Help please!!!!!!!!!!!!!!!!!!!!

Answer: x < 5, see attached

Step-by-step explanation:

     To solve for x, we will isolate the given variable.

Given:

  [tex]\displaystyle 1 > \frac{x}{5}[/tex]

Multiply both sides of the equation by 5:

  [tex]\displaystyle5 > x[/tex]

Flip equation:

  [tex]\displaystyle x < 5[/tex]

     To graph, we will first plot a point on 5 with an open circle. Then, we will shade to the left since x is less than 5. See attached.

Based on the rate of change, the total charge will be $ 12.60 in 4 days

From the question, we have the following parameters that can be used in our computation:

Rate of change of investment = $3.15

Value of the investment = $12.60

Using the above as a guide, we have the following:

Number of days = Value of the investment/Rate of change of investment

Substitute the known values in the above equation, so, we have the following representation

Number of days = 12.60/3.15

Evaluate

Number of days = 4

Hence, the number of days is 4

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Where the information relating to the circle and its diameter are given, the equation of the circle would be: "(x  5)²  + y2 = 81" (Option B)

The above is determined by the standard form equation of a circle which is:

(x- h) ² + (y - k)² = r²

Here,

(h, k)  is the center of the circle and r   is the radius

In this case, the center is (-5 , 0) and the diameter is 18, so the radius is half the diameter, whic is 18/ 2 = 9

So making the required substitutions, the expression becomes:

(x-(-5))² + (y-(0))² = 9²

Which becomes

(x  5)²  + y2 = 81

Thus, it is correct to state that Option B is the equation of the circle.

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Full Question:

Although part of your question is missing, you might be referring to this full question:

The center of a circle is at (-5, 0), and the diameter of the circle is 18. Which of the following is the equation of the circle?

A. (x  5)²  + y = 9

B. (x  5)²  + y2 = 81

C. (x  5)²  + y2 = 9

D. (x  5)²  + y2  81

a) The base area of the cylinder is given as follows: 78.54 ft².

b) The height of the cylinder is given as follows: 2 ft.

The volume of a cylinder of radius r and height h is given by the equation presented as follows:

V = πr²h.

The base area is given as follows:

Ab = πr².

Considering the radius of 5 ft, the base area is of:

Ab = 3.1416 x 5²

Ab = 78.54 ft².

Considering the volume of 157.08 ft³, the height of the cylinder is obtained as follows:

78.54h = 157.08

h = 157.08/78.54

h = 2 ft.

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Answer:

  (d)  180° clockwise rotation

Step-by-step explanation:

Given points A(-2, -7), B(3, -2), C(2, -10) and A'(2, 7), B'(-3, 2), C'(-2, 10), you want to know the angle and direction that rotates ∆ABC to ∆A'B'C'.

We notice the signs of each of the coordinates of ABC have been reversed for the coordinates A'B'C'. For example, A(-2, -7) became A'(2, 7).

A line joining these points is a straight line through the origin. The measure of its angle at the origin is 180°. This is the angle of rotation of A'B'C' with respect to ABC.

The image is created by 180° clockwise rotation, choice D.

__

Additional comment

When rotation is 180°, the direction is immaterial. A clockwise rotation gets you to the same place as a counterclockwise rotation.

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The measure of variability that should be used for both sets of data to determine the location with the most consistent temperature is:

Range, because Flower Town is symmetric

A histogram is a visual representation of statistical data that makes use of rectangles to illustrate the frequency of data points over a range of successive numerical intervals of equal width. The independent variable and dependent variable are plotted along the horizontal axis and the vertical axis, respectively, in the most typical type of histogram.

Now, from the given histograms, we can see that Desert landing is skewed while Flower town is symmetrical entirely.

Thus, The measure of variability that should be used for both sets of data to determine the location with the most consistent temperature is:

Range, because Flower Town is symmetric

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Sample Response/ Explanation: The data sets could be the same, but not necessarily. It is possible for data sets to differ in their spread but still have the same measures of center. The measures of spread could be different.

The data sets could be the same, but not really. It is possible for the data sets to differ in their spread but still have the same measures of center. The measures of spread could be different though.

The range of the repairs to the cars is 241.

The sample variance is 11, 671.33

The sample standard deviation would be 108.03.

