Express ratio in simplest form
1 1/2 capsicums: 1/2 onion

Step-by-step explanation:

Given :

Circumstance = 176 mm

We know that,

C = 2πr

r = C / 2π

r = 176 × 7/ 22 × 2

r = 1232/44

r = 28 mm

Now,

d = 2r = 2(28) = 56 mm

Now,

A = π r²

A = 22/7 × (28)²

A = 22/7 × 784

A = 17248/7

A = 2464 mm²

Answer:

Step-by-step explanation:

Circumference, C = 2πr

given: c=176mm, π=[tex]\frac{22}{7}[/tex]

c = 2 x [tex]\frac{22}{7}[/tex] x r

176 = [tex]\frac{44}{7}[/tex]r

r = [tex]\frac{7 *176}{44}[/tex]

r = 28

Area, A = π[tex]r^{2}[/tex]

A = [tex]\frac{22}{7}[/tex] x [tex]28^{2}[/tex]

A = 2464[tex]mm^{2}[/tex]

The average size of a customer's bill at a restaurant that earns daily $3,250 for the meals that it sells to 200 customers is $16.25. Therefore, the right answer is option (c).

The average or mean is calculated by taking the ratio of the total sum of the outcomes of an event to the frequency or the number of times the event occurs.

It can be written as [tex]\frac{n_1+n_2+.....+n_a}{a}[/tex].

In the given question, the sum of the customer bill is given as $3,250.

And the number of customers served is given to be 200.

Therefore, the average size of a customer's bill is calculated by [tex]\frac{3250}{200}[/tex]

Which turns out to be $16.25.

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The answer is $16.25. To find the average size of a customer's bill, you would divide the total earnings by the number of customers.
$3,250 / 200 customers = $16.25 per customer.

To find the average size of a customer's bill at the restaurant, you need to divide the total daily earnings by the number of customers. Here's a step-by-step explanation:

1. The restaurant earns $3,250 daily from the meals it sells.
2. The restaurant serves 200 customers daily.

Now, calculate the average bill size:

3. Divide the total daily earnings ($3,250) by the number of customers (200).

$3,250 ÷ 200 = $16.25

The average size of a customer's bill at the restaurant is $16.25.

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The number of poetry books at the library that are for children is 510

from the question, we have the following parameters that can be used in our computation:

Books = 600

If 8.5/10 of the poetry books are for children, we can calculate the number of poetry books for children as follows:

Number of poetry books for children = (8.5/10) x 600

Number of poetry books for children = 510

Therefore, there are 510 poetry books at the library for children.

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The annual incidence rate of cryptosporidiosis in your county is approximately 11.57 cases per 100,000 people.

To calculate the annual incidence rate of cryptosporidiosis in the county, we need to divide the number of reported cases (89) by the total population of the county (769,000) and multiply by 100,000 to get the rate per 100,000 people.

Annual incidence rate = (number of cases / total population) x 100,000
Annual incidence rate = (89 / 769,000) x 100,000
Annual incidence rate = 11.57 per 100,000 people
In this case, the number of cases is 89, and the total population is 769,000.

Plugging these numbers into the formula, we get:

Annual incidence rate = (89 / 769,000) x 100,000 ≈ 11.57

Therefore, the annual incidence rate of cryptosporidiosis in the county was 11.57 per 100,000 people.

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If cosθ=-3/4 and tanθ is negative, then sinθ= √(7)/4.

Since cosθ = -3/4 and θ is an angle in the second quadrant where cosθ is negative, we know that sinθ must be positive.

The Pythagorean identity is a trigonometric identity that relates the three basic trigonometric functions: sine, cosine, and tangent

To find sinθ, we can use the Pythagorean identity

sin^2θ + cos^2θ = 1

Substituting the value of cosθ we get

sin^2θ + (-3/4)^2 = 1

Simplifying

sin^2θ + 9/16 = 1

sin^2θ = 7/16

Taking the square root of both sides, we get

sinθ = ±√(7)/4

Since we know that sinθ is positive in the second quadrant, we take the positive value

sinθ = √(7)/4

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to get the equation of any straight line, we simply need two points off of it, let's use those two in the picture below

[tex](\stackrel{x_1}{40}~,~\stackrel{y_1}{30})\qquad (\stackrel{x_2}{100}~,~\stackrel{y_2}{75}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{75}-\stackrel{y1}{30}}}{\underset{\textit{\large run}} {\underset{x_2}{100}-\underset{x_1}{40}}} \implies \cfrac{ 45 }{ 60 } \implies \cfrac{ 3 }{ 4 }[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{30}=\stackrel{m}{ \cfrac{ 3 }{ 4 }}(x-\stackrel{x_1}{40}) \\\\\\ y-30=\cfrac{ 3 }{ 4 }x-30\implies {\Large \begin{array}{llll} y=\cfrac{ 3 }{ 4 }x \end{array}}[/tex]

