Find the value of z such that 0.03 or f the area lies to the right of z Round your answer tom2 decimal places

Find The Value Of Z Such That 0.03 Or F The Area Lies To The Right Of Z Round Your Answer Tom2 Decimal

Answers

Answer 1

ANSWER

z = 1.88

EXPLANATION

We have to find z such that the area under the normal curve to the right of that value is 0.03,

This is the same as finding z such that the area to the left of that value is 1 minus 0.03,

[tex]1-0.03=0.97[/tex]

These are the values that z-score tables show. So, we have to find a z-score where the value in the table is 0.97,

The z-score whose area to its left is closest to 0.97 is z = 1.88.

Hence, for z = 1.88, the area under the curve to its right is 0.03.

Find The Value Of Z Such That 0.03 Or F The Area Lies To The Right Of Z Round Your Answer Tom2 Decimal
Find The Value Of Z Such That 0.03 Or F The Area Lies To The Right Of Z Round Your Answer Tom2 Decimal

Related Questions

The length of a new rectangular playing field is 7 yards longer than quadruple the width. If the perimeter of the rectangular playing field is 454 yards, what are its dimensions?

Answers

The dimensions of new rectangular playing field are 183 yards and 44 yards, by the concept of perimeter of rectangle.

What is perimeter of rectangle?

The whole distance that the sides or limits of a rectangle cover is known as its perimeter. Since a rectangle has four sides, its perimeter will be equal to the sum of those four sides. Given that the perimeter is a linear measurement, the rectangle's perimeter will be expressed in meters, centimeters, inches, feet, etc.

Formula, perimeter of rectangle =2× (length +width)

Given, perimeter of rectangular playing field = 454 yards (equation 1)

Let us assume, width =x

According to question length = 4x+7 (quadruple=4times)

By the above equations,

Perimeter=2×(4x+7+x)

2×(5x+7) =454 (by equation 1)

Dividing the above equation by 2 both the sides

(5x+7) =227

Subtracting the above equation by 7 both the sides

5x=220

Dividing the above equation by 5 both the sides

x=44

Therefore, the required width of new rectangular playing field is 44 yards and length of new rectangular playing field is 183 yards

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Consumption and savings if real domestic output is $370 billion and planned investment is $15 billion

Answers

The consumption is 355 billion  .

Given,

In the question:

Consumption and savings if real domestic output is $370 billion and planned investment is $15 billion.

Now, According to the question:

Based on the given condition,

Formulate;

Aggregate expenditure (consumption)= Output - Savings= Investment

370 - 15

Calculate the sum or difference

= 355billion

Hence, The consumption is 355 billion  .

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Please help me with my Calc hw, it is not outside scope of brainly tutor. I am following along diligently, thanks!

Answers

ANSWER

[tex]-2\sqrt[]{1+\cos(x)}+C[/tex]

EXPLANATION

To solve this integral we have to use the substitution method. Let u = 1 + cos(x), then du is,

[tex]du=-\sin (x)dx[/tex]

Thus, dx is,

[tex]dx=\frac{du}{-\sin (x)}[/tex]

Replace the function and the differential in the integral,

[tex]\int \frac{\sin(x)}{\sqrt[]{1+\cos(x)}}dx=\int \frac{\sin(x)}{\sqrt[]{u}}\cdot\frac{du}{-\sin (x)}[/tex]

The sin(x) cancels out,

[tex]\int \frac{\sin(x)}{\sqrt[]{u}}\cdot\frac{du}{-\sin(x)}=-\int \frac{1}{\sqrt[]{u}}du[/tex]

We have to find a function whose derivative is 1/√u. This function is √u since its derivative is,

[tex]\frac{d}{du}(\sqrt[]{u})=\frac{1}{2\sqrt[]{u}}[/tex]

Note that a coefficient 1/2 is missing, so to cancel it out, we have to multiply by 2. Don't forget the constant of integration,

[tex]-\int \frac{1}{\sqrt[]{u}}du=-2\sqrt[]{u}+C[/tex]

