create a box and whisker plot for the following set of data

Answers

Answer 1

You can plot the box and whisker plot using these values:

Lower whisker: 12Q1: 23.5Q2 (median): 36Q3: 46Upper whisker: 56

How to solve

Step 1: Order the data set from smallest to largest:

12, 19, 28, 32, 34, 38, 45, 47, 50, 56

Step 2: Calculate the lower quartile (Q1), median (Q2), and upper quartile (Q3):

Q1 (25th percentile): The value that separates the lowest 25% of the data from the rest. Since we have 10 data points, the first quartile will be the average of the 2.5th and 3.5th data points. In our case, it's the average of the 2nd and 3rd data points:

Q1 = (19 + 28) / 2 = 23.5

Q2 (50th percentile or median): The value that separates the lowest 50% of the data from the rest. Since we have an even number of data points, the median will be the average of the 5th and 6th data points:

Q2 = (34 + 38) / 2 = 36

Q3 (75th percentile): The value that separates the lowest 75% of the data from the rest. Since we have 10 data points, the third quartile will be the average of the 7.5th and 8.5th data points. In our case, it's the average of the 7th and 8th data points:

Q3 = (45 + 47) / 2 = 46

Step 3: Calculate the interquartile range (IQR):

IQR = Q3 - Q1 = 46 - 23.5 = 22.5

Step 4: Determine the whiskers:

Lower whisker: The smallest value that is not smaller than Q1 - 1.5 * IQRUpper whisker: The largest value that is not larger than Q3 + 1.5 * IQR

Lower whisker limit: 23.5 - 1.5 * 22.5 = -10

Upper whisker limit: 46 + 1.5 * 22.5 = 79.5

Our data points are all within these limits, so the lower whisker is at the smallest value, 12, and the upper whisker is at the largest value, 56.

Now, you can plot the box and whisker plot using these values:

Lower whisker: 12Q1: 23.5Q2 (median): 36Q3: 46Upper whisker: 56

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create a box and whisker plot for the following set of data

12, 19, 28, 32, 34, 38, 45, 47, 50, 56


Related Questions

What are the answers to these questions?
A=?
B=?
f''(A)=?
f''(B)=?
Thus f(x) has a local max or min at A and a local max or min at B.

Answers

We can say that f(x) has a local maximum at A and a local minimum at B.

What is Function?

A function is a mathematical rule that assigns a unique output value to each input value. It describes the relationship between the input and output variables.

Critical numbers of a function are the values of the independent variable where the derivative is zero or undefined, indicating possible extrema or inflection points.

According to the given information:

To find the critical numbers of the function f(x), we need to find the values of x where f'(x) = 0 or f'(x) is undefined.

f(x) = cos(x) + √2/2

f'(x) = -sin(x)

Setting f'(x) = -sin(x) = 0, we get sin(x) = 0, which is true for x = nπ, where n is an integer. However, we only need to consider the values of x in the interval [0,2].

For n = 0, x = 0 is a critical number.

For n = 1, x = π is a critical number.

For n = 2, x = 2π is not in the interval [0,2], so we don't need to consider it.

Therefore, the critical numbers of f(x) in the interval [0,2] are A = 0 and B = π.

To find the nature of the critical points, we need to find the second derivative of f(x).

f''(x) = -cos(x)

Evaluating f''(x) at A and B, we get:

f''(A) = -cos(0) = -1, which means that f(x) has a local maximum at A.

f''(B) = -cos(π) = 1, which means that f(x) has a local minimum at B.

Therefore, we can say that f(x) has a local maximum at A and a local minimum at B.

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How long did Lizzie practice on Thursday and Friday altogether?
J
P
D
Lizzie's Drum Practice
P
S
P
D
P
S
S
Monday Tuesday Wednesday Thursday Friday
= 5 minutes
DONE
0
minutes
7 8
4
00
5
1 2
0
9
6
3

Answers

Answer:

Lizzie practiced for a total of 14 minutes on Thursday and Friday combined.

On Thursday, she practiced for 5 minutes according to the table.

On Friday, she practiced for 9 minutes according to the table.

Adding these two times together, we get:

5 minutes + 9 minutes = 14 minutes

Therefore, Lizzie practiced for a total of 14 minutes on Thursday and Friday combined.

