Compare and contrast between flowcharts that involve:
-simple logic flow and

-simple logic flow with a two way branch

Answer:

The answer to this question is given below in the explanation section. However, the correct option is Technician B.

Explanation:

There are eight steps procedures to diagnose the engine.  

Step 1 Verify the Problem

Step 2 Perform a Thorough Visual Inspection and Basic Tests

Step 3 Retrieve the Diagnostic Trouble Codes (DTCs)

Step 4 Check for Technical Service Bulletins (TSBs)

Step 5 Look Carefully at Scan Tool Data

Step 6 Narrow the Problem to a System or Cylinder

Step 7 Repair the Problem and Determine the Root Cause

Step 8 Verify the Repair and Clear Any Stored DTCs

So the correct technician is Technician B that says that the second step is to perform a thorough visual inspection.

Answer:

false

Explanation:

1 MB = 0.001 GB

Answer:

4

Explanation:

Input/output, datapath, control, and memory

There wrong its C bold it.

:)))))

Answer:

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

              //print the header

              System.out.println("**************************************");

              System.out.println("*                                    *");

              System.out.println("*                                    *");

              System.out.println("*   Gas-N-Clean Service Station      *");

              System.out.println("*                                    *");

              System.out.println("*   March 2, 2004                    *");

              System.out.println("*                                    *");

              System.out.println("**************************************");

               //set the constant values for gasoline

               final double REGULAR_GASOLINE = 2.89;

               final double PLUS_GASOLINE = 3.09;

               final double SUPER_GASOLINE = 3.39;

              // initialize the variables as 0

              double gasolinePrice = 0, gasolineCost = 0, carWashCost = 0, totalCost = 0;

               Scanner input = new Scanner(System.in);

               //ask the user to enter the gallons, gas type and car wash choice

               System.out.print("Enter number of gallons ");

               double gasolinePurchase = input.nextDouble();

               System.out.print("Enter gas type (R, P, S, or N) ");

               char gasType = input.next().charAt(0);

               System.out.print("Enter Y or N for car wash ");

               char carWashChoice = input.next().charAt(0);

               //check the gas type. Depending on the choice set the gasolinePrice from the corresponding constant value

              if(gasType == 'R')

                  gasolinePrice = REGULAR_GASOLINE;

              else if(gasType == 'P')

                  gasolinePrice = PLUS_GASOLINE;

              else if(gasType == 'S')

                  gasolinePrice = SUPER_GASOLINE;

                //calculate the gasolineCost

                gasolineCost = gasolinePurchase * gasolinePrice;

               //check the carWashChoice. If it is yes and gasolineCost is greater than 10, set the carWashCost as 1.25. Otherwise, set the carWashCost as 3.00

               if(carWashChoice == 'Y'){    

                   if(gasolineCost >= 10)

                       carWashCost = 1.25;

                   else

                       carWashCost = 3.00;

               }

              //calculate the total cost, add gasolineCost and carWashCost

              totalCost = gasolineCost + carWashCost;

               //print the values in required format

              System.out.println("Amount Gasoline purchases " + gasolinePurchase);

              System.out.println("Gallons Price per gallons $ " + gasolinePrice);

              System.out.printf("Total gasoline cost $ %.2f\n", gasolineCost);

              System.out.println("Car wash cost $ " + carWashCost);

              System.out.printf("Total due $ %.2f\n", totalCost);

               System.out.println("Thank you for stopping\nPlease come again \nRemember to buckle up and drive safely");

}  

}

Explanation:

*The code is in Java.

Please see the comments in the code for explanation

Answer:

Search

Explanation:

Because you are searching up a specific recording using keywords.

I hope this helps

Answer:

Filter

Explanation:

I got it correct for a quiz.

Answer:

Modify

If scores[index] > highest then highest = scores[index]

End Of highest

Name = students[index]

End For Display

to

If scores[index] > highest then highest = scores[index]

Name = students[index]

End Of highest

End For Display

Explanation:

In the code, you posted the code segment that gets the name of the student with the highest score is outside the if condition that determines the highest.

To make correction, we only need to bring this code segment into the loop.

See Answer

Answer:

def __str__(self):

       return ('Year: %d, VIN: %s' %(self.year_made, self.car_vin))

Explanation:

Here you go! This should do it.

