A) What is the perimeter of the regular hexagon shown above?B) What is the area of the regular hexagon shown above?(see attached image)

A) What Is The Perimeter Of The Regular Hexagon Shown Above?B) What Is The Area Of The Regular Hexagon

Answers

Answer 1

Remember that

A regular hexagon can be divided into 6 equilateral triangles

the measure of each interior angle in a regular hexagon is 120 degrees

so

see the attached figure to better undesrtand the problem

each equilateral triangle has three equal sides

the length of each side is given and is 12 units

Part A) Perimeter

the perimeter is equal to

P=6(12)=72 units

Part B

Find the area

Find the height of each equilateral triangle

we have

tan(60)=h/6

Remember that

[tex]\tan (60^o)=\sqrt[]{3}[/tex]

therefore

[tex]h=6\sqrt[]{3}[/tex]

the area of the polygon is

[tex]A=6\cdot\lbrack\frac{1}{2}\cdot(6\sqrt[]{3})\cdot(12)\rbrack[/tex][tex]A=216\sqrt[]{3}[/tex]alternate way to find out the value of h

applying Pythagorean Theorem

12^2=6^2+h^2

h^2=12^2-6^2

h^2=108

h=6√3 units

A) What Is The Perimeter Of The Regular Hexagon Shown Above?B) What Is The Area Of The Regular Hexagon

Related Questions

If y varies directly with x and y = 48 when x = -4, write the equation that represents this direct variation relationship12 345

Answers

Answer

The equation that represents the direct variation relationship between y and x is

y = -12x

Explanation

We are told that y varies directly with x.

y = 48 when x = -4.

We are then told to write the equation that represents this direct variation relationship.

In mathematical terms, y varies directly with x is written as

y ∝ x

If we introduce a constant of variation, k, we can then write this relationship as

y = kx

To now fully write this relationship, we need to solve for k.

y = 48 when x = -4.

y = kx

48 = k × -4

48 = -4k

-4k = 48

Divide both sides by -4

(-4k/-4) = (48/-4)

k = -12

We can then put in the value of k obtained

y = kx

y = -12x

The equation given is

3y = 10x

Recall that variation is represented as

y ∝ x

And written as

y = kx

So, we can convert 3y = 10x into this form and establish the direct variation and obtain the value of k.

3y = 10x

Divide both sides by 3

(3y/3) = (10x/3)

y = (10x/3)

which is similar to y = kx

k = (10/3)

So, option A is correct.

Hope this Helps!!!

Question
In a pet store, the small fishbowl holds up to 225 gallons of water. The large fishbowl holds up to 213 times as much water as the small fishbowl.

Eloise draws this model to represent the number of gallons of water the large fishbowl will hold.

How many gallons of water does the large fishbowl hold?

Answers

The number of gallons that the large fishbowl holds would be = 47,925 gallons.

What are fishbowls?

The fishbowls are containers that can be used to transport liquid substance such as water and food products such as fish. This can be measured in Liters, millilitres or in gallons.

The quantity of water the small fishbowl can take = 225 gallons.

The quantity of water the large fish bowl can take = 213(225 gallons)

That is, 213 × 225= 47,925 gallons.

Therefore, the quantity of water that the large fishbowl can hold is 47,925 gallons.

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ok so the question is Write an expression to rubbers in the area of the figure the figure is a right triangle with 2X -2 and 4X plus 2 in the answer to that is 4X to the power of 2 - 2X -2 and that's part a and amp RP is what would the area be if X equals negative 2

Answers

ANSWERS

a) A = 4x² - 2x - 2

b) if x = -2, A = 18 units²

EXPLANATION

The area of a triangle is the length of the base, multiplied by its height and divided by 2:

[tex]A=\frac{b\cdot h}{2}[/tex]

In this triangle, b = 4x + 2 and h = 2x - 2. The area is:

[tex]A=\frac{(4x+2)(2x-2)}{2}[/tex]

We can simplify this expression. First we have to multiply the binomials in the numerator:

[tex]\begin{gathered} A=\frac{4x\cdot2x-4x\cdot2+2\cdot2x-2\cdot2}{2} \\ A=\frac{8x^2-8x+4x-4}{2} \\ A=\frac{8x^2-4x-4}{2} \end{gathered}[/tex]

