Given :
The principal = 3,700
Assume a simple interest
The account growing at a rate allowing the money to double every 6 years.
So,
[tex]\begin{gathered} I=P\cdot r\cdot t \\ I=P \\ 3700=3700\cdot r\cdot6 \\ r=\frac{1}{6} \end{gathered}[/tex]How much money would be in the account after 14 years, to the nearest dollar?
So, we will substitute with r = 1/6, t = 14 years
So,
[tex]\begin{gathered} I=3700\cdot\frac{1}{6}\cdot14=8633.33 \\ \\ A=P+I=8633.33+3700=12333.33 \end{gathered}[/tex]Rounding to the nearest dollar
So, the answer will be $12,333
Cost of a CD: $14.50Markup: 30%
Given:
Cost of a CD = $14.50
Markup =30%
If markup 30% then:
[tex]\begin{gathered} =\frac{130}{100} \\ =1.3 \end{gathered}[/tex]So the cost is:
[tex]\begin{gathered} =1.3\times14.50 \\ =18.85 \end{gathered}[/tex]markup cost is 18.85
Is there one line that passes through the point (3, 5) that is parallel to the lines represented by y = 2x - 4 and y = x - 4Explain.
If two lines are parallel, it means that they have the same slope. The given lines are
y = 2x - 4 and y = x - 4
The slope intercept form of a straight line is expressed as
y = mx + c
Where
m represents slope
c represents y intercept
By comparing both equations with the slope intercept form,
For y = 2x - 4
Slope, m = 2
For y = x - 4
Slope, m = 1
We can see that the slopes are not eaual. Thus, the lines are not parallel.
Also, we can conclude that there is no line that passes through the point (3,5) that is parallel to both lines
There is no line that passes through the point (3,5) that is parallel to both lines.
What is an equation of the line?An equation of the line is defined as a linear equation having a degree of one. The equation of the line contains two variables x and y. And the third parameter is the slope of the line which represents the elevation of the line.
The general form of the equation of the line:-
y = mx + c
m = slope
c = y-intercept
Slope = ( y₂ - y₁ ) / ( x₂ - x₁ )
If two lines are parallel, it means that they have the same slope. The given lines are
y = 2x - 4 and y = x - 4
By comparing both equations with the slope-intercept form,
For y = 2x - 4
Slope, m = 2
For y = x - 4
Slope, m = 1
We can see that the slopes are not equal. Thus, the lines are not parallel.
Also, we can conclude that there is no line that passes through the point (3,5) that is parallel to both lines.
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40. Coach Hesky bought 3 new uniforms for his basketball team. He spent a total of $486. If the same amount was spent on each uniform, how much did he spend per player? .
new uniforms = 3
Total amount spent = $486
Amount spent per player = $486 /3 = $162
I don't understand any of this (for a practice assessment)
Answer:
a. The total weight
b. 2 times the weight of Jet
c. The weight of Fido
d. The total weight
Explanation:
We know that Fido weighs 10 pounds more than Jet and together they weigh 46 pounds. So, if j represents Jet's weight, the bar model is:
Now, we can answer each part as:
a. 46 represents the total weight of the small dogs
b. 2j represents 2 times the weight of Jet
c. j + 10 represents the weight of Fido because its weight is the weight of Jet j added to 10.
d. 2j + 10 also represents the sum of the weights of the small dogs.
So, the answers are:
a. The total weight
b. 2 times the weight of Jet
c. The weight of Fido
d. The total weight
See if anybody can answer this. A concession stand sells lemonade for $2 each and sports drinks for $3 each. The concession stand sells 54 cups of lemonade and sport drinks. The total money collected for these items is $204. How much money was collected on sports drinks?
please give a VERY SHORT EXPLANATION NOT LONG! i inserted a picture of the question
If the amount of time spent is lesser than or equal to 250, so the price is $29, so we have the first part of the piecewise equation:
[tex]f(x)=29,\text{ x <= 250}[/tex]Then, for an amount of time greater than 250, the extra minutes are charged by 0.35 per minute, and this extra cost will add the fixed cost of $29, so the second part of the equation is:
[tex]f(x)=29+(x-250)0.35,\text{ x>250}[/tex]The option that shows the correct piecewise equation is option A.
Look at the circle below. D = 6 3What is the area of the circle if the diameter is 6 centimeters? Use 3.14 for pi. A 18.84 square centimetersB 28.26 square centimeters C 37.68 square centimeters D 113.04 square centimeters
we are asked to determine the area of a circle with a diameter of 6 cm. To do that we will use the following formula for the area of a circle:
[tex]A=\frac{\pi D^2}{4}[/tex]Replacing the value of the radius:
[tex]A=\frac{\pi(6\operatorname{cm})^2}{4}[/tex]Replacing the value of pi:
[tex]A=\frac{3.14(6\operatorname{cm})^2}{4}[/tex]Solving the operations:
[tex]\begin{gathered} A=\frac{3.14(36cm^2)}{4} \\ \\ A=3.14(9cm^2)=28.26cm^2 \end{gathered}[/tex]The following are the distances (in miles) to the nearest airport for 13 families.10, 13, 15, 15, 20, 26, 27, 28, 30, 32, 34, 37, 39Notice that the numbers are ordered from least to greatest.Give the five-number summary and the interquartile range for the data set.
We have the next given set for distances (in miles) to the nearest for 13airport families:
10, 13, 15, 15, 20, 26, 27, 28, 30, 32, 34, 37, 39
The minimum is the least number value. Then:
Minimum =10
In this case, we have 13 data, so :
- The middle number is the median:
10, 13, 15, 15, 20, 26, 27, 28, 30, 32, 34, 37, 39
Now, the lower quartile is given by the next equation:
[tex]=(n+1)\ast\frac{1}{4}[/tex]Replacing:
[tex]\begin{gathered} =(13+1)\ast\frac{1}{4} \\ =14\ast\frac{1}{4} \\ =3.5=4 \end{gathered}[/tex]The lower quartile is in the fourth position:
Lower quartile = 15
The upper quartile is given by the next equation:
[tex]\begin{gathered} =(n+1)\ast\frac{3}{4} \\ =(13+1)\ast\frac{3}{4} \\ =10.5=11 \end{gathered}[/tex]The upper quartile is located in the 11th position:
Upper quartile = 34
The interquartile range is given by:
IQR=upper quartile - lower quartile
IQR=34-15
The interquartile range =19
three more than the difference of five and a number
Answer:
5x+3
Step-by-step explanation:
Three more than means we add 3
The product of 5 and a number means some number multiplied by 5 call it 5x
so three more than 5x is 5x+3.
0. Taylor earned the following amount each day. One dollar on the first day Three dollars on the second day Nine dollars on the third day Twenty-seven dollars on the fourth day
Question:
Solution:
Answer:
[tex]f(t)=3^{(t-1)}[/tex]Step-by-step explanation:
one dollar of the first day = 3^0
three dollars on the second day = 3^1
nine dollars on the third day = 3^2
twenty-seven dollars on the fourth day = 3^3
Numbers increase 3 times a day, it is an exponential function, powers of 3
The function is going to be:
[tex]f(t)=3^{(t-1)}[/tex]Put these numbers in order from least to greatest. -27/36, 6, 18/40, 5/20
We have four numbers. We have to know that negative numbers are "smaller" than positive numbers, and when numbers are far away from zero are even "bigger".
The least number is -27/36. It is a negative number.
We can also see that we have some fractions. A fraction is a part of "a whole".
So, as we can see 6 is not a fraction. Therefore, 6 is the greatest number from this list.
So we have the least and the greatest: -27/36 and 6, respectively.
We also need to compare 18/40 and 5/20. What fraction is bigger?
In order to compare them, we need to have two fractions with the same denominator. Then, the fraction with the greatest numerator is "bigger" than the other fraction.
Let us see:
If we divide the numerator and the denominator of 18/40 by 2, we have:
18/2 = 9
40/2 = 20
Then, the equivalent fraction is 9/20 (or 9/20 is equivalent to 18/40). Now, we can compare them:
9/20 and 5/20. So, which one is the greatest? The one with the greatest numerator: 9/20.
Our final list is this way, from least to the greatest as follows:
-27/36, 5/20, 18/40 (9/20), 6.