Tentor, Inc., purchases disposable coffee cups on which to print logos for sporting events, proms, birthdays, and other special occasions. The owner received a large shipment of 861 cups this afternoon, and to ensure the quality of the shipment, he selected a random sample of 410 cups and identified 353 as defective.

What is the estimated proportion of defectives in the population? (Round the final answer to 3 decimal places.)

Answer

What is the standard error of the sample proportion? (Round your answer to 3 decimal places.)

Answer

What are the upper and lower bounds for a 98% confidence level? (Round the final answers to 3 decimal places.)

Upper bound is Answer

Lower bound is Answer

Answers

It is estimated that 0.861 percent of the population is faulty. The sample proportion's standard error is 0.022. A 98% confidence level has an upper bound of 0.910 and a lower bound of 0.812.

What is a proportion?

The comparative relationship between two or more things in terms of their size, amount, or number is referred to as a "proportion." Either a ratio or a fraction can be used to express it. The term "proportion" in statistics refers to the division of the total number of events by the frequency of each event.

The formula p = x/n, where p is the estimated proportion of defectives in the population, x is the number of defectives in the sample, and n is the sample size, can be used to determine the estimated proportion of defectives in the population.

When we substitute values, we obtain:

p = 353/410 = 0.861

As a result, the population's estimated defectiveness rate is 0.861.

The formula SE = √(p(1-p)/n), where SE is the standard error and n is the sample size, can be used to get the standard error of the sample percentage.

When we substitute values, we obtain:

SE is equal to√(0.861(1.0.861)/410) = 0.022.

As a result, the sample proportion's standard error is 0.022.

Using the following formula, the upper and lower bounds for a 98% confidence level can be determined:

Lower bound = z*SE - p

Upper bound = z*SE + p

where z is the z-score for a 98% degree of confidence.

We discover that the z-score corresponding to a 98% confidence level is roughly 2.33 using a z-table or calculator.

When we substitute values, we obtain:

Lower bound is equal to 0.861 - 2.33*0.022, or 0.812.

Upper bound is equal to 0.861 + 2.33 * 0.022 = 0.910.

Consequently, the range of a 98% confidence level is as follows:

Maximum: 0.910

Upper limit: 0.812

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It is estimated that 0.861 percent of the population is faulty. The sample proportion's standard error is 0.022. A 98% confidence level has an upper bound of 0.910 and a lower bound of 0.812.

What is a proportion?

The comparative relationship between two or more things in terms of their size, amount, or number is referred to as a "proportion." Either a ratio or a fraction can be used to express it. The term "proportion" in statistics refers to the division of the total number of events by the frequency of each event.

The formula p = x/n, where p is the estimated proportion of defectives in the population, x is the number of defectives in the sample, and n is the sample size, can be used to determine the estimated proportion of defectives in the population.

When we substitute values, we obtain:

p = 353/410 = 0.861

As a result, the population's estimated defectiveness rate is 0.861.

The formula SE = √(p(1-p)/n), where SE is the standard error and n is the sample size, can be used to get the standard error of the sample percentage.

When we substitute values, we obtain:

SE is equal to[tex]\sqrt{\frac{0.861(1.0.861)}{410)}[/tex]= 0.022.

As a result, the sample proportion's standard error is 0.022.

Using the following formula, the upper and lower bounds for a 98% confidence level can be determined:

Lower bound = z*SE - p

Upper bound = z*SE + p

where z is the z-score for a 98% degree of confidence.

We discover that the z-score corresponding to a 98% confidence level is roughly 2.33 using a z-table or calculator.

When we substitute values, we obtain:

Lower bound is equal to 0.861 - 2.33*0.022, or 0.812.

Upper bound is equal to 0.861 + 2.33 * 0.022 = 0.910.

Consequently, the range of a 98% confidence level is as follows:

Maximum: 0.910

Upper limit: 0.812

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Determine the domain and range of the graph of this function.

Answers

x ≤ 4, -2≤ y ≤ 2  are the domain and range of the graph of this function.

What is the domain and domain of the function in the graph?

Another way to identify domains and feature sets is with graphs. Domain refers to the set of possible input values, so a chart's domain consists of all input values ​​displayed on the x-axis.

                                    A range is the set of possible output values ​​plotted on the y-axis. To find the domain and domain of the equation y = f(x), find the value of the independent variable x for which the function is defined. 

y = f(x)

according to the graph value of y

 x ≤ 4,

-2≤ y ≤ 2

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50 Points! Write the expression x^4+5x^2-8 in quadratic form, if possible. Photo attached. Thank you!