The program gives an implementation of the car record class which displays the model year and registration number of a car. The program written in python 3 goes thus :

class CarRecord :

#initialize a class named carRecord

def __init__(self):

#define the init method of the class

self.year_made = 0

#year car was made is initialized to 0 (integer)

self.car_vin = ' '

#vehicle registration is an empty string

def __str__(self):

#define an str method

return f"Year:{self.year_made}, VIN:{self.car_vin}"

#returns formatted display of the year and VIN number

my_car = CarRecord()

#creates an instance of the carRecord class

my_car.year_made = int(input())

#prompts user for the model year of the car

my_car.car_vin = input()

#prompts user for the model Vin number

print(my_car)

# display the details

A sample run of the program is given

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In python:

print(steps_walked / 2000)

i = 3

while i  <= 21:

   if i % 3 == 0:

       print(i)

   i += 1

The required program written in python 3 is as follows :

num = 3

#initialize a variable called num to 3

multiples_of_3 = []

#empty list to store all multiples of 3

while num <=21 :

#while loop checks that the range is not exceeded.

if num%3 == 0:

#multiples of 3 have a remainder of 0, when divided by 3.

multiples_of_3.append(num)

#if the number has a remainder of 0, then add the number of the list of multiples

num+=1

#add 1 to proceed to check the next number

print(multiples_of_3)

#print the list

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Answer:

mobile computing system

Explanation:

Answer:

mobile computing system... C

Answer:

I hope the above picture may help you.

Answer:

The answer is interpret Proof is down below

Explanation:

Here is the proooooooffffffff i made a 90 but this one was right

Secondary sources interpret information gathered from primary sources.

A secondary source is known to be made up of discussion that is often based on a primary information source.

Hence, the feature of secondary sources are known to give some kind of interpretation to all the information that has been gathered from other primary sources.

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Answer:

Sentence: Jack or Peggy Zale must fix quickly the fax.

Correct: Either Jack or Peggy Zale must quickly fix the fax.

There are 2 errors in these sentence construction. In stating two persons as an option we must use the word "either" to indicate that you only have two choose from the two of them. The word "

Explanation:

The correct sentence would be "either Jake or Peggy Zale must quickly fix the fax".

In the question construction, there is a conjunction and misarrangement error.

In conclusion, the word " "either Jake or Peggy Zale must quickly fix the fax" is correct

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Answer:

B. The process will be terminated by the operating system.

Explanation:

When Round Robin is used for CPU scheduling, a time scheduler which is a component of the operating system is used in regulating the operation. A time limit is set for each of the processes to be run.

So, when a process fails to complete running before its time elapses, the time scheduler would log it off and return it to the queue. This queue is in a circular form and gives each of the processes a chance to run its course.

Based on the information given regarding CPU scheduling, the correct option is C. The process's state will be changed from running to blocked.

It should be noted that in a system where Round Robin is used for CPU scheduling, when a process cannot finish its computation during its current time quantum, the process's state will be changed from running to blocked.

It should be noted that a prices transition to a blocked state occurs when it's waiting for some events like a particular resource becoming available.

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Answer:

And what??????????????

Answer:

C and G

Explanation:

In C language, the asterisks, ' * ', and the ampersand, ' & ', are used to create pointers and references to pointers respectively. The asterisks are used with unique identifiers to declare a pointer to a variable location in memory, while the ampersand is always placed before a variable name as an r_value to the pointer declared.

Answer:

the clock rate of the first machine need to be 1.7 GHz

Explanation:

Given:

CPI of A = 1.9

CPI of B = 1.1

machine, B executes the same program with 20% less instructions and with a CPI of 1.1 at 800MHz

To find:

In order for the two machines to have the same performance, what does the clock rate of the first machine need to be

Solution:

CPU execution time = Instruction Count * Cycles per Instruction/ clock rate

CPU execution time = (IC * CPI) / clock rate

(IC * CPI) (A) / clock rate(A) =  (IC * CPI)B / clock rate(B)

(IC * 1.9) (A) / clock rate(A) = (IC * (1.1 * (1.0 - 0.20)))(B) / 800 * 10⁶ (B)

