a hard drive rotates at 7200 rpm. the disk has a diameter of 5.1 in 13 cm. what is the speed of a point 6.0 cm. from the center axle? what is the acceleration of this point on the disk.

The traveler's weight on another planet whose radius is 3 times that of Earth and whose mass is 2 times that of Earth is 21.647 N

The following is the solution to the given problem:

Mass and gravity are related to one another. Gravity is generated by the planet's mass, and the magnitude of the gravitational force is determined by the mass of the planet on which the object is situated, as well as the mass of the object.

Mass, distance, and gravity are all factors that influence the gravitational force. Mass is directly proportional to the gravitational force and inversely proportional to the square of the distance from the gravitational force's center.

Here is the formula: Force of gravity = G(M1M2)/d²where, G is the gravitational constant 6.67 x 10^{-11} N(m/kg)^2, M1 is the mass of the first body, M2 is the mass of the second body, d is the distance between the centers of two bodies.

On earth, the traveler weighs 682 N. On another planet whose radius is 3 times that of Earth and whose mass is 2 times that of Earth, we have to calculate the traveler's weight.

Mass of Earth is 5.972 × 10^24 kg2,

Radius of Earth is 6.371 x 10^63.

The mass of the planet whose radius is 3 times that of Earth and whose mass is 2 times that of Earth.

Mass of the planet = 2 x mass of Earth = 2 x 5.972 × 10^24 kg = 1.1944 × 10^25 kg4.

The radius of the planet whose radius is 3 times that of Earth,

Radius of the planet = 3 x radius of Earth = 3 x 6.371 x 10^6 m = 1.9113 × 10^7 m5.

The distance between the two planets.

Distance between two planets = radius of planet + radius of Earth

= 1.9113 × 10^7 m + 6.371 x 10^6 m

= 2.54813 x 10^7 m

= 2.54813 x 10^10 cm.

Putting all the values in the formula.

Force of gravity = G (M1 M2) / d²

Where, Mass of the traveler on the other planet is m.

Mass of the Earth is M1 = 5.972 × 10^24 kg.

Mass of the other planet is M2 = 2 x 5.972 × 10^24 kg = 1.1944 × 10^25 kg.

Radius of the Earth is r1 = 6.371 x 10^6 m.

Radius of the other planet is r2 = 3 x 6.371 x 10^6 m = 1.9113 × 10^7 m.

Distance between the two planets is d = 2.54813 x 10^10 cm.682

= G (M1 M2)/d²

G = 6.674 × 10^-11 N m² / kg²

Force of gravity on other planet = G(mM2)/r² where m is the mass of the traveler on the other planet

= 6.674 × 10^-11 × (m × 1.1944 × 10^25)/(1.9113 × 10^7)²

Weight on another planet = force of gravity on another planet × mass of the traveler on another planet

= (6.674 × 10^-11 × (m × 1.1944 × 10^25)/(1.9113 × 10^7)²) × m

= 21.647 N (approximately)

Therefore, the traveler's weight on another planet whose radius is 3 times that of Earth and whose mass is 2 times that of Earth is 21.647 N (approximately).

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20 cm apart, the charges of +1.0 x 10⁻⁶ C and –1.0 x 10⁻⁶ C exert a force of 449.5 N on one another. This force is directed from the negative charge to the positive charge.

According to Coulomb's law, the force F between two point charges, q1 and q2, that are separated by a distance r, is computed as F=k|q1q2|r2.

It is possible to determine the force between two point charges using Coulomb's law:

F = k*(q1*q2)/r²

In this case, we have[tex]q1 = +10.0 x 10^-6 C, q2 = -50.0 x 10^-6 C, and r = 20 cm = 0.2 m.[/tex]

Plugging in these values, we get:

[tex]F = (8.99 x 10^9 N m^2/C^2) * [(+10.0 x 10^-6 C) * (-50.0 x 10^-6 C)] / (0.2 m)^2[/tex]

Simplifying, we get:

F = -449.5 N.

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The amount of the star's mass converted to energy in the explosion is 1.11 x 10^27 kg.

