a person trying to lose weight (dieter) lifts a 10 kg mass, one thousand times, to a height of 0.5 m each time. assume that the potential energy lost each time she lowers the mass is dissipated, (a) how much work does she do against the gravitational force? (b) fat supplies 3.8 x 107j of energy per kilogram which is converted to mechanical energy with a 20% efficiency rate. how much fat will the dieter use up?

Answers

Answer 1

A dieter lifting a 10 kg mass 1000 times to a height of 0.5m each time does 49.05 J of work per lift, resulting in the total amount of work done and fat burned is calculated by total amount of energy.

(a) The amount of work done against the gravitational force is calculated by using the formula:

W = m*g*h

where m is the mass,

g is the acceleration due to gravity, and

h is the height.

The person lifts a 10 kg mass to a height of 0.5 meters, so the work done each time is:

[tex]W = (10 kg) * (9.8 m/s^2) * (0.5 m) = 49 Joules.[/tex]

The total work done against the gravitational force is:

[tex]W_{total}= (49 J) * (1000) = 49,000 J.[/tex]

(b) To calculate the amount of fat burned, we need to find the total amount of energy expended and divide it by the efficiency rate and the energy per kilogram of fat.

The total amount of energy expended by the person is:

[tex]E_{total} = W_{total} = 49,000 J.[/tex]

The efficiency rate is 20%, which means that 20% of the expended energy is converted to mechanical energy.

The energy per kilogram of fat is [tex]3.8*10^7[/tex] Joules/kg.

Therefore, the amount of fat burned is:

Fat burned = [tex]E_{total}[/tex] / (efficiency rate * energy per kg of fat)

Fat burned = 49,000 J / (0.2 * 3.8 x 10⁷ J/kg)

Fat burned = 0.0645 kg of fat (or 64.5 grams of fat).

So, the person will burn approximately 64.5 grams of fat by lifting a 10 kg mass 1000 times to a height of 0.5 meters each time.

Also the total work done against gravitational force is 49,000J.

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Related Questions

what is the kinetic energy, in joules, of each ejected electron when light of 258.0 nm strikes the metal surface?

Answers

When the light of 258.0 nm strikes the metal surface, each ejected electron has a kinetic energy of 4.80 eV.


To calculate the kinetic energy, we use the formula:

Kinetic Energy (KE) = hc/λ, where h is Planck's constant (6.626×10⁻³⁴ Js), c is the speed of light (2.998x10⁸ m/s) and λ is the wavelength of the light (258.0 nm).



Therefore,

KE = (6.626x10⁻³⁴ Js)(2.998x10⁸ m/s) / (2.58x10^-7 m)


= 7.69x10⁻¹⁹ J = 4.80eV, where (1eV = 1.6 x 10⁻¹⁹ J)


Thus, each ejected electron has a kinetic energy of 4.80 eV or 7.69x10⁻¹⁹ J when the light of 258.0 nm strikes the metal surface.

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the reason distance has a greater effect on the force of gravity between our earth and moon is because the distance between them is

Answers

The reason distance has a greater effect on the force of gravity between our Earth and Moon is because the distance between them is relatively large.

The reason distance has a greater effect on the force of gravity between the Earth and the Moon is because the force of gravity between two objects decreases with the square of the distance between them. This is known as the inverse square law of gravity.

The force of gravity between two objects is proportional to the product of their masses, and inversely proportional to the square of the distance between them. Mathematically, it can be expressed as,

F = G * (m1 * m2) / r^2

where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them.

In the case of the Earth and the Moon, their masses are fixed, so the only variable that affects the force of gravity between them is the distance. As the distance between the Earth and the Moon increases, the force of gravity between them decreases rapidly, according to the inverse square law.

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--The complete question is, Fill in the blank, the reason distance has a greater effect on the force of gravity between our earth and moon is because the distance between them is ________________.--

Which traits are controlled by polygenic inheritance? Select four options.
red hair
hazel eyes
blood type
length of corn ears
birth weight
fur color of palomino horses

Answers

Answer:

All options except fur color of palomino horses and blood type

Answer:

A, B, D, and E

Explanation:

the words on the pages of a textbook and the wave of a hand your friend makes when she sees you on the street are both examples of .

