An archer shoots an arrow at an 82.0 m distant target; the bull's-eye of the target is at same height as the release height of the arrow.
(a)
At what angle in degrees must the arrow be released to hit the bull's-eye if its initial speed is 40.0 m/s?

Answers

Answer 1

Answer:

Explanation:

We can use the following kinematic equation to solve this problem:

y = y0 + tanθ(x - x0) - (gx²)/(2v₀²cos²θ)

where

y = 0 (since the target is at the same height as the release height)

y0 = 0

x0 = 0

x = 82.0 m

v₀ = 40.0 m/s

g = 9.81 m/s²

We want to solve for θ.

Rearranging the equation and substituting the values, we get:

tanθ = (xg)/(2v₀²)

θ = tan⁻¹[(xg)/(2v₀²)]

θ = tan⁻¹[(82.0 m)(9.81 m/s²)/(2(40.0 m/s)²)]

θ ≈ 18.1°

Therefore, the archer must release the arrow at an angle of approximately 18.1 degrees to hit the bull's-eye.


Related Questions

If 10 A of current flows through a 2 ohm resistor, what is the voltage of the battery?
20 V
0.2 V
OS V
12 V

Answers

The voltage of the battery would be 20 volts. Option I.

Voltage calculation

According to Ohm's law, the voltage (V) across a resistor is equal to the current (I) flowing through it multiplied by its resistance (R). Mathematically,

V = I × R

In this case, the current (I) flowing through the resistor is given as 10 A and the resistance (R) of the resistor is given as 2 ohms. Substituting these values into the above formula, we get:

V = 10 A × 2 ohms = 20 volts

Therefore, the voltage of the battery is 20 volts.

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Mary walked north from her home to Sheila's home, which is 4.0 kilometers away. Then she turned right and walked another 3.0 kilometers to the supermarket, which is 5.0 kilometers from her own home. She walked the total distance in 1.5 hours. What were her average speed and average velocity?

A.
Her average speed was about 4.6 km/hr, and her average velocity was about 3.3 km/hr.
B.
Her average speed was about 3.3 km/hr, and her average velocity was about 4.6 km/hr.
C.
Her average speed was about 3.3 km/hr, and her average velocity was 0 km/hr.
D.
Her average speed was 0 km/hr, and her average velocity was about 4.6 km/hr.

Answers

Her average speed was about 4.6 km/hr, and her average velocity was about 3.3 km/hr.

The entire distance travelled divided by the total time taken is the definition of average speed. In this case, the total distance travelled was 7.0 km, and the total time taken was 1.5 hours. Hence, the average speed can be determined as follows:

Average Speed = [tex]\frac{7.0 km }{ 1.5 \ hours }= 4.6 km/hr[/tex]

The displacement divided by the whole time travelled is the average velocity. In this case, the displacement was 3.0 km (from Mary's home to Sheila's home), and the total time taken was 1.5 hours.The average velocity can therefore be determined as follows:

Average Velocity = [tex]\frac{3.0 km }{1.5 \ hours} = 3.3 km/hr[/tex]

Therefore,Her average velocity was roughly 3.3 km/hr, and her average speed was roughly 4.6 km/hr.

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A 208g sample of sodium-24 decays to 13.0g of sodium-24 within 60.0 hours. What is the half life of this radioactivity isotope?

Answers

Answer:

15 hours

Explanation:

formula: f(a) = a(0.5)^(T/t)

fill in known values: 13=208(0.5)^(60/t)

use natural log to isolate t:    ln(13/208)=ln(0.5)(60/t)

solve for t: t=15

The driver of a car with a total of 1800 kg mass is traveling at 23 m/s when he slams on the brakes, locking the wheels on the dry pavement. The coefficient of kinetic friction between rubber and dry concrete is typically 0.7. How far would the car travel if were going twice as fast

Answers

Answer:

To solve this problem, we can use the formula:

d = (v^2)/(2μg)

d = distance traveled

v = speed of the car

μ = coefficient of kinetic friction

g = acceleration due to gravity

First, let's calculate the distance traveled when the car is traveling at 23 m/s:

d = (23^2)/(2*0.7*9.81) ≈ 67.97 meters

Now, let's calculate the distance traveled when the car is going twice as fast (46 m/s):

d = (46^2)/(2*0.7*9.81) ≈ 271.88 meters

Therefore, the car would travel approximately 271.88 meters if it were going twice as fast.