Answer: 13 non-apple phone to 12 apple phone

Step-by-step explanation:

48 are apple phone

100-48=52   52 are non-apple phones

52:48

simplify

13:12

Answer:

m = 6

Step-by-step explanation:

We have the proportion:

12/m = 18/9

To solve for m, we can cross-multiply the terms in the proportion:

12 × 9 = 18 × m

Simplifying both sides of the equation, we get:

108 = 18m

Dividing both sides by 18, we get:m = 6

Therefore, the solution to the proportion 12/m = 18/9 is m = 6.

Answer: m = 6

Step-by-step explanation:

First, we will rewrite this proportion:

     [tex]\displaystyle \frac{12}{m} =\frac{18}{9}[/tex]

Next, we will cross-multiply:

     12 * 9 = 18 * m

     108 = 18m

Lastly, we will divide both sides of the equation by 18:

     m = 6

We can also solve this proportion another way.

     We know that 18/9 = 2, so 12/m must equal 2 as well.

     12/6 = 2, so m = 6.

The Total Surface Area and Volume of the given figure are respectively:  398 yd² and 390 yd³

The formula for the area of a rectangle is:

Area = Length * Width

Thus:

Total Surface Area = 2(9 * 3) + 2(4 * 3) + (4 * 10) + 2(9 * 10) + (10 * 3) + (10 * 7)

Total Surface Area = 398 yd²

Volume is given by the formula:

Volume = Length * Width * Height

Volume = (10 * 9 * 7) - (4 * 6 * 10)

= 630 - 240

= 390 yd³

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Answer:

  48

Step-by-step explanation:

You want to know the number of cans 4 inches tall with a volume of 50.24 in³ that will fit on a shelf with a height and depth of 10 inches and a length of 50 inches.

The diameter of the can will be found from the volume formula:

  V = (π/4)d²h

  d = √(4V/(πh)) = √(4·50.24/(4·3.14)) = √16 = 4 . . . inches

The cans are 4 inches in diameter.

The number of cans that will fit in each dimension will be the integer part of the dimension divided by the size of the can in that dimension.

  Height: (10 in)/(4 in/can) = 2.5 cans . . . . cans will fit 2 cans high

  Depth: (10 in)/(4 in/can) = 2.5 cans . . . . cans will fit 2 cans deep

  Length: (50 in/4 in/can) = 12.5 cans . . . . cans will fit 12 cans long

A total of 2 × 2 × 12 = 48 cans will fit on the shelf.

__

Additional comment

There will be 2 inches of empty space in each direction.

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Perimeter of the given triangle is 80 units. Area of the given triangle is 240 square units. Perimeter of the dilated triangle is 20 units. Area of the dilated triangle is 15 square units.

Dilation is a geometric transformation that involves scaling an object in a specific direction from a center point or origin. It is a type of similarity transformation, which means that the resulting image is similar (but not necessarily congruent) to the original object.

Dilation can be performed with respect to a point, a line, or a plane. When dilation is performed with respect to a point, the point is called the center of dilation. The scale factor determines the degree of enlargement or reduction of the object. If the scale factor is greater than 1, the object will be enlarged; if it is less than 1, the object will be reduced. If the scale factor is negative, the object will be reflected about the center of dilation.

During dilation, all points of the object move away from or towards the center of dilation. The distance between each point and the center of dilation is multiplied by the scale factor. For example, if the scale factor is 2 and the distance between a point and the center of dilation is 5, the new distance will be 2 times 5, or 10 units.

Given the given right triangle with hypotenuse = 34, perpendicular = 16, and base = 30.

First, we need to find the missing side of the triangle using the Pythagorean theorem:

a² + b² = c²

30² + 16² = c²

c = √(30² + 16²) = 34

So, the given triangle is a 30-16-34 right triangle.

Perimeter of the given triangle:

P = a + b + c

P = 30 + 16 + 34

P = 80 units

Area of the given triangle:

A = (1/2)bh

A = (1/2)(30)(16)

A = 240 square units

Perimeter of the dilated triangle:

Since the scale factor is 1/4, each side of the dilated triangle will be 1/4 of the given side.

So, the hypotenuse of the dilated triangle will be (1/4)(34) = 8.5.

The perpendicular of the dilated triangle will be (1/4)(16) = 4.

The base of the dilated triangle will be (1/4)(30) = 7.5.

Perimeter of the dilated triangle:

P' = a' + b' + c'

P' = 7.5 + 4 + 8.5

P' = 20 units

Area of the dilated triangle:

Since the scale factor is 1/4, the area of the dilated triangle will be (1/4)^2 times the area of the given triangle.

A' = (1/16)A

A' = (1/16)(240)

A' = 15 square units

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Answer:

the x-coordinate and y-coordinate change places.

Step-by-step explanation: so you reflect a point across the line y = x, the x-coordinate and y-coordinate change places. If you reflect over the line y = -x, the x-coordinate and y-coordinate change places and are negated (the signs are changed). the line y = x is the point (y, x). the line y = -x is the point (-y, -x).

Answer:

$525

Step-by-step explanation:

Jackie starts with $500, and the interest rate is 5% per year.

This means that, after one year, Jackie will have accumulated 5% interest with the $500 she put into the savings account.

Now, we can find 5% of $500 by converting 5% to its fraction form, which is 5/100. 5% of a value means that you need to multiply the fraction (or decimal) by the said value. So, we have:

[tex]\frac{5}{100}[/tex] · 500 =

[tex]\frac{2500}{100}[/tex] =

25

Therefore, the amount of interest she has accumulated in one year is $25. Combined with the money in her savings account, she has $525, since $500 + $25 = $525.

The given expression in the form ax + b will be (B) 1.8x + 4.1.

A finite collection of symbols that are properly created in line with context-dependent criteria is referred to as an expression, sometimes known as a mathematical expression.

An example is the expression x + y, which combines the terms x and y with an addition operator.

In mathematics, there are two different types of expressions: algebraic expressions, which also include variables, and numerical expressions, which solely comprise numbers.

So, we have the expression:

(3.6x-1.4) - (1.8x-5.5)

First, solve it in the form of ax + b as follows:

(3.6x-1.4) - (1.8x-5.5)

3.6x-1.4 - 1.8x+5.5

1.8x + 4.1

So, we have the expression: 1.8x + 4.1

Then, the coefficient and content will be (B) and the correct expression would be 1.8x + 4.1.

Therefore, the given expression in the form ax + b will be (B) 1.8x + 4.1.

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The sample space for each experiment are as follow;

1. rolling a 12 sided fair die, the sample space is 12

2. flipping a coin, the sample space is 2

3. pulling a face card from a standard deck of cards is 12

4. A spin from the spinner, the sample space is 5

A sample space is a collection or a set of possible outcomes of a random experiment. The sample space is represented using the symbol, “S”.

For example the sample space of getting an odd number from a 6 sided fair die is 3, because the odd numbers between 1-6 are 1,3,5.

1. The sample space of rolling a 12 sided fair die is 12, because it will have 12 faces.

2. A coin has two faces, therefore the sample space of flipping a coin is 2

3. There are 12 face cards in a standard deck, therefore, the sample space to pull a face card out of a standard deck is 12.

4. The spinner has 5faces, therefore the sample space for a spin is 5.

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The traffic data can be collected and manipulated using density level (light, medium, or heavy) at each time point.

A Markov process is a mathematical representation of how a system evolves over time in terms of a succession of states, where the system's future state depends only on the present state and not on its past development. To put it another way, a Markov process assumes that the future is independent of the past given the present and is memoryless.

Many real-world events, like stock prices, weather patterns, and traffic patterns, are modelled using Markov processes. Given the system's current state and the likelihood of switching between states, they offer a framework for predicting the behaviour of a system over time.

The traffic data can be collected and manipulated using density level (light, medium, or heavy) at each time point.

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The possible estimation of the acute angle will be 14.5⁰, 14.6⁰, 14.7⁰, 14.8⁰, 14.9⁰ or 15⁰.

An acute angle is an angle that measures less than 90 degrees. In other words, it is an angle that is smaller than a right angle. A right angle measures exactly 90 degrees, while an acute angle measures less than that.

The measure of the given angle is less than 90 degrees, and the measure can range from 0⁰ to 90 degrees.

If we are to estimate within 15⁰, then the possible measure will be 14.5⁰, 14.6⁰, 14.7⁰, 14.8⁰, 14.9⁰ or 15⁰

All the estimation of the angle given above is less than 90 degrees and can be considered an acute angle.

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Answer: 10

Step-by-step explanation:

10

The missing angles in the given pair of lines AB and CD with transversals EF & GH intersecting at O & missing sides on the basis of similarity of triangles are:

∠IKF=w°=109°

JO=z=2.7 units

∠JLO=x°=39°

∠DLO=y°=141°

What is similarity?