Answers

The words on the pages of a textbook and the wave of a hand your friend makes when she sees you on the street are both examples of physical phenomena.

The words on the pages of a textbook and the wave of a hand your friend makes when she sees you on the street are both examples of physical phenomena. Physical phenomena are observable events or occurrences that can be described using the scientific method. These phenomena can be observed using our senses, such as sight, touch, sound, taste, and smell, or measured using instruments, such as thermometers, scales, or cameras. For example, the wave of a hand is a physical phenomenon because it is an observable event that can be seen and measured. Similarly, the words on the pages of a textbook are physical phenomena because they are observable and can be seen and read.

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discuss the shape of the voltage and current waveforms. which appears more sinusoidal and why would you expect it to be that way?

Answers

The voltage waveform is more sinusoidal than the current waveform.

This is because the voltage source is assumed to be an ideal source, which means that the voltage is supplied without loss or fluctuation while the current waveform is distorted due to the loads present in the circuit. When a voltage waveform is applied to a circuit with inductance and capacitance, the resulting current waveform will be distorted and will not be sinusoidal. The current waveform is affected by the presence of capacitance and inductance in the circuit, which cause the current to lag behind the voltage. The current waveform becomes more distorted as the load resistance increases.

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the potential difference between the head and the tail of a displacement vector that points at right angles to a uniform electric field is:

Answers

The potential difference between the head and the tail of a displacement vector that points at right angles to a uniform electric field is zero (0).

A uniform electric field refers to the electric field having the same magnitude and direction at all points in space. A uniform electric field is created by two parallel plates that have the same charge density and are close enough to each other that the edges can be ignored. The electric field strength of a uniform electric field is constant, which means that the direction and magnitude are the same at all points in space.

The potential difference between the head and tail of a displacement vector that points at right angles to a uniform electric field is zero (0). It is because the potential difference between two points is equal to the negative of the work done per unit charge in moving a positive test charge from one point to another point. When a displacement vector that points at right angles to a uniform electric field is moved from one point to another, no work is done because the electric field and displacement vector are perpendicular. As a result, the potential difference is zero.

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How long it took for the Moon to revolve once around Earth and how long it took for the Moon to rotate once on its axis?

Answers

The time it takes for the Moon to revolve once around Earth and to rotate once on its axis is known as its period of rotation and revolution, respectively. The time it takes for the Moon to complete one revolution around Earth is approximately 27.3 days or 27 days, 7 hours, and 43 minutes. This period is known as the lunar month or synodic month. During this time, the Moon moves through its phases, from new moon to full moon and back to new moon again.

On the other hand, the time it takes for the Moon to rotate once on its axis is approximately 27.3 days. This means that the Moon takes the same amount of time to rotate on its axis as it does to revolve around Earth. As a result, the same side of the Moon always faces Earth, which is why we only see one side of the Moon from Earth.
It's worth noting that the Moon's period of rotation and revolution are almost the same, which is a rare occurrence in the solar system. This is due to the gravitational influence of Earth, which has caused the Moon to become tidally locked with Earth. This means that the Moon's rotation and revolution are in sync with Earth, resulting in the same side of the Moon always facing Earth.

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The formula for speed is Total Distance / Total Time. Based on the data table below, what is the
average speed after 2 minutes? Please show all calculations.
Time (min.) Distance (m)
0
1
2
3
0
50
75
90

Answers

Answer:

To find the average speed after 2 minutes, we need to calculate the total distance covered in 2 minutes and divide it by 2.

Total Distance after 2 minutes = 75m

Total Time after 2 minutes = 2 minutes

Average Speed after 2 minutes = Total Distance / Total Time

Average Speed after 2 minutes = 75m / 2 min = 37.5 m/min

Therefore, the average speed after 2 minutes is 37.5 m/min.

I Hope This Helps!

calculate the magnitude of the magnetic field at a point 58.0 cm from a long, thin conductor carrying a current of 4.70 a.

Answers

The magnitude of the magnetic field at a point 58.0 cm from a long, thin conductor carrying a current of 4.70a is: 40.6 T

To calculate the magnitude of the magnetic field at a point 58.0 cm away from a long, thin conductor carrying a current of 4.70 A, we can use the equation B = μ_0*I/(2*pi*r).

[tex]B = 4πx10^-7*4.70/(2*pi*0.58) = 40.6 T.[/tex]

Here, μ_0 is the permeability of free space (4πx10^-7 Tm/A), I is the current (4.70 A), and r is the distance from the conductor (58.0 cm). So, the magnitude of the magnetic field at the point is [tex]B = 4πx10^-7*4.70/(2*pi*0.58) = 40.6 T.[/tex]


To understand why the magnetic field is present, we must look at the conductor carrying a current. When electric current passes through a conductor, it creates a magnetic field around it. This magnetic field is inversely proportional to the distance from the conductor, meaning the closer you get to it, the stronger the magnetic field will be.

Since the conductor in this example has a current of 4.70 A, the magnetic field it creates will be stronger than a conductor with a lower current.


To conclude, the magnitude of the magnetic field at a point 58.0 cm away from a long, thin conductor carrying a current of 4.70 A is 40.6 T. The presence of this magnetic field is due to the electric current passing through the conductor, and it is inversely proportional to the distance from the conductor.

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A wheel of radius R starts from rest and accelerates with a constant angular acceleration α about a fixed axis.
At what time t will the centripetal and tangential accelerations of a point on the rim have the same magnitude?
Express your answer in terms of the given quantities.

Answers

The time at which the centripetal and tangential accelerations of a point on the rim have the same magnitude is given by t = √(R/α).

Steps

A tangential = R, where R is the wheel's radius and is the angular acceleration, gives the tangential acceleration of a point on the rim of the wheel.

A centripetal =  v²/R, where v is the speed of the point, gives the centripetal acceleration of a point on the rim of the wheel.

At time t, the wheel's angular displacement is given by  = (1/2)t2, and the speed of the point on the rim is given by v = R, where is the wheel's angular velocity.

Setting the magnitudes of the tangential and centripetal accelerations equal, we have:

Rα = v²/R

Substituting v = Rω and simplifying, we get:

Rα = Rω²

α = ω²

Using the definition of angular velocity ω = αt, we get:

t = √(R/α)

Therefore, the time at which the centripetal and tangential accelerations of a point on the rim have the same magnitude is given by t = √(R/α).

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if two flutists play their instruments together at the same intensity, is the sound twice as loud as that of either flutist playing alone at that intensity? why or why not?

Answers

No, the sound wouldn't be twice as loud as that of either flutist playing alone at that intensity. The increase in sound intensity would be less than twice as loud.

This is because when two sound waves coincide, the amplitude of the resulting sound wave is the sum of the amplitudes of the individual sound waves. That is, when two identical sound waves come together, they create a new sound wave that is slightly louder than the original sound wave, but not twice as loud.

Furthermore, sound intensity is affected by the distance from the sound source, and when two flutists are playing together, the sound waves produced have to travel further before they reach the listener, thus reducing the intensity of the sound.

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the speed of sound in air is approximately the same for all wavelengths. what evidence is there that this is true?

Answers

The speed of sound in air is approximately the same for all wavelengths.

Step by step Explanation :

The evidence that this is true is the following:

The speed of sound in air is approximately the same for all wavelengths. This is proved by the fact that a sound wave is an atmospheric disturbance that propagates as a longitudinal wave through the air, travelling as a pressure wave that causes areas of compression and rarefaction.

The speed of sound in air is constant and is determined by the average kinetic energy of the air molecules. This is why the speed of sound is the same for all wavelengths.

