Engineering College

The XYZ Company is planning a new product line and a new factory to produce the parts and assemble the final products. The product line will include 13 different models. Annual production of each model is expected to be 1,000 units. Each product will be assembled of 250 components, but 65% of these will be purchased parts (not made in the new factory). There is an average of 8 processing operations required to produce each component, and each processing step takes 30 sec (including an allowance for setup time and part handling). Each final unit of product takes 48 min to assemble. All processing operations are performed at work cells that include a production machine and a human worker. Products are assembled at single workstations consisting of one worker each plus assembly fixtures and tooling. Each work cell and each workstation require 25 m2 of floor space and an additional allowance of 45% must be added to the total production area for aisles, work-in-process storage, shipping and receiving, rest rooms, and other utility space. The factory will operate one shift (the day shift, 2,000 hr/yr). Determine: (a) how many processing and assembly operations, (b) how many workers (direct labor only), and (c) how much total floor space will be required in the plant.

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Answer 1

The plant will need to perform 9,100,000 processing and assembly procedures altogether.

What fundamental processing tasks are carried out in a manufacturing facility?

Shape operations, property-enhancing operations, and surface processing operations are the three distinct categories of processing operations. By using mechanical force, heat, or other forms and combinations of energy, shaping operations change the work material's geometry.

There are 250 components in each product.

Parts purchased as a percentage equal 65%.

250 - (65% x 250) = 87.5 is the number of components that will be produced in the new facility.

Eight processing steps are needed to manufacture each component.

The new factory's processing procedures per component totaled 8 x 87.5, or 700.

13 x 1000 x (700 + 1) = 9,100,000 is the total number of processing and assembly procedures needed for the 13 different models.

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how does the sovent drainage and waste system operate without the venting piping used in traditional systems?

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The solvent drainage and waste system operates without venting piping by using a combination of air flow and pressure.

Instead of relying on venting piping to exhaust fumes and waste, the system takes in air from the atmosphere and circulates it through the system with a blower or compressor. This creates a pressure difference that drives the solvent out of the system, taking any remaining waste with it. The pressure also keeps odors from escaping and prevents the system from backflowing.

Drainage is the removal of a mass of water either naturally or artificially from the surface or subsurface from a place.

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calculate the cumulative infiltration and the infiltration rate on a silty clay soil after one hour of rainfall at 1cm/h if the initial effective saturation is 20 percent. assume ponding depth h0 is negligible in the calculations.

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The cumulative infiltration and infiltration rate on a silty clay soil after one hour of rainfall at 1cm/h with initial effective saturation of 20 percent are 252 cm and 4.21 cm/h, respectively.

To calculate the cumulative infiltration and the infiltration rate on a silty clay soil after one hour of rainfall at 1cm/h if the initial effective saturation is 20 percent, we need to first calculate the cumulative infiltration (Icum) and infiltration rate (f). The cumulative infiltration is given by the equation: Icum = h0 + ∫f (dt). Here, h0 is negligible and ∫f (dt) = f x t. So, Icum = f x t.

The infiltration rate can be calculated using the Kostiakov equation: f = K x t1/2. Here, K is the Kostiakov coefficient, which is a function of the initial effective saturation (Si). For a silty clay soil, K = 0.0026 x Si0.5 (cm/min1/2). Thus, in this case, K = 0.0026 x 200.5 = 0.164 cm/min1/2. Since the rainfall intensity is 1 cm/h, t = 1 hour = 60 min. So, the infiltration rate, f = 0.164 x 601/2 = 4.21 cm/h. The cumulative infiltration is Icum = 4.21 x 60 = 252 cm. So, the answers are 252 cm and 4.21 cm/h, respectively.

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Which is a small plain text file that a website might place on your local drive?

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Answer:A cookie

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what is the purpose of the ground symbol used in electrical circuit diagrams? group of answer choices to show that there is a return path for the current between the source of electrical energy and the load. to show the source of electrical energy for the load. to show that there is common bus for connection of the source of electrical energy to the load.

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Answer:

To show that there is a return path for the current between the source of electrical energy and the load.

which safety hazard are firefighters most likely to find in the space between the ceiling and the roof?

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Firefighters are most likely to find the following safety hazards in the space between the ceiling and the roof: accumulation of combustible material, poor ventilation, and exposure to hazardous chemicals.


Accumulation of combustible materials such as wood, paper, insulation, and other debris can provide fuel for a fire, which can be difficult to contain in a confined space like the one between a ceiling and a roof.

Poor ventilation in this space can make it difficult for firefighters to breathe, and they can be exposed to hazardous chemicals such as asbestos, lead, and dust. Firefighters have to be careful with that.

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