Answer:
The perpendicular bisector of the line segment whose endpoints are (-3, 2) and (7, 6) is y = - 2.5x + 9================
Given Points (-3, 2) and (7, 6)To findThe equation of the perpendicular bisector of the segment with given endpoints.SolutionFind the midpoint of the segment and its slope to determine the perpendicular line passing through the midpoint.
The midpoint has coordinates:
x = ( - 3 + 7)/2 = 4/2 = 2,y = (2 + 6)/2 = 8/2 = 4.The slope:
m = (6 - 2)/(7 - (-3)) = 4/10 = 2/5We know perpendicular lines have opposite/reciprocal slopes.
So the slope of the perpendicular bisector is:
m = - 1/ (2/5) = - 5/2 = - 2.5Use the coordinates of the midpoint and point-slope equation to determine the line:
y - 4 = -2.5(x - 2)y - 4 = - 2.5x + 5y = - 2.5x + 5 + 4y = - 2.5x + 9Answer:
[tex]y=-\dfrac{5}{2}x+9[/tex]
Step-by-step explanation:
A perpendicular bisector is a line that intersects another line segment perpendicularly and divides it into two equal parts.
Given endpoints of the line segment:
(x₁, y₁) = (-3, 2)(x₂, y₂) = (7, 6)Substitute the given endpoints into the slope formula to find the slope of the line segment:
[tex]\implies \textsf{Slope $m$}=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{6-2}{7-(-3)}=\dfrac{4}{10}=\dfrac{2}{5}[/tex]
If two lines are perpendicular to each other, their slopes are negative reciprocals.
Therefore, the slope of the perpendicular line is -⁵/₂.
Find the midpoint of the given line segment by substituting the given endpoints into the midpoint formula:
[tex]\implies \textsf{Midpoint}=\left(\dfrac{x_2+x_1}{2},\dfrac{y_2+y_1}{2}\right)[/tex]
[tex]\implies \textsf{Midpoint}=\left(\dfrac{7-3}{2},\dfrac{6+2}{2}\right)[/tex]
[tex]\implies \textsf{Midpoint}=\left(\dfrac{4}{2},\dfrac{8}{2}\right)[/tex]
[tex]\implies \textsf{Midpoint}=\left(2,4\right)[/tex]
To find the equation of the perpendicular bisector, substitute the found slope and midpoint into the point-slope form of a linear equation:
[tex]\implies y-y_1=m(x-x_1)[/tex]
[tex]\implies y-4=-\dfrac{5}{2}(x-2)[/tex]
[tex]\implies y-4=-\dfrac{5}{2}x+5[/tex]
[tex]\implies y=-\dfrac{5}{2}x+9[/tex]
Therefore, the equation for the perpendicular bisector of the line segment whose endpoints are (-3, 2) and (7, 6) is:
[tex]\boxed{y=-\dfrac{5}{2}x+9}[/tex]
Solve for the value of z.
(7z+7)°
(9z-7)°
Base on congruency of vertical angles, the value of z is 7.
What are vertically opposite angles?Vertically opposite angles are angles that are opposite one another at a specific vertex and are created by two straight intersecting lines.
In other words, vertically opposite angles are angles that opposed each other at one specific vertex, and are formed by two straight intersecting line.
Vertically opposite angles are congruent to each other.
Therefore,
7z + 7 = 9z - 7
subtract 9z from both sides of the equation
7z + 7 = 9z - 7
7z - 9z + 7 = 9z - 9z - 7
-2z + 7 = - 7
subtract 7 from both sides of the equation
-2z + 7 = - 7
-2z + 7 - 7 = - 7 - 7
- 2z = - 14
divide both sides by - 2
z = - 14 / -2
Therefore,
z = 7
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Find g'(x) for g(x) = 2x√x² +7
Answer:
[tex] {2x}^{2} + 7[/tex]
so hope it helps
Simplify 8a^2 ➗ 4a
Asap please
Answer:
2a
Step-by-step explanation:
8a² / 4a
8/4 a²-¹
2a
please rate as brainliest
Answer:
2a
Step-by-step explanation:
8a^2 = 4a x 2a
8a^2 ➗ 4a
= ( 4a x 2a )/4a
= 2a
Miyako is building a raised garden bed the garden is a right rectangular prism with the dimensions shown how many cubic feet of soil does miyako need to fill the garden bed
Answer:
Step-by-step explanation 10:
For a ratio of 3:2, divide AB into 3 equal parts. Each equal part is 3 units, so the point that divides AB into a 3:2 ratio is 0. For a ratio of 3:2, divide AB into 3 equal parts. Each equal part is 3 units, so the point that divides AB into a 3:2 ratio is 3. For a ratio of 3:2, divide AB into 5 equal parts. Each equal part is 2 units, so the point that divides AB into a 3:2 ratio is 1. For a ratio of 3:2, divide AB into 5 equal parts. Each equal part is 2 units, so the point that divides AB into a 3:2 ratio is 2.
