The volume of 100% ethanol required to make 900 ml of 60% (v/v) solution ethanol in water is 540 ml.
To calculate the volume in ml of 100% ethanol required to make 900 ml of 60% (v/v) solution ethanol in water, you will need the following formula:
C1V1 = C2V2
Where C1 is the initial concentration of the solution (in this case, 100%), V1 is the initial volume of the solution (unknown), C2 is the final concentration of the solution (in this case, 60%), and V2 is the final volume of the solution (900 ml).
To solve for V1, we can rearrange the formula as follows:
V1 = (C2V2) / C1
Plugging in the values, we get:
V1 = (0.60 * 900) / 1.00
V1 = 540 ml
Therefore, you will need 540 ml of 100% ethanol to make 900 ml of a 60% (v/v) solution of ethanol in water.
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which of the combinations below will produce an insoluble salt? a) ba(oh)2 hcl b) mnso4 pb(no2)2 c) h2so4 albr3
The combination that will produce an insoluble salt is b) MnSO4 Pb(NO2)2.
A salt is a chemical compound made up of cations (positively charged ions) and anions (negatively charged ions) (negatively charged ions). The ions must be combined in such a way that the sum of the charges is zero. NaCl is the most well-known saltand it is made up of sodium cations (Na+) and chloride anions (Cl-).MnSO4 Pb(NO2)2 is the answer since both of these elements are soluble. MnSO4 is a soluble substance that is sometimes used in the production of ceramics.
MnSO4 is often used as a nutritional supplement for animals since it is a good source of manganese. Pb(NO2)2 is a powder that is bright yellow, it has a molar mass of 325.2 g/mol. It is made up of two NO2 anions (negatively charged ions) and one Pb2+ cation (positively charged ion).The formation of insoluble salts can occur when the cations and anions in a reaction solution bind to create a new solid. Since the newly formed solid is insoluble, it settles to the bottom of the solution and can be separated from the liquid through filtration. The insoluble salt that is formed is a white or colorless substance that appears as a powder.
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ra and p criss cross method
Answer:
Ra3P2
Explanation:
Ra is +2
P is -3
Ra3P2
which type of chemical formula tells how many atoms of each element are in a molecule but does not indicate their arrangement?
Answer: The type of chemical formula that tells how many atoms of each element are in a molecule but does not indicate their arrangement is a molecular formula.
What is a molecular formula?
A molecular formula is a chemical formula that displays the exact number of atoms of each element in one molecule of a compound, but it does not reveal how the atoms are arranged in a molecule.
A molecular formula is a symbolic representation of a molecule’s elements and the number of atoms of each element present in one molecule of that substance.
A molecular formula provides information about the kinds of atoms present in a molecule and the number of each kind of atom present, but it does not provide information about the structure of the molecule.
In other words, a molecular formula only tells us the number of atoms of each element present in a molecule and not their arrangement.
What is a chemical formula?
A chemical formula is a method of expressing the structure of a molecule in a short, concise form. Chemical formulas depict the number of atoms of each element in a molecule using chemical symbols, numerals, and other chemical shorthand. Chemical formulas can be used to represent both ionic and covalent compounds.
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How many atoms are in 32.10 g of He
4.83 x 10^24 atoms are there in 32.10 g of He.
To determine the number of atoms in 32.10 g of He, we first need to convert the mass to moles using the atomic mass of He, which is 4.003 g/mol.
number of moles of He = 32.10 g / 4.003 g/mol = 8.024 mol He
Next, we use Avogadro's number, which is 6.022 x 10^23 atoms/mol, to calculate the number of atoms in 8.024 mol of He:
8.024 mol He x 6.022 x 10^23 atoms/mol = 4.83 x 10^24 atoms
Therefore, there are approximately 4.83 x 10^24 atoms in 32.10 g of He.
Atoms are the fundamental matter units that comprise everything around us, from the air we breathe to the food we consume. They are made up of three different sorts of particles: protons, neutrons, and electrons.
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which of the following properties affects a substance's saturation temperature? multiple choice question. pressure mass volume
The property that affects a substance's saturation temperature is Pressure.