Finally, we have to replace u with the function we substituted before,

[tex]-2\sqrt[]{u}+C=-2\sqrt[]{1+\cos (x)}+C[/tex]

Hence, the result of the integral is,

[tex]-2\sqrt[]{1+\cos(x)}+C[/tex]

Roberts Company has the following sales budget for the first four months and the year:
January February March April

Budgeted units to sell
200
400
800
950
Total - 2,350

Sales price per unit
$25
$25
$25
$25
Total-$25

Total sales
$5,000
$10,000
$20,000
$23,750
Total - $58,750

What is the new amount of budgeted total sales for March if the budgeted number of units is expected to be 1,100 units instead of 800 units?

A. $27,500
B. $10,000
C. $47,500
D. $66,250

Answers

Using some simple mathematical operations we can conclude that the new amount of budgeted total sales is (D) $66,250.

What are mathematical operations?Calculating a value using operands and a math operator is referred to as performing a mathematical "operation." The math operator's symbol has predetermined rules that must be applied to the supplied operands or numbers. A mathematical action is called an operation. Mathematical operations include addition, subtraction, multiplication, division, and finding the root.

So, new amount of budgeted total sales for March:

So, we know that:

2350  × 25 = $58,750

And 2350 is further:

2350 = 200 + 400 + 800 + 950.

Let's replace 800 with 1100.

Now, solve as follows:

200 + 400 + 1100 + 950 = 2,6502,650  × 25 = $66,250

Therefore, using some simple mathematical operations we can conclude that the new amount of budgeted total sales is (D) $66,250.

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wich choice shows the correct solution to 2544÷8?

Answers

ANSWER:

318

STEP-BY-STEP EXPLANATION:

We have the following operation:

[tex]2544÷8[/tex]

So the answer is 318

The correct solution to 2544/8 is the number 318

Question 39.Find the inverse of the given function. Graph both functions on the some set of axes and show the line y=x as a dotted line in the graph.

Answers

First, to find the inverse of a function, call the original function "x" and call call "x" in the original function as the inverse function:

[tex]\begin{gathered} f(x)=5x+1 \\ x=5f^{-1}(x)+1 \end{gathered}[/tex]

Now, we solve for the inverse function:

[tex]\begin{gathered} x=5f^{-1}(x)+1 \\ 5f^{-1}(x)+1=x \\ 5f^{-1}(x)=x-1 \\ f^{-1}(x)=\frac{x}{5}-\frac{1}{5} \end{gathered}[/tex]

To graph lines, we can find two points in it and draw a line that passes through both.

Let's pick x = 0 and x = 1 for the first equation:

[tex]\begin{gathered} f(0)=5\cdot0+1=1 \\ f(1)=5\cdot1+1=6 \end{gathered}[/tex]

So, we plot the points (0, 1) and (1, 6).

For the inverse, we can simply invet the coordinates, which is the same as picking x = 1 and x = 6:

[tex]\begin{gathered} f^{-1}(1)=\frac{1}{5}-\frac{1}{5}=0 \\ f^{-1}(6)=\frac{6}{5}-\frac{1}{5}=\frac{5}{5}=1 \end{gathered}[/tex]

Thus, we have the points (1, 0) and (6, 1).

The line y = x is jus the diagonal that passes though point (0, 0) and (1, 1), for example.

Putting these points and drawing the lines, we get:

Solve for the remaining angle and sides of the triangle described below. Round to the nearest hundredtheA = 50°. B = 45,a=3

Answers

Given:

The angels and sides of the triangle are

A = 50°. B = 45°, and a=3

Aim:

We need to find the angle C and sides c and b.

Explanation:

Use sine law.

[tex]\frac{\sin A}{a}=\frac{\sin B}{b}=\frac{\sin C}{c}[/tex]

[tex]\text{ Consider }\frac{\sin A}{a}=\frac{\sin B}{b}\text{ to find side b.}[/tex]

Substitute A = 50°. B = 45°, and a=3 in the equation.

