Amelia is on a ferris wheel that has a radius of 40m. She starts in a cart at the bottom of the wheel which is 10m off the ground. It takes 45 seconds to complete one full rotation.
Which function models Amelia's height, t seconds since she got on the ride?

The new circle equation is: (x - 4)² + y² = 25

The x-intercepts are:  (9, 0) and (-1, 0)

You already have the answer for the first question, so let's look at b and c.

Here we have a circle equation:

x² + y² = 25

And now this circle is translated by the vector (4, 0) to make a new circle, so the new center will be at the point (4, 0).

That means that the new coordinates of the circle are:

(x - 4)² + (y - 0)² = 25

(x - 4)² + y² = 25

Now we want to get the intercepts of the x-axis, to get these we need to take y = 0.

then:

(x - 4)²  = 25

(x - 4) = ±5

x = 4 ± 5

The x-intercepts are (9, 0) and (-1, 0)

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If it will be 20 feet from the ground then the time will be 3.75sec.

The speed οf an οbject, alsο knοwn as v in cοmmοn parlance and kinematics, is the size οf the change in pοsitiοn per unit οf time οr the size οf the change in pοsitiοn οver time; as such, it is a scalar quantity.

The average speed οf an οbject in a given periοd οf time is equal tο the distance travelled by the οbject divided by the length οf the interval the instantaneοus speed is the upper limit οf the average speed as the length οf Velοcity and speed are different cοncepts.

The rοcket was launched 200 feet up a cliff, which was its height.

u = 120 feet per secοnd is the rοcket's initial speed.

h(t) = -16t2 + 120t + 200 represents the height οf the rοcket with respect tο time t.

By inputting t = 1 h(1) = -16 (1)2 + 120 (1) + 200 = 304, yοu can calculate the rοcket's height after 1 secοnd.

304 feet b after οne secοnd, which is the rοcket's height. The value οf the maximum pοint οf the height-related equatiοn's curve can be determined by using the fοrmula belοw tο determine the maximum height.

At the greatest pοint, h'(t) = d(-16t2 + 120t + 200)/dt = -32t + 120 = 0 t = 120/32 = 3.75.

Hence the time will be 3.75sec.

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Therefore , the solution of the given problem of probability comes out to be P = 0.8236 ,  P= 0.0155 and P = 0.0203

The calculation of the probability that a statement is true or that a particular event will happen is the main objective of the patterns in the form known as hyperparameters. Chance can be represented by any number from range  0 and 1, where 1 typically signifies certainty and 0 typically signifies potential. A probability diagram illustrates the likelihood that a particular occurrence will take place.

Here,

Based on the survey findings, let p represent the likelihood that an executive thinks workers are most productive on Tuesdays: p = 0.48

Suppose there were n leaders who were surveyed: n = 190

Using Appendix A and the binomial distribution method, we can calculate:

=> P(X < 85) = P(X ≤ 84) = 0.0155

b. To determine the likelihood that more than 95 of the executives think that workers are most effective on Tuesdays, use Appendix A and the complement rule.

=> P(X > 95) = 1 - P(X ≤ 95) = 1 - 0.9797 = 0.0203

c. We need to compute P(X > 79) to determine the likelihood that more than 79 executives think workers are most productive on Tuesdays. This can be done using the complement rule and Appendix

A:

=> P(X > 79) = 1 - P(X ≤ 79) = 1 - 0.1764 = 0.8236

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The graph of the compressed function is graph A.

Remember that for any function f(x), we define a horizontal compression of scale factor k (whre we must have k > 1) is defined as:

f(k*x)

Here we have f(4x), so this is an horizontal compression of scale factor 4.

Notice that the original function goes from x = -4 to x = 4

Then the compressed function must go from x = -4/4 = -1 to x = 4/4 = 1

Which is what we can see in graph A, so that is the correct option.

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The speed of the plane in still air is 87 mph and the speed of the wind is 29 mph.

The cost of one package of tulip bulbs is $10.8 and the cost of one bag of daffodil bulbs is $8.5.

A van can carry 14 students and a bus can carry 62 students.

