A large piece of debris that only partially burns up in the atmosphere, leaving a fragment to hit the surface is called: a meteorite
When an asteroid or comet fragment encounters the Earth's atmosphere, it is called a meteor. A meteor is a visual phenomenon that occurs when a meteoroid enters the Earth's atmosphere at high speeds and burns up due to friction with the atmosphere.
As it enters the atmosphere, the meteor heats up and begins to glow, producing a streak of light across the sky. Most meteors burn up completely in the atmosphere, but occasionally, a large piece of debris may only partially burn up, leaving a fragment to hit the surface. This is what is referred to as a meteorite.
Meteorites are valuable to scientists because they provide important information about the origins and evolution of our solar system. They can also give insights into the conditions that existed on early Earth and provide clues to the formation of planets.
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torque does ignoring the mass significantly effect the value you calculate for the force exerted by the triceps? explain why or why not. triceps
When calculating the force exerted by the triceps, ignoring the mass significantly affects the torque value.
The torque is the product of the force and the distance from the force application point to the axis of rotation.
Torque= force*distance (N m)
The torque calculation for a muscle depends on the point of attachment of the muscle. Muscle mass is related to its force production capacity, and it is necessary to consider it when calculating the force applied by the triceps.
However, the force exerted by the triceps muscle would be affected by the mass of the object being lifted or moved. The force required to move an object increases with the mass of the object. Therefore, ignoring the mass of the object would result in an underestimate of the force required to move the object, and thus an underestimate of the force exerted by the triceps.
In summary, ignoring the mass of the object being lifted or moved would not significantly affect the calculated value of torque, but it would affect the calculated value of force.
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Explain why the transverse pulse traveling on a rope held by two people reflects in the opposite orientation each time it reaches a person.
Drag the terms on the left to the appropriate blanks on the right to complete the sentences. ANSWER: - greater - oppose - second law - increase - smaller - the same
- third law - first law
When a transverse wave pulse reaches a fixed end of the rope, the displacement of the rope end exerts a force on the object that is keeping the end fixed (in this case, a person). By Newton's ___ the person must exert a force of __ magnitude in ___ direction; otherwise the end of the rope would not remain stationary but would the opposite accelerate in the direction of the force due to the wave disturbance. Because this force acts to ___ the force of the incoming wave pulse, it initiates an outgoing wave pulse that is inverted with respect to the incoming wave pulse.
To complete the given sentences explaining why the transverse pulse traveling on a rope held by two people reflects in the opposite orientation each time it reaches a person order of the words used is third law, the same, oppose, increase.
When a transverse wave pulse reaches a fixed end of the rope, the displacement of the rope end exerts a force on the object that is keeping the end fixed (in this case, a person). By Newton's third law, the person must exert a force of the same magnitude in oppose direction; otherwise, the end of the rope would not remain stationary but would accelerate in the direction of the force due to the wave disturbance. Because this force acts to increase the force of the incoming wave pulse, it initiates an outgoing wave pulse that is inverted with respect to the incoming wave pulse.
When a transverse pulse traveling on a rope held by two people reaches one of the people, the pulse is reflected in the opposite orientation. This happens because of the interaction between the pulse and the person holding the rope.
By Newton's third law, the displacement of the rope end exerts a force on the person that is equal in magnitude but opposite in direction. If the person did not exert an equal and opposite force, the end of the rope would not remain stationary but would instead accelerate in the direction of the force due to the wave disturbance.
The force exerted by the person opposes the force of the incoming wave pulse, initiating an outgoing wave pulse that is inverted with respect to the incoming wave pulse. This happens due to the conservation of energy and momentum, which are described by Newton's first and second laws. The outgoing pulse has a smaller amplitude than the incoming pulse because some energy is lost in the reflection process.
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which of the following is not an example of mechanical action? group of answer choices electrically charged beaters of the bells on the clavecin electrique digital sampling machines levers and hammers inside an acoustic piano rotors (tonewheels) of a telharmonium
Digital sampling machines are not an example of mechanical action.
What is mechanical action?
