Convert €3.2 per kilogram to unit price dollars per pound

Answers

Answer 1

We get 1.45 dollars per pound when we convert 3.2 Euros per kilogram to dollar per pound.

According to the question,

We have the following information:

3.2 Euros per kilogram

We need to convert its units into dollars per pounds.

We know that 1 Euro is approximately equal to 1 US dollar and 1 kilogram of weight is equal to 2.205 pounds.

(Note that there are various conversions from Euro to dollars which have 1 Euro equal to 1.00755 and many other values. In this case, we have rounded it off to 1 to avoid any confusion.)

(We know that per means the unit given is in divide.)

So, we have:

(3.2*1)/(1*2.205)

3.2/2.205

1.45 dollar per pounds

Hence, the conversion to dollars per pounds is 1.45 dollar per ponds from Euros per kilogram.

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Related Questions

Ashlee was born on 09/08/1981. How many eight digit codes could she make using the digits in her birthday

Answers

Ashlee could make 2520 eight digit codes using the digits in her birthday .

In the question

it is given that

the birthdate of Ashlee is 09/08/1981.

So, the number of digits are 0,0,1,1,8,8,9,9  .

number of digits = 8

So, 8 digits can be arranged in 8! ways

8! = 8*7*6*5*4*3*2*1 = 40320

Repeating digits are

0 repeated 2 times = 2! = 2

1 repeated 2 times = 2! = 2

8 repeated 2 times = 2! = 2

9 repeated 2 times = 2! =2

So, the number of 8 digits codes is = 8!/(2!*2!*2!*2!)

= 8!/(2*2*2*2)

= 40320/16

= 2520

Therefore , Ashlee could make  2520 eight digit codes using the digits in her birthday .

The given question is incomplete , the complete question is

Ashlee was born on 09/08/1981. How many eight digit codes could she make using the digits in her birthday ?

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Which is an example of a survey?A- collecting the cholesterol readings of a group of elderly people in a small townB- interviewing college students to find what percentage expect a job immediately after graduationC- testing the effectiveness of a hair product by allowing one group to use it and comparing results against a control groupD- testing the effectiveness of a mouthwash by allowing one group to use it and comparing results with those of a group that doesn't use ot

Answers

Answer: B- interviewing college students to find what percentage expect a job immediately after graduation

Surveys are meant to collect data that can be used to analyze a population as ahwole. This option analyzes the perspective of college students as a whole, whereas option A only focuses on a minority group of elderly. Additionally, options C and D are moreso experiments and not surveys that can be applied on a larger scale.

Can yoy help me with number 3? I do not understand the question.

Answers

The law of sines states that:

[tex]\frac{\sin\alpha}{a}=\frac{\sin\beta}{b}=\frac{\sin \gamma}{c}[/tex]

where alpha is the opposite angle to side a, beta is the opposite angle to side b and gamma is the opposite angle to side c.

For the triangle given we notice that:

Angle x is opposite to side 2.5.

Angle 28° is opposite to side 3.

Therefore the expression to find x is:

[tex]\frac{\sin x}{2.5}=\frac{\sin 28}{3}[/tex]

brainliest will be given to whoever has the correct answer

Answers

The CLOSEST correct answer regarding "x" is the first one (answer A), since x is 79. The correct answer is: X measures 79 because it is an alternate external angle between parallel lines to the one labeled 79 in the picture.

Nov 28,Quadrilateral ABCD is dilated by a scale factor of to form quadrilateral A'B'C'D'.What is the measure of side DA?Dal1515301B2162А

Answers

The quadrilateral ABCD was dilated by a scale factor of 3/4 to form the quadrilateral A'B'C'D'

This means that each side of the quadrilateral was multiplied by 3/4 to make the dilation.