Calculating energy:

The mass-energy equivalence equation is used to calculate the mass that is converted to energy during a supernova explosion of a 3.2 x 10^31 kg star, producing 1.0 x 10^44 J of energy.

According to Einstein's mass-energy equivalence equation: E = mc² where, E = energy, m = mass, and c = speed of light This equation expresses the relationship between the mass of an object and the amount of energy that can be released from it.

So, to determine the mass that is converted to energy during the supernova explosion, we need to rearrange the equation as m = E/c². Now we have the following data: E = 1.0 x 10^44 Jc = 3.0 x 10^8 m/s² (speed of light). Substitute these values into the equation to get: m = E/c²m = (1.0 x 10^44 J)/(3.0 x 10^8 m/s)²m = 1.11 x 10^27 kg

Therefore, the supernova explosion of a 3.2 x 10^31 kg star converts 1.11 x 10^27 kg of its mass to energy.

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No stable interference pattern is formed on the ceiling.

Instead, you would see a simple combination of the light emitted by both bulbs, creating a uniformly lit ceiling.

The absence of an interference pattern in the scenario you described is due to the nature of the light sources and the way they emit light.

Incandescent light bulbs emit incoherent light, which means the light waves from these bulbs are not in phase with each other.
An interference pattern is created when two coherent light sources, like lasers, emit light waves that are in phase with each other.

When these light waves meet, they create a pattern of constructive and destructive interference.

Constructive interference occurs when the crests (or high points) of two light waves align, resulting in a brighter area, while destructive interference occurs when the crest of one wave aligns with the trough (or low point) of another wave, resulting in a darker area.

This alternating pattern of bright and dark areas is known as an interference pattern.
However, in your scenario with two incandescent light bulbs, the light waves emitted by each bulb are incoherent, meaning they have random phases and do not align consistently.

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The longest wavelength of the light required to cause photoelectric effect is 349 nm (in nm units).

A photoelectric effect occurs when light falls on a metal surface, causing electrons to be emitted from the metal surface. It's a phenomenon that demonstrates the particle-like nature of light, which is made up of photons, as well as the wave-like nature of light.

Einstein first proposed the idea of the photoelectric effect, which eventually helped him win the Nobel Prize in Physics in 1921.Photoelectric Effect’s Formula

The photoelectric effect's formula is as follows:

Kinetic Energy = Energy of Photon - Work Function

KE = hf - Φ

For this question, we have work function, and we will use it to find the longest wavelength.

The formula of work function is given as Φ= hf0

Where f0 is the threshold frequency (frequency of the incoming light, below which the photoelectric effect does not occur).h = Planck’s constant = 6.626 x 10^-34 J s = 4.136 x 10^-15 eV s

The longest wavelength of the light required to cause photoelectric effect is given asλ = c / f

Here, λ is the wavelength of the incoming light, c is the speed of light, and f is the frequency of the incoming light.

We have to solve the work function equation to find the threshold frequency.

The formula is given asf0 = Φ/h

Substituting the values, we get:f0 = 3.56 eV / 4.136 x 10^-15 eV s = 8.60 x 10^14 Hz

To find the longest wavelength, we use the following formula:

λmax = c / f0 = (3 x 10^8 m/s) / (8.60 x 10^14 Hz) = 3.49 x 10^-7 m = 349 nm

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Tom will strike the floor at a distance of 1.28 m from the edge of the table.

Tom the cat is chasing Jerry the mouse across a table surface that is 1.5 m high. Jerry steps out of the way at the last second, and Tom slides off the edge of the table at a speed of 5 m/s. The position of Tom at different times can be analyzed by applying the kinematic equations. Tom is in free fall and his motion is governed by the equations of motion under gravity. Therefore, his initial velocity is zero, and acceleration due to gravity is -9.8 m/s². Let’s use the second equation of motion to calculate the time required for Tom to hit the ground.
v = u + at Where, v = final velocity = 0 m/s, u = initial velocity = 5 m/s, a = acceleration = -9.8 m/s², t = time taken
Solving for t, we get
0 = 5 + (-9.8)t
t = 0.51 s
Therefore, it takes 0.51 s for Tom to hit the ground. The distance traveled by Tom before hitting the ground can be calculated using the third equation of motion.