[tex]\frac{\sin 50^o}{3}=\frac{\sin 45^o}{b}[/tex]

[tex]b=\frac{\sin 45^o}{\sin 50^o}\times3[/tex][tex]b=2.77[/tex]

Use the triangle sum property to find the angle C.

[tex]A+B+C=180^o[/tex]

Substitute A = 50°. and B = 45° in the equation.

[tex]50^o+45^o+C=180^o[/tex]

[tex]95^o+C=180^o[/tex]

[tex]C=180^o-95^o[/tex]

[tex]C=85^o[/tex]

[tex]\text{ Consider }\frac{\sin A}{a}=\frac{\sin C}{c}\text{ to find side c.}[/tex]

Substitute A = 50°. C= 85°, and a=3 in the equation.

[tex]\frac{\sin50^o}{3}=\frac{\sin 85^o}{c}[/tex]

[tex]c=\frac{\sin 85^o}{\sin 50^o}\times3[/tex][tex]c=3.90[/tex]

Final answer:

[tex]C=85^o[/tex][tex]b=2.77[/tex][tex]c=3.90[/tex]

A Snack company can pack 15 granola bars in a box how many boxes are needed for 600 granola bars ?

Answers

Answer:40

Step-by-step explanation: 15 bars to a box.

600 bars in total.

600/15= 40

40 boxes of granola bars

Boris's cat will be having four kittens. Boris performs asimulation by tossing a coin to model whether thesekittens will be male or female.• Let'heads (H) = female kitten• Let tails (T) = male kittenThe results of the simulation are:

Answers

Given:

Boris performs a simulation by tossing a coin to model whether these kittens will be male or female.

The total number of sample space is, N = 10.

Head for female kitten

T for male kitten.

The objective is to find the probability that at least three of the kittens will be male.

Fromthe obtained simulation, the number of sample space with at least thee tail (T) is, n(T)=4

Now, the probability of at least three of the kittens will be male can be calculated by,

[tex]undefined[/tex]

A shoe salesman earns a commission of 30%
of all shoe sales made.
Yesterday he sold 3 pairs of shoes for $70 each and 2 pairs of shoes for $80
each. How much did he earn in commission yesterday?

Answers

Answer: $111 is earn by shoe salesman as commission .

Step-by-step explanation:

As given the statement in the question be as follow.

Shoes salesman sold 3 pairs of shoes for $70 each and 2 pairs of shoes for $80 each.

Total cost of the pair of shoes = 3 × 70 + 2 × 80

                                                 = 210 + 160

                                                 = $ 370

As given

shoe salesman earns a commission of 30% of all shoe sales made.

30% is written is decimal form

= 0.30

Commission earns = 0.30 × Total cost of the pair of shoes .

                              = 0.30 × 370

                              = $ 111

Therefore $111 is earn by shoe salesman as commission .

find the measure of each of the other six angles

Answers

The measure of angle 1 is 71º, we can find this, because angle 1 and angle x form a straight line of 180º, so 180º - 109º = 71º

The measure of angle 2 is also 71º, we can use the vertical angles propierty, then m∠1 = m∠2

The measure of angle 3 is 109º, we can use again the vertical angles theorem to find that m∠x = m∠3

Themeasure of angle 7 is 109º. We need to use the alternating exterior angles theorem. Since angle x and angle 7 are not between the parallel lines they're exterior angles; and since they're on opposite sides of the transversal line, they're alternates. Then the theorem says that m∠x = m∠7

The measure of angle 6 is 71º, again we're using the fact that angle 7 and angle 6 forms a straight line, then m∠6 = 180º - 109º = 71º

Now we can find the lasts two measures using the vertical angles theorem.