You know that the scale factor is 3/4 and the length of D'A' is equal to 30 units, then:

[tex]\begin{gathered} D^{\prime}A^{\prime}=\frac{3}{4}DA \\ 30=\frac{3}{4}DA \end{gathered}[/tex]

Multiply both sides by the reciprocal of 3/4

[tex]\begin{gathered} 30\cdot\frac{4}{3}=(\frac{4}{3}\cdot\frac{3}{4})DA \\ 40=DA \end{gathered}[/tex]

The length of side DA is 40 units.

A chocolate factory has a goal to produce10121012pounds of chocolate frogs per day. If the machines operate for712712hours per day making215215pounds of chocolate frogs per hour, will the chocolate factory make it’s goal?The chocolate factory meet their goal with the total being10121012pounds of chocolate frogs produced.

Answers

First, rewrite all the mixed fractions as impropper fractions:

[tex]\begin{gathered} 10\frac{1}{2}=10\times\frac{2}{2}+\frac{1}{2}=\frac{20}{2}+\frac{1}{2}=\frac{21}{2} \\ \\ 7\frac{1}{2}=7\times\frac{2}{2}+\frac{1}{2}=\frac{14}{2}+\frac{1}{2}=\frac{15}{2} \\ \\ 2\frac{1}{5}=2\times\frac{5}{5}+\frac{1}{5}=\frac{10}{5}+\frac{1}{5}=\frac{11}{5} \end{gathered}[/tex]

Next, multiply the rate of chocolate production over time by the the operating time of the machines to find the total amount of pounds of chocolate frogs produced in one day:

[tex]7\frac{1}{2}\times2\frac{1}{5}=\frac{15}{2}\times\frac{11}{5}=\frac{15\times11}{2\times5}=\frac{3\times11}{2}=\frac{33}{2}=16\frac{1}{2}[/tex]

Then, the chocolate factory can produce 16 1/2 pounds of chocolate frogs per day.

Since 16 1/2 is greater than 10 1/2, then the chocolate factory will meet their goal with the total being over 10 1/2 pounds of chocolate frogs produced.

Give. ∆ABC Angle B = 42°, Angle C = 71° and BC = 22. Find AB and round your answer to nearest integer.

Answers

Let's make a diagram to visualize the problem.

First, let's find angle A.

[tex]\begin{gathered} A+B+C=180 \\ A+42+71=180 \\ A=180-71-42 \\ A=67 \end{gathered}[/tex]

Then, we use the law of sines to find AB.

[tex]\begin{gathered} \frac{AB}{\sin71}=\frac{BC}{\sin A} \\ \frac{AB}{\sin71}=\frac{22}{\sin 67} \\ AB=\frac{22\cdot\sin 71}{\sin 67} \\ AB\approx23 \end{gathered}[/tex]Therefore, AB is 23 units long, approximately.

RATIOS, PROPORTIONS, AND PERCENTSCalculating income taxTeresa made $20,000 in taxable income last year.Suppose the income tax rate is 10% for the first $7500 plus 16% for the amount over $7500.How much must Teresa pay in income tax for last year? I need help with this math problem.

Answers

We need find the tax on the first 7500

7500 * 10%

7500 * .10 = 750

Now we find the tax on what is over 7500

20000 -7500 =12500

The tax rate for this amount is 16%

12500 * 16%

12500 * .16

2000

Add the tax for both amounts together

750 + 2000

2750

The total tax paid is 2750

The shaded triangle has an area of 4 cm?Find the area of the entire rectangleBe sure to include the correct unit in your answer.

Answers

Given:

Area of a shaded region of a rectangle is given.

[tex]\text{Area of the triangle=}4cm^2[/tex]

Area of the rectangle is twice the area of the triangle given.