The correct option regarding the ratio is given as follows:
For a ratio of 3:2, divide AB into 5 equal parts. Each equal part is 2 units, so the point that divides AB into a 3:2 ratio is 2.
RatioA ratio of an amount a over a total amount a + b is given as follows:
r = a/(a + b) = a:b.
In the context of this problem, the ratio is given as follows:
r = 3:2.
Hence the number of equal parts is given by:
equal parts = 3 + 2 = 5.
The length of the segment is:
B - A = 6 - (-4) = 10 units.
Hence the length of each equal part is:
length equal part = 10/5 = 2.
The point that is 3/5 of the way from point -4 to point 6 is found as follows:
x - (-4) = 3/5(6 - (-4))
x + 4 = 30/5
x + 4 = 6
x = 2.
Meaning that the correct option is given by the last one.
Missing informationThe coordinates of A and B are missing, and they are given as follows:
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a list of 20182018 positive integers has a unique mode, which occurs exactly 1010 times. what is the least number of distinct values that can occur in the list?
The least number of distinct values that can occur in the list is 225.
what is mode?The value that appears the most frequently in a data collection when it is unique is known as the mode, and like the median and mean, it can be used to measure central tendency. However, occasionally there is either no mode or more than one mode. When every observed value occurs exactly once in a data collection, there is no mode.
The mode appears 10 times. That leaves 2008 numbers.
The least number of distinct values will occur if all but one of the remaining values appears 9 times
= 2008/9
=223 1/9.
So, The list can include a maximum of 225 distinct values, with the mode appearing 10 times, 223 other values nine times, and the last value once.
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Factor the expression below.
x2 – 81
Answer:
The factors are (x+9),(x−9).
Step-by-step explanation:
true or false: (justify/explain your answer) state whether a or b is the true statement below and then explain why the other statement is false. a. with a large random sample, the sample histogram will closely resemble the normal curve. b. with a large random sample, the probability density function of the sample mean will close resemble the normal curve.
By central limit theorem ,with a large random sample, the sample histogram will not closely resemble the normal curve but with a large random sample, the probability density function of the sample mean closely resembles the normal curve.
The central limit theorem for samples says that if we keep drawing larger and larger samples and calculating their means, the sample forms their own normal distribution (the sampling distribution). The normal distribution will have the same mean as the original distribution and a variance that equals the original variance divided by the sample size. The variable n is the number of values that are averaged together,and not the number of times the experiment is done.
Hence,with a large random sample, the sample histogram will not resemble the normal curve but with a large random sample, the probability density function of the sample mean will closely resemble the normal curve.
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What’s the answer to this ???
ONLY ANSWER IF YOU KNOW !!!!
A polynomial function of degree 3 with real coefficients and given zeros of -3, -1, and 4 is 4(x - 4)(x + 3)(x + 1) for which f(-2) = 24.
Any modifying value connected to a variable through multiplication is referred to as a "coefficient." Any non-imaginary number is a "real" number
How do you locate a degree 3 polynomial with real coefficients?
A polynomial of degree 3 must take the form a(xr1)(xr2)(xr3) since it has three roots. We are provided with the roots 3, 1, and 4. So, all we have to do is change these to r1, r2, and r3. We now get a(x+3)(x+1)(x4).
We must first factor the provided polynomial equation into a linear and quadratic equation in order to obtain the roots of the three-degree polynomial. The zeros of the three-degree polynomial can then be easily found.
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check whether the following are quadratic equations
x^ 2 -2x=(-2)(3-x)
The given equation x²-2x=(-2)(3-x) is a quadratic equation.
What is quadratic equation?A second-degree quadratic equation in algebra is one that involves x.
The quadratic equation is written as ax² + bx + c = 0, where x is the variable, a and b are the coefficients, and c is the constant term.
The coefficient of x2 must be a non-zero term in order for an equation to meet the definition of a quadratic equation.
given:
x²-2x=(-2)(3-x)
on expanding,
x²-2x = -6+2x
x²-4x+6 = 0
hence above equation is in form of ax²+bx+c=0, where a=1, b=-4. c=6
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Let h(x) = x+3−−−−−−√ and k(x) = 2x + 7. Find the value h(k(3)).
The value of the given function h(k(3)) when h(x) =√ x+3 and k(x) = 2x +7 is equal to 4.
As given in the question,
Given functions are :
h(x) =√ x+3 and k(x) = 2x +7
To find the value of the composite function h(k(3)) :
First calculate for k(3) we get,
k(x) = 2x+ 7
Substitute x =3 in k(x) we get,
k(3) = 2(3) +7
⇒ k(3) = 13
Now, Substitute the value of k(3) in the composite function h(k(3)) we get,
h(k(3))
= h(13)
= √ 13 +3
=√16
= 4
Therefore, the value of the given function h(k(3)) when h(x) =√ x+3 and k(x) = 2x +7 is equal to 4.
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67×73=1×3(mod 5)show works
Answer
Check Explanation
Explanation
a ≡ b (mod n)
This means a and b have the same remainder when they are divided by n
So, to check if this question works out, we divide what is on the left hand side and what is on the right hand side by what is after the mod.
1) 67 × 73 ≡ 1 × 3 (mod 5)
4891 ≡ 3 (mod 5)
So, to check,
(4891/5) = 978 remainder 1
(3/5) = 0 remainder 3
The remainders are different.
So, this equation is wrong and does not work.
This equation is false.
2) 83¹⁴⁴ ≡ 15¹⁴⁴ (mod 17)
Noting that it is the units digit that determines the remainder
3 raised to the power of a multiple of 4 gives 81 raised to the power of a positive integer
5 raised to power of a multiple of 4 gives 625 raised to the power of a positive integer
So, using these numbers,
83¹⁴⁴ ≡ 15¹⁴⁴ (mod 17)
81 ≡ 625 (mod 17)
(81/17) = 4 remainder 13
(625/17) = 36 remainder 13
The remainders are the same.
So, this equation is correct and it works.
This equation is true.
Hope this Helps!!!
What is the solution to the equation x\6 = 4\12?options:x = 2x = 6x = 4x = 1
SOLUTION
We want to solve the equation
[tex]\frac{x}{6}=\frac{4}{12}[/tex]cross multiplying, we have
[tex]\begin{gathered} 12\times x=6\times4 \\ 12x=24 \\ x=\frac{24}{12} \\ x=2 \end{gathered}[/tex]Hence the answer is x = 2, the first option
Describe the transformation.y = (x + 7)2 - 4
The parent function of the quadratic function is
[tex]y=x^2[/tex]∵ x is added by 7
∴ The graph of the function is translated 7 units to the left
∴ The image of the function will be
[tex]y=(x+7)^2[/tex]∵ The function is added by -4
∴ The graph of the function translated 4 units down
∴ The image of the function will be
[tex]y=(x+7)^2-4[/tex]The transformation is
Shift 7 units left and shift down 4
The answer is D
please helppp
What is the derivative of 2x^2(cotx)?
the derivitvte of 2x^2(cotx) is −4cot2xcsc^2(2x)
A lighthouse is located on a small island 4 km away from the nearest point P on a straight shoreline and its light makes six revolutions per minute. How fast is the beam of light moving along the shoreline when it is 1 km from P? (Round your answer to one decimal place.)
The beam of light along the shoreline when it is 1 km from P is moving at 125.66 km/min.
Given that, a lighthouse is located on a small island 4 km away from the nearest point P.
What is the differentiation?The process of finding derivatives of a function is called differentiation in calculus. A derivative is the rate of change of a function with respect to another quantity.
[tex]\frac{d\theta}{dt}[/tex] = 6 rev/min
= 6π rad/min
tan θ = x/6
[tex]\frac{d}{dt}tan\theta=\frac{d}{dt}(\frac{x}{6} )[/tex]
[tex]sec^2\frac{d\theta}{dt} = \frac{1}{6}(\frac{dx}{dt} )[/tex]
[tex]\frac{dx}{dt}=6sec^2\theta\frac{d\theta}{dt}[/tex]
At x=1 km; tan θ= x/6 = 1/6
[tex]sec^2 \theta= 1+tan^2 \theta= 1 + (\frac{1}{6})^2[/tex]
[tex]sec^2 \theta = \frac{10}{9}[/tex]
[tex]\frac{dx}{dt} = 6 sec^2\theta \frac{d\theta}{dt}[/tex]
dx/dt = 6 × 10/9 × 6π
dx/dt = 125.66 km/min
Therefore, the beam of light along the shoreline when it is 1 km from P is moving at 125.66 km/min.
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8. The equation below is the standard form of a linear equation. += ax+by=c Which of the following is an equivalent equation? A. =−+ y=−abx+cb B. =+ C. =+ y=bax+bc D. =−+
Answer:
A
Step-by-step explanation:
ax + by = c Subtract ax from both sides
by = -ax + c Divide all the way through by b
[tex]\frac{by}{b}[/tex] = [tex]\frac{-a}{b}[/tex] x + [tex]\frac{c}{b}[/tex]
y = - [tex]\frac{a}{b}[/tex] x +[tex]\frac{c}{b}[/tex]
8x^{3}+26x^{2}+19x+38x
3
+26x
2
+19x+3 is divided by 4x+34x+3.
Applying synthetic division, the quotient between 8x³ + 26x² + 19x + 3 by 4x + 3 is:
2x² + 5x + 1.
Synthetic division algorithmIn the synthetic division algorithm, the coefficients of a polynomial are each divided by a value.This divisor is the zero of the divided polynomial, which goes into the far left box.In this context of this problem, the coefficients of the polynomial 8x³ + 26x² + 19x + 3 are given as follows:
8, 26, 19 and 3.
The divisor is found as follows:
4x + 3 = 0
4x = -3
x = -3/4
x = -0.75.
The resulting coefficients of the quotient are given as follows:
8, 20, 4 and remainder of 0.
Hence the quotient is:
8x² + 20x + 4.
Which can be simplified as:
2x² + 5x + 1.
The first coefficient of the polynomial, of 8, was moved down, the multiplied by -0.75 and added to 26, resulting in 20. Then the same procedure was done with 20(multiplied with -0.75 and added with the next coefficient of 19), until the last coefficient of 3.
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arthur walks 3 km north, and then turns east and walks 4 km. what is distance traveled and his displacement?
If arthur walks 3 km north, and then turns east and walks 4 km. The distance traveled is 7km and his displacement is 5km.
Distance travelled and displacementDistance traveled:
Distance traveled = Km north + East Km
Distance traveled = 3 km + 4 km
Distance traveled = 7 km
Displacement
Using Pythagoras theorem to determine or find the displacement
B² = A ²+AB²
B² = 3 ² +4 ²
B = 9+16
B = √ 25
B = 5 km
Therefore the 7km is the distance and 5km is the displacement.
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Brainly keeps acting up if I go off or don't respond please understand it's brainly kicking me out. The last option for d is 309 yards
From the given diagram, let's find the length of the park's boundary.
We can see the side of the park's boundary is a circular arc and the top and bottom are the bases of triangles.
To find the length of the circular sides, apply the length of arc formula:
[tex]arc\text{ length=}2\pi r\ast\frac{\theta}{360}[/tex]Where:
Θ = 120 degrees
π = 3.14
radius, r = 50 yards
Hence, we have:
[tex]\text{arc length=2}\ast3.14\ast50\ast\frac{120}{360}=104.67\text{ yards}[/tex]This means the length of one circular side of the boundary is 104.67 yards.
We have two circular sides of the boundary.
The top and bottom sides form equilateral traingles.
Hence, the length of the top and bottom sides are 50 yards each.
To find the total length of the boundary, we have:
Total length = 104.67 + 104.67 + 50 + 50 = 309.34 yards
Rounding off to the nearest yard, the length of the park's boundary is:
309 yards
ANSWER:
D. 309 yards
Can someone please help
heeeeeeelp me please
Answer:
x=9
y=27
Step-by-step explanation:
the scale factor is [tex]\frac{4}{3}[/tex] so 6 × [tex]\frac{4}{3}[/tex] is x - 1
x-1 is 8
so x is 9.