Answers

The expression x^4 + 5x^2 - 8 in quadratic form is: (x^2 + 8)(x^2 - 1)

How to solve the expression

It should be noted that to express the given expression x^4+5x^2 - 8 in quadratic form, we need to identify a suitable substitution that will allow us to rewrite the expression as a quadratic in a new variable.

One possible substitution is to let u = x^2, so that we can write:

x^4 + 5x^2 - 8 = u^2 + 5u - 8

We can then factor this quadratic expression as:

u^2 + 5u - 8 = (u + 8)(u - 1)

Substituting back u = x^2, we get:

x^4 + 5x^2 - 8 = (x^2 + 8)(x^2 - 1)

Therefore, the expression x^4 + 5x^2 - 8 in quadratic form is:

(x^2 + 8)(x^2 - 1)

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please answer in detail​

Answers

Answer:

y = 2x + 4

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 2x + 3 ← is in slope- intercept form

with slope m = 2

• Parallel lines have equal slopes , then

slope of line AB is m = 2

line AB crosses the y- axis at (0, 4 ) ⇒ c = 4

y = 2x + 4 ← equation of line AB

Draw place value disk to represent the value of the following expressions

5 times 2=

Answers

When the two sections are combined, the total number of circles would be ten, representing the value of 5 times 2, which is 10.

What is number?

Number is a mathematical concept used to quantify or measure a quantity. It is a symbol or group of symbols that stands for a quantity, such as 2, 4, 5, 10, and so on. Numbers are used to express amounts, to count, and to measure. They are also used to represent relationships between quantities and to compare quantities.

A place value disk can be used to represent the value of 5 times 2, which is equal to 10. The disk would have two sections, one representing the number 5 and the other representing the number 2. The number 5 would be represented by five single circles in the “ones” section, and the number 2 would be represented by two single circles in the “ones” section. When the two sections are combined, the total number of circles would be ten, representing the value of 5 times 2, which is 10.

The place value disk is a useful visual tool to help students understand the concept of multiplication. It allows them to clearly see how the number of circles in each section are multiplied to get the final answer. This can help them better understand the concept of multiplication and how it works.

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Complete questions as follows-

What is one third plus eight twelves

Answers

Answer:

1

Step-by-step explanation:

1/3 + 8/12 ⬅️(factor out by common factor, 4)

= 1/3 + 2/3

=1+2/ 3

=3/3 or 1

please help meeeee. What is the value of k?

Answers

Answer:

k = 10

Step-by-step explanation:

the exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

∠ MYZ is an exterior angle of the triangle , then

4k + 5 + 6k + 10 = 115

10k + 15 = 115 ( subtract 15 from both sides )

10k = 100 ( divide both sides by 10 )

k = 10

Answer:

k = 10

----------------------

Exterior angle of a triangle is equal to the sum of remote interior angles.

In the given picture, the exterior angle is 115°, and remote interior angles are (4k + 5)° and (6k + 10)°.

Set up equation and solve for k:

4k + 5 + 6k + 10 = 11510k + 15 = 11510k = 100k = 10

Therefore the value of k is 10.

given that log c3 = 0.914
PLEASE HELP MATH

Answers

Answer:

≈ 0.153

Step-by-step explanation:

using the rules of logarithms

log x - log y ⇔ log ([tex]\frac{x}{y}[/tex] )

[tex]log_{b}[/tex] b = 1

then

[tex]log_{c}[/tex] ( [tex]\frac{4}{c}[/tex] )

= [tex]log_{c}[/tex] 4 - [tex]log_{c}[/tex] c

= 1.153 - 1

= 0.153

pls help :)

Angie is really fit and wants to test her endurance by competing in a swimming competition over four days. On the first day, she covers 25 per cent of the distance. On the second day, she covers one third of the remaining distance, on the third day, 25 per cent of the remaining distance and, on the final day, she swims half of the remaining distance. She still has 15km to swim to complete the competition. Form a linear equation and find the total distance of the swimming competition. (Use x as the total distance of the swimming competition).

Answers

Let's start by using algebra to represent the problem mathematically.