Notice that 0.20 is basically from 20% less instructions

(IC * 1.9)  / clock rate = (IC * (1.1 * (1.0 - 0.20))) / 800 * 10⁶

(IC * 1.9)  / clock rate =  (IC*(1.1 * ( 0.8))/800 * 10⁶

(IC * 1.9)  / clock rate =  (IC * 0.88) / 800 * 10⁶

clock rate (A) =  (IC * 1.9) / (IC * 0.88) / 800 * 10⁶

clock rate (A) =  (IC * 1.9) (800 * 10⁶) /  (IC * 0.88)

clock rate (A) = 1.9(800)(1000000)  / 0.88

clock rate (A) =  (1.9)(800000000)  / 0.88

clock rate (A) = 1520000000  / 0.88

clock rate (A) = 1727272727.272727

clock rate (A) = 1.7 GHz

Answer:

DNS

Explanation:

Hope this helps

Answer:

Well, First of all, use Linear

Explanation:

My sis always tries to explain it to me even though I know already, I can get her to give you so much explanations XD

I have the Longest explanation possible but it won't let me say it after 20 min of writing

Answer:

Yes

Explanation:

Online privacy is a controversial topic due to the fact that it's a very hard thing to navigate. Some websites use cookies that are used to store your data so in a way there taking your privacy away which is controversial because of the way they use the information. Some websites store it for use of ads while others sell it. This issue is applicable to me and my peers because of the way we use technology. It can be used to steal my information about where I live and what I look up online. Also, the information stored could have my credit or debit card credentials. This issue should be a federal and nationwide issue because this is an everyday occurrence and leaves tons of people in crushing   debt every year.

Answer:

Here is the TeeShirt class:

public class TeeShirt{  //class name

   private int orderNumber;  // private member variable of type int of class TeeShirt to store the order number

   private String size;  // to store the size of tshirt

   private String color;  //  to store the color of shirt

   private double price;  // to store the price of shirt

   public void setOrderNumber(int num){  //mutator method to set the order number

       orderNumber = num;     }    

   public void setColor(String color){  //mutator method to set the color

       this.color = color;        }      

     public void setSize(String sz){  //mutator method to set the shirt size

   size = sz;  

   if(size.equals("XXXL") || size.equals("XXL")){  //if shirt size is XXL or XXXL

       price = 22.99;  // set the price to 22.99 if shirt size is XXL or XXXL

   }else{  //for all other sizes of shirt

       price = 19.99;     }  }  //sets the price to 19.99 for other sizes

   public int getOrderNumber(){  //accessor method to get the order number stored in orderNumber field

       return orderNumber;     }  //returns the current orderNumber

   public String getSize(){  //accessor method to get the size stored in size field

       return size;     }  //returns the current size

   public String getColor(){  //accessor method to get the color stored in color field

       return color;     }  //returns the current color

   public double getPrice(){  //accessor method to get the price stored in price field

       return price;      }  } //returns the current price

Explanation:

Here is the sub class CustomTee:

public class CustomTee extends TeeShirt {  //class CustomTee that inherits from class TeeShirt

private String slogan;   //private member variable of type String of class CustomTee to store slogan

public void setSlogan(String slgn) {  //mutator method to set the slogan

slogan = slgn; }

public String getSlogan() {  //accessor method to get the slogan stored in slogan field

return slogan;}  } //returns the current slogan

Here is DemoTees.java

import java.util.*;

public class DemoTees{  //class name

public static void main(String[] args)  {  //start of main method

TeeShirt tee1 = new TeeShirt();  //creates object of class TeeShirt named tee1

TeeShirt tee2 = new TeeShirt(); //creates object of class TeeShirt named tee2

CustomTee tee3 = new CustomTee(); //creates object of class CustomTee named tee3

CustomTee tee4 = new CustomTee();  //creates object of class CustomTee named tee4

tee1.setOrderNumber(100);  //calls setOrderNumber method of class TeeShirt using object tee1 to set orderNumber to 100

tee1.setSize("XXL");  //calls setSize method of class TeeShirt using object tee1 to set size to XXL

tee1.setColor("blue");  //calls setColor method of class TeeShirt using object tee1 to set color to blue