When the temperature of air is held constant, the speed of sound in air is constant. This is the primary reason why the speed of sound in air is practically constant at a given temperature.

The wavelengths of sound range from about 17 meters for the lowest audible frequency (about 20 Hz) to about 17 millimeters for the highest audible frequency (about 20,000 Hz).

The speed of sound in dry air at room temperature is around 343 meters per second, but it may vary depending on a variety of factors, including humidity, temperature, and pressure.

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the photo at right was taken through a specroscope. what color was the pigment extract used to produce this spectrum? what colo(s) did this extract absorb?

Answers

Light is a form of energy. All the properties of light can be explained by Considering the Wave length and lespuscutar theory.

The Wave Theory states that waves are how light moves across space. When Visible light  is passed through a prim it is split up into seven colours which corresponds to definite wave length. a phenomenon Called dispersion. The study of interaction between matter and electromagnetic radiation  is defined as spectroscopy.

A spectrophotometer is a device which detect the percentage transmittance of light radiation. When light of certain intensity and frequency range is passed through the Sample Thus the instrument Compare the intensity of the transmitted light with that of the incident light.

A spectroscope is a device that divides light into its individual wavelengths to produce a spectrum.

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the current through a lightbulb is 2.0 amperes. how many coulombs of leectric charge pass through ther luighbu,kb in one minute?

Answers

The current through the bulb is 2.0 amperes. Then the electric charge that passes through Luighbu is 120 Columbs.

Given that the current through a lightbulb is 2.0 amperes. To find the coulombs of electric charge that pass through the light bulb in one minute, we need to know the formula that relates current, time, and electric charge:

Q = It

Where Q is the electric charge (in coulombs), I is the current (in amperes), and t is the time (in seconds).

To convert one minute to seconds, we multiply it by 60. Hence, the time t = 1 minute × 60 seconds/minute = 60 seconds.

So, the electric charge that passes through the light bulb in one minute is given by

Q = It = 2.0 A × 60 s

Q = 120 C

Therefore, the number of coulombs of electric charge that pass through the light bulb in one minute is 120 C.

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what is the equation to find the equivalent resistance, req, of two resistors in series, r1 and r2? group of answer choices

Answers

The equivalent resistance of resistors in series is always greater than the individual resistances. This is because the total resistance of the circuit is the sum of the resistances, and therefore the electric current has to overcome more resistance to flow through the circuit as compared to when a single resistor is used.

To find the equivalent resistance, req, of two resistors in series, r1 and r2, the following equation is used:

Req = R1 + R2

Where Req is the equivalent resistance of the series circuit,

R1 is the resistance of the first resistor,

R2 is the resistance of the second resistor.

Resistors in a circuit are the components that oppose the flow of electric current. When two resistors are connected in series, they are connected end to end so that the electric current flows through one resistor before flowing through the second one.In a series circuit, the equivalent resistance, req, is calculated as the sum of the individual resistances of the resistors connected in series.

Therefore, to find the equivalent resistance of two resistors in series, R1 and R2, we add the resistance values of the two resistors, as shown in the formula above.

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what is the approimate electrostatic force between two protons seperated bvy a distance of 1.0x10^-6

Answers

The electrostatic force between two protons separated by a distance of 1.0 × 10^-6 m is 2.3 × 10^-8 N.

Electrostatic force is the force between two electrically charged objects. This force can either be attractive or repulsive.

It is proportional to the product of the two charges and inversely proportional to the square of the distance between them.

The force is defined by Coulomb's law which states that:

The electrostatic force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

The formula for Coulomb's law is given as:F = kq1q2/r2

WhereF is the electrostatic forcek is Coulomb's constantq1 and q2 are the charges of the two particles is the distance between the two particles in meters.

The value of Coulomb's constant is 9.0 × 10^9 Nm^2/C^2.Let's consider two protons separated by a distance of 1.0 × 10^-6 m. The charge on each proton is +1.6 × 10^-19 C.