On the first day, Angie covers 25% of the total distance, which can be written as:

0.25x

On the second day, she covers one third of the remaining distance. After the first day, she has 75% of the total distance left to cover. So, the distance she covers on the second day can be written as:

(1/3)(0.75x) = 0.25x

On the third day, she covers 25% of the remaining distance. After the first two days, she has 50% of the total distance left to cover. So, the distance she covers on the third day can be written as:

0.25(0.5x) = 0.125x

On the final day, she covers half of the remaining distance. After the first three days, she has 25% of the total distance left to cover. So, the distance she covers on the final day can be written as:

0.5(0.25x) = 0.125x

Adding up the distances she covered on each day, we get:

0.25x + 0.25x + 0.125x + 0.125x = 0.75x

This represents the total distance she covered over the four days.

We know that Angie still has 15km left to swim to complete the competition. So, we can set the total distance x equal to the distance she covered plus the remaining distance:

0.75x + 15 = x

Solving for x, we get:

0.25x = 15

x = 60

Therefore, the total distance of the swimming competition is 60km.

Answer: Total distance of the swimming competition is 55.56 km.

Step-by-step explanation:

Let x be the total distance of the swimming competition.

On the first day, Angie covered 25% of the total distance, which means she swam 0.25x km.

On the second day, she covered one-third of the remaining distance, which is (1 - 0.25)x = 0.75x km.

So, she swam (1/3) * 0.75x = 0.25x km on the second day.

On the third day, she covered 25% of the remaining distance, which is (1 - 0.25 - 1/3)x = 0.42x km.

So, she swam 0.25 * 0.42x = 0.105x km on the third day.

On the final day, she swam half of the remaining distance,

which is (1 - 0.25 - 1/3 - 0.5)x = 0.125x km.

The total distance she swam is the sum of the distances swum on each day:

0.25x + 0.25x + 0.105x + 0.125x = 0.73x

We know that the total distance of the competition is x - 15 km (since she still has 15 km left to swim).

So we can set up the equation:

0.73x = x - 15

Solving for x, we get:

x-0.73x = 15

0.27x = 15

x = 55.56

Therefore, the total distance of the swimming competition is 55.56 km.

Please solve this asap.​

Answers

Answer:

height= 3cm

Step-by-step explanation:

to find the base of each triangle just half the bottom to get 4cm

a^2+b^2=c^2

a^2+4^2=5^2

a^2+16=25

a^2=9

a=√9

a=3

A retail manager constructs a 95% confidence interval to estimate the mean amount of money each customer spends per visit to the retail store. Assume that all conditions have been met. The one-sample t-interval is ($10.53, $31.89). The owner of the retail store will issue the manager a bonus if the customers spend $35, on average, per visit. Is it reasonable to believe this manager will receive a bonus? No. Because a different sample might give different results, no conclusion can be drawn. No. Because the interval does not contain $35, the manager would not be issued the bonus. Yes. Because the interval representing the mean amount customers spend per visit is entirely below $35, it is reasonable to believe the manager will be issued a bonus. Yes. Because the interval representing the mean amount customers spend per visit does not contain $35, it is reasonable to believe the manager will be issued a bonus.

Answers

The correct option is: No. Because the interval does not contain $35, the manager would not be issued the bonus.

What is an interval?

An interval refers to a range of values between two points on a numerical scale. It can be represented by two numbers, called endpoints, and includes all the values that lie between these endpoints.

The two common types of intervals are closed intervals and open intervals.

According to the given information:

In a confidence interval, the range of values within which the true population parameter (in this case, the mean amount of money each customer spends per visit) is likely to fall is estimated. A 95% confidence interval means that there is a 95% probability that the true population parameter falls within the interval.

In this case, the confidence interval is ($10.53, $31.89), which means that we are 95% confident that the true mean amount customers spend per visit falls between $10.53 and $31.89. Since the interval does not contain $35, it is not reasonable to believe that the manager will receive a bonus, as the estimated mean amount spent per visit is below $35 according to the confidence interval.

The correct answer is: No. Because the interval does not contain $35, the manager would not be issued the bonus.

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is trigonometry hard?​

Answers

Answer:

yes it is pretty hard but I believe I. you

Is the graph increasing, decreasing, or constant?
-8 -6 4
A. Decreasing
B. Increasing
C. Constant
-2
4-
2
-2
AY
2
4
6
8
SUBMIT

Answers

Is the graph increasing, decreasing, or constant: C. Constant.