s = ut + ½ at² Where, s = distance traveled, u = initial velocity = 5 m/s, a = acceleration = -9.8 m/s², t = time taken = 0.51 s
Solving for s, we get
s = 5 × 0.51 + ½ (-9.8) × (0.51)²
s = 1.28 m
Therefore, Tom will strike the floor at a distance of 1.28 m from the edge of the table. The motion of Tom is an example of projectile motion because he is in free fall and there is no horizontal acceleration acting on him. Projectile motion is a type of motion where an object is thrown near the earth’s surface and moves along a curved path under the action of gravity.

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The recoil speed of the rifle is 0.075 m/s in the opposite direction to the direction of the bullet.

To calculate the recoil speed of the rifle, we can use the conservation of momentum principle. According to this principle, the total momentum of the system (bullet + rifle) is conserved before and after the firing of the bullet.

Initially, the total momentum of the system is zero because the rifle and bullet are at rest. After firing the bullet, the total momentum of the system is given by:

m1v1 + m2v2 = 0

where m1 and v1 are the mass and velocity of the bullet, and m2 and v2 are the mass and recoil velocity of the rifle, respectively.

Substituting the given values, we get:

(0.001 kg)(150 m/s) + (2.0 kg)(v2) = 0

Solving for v2, we get:

v2 = -(0.001 kg)(150 m/s) / (2.0 kg)

v2 = -0.075 m/s

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The frequency of the sound waves created by the guitar string is 256 Hz.

The number of oscillations of the guitar string in 30 seconds is 7680.

The frequency of the guitar string is defined as the number of oscillations per second, so we can calculate the frequency by dividing the total number of oscillations by the time it took to make them:

frequency = number of oscillations / time

frequency = 7680 / 30 seconds = 256 Hz

Therefore, the frequency of the sound waves created by the guitar string is 256 Hz.

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A force of 245 N must be applied vertically to lift the bag off the baggage cart.

The force that must be applied vertically to lift a bag off a baggage cart, given that the bag has a mass of 25 kg, can be determined using the formula F = m*g

where F is force, m is mass, and g is acceleration due to gravity. The value of g is 9.8 m/s².So, F = 25 kg x 9.8 m/s² = 245 N. Therefore, a force of 245 N must be applied vertically to lift the bag off the baggage cart.

The mass of the bag = 25 kg.The formula used is, F = m*gwhereF = Force required to lift the bagm = Mass of the bagg = Acceleration due to gravityF = 25 kg x 9.8 m/s² = 245 N.

Therefore, a force of 245 N must be applied vertically to lift the bag off the baggage cart.

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The angle at which the ray is reflected from the first interaction with the surface of the diamond is known as the angle of reflection. When a light ray hits a surface, it reflects back at the same angle as the angle of incidence.

What is the angle of incidence?

The angle between the incident ray and the normal ray is called the angle of incidence. The incident ray is the ray of light that falls on the surface, while the normal is an imaginary line perpendicular to the surface. The angle of incidence can be calculated by measuring the angle between the incident ray and the normal.

The angle between the reflected ray and the normal ray is known as the angle of reflection. When a light ray hits a surface, it reflects back at the same angle as the angle of incidence. Therefore, the angle of reflection can be calculated by measuring the angle between the reflected ray and the normal.

In summary, the angle at which the ray is reflected from the first interaction with the surface of the diamond is the angle of reflection, which is equal to the angle of incidence. Therefore, the ray is reflected at the same angle as the angle at which it strikes the diamond's surface.

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The magnitude of the change in the momentum of the billiard ball is 0.268 kg⋅m/s. The direction of the change of momentum vector points at 59.6 degrees, measured counterclockwise from the x-axis along the cushion.

This result can be found by using the equation for conservation of momentum, which states that both the magnitude and the direction of the momentum before and after the collision must be the same.