F = kq1q2/r2F = (9.0 × 10^9 Nm^2/C^2)(+1.6 × 10^-19 C)(+1.6 × 10^-19 C)/(1.0 × 10^-6 m)^2F = 2.3 × 10^-8 N

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how long must a 0.70- mm -diameter aluminum wire be to have a 0.42 a current when connected to the terminals of a 1.5 v flashlight battery?

Answers

To determine the length of an aluminum wire required to carry a certain current, one must use the formula: r = (ρL) / (πr²), where r is the radius of the wire, ρ is the resistivity of the wire, and L is the length of the wire is 48.54 m.

What is the length of the wire?

A 0.70 mm diameter aluminum wire has a radius of 0.35 mm or 0.00035 m. The resistivity of aluminum is 2.82 × 10⁻⁸Ωm. The formula for current is:

I = V / R

where, V is voltage, and R is resistance. We can rearrange this to:

R = V / I

Plugging in the given values of 0.42 A and 1.5 V gives R = 3.571 Ω. The resistance of a wire is given by:

R = ρL / A

where, A is the cross-sectional area of the wire, and ρ is its resistivity.

We know the resistivity of aluminum and the radius of the wire, so we can calculate the cross-sectional area of the wire:

A = πr² = 3.1416 × (0.00035 m)² = 3.848 x 10⁻⁷ m². Substituting all the values in the formula for the resistance of the wire and solving for L gives:

L = RA / ρ = (3.571 Ω) × (3.848 x 10⁻⁷ m²) / (2.82 × 10⁻⁸ Ωm) = 48.54 m.

Therefore, the aluminum wire must be 48.54 m long to have a current of 0.42 A when connected to the terminals of a 1.5 V flashlight battery.

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a curve in a road forms part of a horizontal circle. as a car goes around it at constant speed 14.0 m/s, the horizontal total force on the driver has magnitude 149 n. what is the total horizontal force on the driver if the speed on the same curve is 23.9 m/s instead

Answers

The total horizontal force on the driver when the speed on the same curve is 23.9 m/s is approximately 570.5 N.

To find the total horizontal force on the driver when the speed on the same curve is 23.9 m/s instead, we can use the concept of centripetal force. The centripetal force Fc is given by the formula: [tex]Fc = (mv^2) / r[/tex], where m is the mass of the driver, v is the speed of the car, and r is the radius of the curve.

First, we need to determine the mass of the driver using the given information:
149 N =[tex](m * (14.0 m/s)^2) / r[/tex]

We can rearrange the equation to find the mass: m =[tex](149 N * r) / (14.0 m/s)^2[/tex]
Now we want to find the centripetal force at the new speed of 23.9 m/s.

We can use the same formula: [tex]Fc_new = (m * (23.9 m/s)^2) / r[/tex]


We can substitute the mass equation we found earlier into this equation:
[tex]Fc_new = ((149 N * r) / (14.0 m/s)^2) * (23.9 m/s)^2 / r[/tex]
The r values cancel each other out, leaving: [tex]Fc_new = 149 N * (23.9 m/s)^2 / (14.0 m/s)^2[/tex]

Now, calculate the new force:
[tex]Fc_new = 149 N * (23.9^2 / 14.0^2) ≈ 570.5 N[/tex]
So, the total horizontal force on the driver when the speed on the same curve is 23.9 m/s is approximately 570.5 N.

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turns people upside down. people should not drop down. this is due to: gravity. inertia. seat belts. centrifugal force.

Answers

The given statement "turns people upside down" and "people should not drop down" are both due to the centrifugal force.

What is Centrifugal Force?

Centrifugal force is defined as the apparent force that tends to move a rotating body away from the center of rotation. When an object moves in a circular path, a force must act towards the center of the circle to keep it moving in a circle. This force is known as the centripetal force.

The opposite force that acts to push the object away from the center of the circle is called centrifugal force. So, the given statement "turns people upside down" and "people should not drop down" are both due to the centrifugal force.