Range = Maximum repair cost - Minimum repair cost

= 456 - 215

= 241

Find mean :

= (422 + 456 + 401 + 215) / 4

= 373. 5

Sample variance :

= Sum of ( each repair cost - mean ) ² / (Number of cars - 1)

= ( 2, 340.25 + 6, 812.25 + 756.25 + 25, 105.25 ) / ( 4 - 1 )

= 11, 671. 33

Sample standard deviation:

= √sample variance

= √11, 671. 33

= 108. 03

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Answer:

33

Step-by-step explanation:

To solve for the range, simply subtract the largest-value term from the smallest-value term. First, set all numbers from least to greatest:

14 , 23 , 28 , 36 , 40 , 42 , 47

The smallest term is 14.

The largest term is 47.

Subtract 47 with 14:

[tex]47 - 14 = 33[/tex]

The given range value will be 33.

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Answer:

7

Step-by-step explanation:

a= a+b/2*h

If Lois is retiring from her job after 27 years, then if she waited for 4 years, her pension will be $38 higher than if she retires this year.

If Lois retires this year, the flat-amount is $52, So, her monthly pension can be calculated as follows;

⇒ Monthly pension = (52 × 27)/12,

⇒ Monthly pension = $117,

If Lois works for another 4 years, the flat amount used to calculate her monthly pension will increase to $60 for each year of service.

So, her monthly pension will be calculated as follows:

⇒ Monthly pension = (60 × 31)/12,

⇒ Monthly pension = $155,

So, The difference in monthly pension between retiring this year and retiring after working another 4 years can be calculated as follows:

⇒ Difference in monthly pension = $155 - $117,

⇒ Difference in monthly pension = $38,

Therefore, if Lois waits another 4 years before retiring, her monthly pension will be $38 higher than if she retires this year.

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I am not able to create visual content such as an ERD diagram, but I can guide you through the process of creating an ERD for Happy Motor's purchasing department based on the functional description provided.

First, let's identify the entities in the description:

Department (with attributes: department code, name, email)

Vehicle Type (which is produced by each department)

Component (with attributes: component code, name, price)

Vendor (with attributes: vendor code, name, email)

Order (with attributes: order number, date, total amount)

Next, let's identify the relationships between the entities:

Each department produces one or more types of vehicles

Each vehicle type requires at least one or more different specific components

Each department makes orders to buy components from vendors

Each vendor provides one or more types of components

Each order contains several different components, but all components should be from the same vendor

Each component is provided by a specified vendor

An inventory is maintained to keep track of the quantity on hand (QOH) for each component

Based on these relationships, we can create an ERD with the following entities and relationships:

Department (department code, name, email) with a one-to-many relationship with Vehicle Type

Vehicle Type (vehicle type code, name) with a many-to-many relationship with Component

Component (component code, name, price) with a many-to-one relationship with Vendor

Vendor (vendor code, name, email) with a one-to-many relationship with Component and Order

Order (order number, date, total amount) with a many-to-many relationship with Component

To show the inventory relationship, we can add an attribute to the Component entity for QOH.

Note that this is just a general outline of the ERD, and there may be additional details that need to be considered based on the specific requirements of Happy Motor's purchasing department.

To represent the inventory maintained for each component, the Component entity would have an attribute for quantity on hand (QOH).The ERD for Happy Motor® purchasing department would have the following entities and relationships:

Entities:
1. Department - with attributes: department code (PK), name, email
2. Vehicle Type - with attributes: type code (PK), name
3. Component - with attributes: component code (PK), name, price
4. Vendor - with attributes: vendor code (PK), name, email
5. Order - with attributes: order number (PK), date, total amount
Relationships:
1. Department orders Component - one-to-many (1:N) relationship between Department and Component
2. Component belongs to Vehicle Type - many-to-one (N:1) relationship between Component and Vehicle Type
3. Component is provided by Vendor - many-to-one (N:1) relationship between Component and Vendor
4. Order contains Component - many-to-many (M:N) relationship between Order and Component
5. Order is placed by Department - many-to-one (N:1) relationship between Order and Department
6. Order is placed with Vendor - many-to-one (N:1) relationship between Order and Vendor
Additionally, to represent the inventory maintained for each component, the Component entity would have an attribute for quantity on hand (QOH).

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Answer:

Step-by-step explanation:

Answer: 1040

Step-by-step explanation: y=ab

The exponential equation is: y = 1040(1.3^x)

Calculate the value of y, which stands for the albums sold, and x represents the months passed from their release. For an exponential equation structured as y = a(b^x), identify the base b to solve it mathematically.

By analyzing the last month after launch, known as March, 1040 copies were made available for public consumption. One month further down the line, in April, the gross profit jumped up to 1352 units sold.