There are 13 students in each van and 59 students in each bus.

Let the speed of the plane be p and the speed of the wind be w. Then we have the following system of equations:

p + w = d/t1 = 580/5 = 116

p - w = d/t2 = 580/10 = 58

Adding the two equations, we get:

2p = 174

p = 87 mph

Substituting this value into either equation, we get:

w = 29 mph

Therefore, the speed of the plane in still air is 87 mph and the speed of the wind is 29 mph.

Let the cost of one package of tulip bulbs be x and the cost of one bag of daffodil bulbs be y. Then we have the following system of equations:

6x + 12y = 198

7x + 6y = 127

Multiplying the second equation by 2 and subtracting it from the first equation, we get:

5x = 54

x = 10.8

Substituting this value into either equation, we get:

y = 8.5

Therefore, the cost of one package of tulip bulbs is $10.8 and the cost of one bag of daffodil bulbs is $8.5.

Let the number of students a van can carry be x and the number of students a bus can carry be y. Then we have the following system of equations:

16x + 8y = 752

5x + 5y = 380

Simplifying the second equation, we get:

x + y = 76

Multiplying this equation by 8 and subtracting it from the first equation, we get:

8x = 112

x = 14

Substituting this value into either equation, we get:

y = 62

Therefore, a van can carry 14 students and a bus can carry 62 students.

Let the number of students a van can carry be x and the number of students a bus can carry be y. Then we have the following system of equations:

16x + 5y = 417

10x + 8y = 480

Multiplying the first equation by 2 and subtracting it from the second equation, we get:

6x = 42

x = 7

Substituting this value into either equation, we get:

y = 51

Therefore, a van can carry 7 students and a bus can carry 51 students.

Let the number of students in each van be x and the number of students in each bus be y. Then we have the following system of equations:

14x + 16y = 1086

10x + 13y = 870

Multiplying the first equation by 13 and subtracting it from the second equation multiplied by 16, we get:

2x = 26

x = 13

Substituting this value into either equation, we get:

y = 59

Therefore, there are 13 students in each van and 59 students in each bus.

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7) A plane traveled 580 miles to Ankara and back. The trip there was with the wind. It took 5 hours. The trip back was into the wind. The trip back took 10 hours. Find the speed of the plane in still air and the speed of the wind.

8) Amanda and Ndiba are selling flower bulbs for a school fundraiser. Customers can buy packages of tulip bulbs and bags of daffodil bulbs. Amanda sold 6 packages of tulip bulbs and 12 bags of daffodil bulbs for a total of $198. Ndiba sold 7 packages of tulip bulbs and 6 bags of daffodil bulbs for a total of $127. Find the cost each of one package of tulips bulbs and one bag of daffodil bulbs.

9) The local amusement park is a popular field trip destination. This year the senior class at High School A and the senior class at High School B both planned trips there. The senior class at High School A rented and filled 16 vans and 8 buses with 752 students. High School B rented and filled 5 vans and 5 buses with 380 students. Each van and each bus carried the same number of students. How many students can a van carry? How many students can a bus carry?

10) The senior classes at High School A and High School B planned separate trips to New York City. The senior class at High School A rented and filled 16 vans and 5 buses with 417 students. High School B rented and filled 10 vans and 8 buses with 480 students. Every van had the same number of students in it as did the buses. How many students can a van carry? How many students can a bus carry?

11) The senior classes at High School A and High School B planned separate trips to the water park. The senior class at High School A rented and filled 14 vans and 16 buses with 1086 students. High School B rented and filled 10 vans and 13 buses with 870 students. Every van had the same number of students in it as did the buses. Find the number of students in each van and in each bus.

The area of the triangle ABC is 87.176 cm square.

A triangle is a polygon with three vertices and three sides. The internal angle of the triangle, which is 180 degrees, is built. It means that a triangle's internal angles sum to 180 degrees. It has the fewest sides of any polygon. Instead, a triangle is a three-sided, two-dimensional geometry with internal angles that are 180°.

A triangle with a right angle of 90 degrees is equivalent to one of a triangle's angles.