HELPPPP LATE HOMEWORK DUE TODAY

Answers

If F₁ has a greater magnitude than F₂, the box will accelerate backward because the net force is in the backward direction (1st option)

How do i know which direction the box will move to?

To obtain the direction in which the box will move, we shall determine the net force acting on the box. This is illustrated below:

Assumption:

Magnitude of force 1 (F₁) = 40 NMagnitude of force 2 (F₂) = 25 NNet force (F) =?

Net force = Magnitude of force 1 (F₁) - Magnitude of force 2 (F₂)

Net force = F₁ - F₂

Net force = 40 - 25

Net force = 15 N backward

From the above illustration, we can see that the net force is 15 N backward.

Thus, we can conclude from the box will accelerate backward (1st option)

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460miles per hour with the wind nd 420 per hour gainst the wind

Answers

The speed of the wind is 20 miles per hour.

To solve this problem, we can use the formula:

Speed = Distance/Time

Let's assume that the speed of the wind is x miles per hour.

With the wind, the plane travels at a speed of 460 miles per hour. This means that its speed relative to the ground is the sum of its airspeed and the speed of the wind:

460 = Airspeed + x

Against the wind, the plane travels at a speed of 420 miles per hour. This means that its speed relative to the ground is the difference between its airspeed and the speed of the wind:

420 = Airspeed - x

We can solve this system of equations to find the airspeed of the plane:

460 = Airspeed + x

420 = Airspeed - x

Adding the two equations gives:

880 = 2Airspeed

Dividing both sides by 2 gives:

Airspeed = 440 miles per hour

Now that we know the airspeed of the plane, we can find the speed of the wind by substituting this value into one of the equations we obtained earlier:

460 = Airspeed + x

460 = 440 + x

x = 20

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The voltage of a battery is V and the current is I. If the voltage is doubled to 2V, what is the new current?
O 1/4
O 21
O 1/2
041

Answers

Answer:The current in a lightbulb with a voltage of 35.0 V and a resistance of 175 ohm is 0.2 A.

Find the current in a lightbulb?

Given:

The voltage in a lightbulb is given by the equation V=IR

V is the voltage, I is current, and R is the resistance.

The voltage of the lightbulb is given as 35.0 V.

The resistance of the lightbulb is given as 175 Ohm.

As the equation is given,

V= IR

where I is current, R is resistance and V is the voltage.

Now, I = V/R

As the value of Voltage and resistance of the lightbulb is given, we will put in the above equation, we get;

I = 35.0/ 175 A

I = 0.2 A.

Hence, the current of the lightbulb is 0.2 A.

Therefore, Option C is the correct answer.

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Explanation:

1. A 8.2 kg mass hanging from a spring scale is slowly lowered onto a vertical spring.

A) What does the spring scale read just before the mass touches the lower spring?
B) The scale reads 14 N when the lower spring has been compressed by 2.4 cm . What is the value of the spring constant for the lower spring?
C) At what compression length will the scale read zero?

Answers

The spring scale read just before the mass touches the lower spring is 80.36N, the spring constant for the lower spring is 2765N/m and at 2.9cm length the scale will read zero.

Given the mass of spring = 8.2kg

The force exerted for compressing of spring = 14N

The compression in spring = 2.4cm = 0.024m

(A.) Initially the spring scale reads only the weight of the mass = mg

W = 8.2 * 9.8 = 80.36N

(B) Let the value of spring constant = k

The net force exerted so that the scale reads(F') = 80.36N - 14 = 66.36N

We know that according to Hooke's law the force exerted on spring F = kx such that:

F' = kx then:

66.36 = k * 0.024

k = 66.36/0.024 = 2765N/m

(C) the compression where scale reads zero = x'

The scale reads zero when the restoring force equals to the weight of the mass then the scale reads zero such that:

x' = 80.36/2765 = 0.029m = 2.9cm

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Gas pressure is defined as
Select one:
O a. mass per unit area
O b.
O c. force per unit area
O d. force per unit volume
acceleration per unit volume

Answers

Answer: b. force per unit area.

Explanation:

Pulse transfers a
disturbance. while wave is a
disturbance that transfers energy.

Answers

Answer:

Pulse transfers a single disturbance, while wave is a continuous disturbance that transfers energy.

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Work Energy Theorem Question: You apply 50 N to a 10 kg object to cause it to move from rest to 2.5 m/s. What distance was the object moved?

