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An equation that could be used to determine the number of books that Keiko bought include the following: B. 4b - 5 = 71.
The number of books is equal to 19 books.
How to write an equation to model this situation?In order to write a linear equation to describe this situation, we would assign a variable to the number of books, and then translate the word problem into a linear equation as follows:
Let the variable b represent the number of books.
Since Keiko bought some books for $4 and received a discount of $5 off of her total purchase, a linear equation that models the situation is given by this mathematical expression:
4b - 5 = 71
Next, we would calculate the number of books (b) as follows;
4b - 5 = 71
4b = 71 + 5
4b = 76
b = 76/4
b = 19 books.
Read more on equation here: brainly.com/question/18912929
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can someone pls help
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Step-by-step explanation:
A triangle has its interior angle sum as 180°
[tex]{ \tt{ \angle R + \angle S + \angle T = 180 \degree}}[/tex]
[tex]{ \colorbox{silver}{input \: angles}} \\ \\ { \tt{31 \degree + (x + 4) \degree + (3x + 9) \degree = 180 \degree}} \\ \\ { \tt{44 + 4x = 180 \degree}} \\ \\ { \tt{4x = 136}} \\ \\ { \tt{x = 34}} \\ \\ { \colorbox{silver}{for \:R }} \\ \\ { \tt{ m\angle S =x + 4 = 34 + 4}} \\ \\ { \boxed{ \tt{m \angle S = 38 \degree}}} \\ \\ { \colorbox{silver}{for \:T }} \\ \\ { \tt{m \angle T = 3x + 9 = (3 \times 34) + 9}} \\ \\ { \tt{m \angle T = 111 \degree}}[/tex]
Can someone please help me
Answers
the formula for rate of change is
(Y2 - Y1)/(X2-X1).
Plug in any 2 random coordinates.
(6-4)/(5-4)
2/1
2
Choose ALL correct answers.
Which of the following tables are non-linear?
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Find the volume of the triangular prism; do not round.
Answers
Answer:
[tex]\boxed{\mathtt{Volume=33.55m^{3}}}[/tex]
Step-by-step explanation:
[tex]\textsf{For this problem, we are asked to find the Volume of a Triangular Prism.}[/tex]
[tex]\large\underline{\textsf{What is Volume?}}[/tex]
[tex]\textsf{Volume is the amount of space a figure occupies. Volume is measured in Cubic units.}[/tex]
[tex]\large\underline{\textsf{We are Given;}}[/tex]
[tex]\textsf{The Height is 6.1m. Keep in mind that the Height is the Perpendicular Distance}[/tex]
[tex]\textsf{between 2 bases.}[/tex]
[tex]\textsf{The base is; (4.4 x 2.5).}[/tex]
[tex]\textsf{The Height of the Triangle is 2.5m.}[/tex]
[tex]\large\underline{\textsf{Necessary Formulas;}}[/tex]
[tex]\mathtt{Volume=(Base) \times Height}[/tex]
[tex]\mathtt{Area = \frac{1}{2} (Base \times Height)}[/tex]
[tex]\large\underline{\textsf{For this Problem;}}[/tex]
[tex]\mathtt{Volume=(Triangles' \ Area) \times Height}[/tex]
[tex]\large\underline{\textsf{The area of a Triangle is;}}[/tex]
[tex]\mathtt{Area = \frac{1}{2} (Base \times Height)}[/tex]
[tex]\textsf{Find the area of the base first.}[/tex]
[tex]\large\underline{\textsf{Substitute;}}[/tex]
[tex]\mathtt{Area = \frac{1}{2} (4.4 \times 2.5)}[/tex]
[tex]\boxed{\mathtt{Area = 5.5m^{2}.}}[/tex]
[tex]\textsf{We know the Base, now let's find the volume of the figure.}[/tex]
[tex]\large\underline{\textsf{Substitute;}}[/tex]
[tex]\mathtt{Volume=5.5 \times 6.1}[/tex]
[tex]\boxed{\mathtt{Volume=33.55m^{3}}}[/tex]
[tex]\huge\text{Hey there!}[/tex]
[tex]\huge\textsf{Find the \boxed{\bf volume} of a triangular prism is:}[/tex]
[tex]\mathsf{\dfrac{1}{2}(\boxed{\bf b}ase\times\boxed{\bf h}eight\times\boxed{\bf l}ength) = \boxed{\bf v}olume}[/tex]
[tex]\huge\textsf{Your \boxed{\bf equation} should look like:}[/tex]
[tex]\mathsf{volume = \dfrac{1}{2}(4.4\ m \times 2.5\ m\times 6.1\ m)}[/tex]
[tex]\huge\textsf{\boxed{\bf Step-by-step} explanation can be:}[/tex]
[tex]\mathsf{volume = \dfrac{1}{2}(4.4\ m \times 2.5\ m\times 6.1\ m)}[/tex]
[tex]\mathsf{volume = \dfrac{1}{2}\times 4.4\ m \times 2.5\ m\times 6.1\ m}[/tex]
[tex]\mathsf{volume = 0.5\times 4.4\ m \times 2.5\ m\times 6.1\ m}[/tex]
[tex]\mathsf{volume = 2.2\ m\times 15.25\ m}[/tex]
[tex]\mathsf{volume = 33.55}[/tex]
[tex]\huge\textsf{Therefore your \boxed{\bf answer} should be:}[/tex]
[tex]\huge\boxed{\mathsf{volume = 33.55m^2}}\huge\checkmark[/tex]
[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]