Triangles abc and acd. ACD is 108 cm square in size. Calculate ABC's area.

Given: ACD is 108 cm square in size.

Area of ACD = 108, thus calculate the area of ABC.

[tex]\frac{1}{2}*CD*AC=108\\\\\frac{1}{2}*16*AC=108\\\\8*AC=108\\\\AC=\frac{108}{8}\\\\Area\ (ABC)=\frac{1}{2}*AC*BC*sin38,\\ = \frac{1}{2}*\frac{27}{2}*21*sin38\\=87.176 cm^2[/tex]

[tex]\frac{1}{2}*CD*AC=108\\\\\frac{1}{2}*16*AC=108\\\\8*AC=108\\\\AC=\frac{108}{8}\\\\Area\ (ABC)=\frac{1}{2}*AC*BC*sin38,\\ = \frac{1}{2}*\frac{27}{2}*21*sin38\\=87.176 cm^2[/tex]

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The probability of the number of defective bulbs in the sample greater than 15 is approximately 0.9177.Hence option A is correct.

Suppose that a factory produces light bulbs, and the percentage of defective bulbs is 3.5%. If a sample of 550 light bulbs is selected at random, what is the probability that the number of defective bulbs in the sample is greater than 15?We are required to calculate the probability of the number of defective bulbs in the sample greater than 15. Percentage of defective bulbs = 3.5%Number of light bulbs in the sample = 550Let X be the number of defective bulbs in the sample. We know that the probability distribution of X is a binomial probability distribution because the sample is selected randomly and the sample size is less than 10% of the total population,

which is considered as large. Let P (X > 15) be the probability of the number of defective bulbs greater than 15.Now, mean μ = np = 550 × 0.035 = 19.25 and standard deviation σ = √npq Where q = 1 − p = 1 − 0.035 = 0.965∴ σ = √npq = √550 × 0.035 × 0.965 = 3.05Therefore, Z = (15 − μ) / σ = (15 − 19.25) / 3.05 ≈ −1.39Using normal distribution, P (Z > −1.39) = 1 − P (Z ≤ −1.39)We get P (Z ≤ −1.39) = 0.0823Using the standard normal table or calculator, we get P (Z > −1.39) = 1 − 0.0823 = 0.9177Therefore, the probability of the number of defective bulbs in the sample greater than 15 is approximately 0.9177. Hence, option A is correct.

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Answer:

Step-by-step explanation:

i don't know

Answer:

Not remain

Step-by-step explanation:

Answer: 56

Step-by-step explanation:

there are 10,626 possible ways to select a president, a secretary, and a treasurer from a board of directors with 23 members.

To solve this problem, we can use the formula for permutations, which is:

P(n, r) = n! / (n - r)!

where n is the total number of items, and r is the number of items selected.

In this case, we need to select 3 people from a group of 23, without replacement and order matters. Therefore, the number of ways to do this is:

P(23, 3) = 23! / (23 - 3)!

= 23! / 20!

= 23 x 22 x 21

= 10,626 possible ways

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To make a geometric shape with 100 points, there are many options depending on the desired shape.

There are many possible geometric shapes you can make with 100 points, depending on the specific constraints and requirements you have. Few examples are,

Circle: One way to create a circle with 100 points is to evenly distribute the points around the circumference of a circle with a given radius.

Square: Another option is to create a square with 100 points. To do this, you can divide the sides of the square into 25 segments, and then place 4 points at each segment endpoint.

Regular polygon: You can create a regular polygon with 100 sides by following a similar method to the circle.

Spiral: You can create a spiral shape with 100 points by placing the points along a logarithmic spiral.

Fractal: Finally, you can create a fractal shape with 100 points by applying a recursive algorithm to divide and subdivide segments of an initial shape.

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The two events are independent when one event has no effect on another event.

