Calculate the volume of a cone with a height of 6 inches and a diameter of 6 inches.
Leave your answer in terms of PI

Answers

Answer 1

Answer: Volume ≈ 56.55

Step-by-step explanation:

56.54867 is the answer, but I rounded it. I hope this helped! :)

Answer 2

Answer:

18π cubic inches

Step-by-step explanation:

First, we need to find the radius of the cone, which is half of the diameter.

radius = diameter/2 = 6/2 = 3 inches

The formula for the volume of a cone is:

V = 1/3 × π × r^2 × h

where r is the radius of the base of the cone, and h is the height of the cone.

Substituting the values we get:

V = 1/3 × π × 3^2 × 6

V = 1/3 × π × 9 × 6

V = π × 18


Related Questions

100 POINTS HELP PLEASE IM DESPERATE !!!!!!!!!!!!!!!!!!!!

If AB¯¯¯¯¯¯¯¯
is translated right 5
units and down 2
units, what are the coordinates of A′,
the image of point A?

Line Segment A B with coordinates A negative 5, 2 & B negative 2, 6.

Answers

So basically you gotta go uo down left right up up down agian that ur answer
The coordinates for A’ would be (0,0)

Can someone please help me

Answers

Rate of change= (y2-y1)/(x2-x1), in this case the rate of change is 2
2

the formula for rate of change is
(Y2 - Y1)/(X2-X1).

Plug in any 2 random coordinates.

(6-4)/(5-4)

2/1

2

Find the volume of the triangular prism; do not round.

Answers

Answer:

[tex]\boxed{\mathtt{Volume=33.55m^{3}}}[/tex]

Step-by-step explanation:

[tex]\textsf{For this problem, we are asked to find the Volume of a Triangular Prism.}[/tex]

[tex]\large\underline{\textsf{What is Volume?}}[/tex]

[tex]\textsf{Volume is the amount of space a figure occupies. Volume is measured in Cubic units.}[/tex]

[tex]\large\underline{\textsf{We are Given;}}[/tex]

[tex]\textsf{The Height is 6.1m. Keep in mind that the Height is the Perpendicular Distance}[/tex]

[tex]\textsf{between 2 bases.}[/tex]

[tex]\textsf{The base is; (4.4 x 2.5).}[/tex]

[tex]\textsf{The Height of the Triangle is 2.5m.}[/tex]

[tex]\large\underline{\textsf{Necessary Formulas;}}[/tex]

[tex]\mathtt{Volume=(Base) \times Height}[/tex]

[tex]\mathtt{Area = \frac{1}{2} (Base \times Height)}[/tex]

[tex]\large\underline{\textsf{For this Problem;}}[/tex]

[tex]\mathtt{Volume=(Triangles' \ Area) \times Height}[/tex]

[tex]\large\underline{\textsf{The area of a Triangle is;}}[/tex]

[tex]\mathtt{Area = \frac{1}{2} (Base \times Height)}[/tex]

[tex]\textsf{Find the area of the base first.}[/tex]

[tex]\large\underline{\textsf{Substitute;}}[/tex]

[tex]\mathtt{Area = \frac{1}{2} (4.4 \times 2.5)}[/tex]

[tex]\boxed{\mathtt{Area = 5.5m^{2}.}}[/tex]

[tex]\textsf{We know the Base, now let's find the volume of the figure.}[/tex]

[tex]\large\underline{\textsf{Substitute;}}[/tex]

[tex]\mathtt{Volume=5.5 \times 6.1}[/tex]

[tex]\boxed{\mathtt{Volume=33.55m^{3}}}[/tex]

[tex]\huge\text{Hey there!}[/tex]


[tex]\huge\textsf{Find the \boxed{\bf volume} of a triangular prism is:}[/tex]

[tex]\mathsf{\dfrac{1}{2}(\boxed{\bf b}ase\times\boxed{\bf h}eight\times\boxed{\bf l}ength) = \boxed{\bf v}olume}[/tex]


[tex]\huge\textsf{Your \boxed{\bf equation} should look like:}[/tex]

[tex]\mathsf{volume = \dfrac{1}{2}(4.4\ m \times 2.5\ m\times 6.1\ m)}[/tex]


[tex]\huge\textsf{\boxed{\bf Step-by-step} explanation can be:}[/tex]

[tex]\mathsf{volume = \dfrac{1}{2}(4.4\ m \times 2.5\ m\times 6.1\ m)}[/tex]

[tex]\mathsf{volume = \dfrac{1}{2}\times 4.4\ m \times 2.5\ m\times 6.1\ m}[/tex]

[tex]\mathsf{volume = 0.5\times 4.4\ m \times 2.5\ m\times 6.1\ m}[/tex]

[tex]\mathsf{volume = 2.2\ m\times 15.25\ m}[/tex]

[tex]\mathsf{volume = 33.55}[/tex]


[tex]\huge\textsf{Therefore your \boxed{\bf answer} should be:}[/tex]

[tex]\huge\boxed{\mathsf{volume = 33.55m^2}}\huge\checkmark[/tex]


[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]



~[tex]\frak{Amphitrite1040:)}[/tex]
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