The measure of angle 5 is 71º, because m∠6 = m∠5

The measure of angle 4 is 109º, because m∠7 = m∠4

The ratio of the lengths of corresponding sides of two similar triangles is 5:8. The smaller triangle has an area of 87.5cm^2. What is the area of the larger triangle

Answers

Question:

Solution:

Remember the following theorem: the ratio of the areas of two

similar triangles is equal to the ratio of the squares of their corresponding sides. Then, here A1 and A2 are areas of two similar triangles, and S1 and S2 are their corresponding sides respectively :

S1 : S2 = 5 : 8

then

[tex]\frac{S1}{S2}=\frac{5}{8}[/tex]

now, A1 = 87.5. Thus, according to the theorem, we get the following equation:

[tex](\frac{5}{8})^2=\frac{87.5}{A2}[/tex]

this is equivalent to:

[tex]\frac{25}{64}=\text{ }\frac{87.5}{A2}[/tex]

by cross-multiplication, this is equivalent to:

[tex](A2)(25)\text{ = (64)(87.5)}[/tex]

solving for A2, we get:

[tex]A2\text{ =}\frac{(64)(87.5)}{25}=224[/tex]

so that, we can conclude that the correct answer is:

The area of the larger triangle is

[tex]224cm^2[/tex]

If f(x)=x squared + 3x - 10 then over which of the following intervals is f(x)<0 ?

Answers

Given data:

The given function is f(x)= x^2 +3x-10.

The given inequality is,

[tex]\begin{gathered} f(x)<0 \\ x^2+3x-10<0 \\ x^2+5x-2x-10<0 \\ x(x+5)-2(x+5)<0 \\ (x+5)(x-2)<0 \\ -5Thus, the value of x is -5

hello can you help me with this trigonometry question and this a homework assignment

Answers

You have:

sin 2A = -√7/4

In order to determine the value of sin A, first calculate the value of angle A by using sin⁻¹ over the previous equation, just as follow:

sin⁻¹(sin 2A) = sin⁻¹(-√7/4) In this way you cancel out the sin

2A = -41.41° divide by 2 both sides

A = -41.41°/2

A = -20.705°

however, take into account that angle A is in the third quadrant. Then, it is necessary to consider the result A=-20.705° is respect to the negative x-axis.

To obtain the angle respect the positive x-axis (the normal way), you simply sum 180° to 20.705°:

20.705 + 180° = 200.705°

Next, use calculator to calculate sinA:

sin(200.705°) = -0.3535

Madeline is a salesperson who sells computers at an electronics store. She makes a base pay of $80 each day and then is paid a $20 commission for every computer sale she makes. Make a table of values and then write an equation for P,P, in terms of x,x, representing Madeline's total pay on a day on which she sells xx computers.

I need equation

Answers

The equation for 'P', representing Madeline's total pay on a day on which she sells 'x' computers is → P = 80 + 20x.

Given, At an electronics store, Madeline sells computers as a salesperson. She receives a $80-per-day base salary in addition to a $20 commission for each computer she sells.

What is Equation Modelling?

Equation modelling is the process of writing a mathematical verbal expression in the form of a mathematical expression for correct analysis, observations and results of the given problem.

We can model the equation for Madeline's total pay as follows -

P = base pay + (number of sold computer) × (cost of 1 computer)

P = 80 + 20x

Therefore, the equation for 'P', representing Madeline's total pay on a day on which she sells 'x' computers is → P = 80 + 20x

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4) Using the number line to help you, decide which fraction is larger or if they are equal: one/twos or three/fifths. Label each fraction on the number line.

Answers

Explanation:

The number line is between 0 to 1. There are 10 smaller lines in between

Each of the small lines represent 1/10 or 0.1

one/twos is the same as 1/2 = 0.5

three/fifths is the same as 3/5 = 0.6

From the above, 0.6 is greater than 0.5

Showing both numbers on the number line:

Pedro can't decide which size pizza to order. The 10-inch cheese and sausage pizza is $4.99, while the 12-inch deluxe is $5.99. If he gets the 10-inch pizza, the total price will be divided among 3people. If he chooses the 12-inch pizza, then the total price will be divided among 4 people. Which is the better buy? How much will each person pay? (Use 3.14 for r.)A. 10-inch pizza; $1.50B. 12-inch pizza; $1.50C. 10-inch pizza; $1.66 D. 12-inch pizza; $1.66

Answers

Answer: The better buy is the the 12-inch deluxe for $5.99.