Mechanical action refers to the physical movement of mechanical components to produce a sound or perform a specific function. This can include a wide range of actions, such as the striking of hammers on strings in a piano, the rotation of tonewheels in a Hammond organ, or the movement of valves in a trumpet.
Mechanical action can also be found in other types of machinery and equipment, and tools such as engines, gears, and levers, where physical movement is used to perform a specific task or function.
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how much work is done by a person lifting a 6.7-kg object from the bottom of a well at a constant speed of 2.5 m/s for 9 s? write your answer in joules.
The amount of work done by a person lifting a 6.7-kg object from the bottom of a well at a constant speed of 2.5 m/s for 9 s is 1517.25 Joules.
The work done is determined using the equation below;
W = FdW = mgd
Where,W = Work done by the person,m = mass of object = 6.7 kg,g = acceleration due to gravity = 9.8 md = distance lifted by the person = ?We know that F = m(g + a) where a is the acceleration of the object that was lifted. The object is lifted at a constant velocity and so the acceleration of the object is zero. Hence,
F = mgF = 6.7 × 9.8F = 65.66 N
We can now determine the distance d that was lifted using the equation below;
d = vt
Where,v = constant velocity = 2.5 m/s.t = time taken = 9 s
Substituting the values; d = 2.5 × 9d = 22.5 m
Now we can determine the work done;
W = FdW = 65.66 × 22.5W = 1472.85 Joules (3 decimal places)
The work done by the person lifting a 6.7-kg object from the bottom of a well at a constant speed of 2.5 m/s for 9 s is 1517.25 Joules (2 decimal places)Answer: 1517.25 Joules.
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an electric eel can generate a 278-v, 0.8-a shock for stunning its prey. what is the eel's power output?
The electric eel's power output is 222.4 Watts
Given voltage (V) = 278 V
Current (I) = 0.8 A
To find the electric eel's power output, we have to use the formula
P = IV,
Where P is the power output, I is current, and V is the voltage.
So, we can calculate the electric eel's power output as follows:
Power Output (P) = IVP
⇒278 × 0.8
Power Output (P) = 222.4 Watts
Hence, The power output of the electric eel is 222.4 Watts.
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a stone is thrown upward from ground level. the initial speed is 176 feet per second. how high will it go?
The stone thrown upward from ground level with an initial speed of 176 feet per second will reach a maximum height of: approximately 564 feet
To calculate the maximum height, we must use the equation of motion, which states that the final velocity is equal to the initial velocity plus the acceleration times the time. We know the initial velocity (176 feet per second) and the acceleration is equal to the acceleration due to gravity, which is -32 feet per second squared.
Since we do not know the time, we can solve it using the equation Vf = Vi + at. Solving for t, we get[tex]t = (Vf-Vi)/a[/tex], where Vf is 0 and Vi is 176 feet per second. Thus,[tex]t = (0-176)/(-32)[/tex], and t = 5.5 seconds.
Using the equation of motion, we can find the maximum height by using the equation [tex]H = Vi*t + (1/2)*a*t^2[/tex]. We plug in our values and get[tex]H = 176*5.5 + (1/2)*(-32)*5.5^2 = 564 feet.[/tex]
Therefore, the stone thrown upward from ground level with an initial speed of 176 feet per second will reach a maximum height of approximately 564 feet.
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what is the si unit of energy and how is it related to units of mass, distance, and time? multiple choice question. joule, 1 j
The correct option is A, the si unit of energy and how is it related to units of mass, distance, and time is joule.
The joule is a unit of measurement used to express energy or work done. It is named after the English physicist James Prescott Joule, who studied the relationship between heat and mechanical work in the mid-19th century. One joule is equal to the amount of energy needed to perform work of one newton-meter.
This means that if a force of one newton is applied over a distance of one meter, one joule of work is done. The joule is used to measure a wide variety of energies, including potential energy, kinetic energy, and thermal energy. It is also used to express the amount of work done by machines, such as engines and generators.
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Complete Question: -
What is the SI unit of energy and how is it related to units of mass, distance, and time?
a. joule
b. watt
c. kilo
d. Newton
A banjo D string is 0.69 m long and has a fundamental frequency of 294 Hz.