What is a graph?

In Mathematics and Geometry, a graph can be defined as a type of chart that is typically used for the graphical representation of data points or ordered pairs on both the horizontal and vertical lines of a cartesian coordinate, which are the x-coordinate (x-axis) and y-coordinate (y-axis) respectively.

By critically observing the graph shown above, we can reasonably infer and logically deduce that the graph is constant because it assumes only one y-value, which is represented by this equation y = 3.

In conclusion, the above is constant, rather than increasing or decreasing.

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Jason bought 91.5 pounds of fruit for a class party. The class ate 0.2 pounds of the fruit. How much fruit is left?

Answers

91.3 pounds of fruit are left

Jason bought = 91.5 pounds

class ate = 0.2 pounds

You subtract the amount the class ate from the amount Jason bought to get the amount of fruit left.

91.5 - 0.2 = 91.3 pounds

Find the gradients of lines A and B

Answers

I'm afraid you forgot to add a picture?

Given f(x)=3x2−2 and g(x)=7−1/2x2, find the following expressions.
​(a)  (f◦g)(4)     ​(b)  (g◦f)(2)     ​(c)  (f◦f)(1)     ​(d)  (g◦g)(0)

Answers

Answer:

To evaluate the composite functions (f◦g), (g◦f), (f◦f), and (g◦g), we need to substitute one function into the other and simplify the resulting expression.

(a) (f◦g)(4):

To find (f◦g)(4), we need to first find g(4) and then substitute it into f(x):

g(4) = 7 - 1/2(4)^2

= 7 - 8

= -1

Now we substitute g(4) = -1 into f(x):

(f◦g)(4) = f(g(4))

= f(-1)

= 3(-1)^2 - 2

= 1

Therefore, (f◦g)(4) = 1.

(b) (g◦f)(2):

To find (g◦f)(2), we need to first find f(2) and then substitute it into g(x):

f(2) = 3(2)^2 - 2

= 10

Now we substitute f(2) = 10 into g(x):

(g◦f)(2) = g(f(2))

= g(10)

= 7 - 1/2(10)^2

= -43

Therefore, (g◦f)(2) = -43.

(c) (f◦f)(1):

To find (f◦f)(1), we need to find f(f(1)):

f(1) = 3(1)^2 - 2

= 1

Now we substitute f(1) = 1 into f(x):

(f◦f)(1) = f(f(1))

= f(1)

= 1

Therefore, (f◦f)(1) = 1.

(d) (g◦g)(0):

To find (g◦g)(0), we need to find g(g(0)):

g(0) = 7 - 1/2(0)^2

= 7

Now we substitute g(0) = 7 into g(x):

(g◦g)(0) = g(g(0))

= g(7)

= 7 - 1/2(7)^2

= -17/2

Therefore, (g◦g)(0) = -17/2.

x=10 3x+5y=20 in the system of equations, what is the value of x

Answers

The value of x is given as x = 10 in the system of equations 3x + 5y = 20.

This means that we can substitute x = 10 into the equation 3x + 5y = 20 to solve for y:

3(10) + 5y = 20

30 + 5y = 20

5y = -10

y = -2

Therefore, the solution to the system of equations 3x + 5y = 20 and x = 10 is (x,y) = (10,-2).

On January 1, Year 2, Kincaid Company's Accounts Receivable and the Allowance for Doubtful Accounts carried balances of $74,600 and $3,700, respectively. During Year 2, Kincaid reported $208,000 of credit sales, wrote off $2,000 of receivables as uncollectible, and collected cash from receivables amounting to $258,900. Kincaid estimates that it will be unable to collect one percent (1%) of credit sales.

What effect will recognizing the uncollectible accounts expense for Year 2 have on the elements of the financial statements?

Multiple Choice

Decrease total assets and net income


Decrease total assets and increase retained earnings


Increase total assets and decrease net income


Increase total assets and retained earnings

Answers

The correct answer is: Decrease total assets and net income.

What is statistics?

Statistics is a branch of mathematics that deals with the collection, analysis, interpretation, presentation, and organization of numerical data. It involves the use of methods and techniques to gather, summarize, and draw conclusions from data.

The recognition of uncollectible accounts expense for Year 2 will decrease total assets and net income.