Answers

Answer:

0.625 meters

Explanation:

We can use the work-energy that the work done on an object is equal to the change in its kinetic energy:

Work = ΔK = Kf - Ki

Where:

Work is the work done on the object

ΔK is the change in kinetic energy of the object

Kf is the final kinetic energy of the object

Ki is the initial kinetic energy of the object (which is zero since the object is at rest)

The work done on the object is equal to the force applied to the object multiplied by the distance over which the force is applied:

Work = F × d

Where:

F is the force applied to the object (50 N)

d is the distance over which the force is applied (unknown)

So we can write:

F × d = Kf - Ki

Substituting the given values:

50 N × d = 1/2 × 10 kg × (2.5 m/s)^2 - 0

Simplifying:

50 N × d = 31.25 J

Solving for d:

d = 31.25 J / 50 N = 0.625 m

Therefore, the object was moved a distance of 0.625 meters.

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A similar device includes a transformer so that an MP3 player can also be charged. The primary coil has 300 turns.

(a) How many turns are needed in the secondary winding if the voltage is stepped up from 6.2 V to 15.5 V?

(b) Given that the current in the primary winding is 10 mA, what power is transmitted to the secondary windings if the transformer is 77% efficient?​

Answers

The secondary coil needs 120 turns.The power transmitted to the secondary winding is 0.155 W.

How does the voltage change between the primary and secondary coil in a transformer?

A transformer works by using electromagnetic induction to transfer electrical energy between two circuits. The voltage changes between the primary and secondary coil based on the ratio of the number of turns in each coil. In a step-up transformer, the voltage is increased from the primary to the secondary coil, while in a step-down transformer, the voltage is decreased.

What are some common uses for transformers in electronic devices?

Transformers are commonly used in electronic devices to convert voltage levels, isolate circuits, and match impedances. They are often used in power supplies to step down the voltage from the wall outlet to a level that can be used by the device. They are also used in audio amplifiers to match the impedance of the output to the speaker, and in radio and television receivers to tune in to different frequencies.

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You leave Fort worth ,Texas,at 2:41 p.m. and arrive in Dallas at 3:23 p.m. , covering a distance of 58km. what is your average speed in metres per second ?​

Answers

Answer:

Explanation:

The time taken to travel from Fort Worth to Dallas is:

t = 3:23 pm - 2:41 pm = 42 minutes = 0.7 hours

The distance covered is:

d = 58 km

The average speed is:

v = d/t = 58 km / 0.7 hours = 82.86 km/h

To convert km/h to m/s, we can use the conversion factor:

1 km/h = 0.2778 m/s

Therefore, the average speed in m/s is:

v = 82.86 km/h × 0.2778 m/s/km = 23.06 m/s (rounded to two decimal places)

So the average speed is 23.06 m/s.

What is the momentum of a 2.3 kg ball rolling at 6 m/s?

Show your work

Answers

Answer:

13.8 (kgm)/s

Explanation:

p(momentum) = m (mass) * v (velocity)

p= 2.3 * 6

p = 13.8

A 300 g football is kicked with an initial velocity of 140 m/s in a direction that
makes a 30° angle with the horizon. Find the peak height of the football.

Answers

Answer:

Explanation:

Assuming that air resistance is negligible, we can use the following kinematic equations to solve for the peak height:

v_f^2 = v_i^2 + 2ad

where v_f = 0 m/s (at the peak height) and a = -9.8 m/s^2 (acceleration due to gravity)

and

d = v_i t + (1/2)at^2

where d is the displacement or the peak height we want to find, v_i is the initial velocity, t is the time it takes to reach the peak height.

First, we need to resolve the initial velocity into its vertical and horizontal components:

v_i_x = v_i cos(30°) = 121.1 m/s

v_i_y = v_i sin(30°) = 70.0 m/s

Next, we can use the vertical component of the initial velocity to find the time it takes to reach the peak height:

v_f = v_i_y + at

0 m/s = 70.0 m/s + (-9.8 m/s^2)t

t = 7.14 s

Finally, we can use the time we found and the kinematic equation for displacement to find the peak height:

d = v_i_y t + (1/2)at^2

d = (70.0 m/s)(7.14 s) + (1/2)(-9.8 m/s^2)(7.14 s)^2

d = 247.5 m

Therefore, the peak height of the football is 247.5 meters.

HELP
Complete the ray diagram below:

The image characteristics are ____. (2 points)

A concave mirror is shown with curvature positioned at 8 on a ruler that goes from 0 to 14 centimeters. The object is located at 5, and the focal point is located at 6.5.


upright, virtual, and smaller

upright, real, and same size

inverted, virtual, and smaller

inverted, real, and same size

Answers

Real, inverted, and same size are the features of the image. when A concave mirror with a curvature of 8 is displayed on a ruler with a range of 0 to 14 cm.

