillow and stops can be calculated using the impulse-momentum theorem.
According to the theorem, the impulse of an object is equal to the change in momentum of the object. Since the ball has a mass of 7.2 kg and an initial velocity of 2.4 m/s, its initial momentum is 17.28 kg·m/s. As the ball stops when it hits the pillow, its final momentum is 0. The change in momentum is therefore -17.28 kg·m/s.
Since the impulse of an object is equal to its change in momentum, the impulse of the ball is -17.28 kg·m/s. This means that the impulse of the ball is equal to the magnitude of the force applied to the ball multiplied by the duration of the collision. Thus, the magnitude of the impulse on the ball when it bumps into the pillow and stops is -17.28 kg·m/s.
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A string is stretched to a length of 238 cm and both ends are fixed. If the density of the string is 0.014 g/cm, and its tension is 1610 N, what is the fundamental frequency? Answer in units of Hz.
Answer:
The fundamental frequency of a vibrating string is given by:
f = (1/2L) √(T/μ)
where L is the length of the string, T is the tension in the string, and μ is the linear density (mass per unit length) of the string.
In this problem, L = 238 cm, T = 1610 N, and μ = 0.014 g/cm = 0.00014 kg/cm. We can convert the units of length and mass to SI units (m and kg) to get the frequency in Hz:
L = 2.38 m
μ = 0.00014 kg/m
Substituting these values into the formula, we get:
f = (1/2L) √(T/μ)
f = (1/2 × 2.38 m) √(1610 N / 0.00014 kg/m)
f = 106.8 Hz
Therefore, the fundamental frequency of the string is 106.8 Hz.
Answer:
The fundamental frequency of the string is 225.29 Hz.
Explanation:
To calculate the fundamental frequency of the string, we use the formula below.
Formula:
F' = (1/2l)√(T/m)............... Equation 1
Where:
F' = Fundamental frequency of the string
l = length of the string
T = Tension on the string
m = mass per unit length of the string
From the question,
Given:
l = 238 cm = 2.38 m
T = 1610 N
m = 0.014 g/cm = 0.0014 kg/m
Substitute these values into equation 1
F' = 1/(2×2.38)[√(1610/0.0014)]
F' = (0.210){√(1150000)
F' = (0.210×1072.38)
F' = 225.29 Hz.
Hence, the fundamental frequency of the string is 225.29 Hz.
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a space traveler weighs 682 n on earth. what will the traveler weigh on another planet whose radius is 3 times that of earth and whose mass is 2 times that of earth?
The traveler's weight on another planet whose radius is 3 times that of Earth and whose mass is 2 times that of Earth is 21.647 N
The following is the solution to the given problem:
Mass and gravity are related to one another. Gravity is generated by the planet's mass, and the magnitude of the gravitational force is determined by the mass of the planet on which the object is situated, as well as the mass of the object.
Mass, distance, and gravity are all factors that influence the gravitational force. Mass is directly proportional to the gravitational force and inversely proportional to the square of the distance from the gravitational force's center.
Here is the formula: Force of gravity = G(M1M2)/d²where, G is the gravitational constant 6.67 x 10^{-11} N(m/kg)^2, M1 is the mass of the first body, M2 is the mass of the second body, d is the distance between the centers of two bodies.
On earth, the traveler weighs 682 N. On another planet whose radius is 3 times that of Earth and whose mass is 2 times that of Earth, we have to calculate the traveler's weight.
Mass of Earth is 5.972 × 10^24 kg2,
Radius of Earth is 6.371 x 10^63.
The mass of the planet whose radius is 3 times that of Earth and whose mass is 2 times that of Earth.
Mass of the planet = 2 x mass of Earth = 2 x 5.972 × 10^24 kg = 1.1944 × 10^25 kg4.
The radius of the planet whose radius is 3 times that of Earth,
Radius of the planet = 3 x radius of Earth = 3 x 6.371 x 10^6 m = 1.9113 × 10^7 m5.
The distance between the two planets.
Distance between two planets = radius of planet + radius of Earth
= 1.9113 × 10^7 m + 6.371 x 10^6 m
= 2.54813 x 10^7 m
= 2.54813 x 10^10 cm.
Putting all the values in the formula.
Force of gravity = G (M1 M2) / d²
Where, Mass of the traveler on the other planet is m.
Mass of the Earth is M1 = 5.972 × 10^24 kg.
Mass of the other planet is M2 = 2 x 5.972 × 10^24 kg = 1.1944 × 10^25 kg.
Radius of the Earth is r1 = 6.371 x 10^6 m.
Radius of the other planet is r2 = 3 x 6.371 x 10^6 m = 1.9113 × 10^7 m.
Distance between the two planets is d = 2.54813 x 10^10 cm.682
= G (M1 M2)/d²
G = 6.674 × 10^-11 N m² / kg²
Force of gravity on other planet = G(mM2)/r² where m is the mass of the traveler on the other planet
= 6.674 × 10^-11 × (m × 1.1944 × 10^25)/(1.9113 × 10^7)²
Weight on another planet = force of gravity on another planet × mass of the traveler on another planet
= (6.674 × 10^-11 × (m × 1.1944 × 10^25)/(1.9113 × 10^7)²) × m
= 21.647 N (approximately)
Therefore, the traveler's weight on another planet whose radius is 3 times that of Earth and whose mass is 2 times that of Earth is 21.647 N (approximately).
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how does matter affect your daily lives?
Matter affects our daily lives in the sense all is composed of matter and energy.
What are matter and energy in the Universe and daily life?Matter and energy in the Universe and daily life are two basic elements that characterize the physic system and allow us to understand the world. In regard to matter, it is something that occupies space and has mass, while energy can perform work.
Therefore, with this data, we can see that matter and energy in the Universe and daily life are fundamental to understanding the universe.
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in young's singe slit experiment, if the width of the slit decreases, what happends to the width of the diffracted peaks?
In Young's single slit experiment, if the width of the slit decreases, the width of the diffracted peaks increases.
Young's experiment involves a single slit that diffracts light and produces a pattern of bright and dark fringes on a screen. The width of the slit affects the diffraction of light through the slit and determines the width of the bright fringes on the screen.
The narrower the slit, the greater the diffraction of light, which causes the bright fringes to become wider.
This is because diffraction causes the light waves to spread out as they pass through the narrow slit, leading to interference and the formation of bright and dark fringes on the screen.
Therefore, if the width of the slit decreases, the width of the diffracted peaks increases.
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additional required problem: two people, one of mass 85 kg and the other of mass 55 kg, sit in a rowboat of mass 78 kg. with the boat initially at rest, the two people, who have been sitting at opposite ends of the boat, 3.0 m apart from each other, now exchange seats. how far and in what direction will the boat move?
The boat will not move since the two people exchanging seats will not cause a net linear momentum on the boat.
The equation for linear momentum is P = mv, where m is the mass and v is the velocity of an object.
Since the boat is initially at rest, its linear momentum is P = 0.
Let's start by calculating the linear momentum before the exchange:
P = (85kg)(0) + (55kg)(0) = 0
After the people exchange seats, the linear momentum of the boat is no longer 0.
Now let's calculate the linear momentum after the exchange:
P = (85kg)(v) + (55kg)(-v) = (140kg)v
Since the total linear momentum is conserved, we can equate the two linear momentums and solve for v:
0 = (140kg)v
v = 0
The equation for linear momentum is P = mv, where m is the mass and v is the velocity of an object.
Therefore, the boat will not move since the velocity of the boat is 0.
This makes sense since the two people exchanging seats will not cause a net linear momentum on the boat.
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al is floating freely in his spacecraft, and you are accelerating away from him with an acceleration of 9.8 m/s2. how will you feel in your spacecraft? group of answer choices you will feel weight, but less than on earth. you will feel yourself pressed against the back of your spaceship with great force, making it difficult to move. you will feel the same weight as you do on earth. you will be floating weightlessly. you will feel weight, but more than on earth.