Now, using the distributive property for the division:

[tex]\begin{gathered} A=\frac{8x^2}{2}-\frac{4x}{2}-\frac{4}{2} \\ A=4x^2-2x-2 \end{gathered}[/tex]

For part b, we just have to replace x with -2 in the expression above and solve:

[tex]\begin{gathered} A=4(-2)^2-2(-2)-2 \\ A=4\cdot4+4-2 \\ A=16+2 \\ A=18 \end{gathered}[/tex]

Identify the rate of change and Intial Value in this equationy = 3x +6

Answers

The rate of change is 3.

The initial value is 6.

Step - by - Step Explanation

What to find?

• Rate of change.

,

• Initial value.

Given:

y = 3x + 6

The rate of change is also the same as the slope.

To find the slope of the gien equation, compare the equation with y=mx + b.

Where m is the slope (rate of change).

Comparing the two equations, m = 3

Hence, the rate of change is 3.

The initial value also known as the y-intercept, is the value of y at x=0.

y = 3(0) + 6

y = 6

Hence, the initial value is 6.

How many ways can we arrange five of the seven Harry Potter books on a shelf if Harry Potter and The Chamber of Secrets must be one of them?

Answers

There are 7 Harry potter books and 5 books needs to be arranged.

One of the five place is filled by book "Harry Potter and The Chamber of Secrets" and remaining 4 places must be filled by remaining 6 books.

So number of ways are,

[tex]\begin{gathered} 1\cdot^6P_4=1\cdot\frac{6!}{(6-4)!} \\ =1\cdot\frac{6\cdot5\cdot4\cdot3\cdot2\cdot1}{2\cdot1} \\ =1\cdot6\cdot5\cdot4\cdot3 \\ =360 \end{gathered}[/tex]

So there are 360 ways in which 5 of 7 Harry pooter book can be arranges such that " Harry Potter and The Chamber of Secrets" must included.

A deck of cards contains RED cards numbered 1,2,3 and BLUE cards numbered 1,2,3,4. Let R be the event of drawing a red card, B the event of drawing a blue card, E the event of drawing an even numbered card, and O the event of drawing an odd card. Drawing the Red 1 is an example of which of the following events? Select all correct answers.

Answers

The event Red 1 is an example of these following events:

R and O.E'.E or R.

Which events are included into Red 1?

Red cards are represented by the letter R, while the number 1, which is odd, is represented by the letter O.

Both events R and O happen in the, hence the event R and O is one of the possible events to this problem, as the card is both red and has an odd number.

The number is not even, hence the event E' is another one of the events in this problem.

The final event is E or R, as the card has a red number, meaning that at least one of the options E or R are satisfied.

Missing information

The options which the event respect are missing, and are given by the image at the end of the answer.

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4 students from a class of 15 are going to be chosen to be on the dance committee. Findthe number of different 4-person committees that can be made.

Answers

Answer:

[tex]C(15,4)=1365\text{ different committees}[/tex]

Step-by-step explanation:

This situation can be approached using the formula for combinations:

[tex]\begin{gathered} C(n,r)=\frac{n!}{r!(n-r)!} \\ \text{where,} \\ n=\text{ number of possible items that can be }selected \\ r=\text{ number of items that were selected} \end{gathered}[/tex]

Therefore, solve for n=15 and r=4.

[tex]\begin{gathered} C(15,4)=\frac{15!}{4!(15-4)!} \\ C(15,4)=1365\text{ different committees} \end{gathered}[/tex]

At noon a private plane left Austin for Los Angeles, 2100 km away, flying at 500 km/h. One hour later a jet left Los Angeles for Austin at 700 km/h. At what time did they pass each other?