Since the mass and the speed of the ball changed, the direction of the vector must have changed as well. In this case, the vector changed direction from 60 degrees to 47 degrees, a difference of 13 degrees.

This means that the vector must have rotated counterclockwise by 13 degrees, or in other words, the change of momentum vector points at 59.6 degrees, measured counterclockwise from the x-axis along the cushion.

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If the frequency of the incoming light is decreased, the energy of the ejected electrons will decrease.

The frequency of the incoming light will affect the energy of the ejected electrons. This is because the energy of the ejected electrons is proportional to the frequency of the incoming light.

The energy of the electrons can be determined using the equation:

E = h * f,

where E is the energy, h is Planck’s constant, and f is the frequency of the incoming light. This equation shows that the energy of the electrons is directly proportional to the frequency of the incoming light.

Therefore, if the frequency of the incoming light is decreased, the energy of the ejected electrons will also decrease.

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(a)The time-averaged energy density is:U = (1/2μ) |E x B|² = (1/2μ) E₀² B₀² sin²(kx - ωt).

(b)The intensity of an electromagnetic wave is defined as the time-averaged power per unit area. It can be calculated using the Poynting vector: I = <S> = (1/2μ) |E x B|².

S = (1/μ) E x B

where E is the electric field, B is the magnetic field, and μ is the permeability of the medium. In a conducting medium, the permeability is generally the same as that of free space, so μ = μ0.

The time-averaged energy density is then given by:

U = (1/2μ) |E x B|^2

where |E x B| is the magnitude of the cross product of the electric and magnetic fields. Since the cross product of two vectors is orthogonal to both vectors, |E x B| represents the strength of the electromagnetic field.

In a plane wave, the electric and magnetic fields are perpendicular to each other and to the direction of propagation. Without loss of generality, let's assume that the electric field is in the x-direction and the magnetic field is in the y-direction. Then we have:

E = E₀ sin(kx - ωt) i

B = B₀ sin(kx - ωt + π/2) j

where E₀ and B₀ are the amplitudes of the fields, k is the wave vector, ω is the angular frequency, and i and j are unit vectors in the x- and y-directions, respectively.

Taking the cross product of E and B, we have:

E x B = E₀ B₀ sin(kx - ωt) k

Therefore, the time-averaged energy density is:

U = (1/2μ) |E x B|² = (1/2μ) E₀² B₀² sin²(kx - ωt)

Since the sine function oscillates between -1 and 1, the maximum value of sin^2(kx - ωt) is 1. Therefore, the maximum value of the energy density is:

Umax = (1/2μ) E₀² B₀²

Note that the energy density is proportional to both the electric and magnetic field strengths. However, the permeability of a conducting medium is generally less than that of free space, which means that the magnetic field is amplified relative to the electric field. This leads to a situation where the magnetic contribution to the energy density dominates over the electric contribution.

(b) The intensity of an electromagnetic wave is defined as the time-averaged power per unit area. It can be calculated using the Poynting vector:

I = <S> = (1/2μ) |E x B|²

where the brackets denote a time average.

The energy density U is related to the intensity I by:

U = I/ω

where ω is the angular frequency. Substituting the expression for U from part (a), we have:

I/ω = (1/2μ) E₀² B₀²

Solving for I, we obtain:

I = (ω/2μ) E₀² B₀²

Recall that the speed of light in a medium is given by:

v = 1/√(με)

where ε is the permittivity of the medium. Therefore, the wave number k and the angular frequency ω are related by:

k = ω/v = ω√(με)

Substituting this expression into the expression for I, we have:

I = (k/2uw) E₀²

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In an alternating current circuit that contains a resistor, an inductor, and a capacitor with 120V, you can find the current by using Ohm's Law.

Ohm's Law states that the current is equal to the voltage divided by the resistance.

To calculate the resistance in an alternating current circuit, you must take into account the resistor, inductor, and capacitor.

For example, if the resistor has a resistance of 10 ohms, the inductor has a resistance of 5 ohms, and the capacitor has a resistance of 20 ohms, then the total resistance would be 35 ohms.