If two forms or figures have an equal number of comparable sides and angles, they are said to be similar. Similar figures are those when two or more figures share the same shape but have varied sizes.

Given that

∠KIO=39°

∠IKO=71°

∠IOK=70°

IO=12 units

KO=8 units

LO=4 units

a)We know that ∠KIO=∠OLJ  {alternate interior angles}

∠KIO=∠OLJ=39°

∴x° = 39°

b)We know that ∠OLJ+∠OLD=180° {linear pair}

x°+y°=180°

39°+y°=180°

y°=180-39

y°=141°

c)We know that ∠IKO+∠IKF=180° {angles on straight line}

71°+w°=180°

w°=180-71

w°=109°

d)In ΔOKI and ΔOJL, we can see that

∠OIK=∠OLJ=39°

∠OKI=∠OJL=71°

∠KOI=∠JOL=70°

as the angles are congruent, we can say that ΔOKI and ΔOJL are similar.

∴Sides will be in same ratio

[tex]\frac{OI}{OL}[/tex]  = [tex]\frac{OK}{OJ}[/tex]  = [tex]\frac{KI}{JL}[/tex]

Taking [tex]\frac{OI}{OL}[/tex]  = [tex]\frac{OK}{OJ}[/tex]

[tex]\frac{12}{4} = \frac{8}{z}[/tex]

3z = 8

z =2.667

z≈2.7 units

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The calculated value of the length of the segment EG is 54 units.

Since J is the midpoint of EG, we know that EJ = JG.

So, we can set the two expressions equal to each other and solve for x:

5x - 3 = 3x + 9

Subtracting 3x from both sides, we get:

2x - 3 = 9

Adding 3 to both sides, we get:

2x = 12

Dividing both sides by 2, we get:

x = 6

Now that we have x, we can substitute it back into either EJ or JG to find its value:

EJ = 5x - 3 = 5(6) - 3 = 27

JG = 3x + 9 = 3(6) + 9 = 27

Therefore, EG = EJ + JG = 27 + 27 = 54.

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The probability of picking a male from the population whose weight will be greater than 251 lbs is 0.13%.

In order to calculate the probability we need to use the formula of z-score

z = (x -μ)/ σ

here,

x = value of interest

μ = population mean

σ = population standard deviation

now adding the values into the given formula

z = ( 251 -182)/23

z =  69/23

z = 3

now after using the standard distribution table the probability of a z-score greater than 3 is 0.13%

The probability of picking a male from the population whose weight will be greater than 251 lbs is 0.13%.

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Answer:

.40n = 80, so n = 200

.95 × 200 = 190

Answer:

190

Step-by-step explanation:

Answer: 4,500 i got this answer

:)

Step-by-step explanation:

Answer:

Step-by-step explanation:

1.8million/400

[tex]18 * 10 ^{-1} *10^{6}*10^{-2} /4[/tex]

=4.5*10^3

=4.5*1000

=4500

The number of volunteers who worked more than 15 hours can be found by summing up the frequencies

of the bars in the histogram that represent the groups with more than 15 hours of community service.

To determine how many volunteers worked more than 15 hours using the given histogram.

Identify the section of the histogram that represents volunteers who worked more than 15 hours.

Read the height (frequency) of the bars representing the groups of volunteers with more than 15 hours of community

service.

Add the frequencies of these bars to get the total number of volunteers who worked more than 15 hours.

In conclusion, the number of volunteers who worked more than 15 hours can be found by summing up the frequencies

of the bars in the histogram that represent the groups with more than 15 hours of community service.

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The probability that the dog is still lost at the end of the second day is 0.41

To solve this problem, we can use Bayes' theorem, which allows us to update the probability of an event based on new information.

Let A be the event that the dog is in forest A, and B be the event that the dog is in forest B. Let F be the event that the dog is found within two days.

We want to calculate P(F'), the probability that the dog is still lost at the end of the second day. We can use the law of total probability to express this as

P(F') = P(F'|A) × P(A) + P(F'|B) × P(B)

where P(F'|A) is the probability of not finding the dog within two days given that the dog is in forest A, P(F'|B) is the probability of not finding the dog within two days given that the dog is in forest B, and P(A) and P(B) are the prior probabilities of the dog being in forest A and forest B, respectively.