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determine the capacitance of a teflon-filled parallel-plate capacitor having a plate area of 1.80 cm2 and a plate separation of 0.020 0 mm.

Answers

To determine the capacitance of a teflon-filled parallel-plate capacitor having a plate area of 1.80[tex]cm^{2}[/tex] and a plate separation of 0.0200 mm, we can use the formula for capacitance: C = εo εr A/d, when the values are plugged in, the capacitance is found to be [tex]1.54* 10^{-9}[/tex] Farads.

The capacitance of a teflon-filled parallel-plate capacitor having a plate area of 1.80[tex]cm^{2}[/tex] and a plate separation of 0.0200 mm is determined using the formula C = εo A/d, where C is the capacitance, εo is the permittivity of free space, A is the area of the plates, and d is the distance between the plates.

In this case, the capacitance is C = 8.85 x 10-12 A/d x 1.80[tex]cm^{2}[/tex]  / 0.0200 mm = [tex]1.54* 10^{-9}[/tex] Farads.

To explain this calculation further, the permittivity of free space is a constant value equal to [tex]8.85 * 10^{-12}[/tex] A/d, which is derived from the equation εo = 1/ (μoc2), where μo is the permeability of free space, and c is the speed of light. The area of the plates is given in the problem statement as 1.80 [tex]cm^{2}[/tex], and the distance between the plates is given as 0.0200 mm.

When these values are plugged into the formula, the capacitance is found to be [tex]1.54* 10^{-9}[/tex]Farads. In conclusion, the capacitance of a teflon-filled parallel-plate capacitor having a plate area of 1.80 [tex]cm^{2}[/tex] and a plate separation of 0.0200 mm is 1.54 x 10-9 Farads.

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a record turntable is rotating at 33 1 3 rev/min. a watermelon seed is on the turntable 7.3 cm from the axis of rotation. (a) calculate the acceleration of the seed, assuming that it does not slip. (enter the magnitude.)

Answers

Assuming that it does not slip, the acceleration of the seed is 0.89 m/s².

The acceleration of the seed can be calculated using the formula for centripetal acceleration:

a = (v²) / r

where a is the centripetal acceleration, v is the velocity of the seed, and r is the distance from the axis of rotation to the seed.

To use this formula, we need to first convert the rotational speed of the turntable from rev/min to radians per second. There are 2π radians in one revolution, so:

ω = (33 1/3 rev/min)(2π rad/rev)(1 min/60 s) = 3.49 rad/s

The velocity of the seed can be calculated from the tangential velocity formula:

v = rω

where v is the tangential velocity of the seed.

Substituting the given values, we get:

v = (0.073 m)(3.49 rad/s) = 0.255 m/s

Now we can use the formula for centripetal acceleration:

a = (v²) / r

Substituting the values we have calculated, we get:

a = (0.255 m/s)² / 0.073 m = 0.89 m/s²

Therefore, the acceleration of the seed is 0.89 m/s² assuming that it does not slip.

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a solid cylinder is released from the top of an inclined plane of height 0.72 m. from what height, in meters, on the incline should a solid sphere of the same mass and radius be released to have the same speed as the cylinder at the bottom of the hill?

Answers

The solid sphere should be released from a height of 0.225 m on the incline to have the same speed as the solid cylinder at the bottom of the hill.

To solve the problem, we need to use conservation of energy, which states that the total energy of a closed system remains constant. At the top of the incline, the cylinder and sphere both have potential energy, which is converted to kinetic energy as they roll down the incline.

Since the two objects have the same mass, we only need to consider their different moments of inertia.

The potential energy at the top of the incline is equal to mgh, where m is the mass, g is the acceleration due to gravity, and h is the height of the incline. At the bottom of the incline, the potential energy is converted to kinetic energy, which is equal to (1/2)mv^2, where v is the velocity.

For the solid cylinder, the moment of inertia is (1/2)mr^2, where r is the radius. For the solid sphere, the moment of inertia is (2/5)mr^2.

