Launch Problem
a) There are two stores selling boxes of crackers. Based on the information below, which store should Sylvio
purchase the crackers from? Explain your answer.
Store 1
ion
Numbero Boed Cachers
3
5
6
00
9
B
12
2
bl...
Store 2:
C = 1.5b
c = cost and b = boxes of crackers
...
b) Sylvio also needs to purchase lemons. If Sylvio wants to buy 3 boxes of crackers and 6 lemons and he does
not want to go to both stores, which one should he shop at? Explain your answer.
Store 1:
Number of lemons
3
6
9
12
1
Cost (in dollars)
2
3
4

Given:

The given sum is:

[tex]\sum _{k=4}^9(5k+3)[/tex]

To find:

The expanded form and find the sum.

Solution:

We have,

[tex]\sum _{k=4}^9(5k+3)[/tex]

The expanded form of given sum is:

[tex]\sum _{k=4}^9(5k+3)=(5(4)+3)+(5(5)+3)+(5(6)+3)+(5(7)+3)+(5(8)+3)+(5(9)+3)[/tex]

[tex]\sum _{k=4}^9(5k+3)=(20+3)+(25+3)+(30+3)+(35+3)+(4+3)+(45+3)[/tex]

[tex]\sum _{k=4}^9(5k+3)=23+28+33+38+43+48[/tex]

[tex]\sum _{k=4}^9(5k+3)=213[/tex]

Therefore, the correct option is C.

Answer:

Subject : Tomato plant

Explanatory variables : Watering condition ; Fertilizer addition

Treatment : daily watering ; half fertilizer ; full fertilizer

Response variable = Number of tomato picked

Step-by-step explanation:

Subjects are the individuals, animals or plants upon which treatment is applied. The subject here are the tomato plants

The Explanatory variables are the independent variables upon which we want base the variation of the dependent variable. The Independent variables are the watering condition a d the amount of fertilizer added.

Treatment : These are the actual changes made or applied on the subject, they include, daily watering, full or half fertilizer application.

Response variable : The number of tomatoes picked. This is also called the dependent variable, it is the outcome which may be due to the effect of the independent variable.

Answer:

He can lift 160 pounds

Step-by-step explanation:

125 (from last year) + 35 (more pounds) = 160 (total pounds)

125 + 35 = 160

Answer:

28 in.

Step-by-step explanation:

Since the right portion of the figure is a square, the unlabeled bottom must be the same as the top or 6 in., therefore just add up the pieces starting on the right side. (5 + 6 + 2 + 5 + 4 + 6 = 28)

Answer:

Step-by-step explanation:

Answer:

its not loading

Step-by-step explanation:

Answer:

Step-by-step explanation:

First,

7 times 8 = 7 × 8 = 56

Then,

The product divided by 2 = 56 ÷ 2 = 28

Hence,

The required answer is 28

Answer:

≈ 0.52

Step-by-step explanation:

P( head ) = 2/3 , P( tail ) = 1/3

when a head is tossed ; Gambler A wins $1

when a tail is tossed : Gambler B wins $1

Determine the P( Gambler A wins the game ) if he starts with I dollars

Assuming I = $1

n = 5

p ( head ) = P( winning ) = 0.66

p( losing ) = 0.33

applying the conditional probability in Markov which is ;

Pₓ = pPₓ₊₁ + (1 - p) Pₓ₋₁

P( 1) = 0.66P₂ + 0.33P₀

resolving the above using with Markov probability

P( 1 ) = 0.51613

hence the probability of Gambler A winning the game if he starts with $1

≈ 0.52

Answer:

[tex](a)\ Pr = \frac{2}{5}[/tex]

[tex](b)\ Pr = \frac{9}{20}[/tex]

[tex](c)\ E(Orange) = 100[/tex]

[tex](d)\ E(Orange) = 62.5[/tex]

Step-by-step explanation:

Solving (a): Theoretical probability of green or yellow

Here, we consider the spinner itself

From the attached image, we have:

[tex]n= 5[/tex] --- i.e. 5 sections

[tex]Yellow = 1[/tex]

[tex]Green = 1[/tex]

So, the probability is:

[tex]Pr = P(Yellow)\ or\ P(Green)[/tex]

[tex]Pr = \frac{Yellow}{n} + \frac{Green}{n}[/tex]

[tex]Pr = \frac{1}{5} + \frac{1}{5}[/tex]

Take LCM

[tex]Pr = \frac{1+1}{5}[/tex]

[tex]Pr = \frac{2}{5}[/tex]

Solving (b): Experimental probability of green or yellow

Here, we consider the result of the experiment

From the attached image, we have:

[tex]n= 40[/tex] --- i.e. 40 spins

[tex]Yellow = 12[/tex]

[tex]Green = 6[/tex]

So, the probability is:

[tex]Pr = P(Yellow)\ or\ P(Green)[/tex]

[tex]Pr = \frac{Yellow}{n} + \frac{Green}{n}[/tex]

[tex]Pr = \frac{12}{40} + \frac{6}{40}[/tex]

Take LCM

[tex]Pr = \frac{12+6}{40}[/tex]

[tex]Pr = \frac{18}{40}[/tex]

Simplify

[tex]Pr = \frac{9}{20}[/tex]

Solving (c): Expectation of orange outcomes in a spin of 500 times, theoretically.

Here, we consider the spinner itself

From the attached image, we have:

[tex]n= 5[/tex] --- i.e. 5 sections

[tex]Orange = 1[/tex]

So, the probability of having an outcome of orange in 1 spin is:

[tex]Pr = P(Orange)[/tex]

[tex]Pr = \frac{Orange}{n}[/tex]

[tex]Pr = \frac{1}{5}[/tex]

In 500 spins, the expectation is:

[tex]E(Orange) = Pr * 500[/tex]

[tex]E(Orange) = \frac{1}{5} * 500[/tex]

[tex]E(Orange) = 100[/tex]

Solving (c): Expectation of orange outcomes in a spin of 500 times, base on experiments.

Here, we consider the spinner itself

From the attached image, we have:

[tex]n= 40[/tex] --- i.e. 40 spins

[tex]Orange = 5[/tex]

So, the probability of having an outcome of orange is:

[tex]Pr = P(Orange)[/tex]

[tex]Pr = \frac{Orange}{n}[/tex]

[tex]Pr = \frac{5}{40}[/tex]

[tex]Pr = \frac{1}{8}[/tex]

In 500 spins, the expectation is:

[tex]E(Orange) = Pr * 500[/tex]

[tex]E(Orange) = \frac{1}{8} * 500[/tex]

[tex]E(Orange) = 62.5[/tex]

Answer:

x = 2 , 1

Step-by-step explanation:

Answer:

2.5 or 3.5

Step-by-step explanation:

The quadratic formula is [tex]x = -b +/- \frac{\sqrt{b^2 + 4ac}}{2a}[/tex] .

a, b, and c are determined by the terms in the formula ax^2 + bx + c

They gave you the equation x^2 - 3x - 2, which fits that formula. a is 1, b is -3, and c is -2. So plug those values into the equation:

[tex]x = -(-3) +/- \frac{\sqrt{(-3)^2 + 4(1)(-2)}}{2(1)}[/tex]

[tex]x = 3 +/- \frac{\sqrt{9 -8}}{2}[/tex]

[tex]x = 3 +/- \frac{\sqrt{1}}{2}[/tex]

[tex]x = 3 +/- \frac{1}{2}[/tex]

So x is 3 plus or minus -1/2. 3 plus -1/2 is 2.5

3 minus -1/2 is 3.5

So the 2 possible x values are 2.5 and 3.5.

Answer:

Step-by-step explanation:

1/48 + 5/6    

The LCD of 48 and 6 is 48 so we have:

1/48 + 40/48

= 41/38

Answer:

41/48

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

This can be rearranged as 4^3 * 1/(4^6)

or (4^3)/(4^6)

This can be changed to:

(4^3)/((4^3)*(4^3)

Which is equal to 1/(4^3)

or

4^(-3)

Step-by-step explanation:

for mixed number to a improper fraction you take the whole number and times that by the denominator and add the numeriator

for example

[tex]8 \frac{3}{8} [/tex]

8 x 8 = 64

64 + 3 = 67

and after you get your last number (67) you put that over your original denominator which is 8 so it would be

[tex] \frac{67}{8} [/tex]

for the improper to mixed you see how many times you denominator goes into your numerator

another example is

[tex] \frac{13}{7} [/tex]

7 goes into 13 twice so your whole number is 2 and you have a remaining 1 so it would look like

[tex]2 \frac{1}{7} [/tex]

Answer:

A) 9/4

B) 67/8

C) 17/6

D) 9/2

E) 16/3

F) 127/12

G) 37/4

H) 41/6

Q) Whole Number: 1 Fraction: 6/7

R) Whole Number: 4 Fraction: 1/2

S) Whole Number: 1 Fraction: 8/9

T) Whole Number: 2 Fraction: 1/3

U) Whole Number: 2 Fraction: 3/7

V) Whole Number: 3 Fraction: 1/3

W) I am not 100% sure for this one but I think it's right.

Mixed Number - Whole Number: 1 Fraction: 5/8

Improper fraction - 13/8

Step-by-step explanation:

With improper fractions the first thing that you want to do is multiply the whole number with the denominator (the number on the bottom of the fraction), then add the numerator (the number on the top of the fraction). You also want to keep the denominator the same in both fractions.

When working with converting mixed fractions into improper fractions it is kind of the opposite, but it is a little harder to explain. Let's take letter Q as an example. If you know that you cannot divide the numerator and the denominator in anyway to make a whole number, the whole number will become a one and the numerator is how many are left. so in this case the answer for Q would be 1 6/7, 1 being the whole number and 6 from 6+7=13. now let's look at letter R, you know you can divide 2 four times into 9, the whole number will be 4 and the fraction will be 1/2, 4x2+1=9. You can also double check that you did it right by turning it back into a improper fraction from the mixed number state by multiplying the denominator with the whole number, then adding the numerator. Hope that made sense, send me a DM if you need more help!

Answer:

Step-by-step explanation:

Answer:

13 minutes

Step-by-step explanation:

The reason why it is 13 minutes is because you subtract 10:41 AM from 10:28 AM and you get 13 minutes.

Answer:

13

Step-by-step explanation:

41-28= 13

the hours don't change so you just need to subtract the minutes

Answer:

a.

Approximately [tex]24.7\; \rm in[/tex].

b.

While there are three diagonals in a box (a rectangular prism,) all three diagonals goes through the same point- the centroid of this box.  

For a maximum-length poster to fit in this box, it would have to be on one of the main diagonals of this box. Hence, any maximum-length poster that fits in this box would go through the centroid of this box.

It's not possible to force more than one posters to go through the same point (i.e., the centroid) in space. Hence, it would not be possible to fit a second maximum-length poster into this box.

This argument does not apply to  [tex]21.5\; \rm in[/tex] posters. These posters are shorter than the diagonal of this box; they could fit inside the box without having to go through a particular point in space.

Step-by-step explanation:

The longest poster that could be fit into this box (a rectangular prism) would be as long as the longest line segment in this box. That line segment would be one of the three diagonals of this box.

Apply the Pythagorean theorem twice to find the length of that diagonal.

Start by finding calculating the diagonal of the base of this box. The base of this box is a rectangle with width [tex]8\; \rm in[/tex] and length [tex]10\; \rm in[/tex]. The length of its diagonal would be [tex]\sqrt{8^2 + 10^2}[/tex] inches.

Combine that with the height of this box to find the length of the diagonal of this box.

[tex]\begin{aligned}& \sqrt{{\left(\sqrt{8^2 + 10^2}\right)}^2 + 12^2 \\ &= \sqrt{8^2 + 10^2 + 12^2} \\ &\approx 24.7 \end{aligned}[/tex].

Answer:

90°

Step-by-step explanation:

It's simple, the angle of a line is 180°

∠EFG=90°

Line GD-∠EFG=180°-90°=90°

Please mark brainliest!

Answer:

I DONT SEE TRIANGLES

Step-by-step explanation:

Answer:

The 95% confidence interval for the proportion of water specimens that contain detectable levels of lead is (0.472,0.766).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].

In a sample of 42 water specimens taken from a construction site, 26 contained detectable levels of lead.

This means that [tex]n = 42, \pi = \frac{26}{42} = 0.619[/tex]

95% confidence level

So [tex]\alpha = 0.05[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.619 - 1.96\sqrt{\frac{0.619*0.381}{42}} = 0.472[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.619 + 1.96\sqrt{\frac{0.619*0.381}{42}} = 0.766[/tex]

The 95% confidence interval for the proportion of water specimens that contain detectable levels of lead is (0.472,0.766).

Answer:

The nth term is 27 - 30(n-1) or can be simplified to 57 - 30n.

Step-by-step explanation:

This is an arithmetic sequence (ie. each term equals the previous term with a constant value added (or subtracted from it)

T1 = 27

T2 = -3 = T1 - 30 = 27 - 30

T3 = -33 = T2 -30 = 27 -30 - 30=27-30X(2)

T4= -63 = T3 - 30 =27-30X(2)-30=27-30X(3)

In general, the nth term of this sequence:

S(n) = 27 - 30X(n-1)

Answer:

1,408 packs can be made, and 2 pens will be left out.

Step-by-step explanation:

Given that a manufacturer has 5,634 pens to divide into packs of 4 pens, and the manufacturer makes as many packs as possible, to determine how many packs of pens does the manufacturer make, and how many pens are left over, the following must be done calculation:

5.634 / 4 = X

1,408.5 = X

5,634 - (1,408 x 4) = X

5.634 - 5.632 = X

2 = X

Therefore, 1,408 packs can be made, and 2 pens will be left out.

Answer: 1,408 packs can be made and 2 will be left out

Step-by-step explanation:

Answer:

1.004728

Step-by-step explanation:

Mark as brainllest

Answer:

2, 3, 4 (up to down)

Step-by-step explanation:

Rational: can be terminating, repeating, in a fraction

Irrational: Not terminating (ending), doesn't repeat (o.33333....), and you can't put it in a fraction

Hope this helps!!

p.s. brainliest plz

Answer:

simple interest

Step-by-step explanation:

An additional amount of money added to borrowed money only on the principal could be simple interest.

If the initial amount (also called as principal amount) is P, and the interest rate is R% annually, and it is left for T years for that simple interest, then the interest amount earned is given by:

[tex]I = \dfrac{P \times R \times T}{100}[/tex]

Since, the initial amount (also called as principal amount) is P, and the interest rate is R% per unit of time, it is left for T unit of time for that compound interest.

we can conclude that the additional amount of money added to borrowed money only on principal is simple interest.

Learn more about simple interest here:

https://brainly.com/question/5319581

#SPJ2

Answer:

x=3

Step-by-step explanation:

y=-x+3

0=-x+3

x=3

Answer:

Here is the picture

Step-by-step explanation:

The number lies between x-values 4 and 6 and y-values 6 and 9.

Coordinates are a pair of integers (Cartesian coordinates), or occasionally a letter and a number, that identify a certain place on a grid, often referred to as a coordinate plane.

Given that scatter plot lies in quadrant 1 of a coordinate plane, and the 14 points are plotted in the first quadrant.

We need to find the range of x and y values for this scatter plot.

The x values of the 14 points are given as;

2, 4, 4,1, 5, 5, 5, 5, 6, 6, 7, 8, 9.5, 9.5

The y values of the 14 points are given as;

5, 6, 9, 7.2, 6, 6.8, 8, 9, 7, 8.5, 10, 10.5, 9.5, 11.4

We can conclude that that most of the points are clustered between x-values 4 and 6 and y-values 6 and 9.

Therefore, the points are clustered between the x-values 4 and 6 and y-values 6 and 9.

To learn more about the coordinates;

brainly.com/question/27749090

#SPJ7

The complete question is

Select the correct answer. Scatter plot in quadrant 1 of a coordinate plane. 14 points are plotted at (2, 5), (4, 6), (4, 9), (4.1, 7.2), (5, 6), (5, 6.8), (5, 8), (5, 9), (6, 7), (6, 8.5), (7, 10), (8, 10.5), (9.5, 9.5), and (9.5, 11.4). Between which x-values and y-values does the cluster in this scatter plot lie? A. It lies between x-values 2 and 4 and y-values 4 and 6. B. It lies between x-values 4 and 6 and y-values 9 and 10. C. It lies between x-values 4 and 6 and y-values 6 and 9. D. It lies between x-values 7 and 9 and y-values 10 and 11.

sum of observations

no. of observations

50+55+58+90+58+92+99 502

7 7

awnser is 71.7