tee2.setOrderNumber(101);  //calls setOrderNumber method of class TeeShirt using object tee2 to set orderNumber to 101

tee2.setSize("S");  //calls setSize method of class TeeShirt using object tee2 to set size to S

tee2.setColor("gray");  //calls setColor method of class TeeShirt using object tee2 to set color to gray

tee3.setOrderNumber(102);   //calls setOrderNumber method of class TeeShirt using object tee3 of class CustomTee to set orderNumber to 102

tee3.setSize("L");  //calls setSize method of class TeeShirt using object tee3 to set size to L

tee3.setColor("red");  //calls setColor method of class TeeShirt using object tee3 to set color to red

tee3.setSlogan("Born to have fun");  //calls setSlogan method of class CustomTee using tee3 object to set the slogan to Born to have fun

tee4.setOrderNumber(104);  //calls setOrderNumber method of class TeeShirt using object tee4 of class CustomTee to set orderNumber to 104

tee4.setSize("XXXL");  //calls setSize method to set size to XXXL

tee4.setColor("black");  //calls setColor method to set color to black

tee4.setSlogan("Wilson for Mayor");  //calls setSlogan method to set the slogan to Wilson for Mayor

display(tee1);  //calls this method passing object tee1

display(tee2);  //calls this method passing object tee2

displayCustomData(tee3);  //calls this method passing object tee3

displayCustomData(tee4);  }   //calls this method passing object tee4

public static void display(TeeShirt tee) {  //method display that takes object of TeeShirt as parameter

System.out.println("Order #" + tee.getOrderNumber());  //displays the value of orderNumber by calling getOrderNumber method using object tee

System.out.println(" Description: " + tee.getSize() +  " " + tee.getColor());  //displays the values of size and color by calling methods getSize and getColor using object tee

System.out.println(" Price: $" + tee.getPrice()); }  //displays the value of price by calling getPrice method using object tee

public static void displayCustomData(CustomTee tee) {  //method displayCustomData that takes object of CustomTee as parameter

display(tee);  //displays the orderNumber size color and price by calling display method and passing object tee to it

System.out.println(" Slogan: " + tee.getSlogan());  } } //displays the value of slogan by calling getSlogan method using object tee

In this exercise we have to use the knowledge in computational language in JAVA to write the following code:

We have the code can be found in the attached image.

So in an easier way we have that the code is

public class TeeShirt{  

  private int orderNumber;

  private String size;  

  private String color;

  private double price;  

  public void setOrderNumber(int num){  

      orderNumber = num;     }    

  public void setColor(String color){  

      this.color = color;        }  

    public void setSize(String sz){  

  size = sz;  

  if(size.equals("XXXL") || size.equals("XXL")){  

      price = 22.99;  

  }else{

      price = 19.99;     }  }

  public int getOrderNumber(){  

      return orderNumber;     }

  public String getSize(){  

      return size;     }  

  public String getColor(){  

      return color;     }  

  public double getPrice(){

      return price;      }  }

public class CustomTee extends TeeShirt {  

private String slogan;  

public void setSlogan(String slgn) {

slogan = slgn; }

public String getSlogan() {

return slogan;}  }

import java.util.*;

public class DemoTees{

public static void main(String[] args)  {

TeeShirt tee1 = new TeeShirt();

TeeShirt tee2 = new TeeShirt();

CustomTee tee3 = new CustomTee();

CustomTee tee4 = new CustomTee();

tee1.setOrderNumber(100);  

tee1.setSize("XXL");  

tee1.setColor("blue");  

tee2.setOrderNumber(101);

tee2.setSize("S");  

tee2.setColor("gray");  

tee3.setOrderNumber(102);  

tee3.setSize("L");

tee3.setColor("red");  

tee3.setSlogan("Born to have fun");  

tee4.setOrderNumber(104);  

tee4.setSize("XXXL");  

tee4.setColor("black");  

tee4.setSlogan("Wilson for Mayor");  

display(tee1);  

display(tee2);

displayCustomData(tee3);

displayCustomData(tee4);  }  

public static void display(TeeShirt tee) {  

System.out.println("Order #" + tee.getOrderNumber());

System.out.println(" Description: " + tee.getSize() +  " " + tee.getColor());  