When uncollectible accounts expense is recognized, it is recorded as a debit to the allowance for doubtful accounts and a credit to the uncollectible accounts expense account. This reduces the balance of accounts receivable, which is a current asset, and thus decreases total assets. Additionally, recognizing this expense reduces net income by the same amount.

Therefore, the correct answer is: Decrease total assets and net income.

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What is the equation of the circle with centre
(1/2, 0)and radius 2?
Responses (attached)

Answers

The equation of the circle is (x - 1/2)^2 + y^2 = 15/4.

How to calculate the equation

The equation of a circle with center (a,b) and radius r is given by the equation:

(x - a)^2 + (y - b)^2 = r^2

Using the given values, the equation of the circle with center (1/2, 0) and radius 2 is:

(x - 1/2)^2 + (y - 0)^2 = 2^2

Expanding and simplifying, we get:

(x - 1/2)^2 + y^2 = 4 - 1/4

Therefore, the equation of the circle is:

(x - 1/2)^2 + y^2 = 15/4

So, the equation of the circle is (x - 1/2)^2 + y^2 = 15/4.

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Calculate Volume of Air passing through Filter HEPA Filter 100ft/min *- Airflow 4ft 2ft Volume = Filter Area x Airflow Velocity

Answers

The volume of air passing through the HEPA filter is 800 cubic feet per minute (CFM).

Describe Volume?

In general, volume refers to the amount of space occupied by a three-dimensional object. In physics, volume is a measure of the amount of space an object takes up, typically measured in cubic meters (m³) or cubic centimeters (cm³).

In mathematics, volume is often used to refer to the measure of the size of a solid object or region in three-dimensional space. This measure can be calculated using various methods depending on the shape of the object or region, such as integration, formulae, or counting.

For example, the volume of a cube can be calculated by multiplying its length, width, and height together. The volume of a sphere can be calculated using the formula 4/3πr³, where r is the radius of the sphere.

In finance, volume can also refer to the number of shares or contracts traded in a particular market or stock exchange over a given period of time. High trading volume often indicates a more active market, while low trading volume may indicate less interest or activity in a particular security or market.

The formula for calculating the volume of air passing through a filter is:

Volume = Filter Area x Airflow Velocity

Given that the airflow velocity is 100 ft/min and the dimensions of the filter are 4 ft x 2 ft, we can calculate the filter area as:

Filter Area = Length x Width

Filter Area = 4 ft x 2 ft

Filter Area = 8 square feet

Now we can substitute the values into the formula:

Volume = Filter Area x Airflow Velocity

Volume = 8 sq ft x 100 ft/min

Volume = 800 cubic feet per minute (CFM)

Therefore, the volume of air passing through the HEPA filter is 800 cubic feet per minute (CFM).

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Solve by using matrices.
2x -y + 3z = 180
-4x + 2y + 3z = 225
3x - 4y = 270
X
= -66, y = [?], z =
Enter

Answers

Solving the system of equations using matrices is : = -66, y = 163, and z = 11.

Solving the system of equations using matrices ?

To solve this system of equations using matrices, we can write it in the form AX = B, where:

A = coefficient matrix

X = variable matrix (containing x, y, and z)

B = constant matrix (containing the constants on the right-hand side of each equation)

So, we have:

| 2  -1  3 |   | x |   | 180 |

| -4  2  3 | x | y | = | 225 |

| 3  -4  0 |   | z |   | 270 |

We can solve for X by multiplying both sides of the equation by the inverse of A:

X = A^-1 * B

First, we need to find the inverse of A. We can do this by using the formula:

A^-1 = (1 / det(A)) * adj(A)

where det(A) is the determinant of A and adj(A) is the adjugate (transpose of the cofactor matrix) of A.

| 2  -1  3 |

| -4  2  3 |

| 3  -4  0 |

det(A) = 2(20 - 3(-4)) - (-1)(-40 - 33) + 3(-4*(-1) - 2*3) = 16

| 2  -1  3 |

| -4  2  3 |

| 3  -4  0 |

The cofactor matrix is:

| 2  9  6 |

| 12  0  -2 |

| 13  -9  8 |

Taking the transpose of the cofactor matrix gives us the adjugate of A:

| 2  12  13 |

| 9  0  -9 |

| 6  -2  8 |

So, we have:

A^-1 = (1 / det(A)) * adj(A) = (1 / 16) *

| 2  12  13 |

| 9  0  -9 |

| 6  -2  8 |

Multiplying A^-1 by B gives us:

| x |   | -66 |

| y | = | 163 |

| z |   | 11  |

Therefore, x = -66, y = 163, and z = 11.