Part A
Determine the speed of a wave or pulse on the string.
Express your answer to two significant figures and include the appropriate units.
v =
Part B
Identify first three other frequencies at which the string can vibrate.
Enter your answers using two significant figures in order of increasing frequencies separated by commas.
f2, f3, f4 =
Answer:
Part A:
The speed of a wave on the string can be calculated using the formula:
v = fλ
where f is the frequency and λ is the wavelength. In this case, we only know the frequency of the fundamental mode, so we need to use another formula that relates the wavelength and the length of the string:
λn = 2L/n
where n is the mode number (n = 1 for the fundamental mode), and λn is the wavelength of the nth mode. Substituting this expression for λ into the first formula, we get:
v = fn × 2L/n
Substituting the given values, we get:
v = (294 Hz) × 2(0.69 m)/(1)
v = 406 m/s
Therefore, the speed of a wave or pulse on the string is 406 m/s.
Part B:
The frequencies of the other modes of vibration can be calculated using the formula:
fn = nv/2L
where n is the mode number, v is the speed of the wave on the string (which we found in Part A), and L is the length of the string. Substituting the given values, we get:
f2 = (2 × 406 m/s)/(2 × 0.69 m) = 589 Hz
f3 = (3 × 406 m/s)/(2 × 0.69 m) = 883 Hz
f4 = (4 × 406 m/s)/(2 × 0.69 m) = 1178 Hz
Therefore, the first three other frequencies at which the string can vibrate are 589 Hz, 883 Hz, and 1178 Hz.
our resistors are connected to a source of emf as shown. Rank the four resistors in order of the current through the resistor, from highest to lowest.A. the 6.00-S2 resistor B. the 8.00-S2 resistor C. the 20.0-2 resistor D. the 25.0-S2 resistor
the ranking of the resistors in terms of current, from highest to lowest, is A, B, C, D.
To rank the four resistors in order of the current through the resistor from highest to lowest, we need to consider Ohm's Law, which states that the current (I) is equal to the voltage (emf) divided by the resistance (R). Mathematically, this is represented as I = emf / R.
Assuming that all resistors are connected to the same source of emf, the resistor with the lowest resistance will have the highest current, and the resistor with the highest resistance will have the lowest current. Therefore, we can rank the resistors based on their resistance values:
1. A. the 6.00-Ω resistor
2. B. the 8.00-Ω resistor
3. C. the 20.0-Ω resistor
4. D. the 25.0-Ω resistor
So the ranking of the resistors in terms of current, from highest to lowest, is A, B, C, D.
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suppose that you are standing on a surface that is so slick that you can get no traction at all in order to begin moving across the surface. fortunately you are carrying a bag of oranges. how can you get yourself moving to the right?
You can get yourself moving to the right on a slick surface with no traction by throwing the oranges to the left.
Actions and reactionsOne possible way to get moving to the right on a slick surface with no traction is to throw the oranges to the left in a series of quick and forceful motions.
According to Newton's third law of motion, every action has an equal and opposite reaction. As you throw the oranges to the left, your body will experience a reactive force to the right, which can cause you to move in that direction.
By repeating this throwing motion with the oranges, you can continue to generate a reactive force that propels you in the desired direction.
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why do the solar system's many small bodies, such as asteroids, comets, and small moons, seem unlikely as potential homes to life?
The solar system's many small bodies, such as asteroids, comets, and small moons, are unlikely as potential homes to life due to the fact that these celestial objects have too little gravity to support an atmosphere and most have no liquid water.
This is because their small sizes and masses do not allow for enough gravitational force to retain an atmosphere, and the extreme temperatures make liquid water impossible. Additionally, many small bodies lack the necessary components needed to support life, such as organic compounds or the right amount of radiation.
Asteroids, comets, and small moons typically have a low density, which means they are composed of rocks, dust, or ice, which would not support life. Moreover, these celestial objects have highly variable rotational periods and orbits, which would result in chaotic and extremely variable temperatures, making it difficult for any life forms to survive.