B. 12-inch pizza; $1.50

Explanation:

From the information given, the 10-inch cheese and sausage pizza is $4.99, while the 12-inch deluxe is $5.99. If he gets the 10-inch pizza. We would calculate the area of both pizzas by applying the formula for calculating the area of a circle which is expressed as

Area = πr^2

where

π = 3.14

r is the radius of the circle

For the 10-inch cheese and sausage pizza,

diameter = 10

r = 10/2 = 5

Area = 3.14 x 5^2 = 78.5

If it is divided among 3 people,

each person gets 78.5/3 = 26.2 in^2

Amount that each person pays = 4.99/3 = $1.66

This means that each person pays $1.66 for 26.2 in^2

For the 12-inch cheese and sausage pizza,

diameter = 12

r = 12/2 = 6

Area = 3.14 x 6^2 = 113.04

If it is divided among 4 people,

each person gets 113.04/4 = 28.26 in^2

Amount that each person pays = 5.99/4 = $1.5

This means that each person pays $1.5 for 28.26 in^2

Thus, the better buy is the the 12-inch deluxe for $5.99.

The amount that each person pays is

B. 12-inch pizza; $1.50

Could you solve the table

Answers

The relation is decreasing by a factor of 2 each time, so:

[tex]\begin{gathered} y-9=-2(x-0) \\ y=-2x+9 \end{gathered}[/tex]

Therefore:

[tex]\begin{gathered} y(100)=-2(100)+9 \\ y(100)=-200+9 \\ y(100)=-191 \end{gathered}[/tex]

Answer:

-191

using first principles to find derivatives grade 12 calculus help image attached much appreciated

Answers

Given: The function below

[tex]y=\frac{x^2}{x-1}[/tex]

To Determine: If the function as a aximum or a minimum using the first principle

Solution

Let us determine the first derivative of the given function using the first principle

[tex]\begin{gathered} let \\ y=f(x) \end{gathered}[/tex]

So,

[tex]f(x)=\frac{x^2}{x-1}[/tex][tex]\lim_{h\to0}f^{\prime}(x)=\frac{f(x+h)-f(x)}{h}[/tex][tex]\begin{gathered} f(x+h)=\frac{(x+h)^2}{x+h-1} \\ f(x+h)=\frac{x^2+2xh+h^2}{x+h-1} \end{gathered}[/tex][tex]\begin{gathered} f(x+h)-f(x)=\frac{x^2+2xh+h^2}{x+h-1}-\frac{x^2}{x-1} \\ Lcm=(x+h-1)(x-1) \\ f(x+h)-f(x)=\frac{(x-1)(x^2+2xh+h^2)-x^2(x+h-1)}{(x+h-1)(x-1)} \end{gathered}[/tex][tex]\begin{gathered} f(x+h)-f(x)=\frac{x^3+2x^2h+xh^2-x^2-2xh-h^2-x^3-x^2h+x^2}{(x+h-1)(x-1)} \\ f(x+h)-f(x)=\frac{x^3-x^3+2x^2h-x^2h-x^2+x^2+xh^2-2xh-h^2}{(x+h-1)(x-1)} \\ f(x+h)-f(x)=\frac{x^2h+xh^2-2xh+h^2}{(x+h-1)(x-1)} \end{gathered}[/tex][tex]\begin{gathered} \frac{f(x+h)-f(x)}{h}=\frac{x^{2}h+xh^{2}-2xh+h^{2}}{(x+h-1)(x-1)}\div h \\ \frac{f(x+h)-f(x)}{h}=\frac{x^2h+xh^2-2xh+h^2}{(x+h-1)(x-1)}\times\frac{1}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{h(x^2+xh^-2x+h^)}{(x+h-1)(x-1)}\times\frac{1}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{x^2+xh-2x+h}{(x+h-1)(x-1)} \end{gathered}[/tex]