Answers

So if you take the L and do the w it should work

Need help with all of them please help me serious

Answers

we have 4,5,6

In a right triangle

c^2=a^2+b^2

where

c is the hypotenuse (greater side)

a and b are the legs

In an acte triangle

c^2 < a^2+b^2

we have

c=6

a=4

b=5

substitute

c^2=6^2=36

a^2=4^2=16

b^2=5^2=25

36 < 16+25

36 < 41

therefore

is an acute triangle

Part 2

10,24,26 and also classify the triangle

we have

c=26

a=10

b=24

so

c^2=676

a^2=100

b^2=576

in this problem

c^2=a^2+b^2

therefore

Is a right triangle

4x-6a(8x)/98y Solve for x

Answers

1) Solving for x, the following equation:

We're going to isolate the x variable on the left:

[tex]4x-6a\frac{8x}{98y}[/tex]

determine the -domain- and -range- of the graphanswer in interval notation

Answers

Explanation: Let's consider two things

- Domain = represented by the minimum and maximum x-values

- Range = represented by the minimum and maximum y-values

Step 1: Let's take a look at the picture below

As we can see above

max x-value = + ∞

min x-value = - ∞

max y-value = 4

min y-value = - ∞

Final answer: So the final answer is

[tex]\begin{gathered} \text{domain}\Rightarrow(-\infty,+\infty) \\ \text{range}\Rightarrow(-\infty,4) \end{gathered}[/tex]

.

Translate the sentence into an inequality.Twice the difference of a number and 2 is at least −28.Use the variable x for the unknown number.

Answers

To answer this question we have to identify the elements of the inequality.

1. The difference of a number and 2 is represented by the expression: x-2.

2. Twice the difference (...) is represented by the expression: 2(x-2).

3. At least is represented by the sign greater than or equal to ≥.

4. The result is -28.

By putting these all together we obtain the inequality:

[tex]2(x-2)\ge-28[/tex]

It means that the answer is 2(x-2) ≥ -28.

MP is the perpendicular bisector of the side AC of the triangle ABC, in which AB = AC. prove that angle APB = 2 angle B

Answers

We have the following:

[tex]\begin{gathered} \frac{a}{\sin now,[tex]\begin{gathered}

The perimeter of a rectangular field is 360 m.If the width of the field is 85 m, what is its length?

Answers

In order to calculate the length of the rectangular field, you use the following formula for the calculation of the perimeter:

P = 2l + 2w

w: width = 85 m

l: length = ?

P: area = 360m

You know the value of P and w, so, you can solve for l in the formula for the perimeter of the field, just as follow:

P = 2l + 2w

2l = P - 2w

l = (P - 2w)/2

Next, you replace the values of P and w:

l = (360m - 2(85m))/2 = 95 m

Hence, the length of the rectangular field is 95m

E is the midpoint of DF, DE = 2x + 4 and EF = 3x - 1 how do I find the value of x, DE, EF and DF

Answers

We know that

E is midpoint of DF, that means DE is equal to EF, so we can form the following equation

[tex]DE=EF[/tex]

Replacing the given equations, we have

[tex]\begin{gathered} 2x+4=3x-1 \\ 4+1=3x-2x \\ x=5 \end{gathered}[/tex]

Now, we replace this value in each equation to find each part of the segment.

[tex]\begin{gathered} DE=2x+4=2(5)+4=10+4=14 \\ EF=3x-1=3(5)-1=15-1=14 \end{gathered}[/tex]Therefore, each part of the segment is 14 units, and DF is 28.

What is the area of this triangule? h = 12 in, b = 3 in

Answers

Answer:

Area = 18

Explanation:

The area of a triangle is given by

Area = 1/2 height * base length

Now in our case

height = 12 in, base length = 3 in; therefore, the area is

Area = 1/2 * 12 * 3

Area = 6 * 3

Area = 18

Which is our answer!

I need this practice problem answered I will provide the answer options in another pic

Answers

The inverse of a matrix can be calculated as:

[tex]\begin{gathered} \text{When} \\ A=\begin{bmatrix}{a} & {b} & {} \\ {c} & {d} & {} \\ {} & {} & \end{bmatrix} \\ \text{Then A\textasciicircum-1 is:} \\ A^{-1}=\frac{1}{ad-bc}\begin{bmatrix}{d} & -{b} & {} \\ {-c} & {a} & {} \\ {} & {} & \end{bmatrix} \end{gathered}[/tex]

Then, let's start by calculating the inverse of the given matrix:

[tex]\begin{gathered} \begin{bmatrix}{4} & {1} & {} \\ {-2} & {3} & {} \\ {} & {} & \end{bmatrix}^{-1}=\frac{1}{4\cdot3-1\cdot(-2)}\begin{bmatrix}{3} & -{1} & {} \\ {-(-2)} & {4} & {} \\ {} & {} & \end{bmatrix} \\ \begin{bmatrix}{4} & {1} & {} \\ {-2} & {3} & {} \\ {} & {} & \end{bmatrix}^{-1}=\frac{1}{14}\begin{bmatrix}{3} & -{1} & {} \\ {2} & {4} & {} \\ {} & {} & \end{bmatrix} \end{gathered}[/tex]

The problem says he multiplies the left side of the coefficient matrix by the inverse matrix, thus:

[tex]\begin{gathered} \begin{bmatrix}{4} & {1} & {} \\ {-2} & {3} & {} \\ {} & {} & \end{bmatrix}^{-1}\begin{bmatrix}{4} & {1} & {} \\ {-2} & {3} & {} \\ {} & {} & \end{bmatrix}\cdot\begin{bmatrix}{x} & {} & {} \\ {y} & {} & {} \\ {} & {} & {}\end{bmatrix}=\begin{bmatrix}{4} & {1} & {} \\ {-2} & {3} & {} \\ {} & {} & \end{bmatrix}^{-1}\begin{bmatrix}{2} & {} & {} \\ {-22} & {} & {} \\ {} & {} & {}\end{bmatrix} \\ \end{gathered}[/tex]

*These matrices will be the options to put on the first and second boxes.

Then:

[tex]\begin{gathered} \begin{bmatrix}{x} & {} & {} \\ {y} & {} & {} \\ {} & {} & {}\end{bmatrix}=\frac{1}{14}\begin{bmatrix}{3} & -{1} & {} \\ {2} & {4} & {} \\ {} & {} & \end{bmatrix}\cdot\begin{bmatrix}{2} & {} & {} \\ {-22} & {} & {} \\ {} & {} & {}\end{bmatrix}\text{ This is for the third box} \\ \begin{bmatrix}{x} & {} & {} \\ {y} & {} & {} \\ {} & {} & {}\end{bmatrix}=\frac{1}{14}\begin{bmatrix}{3\times2+(-1)\times(-22)} & & {} \\ {2\times2+4\times(-22)} & & {} \\ {} & {} & \end{bmatrix}=\frac{1}{14}\begin{bmatrix}{28} & & {} \\ {-84} & & {} \\ {} & {} & \end{bmatrix}\text{ This is the 4th box} \\ \begin{bmatrix}{x} & {} & {} \\ {y} & {} & {} \\ {} & {} & {}\end{bmatrix}=\begin{bmatrix}{28/14} & & {} \\ {-84/14} & & {} \\ {} & {} & \end{bmatrix}=\begin{bmatrix}{2} & & {} \\ {-6} & & {} \\ {} & {} & \end{bmatrix}\text{ And finally this is the last box} \end{gathered}[/tex]

You have an investment account that has a balance of $50,000. If the account iscompounded daily and has an interest rate of 4%, how much did you originally depositinto the account 10 years ago?

Answers

Since we know the future alue of the account, using the formula for the compounded interest with n = 365 (since the account is compounded daily), t=10, r = 4% and A=50000 in the following equation:

[tex]A=P(1+\frac{r}{n})^{n\cdot t}[/tex]

using these values and solving for P, we get:

[tex]\begin{gathered} 50000=P(1+\frac{0.04}{365})^{365\cdot10} \\ \Rightarrow P=\frac{50000}{(1+\frac{0.04}{365})^{3650}}=33516.74 \\ P=33,516.74 \end{gathered}[/tex]

therefore, the original amount deposited 10 years ago is $33,516.74

What is the value of x? Enter your answer in the box. x =

Answers

Step-by-step explanation:

it is an equilateral triangle : all 3 sides are if equal length (indicated by the same symbol on each side).

automatically with that comes the conclusion that all 3 angles have the same size.

and since the sum of all angles in a triangle is always 180°, this means every angle is 180/3 = 60°.

therefore,

2x - 4 = 60

2x = 64

x = 32

and FYI

5y = 60

y = 12

Find the difference.5 - 12 = don’t be specific be quick i leave. a good review

Answers

Given:

5 - 12

To find the difference , all we have to do is to perform the subtraction. The result of subtraction is called the difference.