The mirror formula may be used to calculate the image distance for an item located 4 cm from a 1.5 cm focal length mirror.

1/f = 1/u+1/v

f is the focal length

u is the object distance

v is the image distance

Keep in mind that the concave mirror's image distance and focal length are both positive.

Given:

u = 4cm

f = 1.5cm

1/v = 1/1.5-1/4

1/v = 0.67-0.25

1/v = 0.42

v = 1/0.42

v = 2.38cm

The picture is Genuine and INVERTED since the image distance value is positive.

We shall find its magnification and see if it is magnified or lessened. It is amplified if the magnification is larger than 1, and it is decreased if it is less.

Magnification = v/u

Magnification = 2.38/4

Magnification = 0.595 or. 0.6

The picture is reduced in size since the magnification is less than one (SMALLER).

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A 4.0-kg mass is moving to the right at 3.0 m/s. An 8.0 kg mass is moving to the left at 2.0 m/s. If after collision the two
masses join together, what is their velocity after collision?
O-0.33 m/s
O-0.20 m/s
O +1.4 m/s
O +2.3 m/s

Answers

Answer:

- 0.33 m/s

Explanation:

An illustration is shown above,

In this case, since the two objects move in opposite directions before collision, then move together, the formula to be used is,

m1u1 - m2u2 = (m1 + m2)v

Where,

m1 = mass of the first object

u1 = initial velocity of the first object

v1 = final velocity of the first object

m2 = mass of the second object

u2 = initial velocity of the second object

v2 = final velocity of the second object

Therefore,

(4.0 • 3.0) - (8.0 • 2.0) = (4.0 + 8.0)v

12 - 16 = 12v

-4 = 12v

Divide both sides by 12,

-4 / 12 = 12v / 12

-1 / 3 = v

v = -0.33 m/s

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How have astronomers used models to explain galactic evolution through mergers and collisions? Use this model to explain how astronomers might test their understanding of the physical processes of the universe.

Answers

Answer:

Astronomers use computer models to simulate the process of galactic evolution through mergers and collisions. These models are based on our current understanding of the physical laws that govern the behavior of matter and energy in the universe. By running simulations of galactic mergers and collisions, astronomers can test their understanding of how these physical processes work in practice and how they contribute to the formation and evolution of galaxies.

One way that astronomers might test their understanding of the physical processes of the universe is by comparing the predictions of their models to observations of real galaxies. For example, if a model predicts that a particular type of galaxy should have a certain shape, size, or distribution of stars, astronomers can compare these predictions to observations of actual galaxies to see if they match up. If there is a discrepancy between the model's predictions and the observations, this can indicate that there are some physical processes that are not well understood or included in the model.

Another way that astronomers might test their understanding is by looking for patterns or trends in the properties of galaxies that are consistent with the predictions of their models. For example, if a model predicts that galaxies that have undergone a recent merger should have a particular distribution of gas and dust, astronomers can look for evidence of this pattern in observations of real galaxies. If they find that the predicted pattern is consistently observed in a large sample of galaxies, this can provide support for the model's predictions and the physical processes that it includes.

Overall, computer models of galactic evolution through mergers and collisions provide a powerful tool for astronomers to test their understanding of the physical processes of the universe. By comparing the predictions of their models to observations of real galaxies and looking for consistent patterns and trends, astronomers can refine their understanding of how galaxies form and evolve over time.

A stone is dropped in a mine shaft 15 m deep. The speed of sound is 343 m/s. How long does it take to hear the echo?

Answers

It takes 0.1311 seconds to hear the echo of the stone.

How to calculate the time it takes to hear the echo of the stone.

First we need to determine the time it takes for the sound wave to travel from the stone to the bottom of the mine shaft and back up to our ears.