[tex]\begin{gathered} \text{Area of a rectangle=2}\times Area\text{ of a triangle} \\ =2\times4 \\ =8cm^2 \end{gathered}[/tex]

Factor each polynomial by factoring out the greatest common factorminimum steps please

Answers

we are given the following expression:

[tex]12x^4+6x^3-8x^2[/tex]

The greatest common factor between 12, 6, and 8 is 2. And the greatest common factor between the variables is:

[tex]\text{GCF(x}^4,x^3,x^2)=x^2[/tex]

Therefore, the factorization is:

[tex]12x^4+6x^3-8x^2=2x^2(6x^2+3x-4)[/tex]

An amusement park's owners are considering extending the weeks of the year that it is opened. The owners would like to survey 100 randomly selected families to see whether an extended season would be of interest to those that may visit the amusement park.What is the best way to randomly choose these 100 families? Have the owners of the amusement park ask the first 100 people they see.Choose a neighborhood near the amusement park and ask 100 families in this neighborhood.Ask the first 100 families that enter the amusement park on a busy weekend day.Allow a random number generator to come up with 100 families within a 50 radius of the amusement park.

Answers

Solution

Option 1:

- The owners asking the first 100 people they see would mean that they would see only those around them. This could be anyone at all from workers in the amusement park to people outside the park; these would not be random, and would not necessarily be a family but the survey is talking about randomly choosing 100 families. Because of these reasons, this is not the best way to randomly choose 100 families.

Option 2:

- Choosing a neighborhood near the amusement park would mean that they go to a neighborhood with families that might visit the amusement park and there would be many families to randomly choose from.

- This option seems like a good choice to randomly choose these 100 families that might visit the amusement park.

Option 3:

- Asking the first 100 families that enter the amusement park on a busy weekend would definitely bias the survey since families that you find in the amusement park are families that definitely want to be there and if they are there on a busy weekend, they certainly would not mind extending the season

6. Suppose that wedding costs in the Caribbean are normally distributed with a mean of $6000 and a standard deviation of $735. Estimate the percentage of Caribbean weddings that cost (a) between $5265 and $6735. % (b) above $6735. % (c) below $4530. % (d) between $5265 and $7470. %

Answers

To solve this problem, the first thing we must do is find the Z-Score of the given costs: $5265 , $6735 , $4530 ,and $7470

Then we proceed to find the percentages for each interval based on the graph

z-score for $5265 )

[tex]Z_{5265}=\frac{5265-6000}{735}=-1[/tex]

z-score for $6735 )

[tex]Z_{6735}=\frac{6735-6000}{735}=1[/tex]

z-score for $4530 )

[tex]Z_{4530}=\frac{4530-6000}{735}=-2[/tex]

z-score $7470 )

[tex]Z_{7470}=\frac{7470-6000}{735}=2_{}[/tex]

now, let's analyze the intervals

a ) between $5265 and $6735

This interval goes from (μ-σ) to (μ+σ)

if we look at the graph we find that this corresponds to a percentage of 68%

b) above $6735

This corresponds to what is to the right of (μ+σ)

This is a percentage of 16%

[tex]\frac{100-68}{2}=\frac{32}{2}=16[/tex]

c ) below $4530

This corresponds to what is to the left of (μ-2σ)

This is a percentage of 2.5%

[tex]\frac{100-95}{2}=\frac{5}{2}=2.5[/tex]

d ) between $5265 and $7470

This interval goes from (μ-σ) to (μ+2σ)

This is a percentage of 81.5%

[tex]\begin{gathered} 100-\frac{100-68}{2}-\frac{100-95}{2} \\ =100-16-2.5 \\ =81.5 \end{gathered}[/tex]

which statement is true of the system of equations shown below

Answers

3x + 7y= 14

3x+7y= 10

Subtract the second equation to the first.

3x +7y= 14

-

3x + 7y= 10

_________

0x +0y = 4

0 = 4

0 is no

Refer to attached image.
213 and 131 are incorrect.

Answers

Answer:

P(X<16) = 0.64P(X>12) = 0.64

Step-by-step explanation:

Given a graph of a probability density function, you want the probabilities ...

P(X < 16)P(X > 12)

Probability from PDF

The probability of a given range of values of X is the area under the density curve for those values of x.

