In one to two sentences, describe the relationship between harmonics and resonance frequency in a piano.

Hi there!

We can use the work-energy theorem and apply it to this situation.

At the top of the ramp, the ball only has gravitational potential energy, and at the bottom of the ramp, the ball has BOTH translational and rotational kinetic energy.

We must use the following equations:
[tex]GPE = mgh \\KE_T = \frac{1}{2}mv^2\\\\KE_R = \frac{1}{2}I \omega^2[/tex]

m = mass of sphere (kg)
g = acceleration due to gravity (m/s²)

h = height of ramp (m)

v = final velocity (m/s)
I = Moment of Inertia (kgm²)

ω = angular velocity (rad/sec)

Since:
[tex]E_i = E_f\\\\mgh = \frac{1}{2}mv^2 + \frac{1}{2}I\omega ^2[/tex]

In order to make things easier, since the ball is not slipping, we can relate angular velocity to translational velocity:
[tex]\omega = \frac{v}{r}[/tex]

Also, recall the equation for the moment of inertia for a solid sphere:
[tex]I = \frac{2}{5}mr^2[/tex]

We can use these to simply our equation:
[tex]KE_R = \frac{1}{2}(\frac{2}{5}mr^2)(\frac{v}{r})^2 = \frac{1}{5}mv^2[/tex]

Now, we can rewrite the equation and solve for 'v'.

[tex]mgh = \frac{1}{2}mv^2 + \frac{1}{5}mv^2\\\\mgh = \frac{7}{10}mv^2\\\\v = \sqrt{\frac{10gh}{7}} = \sqrt{\frac{10(9.8)(2.2 - 1.87)}{7}} = 2.149\frac{m}{s}[/tex]

a)

We can begin by solving for the time taken for the ball to land on the ground. The ball only has a horizontal velocity, so this is essentially a free-fall situation. Use the rearranged kinematic equation:
[tex]t = \sqrt{\frac{2h}{g}} = \sqrt{\frac{2(1.87)}{9.8}} = .6178 s[/tex]

Now, use the following equation to solve for horizontal distance given horizontal velocity and time:
[tex]d_x = v_x t\\\\d_x = 2.149 * .6178 = \boxed{1.328 m}[/tex]

b)
We can use the previously-stated relationship between translational and angular velocity to solve for the angular velocity.

[tex]\omega = \frac{v}{r}[/tex]
It is given that the diameter is 0.14 m, so the radius is 1/2th the diameter, or 0.07 m.

Solve for the angular velocity:
[tex]\omega = \frac{2.149}{0.07} = 30.706 \frac{rad}{sec}}[/tex]

Using the above fall time and dimensional analysis to convert from rad/sec to revolutions, we can solve for the # of revolutions made by the ball:
[tex]\frac{30.706rad}{sec} * .6178 sec * \frac{1 rev}{2\pi rad} = \boxed{3.019 rev}[/tex]

The answer is fossil fuel

Hope it helps!

The answer is fossil fuel

Answer:

The volume of a gas is dependent on pressure and temperature.

Explanation:

Pressure and temperature affect different gases differently giving varied conclusions to the exact volume of that gas.

:-befrank

Answer:

History of the 9 Planets in our solar system The ancient Greeks came across seven lights in the sky that moved against the background pattern of stars: the sun, the moon, Mercury, Venus , Mars, Jupiter, and Saturn. then they decided to name them Planetes, or Wanderers.

Explanation:

A planet is a celestial body. The nickname for the earth is "blue planet".

A celestial body is differentiated from the fixed stars by its apparent mobility (including the moon and sun), especially in relation to its claimed impact on people and events.

The nicknames for the planets in our solar system are:

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Force is a vector, as such we know that the force required to crack a nut is the resultant of the individual forces applied form all sides of the nut.

The term force is used to describe that which causes a change in the position of an object. Now the question is incomplete but I will try to help you the much I can.

Recall that force is a vector quantity. Hence the magnitude of the force required to crack a nut is the resultant of the individual forces applied form all sides of the nut.

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Answer:

no

Explanation:

because if the north pole of the magnet is brought the the refrigerator and it sticks that means the refrigerator is the south pole. So if the south pole magnet is brought the the refrigerator that is also a south pole it would not stick because same poles repel and opposite poles attract.

The magnitude of the centripetal force on the car is 69.6 N.

This is a force acting on a body in circular path and it is directed to the center around which the body is moving.

To calculate the centripetal force on the car, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the magnitude of the centripetal force on the car is 69.6 N.

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Answer:

Finance costs (also known as interest fees) aren't added to your account in a set amount like other fees.

OR

A credit card is a payment card that is issued to users to allow them to pay a merchant for products and services depending on their outstanding debt. The card issuer opens a revolving account for the cardholder and provides a line of credit from which the cardholder can borrow money to pay a merchant or get a cash advance. Consumer credit cards and business credit cards are the two types of credit cards available. The majority of the cards are plastic, however, there are a few metals and gemstone-encrusted metal cards.

Explanation:

Answer:

The buoyant force on a submerged object depends upon the volume of the object.

Explanation:

In series connection the current flow remains constant

Answer:

A planet revolves around the Sun and a moon orbits a planet. Technically, the moon also orbits the Sun as it spins around its planet, but because it has its own sub-orbit of a planet scientists define it as a moon. All planets in our solar system, except for Mercury and Venus, have moons. Earth has one moon, Mars has two, Neptune has thirteen, Uranus has twenty-seven, Jupiter has sixty-six, and Saturn has sixty-two. Pluto, now classified as a dwarf planet, has five moons.

The most likely reason for Mrs. Wilson's warning will be the magnet might lose its magnetism.

Magnetism is a component of the larger phenomena of electromagnetic. The most well-known effects occur in ferromagnetic materials,

Which are highly attracted by magnetic fields and maybe magnetized to become permanent magnets, hence creating magnetic fields. It is also feasible to demagnetize a magnet.

We should not drop a magnet on the floor since magnets progressively lose magnetism and grow weak over time if they are not properly preserved.

Hence this is most likely the reason for Mrs. Wilson's warning will be the magnet might lose its magnetism.

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Answer:

The correct answer is A!

Explanation:

~Hope this helps! :)

Aceleration refers to motion but gravity refers to force

Acceleration is change of velocity with time while gravity is the force of attraction pulling objects. When this force pulls an object it tends to move with a certain type of acceleration called acceleration due to gravity. This is equal to 9.8 m / s^2 for earth

Acceleration is the rate of change in velocity. While g is the acceleration due to gravity. The pace at which a body's velocity varies is represented by acceleration, which is a vector quantity.

The rate of change of velocity with respect to time is known as acceleration. According to Newton's second law, the eventual effect of all forces applied to a body is its acceleration.

[tex]\rm a = \frac{v-u}{t}[/tex]

u is the initial speed

v is the final speed

t is the time interval

a is the acceleration of the ball

Gravitation is a natural law by which all things with all matter are attracted towards one another.

g is the acceleration due to gravity. whose value is equal to 9.81 m/sec².The value of the gravitational acceleration varies according to the height and the planet.

The value of the gravitational acceleration on the earth is 9.81 m/sec².While the value of g at the moon is 1.6333 m/sec².

Hence acceleration is the rate of change of velocity. While g is the acceleration due to gravity.

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The sampling rate that's given regarding the CPU will produce a rate of 256kps.

The following can be gotten from the question:

Sampling rate = 8KHx

Number of bits = 32

The data rate will be:

= 32 × 8kbps

= 256kps

In conclusion, the sampling rate that's given regarding the CPU will produce a rate of 256kps.

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The sampling rate specified for the CPU will result in a 256kb/s rate.Sampling rate is also known as the sampling frequency.

The number of samples per second collected from a continuous signal to create a discrete or digital signal is referred to as sampling rate or sampling frequency.

The given data in the problem is;

Sampling rate= 100 mhz cpu

Number of  bits=32

The rate of the data is;

[tex]\rm R = 32 \times 8 kb/ s \\\\ \rm R = 256 kb / s \\\\[/tex]

Hence the sampling rate specified for the CPU will result in a 256kb/s rate.

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Answer:

B

Explanation:

a=v/t

a=(40m/s)÷(80s)

a=0.5m/s

Answer:

the current is 5.2 Amps

Answer:

displacement, acceleration, potential energy

Explanation:

pretty sure this is correct but dont hold me to it.

The set of three that can have maximum magnitudes at the same instant of time will be displacement, acceleration, and potential energy.

Simple harmonic motion is periodic motion caused by a restoring force that is proportionate to the deviation from equilibrium.

Simple harmonic motion is periodic motion but many other conditions are dependent.

The object is in simple harmonic motion of the following quantities related to the object.

The set of three that can have maximum magnitudes at the same instant of time will be displacement, acceleration, and potential energy.

Hence the set of three quantities is the options i, iii,v.

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Answer:

50N

Explanation:

this is because 5×10all over 100 ,0 will cancile 0 remaining 10 ,1 into 10 ,10times ,so 5×10 =50N

Answer:

S = θ R      where S is the arc length and θ the arc length in radians

S = 2.5 ft * 4 π^3 rad = 2.5 * 124 = 310 ft       (1 radian = 2.5 ft)

Assuming 4π3 means 4π^3

The Reagan travel over an angle of 4π/3radians is 10.47 or 10 feet if the Reagan rides on a playground roundabout with a radius of 2. 5 feet.

It is defined as the combination of points that and every point has an equal distance from a fixed point ( called the center of a circle).

We have Reagan rides on a playground roundabout with a radius of 2.5 feet.

We know the relation between arc length and radius of the circle:

S = R∅

Here R = 2.5 feet, and central angle ∅ = 4π/3

[tex]\rm S = 2.5\times \frac{4\pi}{3}[/tex]

S = 10.47 feet ≈ 10 feet

Thus, the Reagan travel over an angle of 4π/3radians is 10.47 or 10 feet if the Reagan rides on a playground roundabout with a radius of 2. 5 feet.

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Question :-

Answer :-

Explanation :-

As per the provided information in the given question, we have been given that the Speed of the Train is 60 m/s . Time taken to stop the Train is 85 sec . And, we have been asked to calculate the Acceleration of the Train .

For calculating the Acceleration , we will use the Formula :-

[tex] \bigstar \: \: \: \boxed { \sf{ \: Acceleration \: = \: \dfrac{v \: - \: u}{t} \: }} \\ [/tex]

Where ,

Therefore , by Substituting the given values in the above Formula :-

[tex] \dag \: \: \: \: \sf{Acceleration \: = \: \dfrac{Final \: Velocity \: - \: Initial \: Velocity}{Time} } \\ [/tex]

[tex] \longmapsto \: \: \: \sf{Acceleration \: = \: \dfrac{0 \: - \: 60}{85} } \\ [/tex]

[tex] \longmapsto \: \: \: \sf{Acceleration \: = \: \dfrac{60}{85} } \\ [/tex]

[tex] \longmapsto \: \: \: \textbf {\textsf {Acceleration \: = \: 0.70 }} [/tex]

Hence :-

[tex] \underline {\rule {210pt} {4pt}} [/tex]

Note :-

Answer:

Question :-

If a Train going with 60 m/s Speed hits the Brakes, and takes 85 sec to stop. What is the Acceleration of the Train ?

Answer :-

Acceleration of Train is 0.70 m/s² .

Explanation :-

As per the provided information in the given question, we have been given that the Speed of the Train is 60 m/s . Time taken to stop the Train is 85 sec . And, we have been asked to calculate the Acceleration of the Train .

For calculating the Acceleration , we will use the Formula :-

\begin{gathered} \bigstar \: \: \: \boxed { \sf{ \: Acceleration \: = \: \dfrac{v \: - \: u}{t} \: }} \\ \end{gathered}

★

Acceleration=

t

v−u

Where ,

V denotes to Final Velocity .

U denotes to Initial Velocity .

T denotes to Time Taken .

Therefore , by Substituting the given values in the above Formula :-

\begin{gathered} \dag \: \: \: \: \sf{Acceleration \: = \: \dfrac{Final \: Velocity \: - \: Initial \: Velocity}{Time} } \\ \end{gathered}

†Acceleration=

Time

FinalVelocity−InitialVelocity

\begin{gathered} \longmapsto \: \: \: \sf{Acceleration \: = \: \dfrac{0 \: - \: 60}{85} } \\ \end{gathered}

⟼Acceleration=

85

0−60

\begin{gathered} \longmapsto \: \: \: \sf{Acceleration \: = \: \dfrac{60}{85} } \\ \end{gathered}

⟼Acceleration=

85

60

\longmapsto \: \: \: \textbf {\textsf {Acceleration \: = \: 0.70 }}⟼Acceleration = 0.70

Hence :-

Acceleration = 0.70 m/s² .

\underline {\rule {210pt} {4pt}}

Note :-

Kindly Scroll the Screen from Right to Left for Better View .

Answer:

Any of those terms can be converted to either of the other terms, so either term is correct. People are accustomed to everyday temperatures in Fahrenheit. The ideal gas law specifies that

P V = N R T     where T is in Kelvin which is Celsius + 273 deg.

Answer:

The units for specific heat can either be joules per gram per degree (J/goC) or calories per gram per degree

Explanation:

The tension does no (zero) work

F· S = W

Since the tension is perpendicular to the direction of motion, and there is no change in S the work done is zero.

The tangential velocity of the car's tire is the product of the angular velocity and radius of the car's tire which is 11(r) m/s.

The angular velocity of the tire is the rate of change of angular displacement of the tire with time.

The magnitude of the angular velocity of the tire is calculated as follows;

ω = 2πN

where;

ω = 2π x (5.25 / 3)

ω =  11 rad/s

The tangential velocity of the car's tire is the product of the angular velocity and radius of the car's tire.

The magnitude of the tangential velocity is caculated as follows;

v = ωr

where;

v = 11r m/s

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During the collision an impulse is created which due to which is equal to change in momentum.

Mathematically,

[tex]\green{ \underline { \boxed{ \sf{Impulse, F\times t = m (v-u) }}}}[/tex]

where

Now,

[tex]\begin{gathered}\\\implies\quad \sf F \times 0.4 = 850 \times (0-30) \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\implies\quad \sf F \times 0.4 = 850 \times -30 \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\implies\quad \sf F = -\frac{25500}{0.4} \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\implies\quad \sf F = -63750 N \\\end{gathered} [/tex]

[tex]\quad\quad\quad\quad\quad\quad[/tex](-ve sign denotes opposite direction)

Therefore, a force of 63750 Newton will act on the car in opposite direction.

Answer:

open

Explanation:

in open system mechanical energy is lost to its surroundings

Answer:

At some point on say, the receiving screen, light emanating from the left side of the slit will be out of phase (a difference of 1/2 wavelengths) from   light coming from the center of the slit.

Thus for every point that is left of the center of the slit, there will be a point on the right side of the slit that is out of phase,

There will be no light on the screen at that particular point and thus there will be a dark fringe there.

That is the basic explanation for the appearance of dark and bright fringes on the receiving screen.