Subtract 12 from 5.

Thus, we have:

5 - 12 = -7

Therefore, the difference between 5 and 12 is -7

in the figure below, RTS is an isosceles triangle with sides SR=RT, TVU is an equilateral triangle, WT is the bisected of angle STV, points S, T, and U are collinear, and c= 40 degrees.I'm completely lost and have to answer for a, b+c, f, b+f, a+d, e+g

Answers

Step 1: Concept

Triangle SRT is an isosceles triangle with equal base angles a = b

Triangle TUV is an equilateral triangle with all angles equal: g = d = h

Step 2: Apply sum of angles in a triangle theorem to find angle a and b.

[tex]\begin{gathered} a+b+c=180^o \\ c=40^o \\ \text{Let a = b = x} \\ \text{Therefore} \\ x\text{ + x + 40 = 180} \\ 2x\text{ = 180 - 40} \\ 2x\text{ = 140} \\ x\text{ = }\frac{140}{2} \\ x\text{ = 70} \\ a\text{ = 70 and b = 70} \end{gathered}[/tex]

Step 3:

2) a = 70

3) b + c = 70 + 40 = 110

Step 4:

Since WT is a bisector of angle STV,

Angle f = e = x

b + f + e = 180 sum of angles on a straight line.

b = 70

70 + x + x = 180

2x = 180 - 70

2x = 110

x = 110/2

x = 55

Hence, f = 55

4) f = 55

5) f + b = 55 + 70 = 125

Step 5:

Since triangle TUV is an equilateral triangle, angle g = h = d = 60

g = 60

h = 60

d = 60

6) Angle a + d = 70 + 60 = 130

7) e + g = 55 + 60 = 115

Consider the following sets

U = {1,2,3,4,5,6,7,8,9,10,11,12,13}

A= {1,2,3,4,7}

B = {3,4,5,6}

Find the set (A U B)’

Answers

The elements in the set (A u B)' are is {8,9,10,11,12,13}

How to determine the value of the set?

The definitions of the sets and the elements are given as

Universal Set, U = {1,2,3,4,5,6,7,8,9,10,11,12,13}Set A= {1,2,3,4,7}Set B = {3,4,5,6}

The set to calculate is represented by the notation

(A u B)'

Start by calculating the set A u B

This means that we combine the sets A an B without repetition

So, we have

A u B = {1, 2, 3, 4, 5, 6, 7}

Next, we calculate (A u B)'

This represents the sets in U that are not in A u B

So we have

(A u B)' = {8,9,10,11,12,13}

Hence, the value of the set is {8,9,10,11,12,13}

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I resolved this problem for a test already but it looks like the graph it’s not ok can you help me?

Answers

SOLUTION

The function given is

[tex]f(x)=2x+1[/tex]

To obtain the slope, we compare the equation above with the standard form of a slope intercept form.

Hence,, slope intercept is given as

[tex]\begin{gathered} y=mx+c \\ \text{Where m=slope.c=intercept on y (0,c)} \end{gathered}[/tex]

Comparing with the function given, we have

[tex]\begin{gathered} M=2,c=1 \\ \text{Hence } \\ \text{slope}=2,\text{ y-intercept=(0,1)} \end{gathered}[/tex]

Therefore

The slope = 2 and the y-intercept= (0,1 )

The graph of the functionis given in the image below

2. The length of one side of the square is the square root ofits area. Use the table tofind the approximate length of one side of the square. Explain how you used thetable to find this information

Answers

we know that

the area of a square is equal to

A=b^2

where

b is the length side

Apply square root both sides of the formula we have

[tex]\sqrt{A}=b[/tex]

the sum of the measure of angle m and angle r is 90

Answers

Given:

The sum of measure of angle m and r is 90 degrees.

A red die is tossed and then a green dieis tossed. What is the probability thatthe red die shows a six or the green dieshows a six?Hint: The two events are not mutually exclusive. So to the find theprobability of the union, use:P(A or B) = P(A) + P(B) - P(A and B)[?]

Answers

Let's call the event of the red die to show a six as event A, and the event of the green die to show a six as event B.

The theoretical probability is defined as the ratio of the number of favourable outcomes to the number of possible outcomes. On both dices, we have 6 possible outcomes(the numbers from 1 to 6), with one favourable outcome(the number 6), therefore, the probabilities of those events are:

[tex]P(A)=P(B)=\frac{1}{6}[/tex]

Each roll is independent from each other, then, the probability of both events happening simultaneously is given by their product:

[tex]P(A\:and\:B)=P(A)P(B)[/tex]

Using the additive rule of probability, we have the following equation for our problem:

[tex]\begin{gathered} P(A\:or\:B)=P(A)+P(B)-P(A\:and\:B) \\ =P(A)+P(B)-P(A)P(B) \\ =\frac{1}{6}+\frac{1}{6}-\frac{1}{6^2} \\ =\frac{2}{6}-\frac{1}{36} \\ =\frac{12}{36}-\frac{1}{36} \\ =\frac{12-1}{36} \\ =\frac{11}{36} \end{gathered}[/tex]

the probability that the red die shows a six or the green die shows a six is 11/36.

Translate the sentence into an equation.Eight more than the quotient of a number and 3 is equal to 4.Use the variable w for the unknown number.

Answers

We are to translate into an equation

Eight more than the quotient of a number and 3 is equal to 4.

Let the number be w

Hence, quotient of w and 3 is

[tex]\frac{w}{3}[/tex]

Therefore, eight more than the quotient of a number and 3 is equal to 4

Is given as

[tex]\frac{w}{3}+8=4[/tex]

Solving for w

we have

[tex]\begin{gathered} \frac{w}{3}=4-8 \\ \frac{w}{3}=-4 \\ w=-12 \end{gathered}[/tex]

Therefpore, the equation is

[tex]\frac{w}{3}+8=4[/tex]

What property of equity is this identify the property : if B is between O and K, BK=OK

Answers

Segment addition

The sum of the lenghts of the segments OB and Bk will give the total lenght OK

Hello! Need some help on part c. The rubric, question, and formulas are linked. Thanks!

Answers

Explanation:

The rate of increase yearly is

[tex]\begin{gathered} r=69\% \\ r=\frac{69}{100}=0.69 \end{gathered}[/tex]

The number of lionfish in the first year is given beow as

[tex]N_0=9000[/tex]

Part A:

To figure out the explicit formula of the number of fish after n years will be represented using the formula below

[tex]P(n)=N_0(1+r)^n[/tex]

By substituting the formula, we will have

[tex]\begin{gathered} P(n)=N_{0}(1+r)^{n} \\ P(n)=9000(1+0.69)^n \\ P(n)=9000(1.69)^n \end{gathered}[/tex]

Hence,

The final answer is

[tex]f(n)=9,000(1.69)^n[/tex]

Part B:

to figure out the amoutn of lionfish after 6 years, we wwill substitute the value of n=6

[tex]\begin{gathered} P(n)=9,000(1.69)^{n} \\ f(6)=9000(1.69)^6 \\ f(6)=209,683 \end{gathered}[/tex]

Hence,

The final answer is

[tex]\Rightarrow209,683[/tex]

Part C:

To figure out the recursive equation of f(n), we will use the formula below

From the question the common difference is

[tex]d=-1400[/tex]

Hence,

The recursive formula will be

[tex]f(n)=f_{n-1}-1400,f_0=9000[/tex]

Using the information provided in the given table, determine how much monthly income would be necessary to budget in order to cover the expenses of attending a local college for the 9-month academic year. Round your answer to the nearest cent, if necessary.

Answers

We have to add all the annual expenses:

[tex]9122+10612+1109+732+1092+1197+132[/tex][tex]=23,996[/tex]

However, this quantity we obtained are the annual expenses, then, we have to divide them by the months of the academic year:

[tex]\frac{23996}{9}[/tex][tex]=2666.22[/tex]

Answer: $2,666.22

Other Questions
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