What is saturation temperature?Saturation temperature is the temperature at which a liquid and a gas have the same vapor pressure. The vapor pressure of a liquid is affected by temperature, and at the saturation temperature, the vapor pressure of the liquid equals the pressure of the surrounding atmosphere.
A substance's saturation temperature is influenced by several variables. Pressure is one of the variables that influences the saturation temperature of a substance. When the pressure surrounding a substance rises, its saturation temperature rises.
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A hand of bananas is a small bunch made up of 5 bananas ( each banana is called a finger). If a large bunch of bananas is made up of 10 hands, how many bananas does it contain?
There are 50 bananas total in the enormous bunch of bananas.
How many bananas are there in a bunch?There are 10 bunches of bananas, and each bunch has 5 bananas; therefore, there are 50 bananas in all.The difference between a hand and a bunch of bananas. A finger is a single banana. A hand is made up of five to six fingers.A group of hands are all on one stem.Each bunch of bananas that a banana tree produces will eventually perish and need to be removed. Within a year, a fresh shoot will emerge from the rhizome to create a fresh bunch.Visit for more information on a bunch of bananas.
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why is the hybridization model necessary to explain the bonding in a molecule such as ch4? select all that apply.
It helps explain why there are 4 equivalent C-H bonds in CH4,It allows for a better representation of the arrangement of electrons in the molecule, and It helps explain why the dipole moment of the molecule is zero.
What is hybridization?Hybridization is the process of combining two or more distinct entities to create a new, unique entity that has a combination of the characteristics of the original entities. It can be used to describe a wide range of phenomena, ranging from the breeding of plants and animals to the intermixing of different cultures.
In biology, hybridization is the process of combining the genetic material of two different species to create a hybrid organism.
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what is the symbol (including the atomic number, mass number, and element symbol) for the oxygen isotope with 9 neutrons?
The symbol for the oxygen isotope with 9 neutrons is O-16.
The atomic number of oxygen is 8, which means it has 8 protons. The mass number for oxygen-16 is 16, which refers to the total number of particles in the nucleus (8 protons + 8 neutrons). The element symbol for oxygen is O.
Isotopes are atoms that have the same number of protons but different numbers of neutrons.
Oxygen-16 has a total of 9 neutrons, meaning it has one more neutron than the most common isotope of oxygen (oxygen-15, with 8 neutrons).
Due to the difference in neutron numbers, the atomic mass of oxygen-16 is slightly larger than oxygen-15.
Atomic mass is the combined mass of all of the protons and neutrons in an atom's nucleus. In oxygen-16, the protons and neutrons have a combined mass of 16, hence the mass number of 16.
Oxygen-16 is an important isotope because it is present in significant amounts in the Earth's atmosphere and is used in numerous medical and scientific applications.
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organic molecules are those that contain at least multiple choice carbon. carbon and oxygen. carbon and hydrogen. carbon, oxygen, and hydrogen.
Organic molecules are those that contain carbon and often hydrogen atoms bonded together, and they are the building blocks of life.
Carbon is an element that is essential to life on Earth and is the central atom in organic compounds. It can form covalent bonds with other elements such as hydrogen, oxygen, nitrogen, and sulfur.
Carbon has the unique ability to form long chains of molecules, branched structures, and rings that are essential to the structure and function of organic molecules.
Organic molecules include carbohydrates, lipids, proteins, and nucleic acids. Carbohydrates are sugars and starches that provide energy to living organisms.
Lipids are fats and oils that are important for insulation and energy storage. Proteins are complex molecules that carry out many functions in the body, such as catalyzing chemical reactions and providing structure to cells.
Nucleic acids are DNA and RNA, which carry genetic information and are essential for the synthesis of proteins.
Oxygen is another element that is essential to life on Earth. It is often found in organic molecules, especially in carbohydrates and lipids.
Oxygen is important for respiration, the process by which living organisms use energy stored in organic molecules to carry out cellular processes.
In respiration, oxygen reacts with organic molecules such as glucose to produce carbon dioxide, water, and energy in the form of ATP.
Organic molecules contain carbon and often hydrogen atoms bonded together, and they are the building blocks of life.
Carbon has the unique ability to form long chains of molecules, branched structures, and rings that are essential to the structure and function of organic molecules.
Oxygen is another element that is often found in organic molecules and is important for respiration.
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Suppose that an ion has an absorption line at a rest wavelength of 1000.0 nm. this line is shifted to 1000.1 nm in the spectrum of a star. how fast is the star moving? hint: the doppler shift formula is (vrad/c)
The star is moving by a velocity of 3 *10^{5}.
The formula for the Doppler shift is given by
f2/f1 = (c-v)/c,
where c is the speed of light, v is the velocity of the moving object, and f1 and f2 are the emitted and received frequencies of light, respectively.
The Doppler effect occurs when the light source and the observer are moving relative to one another, giving the impression that the light's frequency has changed.
The Doppler effect alters the frequency of light from a moving source, shifting it either to the red or blue. This resembles (but does not necessarily mimic) the behavior of other types of waves, such as sound waves.
The star is moving away from the observer because the wavelength of the spectral line has shifted to a longer wavelength.
doppler shift
Thus, the velocity is given by the formula
:v/c = (Δλ/λ)
where is the rest wavelength and is the change in wavelength.
v/c = (Δλ/λ)v/c = (1000.1 - 1000.0)/1000.0v/c = 0.0001/1000.
0v/c = 1e-7v = (1e-7) × c = 300 × 1e-7 = 3e-5
The star is moving away from the observer at a velocity of[tex]3 *10^{5}[/tex]m/s.
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How many oxygen atoms are there in 2 molecules of CH3ClO?
One molecule of this substance has the molecular formula CH₂ClO, which is methoxychloro. to ascertain how many oxygen atoms there are in 2 molecules of methoxychloro.
What do two oxygen atoms in a molecule represent?
To create dioxygen, or oxygen, two oxygen atoms must make a covalent double bond with one another. Typically, oxygen exists as a molecule. It has the name dioxygen.
With an electrical configuration of (2, 6) and an atomic number of 8, oxygen lacks two more electrons to complete an octet. By exchanging two pairs of electrons with another oxygen atom, the oxygen atom becomes stable. A diatomic oxygen molecule is one that contains two oxygen atoms.
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a solution is made by dissolving 8424 mg of sodium chloride, nacl, in 0.1711 kg of water. what is the concentration in parts per billion?
The concentration of sodium chloride (NaCl) in the solution is 840,000 parts per billion (ppb).
To calculate this, divide the mass of sodium chloride (8424 mg) by the mass of water (0.1711 kg), then multiply the result by 1 billion (10^9).
To calculate the concentration of a solution, you must first determine the mass of the solute (NaCl in this case). The mass of the solute is given in the question as 8424 mg.
The mass of the solvent (water) is given as 0.1711 kg.
To calculate the concentration of the solution, divide the mass of the solute by the mass of the solvent, and then multiply the result by 1 billion (10^9).
In this example, 8424 mg divided by 0.1711 kg is equal to 49,336,297, which multiplied by 1 billion is equal to 49,336,297,000,000, or 840,000 parts per billion (ppb).
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how many electrons does cl want to gain? hint: how many are gained to form a stable noble gas electron configuration, ns2 np6 (octet rule)?
Chlorine (Cl) is a nonmetal, meaning it has the tendency to gain electrons to achieve the electron configuration of a noble gas. The noble gas electron configuration of the nearest noble gas, argon (Ar), is 1s2 2s2 2p6 3s2 3p6, with a total of 18 electrons.
Chlorine has 7 valence electrons, meaning it needs 1 more electron to achieve a stable noble gas electron configuration. Therefore, chlorine wants to gain 1 electron to achieve a stable noble gas configuration.
In terms of bonding, chlorine can either gain 1 electron to form an anion with a 1- charge or it can share electrons with another atom to form a covalent bond. Chlorine most commonly forms a single covalent bond with another atom, such as hydrogen, to form hydrogen chloride (HCl). In this case, both atoms share electrons to form a stable molecule.
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A gas sample at constant pressure and temperature filled with Helium gas had a volume of 221 mL and 4.00 moles. If the volume is increased to 500 ml what is the number of moles of Helium gas that could occupy the container? 0.11 K 9.05 kPa 0.11 kPa 9.05 mol
The number of moles of Helium gas that could occupy the container when the volume is increased to 500 mL is 9.05 mol.
What is the number of moles of the gas?We can use the combined gas law to solve this problem:
(P1 x V1) / (n1 x T1) = (P2 x V2) / (n2 xT2)
where;
P is pressure, V is volume, n is number of moles, and T is temperature.We know that the pressure and temperature are constant, so we can simplify the equation to:
V1/n1 = V2/n2
Solving for n2, we get:
n2 = (V2n1) / V1
Plugging in the values, we get:
n2 = (500 mL * 4.00 mol) / 221 mL
n2 = 9.05 mol
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t a fixed temperature and number of moles, the initial volume and pressure of a helium gas sample are 153 ml and 433 torr, respectively. what is the final volume in ml, if the final pressure is 67.1 torr?
Answer:
yes because temperature is the moles of the initial respectively in the volume torr and 433 torr fixed the temperature heliums gas sample by 153 ml thank you
the identity of an unknown monoprotic organic acid is determined by titration. a 0.173 g sample of the acid is titrated with 0.157 m naoh. what is the molar mass of the compound if 6.12 ml of the naoh solution is required to neutralize the sample?
The molar mass of the unknown monoprotic organic acid is 180.0 g/mol. by titration. If 6.12 ml of the naoH solution is required to neutralize the sample.
In order to determine the molar mass of the unknown monoprotic organic acid, follow the steps given below:
Step 1:
Calculate the number of moles of NaOH used in the titration by using the formula given below:
n(NaOH) = M(NaOH) × V(NaOH)
= 0.157 mol/L × 0.00612 L
= 9.62 × 10^-4 mol
Step 2:
Calculate the number of moles of the acid used in the titration by using the formula given below:
n(acid) = n(NaOH)
= 9.62 × 10^-4 mol
Step 3:
Calculate the mass of the acid used in the titration by using the formula given below:
mass(acid) = n(acid) × M(acid) = 0.173 gM(acid) = mass(acid) / n(acid)
= 0.173 g / 9.62 × 10^-4 mol
= 180.0 g/mol
Therefore, the molar mass of the unknown monoprotic organic acid is 180.0 g/mol.
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a solution of cacl2 cacl 2 in water forms a mixture that is 31.5% 31.5 % calcium chloride by mass. if the total mass of the mixture is 195.4 g, 195.4 g, what masses of cacl2 cacl 2 and water were used?
The masses of calcium chloride (CaCl2) and water used to form the mixture are 61.18 g and 134.22 g, respectively.
The mass of calcium chloride (CaCl2):
The percentage of calcium chloride (CaCl2) in the mixture is 31.5%.
Multiply the total mass of the mixture (195.4 g) by 31.5% to find the mass of calcium chloride (CaCl2) in the mixture:
Mass of calcium chloride (CaCl2) = (195.4 g) x (31.5%) = 61.18 g
The mass of water:
Subtract the mass of calcium chloride (CaCl2) from the total mass of the mixture (195.4 g) to find the mass of water in the mixture:
Mass of water = (195.4 g) - (61.18 g) = 134.22 g
Therefore, masses of calcium chloride (CaCl2) and water used to form the mixture are 61.18 g and 134.22 g, respectively.
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what is the specific rotation of pure (s)-carvone if a sample of (r)-carvone of 85% ee has a specific rotation of -52?
(+61.3) is the specific rotation of pure (s)-carvone if a sample of (r)-carvone of 85% ee has a specific rotation of -52.
A chiral chemical compound's unique rotation is a characteristic in chemistry. It is described as the shift in monochromatic plane-polarized light's orientation, expressed as the product of distance and concentration, as the light passes through a sample of a substance dissolved in solution. Dextrorotary substances are those that spin a plane polarised light beam's polarisation plane clockwise, and they correlate to positive specific rotation values.
