Central angles are made of two​

The prοbability that mοre than 2 animals need tο stay οvernight is apprοximately 0.9124, οr 91.24%.

The binοmial distributiοn is a prοbability distributiοn that describes the number οf successes in a fixed number οf independent trials, each with the same prοbability οf success. The distributiοn is characterized by twο parameters: the number οf trials (n) and the prοbability οf success (p) fοr each trial.

Tο sοlve this prοblem, we need tο use the binοmial distributiοn since we have a fixed number οf trials (25 animals brοught in) and each trial (animal) can either be a success (needs tο stay οvernight) οr a failure (dοesn't need tο stay οvernight).

Let X be the number οf animals that need tο stay οvernight. Then X fοllοws a binοmial distributiοn with n = 25 trials and p = 0.2 prοbability οf success (animal needing tο stay οvernight).

We want tο find the prοbability that mοre than 2 animals need tο stay οvernight, which can be expressed as:

nοw, P(X > 2) = 1 - P(X ≤ 2)

Tο calculate P(X ≤ 2), we can use the binοmial cumulative distributiοn functiοn (CDF) οr simply add up the prοbabilities οf X = 0, X = 1, and X = 2:

similarly, P(X ≤ 2) = P(X = 0) + P(X = 1) + P(X = 2)

[tex]= (0.8)^{25} + 25(0.2)(0.8)^{24} + (25\ \text{choose}\ 2)(0.2)^{2}(0.8)^{23}[/tex]

≈ 0.0876

Therefοre, P(X > 2) = 1 - P(X ≤ 2) ≈ 1 - 0.0876 = 0.9124

Sο the prοbability that mοre than 2 animals need tο stay οvernight is apprοximately 0.9124, οr 91.24%.

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If lisa is on her way home in her car, she has driven 24 miles so far, which is three-fourths of the way home, Lisa's total drive is 32 miles.

Let's represent the total length of Lisa's drive as x. We know that she has driven 24 miles so far, which is three-fourths of the total length. We can write this information as:

24 = (3/4) x

To find x, we need to isolate it on one side of the equation. We can start by multiplying both sides by 4/3 to get rid of the fraction:

24 * (4/3) = x

Simplifying, we get:

32 = x

We can say that Lisa has already driven 24 miles, which is three-fourths of the total distance. To find the total distance, we use the equation 24 = (3/4) x, where x represents the total distance.

To solve for x, we multiply both sides of the equation by 4/3 to cancel out the fraction, giving us 32 = x. Therefore, Lisa's total drive is 32 miles.

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The angle of elevation of the sun is 38.24 degrees (rounded to two decimal places).

The ratio of the height of the tree and the length of the shadow can be found by using the formula for tan which is given by:

tan(x) = (opposite/hypotenuse)

In the given problem statement, the height of the tree is opposite to the angle we are trying to find and the length of the shadow is the hypotenuse of the right-angled triangle. Therefore, we can say that:

tan(x) = opposite/hypotenuse = 86/110

We can use the inverse tangent function to find the value of x. This is because tan is the ratio of the opposite side (height of the tree) to the adjacent side (length of the shadow), and the inverse tangent function gives the angle that has that ratio.

So, tan x = 86/110 => x = tan⁻¹ (86/110) = 38.24 degrees (rounded to two decimal places). Therefore, the angle of elevation of the sun is 38.24 degrees.

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the probability that there are at most 2 defective components in the box is approximately 0.9044 and the probability of having at most 3 defective components out of 250 boxes is very close to zero.

a) Let X be the number of defective components in a box of 10 components. Then X follows a binomial distribution with n=10 and p=0.01, since the probability of a component being defective is 0.01. We want to find the probability that there are at most 2 defective components in the box, i.e., P(X ≤ 2).

Using the binomial probability formula, we get:

P(X ≤ 2) = P(X = 0) + P(X = 1) + P(X = 2)

= (10 choose 0) × 0.01⁰ × 0.99¹⁰ + (10 choose 1) × 0.01¹ × 0.99⁹ + (10 choose 2) × 0.01² × 0.99⁸

= 0.90438222

Therefore, the probability that there are at most 2 defective components in the box is approximately 0.9044 (rounded to four decimal places).

b) We want to find the probability of having at most 3 defective components out of 250 boxes, each containing 10 components. Since np = 100.01 = 0.1 < 5 and n × (1-p)=10 × 0.99=9.9 > 5, we can use the normal approximation to the binomial distribution, with mean μ = np = 2.5 and standard deviation σ = √np(1-p) = 1.577.