These celestial objects are also very small in comparison to other bodies in the solar system, meaning they receive far less sunlight than larger bodies. This is important for life to thrive because it requires energy from the sun to grow, reproduce, and obtain nutrients. The lack of energy from the sun, combined with the lack of liquid water and a protective atmosphere, makes these small bodies unlikely candidates for supporting life.
Therefore, it is unlikely to consider the celestial objects as potential homes because of the lack of sustainable living conditions like gravity, water, oxygen, and other organic substances.
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a pen placed 13.2 cm from a concave spherical mirror produces a real image 14.0 cm from the mirror. a) what is the focal length of the mirror? answer in units of cm.
The focal length of the mirror is 8.57 cm.
The focal length is the distance between the mirror and the focal point.
For a convex lens the focal point is that point at which parallel rays will be focused after passing thru the lens.
For a convex lens, which is thicker at the center and thinner at the edges, the focal point is the point where parallel rays of light that pass through the lens converge.
When parallel rays of light pass through a convex lens, they are refracted, or bent, towards the center of the lens due to the lens's shape and refractive index.
As a result, these rays of light converge at a point on the opposite side of the lens from where the light entered, and this point is known as the focal point of the lens.
The distance between the convex lens and its focal point is called the focal length. It is usually denoted by the symbol 'f' and is an important parameter in lens design and optical systems.
The focal length of a convex lens determines how much the lens will bend or refract light and how much the light will converge at the focal point.
A lens with a shorter focal length will bend light more and converge it at a closer focal point, while a lens with a longer focal length will bend light less and converge it at a farther focal point.
The focal length of the concave spherical mirror can be calculated using the formula: 1/f = (1/p) + (1/q),
where p is the distance from the object to the mirror (13.2 cm) and q is the distance from the image to the mirror (14.0 cm).
Therefore, the focal length of the mirror is 8.57 cm.
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what is the second law of thermodynamics and why does it effect the efficiency of energy conversion?
The second law of thermodynamics states that energy spontaneously flows from high-temperature objects to low-temperature objects until the temperatures are balanced or equal.
The energy quality is reduced when energy changes from one form to another, making it difficult to transform from one form of energy to another, reducing the efficiency of energy conversion.
The second law of thermodynamics is critical to the understanding of energy conversions because it provides a quantitative measure of energy quality, which relates to the ease with which it can be used to perform work.
According to the second law of thermodynamics, the quality of energy tends to degrade over time, resulting in a reduction in efficiency when converting one form of energy to another.
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an isotonic contraction is one that involves a change in length but not a change in tension. true or false
The given statement is false. An isotonic contraction is a type of muscular contraction in which the muscle shortens while maintaining the same level of tension. This means that while the length of the muscle changes, the tension remains constant.
What are isotonic contractions?When a muscle contracts and causes a change in the length of the muscle and the muscle's tension remains constant, this is known as an isotonic contraction. The tension exerted by the muscle remains constant in isotonic contractions, but the length of the muscle changes. Isotonic contractions can be split into two types: eccentric and concentric contractions. The amount of force exerted by a muscle is determined by its ability to contract concentrically, while the ability to withstand loads while elongating is determined by its ability to contract eccentrically. Isometric contractions occur when the muscle's strength is not strong enough to overcome an opposing force. For example, pushing against a wall or attempting to lift an object that is too heavy for you. In both cases, the muscles are producing tension, but there is no movement because the opposing force is too great for the muscles to overcome. Therefore, the given statement is false.
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what is the magnitude of the force that the child exerts on the seat at the lowest point if his mass is 18.5 kg in n?
The magnitude of the force that the child exerts on the seat at the lowest point if his mass is 18.5 kg is 981 N.
To determine the magnitude of the force on the child, we must find the magnitude of the centripetal acceleration of the child at the low point first. We can use the equation:
[tex]a_{c}[/tex] = [tex]\frac{v^{2} }{r}[/tex]
where v = 9 m/s and r = 2 m
thus,
[tex]a_{c}[/tex] = [tex]\frac{9^{2} }{2}[/tex]
[tex]a_{c}[/tex] = 40.5 m/s²
And then, we find out the magnitude of the force that the child exerts on the seat at the lowest point if his mass is 18.5 kg.
∑[tex]f_{y}[/tex] = m × [tex]a_{c}[/tex]
[tex]f_{n}[/tex] - w = m × [tex]a_{c}[/tex]
[tex]f_{n}[/tex] = m × [tex]a_{c}[/tex] + w
[tex]f_{n}[/tex] = (18.5 × 40.5) + 18.5 (9.80)
[tex]f_{n}[/tex] = 981 N
Thus, the magnitude of the force that the child exerts on the seat at the lowest point if his mass is 18.5 kg in N is 981 N.
Your question is incomplete, but most probably your full question was
A mother pushes her child on a swing so that his speed is 9.00 m/s at the lowest point of his path. The swing is suspended 2.00 m above the child’s center of mass.
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a soccer player kicks a rock horizontally off a 34 m high cliff into a pool of water. if the player hears the sound of the splash 2.78 s later, what was the initial speed given to the rock (in m/s)? assume the speed of sound in air is 343 m/s.
The initial speed given to the rock was approximately 100.96 m/s.
The time it takes for the rock to fall from the cliff to the water can be found using the kinematic equation,
h = 1/2gt^2
where h is the height of the cliff (34 m), g is the acceleration due to gravity (-9.81 m/s^2), and t is the time it takes for the rock to fall. Solving for t,
t = sqrt(2h/g) = sqrt(2 * 34 / 9.81) = 2.15 s
The horizontal velocity of the rock can be found using the equation,
v = d/t
where d is the horizontal distance the rock travels (unknown) and t is the time it takes for the rock to hit the water (2.78 s). We can use the speed of sound in air (343 m/s) to find the distance d, since the time it takes for the sound of the splash to reach the player is equal to the time it takes for the rock to travel that distance plus the time it takes for the sound to travel that same distance,
2.78 s = t + d/343
Solving for d,
d = (2.78 - t) * 343 = (2.78 - 2.15) * 343 = 217.11 m
Now that we know the horizontal distance the rock travels, we can find its initial velocity using the equation,
v = d/t = 217.11/2.15 = 100.96 m/s
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if a test point is marked 5 volts and a sedond test point is marked -3.3 volts. what voltage would you expect to read between the two points if the refernece lead is on the lowest voltage
The 5-volt reading we can expect between the two test points if the reference lead is on the lowest voltage.
The given data is as follows:
The first test marked voltage = 5 volts
The second test marked voltage = -3.3 volts
Let us assume that the two test points are there is a conductive track between them, the voltage between the two points can be calculated using the voltage difference between the two test points.
The voltage difference between the two test points is calculated as:
5 volts - (-3.3 volts) = 8.3 volts
If the reference lead is on the lowest voltage, It means that the negative side of the voltmeter is attached to the test point with the lower voltage which is -3.3 volts.
The voltage difference between the two test points is
8.3 volts - 3.3 volts = 5 volts
Therefore we can conclude that the 5-volt reading we can expect between the two test points.
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As a boat moves through water, it experiences drag, which is similar to air resistance. Does drag slow the boat down or speed it up?
Answer:
Whether the object or fluid is moving, drag occurs as long as there is a difference in their velocities. Because it is resistant to motion, drag tends to slow down the object. An effective way to reduce it is to alter the shape of the object and make it streamline. Drag Force Examples of Drag Force
Explanation:
what observation can you make that allows you to determine the relative magnitudes of the forces on the upper book?
Observing the reaction of the book when placed on the table, we can determine the relative magnitudes of the forces on the upper book. If the book stays in place, then the magnitude of the normal force is equal to the gravitational force. If the book slides down, then the gravitational force is greater than the normal force, and if the book slides up, then the normal force is greater than the gravitational force.
To determine the relative magnitudes of the forces on the upper book, we can observe the reaction of the book when placed on the table. If the book stays in place and does not move, then the forces on the upper book are in balance, meaning that the magnitude of the normal force is equal to the gravitational force.
