Answer: I would suggest blue light glasses also go to a doctor because your eye veins are bullging and thats making it worse also Im not a doctor so i cant be sure but this is my tip also be careful looking under microscopes or anything with light.
Explanation:
When 25 mL of 1.0M H₂SO4 is added to 50 mL of 1.0 M NaOH at 25°C in a calorimeter,
the temperature of the aqueous solution increases to 33.9 °C. Assuming that the specific
heat of the solution is 4.18 J/g°C, that its density is 1.00/mL, and that the calorimeter
itself absorbs a negligible amount of heat, calculate the amount of heat absorbed for the
reaction.
Answer: The amount of heat absorbed for the reaction of 25 mL of 1.0 M H₂SO4 and 50 mL of 1.0 M NaOH, resulting in a temperature increase from 25°C to 33.9°C, is 10.14 kJ.
Explanation:
L 4.4.2 Test (CST): Electricity and Energy Resources
Question 11 of 25
What happens to the field lines of two positive charges as the charges are
brought close together?
A. The field lines are attracted to the other charge.
B. The field lines cross together.
C. It would depend on what kind of positive charges they are.
D. The field lines bend away from the other charge.
SUBMIT
Answer:
D
Explanation:
because replusive force is much more
. An IV solution contains 0.0175% of Drug Z, how much of this IV solution should we infuse, if the patient needs 100 mg of Drug Z?
If this solution is infusing at 50 ml/hr, how long will it take take to complete the infusion? Hint: 1mg = 0.001g or ml.
The infusion will be finished in 114.286 hours.
We need to infuse 100 mg of Drug Z. Since the IV solution contains 0.0175% of Drug Z, we can calculate the amount of IV solution needed for the infusion.
To do this, we need to use the following formula:
Amount of IV solution = [tex]\frac{(Amount of Drug Z * 100) }{ Concentration of Drug Z}[/tex]
Amount of IV solution = [tex]\frac{(100 mg * 100) }{0.0175 \% }[/tex]
Amount of IV solution = 5,714.286 ml
To calculate how long it will take to complete the infusion, we need to use the following formula:
Time to complete infusion =[tex]\frac{Amount of IV solution }{ Rate of infusion }[/tex]
Time to complete infusion =[tex]\frac{ 5,714.286 ml }{ 50 ml/hr }[/tex]
Time to complete infusion = 114.286 hr
Therefore, it will take 114.286 hours to complete the infusion.
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A percent composition analysis yields 52.1% carbon, 13.2% hydrogen, and 34.7% oxygen. What is the empirical formula for the compound?
O:C:H ratio is 34.8/16/52.2/12/13/0/1 = 2.17/4.35/13/0 = 1:2/6. Hence, C2H6O is the empirical formula (option D).
What purposes does hydrogen serve?Fuel cells may produce heat and energy from hydrogen. Although transportation and utilities are expanding businesses, fertilizer manufacturing and petroleum refining still use hydrogen most frequently today.
Can hydrogen be burned as fuel?According to the 1992 Energy Policy Act, hydrogen qualifies as an alternative fuel. The ability of hydrogen to power fuel cell technology in zero-emission vehicles, the potential for home consumption, and the high efficiency and quick filling time of fuel cells all contribute to the interest in hydrogen as such an alternative transportation fuel.
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What does conserving mass mean in a chemical equation? Responses There is equal number of each type of atom on the reactant and product side. There is equal number of each type of atom on the reactant and product side. There are more of each type of atom on the product side than on the reactant side. There are more of each type of atom on the reactant side than on the product side. There is an unequal number of each type of atom on both sides of the equation.
Which of the following is already in its empirical formula?
-C22H34O10
-C6H6
-C6H1203
-C5H1202
-none of these
These substances C6H1203 don't already exist in their empirical formula.
How can the empirical formula in MCQS be found?The empirical formula is CH for both C2H2 and C2H6, as it represents the simplest whole number ratio of the various atoms in a molecule. The compound's molar mass is 314 g/mol, and the empirical formula mass is (2 X 12) + 1 + 80 = 105g. Hence, C6H3Br3 is the molecular formula.