So

[tex]\lim_{h\to0}\frac{f(x+h)-f(x)}{h}=\frac{x^2-2x}{(x-1)(x-1)}=\frac{x(x-2)}{(x-1)^2}[/tex]

Therefore,

[tex]f^{\prime}(x)=\frac{x(x-2)}{(x-1)^2}[/tex]

Please note that at critical point the first derivative is equal to zero

Therefore

[tex]\begin{gathered} f^{\prime}(x)=0 \\ \frac{x(x-2)}{(x-1)^2}=0 \\ x(x-2)=0 \\ x=0 \\ OR \\ x-2=0 \\ x=2 \end{gathered}[/tex]

At critical point the range of value of x is 0 and 2

Let us test the points around critical points

[tex]\begin{gathered} f^{\prime}(x)=\frac{x(x-2)}{(x-1)^2} \\ f^{\prime}(0)=\frac{0(0-2)}{(0-1)^2} \\ f^{\prime}(0)=\frac{0(-2)}{(-1)^2}=\frac{0}{1}=0 \\ f^{\prime}(2)=\frac{2(2-2)}{(2-1)^2}=\frac{2(0)}{1^2}=\frac{0}{1}=0 \end{gathered}[/tex][tex]\begin{gathered} f(0)=\frac{x^2}{x-1}=\frac{0^2}{0-1}=\frac{0}{-1}=0 \\ f(2)=\frac{2^2}{2-1}=\frac{4}{1}=4 \end{gathered}[/tex]

The function given has both maximum and minimum point

Hence, the maximum point is (0,0)

And the minimum point is (2, 4)

which of these is closest to the unit distance between points M and M' ?

Answers

the coordinate of M is (-3, -5)

it is given that M is translated 6 unit right , and 5 unit up.

so the coordinate of M' is (-3+6 , -5 + 5) = (3, 0)

so, the distance between M and M' is,

[tex]d=\sqrt[]{(3-(-3))^2+(0-(-5))^2}[/tex][tex]\begin{gathered} d=\sqrt[]{6^2+5^2} \\ d=\sqrt[]{36+25} \\ d=\sqrt[]{61} \end{gathered}[/tex]

d = 7.81

so, the closest to the unit distance is 8

thus, the answer is option D

A publisher for promising new novel figures fixed costs at $61,000 and variable cost at $1.50 for each book produced if the book is sold to distributors for $15 each how many must be produced and sold for publisher to break even?

Answers

SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Write the given information

[tex]\begin{gathered} For\text{ the cost price function:} \\ Fixed\text{ cost=\$61,000 = constant} \\ Variable\text{ cost = \$1.50 }\times\text{ number of books} \\ Let\text{ x be the number of books produced} \end{gathered}[/tex]

The function for the cost price becomes:

[tex]61000+1.5x[/tex]

STEP 2: Get the function for the selling price

The function for the selling price becomes:

[tex]\text{ \$}15x[/tex]

STEP 3: Calculate the number of books required to break even

To get the breakeven, the cost price will be equal to selling price. Therefore,

[tex]\begin{gathered} 61000+1.5x=15x \\ Subtract\text{ 1.5x from both sides} \\ 61000+1.5x-1.5x=15x-1.5x \\ 61000=13.5x \\ Divide\text{ both sides by 13.5} \\ \frac{61000}{13.5}=\frac{13.5x}{13.5} \\ 4518.518519=x \\ x\approx4519 \end{gathered}[/tex]

Hence, the number of books that must be produced and sold to get a breakeven is approximately 4519

give the coordinates of the image of each point under a reflection across to given line.(0,8); y=x

Answers

Answer:

(8, 0)

Explanation:

Whenever a point (x,y) is reflected across the line y=x, the transformation rule is given below:

[tex](x,y)\to(y,x)[/tex]

That is, the x-coordinate and y-coordinate change places.