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Home values in a town have declined 26% per year for each of the past
four years. What was the total percentage decrease in home values
during the four-year period?

Answers

Answer: 104%

Step-by-step explanation: 26% times 4 years

Find the inradius of triangle ABC.

Find the circumradius of triangle ABC.

The sides of the triangle are 5, 29, and 42.

Answers

To find the inradius of triangle ABC, we can use the formula:

inradius = area / semiperimeter,

where the semiperimeter is the sum of the three sides divided by 2, and the area can be found using Heron's formula:

semiperimeter = (5 + 29 + 42) / 2 = 38

area = sqrt(s * (s - a) * (s - b) * (s - c)), where s is the semiperimeter, and a, b, and c are the lengths of the sides.

area = sqrt(38 * (38 - 5) * (38 - 29) * (38 - 42)) = 90

inradius = area / semiperimeter = 90 / 38 = 45 / 19

Therefore, the inradius of triangle ABC is 45/19.

To find the circumradius of triangle ABC, we can use the formula:

circumradius = a/(2*sin(A)) = b/(2*sin(B)) = c/(2*sin(C)),

where a, b, and c are the lengths of the sides, and A, B, and C are the corresponding angles opposite those sides.

We can use the law of sines to find the angles:

sin(A) = (area * 2) / (a * b)
sin(B) = (area * 2) / (b * c)
sin(C) = (area * 2) / (c * a)

where area is the same area we found earlier using Heron's formula.

Substituting the values, we get:

sin(A) = 90 / (5 * 29) = 6/145
sin(B) = 90 / (29 * 42) = 10/87
sin(C) = 90 / (42 * 5) = 2/7

Now we can use the formula for the circumradius:

circumradius = a/(2*sin(A)) = b/(2*sin(B)) = c/(2*sin(C))

circumradius = 5/(2*6/145) = 29/(2*10/87) = 42/(2*2/7)

circumradius = 725/12

Therefore, the circumradius of triangle ABC is 725/12.

A coordinate plane with 2 lines drawn. The first line is labeled f(x) and passes through the points (0, negative 2) and (1, 1). The second line is labeled g(x) and passes through the points (negative 4, 0) and (0, 2). The lines intersect at about (2.5, 3.2)
How does the slope of g(x) compare to the slope of f(x)?

The slope of g(x) is the opposite of the slope of f(x).
The slope of g(x) is less than the slope of f(x).
The slope of g(x) is greater than the slope of f(x).
The slope of g(x) is equal to the slope of f(x)

Answers

Therefore, the correct answer is: The slope of g(x) is less than the slope of f(x).

Where do the X and Y axes intersect on the coordinate plane, at position 0 0?

The origin is the location where the two axes meet. On both the x- and y-axes, the origin is at 0. The coordinate plane is divided into four portions by the intersection of the x- and y-axes. The term "quadrant" refers to these four divisions.

We can use the slope formula to get the slopes of the lines f(x) and g(x):

slope of f(x) = (change in y)/(change in x) = (1 - (-2))/(1 - 0) = 3/1 = 3

slope of g(x) = (change in y)/(change in x) = (2 - 0)/(0 - (-4)) = 2/4 = 1/2

The slope of g(x) is 1/2, which is less than the slope of f(x), which is 3.

Therefore, the correct answer is: The slope of g(x) is less than the slope of f(x).

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Answer:

B

Step-by-step explanation:

Which statements are always true regarding the diagram? Select three options. m∠5 + m∠3 = m∠4 m∠3 + m∠4 + m∠5 = 180° m∠5 + m∠6 =180° m∠2 + m∠3 = m∠6 m∠2 + m∠3 + m∠5 = 180°

Answers

The answer are in angle m∠5+m∠6=180°,m∠2+m∠3=m∠6,m∠2+m∠3+m∠5=180°.

What is angle?