How can use theorem 7-4 to find missing segments? (7-4 is similarity) :)
Given
AD = 6.4
BD = 3.6
Find
AC,BC and DC
Explanation
Using Pythogoras theorem in triangle ADC
[tex]AC^2=DC^2+6.4^2------(1)[/tex]Using PT in triangle BDC
[tex]BC^2=DC^2+3.6^2-------(2)[/tex]Adding equation (1) and (2)
[tex]\begin{gathered} AC^2+BC^2=DC^2+3.6^2+DC^2+6.4^2 \\ AC^2+BC^2=2DC^2+53.92 \end{gathered}[/tex]Using PT in triangle ABC
[tex]10^2=AC^2+BC^2[/tex]Equating above 2 equations
[tex]\begin{gathered} 100=2DC^2+53.92 \\ DC^2=23.04 \\ DC=4.8 \end{gathered}[/tex]Putting this value of DC in equation (2)
[tex]\begin{gathered} BC^2=4.8^2+3.6^2 \\ BC^2=23.04+12.96 \\ BC=6 \end{gathered}[/tex][tex]\begin{gathered} 10^2=AC^2+BC^2 \\ 100=AC^2+36 \\ AC=8 \end{gathered}[/tex]Final Answer
AC = 8
BC = 6
DC = 4.8
Write the equation of the line through the given point. Use slope-intercept form. (-5,2); perpendicular to y = - 2/3x +5
Explanation
Step 1
we have a perpendicular line, its slope is
[tex]\begin{gathered} y=\frac{-2}{3}x+5 \\ \text{slope}=\frac{-2}{3} \end{gathered}[/tex]two lines are perpendicular if
[tex]\begin{gathered} \text{slope}1\cdot\text{ slope2 =-1} \\ \text{then} \\ \text{slope}1=\frac{-1}{\text{slope 2}} \end{gathered}[/tex]replace
[tex]\text{slope1}=\frac{\frac{-1}{1}}{\frac{-2}{3}}=\frac{-3}{-2}=\frac{3}{2}[/tex]so, our slope is 3/2
Step 2
using slope=3/2 and P(-5,2) find the equation of the line
[tex]\begin{gathered} y-y_0=m(x-x_0) \\ y-2=\frac{3}{2}(x-(-5)) \\ y-2=\frac{3}{2}(x+5) \\ y-2=\frac{3}{2}x+\frac{15}{2} \\ y=\frac{3}{2}x+\frac{15}{2}+2 \\ y=\frac{3}{2}x+\frac{19}{2} \end{gathered}[/tex]Write an equation of the line that is parallel to the line y=4x+2 and y-3x=6 are parallel, perpendicular, or neither.
Given:
The point is (-2,3).
The parallel line is y=4x+2.
This is of the form
[tex]y=mx+b_1[/tex]where slope m=4.
We know that the slope of the parallel lines is equal.
Thus we get the slope m =4 for the required line.
Consider the line equaiton
[tex]y=mx+b[/tex]Substitute x= -2,y=3, and m =4 in the equation to find the value of b.
[tex]3=4(-2)+b[/tex][tex]3=-8+b[/tex]Adding 8 on both sides of the equation, we get
[tex]3+8=-8+b+8[/tex][tex]11=b[/tex]We get b=11.
Substitute m=4 and b=11 in the equation, we get
[tex]y=4x+11[/tex]Hence the line equation that passes through the point (-2,3) and parallel to y=4x+2 is
[tex]y=4x+11[/tex]NO LINKS!! Please help me with this probability question. 4a
=====================================================
Explanation:
mu = 500 = mean
sigma = 100 = standard deviation
We'll need the z score for x = 620
z = (x - mu)/sigma
z = (620-500)/100
z = 1.20
The task of finding P(x > 620) is equivalent to P(z > 1.20)
Use a Z table or a Z calculator to find that
P(Z < 1.20) = 0.88493
which leads to
P(Z > 1.20) = 1 - P(Z < 1.20)
P(Z > 1.20) = 1 - 0.88493
P(Z > 1.20) = 0.11507
This converts to 11.507% and rounds to 11.5%
About 11.5% of the students score higher than a 620 on the SAT.
-------------------------
Another approach:
Open your favorite spreadsheet program. The command we'll be using is called NORMDIST. The template is this
NORMDIST(x, mu, sigma, 1)
x = 620 = critical valuemu = 500 = meansigma = 100 = standard deviationThe 1 at the end tells the spreadsheet to use a CDF instead of PDF. Use 0 if you want a PDF value.If you were to type in [tex]\text{=NORMDIST(620,500,100,1)}[/tex] then you'll get the area under the normal distribution to the left of x = 620
This means [tex]\text{=1-NORMDIST(620,500,100,1)}[/tex] will get us the area to the right of 620. The result of that calculation is approximately 0.11507 which leads to the same answer of 11.5% as found earlier.
