Answer:
D
Explanation:
because replusive force is much more
For the following chemical reaction:
In the laboratory, a chemist mixed aqueous barium chloride with aqueous potassium oxide which produced solid barium oxide and aqueous potassium chloride
A. Write the complete balanced chemical equation, including phase labels.
B. Identify the type of reaction that has occurred.
C. Identify the indicator that tells you a chemical reaction has occurred.
Answer:
A. The complete balanced chemical equation, including phase labels, for the reaction is:
BaCl2 (aq) + K2O (aq) → BaO (s) + 2KCl (aq)
B. The type of reaction that has occurred is a double displacement or metathesis reaction. In this reaction, the barium cations (Ba2+) and potassium anions (K+) exchange partners, resulting in the formation of solid barium oxide (BaO) and aqueous potassium chloride (KCl).
C. The indicator that tells you a chemical reaction has occurred is the formation of a solid precipitate. In this reaction, the solid barium oxide (BaO) that forms is a clear indication that a chemical reaction has occurred. Additionally, the fact that the reactants are aqueous and the products include both a solid and an aqueous solution also indicates a chemical reaction has taken place.
After addition of 20.00 mL of 0.500 M standard KOH solution to 10.00 mL of formic acid (HCOOH, Ka = 1.8 × 10-4), the equivalence point is reached. What is the molarity of the formic acid?
What is the pH at the equivalence point, based on the question above? Please make a suggestion for an appropriate indicator.
Answer: 3.79
Explanation: The balanced chemical equation for the reaction between formic acid (HCOOH) and KOH is:
HCOOH + KOH → HCOOK + H2O
We can use the stoichiometry of this reaction to calculate the number of moles of formic acid that reacted with the KOH:
moles of KOH = (20.00 mL)(0.500 mol/L) = 0.01000 moles
moles of HCOOH = moles of KOH
Therefore, the initial number of moles of formic acid is:
moles of HCOOH = (10.00 mL)(x mol/L) = 0.01000 moles
where x is the molarity of formic acid.
Solving for x, we get:
x = 1.00 M
Therefore, the molarity of the formic acid is 1.00 M.
At the equivalence point, all of the formic acid has reacted with the KOH, and the solution contains only the salt formed by the reaction, potassium formate (HCOOK). The pH at the equivalence point can be calculated using the equation for the salt hydrolysis constant:
Kb = Kw/Ka
where Kb is the base dissociation constant of the conjugate base (formate ion), Kw is the ion product constant for water (1.0 × 10^-14 at 25°C), and Ka is the acid dissociation constant of the acid (formic acid). Rearranging this equation, we get:
Kb/Ka = [OH^-][HCOO^-]/[HCOOH]
At the equivalence point, the concentration of the formate ion (HCOO^-) is equal to the concentration of the KOH added (0.01000 moles / 30.00 mL = 0.3333 M). We can assume that the concentration of the hydroxide ion (OH^-) is also equal to 0.3333 M, since KOH is a strong base and will dissociate completely. Substituting these values into the equation above, we get:
Kb/Ka = (0.3333)^2 / [HCOOH]
Solving for [HCOOH], we get:
[HCOOH] = (0.3333)^2 / (1.8 × 10^-4) = 6181.5 M
Taking the negative logarithm of this concentration, we get the pH at the equivalence point:
pH = -log[HCOOH] = -log(6181.5) = 3.79
Therefore, the pH at the equivalence point is 3.79.
Regenerate response
What is the IUPAC-name for this thing?
The IUPAC name for the compound given in the question is 2,3-dibromo-5-methylheptane
How do i determine the IUPAC name for the compound?The IUPAC name for compound can be obtained by using the following steps:
Locate the longest continuous carbon chain. In this case it is carbon 7. Hence, the parent name is heptaneIdentify the substituent groups attached. In this case the substituent groups attached are: Br and CH₃ Give the substituents the best possible low count. In this case, there are two Br groups located at carbon 2 and 3 while the CH₃ is located at carbon 5Combine the above to obtain the IUPAC name for the compound.Thus, the IUPAC name for the compound is: 2,3-dibromo-5-methylheptane
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Please help almost due?
Answer:
-lithium
-atomic number
-mass number
-protons
Explanation:
A student used a balance and a graduated cylinder to collect the data 10.23,20.0, and 21.5 calclulate the density of the elements
Assuming that the student measured the mass of the elements using a balance and the volume using a graduated cylinder, we can use the following formula to calculate the density:
Density = mass / volume
Let's say the masses of the elements were 10.23 grams, 20.0 grams, and 21.5 grams, and the volumes were 10 mL, 20 mL, and 25 mL respectively.
Then, the densities would be:
Density of element 1 = 10.23 g / 10 mL = 1.023 g/mL
Density of element 2 = 20.0 g / 20 mL = 1.0 g/mL
Density of element 3 = 21.5 g / 25 mL = 0.86 g/mL
What is density?
Density is a physical property of matter that describes how much mass is contained in a given volume of a substance. It is defined as the amount of mass per unit volume, and is typically measured in grams per cubic centimeter (g/cm³) or kilograms per cubic meter (kg/m³).
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How many molecules of HCI are in 4.91 L of HCI acid at 25°C if the density equals 1.096 g/ml
To determine the number of HCl molecules in 4.91 L of HCl acid at 25°C, we can use the following steps:
Calculate the mass of the HCl acid in 4.91 L using its density.Convert the mass of HCl acid to the number of moles using its molar mass.Use Avogadro's number to convert the number of moles of HCl to the number of HCl molecules.Calculate the mass of the HCl acid in 4.91 L using its density:[tex]\qquad\sf {Density = \dfrac{mass}{volume}}[/tex]
[tex]\qquad\sf{mass = density \times volume}[/tex]
[tex]\qquad\sf{mass = 1.096 \: g/mL \times 4.91\: L = 5.38\: kg}[/tex]
Convert the mass of HCl acid to the number of moles using its molar mass. The molar mass of HCl is 36.46 g/mol.
[tex]\sf{moles = \dfrac{mass}{ molar\: mass} = \dfrac{5.38\: kg}{36.46\: g/mol} = 147.6\: mol}[/tex]
Use Avogadro's number to convert the number of moles of HCl to the number of HCl molecules. Avogadro's number is [tex]6.02 \times 10^23[/tex] molecules/mol.
[tex]\sf number\: of\: HCl\: molecules = moles \times Avogadro's\: number[/tex]
[tex]\begin{aligned}\sf number\: of\: HCl\: molecules& =\sf 147.6 \: mol \times 6.02 \times 10^23\: molecules/mol \\& =\sf 8.88 \times 10^25\: molecules\end{aligned}[/tex]
Therefore, there are [tex]8.88 \times 10^25[/tex] HCl molecules in 4.91 L of HCl acid at 25°C, assuming the density of the acid is 1.096 g/mL.
[tex]\rule{200pt}{5pt}[/tex]
What's the difference between magnesium and Aluminum?
Answer:
The key difference between aluminum and magnesium is that the aluminum is a corrosion resistant metal whereas magnesium is not. Magnesium and aluminum are two chemical elements that we can categorize as metals in the periodic table. Both are naturally occurring metals in different mineral forms.
Explanation: