D O Probabilities of outcomes are shown on the branches emanating from a decision node. Question 14 The procedure for mathematically solving decision trees and determining the optimal policy and EMV is called: O sensitivity analysis O folding back (rollback) O policy iteration Orisk profiling Question 15 2 pts 2 pts Suppose a chance/event node has 3 branches. The first two have probabilities of 0.35 and 0.25 associated with them. Write down the probability associated with the third branch.

Answers

Answer 1

The procedure for solving decision trees and determining the optimal policy is called folding back. The probability associated with the third branch is 0.40.

The procedure for mathematically solving decision trees and determining the optimal policy and EMV is called: (Answer: 2) folding back (rollback).

Suppose a chance/event node has 3 branches. The first two branches have probabilities of 0.35 and 0.25 associated with them.

The probability associated with the third branch can be calculated by subtracting the sum of the probabilities of the first two branches from 1. Since the total probability must add up to 1, the probability of the third branch would be 1 - 0.35 - 0.25 = 0.40. Answer: The probability associated with the third branch is 0.40.

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