Using the information given in the problem, we can calculate

P(F'|A) = 1 - 0.5 = 0.5 (the probability of not finding the dog in forest A within two days is 1 - 0.5 = 0.5)

P(F'|B) = 1 - 0.8 = 0.2 (the probability of not finding the dog in forest B within two days is 1 - 0.8 = 0.2)

P(A) = 0.7 (the prior probability of the dog being in forest A)

P(B) = 0.3 (the prior probability of the dog being in forest B)

Plugging these values into the formula above, we get

P(F') = 0.5 × 0.7 + 0.2 × 0.3 = 0.41

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The given question is incomplete, the complete question is:

Oscar has lost his dog; there is a 70% probability it is in forest A and a 30% chance it is forest B. If the dog is in forest A and Oscar looks there for a day, he has a 50% change of finding the dog. If the dog is in forest B and Oscar looks there for a day, he has an 80% chance of finding the dog. what is the probability that the dog is still lost at the end of the second day?

Answer:

Step-by-step explanation:

domain is -infinity to positive infinity range is -3 to infinity. Increasing from -3 to infinity and decreasing from - infinity to -3 and it’s minimum

Answer:

A. .88 < 1, so the price of Fuel A is decreasing by 12% per month.

B. Fuel B, from months 1 to 4:

[tex] \frac{3.04 - 3.44}{3.44} (100\%) = - 11.63\%[/tex]

Over this four-month period, Fuel B's price has decreased by about 11.63%.

[tex] \sqrt[3]{1 - .1163} = \sqrt[3]{.8837} = .9596[/tex]

[tex]1 - .9596 = .0404 = 4.04\%[/tex]

So Fuel B's price has been decreasing by an average of about 4.04% per month. Fuel A recorded the higher percentage change in price per month.

Some possible prices for the socks that would meet this condition are $2.99, $2.50, $3.00, $2.95, etc.

A rate is a measure of the amount of change of one quantity with respect to another quantity. It expresses how much one quantity changes in relation to another quantity over a given time or distance.

If Diego has budgeted $35 for 5 pairs of socks and a pair of shorts, we can subtract the cost of the shorts from the total budget to find the amount he has left for the socks:

$35 - $19.95 = $15.05

To find the possible prices for the socks, we can divide the amount Diego has left by the number of pairs of socks he needs:

$15.05 / 5 pairs = $3.01 per pair

Therefore, Diego would be able to stay within his budget if he finds socks that cost $3.01 or less per pair. Some possible prices for the socks that would meet this condition are $2.99, $2.50, $3.00, $2.95, etc.

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The sum of oranges they have altogether is 4x-4

Olu has 2x oranges
Umar has 4 oranges less than olu. Hence the number of oranges that Umar has can be written is (2x-4)

The number of oranges they have altogether can be calculated as

2x + (2x-4)

Remove the brackets

2x + 2x -4

4x-4

Hence the sum of oranges that Olu and Umar has is 4x-4

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(a) The probability of observing exactly 11 heads is 0.1020.

(b) The probability of observing exactly 12 heads is 0.0687.

(c) The cumulative probability of observing 12 or fewer heads is 0.9531.

a. To calculate the probability of observing exactly 11 heads in 30 flips, we can use the binomial distribution with parameters n = 30 (number of flips) and p = 0.50 (proportion of heads):

P(X = 11) = (30 choose 11) * (0.50)^11 * (1 - 0.50)^(30 - 11)

P(X = 11) = 0.1020 (rounded to four decimal places)

Therefore, the probability of observing exactly 11 heads is 0.1020.

b. To calculate the probability of observing exactly 12 heads in 30 flips, we can use the same formula:

P(X = 12) = (30 choose 12) * (0.50)^12 * (1 - 0.50)^(30 - 12)

P(X = 12) = 0.0687 (rounded to four decimal places)

Therefore, the probability of observing exactly 12 heads is 0.0687.

c. To calculate the cumulative probability of observing 12 or fewer heads (a sample proportion of 0.4 or lower), we can sum the probabilities of observing 0, 1, 2, ..., 12 heads:

P(X <= 12) = P(X = 0) + P(X = 1) + ... + P(X = 12)

We can use software or a binomial probability table to calculate these probabilities and then sum them up. Alternatively, we can use the complement rule and subtract the probability of observing 13 or more heads from 1:

P(X <= 12) = 1 - P(X >= 13)

P(X <= 12) = 1 - [P(X = 13) + P(X = 14) + ... + P(X = 30)]

Using a binomial probability table or software, we can find that:

P(X >= 13) = 0.0469 (rounded to four decimal places)

Therefore,

P(X <= 12) = 1 - P(X >= 13) = 1 - 0.0469 = 0.9531

So the cumulative probability of observing 12 or fewer heads is 0.9531.

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