Therefore, the current in the circuit would be 120V/35 ohms = 3.43A.

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The tension in the rope is 173.55 N.

Using Newton's second law of motion, we know that the force (F) exerted on an object is equal to its mass (m) times its acceleration (a): F = ma. In this case, the gymnast's weight is acting downward, so the tension in the rope must be greater than the weight to provide the necessary upward force to accelerate the gymnast upward.

Thus, we can calculate the tension in the rope as follows:

Tension - Weight = ma

T - mg = ma

where T is the tension in the rope, m is the mass of the gymnast, g is the acceleration due to gravity (9.8 m/s^2), and a is the acceleration of the gymnast upward.

T - (63 kg)(9.8 m/s^2) = (63 kg)(2.5 m/s^2)

T = (63 kg)(9.8 m/s^2 + 2.5 m/s^2) = 173.55 N

Therefore, the tension in the rope is 173.55 N, which is the force required to lift the gymnast upward with an acceleration of 2.5 m/s^2.

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The limit on the series resistance so that the energy remaining after one hour is at least 85 percent of the initial energy, is initial energy into 85% by the voltage.

Ohm's Law states that the current in a circuit is directly proportional to the voltage and inversely proportional to the resistance.

Therefore, the total resistance in a circuit can be calculated using the formula: R = V/I

The energy remaining after one hour must be at least 85 percent of the initial energy, we can calculate the resistance by rearranging the formula.

The total resistance can be determined by multiplying the initial energy by 85 percent and dividing it by the voltage. Thus, the limit on the series resistance is [tex]R = (Initial Energy *0.85) / V[/tex].  

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A dieter lifting a 10 kg mass 1000 times to a height of 0.5m each time does 49.05 J of work per lift, resulting in the total amount of work done and fat burned is calculated by total amount of energy.

(a) The amount of work done against the gravitational force is calculated by using the formula:

W = m*g*h

where m is the mass,

g is the acceleration due to gravity, and

h is the height.

The person lifts a 10 kg mass to a height of 0.5 meters, so the work done each time is:

[tex]W = (10 kg) * (9.8 m/s^2) * (0.5 m) = 49 Joules.[/tex]

The total work done against the gravitational force is:

[tex]W_{total}= (49 J) * (1000) = 49,000 J.[/tex]

(b) To calculate the amount of fat burned, we need to find the total amount of energy expended and divide it by the efficiency rate and the energy per kilogram of fat.

The total amount of energy expended by the person is:

[tex]E_{total} = W_{total} = 49,000 J.[/tex]

The efficiency rate is 20%, which means that 20% of the expended energy is converted to mechanical energy.

The energy per kilogram of fat is [tex]3.8*10^7[/tex] Joules/kg.

Therefore, the amount of fat burned is:

Fat burned = [tex]E_{total}[/tex] / (efficiency rate * energy per kg of fat)

Fat burned = 49,000 J / (0.2 * 3.8 x 10⁷ J/kg)

Fat burned = 0.0645 kg of fat (or 64.5 grams of fat).

So, the person will burn approximately 64.5 grams of fat by lifting a 10 kg mass 1000 times to a height of 0.5 meters each time.

Also the total work done against gravitational force is 49,000J.

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Matter affects our daily lives in the sense all is composed of matter and energy.

Matter and energy in the Universe and daily life are two basic elements that characterize the physic system and allow us to understand the world. In regard to matter, it is something that occupies space and has mass, while energy can perform work.

Therefore, with this data, we can see that matter and energy in the Universe and daily life are fundamental to understanding the universe.

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This is due to the fact that the first and second laws of thermodynamics are universally applicable fundamental principles that can be utilised to examine particular systems and processes.

The part of thermodynamics that deals with chemical reactions is called chemical thermodynamics. The first law states that energy is conserved and cannot be created or destroyed. Second law: When natural processes in a closed system result in a rise in entropy, they are spontaneous.

According to the second rule of thermodynamics, an isolated system that is out of equilibrium over time must increase in entropy until it reaches the ultimate equilibrium value.

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Horses that move with the fastest linear speed on a merry-go-round are located near the outside.

A merry-go-round is an amusement park ride that comprises a rotating circular platform equipped with seats or mounts for people to ride on. When the ride is operating, the circular platform rotates around a fixed central axis at a constant velocity, while the people on it rotate with the platform. Linear speed refers to the velocity of the object in a straight line path, regardless of its direction of movement.

Therefore, the linear speed of the mounts on the merry-go-round depends on the radius of the circular path they move on. The closer the horse is to the center, the shorter the path it has to cover during one rotation of the platform, meaning it has a slower linear speed. Conversely, the farther the horse is from the center, the longer the path it has to cover, hence it has a faster linear speed. As a result, the mounts located near the outside of the merry-go-round move with the fastest linear speed.

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The drag force exerted on an object moving through air (a.k.a. force of air resistance) is proportional to the square of the velocity of the object.

Thus, the correct answer is proportional to the square of the velocity of the object.

The аir resistаnce force аcting on аn object moving through аir is referred to аs drаg force. When а body trаvels through а fluid such аs wаter or аir, it fаces resistаnce to its motion, which is proportionаl to the velocity of the object. This resistаnce force аcting on а body moving through аir is referred to аs аir resistаnce or drаg force.

The drаg force on аn object in the аir is proportionаl to the squаre of the object's velocity. When the velocity of the object is doubled, the drаg force becomes four times greаter. Thus, the drаg force grows fаster thаn the object's velocity. In other words, the drаg force аcting on аn object increаses аs the squаre of the object's velocity.

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Amplitude is not measured from peak to trough, but from rest to peak or rest to trough.

The highest and lowest points on the surface of a wave are called crests and troughs respectively. The vertical distance between the peak and the trough is the height of the waves. The horizontal distance between two successive peaks or troughs is called the wavelength.

The amplitude of a wave is the maximum displacement of a particle on a medium with respect to its position of rest.

The amplitude can be thought of as the distance between rest and the peak. The amplitude from the rest position to the dip position can be measured in a similar manner.

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The total mechanical energy and gravitational potential energy of the asteroid-sun system will change.

As the asteroid gets closer to the sun in its highly elliptical orbit, both the total mechanical energy and gravitational potential energy of the asteroid-sun system will change.

The total mechanical energy of the asteroid-sun system is the sum of its kinetic energy and gravitational potential energy. As the asteroid moves closer to the sun, its kinetic energy will increase due to the increase in speed, but its gravitational potential energy will decrease due to the decrease in distance from the sun. Therefore, the total mechanical energy of the asteroid-sun system will remain constant, according to the law of conservation of energy.

However, if the asteroid encounters any gravitational forces or other external forces, such as a collision with another object or a thrust from a spacecraft, its mechanical energy can change.

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The value of the ratio m1/m2 is approximately 0.3559.

Given that a force F applied to an object of mass m1 produces an acceleration of 7.36 m/s², and the same force applied to a second object of mass m2 produces an acceleration of 2.62 m/s².To find the value of the ratio m1/m2, we can use the equation: F = ma Where, F = force m = mass a = acceleration. We have F and a for both objects, and we need to find the ratio of masses m1/m2.Let's write the equation for both objects and then divide the two equations:For object 1:F = m1a1------------------------(1)For object 2:F = m2a2------------------------(2)Dividing the equation (1) by equation (2):m1a1/m2a2 = m1/m2 = (F/m1a1)/(F/m2a2)= (m2a2/F)/(m1a1/F)Now, substituting the values of a1, a2, and F, we get:m1/m2 = (m2 x 2.62)/(m1 x 7.36)= 2.62m2/7.36m1= 0.3559(m2/m1)Therefore, the value of the ratio m1/m2 is approximately 0.3559.

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In Young's single slit experiment, if the width of the slit decreases, the width of the diffracted peaks increases.

Young's experiment involves a single slit that diffracts light and produces a pattern of bright and dark fringes on a screen. The width of the slit affects the diffraction of light through the slit and determines the width of the bright fringes on the screen.

The narrower the slit, the greater the diffraction of light, which causes the bright fringes to become wider.

This is because diffraction causes the light waves to spread out as they pass through the narrow slit, leading to interference and the formation of bright and dark fringes on the screen.

Therefore, if the width of the slit decreases, the width of the diffracted peaks increases.

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A net force of 10 N acts on the rock when it is halfway to the top of its path.

The net force acting on the rock can be calculated using the following equation:

Fnet = ma

Where Fnet is the net force, m is the mass, and a is the acceleration.

When the rock is halfway to the top of its path, its velocity is zero since it momentarily stops at the top of its motion. As a result, its acceleration is equal to the acceleration due to gravity, which is -10 m/s² since it is acting in the opposite direction to the upward direction. This is the gravitational force acting on the rock.

We can now calculate the net force acting on the rock at this point in its motion:

Fnet = ma

Fnet = (1 kg)(-10 m/s²)

Fnet = -10 N

Since the acceleration due to gravity is acting downward and the rock is moving upward, the net force is equal to the force of gravity, which is 10 N.

Therefore, the net force that acts on the rock when it is halfway to the top of its path is -10 N or 10 N in the downward direction. This net force is equal in magnitude to the weight of the rock.

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Answer:

Explanation:

A seatbelt is designed to stretch a bit when the car decelerates rapidly. You travel forward a little while being stopped - you do not stop sharply as you would if you hit the dashboard. The seatbelt stretching increases the time over which your momentum is changed, thereby decreasing the force experienced by your body.

Airbags are made from a strong coated fabric. They are stored in a module mounted on the steering wheel and dashboard and side panels of the car. The inflation of them is initiated by crash sensors that activate upon impact at speeds of more than 10-15 miles per hour. They are mounted in several locations on the car body. In a crash, the sensor sends an electrical signal to the airbag which then causes the airbag to deploy. It ignites a chemical propellant which produces nitrogen gas, which then inflates the bag itself.

The Hubble Space Telescope offers clear and stable views of the cosmos without atmospheric distortion but has disadvantages including aging infrastructure, limited sensitivity to certain wavelengths, and difficulty with maintenance.

Advantages of Hubble Space Telescope:

The following are the disadvantages of the Hubble Space Telescope:

While the Hubble Space Telescope has revolutionized astronomy and made many groundbreaking discoveries, it also faces challenges and limitations that must be addressed as new space-based observatories are developed to continue advancing our understanding of the universe.

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Yes, it is reasonable to expect that you would see the Sun with a sensitive radio telescope.

Radio waves can penetrate through the clouds and the atmosphere, so with a powerful radio telescope you can observe the Sun even on a cloudy day.

Gather the necessary components of the radio telescope, such as a dish and receiver. Point the radio telescope towards the Sun. Tune the receiver to the proper frequency. Take a look at the results from the telescope and observe the Sun.

Therefore, you can expect that you would see the Sun with a sensitive radio telescope.

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The acceleration of the trolley is acceleration = (220 g) / m.

What is acceleration defined as, the rate of change of velocity with respect to time. As acceleration has both a magnitude and a direction, it is a vector quantity. It is also the first derivative of velocity or the second derivative of position with respect to time.

Total force = 200 g + 20 g

= 220 g

where the acceleration brought on by gravity, or g, equals (9.8 m/s²).

We may now use Newton's second law of motion, which states that an object's net force is equal to its mass times its acceleration:

Net force = total force

= 220 g

Mass of the trolley is not given in the problem. Let's assume that it is m.

m * acceleration = 220 g

Solving for acceleration, we get:

acceleration = (220 g) / m

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Question:

A trolley is being pulled by a force that is equal to the weight of two masses, one with a weight of 200 g and the other with a weight of 20 g. Sketch a free-body diagram of the trolley and calculate its acceleration assuming there is no friction or resistance acting on it. (7)

Assume that the trolley is on a flat, level surface and is not initially moving. Additionally, assume that the weight units are in grams.