Question:2 ( 15 marks) An urn contains seven black balls and five white balls. Three balls are randomly awn from the urn without replacement and let X denote the number of black balls drawn. Then e three balls are put back to the urn. Next, four balls are randomly drawn from the urn without placement and let Y denote the number of black balls drawn. Let A=X+Y and B=X−Y . a. Find Cov(A,B) . b. Find Var(A+B) . c. Are A and B independent? Why?Solution:Given,An urn contains seven black balls and five white balls. Three balls are randomly drawn from the urn without replacement and let X denote the number of black balls drawn.Then these three balls are put back to the urn.Next, four balls are randomly drawn from the urn without placement and let Y denote the number of black balls drawn.Let A=X+Y and B=X−Y.a. Cov(A,B)Cov(A, B) = Cov(X+Y, X-Y)= Cov(X,X) - Cov(X,Y) + Cov(Y,X) - Cov(Y,Y) = Var(X) - Cov(X,Y) - Cov(Y,X) + Var(Y)Also, Var(X) = E(X^2) - [E(X)]^2=E(X)(E(X)+1)-E(X)^2 = E(X) + E(X)^2 - E(X)^2 = E(X) = 3.5Simillarly, Var(Y) = E(Y) + E(Y)^2 - E(Y)^2 = E(Y) = 2The probability of choosing a black ball from the urn P(X=1) = (7/12), The probability of choosing a black ball from the urn P(Y=1) = (7/12)Cov(X, Y) = E(XY) - E(X)E(Y) E(XY) = P(X=1,Y=1) + P(X=0,Y=0) = (7/12) * (6/11) * (5/10) + (5/12) * (4/11) * (3/10) = 21/110Cov(X, Y) = E(XY) - E(X)E(Y) = (21/110) - 3.5*2 = -14/110=-0.1272Thus, Cov(A, B) = 3.5 + 2 + 2 - 14/110 = 54/55=0.9818b. Var(A+B)Var(A+B) = Var(X+Y+X-Y) = Var(2X) + Var(2Y) = 4Var(X) + 4Var(Y) = 4(3.5) + 4(2) = 16Thus, Var(A+B) = 16.c. Are A and B independent? Why?A and B are not independent because Cov(A,B) ≠ 0, where Cov(A,B) = 54/55 ≠ 0.Note: In statistics, independence is a condition in which two events (A and B) are unrelated to each other. If the probability of an event A is not affected by the occurrence of another event B, these events are independent. That means, two events are independent when one event has no effect on another event.

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Rational numbers can be represented by the amount (not the %) of two integers. A fraction with a numerator that is not zero is considered fair. In addition to   [tex]1/2[/tex] and [tex]1/5[/tex], rational numbers also include  [tex]3/4[/tex]  .

To rationalize the denominator of 1/√10, we need to multiply both the numerator and denominator by √10. This will give us:

Furthermore, "0" could be stated in a number of ways as a real purpose, such as [tex]0/1, 0/2[/tex]  , as well as 0/3. But also [tex]1/0, 2/0, 3/0[/tex]  , and others. Seven is a respectable number. Two variables can be divided to produce a rational number.

[tex]1/[/tex]√[tex]10[/tex] × √10/√10 = √10/10

We can simplify this fraction by dividing both the numerator and denominator by 2, which gives us:√10/5 This is the simplest form of the expression with a rational denominator.

Therefore, the solution of the given problem of rational numbers comes out to be [tex]1/10[/tex] can be expressed as  [tex]10/10[/tex] When the denominator is logical.

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Answer:

The price of an ice cream sundae is $4.75.

Step-by-step explanation:

Let m be the cost of one milkshake and s be the cost of one ice cream sundae.

4m + 2s = 23.50 -------> 8m + 4s = 47.00

8m + 6s = 56.50 -------> 8m + 6s = 56.50

------------------------

2s = 9.50

s = 4.75

a) The probability that a randomly selected box contains at least one defective bulb is approximately 0.099. b) The probability that a randomly selected box contains at most one defective bulb is approximately 0.9998.

a) To find the probability that a randomly selected box contains at least one defective bulb, we can use the complement rule: the probability of the complement of the event (no defective bulbs) is easier to calculate. The probability that a bulb is not defective is 199/200, so the probability that all 20 bulbs in a box are not defective is (199/200)²⁰. Therefore, the probability that at least one bulb is defective is:

1 - (199/200)²⁰ ≈ 0.099

So the probability that a randomly selected box contains at least one defective bulb is approximately 0.099.

b) To find the probability that a randomly selected box contains at most one defective bulb, we can calculate the probability of each possible outcome (0, 1, or 2 defective bulbs) and add them up.