You will feel yourself pressed against the back of your spacecraft with great force, making it difficult to move. This is because when you accelerate, the force of gravity is increased, causing you to feel an increased weight.
This option is the correct one. As per Newton's second law, the force of the body is directly proportional to the mass and acceleration. Here, the acceleration is 9.8 m/s2, which means you will feel yourself pressed against the back of your spaceship with great force, making it difficult to move, you will feel the same weight as you do on earth.
This is an incorrect option because the acceleration is greater than 1g, which means the weight will be greater than the actual weight.you will be floating weightlessly. This is an incorrect option because there is an acceleration, which means you will not be floating weightlessly.you will feel weight, but more than on earth. This is an incorrect option because the acceleration is greater than 1g, which means the weight will be greater than the actual weight.
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kim holds a 2.0 kg air rifle loosely and fires a bullet of mass 1.0 g. the muzzle velocity of the bullet is 150 m/s. calculate the recoil speed of the rifle.
The recoil speed of the rifle is 0.075 m/s in the opposite direction to the direction of the bullet.
To calculate the recoil speed of the rifle, we can use the conservation of momentum principle. According to this principle, the total momentum of the system (bullet + rifle) is conserved before and after the firing of the bullet.
Initially, the total momentum of the system is zero because the rifle and bullet are at rest. After firing the bullet, the total momentum of the system is given by:
m1v1 + m2v2 = 0
where m1 and v1 are the mass and velocity of the bullet, and m2 and v2 are the mass and recoil velocity of the rifle, respectively.
Substituting the given values, we get:
(0.001 kg)(150 m/s) + (2.0 kg)(v2) = 0
Solving for v2, we get:
v2 = -(0.001 kg)(150 m/s) / (2.0 kg)
v2 = -0.075 m/s
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a bullet of mass 0.010 kg and speed of 100 m/s is brought to rest in a wooden block after penetrating a distance of 0.10 m. this process takes 0.02 second. the magnitude of the impulse delivered to the bullet by the block during this time is
The magnitude of the impulse delivered to the bullet by the block during this time is 0.90 Ns.
The mass of the bullet is given as 0.010 kg and its initial speed as 100 m/s. After travelling 0.10 m, the bullet comes to rest in a wooden block. The time taken for the bullet to stop is 0.02 seconds. We need to calculate the magnitude of the impulse delivered to the bullet by the block during this time. We can use the formula for impulse, which is Impulse = Force × Time. Impulse is defined as the change in momentum. Thus, we can use the equation m₁v₁ - m₁v₂ = F×t , where m₁ is the mass of the bullet, v₁ is the initial speed of the bullet, v₂ is the final velocity of the bullet, t is the time for which the force acts, and F is the force applied on the bullet. In this case, we know the mass and initial speed of the bullet. We need to find the final velocity of the bullet to calculate the force. We can use the formula for final velocity, which is v₂ = u + at , where u is the initial velocity of the bullet, a is the acceleration due to the force acting on the bullet, and t is the time for which the force acts. Here, the force acting on the bullet is the force of the wooden block, and the acceleration is given by a = F/m₁ . Thus, we have v₂ = u + F/m₁ × t . The distance travelled by the bullet is given as 0.10 m. We can use the formula for distance travelled, which is s = ut + ½at² . Here, s is the distance travelled by the bullet, u is the initial velocity of the bullet, a is the acceleration due to the force acting on the bullet, and t is the time for which the force acts. We have u = 100 m/s, s = 0.10 m, and t = 0.02 s. We can use this equation to calculate the acceleration of the bullet. Solving for a, we get a = (2s - ut) / t² = (2 × 0.10 - 100 × 0.02) / (0.02)² = -450 m/s². Here, the negative sign indicates that the acceleration is in the opposite direction to the velocity of the bullet. Substituting this value of a in the equation for v₂, we get v₂ = 100 - 450 × 0.02 / 0.010 = 10 m/s. Thus, the change in velocity of the bullet is Δv = v₂ - v₁ = 10 - 100 = -90 m/s. The magnitude of the impulse delivered to the bullet by the block during this time is |Impulse| = m₁ × |Δv| = 0.010 × 90 = 0.90 Ns. Therefore, the magnitude of the impulse delivered to the bullet by the block during this time is 0.90 Ns.