Therefore, the image of the point (0,8) when reflected across the line y=x is:

[tex](8,0)[/tex]

The correct answer is (8,0).

A sample of 7 students was taken to see how many pencils they were carrying.2, 3, 2, 5, 7, 1, 41. Calculate the sample mean.2. Calculate the standard deviation.

Answers

Sample mean = 3.43

sample standard deviation = 2.07

Explanation:

Given: 2, 3, 2, 5, 7, 1, 4

Total numbers = 7

1) Sample mean is calculated by finding the average of the data set

[tex]\begin{gathered} \text{Sample mean = }\frac{su\text{ m of data set}}{number\text{ of data set}} \\ \text{sample mean = }\frac{2+3+2+5+7+1+4}{7} \\ \text{sample mean = 24/7 } \\ \text{sample mean = }3.43 \end{gathered}[/tex]

2) We have sample standard deviation and population standard deviation.

SInce the question asked for sample mean, we will be calculating sample standard deviation.

Standard deviation is calculated as:

[tex]\begin{gathered} s\tan dard\text{ deviation = }\sqrt[]{\frac{\sum^{}_{}(x_1-mean)^2}{N-1}} \\ \\ s\tan dard\text{ deviation = }\sqrt[]{\frac{\sum ^{}_{}(2-3.43)^2+(3-3.43)^2+(2-3.43)^2+(5-3.43)^2+(7-3.43)^2+(1-3.43)^2+\mleft(4-3.43\mright)^2}{7-1}} \\ s\tan dard\text{ deviation = }\sqrt[]{\frac{25.7143}{6}}\text{ = }\sqrt[]{4.2857} \\ s\tan dard\text{ deviation = }2.07 \end{gathered}[/tex]

Solve for the missing side of the triangle. Round to the hundredths place if needed.

Answers

The Pythagoras theorem gives the relation for the right-angle triangle between the perpendicular, base, and hypotenuse thus the perpendicular x will be 14.70.

What is a triangle?

A triangle is a closed, 2-dimensional shape with 3 sides, 3 angles, and 3 vertices.

Triangle is a very common figure to deal with in our daily life.

In a triangle, the sum of all three angles is 180°

As per the given right-angle triangle,

Pythagoras' theorem states that in a right-angle triangle →

Hyp² = Perp² + Base²

In the given triangle Hyp = 21 , Base = 15 and Perp = x

So,

21² = x² + 15²

x² = 21² - 15²

x = √216 = 14.6993 ≈ 14.70

Hence "The value of x for the given right-angle triangle is 14.70 units".

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It’s supposed to answer in simplest formIf I die is rolled one time find the probability of

Answers

A die can have 6 possible outcomes.

The probability of an event is calculated using the formula:

[tex]P=\frac{number\text{ }of\text{ }required\text{ }outcomes}{number\text{ }of\text{ }total\text{ }outcomes}[/tex]

Therefore, the probability of rolling a 1 is gotten to be:

[tex]P=\frac{1}{6}[/tex]

The probability is 1/6.

What is the value of the expression shown? 5 – a(3² + (ab + 2)² – 7) when a = 2 and b = –3

Answers

The expression has a value of -31 when a = 2 and b = –3

How to evaluate the expression?

From the question, the expression is given as

5 – a(3² + (ab + 2)² – 7)

Also, we have the values of the variables to be

a = 2 and b = –3

Substitute a = 2 and b = –3 in the expression 5 – a(3² + (ab + 2)² – 7)

So, we have the following equation

5 – a(3² + (ab + 2)² – 7) = 5 – 2 * (3² + (2 * -3 + 2)² – 7)

Evaluate the expressions in the bracket

5 – a(3² + (ab + 2)² – 7) = 5 – 2 * (3² + (-4)² – 7)

Evaluate the exponents

5 – a(3² + (ab + 2)² – 7) = 5 – 2 * (9 + 16 – 7)