What are C6H12O6 and C6H6's empirical formulas?Glucose has the chemical formula C6H12O6 = 6 x CH2O c.The molecular weight of glucose is 180 g/mol.. The empirical and molecular formulas are identical because it equals 6 x 30 g/mol.
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reaction is third order for reactant A and zero order for reactant B. If you quadruple the concentration
of A, what happens to the reaction rate? If you quadruple the concentration of B, what happens to
the reaction rate?
Regardless of the reactant B concentration, the reactant rate remains constant. As a result, the response rate is unaffected by increasing B's concentration by a factor of four.
In chemical, what is concentration?The amount of a substance's solute in a specific amount of solution is how concentrated it is. Molarity, or the amount of molecules of solute in one liter of solution, is a common unit of measurement for concentrations.
What exactly are meditation and focus?Focusing for an extended amount of time on one thing without interruption is meditation. Concentrating the mind on a specific object is the basic exercise of concentration that all meditations begin with. After some practice, concentration can eventually turn into meditation when the mind is calm and not easily diverted by other thoughts.
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Is 2 Zn (s) +2HCI(aq)+H2(g) a balanced chemical equation
what is the answers to this someone pls help
Answer:
The nuclide formed by the β decay of 26Al is 26Mg.
Mark my answer as brainliest! this was a difficult one
The pressure of compressed air that occupies 2 L is 30.0 atm. What will be the new volume of the gas if the pressure is reduced to 10.0 atm if the temperature is not allowed to change? Ty in advance!
Answer:
To solve this problem, we can use the Boyle's Law equation, which states that the pressure and volume of a gas are inversely proportional at constant temperature.
Boyle's Law: P1V1 = P2V2
where P1 and V1 are the initial pressure and volume, and P2 and V2 are the new pressure and volume.
Using the given values:
P1 = 30.0 atm
V1 = 2 L
P2 = 10.0 atm
Substituting these values into the Boyle's Law equation, we get:
30.0 atm x 2 L = 10.0 atm x V2
Simplifying and solving for V2, we get:
V2 = (30.0 atm x 2 L) / 10.0 atm
V2 = 6 L
Therefore, the new volume of the gas will be 6 L if the pressure is reduced to 10.0 atm, assuming the temperature remains constant.
I Hope This Helps!
Zinc reacts with hydrochloric acid according to the reaction equation
Zn(s) + 2 HCl(aq) → ZnCl₂(aq) + H₂(g)
How many milliliters of 1.50 M HCl(aq) are required to react with 5.05 g Zn(s)?
volume: ___ mL
Answer:
many milliliters of 1.50 M HCl(aq) are required to react with 5.05 g Zn(s)?
volume: 16 mL
First, we need to calculate the number of moles of Zn:
m(Zn) = 5.05 g
M(Zn) = 65.38 g/mol (molar mass of Zn)
n(Zn) = m(Zn) / M(Zn) = 5.05 g / 65.38 g/mol = 0.0773 mol
According to the balanced chemical equation, 1 mole of Zn reacts with 2 moles of HCl. Therefore, the number of moles of HCl needed is:
n(HCl) = 2 × n(Zn) = 2 × 0.0773 mol = 0.1546 mol
Now we can use the molarity of the HCl solution to calculate the volume needed:
M(HCl) = 1.50 mol/L
n(HCl) = V(HCl) × M(HCl)
V(HCl) = n(HCl) / M(HCl) = 0.1546 mol / 1.50 mol/L = 0.103 L = 103 mL
Therefore, we need 103 mL of 1.50 M HCl(aq) to react with 5.05 g Zn(s).
What is the percent of O in
Ca(С2H302)2?
