A monatomic ideal gas, kept at the constant pressure 1.804E+5 Pa during a temperature change of 26.5 °C. If the volume of the gas changes by 0.00476 m3 during this process, how many mol of gas where present?

Answers

Answer 1

Approximately 0.033482 moles of gas were present during the process of the temperature change.

To find the number of moles of gas present during the process, we can use the ideal gas law:

PV = nRT

where: P is the pressure (1.804E+5 Pa),

V is the volume (0.00476 m³),

n is the number of moles,

R is the ideal gas constant (8.314 J/(mol·K)),

T is the temperature change in Kelvin.

First, we need to convert the temperature change from Celsius to Kelvin:

ΔT = 26.5 °C = 26.5 K

Rearranging the ideal gas law equation to solve for the number of moles:

n = PV / (RT)

Substituting the given values into the equation:

n = (1.804E+5 Pa × 0.00476 m³) / (8.314 J/(mol·K) × 26.5 K)

Simplifying the equation and performing the calculations:

n ≈ 0.0335 mol

Therefore, approximately 0.0335 moles of gas were present during the process.

Read more on the ideal gas law here: https://brainly.com/question/1056445

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