[α] = α / (c×l)
[α] =specific rotation
α = observed rotation
c=concentration in g/mL
l =path length in dm
[α] = (-52)/(1×1)
= -52
(-52) = (0.85)×αr + (0.15)×αs
αs= (-52 - 0.85×αr) / 0.15
[α] = αs
= (-52 - 0.85αr) / 0.15
(-52) = (0.85)(+112.0) + (0.15)α
α = (+61.3)
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calculate the density (in grams per milliliter) for a glass marble with a volume of 7.94 ml and a mass of 15.36 g.
To calculate the density (in grams per milliliter) for a glass marble with a volume of 7.94 ml and a mass of 15.36 g, you must divide the mass by the volume. In this case, the density would be 1.93 g/mL.
To solve this problem mathematically:
Step 1: Identify the mass (m) and volume (v) of the marble.
Mass (m) = 15.36 g
Volume (v) = 7.94 mL
Step 2: Divide the mass by the volume to calculate the density.
Density (d) = m/v
Density (d) = 15.36 g / 7.94 mL
Density (d) = 1.93 g/mL
Therefore, the density of the glass marble is 1.93 g/mL.
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A pie can be cut into eight slices. What is the minimum number of pies you would need if you were to serve a slice of pie with each cup of hot chocolate in item 6? How many slices of pie would be left over?
(a) We would need 7 pies to serve a slice of pie with each cup of hot chocolate.
(b) There would be 6 slices of pie left over.
What is number of pies that will be left over?From item 6, we know that there are 50 cups of hot chocolate to be served.
Since each pie can be cut into 8 slices, we would need to serve 50/8 = 6.25 pies.
Since we cannot serve a fractional pie, we would need to round up to the next whole number of pies, which is 7.
To find out how many slices of pie would be left over, we need to calculate the total number of slices of pie and subtract the number of slices used to serve the hot chocolate.
Total number of slices of pie = 7 pies x 8 slices per pie = 56 slices
Number of slices used to serve the hot chocolate = 50 slices
Therefore, the number of slices of pie left over would be:
56 slices - 50 slices = 6 slices
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plot a theoretical distillation curve of temperature (y-axis) vs. volume in ml (x-axis) for a 15 ml of a mixture containing 60% 1-propanol and 40% 2-propanol. are these two compounds easier to separate by distillation than cyclohexane and toluene? explain your answer. (6 pts)
To plot a theoretical distillation curve please follow the steps while we continue our discussion. Since their boiling point difference is higher it is easier to separate Cyclohexane and toluene by distillation than 1-propanol and 2-propanol.
How to separate two compounds by distillation?Plot a theoretical distillation curve of temperature (y-axis) vs. volume in ml (x-axis) for a 15 ml mixture containing 60% 1-propanol and 40% 2-propanol, follow these steps:
1. Determine the boiling points of 1-propanol and 2-propanol. 1-propanol has a boiling point of 97°C, while 2-propanol has a boiling point of 82°C.
2. Calculate the volumes of each compound in the mixture. 60% of 15 ml is 9 ml (1-propanol) and 40% of 15 ml is 6 ml (2-propanol).
3. Plot the boiling points of each compound on the y-axis, and their respective volumes on the x-axis.
4. Draw a curve connecting the two points to represent the theoretical distillation curve.
To determine if 1-propanol and 2-propanol are easier to separate by distillation than cyclohexane and toluene, compare the boiling point differences between the compounds. The boiling point difference between 1-propanol and 2-propanol is 15°C (97°C - 82°C). The boiling point difference between cyclohexane and toluene is 34°C (110°C - 76°C).
Since the boiling point difference between cyclohexane and toluene is greater than that of 1-propanol and 2-propanol, it can be concluded that cyclohexane and toluene are easier to separate by distillation than 1-propanol and 2-propanol.
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you have a stock solution of 0.6 molar sucrose, and want to prepare 3 ml of 0.24 molar sucrose solution. what are the correct amounts of 0.6 m sucrose and water that you will need to use?
Answer : To prepare 3 mL of 0.24 M sucrose solution from a stock solution of 0.6 M sucrose, 1.2 mL of the stock solution and 1.8 mL of water should be used.
The amount of 0.6 Molar sucrose needed to prepare 3 mL of 0.24 Molar sucrose solution, as well as the volume of water required, can be calculated using the M1V1 = M2V2 formula. Where M1 is the molarity of the stock solution, V1 is the volume of the stock solution required, M2 is the desired molarity of the solution to be prepared, and V2 is the volume of the solution to be prepared.
Given that the stock solution of sucrose is 0.6 M, and we need to prepare 3 mL of a 0.24 M solution, we can use the formula:
0.6 M x V1 = 0.24 M x 3 mL Solving for V1:
V1 = (0.24 M x 3 mL)/0.6 M
V1 = 1.2 mL
This means that 1.2 mL of the stock solution of 0.6 M sucrose is required to prepare 3 mL of 0.24 M sucrose solution.
The volume of water required can be calculated by subtracting the volume of the stock solution from the total volume of the solution to be prepared: Volume of water = 3 mL - 1.2 mL and Volume of water = 1.8 mL
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4. a laboratory experiment calls for 0.150 m hno3. what volume of 0.150 m hno3 can be prepared form 0.350 l of 1.98 m hno3?
The volume of 0.150 M HNO3 that can be prepared from 0.350 L of 1.98 M HNO3 is 0.07112 L, or approximately 71.12 mL (since 1 L = 1000 mL).
The given equation is used to calculate the volume (V1) of a desired concentration of a solution (0.150 M HNO3) that can be prepared from a given volume (V2) of a known concentration solution (1.98 M HNO3), using the ratios of their concentrations (C1 and C2).
Let's break down the calculation step by step using the given values:
V2 (given volume) = 0.350 L
C1 (desired concentration) = 0.150 M
C2 (known concentration) = 1.98 M
Plugging these values into the equation, we get:
V1 (0.150 M HNO3) = V2 (1.98 M HNO3) x (C1 (0.150 M) / C2 (1.98 M))
V1 = 0.350 L x (0.150 M / 1.98 M)
V1 = 0.350 L x 0.0758
V1 = 0.07112 L
Therefore, the volume of 0.150 M HNO3 that can be prepared from 0.350 L of 1.98 M HNO3 is 0.07112 L, or approximately 71.12 mL (since 1 L = 1000 mL).
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Describe how finding the formula differs between Ionic and Covalent compounds.
Answer:
covalent compounds
CsF
Nao
CHN
PCI
CAO
NH
WO
lonic compounds
CS
CdBr
N
SOS
if the rate constant for a reaction triples when the temperature rises from 25 oc to 65 oc, what is the activation energy of the reaction? give answer in kj/mole.
The activation energy of the reaction, given that the rate constant has tripled when the temperature rose from 25 °C to 65 °C, is 42.6 kJ/mole.
Activation energy is the minimum energy required for a reaction to take place. It is calculated using the Arrhenius equation, which states that the rate constant, k, is proportional to the exponential of negative activation energy (Ea) divided by the gas constant (R) multiplied by the absolute temperature (T).
As the rate constant has tripled when the temperature increased, the activation energy can be calculated as Ea = -R * (1/T2 - 1/T1).
Plugging in the given temperature values of 25 °C and 65 °C and the gas constant, R, the activation energy is 42.6 kJ/mole.
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why is it important not to dilute the initial sample befoe it has been loaded onto the chromatography column
It is important not to dilute the initial sample before loading it onto the chromatography column because this can negatively impact the separation and resolution of the components in the sample.
Dilution can lead to a decrease in the concentration of the components in the sample, which can result in poor separation and overlap of the peaks. Additionally, dilution can cause loss of the target compound or impurities in the sample due to adsorption onto the walls of the container used for dilution.
By keeping the sample concentrated and loading it directly onto the chromatography column, the chances of obtaining a clear separation and good resolution of the components in the sample are increased
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predict which of the following 0.1m solutions would have the lowest freezing point: mg(cl)2, catechin, or sucrose. explain your reasoning.
The freezing point of a 0.1m solution is determined by its solute concentration, and the type of solute affects the freezing point and it will be Catechin.
The lowest freezing point will be found in the solution with the lowest solute concentration.
In this case, catechin has the lowest solute concentration of 0.001 mol/L, so it will have the lowest freezing point.
The freezing point of a solution is also affected by the type of solute present.
Magnesium chloride (MgCl2) and sucrose both have high molecular weights, and therefore will decrease the freezing point more than catechin. Therefore, catechin will still have the lowest freezing point.
The freezing point of a solution can also be affected by the presence of electrolytes.
Magnesium chloride is an electrolyte, which means it will dissociate in water and lower the freezing point more than catechin or sucrose. Therefore, catechin still has the lowest freezing point.
In summary, catechin has the lowest freezing point of the three solutions (MgCl2, catechin, and sucrose) because it has the lowest solute concentration and does not contain any electrolytes.
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in a 55.0-g aqueous solution of methanol, ch4o, the mole fraction of methanol is 0.100. what is the mass of each component?
The mass of methanol in a 55.0-g aqueous solution of methanol, CH4O, is 5.53 g and the mass of water is 27.91 g. when the mole fraction of methanol is 0.100.
The mass of each component in a 55.0-g aqueous solution of methanol, CH4O, can be found by using the mole fraction of methanol (0.100).
First, calculate the total number of moles of the solution:
55.0 g x (1 mol/32.04 g) = 1.72 moles
Then, calculate the number of moles of methanol:
1.72 moles x (0.100 mole fraction) = 0.172 moles
Finally, calculate the mass of each component:
Methanol mass: 0.172 moles x (32.04 g/mol) = 5.53 g
Water mass: 1.72 moles - 0.172 moles = 1.55 moles x (18.02 g/mol) = 27.91 g
Therefore, the mass of methanol in a 55.0-g aqueous solution of methanol, CH4O, is 5.53 g and the mass of water is 27.91 g.
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Complete orbital diagrams (boxes with arrows in them) to represent the electron configuration of valence electrons of carbon before and after sp hybridization Drag the appropriate labels to their respective targets. Labels can be used once, more than once, or not at all. Reset Help Before hybridization 2s 2p After hybridization sp 2p
The electron configuration of valence electrons of carbon before and after sp hybridization are shown below:Before hybridization: 2s2 2p2After hybridization: sp2 2p2The orbital diagram before sp hybridization shows two electrons in the 2s orbital and two electrons in each of the 2p orbitals. After hybridization, the 2s orbital mixes with one of the 2p
orbitals to form two sp hybrid orbitals. These sp hybrid orbitals are oriented at 180° to each other, which allows maximum overlap with two 2p orbitals of the carbon atom. The remaining 2p orbital remains unhybridized and
unchanged. Therefore, the hybridized orbitals contain only one electron each and the unhybridized 2p orbital has two electrons.The boxes with arrows in the orbital diagram represent the orbitals and their electrons. The label "2s" is
dragged to the box representing the 2s orbital before hybridization. Similarly, the labels "2p" and "sp" are dragged to the boxes representing the unhybridized and hybridized orbitals after hybridization, respectively. The label "2p" is also dragged to the unhybridized 2p orbital after hybridization.
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a sample of xe takes 75 seconds to effuse out of a container. an unknown gas takes 37 seconds to effuse out of the identical container under identical conditions. what is the most likely identity of the unknown gas?
The most likely identity of the unknown gas that effuses taking 37s is Oxygen(O₂).
Since the unknown gas effuses out faster, it must be lighter than Xe.
The most likely identity of the unknown gas can be determined using Graham's Law of Diffusion. According to this, the time taken for effusion/diffusion of two different gases under identical conditions is directly proportional to the square roots of their densities or molecular masses. It is given as:
t₂/t₁ = √(M₂/M₁)
where t₂,t₁ are the times taken and M₂, M₁ are the molecular masses.
This ratio is determined by the ratio of the molecular weights of the unknown gas and the sample of Xe. The heavier the molecular weight, the slower the rate of effusion.
Rearranging and plugging in the values as t₂= 75s, t₁= 37s, M₁= 131g (for Xe), we get M₂ as follows:
M₂= (37/75)² x 131 = 31.8 ≈ 32g
32g corresponds to the molecular weight of O₂ and it is lighter than Xe.
Therefore, the unknown gas that effuses out of the container faster than the sample of Xe, resulting in the unknown gas taking 37 seconds, and the sample of Xe taking 75 seconds is oxygen(O₂).
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