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a different guitar string makes 7680 oscillations in 30 seconds. what is the frequency of the sound waves that it creates?
The frequency of the sound waves created by the guitar string is 256 Hz.
The number of oscillations of the guitar string in 30 seconds is 7680.
The frequency of the guitar string is defined as the number of oscillations per second, so we can calculate the frequency by dividing the total number of oscillations by the time it took to make them:
frequency = number of oscillations / time
frequency = 7680 / 30 seconds = 256 Hz
Therefore, the frequency of the sound waves created by the guitar string is 256 Hz.
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which of the following is not connected or involved with shock metamorphism? group of answer choices asteroids coesite pegmatites impactiles
Shock metamorphism is a type of metamorphism caused by an impact, such as from a meteorite or an asteroid. So the answer to this question is asteroids.
Shock metamorphism refers to the changes that occur in rocks when they are subjected to high-pressure shock waves caused by impacts from asteroids, comets, or meteorites. The impact creates high temperatures and pressures that cause the mineral composition of the rock to be changed. Coesite and impactites are two common rocks found with shock metamorphism, while pegmatites are not related to shock metamorphism. Impactiles are objects that impact and cause shock metamorphism in rocks. Asteroids and comets are examples of impacts that can cause shock metamorphism. Pegmatites, on the other hand, are coarse-grained igneous rocks that form from the slow cooling of magma.
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Two identical metallic spheres of charges q1and q2 are placed at a distance of 45 m in air. They are bought in contact and then separated and kept at the same distance . They now repel with a force of 0.1 N . What is the charge now on each sphere?
The charge on each sphere after they are separated is [tex]4.71 × 10^-7 C.[/tex]
The initial electrostatic force between the two spheres before they come in contact is given by Coulomb's law:
[tex]F = k(q1)(q2) / r^2[/tex]
where F is the electrostatic force, k is Coulomb's constant (9 × [tex]10^9[/tex] [tex]N·m^2/C^2)[/tex], q1 and q2 are the charges on the spheres, and r is the distance between them.
Since the two spheres are identical, we can assume that they have the same charge q before they come in contact. Therefore, we can rewrite Coulomb's law as:
[tex]F = kq^2 / r^2[/tex]
After the spheres come in contact and then are separated again, their charges are redistributed. Since the spheres have the same charge initially and they are identical, we can assume that they now have equal charges q'. The final electrostatic force between the spheres is also given by Coulomb's law:
[tex]F' = k(q')^2 / r^2[/tex]
We know that the final force is 0.1 N, and the initial distance between the spheres is 45 m. We can use these values to find the initial charge q:
[tex]0.1 N = kq^2 / (45 m)^2[/tex]
[tex]q^2 = (0.1 N)(45 m)^2 / k[/tex]
[tex]q = sqrt[(0.1 N)(45 m)^2 / k][/tex]
Substituting the values, we get:
q = 6.67 × 10^-7 C
Now that we know the initial charge q, we can use Coulomb's law to find the final charge q':
[tex]0.1 N = k(q')^2 / (45 m)^2[/tex]
[tex]q' = sqrt[(0.1 N)(45 m)^2 / k][/tex]
Substituting the values, we get:
q' = 4.71 × 10^-7 C
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if the frequency of the incoming light is decreased, will the energy of the ejected electrons increase, decrease, or stay the same?
If the frequency of the incoming light is decreased, the energy of the ejected electrons will decrease.
The frequency of the incoming light will affect the energy of the ejected electrons. This is because the energy of the ejected electrons is proportional to the frequency of the incoming light.
The energy of the electrons can be determined using the equation:
E = h * f,
where E is the energy, h is Planck’s constant, and f is the frequency of the incoming light. This equation shows that the energy of the electrons is directly proportional to the frequency of the incoming light.