The probability of no defective bulbs is (199/200)²⁰ ≈ 0.9048.

The probability of exactly one defective bulb is:

20C1 * (1/200) * (199/200)¹⁹ ≈ 0.0950

where 20C1 is the number of ways to choose one defective bulb out of 20.

The probability of two defective bulbs is:

20C2 * (1/200)² * (199/200)¹⁸ ≈ 0.0002

where 20C2 is the number of ways to choose two defective bulbs out of 20.

Therefore, the probability of at most one defective bulb is:

0.9048 + 0.0950 ≈ 0.9998

So the probability that a randomly selected box contains at most one defective bulb is approximately 0.9998.

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The box plots show the average wind speeds, in miles per hour, for various cities in two different countries.

Box plots are graphical representations of data that summarize important features such as the center, spread, and shape of a distribution. In this case, the box plots show the average wind speeds, in miles per hour, for different cities in two different countries.

The box in the plot represents the middle 50% of the data, with the line inside the box showing the median. The whiskers extend to the minimum and maximum values of the data, excluding any outliers, which are shown as individual points outside the whiskers.

Comparing the box plots for the two countries, we can see that the average wind speeds for the cities in Country A are generally lower than those in Country B. The box in Country A is shorter and closer to the bottom of the plot, indicating less variability in the data. Meanwhile, the box in Country B is taller and more spread out, suggesting a wider range of wind speeds across the cities.

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Based on the box plot, which type of Raina's squash has a higher median length?

The derivative of x23x is $\frac{2}{3}x^{-1/3}3^x+ x^{2/3} \ln(3)3^x$.

The functions are as follows: (a) 23x(b) 10(5−6n+n2)(c) 3x2+2(d) t2t​(e) x23xDifferentiation is the process of finding the derivative of a function or equation. The derivative of a function, in calculus, is the rate at which it changes with respect to its independent variable.

In other words, it represents the slope of the tangent line at a particular point on the graph of the function. The following are the derivatives of the functions mentioned above: (a) 23x Solution:We know that, f(x) = 23xNow, differentiating both sides of the equation with respect to x we get, $\frac{d}{dx}(f(x))= \frac{d}{dx}(23x)$Here, $\frac{d}{dx}$ is the differential operator.

It implies that we need to find the derivative of the function with respect to x.Then, $\frac{d}{dx}(23x)= 23 \frac{d}{dx}(x)$Now, $\frac{d}{dx}(x)= 1$So, $\frac{d}{dx}(f(x))= 23$Therefore, the derivative of 23x is 23. (b) 10(5−6n+n2) Solution:We know that, f(x) = 10(5−6n+n2)Now, differentiating both sides of the equation with respect to x we get, $\frac{d}{dx}(f(x))= \frac{d}{dx}[10(5−6n+n^2)]$Here, $\frac{d}{dx}$ is the differential operator.

It implies that we need to find the derivative of the function with respect to x.Then, $\frac{d}{dx}(10(5−6n+n^2))= 10 \frac{d}{dx}(5−6n+n^2)$Now, $\frac{d}{dx}(5−6n+n^2)= \frac{d}{dx}(5)- \frac{d}{dx}(6n)+ \frac{d}{dx}(n^2)$Now, $\frac{d}{dx}(5)= 0$ because 5 is a constant, and its derivative is always 0. Hence, we can ignore it.Then, $\frac{d}{dx}(6n)= 6 \frac{d}{dx}(n)$Now, $\frac{d}{dx}(n)= 1$So, $\frac{d}{dx}(6n)= 6$Then, $\frac{d}{dx}(n^2)= 2n$Therefore, $\frac{d}{dx}(f(x))= 10 (0 - 6 + 2n) = 20n - 60$Therefore, the derivative of 10(5−6n+n2) is 20n - 60. (c) 3x2+2 Solution:We know that, f(x) = 3x2+2Now, differentiating both sides of the equation with respect to x we get, $\frac{d}{dx}(f(x))= \frac{d}{dx}(3x^2+2)$Here, $\frac{d}{dx}$ is the differential operator.