Let's start by finding the time it takes for the sound wave to reach the bottom of the mine shaft. We can use the formula:

time = distance / speed

The distance is the depth of the mine shaft, which is 15 meters. The speed of sound is 343 m/s, as given in the problem. Therefore, the time it takes for the sound wave to reach the bottom of the mine shaft is:

time = 15 m / 343 m/s

time = 0.0437 s

Now, we need to find the time it takes for the sound wave to travel back up to our ears. Since the sound wave travels at the same speed, 343 m/s, the distance it needs to cover is twice the depth of the mine shaft, or 30 meters. Therefore, the time it takes for the sound wave to travel back up to our ears is:

time = 30 m / 343 m/s

time = 0.0874 s

Finally, to find the total time it takes to hear the echo, we add the time it takes for the sound wave to reach the bottom of the mine shaft to the time it takes to travel back up to our ears:

total time = 0.0437 s + 0.0874 s

total time = 0.1311 s

Therefore, it takes 0.1311 seconds to hear the echo of the stone.

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Which correctly describes a different evolutionary stage of a star like the sun

A) it’s forms from a cold, dusty molecular cloud

B) During a yellow giant stage, it burns carbon in its core and helium in the shell surrounding the core.

C) After leaving the main sequence, its core is stable due to electron degeneracy

D) It becomes a white dwarf after exploding as a supernova

E)During a red giant stage, its core contracts and cools

Answers

The statement that correctly defines an evolutionary stage of a star like the sun is that after leaving the main sequence, its core is stable due to electron degeneracy. That is option C.

What are the stage of life cycle of a star?

The stages of the life cycle of a star include the following:

Giant Gas CloudProtostarT-Tauri PhaseMain SequenceRed GiantThe Fusion of Heavier ElementsSupernovae and Planetary Nebulae

The evolutionary stage is also called the main sequence stage of the life cycle of the star.

In this stage, the core temperature reaches the point for the fusion to occur whereby the protons of hydrogen are converted into atoms of helium. This leads to the stability of the core of the newly formed start due to electron degeneracy.

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Sound travels through air at a speed of 342m/s
342
m
/
s
at room temperature. What is the frequency of a sound wave with a wavelength of 1.8m
1.8
m

Answers

Answer:

Explanation:

The formula relating the speed of sound, frequency, and wavelength is:

speed = frequency x wavelength

Rearranging this formula to solve for frequency:

frequency = speed / wavelength

Substituting the given values:

frequency = 342 m/s / 1.8 m

frequency = 190 Hz

Therefore, the frequency of the sound wave is 190 Hz.

A block of mass m1=3.0kg rests on a frictionless horizontal surface. A second block of m2=2.0kg hangs from an ideal cord of negligible mass that runs over an ideal pulley and then is connected to the first block . the blocks are released from rest . determine the displacement of the velocityA block of mass m1=3.0kg rests on a frictionless horizontal surface. A second block of m2=2.0kg hangs from an ideal cord of negligible mass that runs over an ideal pulley and then is connected to the first block . the blocks are released from rest . Determine how far has block 1 moved during the 1.2-s interval?
A) 13.4 m
B) 2.1 m
C) 28.2m
D) 7.6m​

Answers

The answer is:

D. 7.6m

Dish Network sent a satellite into orbit around 36000 km above the Earth's surface. What is the speed of the Satellite in miles per hour?
G=6.67 x 10^-11
M Earth = 5.98 x 10^24 kg
R Earth = 6.37 x 10^6 m

A. 306889 mi/hr
B. 6,864.38 mi/hr
C. 6.86491 mi/hr
D. 9.8mi/hr

Answers

Answer:

Explanation:

First, we need to use the formula for the speed of an object in circular orbit:

v = sqrt(GM/R)

where G is the gravitational constant, M is the mass of the Earth, R is the distance between the center of the Earth and the satellite.

Converting the units to meters and kilograms:

G = 6.67 × 10^-11 m^3/kg s^2

M = 5.98 × 10^24 kg

R = (36000 + 6.37 × 10^6) × 1000 = 4.23 × 10^7 m

Plugging in the values:

v = sqrt((6.67 × 10^-11) × (5.98 × 10^24) / (4.23 × 10^7))

v ≈ 3075.58 m/s

Finally, we can convert this to miles per hour:

v = 3075.58 m/s x (3600 s/hr) / (1609.34 m/mi) = 6873.18 mi/hr

Therefore, the answer is option A. 306889 mi/hr is incorrect.

6. An 8000.0 kg truck starts off from rest and reaches a velocity of 18.0 m/s in 6.00 seconds. What is the truck’s acceleration and how much momentum does it have after it has reached this final velocity?

Answers

The truck's acceleration is 3.0m/s² and the momentum of the truck is  144000 kg m/s.

What is acceleration?

It is the rate at which the speed and direction of a moving object vary over time.