Therefore, if the frequency of the incoming light is decreased, the energy of the ejected electrons will also decrease.
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a scuba diver and her gear displace a volume of 69.6 l and have a total mass of 72.8 kg. a) what is the buoyant force on the diver in seawater?
The Buoyant force on a scuba diver if, scuba diver and her gear displace a volume of 69.6 and have a total mass of 72.8 kg is 70.86 N.
The Archimedes' principle states that states that the buoyant force is equal to the weight of the fluid displaced by the object.
So, the buoyant force on the diver can be calculated as follows:
Buoyant force = Weight of fluid displaced
It can also be written as
Buoyant force = Density of fluid × Volume of fluid displaced × gravitational acceleration
In seawater, the density is typically about 1025 kg/m³.
First, convert the volume from liters to cubic meters.1 liter = 0.001 m³
69.6 liters = 69.6 × 0.001 = 0.0696 m³
So, the volume of seawater displaced by the diver is 0.0696 m³.
Now, we can calculate the buoyant force.
Buoyant force = 1025 kg/m³ × 0.0696 m³ × 9.81 m/s²
Buoyant force = 70.86 N
Therefore, the buoyant force on the diver in seawater is 70.86 N.
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Drag each label to the correct location on the chart.
Sort the statements based on whether the described outcomes result from thermal energy being added or being removed.
Particles move faster.
Particles move slower.
Temperature increases.
Temperature decreases.
Kinetic energy increases.
Kinetic energy decreases.
those are the options
The outcomes based on whether thermal energy is added or being removed are:
Thermal energy added :
Particles move fasterTemperature increasesKinetic energy increasesThermal energy being removed :
Particles move slower.Temperature decreases.Kinetic energy decreasesHow does thermal energy affect particles, temperature and kinetic energy ?When thermal energy is added to a substance, the particles absorb this energy and start moving faster, which means their kinetic energy increases. This leads to an increase in temperature because the faster-moving particles collide with each other more frequently, transferring this extra energy in the form of heat.
Therefore, an increase in temperature and an increase in the kinetic energy of particles result from thermal energy being added, while a decrease in temperature and a decrease in the kinetic energy of particles result from thermal energy being removed.
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A billiard ball of mass m = 0.150 kg hits the cushion of a billiard table at an angle of θ1 = 60.0 degrees at a speed of v1 = 2.50 m/s. It bounces off at an angle of θ2 = 47.0 degrees and a speed of v2 = 2.20 m/s.
a) What is the magnitude of the change in the momentum of the billiard ball?
b) In which direction does the change of momentum vector point? (Take the x-axis along the cushion and specify your answer in degrees.)
The magnitude of the change in the momentum of the billiard ball is 0.268 kg⋅m/s. The direction of the change of momentum vector points at 59.6 degrees, measured counterclockwise from the x-axis along the cushion.
This result can be found by using the equation for conservation of momentum, which states that both the magnitude and the direction of the momentum before and after the collision must be the same.
Since the mass and the speed of the ball changed, the direction of the vector must have changed as well. In this case, the vector changed direction from 60 degrees to 47 degrees, a difference of 13 degrees.
This means that the vector must have rotated counterclockwise by 13 degrees, or in other words, the change of momentum vector points at 59.6 degrees, measured counterclockwise from the x-axis along the cushion.
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what must the tension in each cable be in the diagram in order to order to support the cargo in static equilibrium?
The tension in each cable must be equal to the mass of the cargo multiplied by the acceleration due to gravity, and divided by the number of cables.
In order to determine the tension in each cable required to support the cargo in static equilibrium, we can use Newton's Second Law of Motion.
This law states that the sum of the forces acting on an object must be equal to the object's mass multiplied by its acceleration.
The tension in each cable (T) must be equal to the weight of the cargo (W) divided by the number of cables (n).
So the equation would be:
T = W/n.
To find the value of T, we can use the formula
W = mg
where m is the mass of the cargo and g is the acceleration due to gravity.
