Answers
Answer:
Id say beat it with a hammer and light it on fire. Then if it doesn't work, sacrifice it.
Explanation:
Related Questions
If you apply a net force of 100 N to the hoverboard, and it accelerates
2m/s/s, how much mass does it have?
Answers
Answer:
50 kgExplanation:
The mass of an object given only the force acting on it and it's acceleration can be found by using the formula
[tex]m = \frac{f}{a} \\ [/tex]
f is the force in N
a is the acceleration in m/s²
From the question
f = 100 N
a = 2 m/s²
We have
[tex]m = \frac{100}{2} = 50 \\ [/tex]
We have the final answer as
50 kgHope this helps you
The diagram below shows a 5.00-kilogram block
at rest on a horizontal, frictionless table.
5.00-kg
block
Table
Which of the following is the correct name and strength of the force holding the block up?
Answers
The name and strength of the force holding the block up is 50 N upward - Normal force.
The given parameters:
Mass of the block, m = 5 kgThe weight of the block acting downwards due to gravity is calculated as follows;
W = mg
where;
g is acceleration due to gravity = 10 m/s²W = 5 x 10
W = 50 N (downwards)
Since the block is at rest, an a force equal to the weight of the block must be acting upwards. This force is known as normal reaction.
Fₙ = 50 N (upwards)
Thus, the name and strength of the force holding the block up is 50 N upward - Normal force.
Learn more about Normal force here: https://brainly.com/question/14486416
The block will remain on the table because the normal force balances with the weight of the block. The correct answer is 50 N upward normal force
From the diagram shown a 5.00-kilogram block at rest on a horizontal, frictionless table. The weight of the block will act downward which will be
Weight W = mg
let g = 10 m/[tex]s^{2}[/tex]
W = 5 x 10
W = 50 N
The block will also produce an equal but in opposite direction of a normal force which is equal to the weight of the block. That is,
Normal force N = 50 N
The block will remain on the table because the normal force balances with the weight of the block.
Therefore, the correct name and strength of the force holding the block up is 50 N upward normal force.
Learn more about stability here: https://brainly.com/question/517289
I need help. please look at the image below and let me know I need this by 7:20 am pst.
Answers
Answer:
3(1.5) = 4.5 V
Explanation:
HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!pls
Answers
1: U-1, F,-4
2: Na-6, Mo-1, O-4
3: Bi-1, O-1, C-1, I-1
4: In-9, N-1
5: N-2, H-4, S-1, C-1
6: Ge- 15, N-4
7: N-1, H-4, C-1, I-1, O-3
8: H-7, F-1
9: N-1, O-5, H-1, S-1
10: H-8
11: Nb-1, O-1, C-1, I-3
12: C-3, F-3, S-1, O-3, H-1
13: Ag-1, C-1, N-1, O-1
14: Pb-6, H-1, As-1, O-4
2 examples of non fossil fuels ?
Answers
Answer:
-> Hydropower
-> Solar power
Explanation:
-> Hydropower
[] The power of water! It is the use of falling or fast-running water to produce electricity for power. Impoundments or da*ms are mainly used in this type of power source.
-> Solar power
[] The power of the sun! It is the use of sunlight, or solar energy, to produce electricity for power. You have probably heard of solar panels, and this is the main way to collect it.
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
Answer:
Wind energy and solar power
Explanation:
they do not use fossil fuels
A 0.50-kg block attached to an ideal spring with a spring constant of 80 N/m oscillates on a horizontal frictionless surface. The total mechanical energy is 25 J. The maximum speed of the block is:
Answers
Answer:
Explanation:
easy way
when system is all kinetic energy, velocity is at a maximum
E = ½mv²
v = √(2E/m) = √(2(25)/0.5) = √100 = 10 m/s
harder way
ω = √(k/m) = √(80/0.5) = √160 rad/s
When the system is entirely spring potential, the amplitude A is
E = ½kA²
A = √(2E/k) = √(2(25)/80) = 0.790569... = 0.79 m
maximum velocity is ωΑ = 0.79√160 = 10 m/s
A 5 kilograms bowling ball is dropped out a window. It hits the ground, and bounces upward. The velocity change of the ball is noted to be 15 m/s downward and 12 m/s upward. What is the contact time for the ball if the force applied on the ball from the ground is equal to 10 N?
Answers
Answer:
13.5
Explanation:
Mass: 5kg
Initial Velocity: -15
Final Velocity: 12
Force: 10
We can use the equation: Vf = Vi + at
We need to find acceleration, and we can use the equation, F=ma,
We have mass and the force so it would look like this, 10=5a, and 5 times 2 would equal 10, so acceleration would be 2.
Now we have all the variables to find time.
Back to Vf = Vi + at, plug the numbers in, 12 = -15 + 2(t)
Plugging them in into desmos gives 13.5 for time.
why is it so important that you take care of your nervous system?
Answers
Answer:
The nervous system handles the stress response, which, if overworked, can eventually lead to diseases ranging from high blood pressure to diabetes.
Explanation:
hope I helped
WILL GIVE BRAINLIEST!!! NO LINKS PLZ!!!!
A 225 g hockey puck is sliding on ice in an arena towards the end boards that are 15.7 m away. The puck is travelling 12.0 m/s when it slides into some rough ice (coefficient of kinetic friction= 0.550).
Determine:
a) the acceleration of the puck on the rough ice.
b) the distance from the end boards the puck is when it comes to a stop.
Please show work.
Answers
Answer:
Explanation:
a) the acceleration of the puck on the rough ice.
a = μg = 0.550(9.81) = 5.3955 = 5.40 m/s²
(comes from μ = F/N = ma/mg = a/g)
b) the distance from the end boards the puck is when it comes to a stop.
v² = u² + 2as
0² = 12.0² + 2(-5.40)s
s = 13.3 ft
so distance from the boards is
15.7 - 13.3 = 2.4 m
by the way...that's some VERY rough ice...more like sand.
A wheel in the shape of a flat, heavy, uniform, solid disk is initially at rest at the top of an inclined plane of height 2.00 m when it begins to roll down the incline. If rolling and sliding friction are neglected, what is the linear velocity, in m/s, of the center-of-mass of the wheel when it reached the bottom of the incline?
Answers
Answer:
Explanation:
If friction is neglected, the wheel cannot roll and can only slide frictionlessly and will have the same velocity at the bottom of the ramp as if it had been in free fall as it has converted the same amount of potential energy.
mgh = ½mv²
v = √(2gh) = √(2(9.81)(2.00)) = 6.26418... = 6.26 m/s
However if we do not ignore all friction and the wheel rolls without slipping down the slope, the potential energy becomes linear and rotational kinetic energy
mgh = ½mv² + ½Iω²
mgh = ½mv² + ½(½mR²)(v/R)²
2gh = v² + ½v²
2gh = 3v²/2
v = √(4gh/3) =√(4(9.81)(2.00)/3) = 5.11468... = 5.11 m/s
A car travels a certain distance from A to B with a speed of 60km/hr and then returns along the same path to the starting point with a speed of 40km/hr. Find the average speed and average velocity.
a) Km/hr
b) m/s
wrong answers will be reported!
Answers
Answer:
Explanation:
Speed is total distance traveled over time taken to do so.
If AB is measured in kilometers, time (t) for the whole trip is
t = AB/60 + AB/40
t = 2AB/120 + 3AB/120
t = 5AB/120 hrs
Average speed is distance over time
s = 2AB / (5AB/120)
s = 2(120)/5
s = 48 km/hr
s = 48(1000 m/km / 3600 s/hr) = 13.333333.... 13 m/s
Velocity is displacement over time.
As displacement is zero, velocity is zero
v = 0 km/hr = 0 m/s
Pretty harsh reporting answers just because they are wrong.
A 300 cm rope under a tension of 120 N is set into oscillation. The mass density of the rope is 120 g/cm. What is the frequency of the first harmonic mode (m
Answers
Answer:
Explanation:
f = [tex]\sqrt{T/(m/L)} / 2L[/tex]
T = 120 N
L = 3.00 m
(m/L) = 120 g/cm(100 cm/m / 1000 g/kg) = 12 kg/m
(wow that's massive for a "rope")
f = [tex]\sqrt{120/12} /(2(3))[/tex])
f = [tex]\sqrt{10\\}[/tex]/6 = 0.527 Hz
This is a completely silly exercise unless this "rope" is in space somewhere as the weight of the rope (353 N on earth) far exceeds the tension applied.
A much more reasonable linear density would be 120 g/m resulting in a frequency of √1000/6 = 5.27 Hz on a rope that weighs only 3.5 N
8 N to the left , and 4 N to the right. Find the net force. Is this balanced?
Answers
Explanation:
12N by first law of newton is net force after colloision
Explain how the linear rate spring operates?
Answers
I need a short answer ?
Answers
Answer:
Explanation:
7a) t = d/v = 100/45cos14.5 = 2.29533...= 2.30 s
7b) h = ½(9.81)(2.29533/2)² = 6.46056... = 6.45 m
or
h = (45sin14.5)² / (2(9.81)) = 6.47 m
which rounds to the same 6.5 m when limiting to the two significant digits of the initial velocity.
Use the sentence to answer the question.
Light is affected by gravity.
Which inference can be made based on this fact?
(1 point)
Light behaves differently in space than on Earth.
Light behaves differently in space than on Earth.
Gravity causes light to refract.
Gravity causes light to refract.
Light moves faster in space than on Earth.
Light moves faster in space than on Earth.
Stronger gravity causes an increase in light.
Answers
Answer:
Light behaves differently in space than on Earth.
Explanation:
Because the gravity field is greater near earth than in most of space. Not the areas near stars, black holes, pulsars, and such but in the vast emptyness between the clumpy spots.
Question 4 of 10
What is thermodynamics?
A. The movement of matter
B. The flow of fluids
C. The movement of particles
D. The flow of energy, heat, and work
SUBMIT
Answers
Answer:
Explanation:
D.
Thermodynamics is the study of how different types of energy is transferred through the chemical systems
Answer: Thermodynamics is the flow of energy, heat, and work.
Explanation: This is seen in the formula for the first law of thermodynamics, U = Q - W, or “The change of the internal energy of a system (U) is equal to the heat absorbed (Q) minus the work done by that system (W).”
An object, initially traveling at a velocity of 73 m/s, experiences an acceleration of -9.8 m/s^2. How much time will it take it to come to rest?
Answers
7.4 s
Explanation:
Given:
[tex]v_0 = 73\:\text{m/s}[/tex]
[tex]v = 0[/tex]
[tex]a = -9.8\:\text{m/s}^2[/tex]
[tex]t = ?[/tex]
To solve the time it takes for the object to come to a stop, we are going to use the equation below:
[tex]v = v_0 + at \Rightarrow t = \dfrac{v - v_0}{a}[/tex]
Using the given values above, we get
[tex]t = \dfrac{0 - 73\:\text{m/s}}{-9.8\:\text{m/s}^2}[/tex]
[tex]\;\;\;\;= 7.4\:\text{s}[/tex]
What initial speed v is required if the blocks m1 =2.5 kg and m2=1.5 kg are to travel a distance d =7.0cm before coming to rest? Assume the coefficient of kinetic friction between m1 and the tabletop is ųk=0.21
Answers
Answer:
OPTRIMUM PRIDE URGH URGH URGH
Explanation:
AHHAAHAHAHAHA
What causes the difference in the angle of the sun on the Earth's surface throughout the year?
Answers
Answer:
The axis is tilted and points to the North Star no matter where Earth is in its orbit. Because of this, the distribution of the Sun's rays changes. ... It also means that the angle at which sunlight strikes different parts of Earth's surface changes through the year.
Explanation:
Pls sub to bdoggaming if this helped
5.000 km =
3.125
mi
8.000 fl oz =
mL
Answers
Answer:
236.588 mL
Explanation:
The formula for an approximate result is to multiply the volume value by 29.574
[tex]8.000 \times 29.574 = 236.588[/tex]
Is that what you were asking for?
Calculate the change in the kinetic energy (KE) of the bottle when the mass is increased. Use the formula
KE = one half.mv2, where m is the mass and v is the speed (velocity). Assume that the speed of the soda bottle falling from a height of
0.8 m will be 4 m/s, and use this speed for each calculation.
Record your calculations in Table A of your Student Guide.
When the mass of the bottle is 0.125 kg, the KE is
✔ 1
kg m2/s2.
When the mass of the bottle is 0.250 kg, the KE is
✔ 2
kg m2/s2.
When the mass of the bottle is 0.375 kg, the KE is
✔ 3
kg m2/s2.
When the mass of the bottle is 0.500 kg, the KE is
✔ 4
kg m2/s2.
Answer included in Question
Answers
Answer:
kinetic energy is given as KE = (0.5) m v²given that : v = speed of the bottle in each case = 4 m/s when m = 0.125 kg KE = (0.5) m v² = (0.5) (0.125) (4)²
Explanation:
Answer:
1. 0.5 2. 2 3. 3.75 4. 5
Explanation:
Kyle, a 23-year-old-male, feels as if he is always on the “edge of his seat,” as if something is going to happen. He also has problems sleeping. Kyle feels nervous continuously and cannot seem to relax. When asked if he is nervous about something in particular, he can’t pinpoint the source of his anxiety.
Answers
Based on the information given, it can be posited that Kyle has a general anxiety disorder.
Generalized Anxiety Disorder is a disorder that is characterized by persistent and excessive worry about different things. People with the disorder may anticipate disaster and are concerned about money, health, family, or other issues.
Some of the effective ways of treatment are spending more time with family and friends, doing regular exercises , enough sleeping, etc.
Learn more about disorder on:
https://brainly.com/question/25771019
Important parts of stydi g physics
Answers
Answer:
put your question in proper way' i hope you understand.
Explanation:
Cody hits up food king and uses a scale to weigh the mass of an apple. if the spring potential energy in the scale is .09 j and is spring is stretched 0.6 meters, calculate the spring constant
Answers
Answer:
oK so here's what you should do is add .09 and 0.6
Explanation:
Air currents escape room level 3 how to do it
Answers
Answer:
just do it. it's simple be smart friends
What are sound detectors?
Answers
Answer:
A sound detector comes in the shape of a rectangular board which comprises a microphone as well as a processing circuitry.
Answer:
Sound detection sensor works similarly to our Ears, having diaphragm which converts vibration into signals.
Which of these is Newton's 3rd law of motion?
Equal and opposite forces
F = m x a
Inertia
Gravity
Answers
The number of wavelengths that pass a fixed point on a wave is called ______?
Answers
Explanation:
it's called a wave frequency
im pretty sure but than again I'm in Middle School but just trust me
Answer:
wave frequency i think. hope its helps
A wagon of dog treats (combined mass 55 kg) is rolling at 2.1 m/s. A dog with mass 21 kg dives into the wagon, colliding with just enough momentum to make both stop. If the collision between the dog and the wagon lasts 0.1 s, what is the magnitude of the average force that will be exerted on the dog by the collision with the wagon
Answers
Answer:
Explanation:
An impulse results in a change of momentum
If the wagon and dog both stop, they must have had equal and opposite momentums
FΔt = mΔv
F = mΔv/Δt = m(v₁ - v₀)/(t₁ - t₀)
v₁ = t₀ = 0
F = m(v₀)/t₁
F = 55(2.1)/0.1 = 1155 N
We could have also figured the dog's initial velocity and used the dog's mass in the equation as well. Result would be identical.