When using a spreadsheet, don't forget about the equal sign up front. Otherwise, the spreadsheet will treat the input as text and won't evaluate the command.
-------------------------
Another option is to use a TI83 or TI84 calculator.
Press the button labeled "2nd" in the top left corner. Then press the VARS key. Scroll down to "normalcdf"
The template is
normalcdf(L, U, mu, sigma)
L = lower boundaryU = upper boundarymu = mean sigma = standard deviationThe mu and sigma values aren't anything new here. But the L and U are. In this case L = 620 is the lower boundary and technically there isn't an upper boundary since it's infinity. Unfortunately the calculator wants a number here, so we just pick something very large. You could go for U = 99999 as the stand in for "infinity". The key is to make sure it's more than 3 standard deviations away from the mean.
So if you were to type in [tex]\text{normalcdf(620,99999,500,100)}[/tex] then the calculator will display roughly 0.11507, which is in line with the other answers mentioned earlier.
As you can see, there are many options to pick from. Searching out "normal distribution calculator" or "z calculator" will yield many free options. Feel free to pick your favorite.
Mr. Edmonds is packing school lunches for a field trip for the 6th graders of Apollo Middle school. He has 50 apples and 40 bananas chips. Each group of students will be given one bag containing all of their lunches for the day. Mr. Edmonds wants to put the same number of apples and the same number of bananas in each bag of lunches. What is the greatest number of bags of lunches Mr. Edmonds can make? How many apples and bananas will be in each bag?
The greatest number of bags of lunches Mr. Edmonds can make = 40, And , in each bag there will be one apple and one banana chips bag.
In the above question, the following information is given :
Mr. Edmonds wants to pack lunches for the schools field trip where he wants to put the same number of apples and the same number of bananas in each bag of lunches
We are given that,
Number of available bananas chips packs = 40
Number of available apples = 50
We need to find the greatest number of bags of lunches Mr. Edmonds can make
As the pair should be an even number and we have less number of banana chips bags than apples. So the number of lunches which can be packed with equal number of apples and banana chips bags depend on banana chips bags
Therefore, the greatest number of bags of lunches Mr. Edmonds can make = 40
And , in each bag there will be one apple and one banana chips bag.
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Consider the following when d = 14 ft. Give both exact values and approximations to the nearest hundredth.(a) Find the circumference of the figure.ftftx(b) Find the area of the figure.ft?x7A²teh
(a)Recall that the circumference of a circle is given by the following formula:
[tex]C=\pi d.[/tex]Where d is the diameter of the circle.
Substituting d=14 ft in the above formula, we get:
[tex]C=\pi(14ft)\approx43.98ft\text{.}[/tex](b) Recall that the area of a circle is given by the following formula:
[tex]A=\frac{\pi d^2}{4}.[/tex]Substituting d=14 ft in the above formula, we get:
[tex]A=\frac{\pi(14ft)^2}{4}=49\pi ft^2\approx153.94ft^2.[/tex]Answer:
(a)
Exact solution:
[tex]14\pi ft.^{}[/tex]Approximation:
[tex]43.98\text{ ft.}[/tex](b) Exact solution:
[tex]49\pi ft^2\text{.}[/tex]Approximation:
[tex]153.94ft^2.[/tex]In physics, the Ideal Gas Law describes the relationship among the pressure, volume, and temperature of a gas sample. This law is represented by the formula PV = nRT, where P is the pressure, V is the volume, T is the temperature, n is the amount of gas, and R is a physical constant. Select all the equations that are equivalent to the formula PV = nRT.
The equations that are equivalent to the formula PV = nRT are V = nRT/P, n = PV/RT and R = PVnT. Option B, C and D
How to determine the equationsFrom the information given, we have that;
The Ideal Gas law is represented as;
PV = nRT
Given that;
P is the pressure V is the volumeT is the temperaturen is the amount of gasR is a physical constantSubject of formula is described as the variable expressed in terms of other variables in an equation.
It is made to stand on its own on one end of the equality sign.