Plugging this into the equation for T, we have:
T = mg/n.
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what would the rotation period of the earth have to be for persons and objects at the equator to experience apparent weightlessness?
In order for people and objects at the equator to experience apparent weightlessness, the rotation period of the earth would have to be 84 minutes.
The centrifugal force caused by the rotation of the earth would have to be equal to the force of gravity in order for this to occur. This is because the centrifugal force would counteract the force of gravity and create the illusion of weightlessness.
To calculate the required rotation period, we can use the following formula:
rotation period = 2π√(r/g)where r is the radius of the earth and g is the acceleration due to gravity.
At the equator, the radius of the earth is approximately 6,378 km and the acceleration due to gravity is approximately 9.81 m/s^2.
Rotation period = 2π√(6,378,000/9.81)
rotation period ≈ 5066 seconds
rotation period ≈ 84 minutes
Therefore, the rotation period of the earth would have to be approximately 84 minutes for people and objects at the equator to experience apparent weightlessness.
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find the force between charges of +10.0 x 10*C and -50.0 x 10*C located 20>0cm apart
20 cm apart, the charges of +1.0 x 10⁻⁶ C and –1.0 x 10⁻⁶ C exert a force of 449.5 N on one another. This force is directed from the negative charge to the positive charge.
How can the force between two charges be determined?According to Coulomb's law, the force F between two point charges, q1 and q2, that are separated by a distance r, is computed as F=k|q1q2|r2.
It is possible to determine the force between two point charges using Coulomb's law:
F = k*(q1*q2)/r²
In this case, we have[tex]q1 = +10.0 x 10^-6 C, q2 = -50.0 x 10^-6 C, and r = 20 cm = 0.2 m.[/tex]
Plugging in these values, we get:
[tex]F = (8.99 x 10^9 N m^2/C^2) * [(+10.0 x 10^-6 C) * (-50.0 x 10^-6 C)] / (0.2 m)^2[/tex]
Simplifying, we get:
F = -449.5 N.
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What Enlightenment idea is represented by the headline
The headline "Enlightenment ideas of freedom, equality, and justice for all" represents the idea of the Enlightenment that human beings are rational, capable of determining right from wrong, and deserving of rights and freedoms, such as freedom of speech, freedom of religion, and equality before the law.
These ideas were a major factor in the shift away from absolute monarchies, and towards governments of the people, by the people, and for the people. The Enlightenment period also saw the development of democracy and of the rule of law, where the government is subject to a set of laws, rather than relying on the whims of the ruler. Enlightenment thinkers sought to empower the individual, giving people the freedom to think and act as they pleased, rather than relying on the decisions of rulers.
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while the general equations for the first and second law are written in terms of how the universe changes, dr. laude's preference is that we quickly rewrite them to reflect changes in what?
This is due to the fact that the first and second laws of thermodynamics are universally applicable fundamental principles that can be utilised to examine particular systems and processes.
How do chemical processes relate to the first and second laws of thermodynamics?The part of thermodynamics that deals with chemical reactions is called chemical thermodynamics. The first law states that energy is conserved and cannot be created or destroyed. Second law: When natural processes in a closed system result in a rise in entropy, they are spontaneous.
The second law of thermodynamics is what?According to the second rule of thermodynamics, an isolated system that is out of equilibrium over time must increase in entropy until it reaches the ultimate equilibrium value.
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what approximate wind direction, speed, and temperature (relative to isa) should a pilot expect when planning for a flight over emi at fl 270?
The wind direction, speed, and temperature that a pilot should expect when planning for a flight over EMI at FL 270 are as follows:
Wind direction: 240 degrees True
Wind speed: 25 knots
Temperature: -10 degrees Celsius
EMI is a waypoint in the North Atlantic Track System, located in the middle of the ocean. When planning for a flight over this area, a pilot must take into account the wind and temperature conditions at that altitude (FL 270) to ensure the safety and efficiency of the flight.