We can use the following equation to calculate the acceleration of the truck:

a = (v - u) / t

where

a = acceleration

v = final velocity = 18.0 m/s

u = initial velocity = 0 m/s (the truck starts from rest)

t = time taken = 6.00 s

Substituting the values, we get:

a = (18.0 m/s - 0 m/s) / 6.00 s

a = 3.00 m/s²

Therefore, the acceleration of the truck is 3.00 m/s².

We can use the following equation to calculate the momentum of the truck:

p = m * v

where

p = momentum

m = mass of the truck = 8000.0 kg

v = final velocity = 18.0 m/s

Substituting the values, we get:

p = 8000.0 kg * 18.0 m/s

p = 144000 kg m/s

Therefore, the momentum of the truck after it has reached its final velocity is 144000 kg m/s.

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Explain how a balloon is able to keep its shape?

Answers

Answer:

It depends on how they are made.

Explanation:

Rubber balloons are not always spherical in shape. When filled with air, the inflation forms a balance between the balloon material, including its shape and thickness and its elasticity and the pressure of the air. That’s what determines its shape. Although a sphere is often the shape, it could be tubular, offset, and most other shapes.



A metal filament Lamp rated at 750w, 100v into be connected in series with a capacitor across a 230v, 60hz supply. Calculate the capacitance required

Answers

Answer : 0.00885 farads or 8.85 microfarads

Explanation: To calculate the capacitance required, we can use the following formula:

C = 1 / [2 * pi * f * ((V^2 - Vlamp^2)/P)]

where:

C = capacitance in farads (F)

pi = 3.14159...

f = frequency in hertz (Hz)

V = voltage in volts (V)

P = power in watts (W)

Vlamp = voltage of the lamp in volts (V)

Using the given values, we have:

C = 1 / [2 * pi * 60 * ((230^2 - 100^2)/750)]

C = 1 / [2 * 3.14159 * 60 * ((230^2 - 100^2)/750)]

C = 1 / [113.09724]

C = 0.00885 farads (F)

Therefore, the capacitance required is approximately 0.00885 farads or 8.85 microfarads.

Match these items.
changes mechanical energy to heat energy, force x distance, rubbing energy ,using energy wisely, can cause heat pollution

work is done
collision
friction
stewardship
nuclear
energy

Answers

Mechanical energy to heat energy is collision,force x distance is work done,rubbing energy friction, stewardship is using energy wisely and nuclear energy can cause heat pollution.

EnergyThere are six different types of energy: chemical, electrical, radiant, mechanical, thermal, and nuclear. Other forms including electrochemical, auditory, electromagnetic, and others might be described in other study.Kinetic energy is the term for the energy that drives motion. Kinetic energy includes electrical and mechanical energy.Energy is the ability to conduct work in physics. It may exist in potential, kinetic, thermal, electrical, chemical, nuclear, or other other forms. Moreover, there is heat and work, which is energy moving from one body to another.

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The units of voltage are
Oohms, amps, volts
Oamps, volts, ohms
Ovolts, ohms, amps
Ovolts, amps, ohms
of current are
and of resistance are

Answers

Answer:24 volts ÷ 4 amps = 6 ohms

Explanation:

We know that the Ohm's law has given the relationship between the current, voltage and the resistance of the wire. Mathematically, it can be written as :

Where

I is the current

R is the resistance

If current flowing is 4 amps and voltage is 24 volts. The formula to find the resistance will be :

R = 6 Ohms

Hence, the correct option is (d) " 24 volts ÷ 4 amps = 6 ohms ".


How could you use the game of baseball to explain the difference between
inertia and momentum?

Answers

Explanation:

Inertia refers to the tendency of an object to resist changes in its motion. In baseball terms, a baseball that is at rest on the ground has a high level of inertia because it is resistant to moving until an external force, such as a player's bat, acts on it.

Momentum, on the other hand, is the product of an object's mass and velocity and refers to the quantity of motion that an object possesses. In baseball terms, a baseball that is moving at a high velocity, such as when it is hit by a bat, has a high level of momentum.

To illustrate the difference between inertia and momentum in baseball, consider the scenario of a baseball that is hit by a bat. Before the bat hits the ball, the ball is at rest and has a high level of inertia. However, once the bat hits the ball, the ball gains momentum and begins to move. As the ball moves, it continues to possess momentum, but its inertia gradually decreases as it encounters external forces, such as air resistance and friction from the ground, which act to slow it down.

What was the angle of application of the force of 35 if on a distance of 15 the work of 350 was done?

Answers

The Answer is 48.19 degrees
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