Let's make 'V' the subject of formula
Divide both sides by the coefficient of V which is the variable 'P', we have;
V = nRT/P
Making 'R' the subject of formula, we have
R = PV/ nT
Making 'n' the subject of formula, we have;
n = PV/RT
Hence, the equations are options B, C and D
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The complete question:
In physics, the Ideal Gas Law describes the relationship among the pressure, volume, and temperature of a gas sample. This law is represented by the formula PV = nRT, where P is the pressure, V is the volume, T is the temperature, n is the amount of gas, and R is a physical constant. Which of the equations below are equivalent to the formula PV = nRT? Select all that apply. A. P = VnRT B. V = nRT/P C. n = PV/RT D. R = PVnT E. T = nR/PV
Answer:Pv=NRT
Step-by-step explanation:
answer this, please?
Sidney made root beer floats for her friends when they came over. The table shows the ratio of cups of ice cream to cups of soda used to make the floats.
Ice Cream (cups) Soda (cups)
3.5 10.5
8 24
12.5 37.5
19 ?
At this rate, how much soda will Sidney use for 19 cups of ice cream?
30 cups
38 cups
57 cups
72 cups
Sidney will use 57 cups of soda for 19 cups of ice cream.
What is a ratio?The ratio shows how many times one value is contained in another value.
Example:
There are 3 apples and 2 oranges in a basket.
The ratio of apples to oranges is 3:2 or 3/2.
We have,
From the table,
The ratio of cups of ice cream to cups of soda.
3.5 cups ice cream = 10.5 cups of soda
Divide both sides by 3.5.
1 cup of ice cream = 3 cups of soda
Multiply 19 on both sides.
19 cup of ice cream = 57 cups of soda
Thus,
57 cups of soda.
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Find the area of the triangle below.9 cm6 cm2 cm
We recall that the area of a triangle is defined by the product of the triangle's base times its height divided by 2.
So we notice that in our image, we know the height (6 cm), and we also know the base of the triangle (2 cm)
Therefore the triangles are is easily estimated via the formula:
[tex]\text{Area}=\frac{base\cdot height}{2}=\frac{2\cdot6}{2}=6\, \, cm^2[/tex]Then the area is 6 square cm.
y = -2x + 5a. What is the slope? b. What is the vertical intercept? c. What is the horizontal intercept? d. Graph the equation
Given: The equation below
[tex]y=-2x+5[/tex]To Determine: The slope, the vertical and horizontal intercept, and the graph of the equation
Solution
The general slope-intercept form of a straight line is as shown below
[tex]\begin{gathered} y=mx+c \\ Where \\ m=slope \\ c=vertical-intercept \end{gathered}[/tex]Let us compare the general slope-intercept form of a straight line to the given
[tex]\begin{gathered} y=mx+c \\ y=-2x+5 \\ slope=m=-2 \end{gathered}[/tex]The vertical intercept is the point where the x values is zero
[tex]\begin{gathered} y=-2x+5 \\ x=0 \\ y=-2(0)+5 \\ y=0+5 \\ y=5 \end{gathered}[/tex]The vertical intercept is y = 5, with coordinate (0, 5)
The horizontal intercept is the point where the y value is zero
[tex]\begin{gathered} y=-2x+5 \\ y=0 \\ 0=-2x+5 \\ 2x=5 \\ x=\frac{5}{2} \end{gathered}[/tex]The horizontal intercept is x = 5/2, with coordinate (5/2, 0)
The graph of the equation is as shown below
Answer Summary
(a) slope = -2
(b) Vertical intercept, y = 5
(c) Horizontal intercept, x = 5/2
Select all rational numbers
help ASAP please
15 points
The resulting rational number is √100
Rational numbers:
A rational number is a number that can be represented a/b where a and b are integers and b is not equal to 0.
Given,
Here we have the following list of numbers
√75, -√25, 2√7, √100, √0.36, √0.0144, √3/7 , -√36/49
Now, we need to identify whether these are the rational numbers or not.
AS per the definition of rational number,
When we take the root for the value √75, we get 8.660 that is a non-whole square root, 8.660 is not a rational number.
The value -√25 takes the negative value so it is not a rational number.
The number 2√7, this one also produce on-whole square root, so this one is not a rational number.
The value of √100 is 10, and it is a rational number.
The value of √0.36 is 0.6 which is less than 0, so it is not a rational number.
The value of √0.0144 is 0.012 which is less than 0, so it is not a rational number.