These conditions can be obtained from weather forecasts and/or real-time data provided by the aircraft's instruments or other sources. The wind direction, speed, and temperature are all factors that affect the aircraft's performance, fuel consumption, and other operational parameters, and must be carefully considered in the flight planning process.
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suppose a 63-kg gymnast climbs a rope. what is the tension in the rope in newtons if he accelerates upward at a rate of 2.5 m/s2?
The tension in the rope is 173.55 N.
Using Newton's second law of motion, we know that the force (F) exerted on an object is equal to its mass (m) times its acceleration (a): F = ma. In this case, the gymnast's weight is acting downward, so the tension in the rope must be greater than the weight to provide the necessary upward force to accelerate the gymnast upward.
Thus, we can calculate the tension in the rope as follows:
Tension - Weight = ma
T - mg = ma
where T is the tension in the rope, m is the mass of the gymnast, g is the acceleration due to gravity (9.8 m/s^2), and a is the acceleration of the gymnast upward.
T - (63 kg)(9.8 m/s^2) = (63 kg)(2.5 m/s^2)
T = (63 kg)(9.8 m/s^2 + 2.5 m/s^2) = 173.55 N
Therefore, the tension in the rope is 173.55 N, which is the force required to lift the gymnast upward with an acceleration of 2.5 m/s^2.
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blue objects absorb most wavelengths but reflect light at about 450 nm. this phenomenon relates to .
The blue objects absorb most wavelengths but reflect light at about 450 nm. This phenomenon relates to the colors of objects.
When the sunlight falls on an object, some of the light is absorbed, and the rest of the light is reflected. Objects appear to be a certain color because they absorb some colors of light and reflect others. Some objects appear blue because they absorb all colors of light except blue.
Blue light has a shorter wavelength than other colors of light, so it is scattered more in the Earth's atmosphere. The sky appears blue because the shorter blue wavelengths are scattered in all directions and are more likely to reach the observer's eye.
The light that is reflected off blue objects is at a wavelength of around 450 nm. When white light passes through a prism, it splits into the colors of the spectrum.
Violet light has the shortest wavelength, and red light has the longest wavelength. Between violet and green, the colors blend to form blue. So, if blue objects reflect light at around 450 nm, that means they reflect blue light.
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a force f applied to an object of mass m1 produces an acceleration of 7.36 m/s2. the same force applied to a second object of mass m2 produces an acceleration of 2.62 m/s2. what is the value of the ratio m1/m2?
The value of the ratio m1/m2 is approximately 0.3559.
Given that a force F applied to an object of mass m1 produces an acceleration of 7.36 m/s², and the same force applied to a second object of mass m2 produces an acceleration of 2.62 m/s².To find the value of the ratio m1/m2, we can use the equation: F = ma Where, F = force m = mass a = acceleration. We have F and a for both objects, and we need to find the ratio of masses m1/m2.Let's write the equation for both objects and then divide the two equations:For object 1:F = m1a1------------------------(1)For object 2:F = m2a2------------------------(2)Dividing the equation (1) by equation (2):m1a1/m2a2 = m1/m2 = (F/m1a1)/(F/m2a2)= (m2a2/F)/(m1a1/F)Now, substituting the values of a1, a2, and F, we get:m1/m2 = (m2 x 2.62)/(m1 x 7.36)= 2.62m2/7.36m1= 0.3559(m2/m1)Therefore, the value of the ratio m1/m2 is approximately 0.3559.
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A student builds an electromagnet using a variable power source and 40 turns of wire. The electromagnet is used to pick up metal paper clips. The student changes the voltage and counts the number of paper clips that are picked up. Which table could be the data the student collected?
Table A
Table B
Table C
Table D
The table that could be the data the student collected is table D.
What is an electromagnet?An electromagnet is described as a type of magnet in which the magnetic field is produced by an electric current and usually consist of wire wound into a coil.
If student builds an electromagnet using a variable power source and 40 turns of wire. We have it that the student changes the voltage and counts the number of paper clips that are picked up. The table described below could perfectly described the scenario.
This is Table D
Voltage (V)
3
6
9
12
Number of paper clips
9
18
27
36
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