To explain further, the normal force is the force that the table exerts on the book. It opposes the force of gravity, which is the force of attraction between the book and the Earth. When the normal force is equal to the gravitational force, the book is in equilibrium, meaning that it stays in place. When the gravitational force is greater than the normal force, the book slides down, and when the normal force is greater than the gravitational force, the book slides up.
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a tiny neutrally buoyant electronic pressure probe is released into the inlet pipe of a water pump and transmits 2000 pressure readings per second as it passes through the pump. is this a lagrangian or an eulerian measurement?
A tiny neutrally buoyant electronic stress probe is launched into the inlet pipe of a water pump and transmits 2000 strain readings per second as it passes through the pump. This is a lagrangian measurement.
Lagrangian measurement is a technique used in fluid dynamics to track the motion of particles or objects within a fluid. The Lagrangian approach follows the motion of individual fluid particles, while the Eulerian approach observes the flow of fluid at fixed points in space. In Lagrangian measurement, the position, velocity, and acceleration of each particle is tracked over time.
Lagrangian measurements can provide information on the mixing and dispersion of pollutants in the environment, the transport of sediment in rivers, and the movement of microorganisms in oceans. Lagrangian measurements can be conducted using a variety of techniques, such as tracer particles, acoustic or optical sensors, and satellite imagery. These measurements have applications in a range of fields, including meteorology, oceanography, and environmental science.
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Three masses are connected by ropes over frictionless pulleys. The masses are known, m1 = 10.2 kg, m2 = 3.1 kg, and m3 = 4.8 kg. Determine the acceleration of m1 if μs = 0.38 and μk = 0.26.
Just the pull from the rope's tension acts horizontally on mass 1, functioning as the only force. In this case, T=m1*F/(m1+m2) represents the tension (again, the acceleration is the same because of the rope and the lack of friction, I think).
Is a spring used to join the two mass blocks, m1 and m2, together?The blocks with masses of 1 kg and 2 kg lie on a rough horizontal surface and are joined by a spring. It is not strained to any degree. K=2 N/m represents the spring constant. Blocks and a horizontal surface interact with each other with a 0.5 coefficient of friction.
The masses shift in such a way that the string's length between P1 and P2 is parallel to the inclined plane.
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the earth is approximately 8000 miles in diameter. i'm riding in a hot air balloon 1.5 miles above the surface of the earth. approximately how far away is the horizon?
The horizon is approximately 3,474 miles away when viewed from 1.5 miles above the surface of the Earth.
Calculation: The radius of the Earth is 4,000 miles, so the circumference of the Earth is 8,000 miles (2pir). The distance to the horizon is the circumference divided by 2pi, or 8,000 miles / 2pi = 3,474 miles.
The horizon is approximately 1.32 × √ (h) miles away, where h is the height of the observer above the surface of the Earth. Given the Earth's diameter, an observer in a hot air balloon at 1.5 miles above the surface of the Earth would be approximately 1.32 × √ (1.5) miles from the horizon.
The calculation is done as follows.1.32 × √ (1.5) miles= 1.32 × √ (1.5) miles = 1.32 × 1.22 miles= 1.61 miles So, an observer in a hot air balloon 1.5 miles above the surface of the Earth would be approximately 1.61 miles away from the horizon.
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bioelectrical impedance analysis is a commercially available method used to estimate body fat percentage. the device applies a small potential between two parts of the patient's body and measures the current that flows through. with an estimate of the resistance individually of the muscle and fat between the two points, the composition of the tissue can be estimated. assume that the muscle and fat tissue can be modeled as resistors in parallel. part a part complete if the resistance of fat is 3 times that of muscle, what is the resistance of fat if a 1 ma m a current is measured when potential difference of 0.5 v v is applied to the patient's arm?
2000 ohms is the the resistance of fat if a 1 ma m a current is measured when potential difference of 0.5 v v is applied to the patient's arm.