Angle is a geometric concept that is used to describe the relationship between two lines or planes. It is measured in degrees, with a full circle being 360 degrees. Angles are used in mathematics to measure the size of a shape and the amount of turn between two lines. In physics, angles are used to describe the force of friction, the direction of a force, and the direction of light. Angles can also be used to describe the orientation of objects in space.

case A) we have

m∠5+m∠3=m∠4 ----> equation A

we know that

m∠3+m∠4=180° -----> by supplementary by angles

m∠4=180°-m∠3 ----> equation B

substitute the equation- B in equation A

m∠5+m∠3=180°-m∠3

m∠5+m∠3+m∠3=180°

This equation is true when m∠2=m∠3

therefore

Is not always true

case B) we have

m∠3+m∠4+m∠5=180° ----> equation A

we know that

m∠3+m∠4=180° -----> by supplementary to angles

m∠4=180°-m∠3 ----> equation B

substitute equation B in equation A

m∠3+(180°-m∠3)+m∠5=180°

m∠5=0°

This option is not true

case C) we have

m∠5+m∠6=180°

we know that

m∠5 and +m∠6 are supplementary angles

so

Their sum is always 180 degrees

therefore

This option is always true

case D) we have

m∠2+m∠3=m∠6 -----> equation A

we know that

m∠5+m∠6=180° ----> by supplementary angles

m∠6=180°-m∠5 ----> equation B

substitute equation B in equation A

m∠2+m∠3=180°-m∠5

m∠2+m∠3+m∠5=180°

Remember that the sum of any of tAnswer:

Step-by-step explanation:

he interior angles that of a triangle must be equal to 180 degrees

therefore

This option is true for sure

case E) we have

m∠2+m∠3+m∠5=180°.

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what is the surface area of this figure ?

Answers

The surface area of this figure is determined as 980.5 m².

What is the surface area of the figure?

The total surface area of the figure is the sum of all the area of the six faces and it is calculated as follows;

Area of top face = 12.7 m x 11 m = 139.7 m²

Area of bottom face = 9.5 m x 16 m = 152 m²

Area of far right face = 12.7 m x 14 m = 177.8 m²

Area of far left face = 9.5 m x 14 m = 133 m²

Area of front face = 16 m x 14 m = 224 m²

Area of back face = 11 m x 14 m = 154 m²

Total surface area = 139.7 m² + 152 m² + 177.8 m² + 133 m² + 224 m² + 154 m²

= 980.5 m²

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The number of potholes in any given 1 mile stretch of freeway pavement in Pennsylvania has a bell-shaped distribution. This distribution has a mean of 62 and a standard deviation of 11. Using the empirical rule (as presented in the book), what is the approximate percentage of 1-mile long roadways with potholes numbering between 51 and 84?

Answers

According to the empirical rule (also known as the 68-95-99.7 rule), for a bell-shaped distribution (or normal distribution), approximately:

- 68% of the data falls within one standard deviation of the mean
- 95% of the data falls within two standard deviations of the mean
- 99.7% of the data falls within three standard deviations of the mean

In this case, we can use the empirical rule to estimate the percentage of 1-mile long roadways with potholes numbering between 51 and 84.

To do this, we need to first calculate the z-scores for the values 51 and 84, using the formula:

z = (x - μ) / σ

where x is the value, μ is the mean, and σ is the standard deviation.

For x = 51:

z = (51 - 62) / 11 = -1

For x = 84:

z = (84 - 62) / 11 = 2

These z-scores tell us how many standard deviations away from the mean each value is. A z-score of -1 means that the value is 1 standard deviation below the mean, and a z-score of 2 means that the value is 2 standard deviations above the mean.

Now, we can use the empirical rule to estimate the percentage of 1-mile long roadways with potholes numbering between 51 and 84:

- The percentage of data within one standard deviation of the mean is approximately 68%. Since the mean is 62 and the standard deviation is 11, one standard deviation below the mean is 51, and one standard deviation above the mean is 73 (62 - 11 = 51, 62 + 11 = 73). Therefore, approximately 68% of the 1-mile long roadways have potholes numbering between 51 and 73.
- The percentage of data within two standard deviations of the mean is approximately 95%. Since two standard deviations below the mean is 40, and two standard deviations above the mean is 84 (62 - 2(11) = 40, 62 + 2(11) = 84), approximately 95% of the 1-mile long roadways have potholes numbering between 40 and 84.

Therefore, the approximate percentage of 1-mile long roadways with potholes numbering between 51 and 84 is approximately 95%.

ZA =
Round your answer to the nearest hundredth.

Answers

Angle A equals 41.81°

c:

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