It implies that we need to find the derivative of the function with respect to x.Then, $\frac{d}{dx}(3x^2+2)= 3 \frac{d}{dx}(x^2)+ \frac{d}{dx}(2)$Now, $\frac{d}{dx}(x^2)= 2x$So, $\frac{d}{dx}(f(x))= 3(2x)+ 0 = 6x$Therefore, the derivative of 3x2+2 is 6x. (d) t2t​ Solution:We know that, f(x) = t2t​Now, differentiating both sides of the equation with respect to x we get, $\frac{d}{dx}(f(x))= \frac{d}{dx}(\frac{t^2}{t})$Here, $\frac{d}{dx}$ is the differential operator.

It implies that we need to find the derivative of the function with respect to x.Then, $\frac{d}{dx}(\frac{t^2}{t})= \frac{d}{dx}(t^{2-1})$Now, $\frac{d}{dx}(t^{2-1})= 1 t^{2-1-1} \frac{d}{dx}(t)$So, $\frac{d}{dx}(t)= 0$ because t is a constant. Hence, we can ignore it.Then, $\frac{d}{dx}(f(x))= 1 t \frac{d}{dx}(t)= t$Therefore, the derivative of t2t​ is t. (e) x23x Solution:We know that, f(x) = x23xNow, differentiating both sides of the equation with respect to x we get, $\frac{d}{dx}(f(x))= \frac{d}{dx}(x^{2/3}3^x)$Here, $\frac{d}{dx}$ is the differential operator.

It implies that we need to find the derivative of the function with respect to x.Then, $\frac{d}{dx}(x^{2/3}3^x)= \frac{d}{dx}(x^{2/3})3^x+ x^{2/3} \frac{d}{dx}(3^x)$Now, $\frac{d}{dx}(x^{2/3})= \frac{2}{3}x^{-1/3}$Then, $\frac{d}{dx}(3^x)= \ln(3)3^x$So, $\frac{d}{dx}(f(x))= \frac{2}{3}x^{-1/3}3^x+ x^{2/3} \ln(3)3^x$Therefore, the derivative of x23x is $\frac{2}{3}x^{-1/3}3^x+ x^{2/3} \ln(3)3^x$.

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60

8.43

alternative hypothesis

(a) The hypotheses for this question are:

1) H0: μ = 60  
Ha: μ > 60

2) H0: μ = 60  
Ha: μ < 60

3) H0: μ = 60
Ha: μ ≠ 60

(b) The test statistic is calculated as:
t = (103-60)/(35/√32) = 8.43

(c) Based on a significance level of α = 0.01, the correct conclusion for the hypothesis test is that the mean chirp rate for crickets on a high-protein diet is greater than 60 chirps per second, as the test statistic (8.43) is greater than the critical value (2.58). Therefore, we can reject the null hypothesis and accept the alternative hypothesis.

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Sure! CER stands for Claim, Evidence, and Reasoning. It is a great way to organize our thoughts and show our work.

Claim: Melody had X amount of money after making the deposit.

Evidence: Melody's account was overdrawn by $32. She made a deposit of $100.

Reasoning: To find out how much money Melody has after making the deposit, we need to add the amount of the deposit to the amount of money she had before the deposit.

So, let's start by finding out how much money Melody had before the deposit. Since her account was overdrawn by $32, we can assume that she had a negative balance of $32. To find out the positive balance, we need to add $32 to $100 (the amount of the deposit):

$32 + $100 = $132

Therefore, Melody had $132 after making the deposit.

Claim: Melody had $132 after making the deposit.

Evidence: Melody's account was overdrawn by $32. She made a deposit of $100.