So, we have

5 – a(3² + (ab + 2)² – 7) = 5 – 2 * 18

This gives

5 – a(3² + (ab + 2)² – 7) = 5 – 36

Evaluate the difference

5 – a(3² + (ab + 2)² – 7) = -31

Hence, the value of the expression is -31

Read more abour expressions at

https://brainly.com/question/15775046

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Sarkis OganesyanCombine Like Terms (Basic, Decimals)May 20, 11:02:29 AMA triangle has side lengths of (1.1p + 9.59) centimeters, (4.5p - 5.2r)centimeters, and (5.3r + 5.4q) centimeters. Which expression represents theperimeter, in centimeters, of the triangle?14.89 + 5.6p + 0.2rO 0.1r + 5.6p + 14.99Submit Answer-0.7pr + 10.7qr + 10.6pq9.7qr + 10.9pr

Answers

The sides of the triagle have lengths:

1.1 p + 9.5 q

4.5 p - 5.2 r

5.3 r + 5.4 q

Or:

1.1 p + 0 r + 9.5 q

4.5 p - 5.2 r + 0 q

0 p + 5.3 r + 5.4 q

If we want to calculate the perimeter of the triangle, we just need to sum the three lenghts:

(1.1 + 4.5) p + (-5.2 + 5.3) r + (9.5 + 5.4) q

= 5.6 p + 0.1 r + 14.9 q

Please help with the question below (please try to answer in maximum 10/15 minutes).

Answers

Solution:

Given the dimensions of the composite figure below

[tex]\begin{gathered} For\text{ the cuboid:} \\ l=12\text{cm} \\ w=4\text{ cm} \\ h=3cm \\ For\text{ the triangular prism:} \\ a=3\text{ cm} \\ b=4\text{ cm} \\ c=13\text{ cm} \\ h=5\text{ cm} \end{gathered}[/tex]

To find the surface area, SA, of the composite figure, the formula

[tex]SA=2(lh)+2(wh)+(lw)+2(\frac{1}{2}lh)+(bc)+(ah)[/tex]

Substitute the values of the variables into the formula above

[tex]\begin{gathered} SA=2\left(12\cdot3\right)+2\left(3\cdot4\right)+\left(12\cdot4\right)+2\left(\frac{1}{2}\left(12\cdot5\right)\right)+\left(13\cdot4\right)+\left(4\cdot5\right) \\ SA=2(36)+2(12)+(48)+(60)+(52)+20 \\ SA=72+24+48+60+52+20 \\ SA=276\text{ cm}^2 \end{gathered}[/tex]

Hence, the surface area, SA, is

[tex]276\text{ cm}^2[/tex]

For what values of b will F(x) = logb x be a decreasing function?A.0 < b < 1B.0 > b > -1C.b > 0D.b < 0

Answers

Given:

There is a function given as below

[tex]F(x)=\log_bx[/tex]

Required:

For what value of b the given function in decreasing

Explanation:

The given function is logarithm function

also written as

[tex]F(x)=\frac{log\text{ x}}{log\text{ b}}[/tex]

The base b is determines that if the function is increasing or decreasing

here

for

[tex]0the given function is decreasing

for

[tex]b>1[/tex]

the given function is increasing

Final answer:

[tex]0

An inspector found 18 defective radios during an inspection. If this is 0.024% of the total number of radios inspected, how many radios were inspected?

Answers

Total number of defected radios is 18

Let the total number of defective radios be taken as y

If 0.024% of the total number of radios inspected are defective, i.e 0.024% of y

[tex]\frac{0.024}{100}y=18[/tex]

Solve for y, by cross multiplying

[tex]\begin{gathered} \frac{0.024}{100}y=18 \\ 0.024y=18\times100 \\ \text{Divide both sides by 0.024} \\ \frac{0.024y}{0.024}=\frac{1800}{0.024} \\ y=75000 \end{gathered}[/tex]

Hence, the number of radios inspected, y, is 75000

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