P(X < 16)

The triangular area to the left of X=16 has a base of 16 and a height of 0.08. Its area is given by the area formula for a triangle:

  A = 1/2bh

  A = 1/2(16)(0.08) = 0.64

The probability is P(X<16) = 0.64.

P(X > 12)

The area to the right of X=12 is a trapezoid with parallel "bases" of 0.06 and 0.10. The "height" of the trapezoid is 20-12 = 8. The area is given by the formula ...

  A = 1/2(b1 +b2)h

  A = 1/2(0.06 +0.10)(8) = 0.64

The probability is P(X>12) = 0.64.

Identify each pair of angles as corresponding, alternate interior, alternate exterior, consecutiveinterior, vertical, or adjacent.

Answers

SOLUTION

Given the image on the answer tab;

Explanation;

The two angles are said to be adjacent angles when they share the common vertex and side.

Considering our question;

Assume the random variablex is normally distributed with mean p=85 and standard deviation o=5. Find the indicated probabiliP73

Answers

Remember that

z =(x - μ)/σ

we have

μ=85

σ=5

For x=73

Find out the value of Z1

z1=(73-85)/5

z1=-2.4

For x=76

Find out the value of Z2

z2=(76-85)/5

z2=-1.8

using a z-scores table values

we have that

P(73

Select all the situations in which a proportional relationship is described.
Jackson saves $10 in the first month and $30 in the next 3 months.
Mia saves $8 in the first 2 months and $4 in the next month.
Piyoli spends $2 in the first 2 days of the week and $5 in the next 5 days.
Robert spends $2 in the first 3 days of the week and $5 in the next 4 days.

Answers

The situations that describe a proportional relationship are:

Jackson saves $10 in the first month and $30 in the next 3 months.

Mia saves $8 in the first 2 months and $4 in the next month.

Piyoli spends $2 in the first 2 days of the week and $5 in the next 5 days.

What is a proportional relationship?

A relation is proportional if the rate of change of the variables is constant. The variables can either increase or decrease at a constant rate. A proportional relationship can be modelled with a linear equation.

Is Jackson's saving proportional?

Average of the amount saved in the next 3 months: $30 / 3 = $10

The relationship is proportional because the amount saved in the first month and the average is equal.

Is Mia's saving proportional?

Average of the amount saved in the first 2 months: $8 / 2 = $4

The relationship is proportional because the amount saved in the thir month and the average is equal.

Is Piyoli's spending proportional?

Average of the amount spent in the first 2 days: $2 / 2 = $1

Average of the amount spent in the next 5 days = $5 / 5 = $1

The relationship is proportional because the averages are equal.

Is Robert's spending proportional?

Average of the amount spent in the first 3 days: $2 / 3 = $0.67

Average of the amount spent in the next 4 days = $5 / 4 = $1.25

The relationship is not proportional because the averages are not equal.

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50 points.
Daisy is a botanist who works for a garden that many tourists visit. The function f(s) = 3s + 30 represents the number of flowers that bloomed, where s is the number of seeds she planted. The function s(w) = 12w represents the number of seeds she plants per week, where w represents the number of weeks.

Part A: Write a composite function that represents how many flowers Daisy can expect to bloom over a certain number of weeks.

Part B: What are the units of measurement for the composite function in Part A?

Part C: Evaluate the composite function in Part A for 36 weeks.

Answers

From the situation described in this problem, it is found that:

A. The composite function is: f(s(w)) = 36w + 30.

B. The unit of measurement of the composite function is: flowers.

C. After 36 weeks, Daisy can expect to bloom 1326 flowers.

Composite function

For a composite function, the output of the inner function serves as the input of the outer function.

In the context of this problem, the functions are given as follows:

f(s) = 3s + 30.s(w) = 12w.

Hence the composite function that represents how many flowers Daisy can expect to bloom over a certain number of weeks is:

f(s(w)) = f(12w) = 3(12w) + 30 = 36w + 30.