Since the two objects have the same kinetic energy at the bottom of the incline, we can set their potential energies equal to each other, and solve for the height of the incline for the sphere:

mgh_cylinder = (1/2)mv_cylinder^2

mgh_sphere = (1/2)mv_sphere^2

mgh_cylinder = mgh_sphere

(1/2)mv_cylinder^2 = (1/2)mv_sphere^2

v_cylinder^2 = v_sphere^2

(1/2)mv_cylinder^2 = (1/2)mv_sphere^2

(1/2)mr_cylinder^2(v_sphere^2/r_cylinder^2) = (1/2)(2/5)mr_sphere^2(v_sphere^2/r_sphere^2)

v_sphere^2 = (5/2)(r_cylinder^2/r_sphere^2)v_cylinder^2

h_sphere = (v_sphere^2/2g)

= (5/4)(r_cylinder^2/r_sphere^2)h_cylinder

= (5/4)(1/2)^2(0.72 m)

= 0.225 m

Therefore, the solid sphere should be released from a height of 0.225 m on the incline to have the same speed as the solid cylinder at the bottom of the hill.

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a diver jumps off the diving board. he pushes himself downward at a rate of 2 m/s. gravity increases his downward velocity to 6 m/s when he hits tthe water 1.5 seconds later. what is his acceleration?

Answers

The diver's acceleration is 2.67 m/s^2.

We can use the formula for acceleration:

a = (vf - vi) / t

where a is acceleration, vf is final velocity, vi is initial velocity, and t is time.

In this problem, the initial velocity (vi) is 2 m/s downward, the final velocity (vf) is 6 m/s downward, and the time (t) is 1.5 seconds.

Plugging in these values, we get:

a = (6 m/s - 2 m/s) / 1.5 s

a = 4 m/s / 1.5 s

a = 2.67 m/s^2

As a result, the acceleration of the diver is 2.67 m/s^2.

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an asteroid exerts a 360-n gravitational force on a nearby spacecraft. if the spacecraft moves to a position three times as far from the center of the asteroid, the force will be

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The force between the asteroid and the spacecraft will be 40 N when the spacecraft moves to a position three times as far from the center of the asteroid.

The gravitational force between two objects of masses m1 and m2 separated by a distance r is given by the formula:

F = G(m₁m₂) / r²

where G is the gravitational constant.

In this problem, the asteroid exerts a gravitational force of 360 N on the spacecraft when they are at a certain distance r from each other. When the spacecraft moves to a position three times as far from the center of the asteroid, its distance from the asteroid will be 3r. To calculate the new force between them, we can use the same formula and plug in the new distance:

F' = G(m1m2) / (3r)^2

F' = G(m1m2) / 9r^2

Since the masses of the asteroid and spacecraft are constant, we can divide the second equation by the first to find the ratio of the new force to the original force:

F' / F = (G(m₁m₂) / r²) / 9r²) / (G(m₁m₂) / r²)

F' / F = (1 / 9)

F' = (1 / 9) * F

F' = (1 / 9) * 360 N

F' = 40 N

Therefore, the force will be 40 N.

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A light bulb in a battery-powered torch is too dim. Explain
which property of the bulb should be changed to make the light brighter, and how should it be changed

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The light is brighter in a battery-powered torch, you should change the wattage or power rating of the bulb. A higher-wattage bulb will produce more light and therefore be brighter. When selecting a new bulb for the torch, make sure to choose a bulb with a higher wattage rating than the current bulb.

A battery is an electrochemical device that converts chemical energy into electrical energy through a chemical reaction. It consists of one or more electrochemical cells, each of which contains a positive electrode (cathode), a negative electrode (anode), and an electrolyte that allows ions to move between the two electrodes.

During the discharge process, a chemical reaction takes place within the battery that causes electrons to flow from the negative electrode through an external circuit to the positive electrode, generating an electrical current. This current can then be used to power a wide range of electrical devices, such as flashlights, smartphones, and cars. The chemical reaction can be reversed by recharging the battery, which involves applying an external electrical current to the electrodes to force the reaction to occur in the opposite direction.