Let X be the number of boxes with at most 3 defective components. Then X follows an approximate normal distribution with mean μ' = np=2.5250 = 625 and standard deviation σ' = √np(1-p)) = 12.5 × 1.577 = 19.712.

We want to find P(X ≤ 250), which can be written as P(X < 251) since X is a discrete variable. Using the continuity correction, we can approximate this probability as P(X < 251.5). Then we standardize the variable:

z = (251.5 - μ')/σ' = (251.5 - 625)/19.712 = -18.919

Using a standard normal table or calculator, we find that P(Z < -18.919) is a very small number, practically zero. Therefore, the probability of having at most 3 defective components out of 250 boxes is very close to zero.

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Complete Question

factory produces components of which 1% are defective. The components are packed in boxes of 10. A box is selected by random a) Find the probability that there are at most 2 defective components in the box b) Use a suitable approximation to find the probability of having at most 3 defective (inclusive 3 cases) components out of 250.

Answer:772

Step-by-step explanation:

SA=PH+2b

SA=(10+8+10+8)(17)+2(8x10)

SA=772

Answer:

Step-by-step explanatin

multiply all of them

The transformation that would not result in a congruent figure when performed on triangle RST is A. A dilation by a scale factor of 2 with respect to point R.

The equation that has the same solution as the system of equations is C. 4x + 9y = 10

4x + 6y = 24.

Transformations that change the shape or size of a figure can change its congruency.  A dilation is a transformation that changes the size of a figure so this would mean that RST dilated would not result in a congruent figure.

When the system of equations, 4x + 9y = 10, 2x + 3y = 12 is solved, we find that x = 13 and y = - 14/ 3.

Options A,B, and D cannot have the same value because the numbers are the same and so they should have different values., Only option C can be the same and when the values are slotted in, this is proven.

Option C, 4x + 9y = 10 , 4x + 6y = 24 is therefore correct.

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Based on the boxplot, approximately 25% of these Ayrshire cattle had a butterfat percentage higher than 8.3%.

To determine this, we can look at the boxplot and see that the third quartile (Q3) is at 8.3%. Since 25% of the data is greater than 8.3%, we can infer that 25% of these Ayrshire cattle had a butterfat percentage higher than 8.3%. To further explain, a boxplot is a graphical representation of the five-number summary of a dataset, which consists of the minimum, first quartile (Q1), median (Q2), third quartile (Q3), and maximum.

The boxplot is divided into two parts, the box and the whiskers. The box indicates the interquartile range (IQR) which is the difference between the third and first quartile. The whiskers represent the minimum and maximum of the dataset. The median is shown by a line within the box. In this boxplot, the first quartile (Q1) is 6.7%, the median (Q2) is 7.4%, and the third quartile (Q3) is 8.3%. Therefore, based on the boxplot, about 25% of these Ayrshire cattle had a butterfat percentage that was higher than 8.3%.

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Complete Question : Based on the boxplot, about 25% of these ayrshire cattle had a butterfat percentage that was higher than?

let's firstly convert the mixed fractions to improper fractions and then add them up.

[tex]\stackrel{mixed}{1\frac{12}{15}}\implies \cfrac{1\cdot 15+12}{15}\implies \stackrel{improper}{\cfrac{27}{15}}~\hfill \stackrel{mixed}{1\frac{5}{15}} \implies \cfrac{1\cdot 15+5}{15} \implies \stackrel{improper}{\cfrac{20}{15}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{27}{15}~~ + ~~\cfrac{20}{15}\implies \cfrac{27~~ + ~~20}{\underset{\textit{denominator is the same}}{15}}\implies \cfrac{47}{15}\implies 3\frac{2}{15}[/tex]

Answer:

28/51

Step-by-step explanation:

First you add up all the values: 28 + 15 + 8 = 51. That is your denominator because the total is the denominator. Then you put 28 as your numerator because that's how many off all the people that only like pizza.

Answer:

[tex]y-3=-\frac{3}{2}(x-2)[/tex]

Step-by-step explanation:

In order to find an equation that is parallel, it must have the same slope. This means the y intercept could literally be anything.

By equation of the line, we can write it in point slope form

[tex]y-y1=m(x-x1)[/tex]

where y1 and x1 are points on the coordinate plane and m is the slope.

We are already given the slope, so we just plug in the numbers.

[tex]y-3=-\frac{3}{2}(x-2)[/tex]

Therefore, the average velocity of the person over the interval 0 ≤ t ≤ 12 can be calculated as follows:Average Velocity = Total distance travelled / Total time taken= 6.6 / 12= 0.55 m/s.

In the given question, we need to find the average velocity of a person running in a straight line across a field, given differentiable function v(t) on the interval [0,12]. Therefore, to calculate the average velocity of a person, we use the following formula:Average Velocity = Total distance travelled / Total time takenWe have a graph with the velocity of the person, which is a differentiable function v(t) given above on the interval 0 ≤ t ≤ 12.

We need to find the distance travelled by the person. Therefore, we use the following formula:Distance travelled = ∫v(t)dt From the given graph, the velocity of the person is zero when t = 0 and when t = 5. Similarly, the velocity of the person is 0 when t = 10 and when t = 12.So, we have to calculate the distance travelled from 0 to 5, from 5 to 10, and from 10 to 12 to determine the total distance travelled by the person over the given interval .Distance travelled from 0 to 5 can be calculated as follows :

Distance travelled from 0 to 5 = ∫v(t)dt from [tex]0 to 5= 5 x 0.6 = 3[/tex]Distance travelled from 5 to 10 can be calculated as follows :Distance travelled from 5 to 10 = [tex]∫v(t)dt[/tex] from [tex]5 to 10= 5 x 0.4 = 2[/tex]

Distance travelled from 10 to 12 can be calculated as follows: Distance travelled from 10 to 12 = ∫v(t)dt from 10 to 12= 2 x 0.8 = 1.6Total distance travelled = Distance travelled from 0 to 5 + Distance travelled from 5 to 10 + Distance travelled from 10 to [tex]12= 3 + 2 + 1.6= 6.6[/tex]

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Answer:L x b

              98ft x 56ft =5488

                                  =5488 / $3.75= $1463.47

Step-by-step explanation: Play ground is more like a rectangle so we use the formula for the rectrectangle to get total area . A=Lxb

Divide  the total with the cost since it say each per sqr feet

A=lxb

98x56=5488

5488/3.75= 1463.47

There are 120 different ways to form the dance delegation from five pairs of dance partners if two dance partners can never be together on the delegation.

The total number of ways to form the delegation from five pairs of dance partners can be calculated using the combination formula. The combination formula is used to calculate the number of different combinations of n objects taken r at a time without repetition.

In this question, n is the total number of dance partners (5) and r is the number of people on the delegation (4).

Therefore, the calculation is as follows:

total number of ways = nCr

                    = 5C4

                    = 5! / 4!(5-4)!

                    = 5! / 4!1!

                    = 5 x 4 x 3 x 2 x 1 / 4 x 1 x 1

                    = 5 x 4 x 3 x 2

                    = 120

Hence, there are 120 different ways to form the dance delegation from five pairs of dance partners if two dance partners can never be together on the delegation.

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The student should record the area of the paper as option (c) 602 cm^2

The student measured the length and width of a single sheet of paper and was asked to calculate its surface area. The surface area of the paper is the product of its length and width, which can be calculated by multiplying the two measurements together.

The surface area of the paper can be calculated as the product of the length and the width

Surface area = length × width

Substituting the given measurements, we get

Surface area = 43 cm × 14 cm

Surface area = 602 cm^2

Therefore, the correct option is (c) 602 cm^2

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The given question is incomplete, the complete question is;

A student is calculating the surface area of a single sheet of paper. he measures the length to be 43 cm he measures the width to be 14cm the student should record the area of the paper as (a) 602.64 cm^2 . (b) 602.6 cm^2 . (c) 602 cm^2 . (d) 603 cm^2 .