The unit of measurement of the composite function is the unit of the outer function, which is flowers.

After 36 weeks, the number of flowers that Daisy can expect to bloom is given as follows:

f(s(36)) = 36(36) + 30 = 1326 flowers.

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the question is on the sheet .The shaded region is the area within the figure but not the corner squares

Answers

Based on the information given in the exercise, you know that the shaded region has this area:

[tex]6x^2-2xy+3y^2[/tex]

And the area of each square region in the corners is:

[tex]4x^2[/tex]

Since there are four square regions, you can multiply that the area of any of them by 4, in order to find the total area of them:

[tex]4(4x^2)=16x^2[/tex]

Then, in order to find the total area of the figure, you must add the area of the shaded region and the total area of the square regions:

[tex](6x^2-2xy+3y^2)+(16x^2)=22x^2^{}-2xy+3y^2[/tex]

Therefore, the total of the figure is:

[tex]22x^2-2xy+3y^2[/tex]

Which ordered pair is a solution set for the linear equation, x + 16 = 6y? A (16,4) B (2, 3) C (-4,-2) D (-10,-1)

Answers

Explanation

to figure out if a pair is a solution, just replace x and y values and check if the equation is true,then

Step 1

[tex]\begin{gathered} x+16=6y \\ A)(16,4)\rightarrow when\text{ x=16 and y =4} \\ \text{replace} \\ 16+16=6\cdot4 \\ 32=24\rightarrow False,then\text{ A is not a solution} \end{gathered}[/tex]

Step 2

[tex]\begin{gathered} B)(2,3)\rightarrow whenx=\text{ 2 and y=3} \\ x+16=6y \\ \text{replace} \\ 2+16=6\cdot3 \\ 18=18\rightarrow true \\ so\text{ B is a solution} \end{gathered}[/tex]

Step 3

[tex]undefined[/tex]

A classic car is now selling for $2000 more than two times its original price. If the selling price is now $12,000, what was the car's original price?

Answers

The selling price is $2000 more so we will subtract 2000 from the final amount

$12000-&2000 = $10000

As the selling price is two times then
It is 10000 /2 = $5000

find the first second and third derivatives of the function

Answers

Given the function

[tex]f(x)=\frac{8}{5}x-9[/tex]

Finding the derivative we have

[tex]f^{^{\prime}}(x)=\frac{8}{5}[/tex]

Also

[tex]f^{\doubleprime}(x)=0^{}[/tex]

Finally

[tex]f^{^{\doubleprime}^{\prime}}(x)=0[/tex]

There are 130 people in a sport centre.
76 people use the gym
60 people use the swimming pool.
32 people use the track.
23 people use the gym and the pool.
8 people use the pool and the track.
20 people use the gym and the track.
6 people use all three facilities.
Given that a randomly selected person
uses the gym and the track, what is
the probability they do not use the
swimming pool?

Answers

The probability is 0.57

What is meant by probability?

Probability is a discipline of mathematics that deals with appropriate units of how probable an event is to occur or how likely a statement is to be true. The probability of an occurrence is a number ranging from zero and 1, where 0 denotes the event's feasibility and 1 represents certainty. The greater the likelihood of an occurrence, the more probable it will occur. Tossing a fair (unbiased) coin is a basic example. Because the coin is fair, the two possibilities ("heads" and "tails") are equally likely; the chance of "heads" equals the probability of "tails," and because no other outcomes are possible, the probability of either "heads" or "tails" is 1/2.

Probability of using the pool = 97/225 = 0.43

Probability that they do not use the swimming pool = 1 - 0.43 = 0.57

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Rigid Transformations: Question 3A military compound is located in a city where the streetsare arranged in a grid. The compound is going to be movedto a new location in the same city. The new compound willbe exactly the same as the old one and in the sameorientation. The existing location is represented on thecoordinate grid shown, where each unit represents one cityblock. Which of the following best describes the situation?14B1210CDD'C6 4AB2-14 12 10 86226 8 10 12 142D4С6 8N10Wm12s141

Answers

In this question, we are given two locations of a military compound.