(Ca = 40.08 g/mol, C = 12.01 g/mol,
H= 1.01 g/mol, O = 16.00 g/mol)
40.5%
Explanation:
Ca×1 = 40
C×4 = 48
H×6 = 6
O×4 = 64
64÷158×100% = 40.5%
calculate the mole fraction of HCl in a 9.8% (by mass) aqueous solution. the density of the solution is 1.03 g/mL
The mole fraction of HCl in the given solution is 0.051.
What is the mole fraction of the HCL?To calculate the mole fraction of HCl in the given solution, we need to first find the mass of HCl and water present in the solution.
Let's assume we have 100 g of the solution, so 9.8 g of it is HCl, and 90.2 g is water.
Next, we need to find the moles of HCl present in the solution.
To do this, we divide the mass of HCl by its molar mass.
The molar mass of HCl is 36.46 g/mol (1.01 g/mol for hydrogen + 35.45 g/mol for chlorine).
moles of HCl = 9.8 g / 36.46 g/mol = 0.269 mol
The moles of water can be calculated using its molar mass which is 18.015 g/mol.
moles of water = 90.2 g / 18.015 g/mol = 5.005 mol
The total number of moles in the solution is the sum of the moles of HCl and water.
total moles = 0.269 mol + 5.005 mol = 5.274 mol
The mole fraction of HCl can now be calculated by dividing the moles of HCl by the total number of moles.
mole fraction of HCl = 0.269 mol / 5.274 mol = 0.051
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In the reaction NH3(g) + O2(g) → NO(g) + H₂O(g) How many grams of H₂0 are generated when 1.54 moles of NH3 react?
Answer: 2.31 mole H2O
Explanation: blance the equation first
4 NH3 + 5O2 --> 4 NO + 6 H20
1.54 moles NH3 x ( 6 mole H20/ 4 moles NH3) X (18 g H20/1mole H20)
2.31 mole H20
A buffer solution is made using weak acid, HA, with a pKa of 6.98. If the ratio of [A-] to [HA] is 1.0 x 10^3, what is the pH of the buffer
Ten years ago, a vacant lot in a subdivision was purchased for $30,500. The owner hired a general contractor to build a home on the lot. The contractor charged $375,000. The homeowner is planning to refinance the mortgage. The bank recently appraised the home at $410,000. What is the value of the property?
The value of the property at the end of the given time period is determined as $410,000.
What is the value of the property?The value of the property is the sum of the purchase price of the lot and the cost of building the home, which is:
$30,500 (purchase price of the lot) + $375,000 (cost of building the home) = $405,500
However, the bank has appraised the home at $410,000, which means that the value of the property has increased by $4,500.
Therefore, the value of the property is:
$405,500 (original value) + $4,500 (increase in value) = $410,000.
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What's absolute zero?
A. The temperature at which all liquids freeze
B. The temperature at which water freezes
C. The coldest temperature ever recorded in nature on Earth
D. The temperature at which all molecular motion is stopped
Answer:
D. The temperature at which all molecular motion is stopped.Explanation:Absolute zero is the theoretical temperature at which all matter would have zero thermal energy and all molecular motion would stop. This temperature is equal to -273.15 degrees Celsius or -459.67 degrees Fahrenheit. It is the lowest possible temperature in the universe and cannot be reached in practice, as it is impossible to completely eliminate all thermal energy from matter.
How many moles of MgS are in 1.00g MgS?
Answer:
24.31 g/mol.
Explanation:
moles =mass/molar mass
n=w/m
A 25.0 kg iron weight lifting plate has a volume of 3180 cm3 . what is the density of the iron plate in g/cm3?
Answer:
The density of a substance is given by dividing the mass by the volume.
The S.I units of density are kg/m³, but can be measured by other units such as g/cm³
The mass of the iron is 29 kg or 29000 g
Therefore; Density = 29000 g/ 3680 cm³
= 7.880 g/cm³
Hence, the density of the iron plate is 7.880 g/cm³
Explanation:
On a distance time graph of an objects motion distance is usually what
The volume of a gas is 200 mL at 350.0 kPa pressure. What will the volume be when the pressure is reduced to 125.0 kPa, assuming the temperature remains constant.