How to solve for the resistancewe have r = resistance of the muscle
R = fat resistance
we are given R = 3r
such that the R total would be solved using ohms law:
We would have 3r² / 4r
= 0.75r
when we use the Ohm's law we would have the follwoing calculation
0.5 = 0.001 * 0.75 r
we are to solve for the value of r
0.5 = 0.00075r
divide through by:
r = 0.5 / 0.00075
= 666.667
Remember that R = 3r
R = 3 * 666.667
R = 2000 ohms
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an observer is positioned 3 km away from a rocket launch pad. how fast is the distance between the rocket and the observer increasing, when the rocket is 4 km above the ground and is moving straight up at the speed of 300m/sec?
The distance between the rocket and the observer is increasing at a rate of about 186.6 m/s.
We can use the Pythagorean theorem to relate the distance between the rocket and the observer to the height of the rocket above the ground. Let d be the distance between the observer and the launch pad, and let h be the height of the rocket above the ground. Then,
d^2 = h^2 + 3^2 (1)
We can take the derivative of both sides of equation (1) with respect to time to get,
2d (dd/dt) = 2h (dh/dt) (2)
where (dd/dt) is the rate of change of distance between the observer and the rocket, and (dh/dt) is the rate of change of height of the rocket.
At the moment when the rocket is 4 km above the ground, h = 4 km = 4000 m, and (dh/dt) = 300 m/s.
Substituting these values into equation (2) and solving for (dd/dt),
dd/dt = (h/d) x (dh/dt) = (4000 m / √(4000^2 + 3000^2) m) x (300 m/s)
≈ 186.6 m/s
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the wavelengths for visible light rays correspond to which of these options? a. about the size of a pen b. about the size of a virus or a large molecule
The wavelengths for visible light rays correspond to about the size of a pen. Option a is correct.
Visible light consists of electromagnetic waves with wavelengths that range from approximately 400 to 700 nanometers (nm), or billionths of a meter. This corresponds to frequencies ranging from approximately 430 to 750 terahertz (THz). These wavelengths are much larger than the size of a virus or a large molecule, which typically range from a few nanometers to a few micrometers in size. In comparison, the size of a pen is typically several centimeters long, which is much larger than the wavelength of visible light. Hence, option a is correct choice.
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Answer: C.
about the size of an amoeba
Explanation: ed mentum or plato
what magnitude force is required to give a helicopter of mass m an acceleration of 0.10g upward? express your answer in terms of the variable m and appropriate constants.
Magnitude of the force required to give the helicopter an acceleration of 0.10g upward is 0.981m N, where m is the mass of the helicopter in kilograms.
What is force?Physical quantity which causes or tends to cause a motion in any object at rest or changes or tends to change the direction of motion of a moving object or shape or size of object is called force.
Force required to give a helicopter of mass m an acceleration of 0.10g upward can be calculated using Newton's second law. Here, the acceleration is 0.10g, which can be expressed as:
a = 0.10g = 0.10 * 9.81 m/s² = 0.981 m/s²
F = ma
F = m * 0.981
Therefore, magnitude of the force required to give the helicopter an acceleration of 0.10g upward is 0.981m N, where m is the mass of the helicopter in kilograms.
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once body density is determined as with hydrostatic weighing and air displacement plethysmography, percent body fat can be calculated using
Once body density is determined as with hydrostatic weighing and air displacement plethysmography, percent body fat can be calculated using the Siri equation. Body density refers to the measurement of an individual's body mass. It is the mass of an individual's body divided by the volume of their body.
It is expressed in kilograms per cubic meter in SI units. Body density can be used to calculate body fat percentage. Body fat percentage, also known as adiposity index, is the amount of body fat present in an individual's body divided by their total body mass. Body fat is essential for proper functioning of the body, but it needs to be maintained in the right amount for overall health and well-being.
Percent body fat calculation using the Siri equation Once the body density is determined, percent body fat can be calculated using the Siri equation. The Siri equation is expressed as: Percent body fat = [(4.95/Body Density) - 4.50] x 100The Siri equation is an accurate way of calculating percent body fat. It uses body density as its basis for measurement.
Body density is determined by measuring the mass and volume of the individual's body. Hydrostatic weighing and air displacement plethysmography are the two most common methods for determining body density. These methods are accurate and reliable for body density measurement.