Let's take the coordinates of point A from the graph,

A = (-3, 2)

The new coordinates of A' = (5, 13)

translation in x-axis = 5 - (-3) = 5 + 3 = 8

translation in y-axis = 13 - 2 = 11

hence, each point of the figure will be translated to 8 units on the x-axis and 11 units on the y-axis.

Find the slope and the equation of the line having the points (0, 2) and (5, 5)

Answers

Answer:

The slope is 3/5 and the equation is:

[tex]y=\frac{3}{5}x+2[/tex]

Explanation:

Given the points (0,2) and (5, 5)

The slope of a line is the ratio of the difference between the y coordinates to the x coordinates. The x coordinates are 0 and 5, the y coordinates are 2 and 5.

[tex]\begin{gathered} m=\frac{5-2}{5-0} \\ \\ =\frac{3}{5} \end{gathered}[/tex]

The equation of a straight line is given as:

y = mx + b

Where m is the slope and b is the y-intercept

Using any of the given points, we can find b

Use (0, 2), with x = 0, y = 2

2 = (3/5)(0) + b

b = 2

Now the equation is:

[tex]y=\frac{3}{5}x+2[/tex]

Find the value of this expression if x = 1 andy = -7x2y-9

Answers

We are asked to evaluate the expression:

[tex]\frac{x^2y}{-9}[/tex]

when x = 1 and y = -7

so we replace them as shown below, making sure we include them inside parenthesis to keep clear that the expressions in x and in y are multiplying each other:

[tex]\frac{x^2y}{-9}=\frac{(1)^2(-7)}{-9}=\frac{-7}{-9}=\frac{7}{9}[/tex]

So we see that x^2 becomes 1 and the factor y stays as -7. The final expression cancels out the negative sign in numerator (from -7) and in denominator (from -9) and gives 7/9.

how long is the hypotenuse of this right triangle?28 519023

Answers

To calculate the hypotenuse of a right angled triangle as shown in the diagram, we can apply the Pythagoras theorem which states as follows;

AC^2 = AB^2 + BC^2

Where AC is the hypotenuse (the longest side) 28 units, AB is one of the other two sides, 23 units and BC is the third side.

We can now re-write the formula as follows;

28^2 = 23^2 + BC^2

784 = 529 = BC^2

Subtract 529 from both sides of the equation

255 = BC^2

Add the square root sign to both sides of the equation and you have

BC = 15.9687

BC is approximately 16 units

The lengths of two sides of the right triangle ABC shown in the illustration givena=12 cm and c= 20cm

Answers

In the right triangle of sides a, b, and c

[tex]a^2+b^2=c^2[/tex]

Since a = 12 and c = 20

Substitute them in the given rule

[tex]\begin{gathered} (12)^2+b^2=(20)^2 \\ 144+b^2=400 \end{gathered}[/tex]

Subtract 144 from both sides

[tex]\begin{gathered} 144-144+b^2=400-144 \\ b^2=256 \end{gathered}[/tex]

Take a square root for both sides

[tex]\begin{gathered} \sqrt[]{b^2}=\sqrt[]{256} \\ b=16 \end{gathered}[/tex]

The answer is b = 16

The number of inequality’s and signs can be changed by the way

Answers

Linear Optimization

It consists of finding the optimum solution to a problem where all the conditions are related as linear functions.

We'll use the graphic method to solve the problem.

The problem is as follows:

Ava sells burritos amd tacos. Let's call x to the number of tacos sold and y to the number of burritos sold.