The value of √3/7 this one also produce on-whole square root, so this one is not a rational number.
The value -√36/49 takes the negative value so it is not a rational number.
Therefore, the rational number is √100.
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Given the following absolute value function sketch the graph of the function and find the domain and range.
ƒ(x) = |x + 3| - 1
pls show how did u solve it
In order to sketch the graph we need to find the vertex and two more points to connect with the vertex.
To do so set the inside of absolute value to zero:
x + 3 = 0x = - 3The y-coordinate of same is:
f(-3) = 0 - 1 = - 1.So the vertex is (- 3, - 1).
Since the coefficient of the absolute value is positive, the graph opens up, and the vertex is below the x-axis as we found above.
Find the x-intercepts by setting the function equal to zero:
|x + 3| - 1 = 0x + 3 - 1 = 0 or - x - 3 - 1 = 0x + 2 = 0 or - x - 4 = 0x = - 2 or x = - 4We have two x-intercepts (-4, 0) and (-2, 0).
Now plot all three points and connect the vertex with both x-intercepts.
Now, from the graph we see there is no domain restrictions but the range is restricted to y-coordinate of the vertex.
It can be shown as:
Domain: x ∈ ( - ∞, + ∞),Range: y ∈ [ - 1, + ∞)Answer:
Vertex = (-3, -1).y-intercept = (0, 2).x-intercepts = (-2, 0) and (-4, 0).Domain = (-∞, ∞).Range = [-1, ∞).Step-by-step explanation:
Given absolute value function:
[tex]f(x)=|x+3|-1[/tex]
The parent function of the given function is:
[tex]f(x)=|x|[/tex]
Graph of the parent absolute function:
Line |y| = -x where x ≤ 0Line |y| = x where x ≥ 0Vertex at (0, 0)Translations
[tex]f(x+a) \implies f(x) \: \textsf{translated $a$ units left}.[/tex]
[tex]f(x-a) \implies f(x) \: \textsf{translated $a$ units right}.[/tex]
[tex]f(x)+a \implies f(x) \: \textsf{translated $a$ units up}.[/tex]
[tex]f(x)-a \implies f(x) \: \textsf{translated $a$ units down}.[/tex]
Therefore, the given function is the parent function translated 3 units left and 1 unit down.
If the vertex of the parent function is (0, 0) then the vertex of the given function is:
⇒ Vertex = (0 - 3, 0 - 1) = (-3, -1)
To find the y-intercept, substitute x = 0 into the given function:
[tex]\implies \textsf{$y$-intercept}=|0+3|-1=2[/tex]
To find the x-intercepts, set the function to zero and solve for x:
[tex]\implies |x+3|-1=0[/tex]
[tex]\implies |x+3|=1[/tex]
Therefore:
[tex]\implies x+3=1 \implies x=-2[/tex]
[tex]\implies x+3=-1 \implies x=-4[/tex]
Therefore, the x-intercepts are (-2, 0) and (-4, 0).
To sketch the graph:
Plot the found vertex, y-intercept and x-intercepts.Draw a straight line from the vertex through (-2, 0) and the y-intercept.Draw a straight line from the vertex through (-4, 0).Ensure the graph is symmetrical about x = -3.Note: When sketching a graph, be sure to label all points where the line crosses the axes.
The domain of a function is the set of all possible input values (x-values).
The domain of the given function is unrestricted and therefore (-∞, ∞).
The range of a function is the set of all possible output values (y-values).
The minimum of the function is the y-value of the vertex: y = -1.
Therefore, the range of the given function is: [-1, ∞).
two parallel lines are intersected by a transversal one angle is 100 degrees, more info on the picture
Obtuse angles (90°–180°) are those that fall within this range. Right angles are those that have a 90 degree angle ( = 90°). Straight angles are those that have a 180 degree ( = 180°) angle.
Explain about the obtuse angle?Any angle more than 90 degrees is deemed obtuse: A straight angle is one with a 180° measurement. A zero angle is one with a measurement of 0°: Angles with measures that add up to 90 degrees are said to be complementary angles: Angles with measures that add up to 180° are referred to as supplementary angles.
We now understand that an obtuse angle is one that is greater than 90 degrees but less than 180 degrees. Obtuse angle examples include 110°, 135°, 150°, 179°, 91°, and more. As a result, all angles between 90° and 180° are obtuse angles.