Write the equation of the line that contains the point (-8,6) and has the same slope as the line represented by the table of values below.
step 1
Find the slope of the line represented by the table of values
take the points
(-8,13) and (-4,5)
m=(5-13)/(-4+8)
m=-8/4
m=-2
step 2
Write the equation of the line that contains the point (-8,6) and has the same slope as the line represented by the table
y=mx+b
we have
m=-2 -----> the same slope of the given line
point (-8,6)
substitute in the equation of the line in slope intercepot form
6=-2*(-8)+b
solve for b
6=16+b
b=-10
therefore
teh equatiion of the line is
y=-2x-10If 4x-y=-10 is a true equation, what would be the value of 6+4x-y
Answer:
-4
Step-by-step explanation:
6 + 4x-y = 6 + (4x-y) = 6 + (-10) = -4
Which of the following belongs under the radical symbol in the quadraticformula below?-bt 土?X2a
The quadratic formula for a polynomial is given by:
[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]Therefore, option (C) is correct.
Use the following data set to answer the question below.8 12 15 910121218 141510 11 12 9 17What is the mode for the data set?
12
1) Considering this Data Set:
8 12 15 9 10 12 12 18 14 15 10 11 12 9 17
2) And the fact that the mode is the central tendency measure that indicates the data point that repeats itself the most, we can tell that the mode is:
[tex]12[/tex]Note that this is the data point that repeats itself the most.
Please answer quickly
Answer:
[tex]y+2=\frac{5}{2} (x-6)[/tex]
Step-by-step explanation:
point-slope form: y-y1=m(x-x1)
x1=6
y1=-2
m=5/2
[tex]y+2=\frac{5}{2} (x-6)[/tex]
The table shows the cumulative number of minutes Alice practices clarinet for the first part of the school year:The table shows the cumulative number of minutes Alice practices clarinet for the first part of the school year:
The correct option regarding the scale and the origin of the graph are as follows:
D.
x-axis scale: 1 unit = 1 week
y-axis scale: 1 unit = 150 minutes
origin: (0 weeks, 0 minutes)
Scale and originThe scale should be chosen focusing on improving the readability of the data-set by the reader, while the origin should be chosen according to the values assumed by the variables.
In the context of this problem, the values of x, in weeks, are:
2, 3, 4, 5, 6, 7, 8.
They increase by one, hence the scale of x should be of 1 unit = 1 week.
The values of y, in minutes are given as follows:
300, 450, 600, 750, 900, 1050, 1200.
They increase by 150, hence the scale of y should be of 1 unit = 150 minutes, which is the rate of change of the problem.
As the measures are both positive values, the origin should be of (0,0), hence the correct option for the scales and the origin is option D.
Complete problemThe table is:
Weeks Minutes
2 300
3 450
4 600
5 750
6 900
7 1,050
8 1,200
The options are:
A. x-axis scale: 1 unit = 2 weeks
y-axis scale: 1 unit = 50 minutes
origin: (0 weeks, 0 minutes)
B. x-axis scale: 1 unit = 2 weeks
y-axis scale: 1 unit = 150 minutes
origin: (2 weeks, 300 minutes)
C. x-axis scale: 1 unit = 1 week
y-axis scale: 1 unit = 50 minutes
origin: (2 weeks, 300 minutes)
D. x-axis scale: 1 unit = 1 week
y-axis scale: 1 unit = 150 minutes
origin: (0 weeks, 0 minutes)
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In the figure below, XY = 15 and YZ = 17. Find XZ
The value of XZ is 32.
What is the value of XZ?
Trigonometry simply means the branch of mathematics that is concerned with functions of angles as well as their applications to calculation. It also deals with the relationship between ratios and their angles.
From the figure, XY = 15 and YZ = 17
XZ is the sum of XY and YZ:
XZ = XY + YZ
XZ = 15 + 17 = 32
Therefore, XZ is 32.
This shows the concept of trigonometry.
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-4x = -60 on a graph
The graph of the equation -4x = -60 is shown below.
How to Graph the Equation of a vertical Line?A vertical line is expressed as the equation, x = b. Here, the variable "b" is the point on the x-axis where the line intercepts the horizontal axis.
Thus, to plot the graph for a vertical line with the equation, x = b, we would simply draw a vertical line that crosses the x-axis at point b.
Given the equation, -4x = -60, rewrite the equation in the form x = b, to determine the value of b:
-4x/-4 = -60/-4 [division property of equality]
x = 15
This means that the graph of the equation, -4x = -60, would be a graph that has a vertical line that crosses the x-axis at 15.
the graph is shown below.
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