The first condition we find is that she can only produce a maximum of 130 units between tacos and burritos. This gives us the first inequality:

x + y ≤ 130 (1)

She sells each taco for $3.75 and each burrito for $6. She must sell a minimum of $600 worth of both products, so:

3.75x + 6y ≥ 600

Multiply this inequality by 4:

15x + 24y ≥ 2400

And divide it by 3:

5x + 8y ≥ 800 (2)

We are given a final condition that she can sell a minimum of 80 burritos, thus:

y ≥ 80 (3)

There are two obvious conditions not explicitly said but they can be deducted by the wording of the problem. Both x and y must be greater or equal to zero:

x ≥ 0 (4)

y ≥ 0 (5)

Let's put this all together:

x + y ≤ 130 (1)

5x + 8y ≥ 800 (2)

y ≥ 80 (3)

x ≥ 0 (4)

y ≥ 0 (5)

The optimum solution must satisfy all the conditions. They form a feasible region in the x-y coordinates system. One of the corners of that region will eventually be the best solution, depending on the objective function (not given here).

We need to graph all five lines in one common grid. It's shown below.

According to the graph, one possible solution is to sell x=50 tacos and y=80 burritos

What is the day supply for 30 tablets if the direction is a half tabletsFor 7 days then 1 once daily

Answers

Answer:

33 days

Explanation:

If you use a half tablet for 7 days, you will consume:

0.5 x 7 days = 3.5 tablets.

So, at the end of the 7th day, you will consume 3.5 tablets and you will have 26.5 tablets left because:

30 tablets - 3.5 tablet = 26.5 tablets.

Then, you will consume 1 tablet daily, so if you have 26.5 tablets, you will have a tablet daily for 26 days.

Therefore, the day supply for 30 tablets will be the sum of the initial 7 days and the 26 days, so:

7 days + 26 days = 33 days.

Therefore, the answer is 33 days

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TEXT 1A sense of safety.Within Belfast the west of the city is predominately Catholic, east Belfast is largely Protestant, the southof the city is more mixed, and north Belfast is a patchwork of Protestant and Catholic neighborhoods.We found that the everyday use of parks in west and north Belfast was often focused on local facilitieswithin a 10minute walk. People are prepared to travel for specific activities, but maintain a morefrequent relationship with local spaces which act as community hubs.Remnants of The Troubles remain in Belfast. Distrust of Belfast City Council and the Police ServiceNorthern Ireland, as well as communities from different parts of the city, persists. Some residents stay intheir local area as it provides a sense of ownership and safety they may not feel elsewhere.How Belfasts parks promote shared space in a historically divided city, The Conversation, 20 Oct 2020.TEXT 2The celebrated peace walls.The undercurrent of savagery is rarely far awayIts been that way from ancient times, until the present dayThat murky world of politics, where they always try and failWhere deals are done in private, behind the secret veilHeld up as a precedent, for all the world to seeHow little Ulster saved itself, from a life of miseryWe listen to the sound bites, each days a brand-new startYet our celebrated peace walls, keep communities apartLeslie Wilson, Peace? (excerpt)TEXT 3The Re-Imaging Communities projectIn Belfast, the capital of Northern Ireland, hundreds of colorful murals line the citys streets, detailing acenturys worth of conflict and political division. ()In 1998, the internationally-brokered Good Friday Agreement also called the Belfast Agreement, officiallyended the conflict and set up a power-sharing government between Protestant Unionists and CatholicNationalists. Since then the violence has largely subsided. But tensions still linger between Protestantand Catholic neighborhoods, with some residents reluctant to bridge the gap. ()In the last several years, some communities have repainted portions of the most controversial murals orerected new ones in an effort to continue normalizing relationships between Protestants and Catholics.Under the Re-Imaging Communities project through the Arts Council of Northern Ireland, somecommunities received funding to create new murals in place of older images.These murals lie at the center of a debate over Northern Irelands future, Canvas Arts, PBS NewsHour, Feb25 2017QuestionsMake an account in English of the three texts in order to answer the questions: How is the current situation between Catholics and Protestants in Belfast portrayed in the three texts? What explanations for the situation and solutions for improvement are mentioned? A focus group was formed to provide opinions for a target market.what type of data is being collected from the focus group ? 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