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a mass of 500g ball is kicked at angle of 45 degree to the horizontal the ball reaches 12m height what is the initial velocity
The initial velocity of a 500g ball kicked at a 45-degree angle to the horizontal and reaching a height of 12m can be calculated using the kinematic equation.
What is the kinematic equation?The equation of kinematics is a set of equations that are used to describe the motion of objects. They relate to displacement, velocity, acceleration, and time. Kinematic equations are divided into two categories, depending on the object's acceleration: zero acceleration and non-zero acceleration.
The kinematic equation for the object in motion with uniform acceleration is as follows:v^2 = u^2 + 2asWhere: v = final velocity u = initial velocity a = acceleration s = displacement. To calculate the initial velocity of the ball, we can rearrange the equation above to obtain:u^2 = v^2 - 2as From the given, a = -9.8 m/s² (negative acceleration indicates that the ball is decelerating or moving upward) s = 12m v = 0 (the final velocity is zero because the ball has stopped rising and is about to start falling). We'll use these values to calculate the initial velocity of the ball.u² = (0)² - 2(-9.8)(12)u² = 235.2u = sqrt(235.2)u = 15.33 m/s.
Therefore, the initial velocity of the ball is approximately 15.33 m/s.
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what results when two waves, in phase and with the same wavelength, interact? what results when two waves, in phase and with the same wavelength, interact? a wave with an amplitude that is the difference between the amplitudes of the initial two waves. a wave with an amplitude that is the larger of the amplitudes of the initial two waves. a wave with an amplitude that is the multiplication of the amplitudes of the initial two waves. a wave with an amplitude that is the sum of the amplitudes of the initial two waves.
When two waves, in phase and with the same wavelength, interact, the result is a wave with an amplitude that is the sum of the amplitudes of the initial two waves.
Thus, the correct answer is a wave with an amplitude that is the sum of the amplitudes of the initial two waves (D).
What is a wave?А wаve is а disturbаnce thаt trаvels through а medium, trаnsferring energy from one point to аnother without trаnsferring the mаteriаl medium itself. Wаves cаn be of vаrious types, such аs sound wаves, electromаgnetic wаves, аnd more.
When two wаves interаct, there аre three possible results: reinforcement, interference, аnd а combinаtion of the two. When two wаves interfere with one аnother, their displаcements аdd up to form а resultаnt wаve. The crest of one wаve is in line with the crest of the other wаve, resulting in constructive interference, which results in а wаve with аn аmplitude thаt is the sum of the аmplitudes of the initiаl two wаves.
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a tow rope is being used to tow 10 skiers up a ski hill at a constant speed. the average mass of the skiers is 66.0 kg. the hill is inclined at 8.5 degrees. the power output of the motor is 4.70 kw. with what maximum speed can the skiers be towed? assume that there is negligible friction.
The average mass of the skiers is 66.0 kg. The power output of the motor is 4.70 kw. The maximum speed at which the skiers can be towed is 4.21 m/s.
Since there are 10 skiers, the total mass is:
M = 10m = 10(66.0 kg) = 660.0 kg
The force exerted by the tow rope is:
F = Mg sin([tex]\theta[/tex])
F = (660.0 kg)(9.81 m/s^2) sin(8.5 degrees)
F = 1117.9 N
Now, we can use the equation P = Fv to solve for the maximum speed at which the skiers can be towed:
v = P/F
v = (4.70 kW)/(1117.9 N)
v = 4.21 m/s
Speed is a fundamental concept in physics and is used to describe the motion of objects. It is a relative quantity and depends on the observer's frame of reference. For example, the speed of a car traveling at 60 miles per hour relative to the ground is different from the speed of the same car traveling at 0 miles per hour relative to the driver.
Speed is also related to other physical quantities such as velocity, acceleration, and momentum. Velocity is the speed of an object in a particular direction, while acceleration is the rate of change of velocity over time. Momentum is the product of an object's mass and velocity, and it determines how difficult it is to stop the object's motion.
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