When we divide the copies traded throughout April by those resold in March, the value identifies the base:

b=1352/1040 ≈ 1.3

Thus, applying the coefficient a for the initial sales registered during March - totaling 1,040 copies - leads us to define the following form for our equations:

y = 1040(1.3^x)

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The points of the polygon are:

(1.5, 2)

(-4, 2)

(-4, -4.5)

(1.5, -4.5)

Option D is the correct answer.

We have,

From the coordinate plane,

There are 4 points that form the polygon,

The points are all in ordered pairs.

So,

(1.5, 2)

(-4, 2)

(-4, -4.5)

(1.5, -4.5)

Thus,

The points of the polygon are:

(1.5, 2)

(-4, 2)

(-4, -4.5)

(1.5, -4.5)

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Answer: 15,625,000

Step-by-step explanation: x5, 8, 40, 200, 1,000, 5,000, 25,000, 125,000, 625,000, 3,125,000, 15,625,000

There is no association between the number of fat grams and the number of calories because there are no outliers or clusters.

To make this clear, when we claim that there is no correlation between two variables, it indicates a lack of comprehensible patterns or connections. Put another way, adjustments in one factor do not seem to impact the other.

In relation to the inquiry at hand, if fat grams and calorie figures have no notable outliers or groupings, there might be an inference that these two variables are not related.

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When p = 9 and w = 225, the value of m is 94.5

We know that m varies jointly as p and the square root of w, then we can write.

m = k*p*√w

Where k is a constant.

We know that m=21 when p=5 and w=36, replacing that we will get:

21 = k*5*√46

21 = k*30

21/30 = k

7/10 = k

Then the equation is:

m = (7/10)*p*√w

Then when p = 9 and w = 225 we will have:

m = (7/10)*9*√225

m = 94.5

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Answer:

Given system of linear equations are

2x+3y+3z=5

x−2y+z=−4

3x−y−2z=3.

Represent it in matrix form

⎣

⎢

⎢

⎡

2

1

3

3

−2

−1

3

1

−2

⎦

⎥

⎥

⎤

⎣

⎢

⎢

⎡

x

y

z

⎦

⎥

⎥

⎤

=

⎣

⎢

⎢

⎡

5

−4

3

⎦

⎥

⎥

⎤

which is in the form of AX=B

A=

⎣

⎢

⎢

⎡

2

1

3

3

−2

−1

3

1

−2

⎦

⎥

⎥

⎤

∣A∣=10+15+15=40



=0

∴ A

−1

exists

To find adjoint of A

A

11

=5,A

12

=5,A

13

=5

A

21

=3,A

22

=−13,A

23

=11

A

31

=9,A

32

=1,A

33

=−7

Adj(A)=co-factor

⎣

⎢

⎢

⎡

5

3

9

5

−13

1

5

11

−7

⎦

⎥

⎥

⎤

=

⎣

⎢

⎢

⎡

5

5

5

3

−13

11

9

1

−7

⎦

⎥

⎥

⎤

A

−1

=

∣A∣

1

Adj(A)

=

40

1

⎣

⎢

⎢

⎡

5

5

5

3

−13

11

9

1

−7

⎦

⎥

⎥

⎤

X=A

−1

B

=

40

1

⎣

⎢

⎢

⎡

5

5

5

3

−13

11

9

1

−7

⎦

⎥

⎥

⎤

⎣

⎢

⎢

⎡

5

−4

3

⎦

⎥

⎥

⎤

X=

40

1

⎣

⎢

⎢

⎡

25−12+27

25+52+3

25−44−21

⎦

⎥

⎥

⎤

X=

40

1

⎣

⎢

⎢

⎡

40

80

−40

⎦

⎥

⎥

⎤

⎣

⎢

⎢

⎡

x

y

z

⎦

⎥

⎥

⎤

=

⎣

⎢

⎢

⎡

1

2

−1

⎦

⎥

⎥

⎤

Hence, x=1,y=2 and z=−1

The solution to the system of equations is

x = 3

y = 2

z = 2

To solve for x, y, and z, we can use the elimination method or substitution method. Here, we will use the elimination method.

First, we will eliminate y from the equations by multiplying the first equation by 3 and the second equation by 1, and then adding them:

(3) (2x – y + 3z = 10)

6x – 3y + 9z = 30

(1) (x + 3y – 2z = 5)

x + 3y – 2z = 5

Adding the two equations gives:

7x + 7z = 35

Simplifying, we get

x + z = 5 (Equation 1)

Next, we will eliminate y again by multiplying the second equation by 2 and the third equation by 3, and then adding them:

(2) (x + 3y – 2z = 5)

2x + 6y – 4z = 10

(3) (3x – 2y + 4z = 12)

9x – 6y + 12z = 36

Adding the two equations gives:

11x + 8z = 46

Substituting x + z = 5 from Equation 1 into the above equation, we get:

11(x + z) + 8z = 46

11x + 19z = 46

Solving for z, we get:

z = 2

Substituting z = 2 into x + z = 5 from Equation 1, we get:

x + 2 = 5

x = 3

Finally, substituting x = 3 and z = 2 into any of the original equations, we can solve for y:

2x – y + 3z = 10

2(3) – y + 3(2) = 10

6 – y + 6 = 10

y = 2

Therefore, the solution to the system of equations is:

x = 3

y = 2

z = 2

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The area of triangle LMN is 49.61 square units.