System.out.println(" Price: $" + tee.getPrice()); }

public static void displayCustomData(CustomTee tee) {

display(tee);  

System.out.println(" Slogan: " + tee.getSlogan());  } }

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Answer:

speed and storage

Explanation:

The pros and cons of both are mainly in regards to speed and storage. Due to linked lists elements being connected to one another it requires that each previous element be accessed in order to arrive at a specific element. This makes it much slower than an array-based implementation where any element can be quickly accessed easily due to it having a specific location. This brings us to the other aspect which is memory. Since Arrays are saved as a single block, where each element has a specific location this takes much more space in the RAM as opposed to a linked implementation which is stored randomly and as indexes of the array itself.

Array Implementation:

Linked Implementation

Answer:

please find the attachment of a graph:

Explanation:

Description of the model:

Enhanced Entity relationships[EER] represent the requirements and complexities of a complex database.

Here, the account entity generalized into three entities and these are checking, savings, and loan.

Also, the common attribute the three of them have can be considered in the account entity which is common in them while the individual attributes must be specified under its own entity.

EER models are the helpful tools used for designing databases that have high-level models.

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Answer:

Throughout the interpretation section elsewhere here, the explanation of the problem is summarized.

Explanation:

Answer:

Written in C

#include <stdio.h>

int main() {

   float salary;

   printf("Salary: ");

   scanf("%f", &salary);

   float HRA, DA;

   if(salary <= 10000){

       HRA = 0.20; DA = 0.80;

   }

   else if(salary >= 10000 && salary <= 20000){

       HRA = 0.25; DA = 0.90;

   }

   else{

       HRA = 0.30; DA = 0.95;

   }

   salary = salary + salary * HRA + salary * DA;

     printf("Gross Salary: %.2f\n", salary);

   return 0;

}

Explanation:

I've added the full program as an attachment where I used comments as explanation

Answer:

i choose choice D

Explanation:

reason as to my answer public keys are simply input keys used to encrypt data into either a computer or any electrical device as private keys are out put used to either erase or edit

Answer:

umm that is a todler song

Explanation:

umm that is a todler song that they sing to them when there crying

A country, called Simpleland, has a language with a small vocabulary of just “the”, “on”, “and”, “go”, “round”, “bus”, and “wheels”. As per the given scenario, the vector of counts will be 2111211. The correct option is C.

C++ has a built-in function that counts the length of the vector. Size is the function's name ().

It returns the size or total number of elements of the vector that was utilized to create it. There is no need for debate.

The number of observations (rows) includes deleted observations as well. In an SAS data collection, there can be a maximum of 2 63-1 observations, or roughly 9.2 quintillion observations. For the majority of users, going above that limit is quite rare.

The vector of counts in the above scenario will be 2111211.

Thus, the correct option is C.

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Answer:

The program equivalent in C++ is:

#include <cstdio>

#include <cstdlib>

#define SIZE 5

using namespace std;

int main(int argc, char *argv[]) {

int numerator = 25;

int denominator = 10;

FILE * inPut = fopen(argv[1], "r");

FILE * outPut = fopen(argv[2], "w");

float result = (float)numerator/denominator;

fprintf(outPut,"Result is %.2f\n", result);

float arr[SIZE];

for(int i = 0; i < SIZE; i++) {

fscanf(inPut, "%f", &arr[i]);

fprintf(outPut, "%7.4f\n", arr[i]);

}

return 0;

}

Explanation:

See attachment for explanation.

Each line were numbered with equivalent line number in the C program

Answer:

270 nsec

Explanation:

Ripple-carry adder is a combination of multiple full-adders. It is relatively slow as each full-adder waits for the output of a previous full-adder for its input.

Formula to calculate the delay of a ripple-carry adder is;

  = 2( n + 1 ) x D

delay in a full-adder = 150 nsec.

number of full-adders = number of ripple-carry bits = 8

 = 2 ( 8 + 1 ) x 150

 = 18 x 150

 = 270 nsec

Answer:Click the Microsoft Office button.

Select New. The New Document dialog box appears.

Select Blank document under the Blank and recent section. It will be highlighted by default.

Click Create. A new blank document appears in the Word window.

Explanation: