Answer:
30.95 cm
Explanation:
The focal length f, the object distance do, and the image distance di are related with the following equation:
[tex]\frac{1}{f}=\frac{1}{d_0}+\frac{1}{d_i}[/tex]So, replacing the values, we get:
[tex]\frac{1}{6.25}=\frac{1}{5.20}+\frac{1}{d_i}[/tex]Then, solving for di, we get:
[tex]\begin{gathered} \frac{1}{6.25}-\frac{1}{5.2}=\frac{1}{d_i} \\ -\frac{21}{650}=\frac{1}{d_i}_{} \\ -\frac{650}{21}=d_i \\ -30.95\operatorname{cm}=d_i \end{gathered}[/tex]Therefore, the image distance is 30.95 cm
a pipe that is 0.46 m long and open at both ends vibrates in the second overtone with a frequency of 1150 hz. in this situation, the distance from the center of the pipe to the nearest antinode is closest to group of answer choices zero. 7.7 cm. 15 cm. 12 cm. 3.8 cm.
The distance of the center pipe to the nearest antinode at the second harmonic frequency is closest to 12 cm.
We need to know about the harmonic frequency to solve this problem. When the string is vibrating at its second harmonic frequency, it should follow the rule
λ = L
where λ is wavelength and L is the length of the string
From the question above, we know that
f = 1150 Hz
L = 0.46 cm
Find the wavelength
λ = L
λ = 0.46 m
The distance from the center of the pipe to the nearest antidote is equal to 1/4 of the wavelength. Hence,
s = 1/4 λ
s = 1/4 . 0.46
s = 0.115 m
s ~ 12 cm
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a 60- kg mountain climber moves 10 m up a vertical slope. if the muscles in her body convert chemical energy into gravitational potential energy with an efficiency of no more than 5%, what is the chemical energy used to climb the slope?
120000 Joules of Chemical Energy is used by the climber to climb the rope.
As the climber is moving up, its gravitation potential energy energy (G) will be given by,
Gravitational potential Energy = MgH
G = MgH
Where,
M is mass of climber which is 69 Kg,
g is acceleration due to gravity which is 10m/s².
H is the height above the earth's surface which is 10 meters.
It is provided that the chemical energy is converted to gravitational energy at a rate of 5%.
So, we can write,
5% Chemical energy (C) = Gravitational potential energy (G)
So,
5%C = MgH
Putting all the values,
5C/100 = 60(10)(10)
C = 120000 Joules.
The used chemical energy is 120000 Joules.
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two boys hang by their hands from the same tree branch. the branch is straight, and grows out from the tree trunk at an angle of 30 degree above the horizontal. one boy, with a mass of 50.00 kg, is hanging 1.40 m along the branch from the tree trunk. the other boy, with a mass of 33.00 kg, is hanging 2.10 m from the tree trunk. what is the magnitude of the net torque exerted on the branch by the children? assume that the axis is located where the branch joins the tree trunk and is perpendicular to the plane formed by the branch and the trunk.
Magnitude offers products that automate and provide insights throughout the whole supply chain. Determine and emphasize any bottlenecks, potential delays, and urgent.
Calculation Magnitude?Magnitude offers products that automate and provide insights throughout the whole supply chain. Determine and emphasize any bottlenecks, potential delays, and urgent.
The size of the undertaking would have discouraged a regular man due to its importance.
Magnitude is a way to gauge a star's brightness.
inclination of tree from horizontal =30°
mass of first child m[tex]1[/tex]=50kg
distance of first child r[tex]1[/tex]=1.4
mass of first child m[tex]2[/tex]=33kg
distance of first child r[tex]2[/tex]=2.10
Torque exerted by first child
T[tex]1[/tex]=m[tex]1[/tex] cos 0*r1
T1=50*9.8 cos27*2*1.4
=489.7513N-M
Torque exerted by second child
T2=m2 cos0*r2
T2=33 *9.8cos27*2
=292.7374
Both torques are in same sense therefore
T[tex]net[/tex]=T1+T2
T[tex]net[/tex]=489.75+292.73
T[tex]net[/tex]=782.48N-m
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a canon is firing horizontally from the high wall of a castle located in the midst of a flat plain. if i drop a canon ball from the wall where the canon is located, it it takes 3 sec to hit the ground. what do i need to know to find how far away from the wall the canon balls will land when fired from the canon? the exit velocity from the canon, only. no further information is needed. the height of the wall, only.
D=44.13, Horizontal velocity is unimportant. The time it takes the cannon ball to fall to the ground is the key to determining the height of the cliff. where that cannon is present.
The speed of any projectile travelling along a Horizontal velocity is known as the horizontal velocity. When a particle or object is launched into the air at an angle other than 90 degrees, it moves along the trajectory path and changes the shape of the curve to a parabolic one.
the speed at which velocity changes over time. Due to its magnitude and direction, acceleration is a vector quantity. The first derivative of velocity with respect to time or the second derivative of position with respect to time are further examples. This is called acceleration.
Distance to the ground is d = 1/2gt^2,
where g is the acceleration rate of gravity (9.80665 m/s^2)
and t = 3 secs.
d = .5×9.80665×9 = 44.13 m.
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Answer: D=44.13, Vertical velocity is not significant. The height of the cliff can be calculated using the time it takes the cannonball to hit the earth. where there is that gun.
Explanation: The horizontal velocity is the rate at which any projectile is moving along a plane. A particle or object that is propelled into the air at an angle other than 90 degrees goes along the trajectory line and transforms the curve's shape into a parabolic one.
the rate of change of velocity over time. Acceleration is a vector number because of its size and directional characteristics. Additional examples are the second derivative of location with respect to time or the first derivative of velocity with respect to time. Here is
Distance to the ground is d = 1/2gt^2,
where g is the acceleration rate of gravity (9.80665 m/s^2)
and t = 3 secs.
d = .5×9.80665×9 = 44.13 m
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If a car can go from 0-69mi/hr in 8.0 seconds, what would be its final speed after 5.0 seconds if it’s starting speed was 50mi/hr
If a car can go from 0 - 69 mi/hr in 8.0 seconds, then the final speed after 5.0 seconds would be 41.6 m/s, if its starting speed was 50 mi/hr.
What is Velocity?The total displacement covered by any object per unit of time is known as velocity. It depends on the magnitude as well as the direction of the moving object.
The acceleration of the car If a car can go from 0-69mi/hr in 8.0 seconds,
69 miles / hour = 69 × 1609 / 3600
= 30.83 m / s
v = u + at
30.83 = 0 + a × 8.0
a = 30.83 / 8.0
= 3.85 meters / second²
50 miles per hour = 50 × 1609 / 3600
= 22.35 m / s
The velocity of the car after 5 seconds,
v = 22.35 + 3.85 × 5
= 41.6 m / s
Thus, the velocity of the car after 5 seconds would be 41.6 m / s.
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a propeller is modeled as five identical uniform rods extending radially from its axis. the length and mass of each rod are 0.711 m and 2.99 kg, respectively. when the propellor rotates at 569 rpm (revolutions per minute), what is its rotational kinetic energy?
The rotational kinetic energy of five identical uniform rods is 9436.21 joule.
We need to know about rotational kinetic energy to solve this problem. Rotational kinetic energy can be defined as the energy of a rotating object. The magnitude of rotational energy is
KE = 1/2 . I . ώ²
where KE is rotational kinetic energy, I is inertia and ώ is angular velocity.
From the question above, the given parameters are
L = 0.711 m
m = 2.99 kg
N = 5
ώ = 569 rpm = 59.59 rad/s
Find the total inertia of five identical rods
I = N . 1/2 . m . L²
I = 5 . 1/2 . 2.99 . 0.711
I = 5.31 kg.m²
Calculate the rotational kinetic energy
KE = 1/2 . I . ώ²
KE = 1/2 . 5.31 . 59.59²
KE = 9436.21 joule
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The skater eventually comes to a stop.
What has happened to all of the skater's
original potential energy?
Find the acceleration of the 1kg block m the following diagram 5n 4n 5n
Explanation:
56777^7744 hold the 4 nd add 2
Help show how you got answers
The speed at which a wave of frequency of 14 Hz and a wavelength of 3 m will travel is 42 m / s
v = λ / T
f = 1 / T
v = f λ
v = Wave speed
λ = Wavelength
T = Time period
f = Frequency
f = 14 Hz
λ = 3 m
v = 14 * 3
v = 42 m / s
Frequency is the number of time an event occurs repeatedly in an unit amount of time. Its unit is hertz which in terms of SI unit is [tex]s^{-1}[/tex].
Therefore, the speed at which the wave will travel is 42 m / s
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Imagine a black hole lacking any accretion disk whatsoever. Would this black hole produce any light? why?.
Once a beam of light enters a black hole, it can never exit.
Moreover, A black hole is a region where space-time is so curved that every possible path that light could take eventually curves back inside the black hole. As a result, once a beam of light enters a black hole, it can never exit. Because of this, a black hole is truly black and never emits light. It appears as a dark circle silhouetted by an orbiting disk of hot, glowing matter. The supermassive black hole is located at the heart of a galaxy called M87, located about 55 million light-years away, and weighs more than 6 billion solar masses.
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The potential energy of a roller coaster is 50 joules. The kinetic energy of the same coaster is 50 joules. What is the mechanical energy of the coaster?.
Mechanical energy of the coaster is 100 joules.
We need to know about mechanical energy to solve this problem. Mechanical energy is the sum of the potential energy and kinetic energy of an object. It can be written as
E = KE + PE
where E is mechanical energy, PE is potential energy and KE is kinetic energy.
From the question above, the given parameters are
KE = 50 J
PE = 50 J
By substituting the given parameters, we can calculate mechanical energy
E = KE + PE
E = 50 + 50
E = 100 J
The total energy is 100 joules
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what is the principal difference between a radio wave and light? what is the principal difference between a radio wave and light? radio waves have significantly higher frequencies than light. a radio wave is a mechanical vibration of matter and light is a vibration of electric and magnetic fields. radio waves have significantly lower frequencies than light. light is a mechanical vibration of matter and radio wave is a vibration of electric and magnetic fields.
The principal difference between a radio wave and light is that radio waves have significantly lower frequencies than light.
Explanation:
Both radio waves and light are electromagnetic waves; their main difference is their frequency. Radio waves have a lower frequency and longer wavelength than visible light waves. Light waves have a lower frequency and longer wavelength than X-rays.
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HELP!
A box is sitting on a frictionless surface when a net force of 15 N is applied to the right. If the acceleration of the box is 0.33 m/s2 to the right, what is the mass of the box?
a
2.0 kg
b
5.0 kg
c
18 kg
d
45 kg
Answer:
F=m × a - answer is D
Explanation:
F=15N
m=m
a=0.33
15÷0.33=45.45...
Study the graph shown below. It is a graphic of a car trip taken by Amber and Ken. The starting position (0,0) is their home.
Graph of position versus time, with position on the y axis from 0 to 75 miles and time on the x axis from 0 to 8.5 hours. Segment 1 goes from 0,0 to 1,30. Segment 2 goes from 1,30 to 3,50. Segment 3 goes from 3,50 to 4,50. Segment 4 goes from 4,50 to 5,70. Segment 5 goes from 5,70 to 6,70. Segment 6 goes from 6,70 to 7,30. Segment 7 goes from 7,30 to 8,0.
How far had they traveled after four hours of travel?
a
30 miles
b
40 miles
c
50 miles
d
60 miles
The distance that they had traveled after four hours is given by:
c 50 miles.
How to find the distance traveled?We are given the a set of points (x,y) in this problem, in which the input and the output are defined as follows:
Input: x is the number of hours.Output: y is the distance traveled, in miles, after a time of x hours.The endpoints of the segments are as follows:
(0,0): Initially, 0 miles were traveled.(1,30): 30 miles were traveled in one hour.(3, 50): 50 miles were traveled in three hours.(4,50): 50 miles were traveled in four hours.Hence, the distance that they had traveled after four hours is given by 50 miles, and option c is the correct option in the context of this problem (how long they had traveled).
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alena is performing a floor routine. in a tumbling run she spins through the air, increasing her angular velocity from 43.00 to6 5.00 rev/s while rotating through one-half of a revolution. how much time does this maneuver take?
The tumbling run by Alena lasted for 0.009 seconds.
The time of tumbling can be calculated using the formula -
time = (2 × theta) ÷ (initial angular velocity + final angular velocity)
Keep the values in formula to find the amount of time took while tumbling.
Time = (2 × 0.5) ÷ (43 + 65)
Performing multiplication in numerator and addition in denominator of Right Hand Side of the equation
Time = 1 ÷ 108
Performing division on Right Hand Side of the equation
Time = 0.009 seconds
Thus, Alena took 0.009 seconds in tumbling while performing floor routine.
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An electric drill transfers some energy wastefully. Aside from heat, what else carries the energy that it transfers wastefully?
Answer:
Explanation:
Mechanical energy
Answer:
The right answer is "sound" or "sound waves"
Explanation:
Electric drills are noisy, but this is not useful, so sound is a wasted energy transfer.
A 10 kg box is pulled across a level floor, where the coefficient of kinetic friction is
0.35. What horizontal force is required for an acceleration of 2.0 m/s2?
A 10 kg box is pulled across a level floor, where the coefficient of kinetic friction is 0.35. The horizontal force is required for an acceleration of 2.0 m/s2 will be 54.3 N
Newton’s second law states that the acceleration of an object depends upon two variables – the net force acting on the object and the mass of the object. The acceleration of the body is directly proportional to the net force acting on the body and inversely proportional to the mass of the body.
equation of motion will be
F(net) = mass * acceleration
F - fr = m * a
where
F = force by which the box is moving
fr = force due to friction
m = mass of the object
a = acceleration by the object is moving
F = fr + m * a
= (mu * N) + ma where N = mg
= (mu * mg) + ma
= (0.35 * 10 * 9.8) + 10 * 2
= 54.3 N
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The atomic number of aluminum is 13. What is the correct designation of the electron configuration of aluminum?.
Aluminum has the following electron configuration: 1s2, 2s2, 2p6, 3s2, and 3p1.
According to the information supplied, aluminum has an atomic number of 13. That makes it abundantly evident that the nucleus of any atom that is an isotope of aluminum will contain 13 protons. The proton number will be equal to the number of electrons surrounding the nucleus. There will be 13 electrons as a result.
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A football player kicks a football off a tee with a speed of 21 m/s at an angle of 51°.
a. What is the horizontal component of the velocity?
b. What is the vertical component of the velocity?
c. How long does it take the ball to reach its highest point?
d. What is the maximum height of the ball?
e. What is the total amount of time that the ball is in the air?
f. How far is the ball from the football player when it lands?
A football player kicks a football off a tee with a speed of 21 m/s at an angle of 51°, then the horizontal component of the velocity would be 15.58 m/s and the vertical component of the velocity would be 14.07 m/s.
What is a projectile motion?
It can be defined as the motion of any object or body when thrown from the earth's surface and follows any curved path under the effect of the gravitational force of the earth.
The horizontal component of the velocity = 21 × cos51 = 15.58 m/s
The vertical component of the velocity = 21 × sin51 = 14.07 m/s
Thus, the horizontal component of the velocity would be 15.58 m/s and the vertical component of the velocity would be 14.07 m/s.
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Isaac is practicing his volleyball skills by volleying a ball straight up and down, over and over again. His teammate
Marie notices that after one volley, the ball rises 3.6 m above Isaac's hands. What is the speed with which the ball left
Isaac's hand? (8.4 m/s)
Answer:
the velocity of a ball at highest point is 8.5m/s
Explanation:
: The Freefall Problem
Xue,is standing on the roof of a building. Emily is standing below and tosses a ball straight upwards to Xue. It travels up past
Xue, comes back down and Xue reaches out and catches it. Xue catches the ball 6.0 m above Emily’s hands. The ball was
travelling at 12.0 m/s upwards the moment it left Emily’s hand. We would like to know how much time this trip takes.
1. Represent. Complete part A below. Indicate the y-origin for position measurements and draw a sign convention where
upwards is positive. Label the important events.
2. Represent. Complete part C below. Make sure the two graphs line-up vertically. Draw a single dotted vertical line
through the graphs indicating the moment when the ball is at its highest.
A: Pictorial Representation
Sketch, coordinate system, label givens, conversions, describe events
Event 1:
Event 2:
Event 3:
C: Physics Representation
Motion diagram, motion graphs, key events
The total length of the path traveled by an object is the distance. The change in position, from one event to another is the
displacement. Distance is a scalar quantity and displacement is a vector quantity.
3. Reason. Explain why this in this example it is relatively easy to find the displacement, but harder to find the distance.
4. Reason. The BIG 5 equations are valid for any interval of motion where the acceleration is uniform. Does the ball
accelerate uniformly during events 1 and 3? Explain D: Mathematical Representation
Describe steps, complete equations, substitutions with final statement isThere are multiple ways of solving…one
will require the use of the quadratic formula.
The other way will take additional steps.
x = -b+-under root b^2-4ac/2a
the one component of the material of the milky way galaxy that prevents us from seeing and photographing the galactic center at optical wavelengths is the one component of the material of the milky way galaxy that prevents us from seeing and photographing the galactic center at optical wavelengths is very cold hydrogen gas. hot hydrogen gas. the glare of light from nearby stars. interstellar dust.
The one component of the material of the milky way galaxy that prevents us from seeing and photographing the galactic center at optical wavelengths is interstellar dust.
The Milky Way is a vast collection of stars dust and gas. It is called a spiral galaxy because it looks like a spinning windmill when viewed from above or below. The Sun is in one of the spiral arms about 25,000 light-years away from the center of the galaxy. Astronomers have released the first images of a supermassive black hole at the center of our Milky Way.
The results provide overwhelming evidence that this object is indeed a black hole and provide valuable clues about the workings of the giant galaxies thought to reside at the center of most galaxies. This extreme environment exposes you to intense UV and X-rays. But much of this activity is obscured from view by a huge plume of interstellar dust. The center of our Milky Way is hidden from the prying eyes of optical telescopes by clouds of dust and gas.
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light enters glass from air. the angle of refraction will be: group of answer choices less than the angle of incidence. equal to the angle of incidence. greater than the angle of incidence
Less than the angle of incidence, the angle of refraction will exist.
What is angle of refraction?Angle of refraction refers to the angle formed by the refracted ray and the normal at the point of incident.
In a mirror, the angle of incidence and angle of reflection are the same. If the incident ray falls along the normal, the angle of incidence for a plane mirror is 0 degrees rather than 90 degrees.
The behavior of light is described by Fermat's principle, which states that a light ray always chooses the shortest route to its destination. On reflection, the exact same behavior is seen. The angle of incidence and the angle of reflection are equal when a ray is reflected from a plane.
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A bar magnet is cut into two pieces from the middle as shown in the figure. Mark the poles on these magnets if it is further broken into smaller pieces?
Giving brainliest!
If we cut the magnet into smaller pieces as we can see in the image attached to the question then each of the ends of the smaller magnets would form a north and south pole respectively.
What is a magnet?The term magnet can be used to describe the material that is able to pick up any magnetizable material. We have to note that a magnet is able to create a magnetic field around it. The magnetic field is the vicinity where the impact of the magnet can be felt.
We know that a magnet has two poles, the north pole and the south pole. These are the points where the influence of the magnetic field is greatest In this discussion, we must keep it at the back of our minds that the influence of the magnetic force is stronger at the ends of the magnet than it is at the center of the magnet as it were.
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What is the magnitude of the velocity of the plane
We will have the following:
First, we are told that the wind accelerates directly northwest, that means that the angle of inclination is 45°, so the following is true:
[tex]\begin{gathered} \sum F_x=115-75cos(45) \\ \\ \sum F_y=75sin(45) \end{gathered}[/tex]Then:
[tex]\begin{gathered} v_f=\sqrt{(115-75cos(45))^2+(75sin(45))^2}\Rightarrow v_f=81.56229536... \\ \\ \Rightarrow v_f\approx81.6 \end{gathered}[/tex]So, the magnitude of the final velocity is approximately 81.6 m/s.
a 0.230-kg block along a horizontal track has a speed of 1.40 m/s immediately before colliding with a light spring of force constant 3.75 n/m located at the end of the track. (a) what is the spring's maximum compression if the track is frictionless? m (b) if the track is not frictionless, would the spring's maximum compression be greater than, less than, or equal to the value obtained in part (a)? greater less equal
The spring's maximum compression is 0.346 when mass of the block is 0.230 Kg and Speed is 1.40 m/s.
given,
mass of block = 0.230 Kg
speed = 1.40 m/s
spring constant = k = 3.75 N/m
using conservation of energy
a) K.E = P.E
1/2mv^2=1/2kx^2
1/2*0.23*1.40^2=1/2*3.75*x^2
X^2=0.120
X=0.346
b) The maximum compression will be equal to the compression in part an if the track is not friction-less.
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The deepest section of ocean in the world is the Mariana Trench, located in the Pacific Ocean. Here,the ocean floor is as low as 10,918m below the surface. If the index of refraction of water is 1.33, howlong would it take a laser beam to reach the bottom of the treach?
Given:
The depth of the trench, d=10,918 m
The refractive index of the water, n=1.33
To find:
The time it takes for the laser beam to reach the bottom of the ocean.
Explanation:
The refractive index of water is given by,
[tex]n=\frac{c}{v}[/tex]Where c is the velocity of the laser in vacuum and v is the velocity of the laser in water.
On substituting the known values,
[tex]\begin{gathered} 1.33=\frac{3\times10^8}{v} \\ \implies v=\frac{3\times10^8}{1.33} \\ =2.3\times10^9\text{ m/s} \end{gathered}[/tex]The velocity is given by the equation,
[tex]v=\frac{d}{t}[/tex]Where t is the time it takes for the laser to reach the bottom of the trench.
On substituting the known values,
[tex]\begin{gathered} 2.3\times10^8=\frac{10,918}{t} \\ \implies t=\frac{10,918}{2.3\times10^8} \\ =47.5\times10^{-6}\text{ s} \\ =47.5\text{ }\mu\text{s} \end{gathered}[/tex]Final answer:
The laser beam would reach the bottom in 47.5 μs
what is the loudness and softness of music related to specifically? multiple choice question. beats of two tones that are similar in frequency tone color of the instrument producing the sound frequency of the vibration that produces the sound amplitude of the vibration that produces the sound
The correct answer choice from above among loudness and softness of music in a wave system is connected by means of amplitude of the vibration that produces the sound.
The correct answer choice is option d.
How the loudness and softness of music is linked with amplitude.In general, the amplitude of a wave of a music is related to how soft or loud a music is as this depends largely on that force of vibration in the the musical system. For instance, when you hit the the wooden or iron door of a building, a soft sound is produced. This happens simply because amplitude.
Be that as it may, a wave is referred to as a disturbance which travels through a particular medium, transferring energy from one point to another point.
So therefore, the amplitude of a wave goes a long way to determine the loudness and softness of music.
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a boy and a girl are at rest on separate skis 12 m apart on a horizontal icy surface. the boy and his skis have twice the inertia of the girl and her skis. determine the location of the center of mass in meters measured from the position of the girl.
With the position of the girl as a reference point, the center of mass is 8 m from the girl position.
If there are two objects as shown on the attached picture, the center of mass is:
xc = m₁ / (m₁ + m₂) . x₁ + m₂ / (m₁ + m₂) . x₂
From the problem, we know that the boy and his skis have twice the inertia of the girl and her skis. We can replace the mass in the equation with inertia, hence:
xc = I₁ / (I₁ + I₂) . x₁ + I₂ / (I₁ + I₂) . x₂
Let:
I₁ = the girl's inertia
I₂ = the boy's inertia
Hence,
I₂ = 2 I₁
Let make the position of the girl as a reference point, then,
x₁ = 0
x₂ = 12
Plug these parameters into the formula:
xc = I₁ / (I₁ + I₂) . 0 + 2 I₁ / (I₁ + 2 I₁) . 12
xc = 2/3 . 12 = 8 m
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How long would it take an airplane to travle 1089 miles if its flying at a speed of 375 miles per hour
Answer:
2.904
Explanation:
It would take an airplane 2.904 hours to travel 1089 miles.
As a fraction, this would equal 363/125
As a percentage, this would equal 290.4%
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The gravitational force between two objects is 36 N. What will the new gravitational force be if the distance between them is tripled (x3)? A.4 N B.9 N C.18 N D.27 N
The new gravitational force when the distance between them is tripled is 4 N.
What is the gravitation force between the objects?
The gravitation force between the objects is calculated by applying Newton's law of universal gravitation.
F = Gm₁m₂/R²
where;
G is universal gravitation constantm is the mass of the objectsR is the distance between the objectsF is the forceFrom the equation above;
F₁R₁² = F₂R₂²
F₂ = F₁R₁²/R₂²
When the distance is tripled,
R₂ = 3R₁
F₂ = F₁R₁²/(3R₁)²
F₂ = F₁R₁²/9R₁²
F₂ = F₁/9
F₂ = 36 N/9
F₂ = 4 N
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The gravitational force between two object is 36 N then the new gravitational force will be 4 N. Hence, option A is correct.
What is gravity?Gravity, also referred to as gravitation, is the unchanging force of attraction that binds everything together in mechanics. Being the weakest known force in nature, it has little effect on determining the intrinsic properties of common objects.
F = Gm₁m₂/ R²
From the equation above;
F₁ × R₁² = F₂ × R₂²
F₂ = F₁R₁²/R₂²
According to the question, when the distance is tripled,
R₂ = 3R₁
F₂ = F₁ R₁²/(3R₁)²
F₂ = F₁ R₁²/ 9R₁²
F₂ = F₁ / 9
F₂ = 36 N/9
F₂ = 4 N
Hence, the new gravitational force will be 4 N.
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