The volume of the gas will be 560 mL when the pressure is reduced to 125.0 kPa, assuming the temperature remains constant.
What will be the volume of the gas when the pressure is reduced to 125.0 kPa?Boyle's law simply states that "the volume of any given quantity of gas is inversely proportional to its pressure as long as temperature remains constant.
Boyle's law is expressed as;
P₁V₁ = P₂V₂
Where P₁ is Initial Pressure, V₁ is Initial volume, P₂ is Final Pressure and V₂ is Final volume.
Substituting the given values, we get:
P₁ = 350.0 kPa (initial pressure)
V₁ = 200 mL (initial volume)
P₂ = 125.0 kPa (final pressure)
V₂ = ?
Solving for V₂, we get:
V₂ = ( P₁ × V₁ ) / P₂
V₂ = (350.0 kPa × 200 mL) / 125.0 kPa
V₂ = 560 mL
Therefore, the final volume of the gas is 560 mL.
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5. Use the formula that states the mass-to-volume ratio of a substance to solve the following:
(a) what is the density of a substance that has a mass of 7.9 g and a volume of 4.3 cm³?
(b) what is the mass of a substance that has a density of 8.9 g/cm³ and a volume of 5 cm³?
(c) what is the volume of a substance that has a density of 1.25 g/mL and a mass of 150 g?
Answer:
Explanation:
Part A
Density equals mass divided by volume. The units for density are g/cm³ or g/mL. Note that 1 cm³ = 1 mL.
d = m/v
Substitute the mass and the volume into the equation and then divide the bottom number into the top number.
d = 7.9 g/4.3 cm³ = 1.8 g/cm³
Part B
The density of a substance can be used as a conversion factor to find either the mass of the substance or the volume of the substance.
5 cm³ x 8.9 g/cm³ = 45 g
Note that cm³ units cancel and you are left with grams.
Part C
We will use the density of the substance to find the volume of the substance.
150 g x 1 mL/1.25 g = 120 mL
Note that you can invert density so the units of g cancel and you are left with mL.
How many moles of MgS are in 100.g MgS?
The number or amount of moles of magnesium sulfide in 100g of MgS is 1.774 moles.
How to calculate number of moles?The number of moles in a substance can be calculated by dividing the mass of the substance by its molar mass as follows:
Mole is the base unit of amount of substance i.e. the amount of substance of a system which contains exactly 6.02214076 × 10²³ elementary entities.
no of moles = mass ÷ molar mass
According to this question, 100g of magnesium sulfide is given. The molar mass of magnesium sulfide is 56.38 g/mol.
moles = 100g ÷ 56.38g/mol
moles = 1.774 moles
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Consider the reaction for the formation of aluminum oxide from aluminum and oxygen.
4Al(s)+3O2(g)⟶2Al2O3(s)Δ1
Express the enthalpy of the following reaction, Δ2,
in terms of Δ1.
2Al2O3(s)⟶4Al(s)+3O2(g)Δ2
Express the enthalpy of the following reaction, Δ3,
in terms of Δ1.
12Al(s)+9O2(g)⟶6Al2O3(s)Δ3
Express the enthalpy of the following reaction, Δ4,
in terms of Δ1.
2Al(s)+32O2(g)⟶Al2O3(s)Δ4
To solve for Δ2, we need to reverse the reaction and change the sign of Δ1:
2Al2O3(s)⟶4Al(s)+3O2(g)Δ2 = -Δ1
Therefore, Δ2 = -Δ1.
To solve for Δ3, we need to add the reactions for the formation of two moles of Al2O3 from aluminum and oxygen:
4Al(s)+3O2(g)⟶2Al2O3(s)Δ1
2Al2O3(s)⟶4Al(s)+3O2(g)Δ3
Adding these equations gives:
12Al(s)+9O2(g)⟶6Al2O3(s)Δ3
Therefore, Δ3 = 2Δ1.