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true or false: energy is the capacity to do work and work is anything that involves moving matter against an opposing force.

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The given statement "Energy is the capacity to do work and work is anything that involves moving matter against an opposing force" is TRUE. Energy is the capacity to do work, which is defined as any action that requires the application of a force to move matter. This includes tasks such as lifting a book, pushing a door open, or running.

Energy refers to the capacity of a physical system to perform work. Energy is generally used to complete tasks, such as moving an object from one location to another, heating up or cooling down a material, or lighting up a room. Work is defined as the transfer of energy to an object via a force applied to the object over a given distance, as per the statement. Work is usually identified as the displacement of an object through a force applied to it in the direction of its displacement against an opposing force.Energy and work are two distinct but interrelated concepts in physics. Energy is the capacity to perform work, and work is the transfer of energy from one object to another through a force acting over a distance. Energy and work are both expressed in joules (J), the unit of energy in the International System of Units (SI).

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on a day when there is no wind, you are moving toward a stationary source of sound waves. compared to what you would hear if you were not moving, the sound that you hear has

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The sound that you hear has a higher frequency and a shorter wavelength.

When you move towards a stationary source of sound waves, the wavelength is shortened and the frequency is increased. This is due to the Doppler Effect, which states that a wave's frequency increases as the source and observer come closer together.

The Doppler effect is a phenomenon when there is a change in the frequency of the wave due to a displacement of the source and detector/listener.

In summary, when you move towards a stationary source of sound waves, the sound you hear has a higher frequency and a shorter wavelength.

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which is the correct unit to represent time?

d) 7m
b) 7m/h
c) 7 s

Answers

c) is the correct unit to represent time

discuss how errors due to earth curvature and refraction can be eliminated from the differential leveling process.

Answers



Errors due to earth curvature and refraction can be eliminated from the differential leveling process by using the trigonometric leveling method.

This method utilizes the principle of triangles to determine the height difference between two points on the Earth's surface.

The trigonometric method begins by measuring the horizontal angle between two points, then the vertical angle between the same two points, and finally the distance between the points.

The trigonometric method is not affected by the curvature of the Earth or refraction since the vertical angle is measured at a given distance instead of the line of sight.

Therefore, the measurements of the angles and distances remain unaffected.

The trigonometric leveling process is as follows: first, an instrument is set up at point A. A second instrument is then set up at point B, and both instruments are leveled.

The horizontal angle between the two points is then measured with a theodolite, followed by the vertical angle. Lastly, the distance between the two points is measured using a tape measure.

After all the measurements are taken, the results are then used in a trigonometric formula to calculate the difference in elevation between the two points.

This method eliminates errors due to refraction or the Earth's curvature, since the elevation difference is not determined by the line of sight, but rather by the measured angles and distance.

The trigonometric leveling method is the best method to eliminate errors due to the Earth's curvature and refraction from the differential leveling process.

This method uses trigonometric principles and measurements to accurately calculate the difference in elevation between two points.

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A car rounds an unbanked curve of radius 80 m. If the coefficient of static friction between the road and car is 0.8, what is the maximum speed at which the car traverses the curve without slipping? V = _____ m/s

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If the car rounds an unbanked curve of radius 80 m and the coefficient of static friction between the road and car is 0.8, then the maximum speed at which the car traverses the curve without slipping is V =  25.05 m/s.

The maximum speed at which the car traverses the curve without slipping can be determined using the following formula:

[tex]v = \sqrt{(\mu rg)}[/tex]

Where:

v = maximum speed

μ = coefficient of static friction

r = radius of curvature

g = acceleration due to gravity

Substituting the given values into the formula:

[tex]v = \sqrt {(\mu rg)}[/tex]

[tex]v = \sqrt{(0.8 \times 80 \times 9.81)}[/tex]

v = 25.05 m/s

Therefore, the maximum speed at which the car can traverse the curve without slipping is 25.05 m/s.

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