Reasoning: We added the amount of the deposit to the amount of money she had before the deposit to find out how much money she had after making the deposit.

The two expressions used to solve the product are 3 * (3/6)  and (3/1) * (1/2). The product of the given expression is 3/2.

A fraction is a number that expresses a portion of a total or the relationship between two quantities. Normally, it is written with a horizontal line separating the numerator from the denominator. The denominator represents the entirety or the second number, whereas the numerator represents a portion of the total or the first amount. The simplest way to multiply a fraction is to add the numerators and denominators together.

The product of 3 and (3/6), is:

3 * (3/6) = (3 * 3) / 6 = 9/6 = 3/2

Therefore, the product of 3 and (3/6) is 3/2.

Another expression that is equivalent to the product of 3 and (3/6) is:

3 * (3/6) = (3/1) * (1/2) = 3/2

This expression is equivalent to the previous one, as both represent the same value of 3/2.

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Value of the given expression when x = 0 and y = -1 is 3/8.

The given expression is (3x^2 y - 2x - 6y - 9)/(-11y + 5). We need to evaluate it when x = 0 and y = -1.Let's substitute the given values of x and y in the expression.(3x^2 y - 2x - 6y - 9)/(-11y + 5) = (3(0)^2 (-1) - 2(0) - 6(-1) - 9)/(-11(-1) + 5)= (-3 + 6 - 9)/(-5 - 11)= -6/-16= 3/8Therefore, the value of the given expression when x = 0 and y = -1 is 3/8.An HTML formatted answer is given below.

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The cost of the fabric needed to make the square table cloth is $3.75

Firstly, it's essential to understand that the cost of the fabric is calculated per square foot. This means that the more square feet of fabric you use, the higher the cost will be. Therefore, the first step is to measure the dimensions of the tablecloth.

For instance, if the tablecloth is 5 feet long and 3 feet wide, the total area would be 15 square feet.

Next, you can multiply the total square footage of the tablecloth by the cost of the fabric per square foot.

In this case, if the cost of the fabric is $0.25 per square foot, the cost of the fabric needed for the tablecloth would be

=> 15 (total square feet) x 0.25 (cost per square foot) = $3.75.

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After addressing the issue at hand, we can state that This is an unusual angles result because it implies that point A is on line segment BC, and thus triangle ABC is a straight line.

An angle is a shape in Euclidean geometry that is made up of two photons, known as the tone's sides, that connect at their center at a point known as the angle's vertex. Two rays may combine to form an angular velocity there in plane where they are positioned. When two planes make contact, an angle is formed. These are started referring to as wing angles. In plane geometry, an angle is really the plausible configuration of multiple rays or rows that express a termination. The English word "angle" originates from the Latin word "angulus," that means "horn." The vertex is the point at which the two rays, also renowned as the angle's sides, intersect.

We can use the property that the sum of angles in a triangle is 180 degrees to find the value of x in the given figure.

We can begin by calculating the value of angle ABC using the following information:

ABC angle = 180 - angle ABD - ACD angle = 180 - 35 - 58 = 87 degrees

angle ABE stands for angle. Angle ACD = 58 degrees Angle = CDE 35 degrees CBE

angle BAC = angle - 180 angle - ABC ABE stands for angle. CBE = 180 - 87 - 58 - 35 = 0°

This is an unusual result because it implies that point A is on line segment BC, and thus triangle ABC is a straight line.

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The longer side of the Quadrilateral/Parallelogram is approximately 16.28 cm.

what are quadrilaterals?

Quadrilaterals are geometric figures with four sides and four angles. They are two-dimensional shapes that can be classified based on their properties such as angles, side lengths, and symmetry.