Answer:

15 Full orbits per day

Step-by-step explanation:

To work out the number of full orbits the ISS does in 1 day, we need to know how long it takes for the ISS to complete one orbit around the Earth.

We can use the information given to us to calculate the time it takes for the ISS to complete one orbit:

Distance traveled in one orbit = 42,600 kilometers

Speed of the ISS = 27,576 kilometers per hour

To calculate the time taken for one orbit:

Time taken = Distance traveled / Speed

Time taken = 42,600 kilometers / 27,576 kilometers per hour

Time taken = 1.54 hours (rounded to 2 decimal places)

So, the ISS takes approximately 1.54 hours to complete one orbit around the Earth.

Now, we can calculate the number of orbits the ISS does in one day:

Number of orbits per day = 24 hours / Time taken for one orbit

Number of orbits per day = 24 hours / 1.54 hours

Number of orbits per day = 15.58 (rounded to 2 decimal places)

Therefore, the ISS completes approximately 15 full orbits around the Earth in one day.

The number of different ways to order 11 different pictures in a photo album is 39,916,800.

To calculate this number, we can use the formula for permutations, which is:

n! / (n - r)!

where n is the total number of items to choose from (in this case, 11 pictures) and r is the number of items to be selected (also 11, since we want to order all the pictures).

Plugging in the values, we get:

11! / (11 - 11)! = 11! / 0! = 11!

We can simplify 11! as:

11! = 11 x 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1

Using a calculator or by hand, we can find that 11! equals 39,916,800.

Therefore, there are 39,916,800 different ways to order 11 different pictures in a photo album.

Hence, the number of ways to order 11 pictures in a photo album can be calculated using the permutation formula, which gives a total of 39,916,800 possible arrangements.

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To perform the opposite translation, we add the opposite of the translation vector to the image point A': the coordinates of point A are (16, 5).

what is a vector?

In mathematics, a vector is an object that represents a quantity having both magnitude (or length) and direction. Vectors can be represented geometrically as arrows, where the length of the arrow represents the magnitude of the vector and the direction of the arrow represents the direction of the vector.

To find the coordinates of point A, we need to perform the opposite translation of moving along the vector 〈−6, 0〉 from the image point A'(10, 5). This is because a translation is a rigid motion that preserves the distance between points, so the distance between A and A' is the same as the distance between their respective translations.

To perform the opposite translation, we add the opposite of the translation vector to the image point A':

A = A' - 〈-6, 0〉 = (10, 5) - (-6, 0) = (16, 5)

Therefore, the coordinates of point A are (16, 5).

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Answer:

x = ±9

Step-by-step explanation:

If x² = k, then x = ±√k.

x² - 81 = 0

x² = 81

x = ±√81

x = ±9

End of unit 4 assessment on right triangle trigonometry is an evaluation of a student's understanding of the basic concepts and applications of trigonometry involving right triangles.

This assessment may cover topics such as the trigonometric functions, Pythagorean theorem, special right triangles, and solving right triangles.

Trigonometry is the study of the relationships between the angles and sides of triangles, particularly right triangles. It is a branch of mathematics that has numerous applications in fields such as physics, engineering, and astronomy.

The trigonometric functions are sine, cosine, and tangent, which are ratios of the sides of a right triangle. These functions can be used to solve problems involving angles and sides of right triangles, such as finding the missing side or angle.

The Pythagorean theorem is another fundamental concept in right triangle trigonometry. It states that in a right triangle, the square of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides.

Special right triangles, such as the 30-60-90 triangle and the 45-45-90 triangle, have specific ratios of their side lengths that can be used to solve problems more easily.

Solving right triangles involves finding the measures of all the angles and sides of a right triangle given certain information, such as the length of one side and the measure of one angle.

In conclusion, the end of unit 4 assessment on right triangle trigonometry evaluates a student's understanding of the basic concepts and applications of trigonometry involving right triangles. This assessment is important for students to demonstrate their mastery of the subject and to prepare them for further studies in mathematics and related fields.