To solve for Δ4, we need to divide the reaction for the formation of two moles of Al2O3 by two:
2Al(s)+3O2(g)⟶Al2O3(s)Δ1/2
Multiplying this equation by 16 gives:
32Al(s)+48O2(g)⟶16Al2O3(s)8Δ1/2
We can then cancel out the formation of 14 moles of Al2O3:
2Al(s)+32O2(g)⟶Al2O3(s)Δ4 = 8Δ1/2 - 7Δ1
Therefore, Δ4 = 8Δ1/2 - 7Δ1.
When a protonated epoxide is attacked by water, the nucleophile attacks from the ___________ in an __________ process.
When a protonated epoxide is attacked by water, the nucleophile attacks from the "top" or "front" of the epoxide ring in an "S_N2" substitution nucleophilic bimolecular process.
What is protonated epoxide ?
A protonated epoxide is a molecule that contains an epoxide ring (a three-membered ring consisting of two carbon atoms and one oxygen atom) that has been protonated, or had a hydrogen ion (H+) added to it.
The protonation of an epoxide ring can occur in the presence of an acidic medium, such as a strong acid like sulfuric acid (H2SO4) or hydrochloric acid (HCl).
In acidic conditions, the lone pair of electrons on the oxygen atom of the epoxide ring can interact with the positively charged hydrogen ion, resulting in the formation of a protonated epoxide.
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What happens to the solubility of gases in water as pressure increases?
Question 9 options:
solubility increases so less solute dissolves
solubility decreases so more solute dissolves
solubility increases so more solute dissolves
solubility decreases so less solute dissolves
Answer: Solubility increases so more solute dissolves
Explanation:
The solubility is a measure of the concentration of the dissolved gas particles in the liquid and is a function of the gas pressure. As you increase the pressure of a gas, the collision frequency increases and thus the solubility goes up, as you decrease the pressure, the solubility goes down.
I don’t get this at allll
The volume of the nitrogen oxide gas is 35.2 L
How do you apply stoichiometry?Stoichiometry is the quantitative study of reactants and products in a chemical reaction. It is used to determine the amount of reactants needed to produce a certain amount of product, or to determine the amount of product that will be produced from a given amount of reactant.
To apply stoichiometry;
We know that;
Number of moles of Cu = 150/ 63.5g/mol = 2.36 moles
If 3 moles of Cu produced 2 moles of NO
2.36 moles of Cu will produce 2.36 * 2/3
= 1.57 moles
If 1 moles of NO occupies 22.4 L
1.57 moles of NO will occupy 1.57 * 22.4/1
= 35.2 L
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Which of the following could be a useful IPM monitoring strategy to reduce crop damage from pests?
A.mating disruption devices B.noisemakers C.pesticides D.forecasting software
Answer:
C. pesticides
Explanation:
hope it helps :)
which statement describes density? Check all that apply
Density is a chemical property of an object.
The density of an object is constant.
Density is a derived unit of measure.
Density is the sum of the mass and volume of an object.
The density of an object determines whether it will sink or float.
Answer:
The density of an object is constant.
Density is a derived unit of measure.
The density of an object determines whether it will sink or float.
42 grams of nitrogen gas react with
13 grams of hydrogen gas. What is the
limiting reactant and how many grams of
ammonia will be produced?
N2 + 3H22NH3
A) H2; 74 grams NH3 produced
B) H2; 4.3 grams NH3 produced
C) N2; 3.0 grams NH3 produced
D) N2; 51 grams NH3 produced
Answer:
d
Explanation:
Nitrogen is the limiting reactant.
42 g N2x (1mole N2/28 g N2) X (2 moles NH3/ 1mole N2) X (17 grams NH3/1mole NH3) = 51 g
13 g H2 x (1 mole H2/2 g H2) X (2 moles NH3/3moles H2) X (17 g NH3/1mole NH3) =73.66g
since 51 is smaller than 73.66 and it started with N2 that is why N2 is the limiting reactant)