Now,

Let's denote the shorter side of the parallelogram by x and the longer side by y. Since opposite sides of a parallelogram are congruent, the perimeter of the parallelogram is:

2x + 2y = 80

Simplifying this equation, we get:

x + y = 40

Now, let's consider the diagonal that is perpendicular to one of the sides. This diagonal divides the parallelogram into two right triangles. Let's denote the length of the altitude (or height) of each right triangle by h, as shown in the diagram below:

         /|\

       /  |  \

     /    |    \

   /______|______

           20 cm

Using the Pythagorean theorem, we have:

h² + (x/2)² = 20²

Simplifying this equation, we get:

h² + x²/4 = 400

4h² + x² = 1600

Since h is also the height of the parallelogram, we know that h is perpendicular to the longer side y. Thus, we have:

h² + y² = (2h)²

h² + y² = 4h²

Substituting the value of h² from the first equation into the second equation, we get:

x²/4 + y² = 4(400 - x²/4)

x² + 4y² = 1600

Substituting x = 40 - y from the perimeter equation, we get:

(40 - y)² + 4y² = 1600

5y² - 80y + 400 = 0

y² - 16y + 80 = 0

Using the quadratic formula, we get:

y = (16 ± √(16² - 4*80))/2

y = 8 ± √(14)

Since y must be greater than x, we take the larger value of y:

y = 8 + √(14)

Therefore, the longer side of the parallelogram is approximately 16.28 cm.

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Therefore , the solution of the given problem of unitary method comes out to be the distance between Barry and Dillon is roughly 6.2 feet.

Using the unilateral approach, the task can be completed by increasing the information obtained from such a nanosection by two. In essence, that whenever a wanted item emerges, the colour area of both the production runs were either skipped or the defined entity is set. For forty pens, a variable charge of Inr ($1.01) could have been required.

Here,

We can use a diagram to show the three passengers' locations on the bus in order to solve this issue:

Let x serve as a proxy for the separation between Barry and Dillon.

Using the knowledge provided, we can create two equations:

Barry is five steps away from Julian.

=> x² +d² = 5.

They are eight feet apart, Dillon and Julian.

Duplicate the formula

d = distance between Barry and Dillon (d = x² + 8² ).

The two formulae can be made equal to one another in order to find d:

=> x² + 5² = x² + 8²

=> 25 = 64 - x²

=> x² = 39

=> x ≈ 6.2

This means that, rounded to the closest tenth, the distance between Barry and Dillon is roughly 6.2 feet.

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Answer:

6.2 ft

Step-by-step explanation:

To find:-

Answer:-

On drawing a figure representing the given situation , we get a right angled triangle . To find out the distance between Barry and Dillon we can use Pythagoras theorem, according to which;

[tex]\rm\implies h^2=a^2+b^2\\[/tex]

Here h is the longest side and a and b are two other sides. And in this question, hypotenuse is 8ft . One of the other side is 5ft .

On substituting the respective values , we have ;

[tex]\rm\implies 8^2 = 5^2+a^2 \\[/tex]

[tex]\rm\implies 64 = 25 + a^2\\[/tex]

[tex]\rm\implies 64 - 25 = a^2 \\[/tex]

[tex]\rm\implies 39 = a^2 \\[/tex]

[tex]\rm\implies a =\sqrt{39}\\[/tex]

[tex]\rm\implies \red{ a = 6.2 } \\[/tex]

Hence the distance between Barry and Dillon is 6.2 ft. (nearest tenth) .

The total amount of fees for each bank is First state bank = $8, National bank = $12.50, and third city bank = $9.

The fundamentals of mathematics are arithmetic operations. Operations like addition, subtraction, multiplication, and division make up the majority of it. Sometimes referred to as mathematical operations, these. In daily life, we employ mathematical operations to calculate overall business revenue and costs, create monthly or yearly budgets, measure distances, and more. We use them nearly constantly throughout the day. For instance, we use them to calculate the overall amount of homework problems, time, money, the number of chocolates we ate, the total number of grades we received across all courses, etc.

Given that, one month you write 5 checks and use bank's ATM machine 3 times, you use a non bank ATM twice and your debit card 8 times

The total amount for first state bank is:

C = 5(1) + 3(1) = $8

The total amount for National bank is:

C = 12.50

The total amount for third city bank is:

C = 3(1) + 8(0.75) = 9

Hence, the total amount of fees for each bank is First state bank = $8, National bank = $12.50, and third city bank = $9.

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