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End of unit 4 assessment right triangle trigonometry describe the importance of Side ratios in right triangles as a function of the angles ?

a.) The mode for the chart is 24.

b.) The probability that the winning score will be 25 = 7/50

C.)The probability that the winning score will be 23 or more = 37/50.

The number of times the game is played = 50 times

The number of games that showed the score of 25= 7

The probability of winning a score of 25 = 7/50

The scores that are 23 and above; 10+14+7+4+2= 37

The probability of winning a score of 23 and above = 37/50

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We must prioritize biblical teachings and values over the cultural trends of the day. We should be salt and light to the world and live our lives in a way that honours God.

As Christians, it is our responsibility to be salt and light to the world. The dominant culture may be a reflection of the majority of the population's thoughts, but it may not necessarily align with the Bible's teachings. We should not be swayed by the current trends and instead prioritize God's standards.

The counterculture of the 1960s, according to some, promoted ideas that are contrary to Christian teachings. Many people who were part of this movement advocated for sexual freedom, drug use, and rebellion against authority. Christians should not have supported these behaviours or beliefs since they are inconsistent with biblical principles.

Likewise, in today's world, there are areas in which Christians must not conform to the dominant culture. One of the primary areas where Christians may be tempted to conform is in terms of sexual morality. Many people believe that premarital sex and homosexuality are acceptable practices, but these beliefs are not supported by the Bible.

As a result, Christians should not follow these cultural trends, but rather stick to biblical teachings and live their lives according to God's standards.Another example is in regards to materialism. The desire to accumulate wealth and material possessions is prevalent in modern culture.

Still, Christians must resist the temptation to make money and possessions their god, as this is against the Bible's teachings. Instead, we should focus on using our resources to glorify God and help others.In conclusion, Christians must be cautious about conforming to the dominant culture.

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Answer:

Step-by-step explanation:

Not sure.

The equations without absolute value for the given conditions are: 1. y = -3x + 6 if x > 5; 2. y = -x - 6 if x < -2; 3. y = x - 6 if 3 ≤ x ≤ 5, and y = -x - 6 if x < 3.

1. When x > 5, the expression (x - 3) is positive, (x + 2) is positive, and (x - 5) is positive. Thus, to get absolute value we can rewrite the equation as:

y = (x - 3) + (x + 2) - (x - 5)

Simplifying this, we get:

y = 2x - 4

2. When x < -2, the expression (x - 3) is negative, (x + 2) is negative, and (x - 5) is negative. Thus, we can rewrite the equation as:

y = -(x - 3) - (x + 2) + (x - 5)

Simplifying this, we get:

y = -2x + 6

3. When -2 ≤ x ≤ 3, the expression (x - 3) is negative, (x + 2) is positive, and (x - 5) is negative. Thus, we can rewrite the equation as:

y = -(x - 3) + (x + 2) - (x - 5)

Simplifying this, we get:

y = 10 - x

When x > 3, the expression (x - 3) is negative, (x + 2) is positive, and (x - 5) is positive. Thus, we can rewrite the equation as:

y = -(x - 3) + (x + 2) + (x - 5)

Simplifying this, we get:

y = -2x + 6

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The fact that the sample averages are not all the same can be an illustration of the concept of the central limit theorem, while the fact that the sample averages systematically overestimate the true population average can be an illustration of the concept of bias.

The given statement is incomplete, we need additional information in order to provide a solution. It is important to provide the complete statement so that we can help you in the best way possible.

However, based on the given options, we can provide a general explanation of the concepts mentioned, which are the concepts of the central limit theorem and bias.

The central limit theorem states that the distribution of the sample means approaches a normal distribution as the sample size increases. In other words, as the sample size increases, the means of the samples drawn from a population tend to be normally distributed. The central limit theorem has important implications for statistics and hypothesis testing.

Bias, on the other hand, refers to a systematic error in data collection or analysis. Bias can be caused by a variety of factors, such as the selection of participants or the measurement instruments used. A biased sample or analysis can lead to inaccurate conclusions about a population.

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The quadratic function that only has one root at 3 and passes through the point (0,4) is: f(x) = (4/9)(x - 3)^2

A quadratic equation is a polynomial equation of degree 2, meaning that the highest exponent of the variable is 2. It has the general form:

ax^2 + bx + c = 0

If a quadratic function has only one root at 3, then it must be of the form:

f(x) = a(x - 3)^2

where a is a constant. This is because a quadratic function with only one root must have a double root, meaning that the parabola only touches the x-axis at that point and does not cross it. And a quadratic function with vertex at (3,0) and opening upwards satisfies this condition.

To determine the value of a, we can use any additional information that may be provided, such as the value of the function at another point. For example, if we know that f(0) = 4, then we can substitute these values into the equation to get:

4 = a(0 - 3)^2

4 = 9a

a = 4/9

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The quadratic function that has only one root at 3 and passes through (0,4) is: [tex]f(x)=(\frac{4}{9} )(x-3)^{2}[/tex]

A quadratic equation is a second-degree algebraic problem in x. In its standard form, the quadratic equation is [tex]ax^2+bx+c=0[/tex], where an as well as b are the coefficients, x is the variable, and c is the value of the constant component. The essential requirement for a formula to be a quadratic equation is that the coefficient of [tex]x^2[/tex] is not zero (a 0). When writing an equation with quadratic equations in conventional format, the [tex]x^2[/tex] term comes first, then the x term, and lastly the constant term.

A quadratic equation is a polynomial expression of degree 2, which means that the variable's greatest exponent is 2. It takes the following basic form:

[tex]ax^2+bx+c=0[/tex]

If the quadratic function has only one root at 3, it must have the following form:

[tex]f(x)=a(x-3)^2[/tex]

This requirement is satisfied by a quadratic function with a vertex at (3,0) and an opening upwards.

We know that f(0) = 4, so we can plug these numbers into the equation to get:

[tex]4=a(0-3)^2[/tex]

simplify the above equation

4 = 9a

The value is,

a = 4/9

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Samantha would fill in the following information on the survey sheet based on the data provided:

Sex: Female

Age: 13-14

How much pressure do you feel to achieve at school? c. A lot

Samantha, a 14-year-old girl, would complete the survey slip by selecting "Female" under "Sex," "13-14" under "Age," and "A lot" under "How much pressure do you feel to achieve at school?"

This indicates that Samantha is feeling a significant amount of pressure to succeed academically. It's common for high school students to feel pressure to perform well in school, and this can be due to various factors such as parental expectations, college aspirations, or personal goals.

As a school counselor, it's essential to understand the level of pressure students are experiencing to provide appropriate support and guidance. Identifying and addressing the sources of pressure can help students like Samantha better manage stress and achieve academic success.

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The question is -

A school counselor conducted a survey among a group of high school students using the following survey slip:

Survey (please tick the correct boxes)

Sex:  Male  Female

Age:  13-14  15 -16  17–18

How much pressure do you feel to achieve at school?

a. None b. A little c. A lot  And d. the unbearable amount

Show, by completing the survey slip on the answer sheet, how Samantha – a 14-year-old girl who feels a lot of pressure to achieve at school – would complete the survey

The given statement regarding the GDP of major economies of the world is False.

To determine the accuracy of this statement, we would need to gather data on the real GDP per capita growth rates of major economies between 1982 and 2009 and compare them. Without this data, we cannot definitively say whether the statement is true or false. However, based on historical trends and current economic data, it is unlikely that Italy had the highest growth rate of real GDP per capita during this time period.

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Therefore , the solution of the given problem of unitary method comes out to be  the composite shape's overall size is 30  square units.

Utilizing previously well-known variables, this uniform convenience, or all crucial elements from a prior flexible study that followed a particular methodology event can all be used to achieve the goal. It will be possible to contact the entity again if the anticipated assertion outcome actually happens; if it doesn't, both important systems will surely miss the statement.

Here,

We must divide the composite shape into smaller shapes and sum up their areas in order to determine the area of the composite shape.

We can see that the composite form is made up of a triangle with a base of four and a height of three, and a rectangle with dimensions of six by four.

=> length times breadth equals six by four, or 24 square units, for a rectangle.

Triangle's area is equal to

=>  (1/2) x base times height, or (1/2) x 4 times 3, or 6 square units.

As a result, the composite shape's overall size is:

=> 24 + 6 = 30  square units.

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