Hence obtuse angle is one of the angle which is not correct 100 degree angle
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Which of the following shows a graph of a tangent function in the form y = atan(bx − c) + d, such that b equals one fourth question mark
ANSWER :
EXPLANATION :
Given the triangle ABC with the points A = ( 4, 6 ) B = ( 2, 8 ) C = ( 5, 10 ) and it's dilation, triangle A'B'C', with points A' = ( 2, 3 ) B' = ( 1, 4 ) C' = ( 2.5, 5 ) what is the scale factor?
Answer:
Explanation:
Given A = (4, 6) B = (2, 8) C = (5, 10)
[tex]\begin{gathered} AB=\sqrt{(2-4)^2+(8-6)^2} \\ \\ =\sqrt{8} \\ \\ BC=\sqrt{(5-2)^2+(10-8)^2} \\ \\ =\sqrt{8} \end{gathered}[/tex]SImilarly, for A' = (2, 3) B' = (1, 4) C' = (2.5, 5)
[tex]\begin{gathered} A^{\prime}B^{\prime}=\sqrt{(1-2)^2+(4-3)^2} \\ \\ =\sqrt{2} \\ \\ B^{\prime}C^{\prime}=\sqrt{(2.5-1)^2+(5-4)^2} \\ \\ =\sqrt{3.25} \end{gathered}[/tex]
Since it is a dilation, AB/A'B' should be the same as BC/B'C', but that is not the case here.
Write the the function f(x) = -5(x + 5)² - 2 in the form f(x) = ax² +bx+c
start expanding the squared expression using the square of a binomial,
[tex](a+b)^2=a^2+2\ast a\ast b+b^2[/tex]then,
[tex]\begin{gathered} (x+5)^2=x^2+2\ast5\ast x+5^2 \\ (x+5)^2=x^2+10x+25 \end{gathered}[/tex]replace in the original function
[tex]-5(x^2+10x+25)-2[/tex]apply distributive and simplify
[tex]\begin{gathered} -5x^2-50x-125-2 \\ -5x^2-50x-127 \end{gathered}[/tex]Answer:
[tex]-5x^2-50x-127[/tex]The amounts of money three students earn at their jobs over time are given in the tablesStudent ETime (hr) Amount Earned2$15.005$37.508$60.00Student FTime (hr) Amount Earned3$27.006$54.0010$90.00Student GTime (hr) Amount Earned1$8.504$34.007S59.50According to the tables, which statement is true?Student E cams the most amount of money per hourStudent E cars more money per hour than studentStudent Goarns the least amount of money per hourStudent G earns less money per hour than student F
the answer is:
Student G earns less money per hour than student F
write an equation that gives the proportinal relationship of the graph
Answer:
y=5x
Explanation:
The slope-intercept form of the equation of a line is:
[tex]y=mx+b\text{ where }\begin{cases}m=\text{slope} \\ b=y-\text{intercept}\end{cases}[/tex]First, we find the slope of the line by picking two points from the line.
• The points are (0,0) and (3,15).
[tex]\begin{gathered} \text{Slope},m=\frac{Change\text{ in y-axis}}{Change\text{ in x-axis}}=\frac{15-0}{3-0}=\frac{15}{3} \\ \implies m=5 \end{gathered}[/tex]Next, the line crosses the y-axis at y=0.
Therefore, the y-intercept, b=0.
Substitute m=5 and b=0 into the slope-intercept form:
[tex]\begin{gathered} y=5x+0 \\ \implies y=5x \end{gathered}[/tex]The equation that gives the proportional relationship of the graph is y=5x.
what is the slope of the line which goes through the points (-2, -9) and (2, 11) the slope of the line is___
We know the equation of a line is given by:
[tex]y=mx+b[/tex]where m is its slope and b its interpcetion with y - axis.
We know the slope equation is
[tex]\begin{gathered} m=\frac{\Delta y}{\Delta x} \\ =\frac{y_2-y_1}{x_2-x_1} \end{gathered}[/tex]If (x₁, y₁) = (-2, -9) and (x₂, y₂) = (2, 11) then replacing in the slope equation
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ =\frac{11-(-9)}{2-(-2)} \\ =\frac{11+9}{2+2} \\ =\frac{20}{4}=5 \end{gathered}[/tex]Answer: the slope of the line is 5