We have,

To find the area of triangle LMN.

Area = (1/2) x base x height

where the base and height are the sides of the triangle perpendicular to each other.

First, we need to find the length of side L.

We can use the Law of Cosines.

L² = M² + N² - 2MNcos(132°)

L² = 6² + 8.3² - 268.3cos(132°)

L² = 36 + 68.89 + 99.36

L² = 204.25

L = √204.25

L = 14.28

Now that we know the length of the base of the triangle, we can find the height by dropping a perpendicular from vertex M to side LN.

Since triangle LMN is obtuse, the perpendicular will fall outside of the triangle.

Let's call the foot of the perpendicular point P.

Since M∠M is 132°, we can find the measure of the acute angle ∠LMP:

M∠LMP = 180° - M∠M

M∠LMP = 180° - 132°

M∠LMP = 48°

We can use trigonometry to find the length of MP:

tan(48°) = h/6

h = 6 x tan(48°)

h = 6.93

The area of triangle LMN is:

Area = (1/2) x base x height

Area = (1/2) x 14.28 x 6.93

Area ≈ 49.61

Thus,

The area of triangle LMN is 49.61 square units.

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In this problem, we have that the graph in fact represents a function, as there are no vertically aligned points, that is, each input is mapped to a single output.

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Answer: 70 pages

Step-by-step explanation: If she read 1/7 pages on monday and the book is 490 pages, divide. 490 ÷ 1/7 = 70. 70 × 7 is 490. So use these operations in future problems. Just make sure to read carefully!

The numeric ratio of the segment ratio are:

To find the numeric ratios of the given segment ratios, to calculate the distances between the given points.

CD: DB

The distance between C(6,2) and D(4,3) is:

CD = √[(6 - 4)² + (2 - 3)²] = √5

The distance between D(4,3) and B(-4,7) is:

DB = √[(4 + 4)² + (3 - 7)²] = 10

Therefore, the numeric ratio of CD:DB is:

CD:DB = √5:10

CE: CA

The distance between C(6,2) and E(4,2) is:

CE = √[(6 - 4)² + (2 - 2)²] = 2

The distance between A(-4,2) and C(6,2) is:

CA = √[(-4 - 6)² + (2 - 2)²] = 10

Therefore, the numeric ratio of CE:CA is:

CE:CA = 2:10

DE: BA

The distance between D(4,3) and E(4,2) is:

DE = √[(4 - 4)² + (3 - 2)²] = 1

The distance between B(-4,7) and A(-4,2) is:

BA = √[(-4 + 4)² + (7 - 2)²] = 5

Therefore, the numeric ratio of DE:BA is:

DE:BA = 1:5

CD: CB

The distance between C(6,2) and D(4,3) is:

CD = √[(6 - 4)² + (2 - 3)²] = √5

The distance between C(6,2) and B(-4,7) is:

CB = √[(6 + 4)² + (2 - 7)²] = √181

Therefore, the numeric ratio of CD:CB is:

CD:CB = √5:√181

Based on the numeric ratios, determine the type of ratio for each segment ratio:

CD: DB is a part:part ratio

CE: CA is a part:whole ratio

DE: BA is a part:part ratio

CD: CB is a part:whole ratio

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Answer:

1/60

Step-by-step explanation:

For each cake, there is a 1/20 chance to find the gold ring since it is in one of the 20 slices. The probability for each cake is independent of each other, so we multiply

1/20 x 1/20 x 1/20

=1/60

The number of photos from Julia dance class = 5/7 or 40/56 photos.

We shall use mathematical operations to calculate the photos that are of Julia dance class

Five sevenths of the images are photos from dance class, meaning that 5/7 x 56 = 40 photos from dance class.

We express the answer as a fraction with a denominator of 56 like this:

Number of photos / Total number of photos = 40/56

Number of photos from dance class / Total number of photos = 5/7

Therefore, the fraction of photos that are of Julia dance class (as a fraction with a denominator of 56) = 5/7 or 40/56.

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